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Research article

Image restoration via Picard's and Mountain-pass Theorems

  • Received: 01 December 2021 Revised: 02 February 2022 Accepted: 20 February 2022 Published: 08 March 2022
  • In this work, we present existence results for some problems which arise in image processing namely image restoration. Our essential tools are Picard's fixed point theorem for a strict contraction and Mountain-pass Theorem for critical point.

    Citation: Souad Ayadi, Ozgur Ege. Image restoration via Picard's and Mountain-pass Theorems[J]. Electronic Research Archive, 2022, 30(3): 1052-1061. doi: 10.3934/era.2022055

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  • In this work, we present existence results for some problems which arise in image processing namely image restoration. Our essential tools are Picard's fixed point theorem for a strict contraction and Mountain-pass Theorem for critical point.



    In image processing, some degradations often affect an image during its acquisition or transmission. These deteriorations can be related to the image acquisition modality or the noise coming from any signal transmission. Image restoration is an important step in image processing. It permits to improve the quality of the image. There are some purposes of image restoration such as removing the noise or the blur, and adding some informations to the image. The main idea is to estimate the original image from the degraded.

    The image restoration problem is modeled in [1] as follows. Let ΩR2 be a bounded subset (the domain of the image u) where u:ΩR is the original image describing a real scene, and f be the observed image of the same scene (that is the degraded version of u). Assume that the image u has been degraded by a noise η and a linear operator φ which is not necessarily invertible, even if it is invertible, its inverse is difficult to calculate numerically.

    We seek to recover u from f such that

    f=φu+η. (1.1)

    The idea is to find an approximation of u by solving the problem

    infuΩ|fφu|2dx. (1.2)

    When the noise is neglected and if u is a minimum of (1.2), then u satisfies the equation

    φf=φφu (1.3)

    with φ which is the adjoint of φ. Since φ is not necessarily invertible, one can get u from (1.3).

    The problem of image restoration is an ill posed problem, generally its resolution is based on numerical approaches; such as gradient descent which gives approximate solutions. The direct method in the calculus of variations [1,2] is the most used when we study the problem of restoration from a theoretical point of view seeking to show that the problem admits at least a solution, and therefore one wonders if other minimization theorems such as Mountain-Pass Theorem can be applicable. Recently, authors have introduced fixed point theorems in image processing [3,4,5,6]. For detailed information on metric spaces and well-known fixed point theorems, see [7,8,9].

    Besides, recent papers deal with image restoration using fixed point theory [10,11] where authors propose new TVL1, TVL2 regularization model for image restoration. It is obvious to see the efficiency of fixed point theorems in image restoration using other regularization terms. However, the variational approach in the image restoration is the most classic. Indeed, the idea of Tikhonov and Arsenin in 1977 was to regularize the problem (1.2), that is to consider a related problem that admits a unique solution. The authors proposed to consider the problem

    infu(Ω|fφu|2dx+αΩ||2dx),α>0. (1.4)

    The functional

    Eα=Ω|fφu|2dx+αΩ||2dx,α>0 (1.5)

    is well-defined in the space H1(Ω) and the Euler-Lagrange equation associated to the problem

    infu{Eα,uH1(Ω)} (1.6)

    is

    φφuφfαΔu=0 (1.7)

    with the Neumann boundary condition

    uN=0onΩ (1.8)

    where N is the outward normal to Ω, Ω|fφu|2dx is the fidelity term to the data, αΩ||2dx is a smoothing term and α is a positive weighting constant. It was proven in [1], that under suitable assumptions on φ, the problem (1.6) has a unique solution in the space H1(Ω).

    Our first main result is to prove existence and uniqueness of solution for the problem (1.6) in the case where the operator φ designates the identity operator. Our tool is a fixed point theorem. That is to rewrite the boundary value problem

    {αΔu+u=fon ΩuN=0onΩ (2.1)

    as a fixed point problem, namely u=Au, where the operator A will be defined later; then applying fixed point theorems such as Banach's and Picard's contraction principles.

    Let us consider the following boundary value problem:

    {αΔu+u=f,on ΩuN=0,onΩ, (2.2)

    where uH1(Ω) and fL2(Ω). This problem can be written as follows:

    {Δu=1α(fu)on ΩuN=0onΩ (2.3)

    Our main result is stated as follows:

    Theorem 2.1. Let fL2(Ω) and assume that

    0<1α(Δ)1L(L2(Ω))<1.

    Then the problem (2.3) has a unique solution u0 in H1(Ω).

    To proof Theorem 2.1, we need Picard's Theorem.

    Theorem 2.2. (Picard's Theorem)([12]) Let (X,d) be a complete metric space and let T:XX be a strict contraction. Then T has a unique fixed point u0=Tu0X. Furthermore, for any vX, the sequence (Tn(v)) converges to u0 as n+ where T0(v)=v and

    Tn+1(v)=T(Tn(v)),  vX,  n{0,1,2,}.

