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On the existence of solutions for the Frenkel-Kontorova models on quasi-crystals

  • This article focuses on recent investigations on equilibria of the Frenkel-Kontorova models subjected to potentials generated by quasi-crystals.

    We present a specific one-dimensional model with an explicit potential driven by the Fibonacci quasi-crystal. For a given positive number θ, we show that there are multiple equilibria with rotation number θ, e.g., a minimal configuration and a non-minimal equilibrium configuration. Some numerical experiments verifying the existence of such equilibria are provided.

    Citation: Jianxing Du, Xifeng Su. On the existence of solutions for the Frenkel-Kontorova models on quasi-crystals[J]. Electronic Research Archive, 2021, 29(6): 4177-4198. doi: 10.3934/era.2021078

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  • This article focuses on recent investigations on equilibria of the Frenkel-Kontorova models subjected to potentials generated by quasi-crystals.

    We present a specific one-dimensional model with an explicit potential driven by the Fibonacci quasi-crystal. For a given positive number θ, we show that there are multiple equilibria with rotation number θ, e.g., a minimal configuration and a non-minimal equilibrium configuration. Some numerical experiments verifying the existence of such equilibria are provided.



    We consider the Frenkel-Kontorova models with quasi-periodic potentials. One may refer to [6] for several physical interpretations of such models.

    In order to give a unified picture of the known results, let's take the one-dimensional quasi-crystals case for example (see [11] for more advanced studies on general quasi-crystals). Frenkel-Kontorova models describe the dislocations of particles deposited over a substratum given by the quasi-crystals (see [6]). That is, we model the position of the i-th particle by xiR and the total energy is formally composed of the summation over all iZ of spring potential 12(xixi+1)2 between the nearest neighbors i-th and the (i+1)-th particles, and the potential V(xi) from interaction of the i-th particle with the quasi-periodic substratum:

    S((xi)iZ):=iZ[12(xixi+1)2+V(xi)].

    In this article, we are concerned with the case that the potential function V is a pattern equivariant function (see Definition 2.11 for details) and aim to discuss existing approaches to prove the existence of equilibria. Related problems of finding equilibria generated by other types of quasi-periodic functions are discussed in [13,14] and references therein. [10] presents an example to show the non-existence of bounded correctors in the setting of homogenization.

    The aperiodicity will bring us difficulties such as loss of compactness and less results are known for the quasi-periodic case than for the periodic one. We now recall the existing results in the literature. In [3,16], under the assumptions that the potential function is large enough, the authors use the idea of the anti-integrable limits to obtain multiple equilibria with any prescribed rotation number or without any rotation numbers. This approach also works for higher dimensional generalization of the quasi-periodic Frenkel-Kontorova model but requires that the corresponding system is far away from the integrable case.

    In another direction, [7] considers the one-dimensional Fibonacci quasi-crystals without extra assumption on whether the system is integrable or not, and mainly uses topological methods to establish the existence of the minimal configurations with any given rotation number. Here it is rather essential that the configuration space is one dimension. Note that the minimal configuration is a special equilibrium with extra properties. One may refer to [8] for other methods to search minimal configurations.

    In this article, we construct an explicit potential V driven by the Fibonacci quasi-crystals. Our goal here is to provide several approaches to tackle variational problem for the Frenkel-Kontorova models. More precisely, we aim to find minimal configurations and non-minimal equilibrium configurations of the Frenkel-Kontorova model with quasi-periodic potentials.

    In order to give a simple and self-contained proof, we fix at the beginning a positive number θ=(3τ+1)/2 where τ=(5+1)/2=1.618. We state the main result as follows:

    Theorem 1.1. For the Frenkel-Kontorova model with the potential V (which is defined in Section 2.3),

    (i) there exists a minimal configuration with the rotation number θ,

    (ii) there exists a non-minimal equilibrium configuration with the rotation number θ.

    Remark 1. (1) We choose θ=(3τ+1)/2 for computational convenience. In fact, Theorem 1.1 is valid for any θR.

    (2) Related results could also hold for other one-dimensional quasi-periodic tilings.

    But so far, analogues of the above result in higher dimensions are not yet known. We hope to get some inspiration from the specific example and corresponding numerical simulations. For numerical computations of minimal configurations, one may refer to [2,15,5].

