In this paper, we study the existence of entire positive solutions for the k-Hessian type equation
Sk(D2u+αI)=p(|x|)fk(u), x∈Rn
and system
{Sk(D2u+αI)=p(|x|)fk(v), x∈Rn,Sk(D2v+αI)=q(|x|)gk(u), x∈Rn,
where D2u is the Hessian of u and I denotes unit matrix. The arguments are based upon a new monotone iteration scheme.
Citation: Shuangshuang Bai, Xuemei Zhang, Meiqiang Feng. Entire positive k-convex solutions to k-Hessian type equations and systems[J]. Electronic Research Archive, 2022, 30(2): 481-491. doi: 10.3934/era.2022025
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In this paper, we study the existence of entire positive solutions for the k-Hessian type equation
Sk(D2u+αI)=p(|x|)fk(u), x∈Rn
and system
{Sk(D2u+αI)=p(|x|)fk(v), x∈Rn,Sk(D2v+αI)=q(|x|)gk(u), x∈Rn,
where D2u is the Hessian of u and I denotes unit matrix. The arguments are based upon a new monotone iteration scheme.
Consider the existence of entire positive k-convex solutions to the following k-Hessian type equation
Sk(D2u+αI)=p(|x|)fk(u), x∈Rn, | (E) |
and system
{Sk(D2u+αI)=p(|x|)fk(v), x∈Rn,Sk(D2v+αI)=q(|x|)gk(u), x∈Rn, | (S) |
where k∈{1,2,…,n}, α≥0 is a constant, I is the identity function and p,q are continuous functions on [0,+∞). Letting D2u=(∂2u∂xi∂xj) denote the Hessian of u∈C2(Rn) and λi (i∈{1,2,…,n}) denote the eigenvalues of D2u, then
Sk(D2u+αI)=∑1≤i1<...<ik≤n1≤j1<...<jk≤n1k!δi1,i2,...,ikj1,j2,...,jk(λi1+α)(λi2+α)...(λik+α), |
where δi1,i2,...,ikj1,j2,...,jk is the generalized Kronecker symbol, is the k-Hessian type operator. When α=0, Sk(D2u) is the standard k-Hessian operator.
Denote
Γk:={λ∈Rn:Sj(λ)>0,1≤j≤k}. |
We call a function u∈C2(Rn) k-convex in Rn if λ(D2u(x)+αI)∈Γk for all x∈Rn.
In particular,
S1(D2u+αI)=n∑i=1λi=Δu;Sn(D2u+αI)=n∏i=1λi=det(D2u+αI). |
The k-Hessian equation is fully nonlinear PDEs for k≠1 (see Urbas [1] and Wang [2]), and there are many important applications in fluid mechanics, geometric problems and other applied subjects. Many authors have demonstrated increasing interest in k-Hessian equations by different methods, for instance, see ([3,4,5,6,7,8,9]) and the references cited therein([10,11,12,13,14,15]). In particular, problem (E) reduces to the problems studied by Keller [16] and Osserman [17] when k=1, p(|x|)=1 on Rn and f:[0,∞)→[0,∞) is continuous and increasing. The authors studied a necessary and sufficient condition
∫∞1dt√2F(t)=∞, F(t)=∫t0f(s)ds |
for the existence of entire large positive radial solutions to (E). When k=1, f(u)=uγ (γ∈(0,1]) and p:[0,∞)→[0,∞) is continuous, Lair and Wood [18] showed that (E) admits infinitely many entire large positive radial solutions if and only if
∫∞0rp(r)dr=∞. |
For the case k=1, system (S) reduces to the following problem
{Δu=p(|x|)f(v), x∈Rn,Δv=q(|x|)g(u), x∈Rn. | (1.1) |
Lair and Wood [19] analyzed the existence and nonexistence of entire positive radial solutions to Eq (1.1) when f(v)=vβ, g(u)=uγ (0<β≤γ). For the further results, we can see [20,21,22,23] and the reference therein.
When α=0, Zhang and Zhou [24] considered the existence of entire positive k-convex solutions to problem (E) and system (S).