    Remark 2.3. Theorem 2.2 allows us to prove the existence and uniqueness of the solution and to give an approximation of this solution at the same time.

    Our proof for Theorem 2.1 is based on a fixed point approach where we define a compact operator such that assumptions of Theorem 2.2 will be satisfied.

    Proof. Let us consider the operator A defined from L2(Ω) to L2(Ω) such that:

    Au=1α(Δ)1(fu). (2.4)

    One can see that a fixed point of the operator A satisfies (2.3). Hence to solve (2.3) we search fixed points of the operator A. It is well-known [12] that the linear operator (Δ)1 is continuous from L2(Ω) to H10, it follows from the compact embedding i:H10L2(Ω) that i(Δ)1 is compact from L2(Ω) to L2(Ω). Then the linear operator (Δ)1:L2(Ω)L2(Ω) is continuous. Now, we can prove that under assumptions of Theorem 2.1, the operator A is a strict contraction on L2(Ω). Indeed, for every u1,u2L2(Ω), we obtain

    Au1Au2L2=1α(Δ)1(fu1)(Δ)1(fu2)L2=1α(Δ)1(fu1f+u2)L2=1α(Δ)1(u2u1)L21α(Δ)1L(L2(Ω))u1u2L2(Δ)1L(L2(Ω))u1u2L2ku1u2L2,

    where k=1α(Δ)1L(L2(Ω)).

    As k<1, then A is a strict contraction and the conclusion follows from Picard's Theorem which confirms that the operator A has a unique fixed point u0L2(Ω)H1(Ω). Hence, the problem (2.1) has a unique solution in H1(Ω).

    Remark 2.4. This theorem allows us to choose a good value of α which gives the right approximation of the restored image.

    Unfortunately, the presence of the Laplacian does not lead to a good restoration of the degraded image, given that the Laplacian is a very strong smoothing operator and does not preserve the edges. So the obtained image does not contain noise but it is very blurry. For this reason, several authors have sought to find regularization terms which allow the contours to be preserved. In this direction, authors [1] proposed another term of regularization and the study the following energy:

    J(u)=12Ω|fφu|2dx + αΩϕ(|u|)dx,  α>0,  uV (2.5)

    where V={uL2(Ω), uL1(Ω)} is a suitable space and u:ΩR2R, ϕ is chosen so that the smoothing is the same in all directions in places where the gradient is low and at the same time controls the smoothing in the neighborhood of contours in order to preserve them. If u is a minimum point to J(u), then it satisfies the Euler-Lagrange equation:

    φφuφfλdiv(ϕ(u)u.u)=0. (2.6)

    This equation cannot be solved in the space V because it is not reflexive. Authors in [1] calculated the relaxed functional of (2.5) in the BVw and then used direct method of the calculus of variations to prove that the relaxed problem has a unique solution and then deduced the existence of a unique solution for the original problem. Recall that BVw denotes the space of functions of bounded variation endowed with weak topology.

    In [13], authors studied the problem

    div(ψ(u))=λg(x)up2u,xRN, (2.7)

    where 1<p<N, N3 and g(x) is a positive and measurable function. Using Mountain Pass Theorem, it was proven that under suitable conditions, the problem (2.7) admits a weak solution in W1,p(RN).

    Inspired by [1,13], we seek to show that the problem

    div(ψ(u))=F(u),   uW1,20(Ω)

    has a weak solution under some assumptions on F and ψ, where Ω is an open bounded set ΩRN.

    Let us consider the Hilbert space H10(Ω) endowed with the scalar product

    <u,v>H10=<u,v>L2(Ω)=Ωu.v dx

    and the associated norm

    uH10=(Ω|u(x)|2dx)12=uL2.

    Now, let J(u) be the functional defined by

    J(u)=12(uu02H10u02H10)αΩϕ(|u|)dx,  uH10(Ω),  α>0 (2.8)

    where ϕ is strictly convex and nondecreasing on R+ into R+ with

    ϕ(0)=0   and   ϕ(0)=0,
    thereexistsc>0, b0,  csbϕ(s)cs,  s>0 (2.9)

    and

    thereexistsψH10(Ω)  suchthat ψH10<1. (2.10)

    We also assume that:

     M>0  suchthat ϕ(s)sM,  s>0. (2.11)

    The functional J(u) in (2.8) is well-defined and is class C1 (see [12]). Using (2.8), we obtain the following:

    J(u)v=Ω(uu0).vdxαΩϕ(|u|)|u|u.v dx.

    Then we have

    J(u)v=<uu0,v>H10αΩϕ(|u|)|u|u.v dx.