    Organization of the article. In Section 2, we introduce some necessary fundamentals about quasi-crystals and the variational problem for the Frenkel-Kontorova models. In particular, we give an example of the quasi-crystals, the Fibonacci chain, and an example of the Frenkel-Kontorova models with quasi-periodic potentials.

    Section 3 is devoted to the proof of Theorem 1.1. Numerical simulations searching for equilibrium configurations are provided here.

    In fact, in Section 3.1, we obtain the minimal configurations for the Frenkel-Kontorova models on one-dimensional Fibonacci quasi-crystals with slight modifications compared with those in [7]. Thus we finish the proof of item (i) in Theorem 1.1. Of course, the KAM circles are minimizers.

    We apply the idea of anti-integrable limits to prove the existence of equilibrium configurations of type h in Section 3.2. Then we prove that these equilibrium configurations are non-minimal, which completes the proof of item (ii) in Theorem 1.1.

    We recall several standard notions of quasi-crystals in Section 2.1. In Section 2.2, we introduce the minimal and equilibrium configurations of the variational problem for the Frenkel-Kontorova models. Particularly, in Section 2.3, we state the definition of pattern equivariant potential which we take as the potential in the variational problem, and finally an example is provided.

    In the d-dimensional Euclidean space Rd, the open ball centered at x with radius r is denoted by Br(x). The closure of a set A and its cardinality are denoted by ¯A and Card(A), respectively. The Lebesgue measure of a Lebesgue-measurable set A is denoted by λ(A). Countable subsets in Rd are called point sets.

    A point set ΛRd is uniformly discrete if there exists r>0 such that (x+Br(0))(y+Br(0))= holds for all distinct x,yΛ, where the sign "+" is the Minkowski sum. A point set Λ is relative dense if there exists R>0 such that Λ+¯BR(0)=Rd.

    Definition 2.1 (Delone sets). A point set ΛRd is Delone if it is both uniformly discrete and relative dense.

    A cluster of the point set Λ is the intersection KΛ for some compact set KRd. In particular, if the compact set K is convex, we call such cluster KΛ a patch. Two clusters P1 and P2 are said to be equivalent if there exists a vector vRd such that P1+v=P2.

    Definition 2.2 (finite local complexity). A point set ΛRd is of finite local complexity if for any M>0, the point set Λ possesses only finitely many equivalence classes of clusters with diameters smaller than M, where the diameter of a subset ARd is supx,yA|xy|.

    Definition 2.3 (repetitive). A point set ΛRd is repetitive if for any cluster PΛ, there exists R>0 such that any ball with radius R contains a cluster equivalent to P.

    Definition 2.4 (non-periodic). A point set ΛRd is non-periodic if t+ΛΛ for any tRd{0}.

    Definition 2.5 (quasi-crystal). A point set ΛRd is called a quasi-crystal if it is repetitive, non-periodic and of finite local complexity.

    Let KRd be a compact set and fix a cluster P=ΛK of a point set Λ. Given a ball Br(a), we consider the quantity

    Card{tBr(a)(t+Λ)K=P}λ(Br(a)).

    If the above quantity converges as r+ with aRd fixed, we call the limit the absolute frequency of the cluster P in Λ at a and denote it by Freqa(P). If the convergence is uniform in a, the limit is called the uniform absolute frequency of P and is denoted by Freq(P).

    In this section, we will provide the Fibonacci chain as an example of one-dimensional quasi-crystals whose construction will be divided into the following three steps.

    Step 1. Construct a one-sided Fibonacci word. Consider a two-letter alphabet {a,b} and the free group a,b generated by letters a and b. A substitution rule ρ on {a,b} is an endomorphism of a,b. Specifically, we consider the substitution rule

    ρ:aabba

    and define a sequence (u(i))iZ+ of finite words by

    u(i+1)=ρ(u(i))i1 with u(1)=a. (1)

    The iterating process can be illustrated as follows:

    aρabρabaρabaabρabaababaρabaababaabaabρ.

    It can be directly derived from the definition by induction that

    u(i+2)=u(i+1)u(i) for all i1. (2)

    Thus the sequence (u(i))iZ+ converges to an infinite word

    u:=u0u1u2:=abaababaabaab

    as i+ in the product topology of {a,b}Z+, where u0,u1,,uj,{a,b}. The limit u is a fixed point of ρ and is called the one-sided Fibonacci word.