For the case k=n, Zhang and Liu [25] studied the existence of entire radial large solutions for a Monge-Ampère type equation
det(D2u)−αΔu=a(|x|)f(u), x∈Rn | (1.2) |
and system
{det(D2u)−αΔu=a(|x|)f(v), x∈Rn,det(D2v)−βΔv=b(|x|)g(u), x∈Rn. | (1.3) |
Their results have been improved by Covei [26].
Recently, when p(|x|)≡1 on Rn, Dai [27] showed that there exists a subsolution u∈C2(Rn) of (E) if and only if
∫∞(∫τ0f(t)dt)−1k+1dτ=∞ |
holds.
Motivated by these works mentioned above, in this paper we will obtain some new results on the existence of entire positive k-convex radial solutions for equation (E) and system (S). The arguments are based upon a new monotone iteration scheme.
Let α0 denote a positive constant. In the following, we always suppose that
α0>nk(nCk−1n−1k)1kα=nk(Ckn)1kα. | (1.4) |
We give the following conditions:
(f1) f, g :[0, ∞)→ (α0,∞) are continuous and nondecreasing;
(f2) p, q :[0, ∞)→ (0,∞) are continuous and nondecreasing.
Define
P(∞):=limr→∞P(r), P(r):=∫r0(tk−nC0∫t0sn−1p(s)ds)1kdt, r≥0; | (1.5) |
Q(∞):=limr→∞Q(r), Q(r):=∫r0(tk−nC0∫t0sn−1q(s)ds)1kdt, r≥0, | (1.6) |
where
C0=Ck−1n−1k. |
For an arbitrary a>0, we also define
H1a(∞):=limr→∞H1a(r), H1a(r):=∫radτf(τ), r≥a; | (1.7) |
H2a(∞):=limr→∞H2a(r), H2a(r):=∫radτf(τ)+g(τ), r≥a, | (1.8) |
and we see that
H′1a(r)=1f(r)>0, H′2a(r)=1f(r)+g(r)>0, ∀r>a, |
and H1a,H2a admit the inverse functions H−11a and H−12a on [0,H1a(∞)) and [0,H2a(∞)) respectively.
The main results of this paper can be stated as follows.
Theorem 1.1. Suppose that (f1) and (f2) hold. If α=0, then Eq (E) admits an entire positive k-convex radial solution u∈C2(Rn) satisfying
a+α0P(r)≤u≤H−11a(P(r)), ∀r≥0. |
Moreover, if P(∞)=∞ and H1a(∞)=∞, then limr→∞u(r)=∞; if P(∞)<H1a(∞)<∞, then u is bounded.
If α>0 and p(|x|)≥1, then Eq (E) admits an entire positive k-convex radial solution u∈C2(Rn) satisfying
a+α0P(r)−α2r2≤u≤H−11a(P(r)), ∀r≥0. |
If further suppose H1a(∞)=∞, then limr→∞u(r)=∞.
Theorem 1.2. Suppose that (f1) and (f2) hold. If α=0, then system (S) admits an entire positive k-convex radial solution (u,v)∈C2(Rn)×C2(Rn) satisfying
a2+α0P(r)≤u≤H−12a(P(r)+Q(r)), ∀r≥0;a2+α0Q(r)≤v≤H−12a(P(r)+Q(r)), ∀r≥0. |
Moreover, if P(∞)=∞=Q(∞) and H2a(∞)=∞, then limr→∞u(r)=limr→∞v(r)=∞; if P(∞)+Q(∞)<H2a(∞)<∞, thenu and v are bounded.
If α>0 and p(|x|)≥1, q(|x|)≥1, then system (S) admits an entire positive k-convex radial solution (u,v)∈C2(Rn)×C2(Rn) satisfying
a2+α0P(r)−α2r2≤u≤H−12a(P(r)+Q(r)), ∀r≥0;a2+α0Q(r)−α2r2≤v≤H−12a(P(r)+Q(r)), ∀r≥0. |
If further suppose H2a(∞)=∞, limr→∞u(r)=limr→∞v(r)=∞.