    Let z be such that z=ϕ(|u|)|u|u, then

    J(u)v=<uu0,v>H10αΩzu,

    hence

    J(u)v=<uu0,v>H10α<z,v>H10,

    it follows that

    J(u)=(uu0)αz.

    If u is such that J(u)=0 that is u is a critical point for J in other words to solve the equation J(u)=0, we seek for critical points for J. An important theorem in this area is a minimization theorem named Mountain Pass Theorem.

    Theorem 2.5. (Mountain Pass Theorem [14,15]) Let H be a Banach space and JC1(H,R) satisfies the Palais-Smale condition. Assume J(0)=0 and thereexist positive numbers ρ and δ such that:

    1) J(u)δ if u=ρ,

    2) There exists ϑH such that ϑ>ρ and J(ϑ)<δ.

    Then μ is a critical value of J with μδ, where

    μ=minAΓmaxuAJ(u),

    and

    Γ={γ([0,1]): γC([0,1],H), γ(0)=0, γ(1)=ϑ}.

    Definition 2.6. (Palais-Smale condition)[15,16,17] Let JC1(H,R). If any sequence (un)H for which (J(un)) is bounded in R and J(un)0 as n+ in H possesses a convergent subsequence, then we say that J satisfies Palais-Smale condition.

    Our second main result is the following theorem:

    Theorem 2.7. Under assumptions (2.9)–(2.11), the equation J(u)=0 admits at least a nontrivial solution.

    Proof. We will show that all conditions of Theorem 2.5 are satisfied.

    1) It can be easily seen that J(0)=0.

    2) J(u) satisfies the Palais-Smale condition. Indeed, let (un) be a sequence H10(Ω) such that J(un) is bounded and J(un)0 in H1(Ω) which is the dual space of H10(Ω), we prove that (un) admits a convergent subsequence in H10(Ω). Since J(un) is bounded, there exists K>0 such that

    KJ(un)12un2H10un,u0αΩc|un|dx12un2H10unH10u0H10αcunL112un2H10unH10u0H10αηcunL212un2H10unH10u0H10αηcunH10.

    As Ω is bounded, we use Cauchy-Schwartz inequality and the continuous embedding of L2(Ω) in L1(Ω). (un) is bounded in the reflexive space H10(Ω). Then there exist a subsequence unk and w such that unkw in H10(Ω) as nk+. Using the compact embedding H10(Ω) in L2(Ω), we have unkw in L2(Ω) as nk+. Now, we have to show that unkw in L2(Ω) as nk+ to deduce that unkw in H10(Ω) as nk+. From the definition of weak convergence, we have

    unkw0  in  H10(Ω)

    and

    limnk+J(unkw),(unkw)0.

    On the other hand, by the following statements

    0=limnk+J(unk)(unkw)=limnk+Ω(unku0)(unkw) dx   αlimnk+Ωϕ(|(unk)|)|(unk)|(unk).(unkw)dx,

    this last result cannot be true unless

    (unkw)0 in L2(Ω),

    i.e., (unk)w in L2(Ω). Indeed, if (unkw) L2(Ω), then

    limnk+Ω(unku0)(unkw) dx=0

    when (unk)w in L2(Ω). On the other hand, by (2.11) and the fact that unkH10(Ω), we have

    ϕ(|(unk)|)|(unk)|(unk)in L2(Ω).

    Then,

    limnk+Ωϕ(|(unk)|)|(unk)|(unk).(unkw)dx=0

    when (unk)w in L2(Ω).

    3) Let η>0 be the constant of the continuous embedding of L2(Ω) in L1(Ω) and

    ρ>2(u0H10+αηc).

    Then there exists δ>0 such that if u=ρ, then J(u)>δ. In fact,

    J(u)12u2H10u0H10uH10αΩc|u|dx12u2H10u0H10uH10αcηuL212u2H10u0H10uH10αcηuH10uH10[12uH10u0H10αcη]ρ(12ρu0H10αcη)δ,

    with δ=ρ(12ρu0H10αcη).

    4) Now, we will show that ϑH10(Ω) such that ϑ>ρ and J(ϑ)<δ. Putting ϑ=λψ with λ>0 and

    ψ, u0H10+αcψL1>12λ,

    then we have

    J(ϑ)12λ2ψ2H10λψ,u0H10+αΩ(c|λψ|+b) dx12λ2ψ2H10λψ,u0H10λαcψL1+bα|Ω|12λ2ψ2H1012λ2+bα|Ω|12λ2[ψH101+αb|Ω|2λ2]

    and thus J(ϑ) as λ+. Since δ>0, it is obvious that J(ϑ)<δ.

    The functional J satisfies the hypotheses of Mountain Pass Theorem, so J has a critical point.

    The authors express their gratitude to the anonymous referees for their helpful suggestions and corrections.

    The authors declare there is no conflicts of interest.



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