    Remark 2. Notice that the length of u(i) is the Fibonacci number fi defined by f1=1, f2=2 and fi+2=fi+1+fi for all i1. As a convention, let f0=1,f1=0 and τ=(1+5)/2. It is easy to show that

    fi=τi+1(1τ)i+15. (3)

    Furthermore, the number of times the letter a appears in u(i) is fi1 and the number of times the letter b appears in u(i) is fi2.

    Step 2. Construct a two-sided Fibonacci word. Define a sequence (w(i))iZ+ of finite words by w(i)=u(i)|u(i):

    a|aρab_|abρaba_|abaρabaab_|abaabρabaababa_|abaababaρabaababaabaab_|abaababaabaabρ

    where the vertical line indicates the reference point. In fact, we can get palindromes by eliminating the last two letters of u(i) for all i3, see [1]. Thus we have

    w(i)={b1a1~u(i)ba_|u(i) if i is odd, a1b1~u(i)ab_|u(i) if i is even, 

    for all i3, where ~u(i) denotes the reversal of u(i). Furthermore (w(i))iZ+ has two limit points that are 2-periodic points under the substitution ρ:

    ˜uba_|u:=abaababaabaababaababa_|abaababaabaababaababa˜uab_|u:=abaababaabaababaabaab_|abaababaabaababaababa.

    That is, the two bi-infinite words are fixed points of ρ2. Here we only consider the first bi-infinite word whose underlined position is ba_, and we denote it by

    w:=w3w2w1|w0w1w2w3:=˜uba_|u=ababa_|abaab

    where wj{a,b} for all jZ.

    Step 3. Obtain a point set by the bi-infinite word as a quasi-crystal. Let w[k,l] be the finite subword of w from position k to l where k,lZ and kl. Note that w[k,k]=wk{a,b}. We then define an assignment function || on any finite word of alphabet {a,b} by

    |x1x2|=|x1|+|x2| for any two finite words x1 and x2,

    with |a|=τ, |b|=1. Note that this is a cocycle in the free group.

    Then we can recursively define a bi-infinite sequence S:=(Si)iZRZ by Si=Si1+|wi1| with S0:=0R and wi1{a,b} constructed in Step 2. The range of the sequence S:ZR, also denoted by S, is called the Fibonacci chain.

    Remark 3. Our discussion will concern three kinds of words - geometric words, symbolic words and interval words. We will use the following example to illustrate the relationship among these three kinds of words. The geometric word S[τ,τ+1] is the point set {τ,0,τ,τ+1} and its corresponding symbolic word is a|ab which is more visually appealing. It is obvious that geometric and symbolic words can be transformed into each other. The corresponding interval word is the left-closed and right-open interval [τ,τ+1). The geometric and symbolic words can be transformed into the interval words but not vice versa.

    Lemma 2.6. The Fibonacci chain S is a quasi-crystal, so we also call S the Fibonacci quasi-crystal.

    Proof. We will prove the lemma by checking the definition of quasi-crystals.

    (i). We will first show that S is repetitive. Suppose that P=KS is a cluster of S where K is a compact set in R. Then P is a finite subset of S and we denote the corresponding index set by I={iZ:SiP}. Consider the finite word wP:=w[minI1,maxI] corresponding to P. There exists iZ+ such that wP is a subword of w(i). Since w(1) is a subword of u(4), by induction, w(i) is a subword of u(i+3). The word bb never occurs in w since b only appears in ab as an image of ρ. Thus any 2-letter subword of w contains a. Any 6-letter subword of w contains two images of some letter under ρ and so contains ρ(a). By induction, any (2i+32)-letter subword of w contains ρi+2(a)=u(i+3) and thus contains wP. Any ball of radius 2i+2τ in R contains at least 2i+3 points in S and the corresponding (2i+31)-letter subword of w contains wP. Hence P is contained in any ball of radius 2i+2τ.

    (ii). Obviously, S is of finite local complexity since |SiSi1| ranges on {τ,1} for all iZ and there are only a limited number of arrangements of intervals in a bounded range.

    (iii). If S has non-zero period, then w=limn+xn for some finite word x. Then the frequency of the letter a in w would be the quotient of the number of letter a in x divided by the length of x, which is rational. But on the other hand, the frequency of the letter a is

    limi+ the number of letter a in u(i) the length of u(i)=limi+fi1fi=1τ

    and is irrational, which is a contradiction.