For convenience, we give some lemmas for the radial functions before proving the main results.
Let r=|x|=√x21+...+x2n and BR:={x∈Rn:|x|<R} for R∈(0,∞].
Lemma 2.1. (Lemma 2.1, [25]) Suppose that φ∈C2[0,R) with φ′(0)=0. Then, for u(x)=φ(r), we have u(x)∈C2(BR), and the eigenvalues of D2u+αI are
λ(D2u+αI)={(φ″(r)+α,φ′(r)r+α,...,φ′(r)r+α), r∈(0,R),(φ″(0)+α,φ″(0)+α,...,φ″(0)+α), r=0, |
and so
Sk(D2u+αI)={Ck−1n−1(φ″(r)+α)(φ′(r)+αr)k−1rk−1+Ckn−1(φ′(r)+αr)krk, r∈(0,R),Ckn(φ″(0)+α)k, r=0. |
By Lemma 2.1, we can conclude that u(x)=φ(r) is a C2 radial solution of (E) if and only if φ(r) satisfies
Ck−1n−1(φ″(r)+α)(φ′(r)+αr)k−1rk−1+Ckn−1(φ′(r)+αr)krk=p(r)fk(φ(r)), r∈(0,R). | (2.1) |
Lemma 2.2. Suppose that (f1) and (f2) hold. For any positive number a, let φ∈C[0,R)∩C1(0,R) be a solution of the Cauchy problem
{φ′(r)=(rk−nC0∫r0sn−1p(s)fk(φ(s))ds)1k−αr, r>0,φ(0)=a>0. | (2.2) |
Then φ∈C2[0,R), and it satisfies (2.1) with φ′(0)=0.
Proof. Firstly, we have
φ′(0)=limr→0φ(r)−φ(0)r−0=limr→0φ′(r)=limr→0(rk−nC0∫r0sn−1p(s)fk(φ(s))ds)1k−αr=0. |
Since
limr→0φ′(r)=limr→0(rk−nC0∫r0sn−1p(s)fk(φ(s))ds)1k−αr=0=φ′(0). |
This shows that φ(r)∈C1[0,R).
Secondly,
φ″(0)=limr→0φ′(r)−φ′(0)r−0=limr→0(rk−nC0∫r0sn−1p(s)fk(φ(s))ds)1k−αrr=limr→0(k−nC0rk−n−1∫r0sn−1p(s)fk(φ(s))ds+rk−1C0p(r)fk(φ(r))rk)1k−α=(1nC0p(0))1kf(φ(0))−α. |
It is easy to know that φ(r)∈C2(0,R) for r∈(0,R). By calculating,
limr→0φ″(r)=limr→0k−nkr−nk(∫r01C0p(s)fk(φ(s))sn−1ds)1k+limr→01kC0rk−nk(∫r01C0p(s)fk(φ(s))sn−1ds)1k−1rn−1p(r)fk(φ(r))−α=k−nk(1nC0p(0))1kf(φ(0))+nk(1nC0p(0))1kf(φ(0))−α=(1nC0p(0))1kf(φ(0))−α. |
Hence, φ(r)∈C2[0,R). And by direct calculation, we can prove that φ(r) satisfies (2.1).
Remark 2.3. When p(r)≡1, Lemma 2.2 is consistent with Lemma 2.3 in [25].
Lemma 2.4. (Lemma 2.2, [25]) Suppose that (f1),(f2) hold and φ(r)∈C2[0,R) satifies (2.1) with φ′(0)=0. Then φ′(r)≥0 and φ″(r)+α>0.