    In conclusion, we have constructed the Fibonacci quasi-crystal S which is a geometric word associated with the bi-infinite symbolic word w.

    We consider the space RZ of bi-infinite real-valued sequences with the product topology. An element xRZ is denoted by (xi)iZ and is sometimes called a configuration.

    Given a function H:R2R we extend H to arbitrary finite segments (xj,,xk),j<k, of configuration xRZ by

    H(xj,,xk):=k1i=jH(xi,xi+1).

    We say that the segment (xj,,xk) is minimal with respect to H if

    H(xj,,xk)H(xj,,xk)

    for all (xj,,xk) with xj=xj and xk=xk.

    Definition 2.7 (minimal configuration). A configuration xRZ is minimal if every finite segment of x is minimal.

    Definition 2.8 [stationary configuration] If H is C1, we say that xRZ is a stationary configuration or an equilibrium configuration if

    2H(xi1,xi)+1H(xi,xi+1)=0 for all iZ. (4)

    Obviously, each minimal configuration is a stationary configuration.

    In this article, we take the function H as follows:

    H(ξ,η)=12(ξη)2+V(ξ). (5)

    Then (4) becomes

    2xixi1xi+1+V(xi)=0 for all iZ.

    In order to further describe the configurations, we introduce the following two notions.

    Definition 2.9 (rotation number). Let ρR. A configuration xRZ has a rotation number ρ if the limit

    limi±xii=ρ.

    Definition 2.10 (type-h configurations). Let h:ZR. A configuration xRZ is of type-h if

    supiZ|xih(i)|<.

    It is easy to see that the notion of the type-h configurations is more general than that of the rotation number. Taking h(i)=ρi for instance, any configuration of type-h has a rotation number ρ.

    In this section, we aim to build some special equivariant potential generated by the Fibonacci quasi-crystal. We will first introduce the following notion of "equivariant" in our settings.

    Definition 2.11 For any point set ΛRd, we say a continuous function f:RdR is Λ-equivariant if there exists R>0 such that if x,yRd satisfy

    (Λx)BR(0)=(Λy)BR(0)

    then f(x)=f(y).

    Given x0, we denote

    α(x):=max{yS|yx},β(x):=min{yS|y>x}.

    It is easy to see that both α and β are right-continuous step functions.

    As is explained in Remark 3, for all iZ+, we can regard u(i) defined in (1) as a left-closed and right-open interval in R, and one can always find some i(x)Z+ such that xu(i(x))u(i(x)1) with u(0)=. Or, in other words, due to (3), we have

    |u(i)|=fi1τ+(fifi1)=τi for all iZ+, (6)

    and so we get either

    0x<τ or τn1x<τn1+1 for some n1Z+.

    Let us consider the later case, and we have 0xτn1<τn11. Therefore, considering xτn1 instead of x, we get either

    0xτn1<τ or τn2xτn1<τn2+1 for some n2Z+.

    Hence, we could repeat the above procedure finitely many times and obtain either (i) 0x<τ or (ii) there exist finitely many n1,n2,,nrZ+ such that

    0xτn1τn2τnr<τ. (7)

    This means that x is covered either by the associated closed interval of u(1)=a or u(n1)u(n2)u(nr)v where v is an unknown word. By (7), it would be easy to see that v could be a, b, ba and bb.

    Based on the discussion above, we could obtain the following facts.

    Lemma 2.12. If nr>1, then v=a. If nr=1, then v=b. Moreover, we have

    β(x)={α(x)+1,if nr=1α(x)+τ,otherwise,where α(x)={0,if 0x<ττn1+τn1++τnr,if xτ.

    Proof. One could immediately have the expression of α(x). It then suffices to analyze the position of x in the quasi-crystal into the following two cases (see Figure 1):

    Figure 1.  the two possible position of x in the quasi-crystal.

    Case 1.: If nr=1 and so nr+1=2, we have either xτn1τnr1τnr=0, that is x is just both the right end point of the associated interval of a and the left end point of the associated interval of b or 0<xτn1τnr1τnr<τ, that is x is inside the associated interval of b. In both cases, we have β(x)α(x)=1.

    Case 2.: If nr>1, we obtain u(nr+1)=u(nr)u(nr1) due to (2), that is, x is covered by u(n1)u(nr1)u(nr+1) but not u(n1)u(nr1)u(nr). Therefore, v must be a front part of u(nr1). Then the first letter of v is a and v=a and so β(x)α(x)=τ.

    Notice that we have defined α(x) and β(x) only for x0. Since w=˜uba|u, we can extend α(x) and β(x) on the entire real line R by

    α(x)={β(x), if τ2x<0β(xτ2)τ2, if x<τ2 and β(x)={α(x), if τ2x<0α(xτ2)τ2, if x<τ2.

    Let ζ:RR be a function (see Figure 2 below) given by

    ζ(x)={6427(3|x|1)2(96|x|11),ifx(13,14)(14,13),64x2+16027,ifx[14,14],0,otherwise.
    Figure 2.  the graph of ζ.

    It is easy to check that ζ is C1 everywhere and C2 except at x=±1/3. The potential V:RR of the interaction (see Figure 3 below) is defined by

    V(x)={ζ(xα(x)), if 2xα(x)+β(x),ζ(xβ(x)), if 2x>α(x)+β(x). (8)
    Figure 3.  the graph of V.

    Lemma 2.13. The potential V is S-equivariant with range 1.

    Proof. Fix x,yR. if

    (Sx)B1(0)=(Sy)B1(0),

    then

    SB1(x)x=SB1(y)y.

    If α(x)x>1, then α(x)SB1(x). Hence α(y)SB1(y) and α(x)x=α(y)y.

    If α(x)x1, then β(x)α(x)>xα(x)1. Since α(x),β(x)S, we have β(x)α(x)=τ. Similarly, we also have β(y)α(y)=τ. Thus β(x)x=α(x)x+ττ1<1. Then β(x)x=β(y)y. Hence α(x)x=(β(x)x)(β(x)α(x))=(β(y)y)(β(y)α(y))=α(y)y.

    Hence we always have α(x)x=α(y)y. Similarly, β(x)x=β(y)y. Therefore, by the definition of the function V, we have V(x)=V(y).

    Lemma 2.14. The potential V is not periodic.

    Proof. The potential V(x) reaches the maximum 160/27 if and only if xS. If the potential V had a positive period T, then we must have S+TS, which is impossible since S is non-periodic.

    So far, we have constructed the interaction function H in (5) where the potential V is given by (8).

    Our goal in this section is to present the one-dimensional Fibonacci Frenkel-Kontorova model, i.e. the interaction function H given in the above section, for which we can obtain minimal configurations, equilibrium configurations and multiple equilibria with or without any rotation number.

    In this section, we aim to find a minimal configuration with rotation number (3τ+1)/2 where such minimal configurations exist according to [7]. Here we will give a more concrete construction.

    For any xR, the translation Sx of S is still a quasi-crystal. Let S+R={SxxR} be the collection of all translations of S.

    Let P be a given patch of quasi-crystal S and U be a subset in R. The cylinder set ΩP,U is the set of all quasi-crystals in S+R that contain a copy of P translated by an element of U, that is,

    ΩP,U:={TS+RPu is a patch in T for some uU}.

    In particular, we denote ΩP:=ΩP,{0}. It is easy to check that ΩP,U=uU(ΩPu).

    For any integer l1, let

    cl:=S[τ2l,τ2l],εl,1:=S[τ2l,τ2l+2],εl,2:=S[τ2l1,2τ2l+2]τ2l+1.

    We also use the corresponding symbolic words to represent these patches, for example:

    c1=ba|ab,ε1,1=ba|abaab,ε1,2=ba|ababaab;
    c2=ababa|abaab,ε2,1=ababa|abaababaabaab,ε2,2=ababa|abaababaababaabaab.

    Let Cl:=Ωcl, El,1:=Ωεl,1 and El,2:=Ωεl,2. Obviously, El,1 and El,2 are subsets of Cl.

    Remark 4. The definitions of patches cl,εl,1 and εl,2 above are motivated as follows. Consider the function

    Ll:ClRTinf{t>0TtCl}.

    The patches translated from cl are distributed over the real line and we use the function Ll to measure the distance between every pair of adjacent patches. In the following Lemma 3.1, we will show that the distance can only take two values τ2l+1 and τ2l+2, i.e., the range of Ll is {τ2l+1,τ2l+2}. Then, it is easy to see that εl,1 and εl,2 are two different patches which both start and end with cl and do not have any other cl in between.