Proof. From (2.1), we have
Ck−1n−1(rn−k(φ′(r)+αr)k)′=krn−1p(r)fk(φ(r)). |
Noticing that φ′(0)=0 and intergrating from 0 to r, combining with (1.7), we have
φ′(r)=(rk−nC0∫r0sn−1p(s)fk(φ(s))ds)1k−αr. |
If α=0, then we can easily prove that φ′(r)>0; if α>0 and p(|x|)>1, then we have
φ′(r)≥α0(rk−nC0∫r0sn−1ds)1k−αr>(nC0)−1knk(nC0)1kαr−αr=α(nk−1)r≥0. |
On the other hand, by calculating, for 0<s<r, we have
φ″(r)+α=k−nkr−nk(∫r01C0p(s)fk(φ(s))sn−1ds)1k+1kC0rk−nk(∫r01C0p(s)fk(φ(s))sn−1ds)1k−1rn−1p(r)fk(φ(r))=r−nk(∫r01C0p(s)fk(φ(s))sn−1ds)1k−1[k−nk∫r01C0p(s)fk(φ(s))sn−1ds+1kC0rnp(r)fk(φ(r))]≥r−nk(∫r01C0p(s)fk(φ(s))sn−1ds)1k−1[k−nk1C0p(r)fk(φ(r))rnn+1kC0rnp(r)fk(φ(r))]=r−nk(∫r01C0p(s)fk(φ(s))sn−1ds)1k−1[1nC0rnp(r)fk(φ(r))]>0. | (2.3) |
This gives the proof of Lemma 2.4.
Remark 2.5. When p(r)≡1, Lemma 2.4 is consistent with Lemma 2.2 in [25].
In this section, we prove Theorems 1.1 and 1.2.
Proof of Theorem 1.1. Firstly, we consider the equations
Ck−1n−1(u″(r)+α)(u′(r)+αr)k−1rk−1+Ckn−1(u′(r)+αr)krk=p(r)fk(u(r)), r>0, | (3.1) |
u′(r)=(rk−nC0∫r0sn−1p(s)fk(u(s))ds)1k−αr, r>0, u(0)=a, | (3.2) |
and
u(r)=a+∫r0(tk−nC0∫t0sn−1p(s)fk(u(s))ds)1kdt−α2r2, r≥0. | (3.3) |
Apparently, solutions in C[0,∞) to (3.3) are solutions in C[0,∞)∩C1(0,∞) to (3.2).
Let {um}m≥1 be the sequences of positive continuous functions defined on [0,∞) by
u0(r)=a, um(r)=a+∫r0(tk−nC0∫t0sn−1p(s)fk(um−1(s))ds)1kdt−α2r2, r≥0. |
Obviously, for all r≥0 and m∈N, we have
um(r)=a+∫r0(tk−nC0∫t0sn−1p(s)fk(um−1(s))ds)1kdt−α2r2≥a+α0∫r0(tk−nC0∫t0sn−1p(s)ds)1kdt−α2r2≥a+α0P(r)−α2r2. |
Therefore, um(r)≥a, and u0(r)<u1(r). Since (f1) holds, we have u1(r)<u2(r) for r≥0. According to the above reasons, we obtain that the sequences {um} is increasing on [0,∞). Also, we obtain by (f1) and (f2) that for each r>0
u′m(r)=(rk−nC0∫r0sn−1p(s)fk(um−1(s))ds)1k−αr≤f(um(r))(rk−nC0∫r0sn−1p(s)ds)1k−αr≤f(um(r))P′(r). |
Therefore,
∫um(r)a1f(τ)dτ≤P(r), r>0. |
This shows that
H1a(um(r))≤P(r), ∀r≥0, | (3.4) |
and
um(r)≤H−11a(P(r)), ∀r≥0. | (3.5) |
It follows that the sequences {um}, {u′m} are bounded on [0,R0] for an arbitrary R0>0. By Arzelˊa-Ascoli theorem, {um} has subsequences converging uniformly to u on [0,R0]. Since {um} is increasing on [0,∞), we see that {um} itself converges uniformly to u on [0,R0]. By arbitrariness of R0 and Lemma 2.2, we get that u is an entire positive k-convex radial solution to (E), and u satisfies
a+α0P(r)−α2r2<u(r)≤H−11a(P(r)), ∀r≥0. | (3.6) |
If α=0, by (3.6), it is easy to obtain that if P(∞)=∞ and H1a(∞)=∞, then limr→∞u(r)=∞; if P(∞)<H1a(∞)<∞, then u is bounded. If α>0, combining the fact that p(|x|)≥1, α0>nk(Ckn)1kα and H1a(∞)=∞, it is obvious that limr→∞u(r)=∞. This finishes the proof of Theorem 1.1.
Remark 3.1. Theorem 1.1 generalizes Theorem 1.1 with α>0 in [24]. In the case α>0, since P(∞)=∞ for the positivity of u, it is difficult to ensure if there is bounded positive entire solution of (E).
Proof of Theorem 1.2. Consider the following systems
{Ck−1n−1(u″(r)+α)(u′(r)+αr)k−1rk−1+Ckn−1(u′(r)+αr)krk=p(r)fk(v(r)), r>0,Ck−1n−1(v″(r)+α)(v′(r)+αr)k−1rk−1+Ckn−1(v′(r)+αr)krk=q(r)gk(u(r)), r>0, |
and
{u(r)=a2+∫r0(tk−nC0∫t0sn−1p(s)fk(v(s))ds)1kdt−α2r2, r≥0,v(r)=a2+∫r0(tk−nC0∫t0sn−1q(s)gk(u(s))ds)1kdt−α2r2, r≥0. |
Let {um}m≥1 and {vm}m≥1 be the sequences of positive continuous functions defined on [0,∞) by
{v0=a2,um(r)=a2+∫r0(tk−nC0∫t0sn−1p(s)fk(vm−1(s))ds)1kdt−α2r2, r≥0,vm(r)=a2+∫r0(tk−nC0∫t0sn−1q(s)gk(um(s))ds)1kdt−α2r2, r≥0. |
Similarly, for all r≥0 and m∈N, when m≥1, we have
um(r)>a2+α0P(r)−α2r2;vm(r)>a2+α0Q(r)−α2r2. |
Therefore, um(r)≥a2, vm(r)≥a2 and v0(r)<v1(r). Since f, g are continuous and nondecreasing, we have u1(r)<u2(r), ∀r≥0, and v1(r)<v2(r), ∀r≥0. According to the above reasons, we obtain that the sequences {um} and {vm} are increasing on [0,∞).
Moreover, for r>0, by (f1) and (f2), one can prove that
u′m(r)≤(f(vm(r)+um(r))+g(vm(r)+um(r)))P′(r);v′m(r)≤(f(vm(r)+um(r))+g(vm(r)+um(r)))Q′(r), |
and
u′m(r)+v′m(r)≤[f(vm(r)+um(r))+g(vm(r)+um(r))](P′(r)+Q′(r)). |
Therefore,
∫um(r)+vm(r)a1f(τ)+g(τ)dτ≤P(r)+Q(r), r>0, |
which shows that
H2a(um(r)+vm(r))≤P(r)+Q(r), ∀r≥0, |
and
um(r)+vm(r)≤H−12a(P(r)+Q(r)), ∀r≥0. |
It so follows that the sequences {um}, {u′m} and {vm}, {v′m} are bounded on [0,R0] for an arbitrary R0>0. By Arzelˊa-Ascoli theorem, {um} and {vm} have subsequences converging uniformly to u and v respectively on [0,R0]. Since {um}, {vm} are increasing on [0,∞), we see that {um} itself converges uniformly to u on [0,R0], so is {vm}. By arbitrariness of R0 and Lemma 2.2, we get that (u,v) is an entire positive k-convex radial solution to (S).
The rest proof is similar to that of Theorem 1.1. So we omit it here.
In this paper, we use a new monotone iteration scheme to obtain some new existence results of entire positive solutions for a k-Hessian type equation and system.
S. Bai, X. Zhang and M. Feng are partially supported by the Beijing Natural Science Foundation of China (1212003).
The authors declare there is no conflict of interest.
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3. | Haitao Wan, Yongxiu Shi, Sharp conditions for the existence of infinitely many positive solutions to q-k-Hessian equation and systems, 2024, 32, 2688-1594, 5090, 10.3934/era.2024234 | |
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Positive Radial Solutions to the Double Singular ki -Hessian System: Existence, Multiplicity and Dependence on a Parameter,
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