    For any integer l1, we define the following point sets of R:

    Sl:={xRPx=cl for some patches P in S}.

    For any xR, let αl(x) be the largest number in Sl such that αl(x)x and βl(x) be the least number in Sl such that βl(x)>x.

    Lemma 3.1. For each l1,

    (i) Cl=El,1El,2,

    (ii) S+R=Ωεl,1,[0,τ2l+1)Ωεl,2,[0,τ2l+2).

    Proof. (1). Firstly, we show that the range of Ll is {τ2l+1,τ2l+2}. The Fibonacci quasi-crystal S is the corresponding geometric word of the symbolic word ω in Section 2.1.1. Then the substitution rule ρ2 defined on any subword of ω can be also defined on any patches of S by the connection between geometric words and symbolic words. Since ρ2(w)=w, the image of a patch of S under ρ2 is still a patch of S. In particular, we have

    ρ2(S[τ2l,τ2l])=S[τ2l×τ2,τ2l×τ2]=S[τ2(l+1),τ2(l+1)],

    that is, cl+1=ρ2(cl). Hence Ll+1(T)=τ2Ll(T) for all TCl+1. We only need to show the claim when l=1. Notice that ε1,1=ba|abaab=c1aab=ba|ac1, we have L1(E1,1)={τ3}. It is also easy to see that L1(E1,2)={τ4}. We claim that

    [(0,τ3)(τ3,τ4)(τ4,+)]{t>0TCl,TtCl and TsCls(0,t)}=.

    In fact, for any t(0,τ3) and any TCl, if TtCl, then the corresponding symbolic word of Tt must be ba|ab. Then the corresponding symbolic word of T could only be baab| or baa|b, which is impossible since TCl. For t(τ3,τ4), in the same way, the corresponding symbolic word of T could only be baab| or baab|. Furthermore, the word baab| must be baabaaa|, which is impossible since aaa is not a subword of w. Hence the corresponding symbolic word of T could only be baab|. Since TCl, its corresponding symbolic word is baabba|ab, which is impossible since bb is not a subword of w. If t(τ4,+), the corresponding symbolic word of T could only be baabPba|ab. the subword P formed by more than one letters must be like ababaaba since bb and aa are not subwords of P. In fact, if aa is a subword of P, then baab is a subword of P, which contradicts that TsCl, s(0,t). Then the word baabPba|ab has subword ababab which is impossible since aaa is not a subword of ω and ρ(aaa)=ababab. Hence the range of L1 is {τ3,τ4}. It is obvious that

    C1=(L1)1(τ3)(L1)1(τ4)=E1,1E1,2.

    Since εl+1,i=ρ2(εl,i), i{1,2}, by induction, we get (i).

    (2). Recall the above definition of αl and βl. We have proved that βl(x)αl(x) is τ2l+1 or τ2l+2. If βl(x)αl(x)=τ2l+1, then

    (Sαl(x))[τ2l,τ2l+2]=εl,1.

    If βl(x)αl(x)=τ2l+2, then

    (Sαl(x))[τ2l,τ2l+2+τ2l]=εl,2.

    For any T=SxS+R, we have T(xαl(x))=Sαl(x) and thus

    S+RΩεl,1,[0,τ2l+1)Ωεl,2,[0,τ2l+2).

    The proof of the opposite inclusion is obvious and so we complete the proof of (ii).

    If βl(x)αl(x)=τ2l+1, then we denote the corresponding symbolic word of S[αl(x),βl(x)] by Al. If βl(x)αl(x)=τ2l+2, then we denote the corresponding symbolic word of S[αl(x),βl(x)] by Bl. For example,

    A1=aba,B1=ababa,A2=abaababa,B2=abaababaababa.

    Notice that A2=A1B1 and B2=A1B1B1. Since εl+1,i=ρ2(εl,i) for i{1,2}, we have Al+1=ρ2(Al) and Bl+1=ρ2(Bl). Hence we have Al+1=AlBl and Bl+1=AlBlBl for all l1 by induction. Let

    M:=(1112):=(the number of Al in Al+1the number of Bl in Al+1the number of Al in Bl+1the number of Bl in Bl+1)

    then

    Mn=15(τ2n+1+τ2n1τ2n+τ2nτ2n+τ2nτ2n1+τ2n+1)=(the number of Al in Al+nthe number of Bl in Al+nthe number of Al in Bl+nthe number of Bl in Bl+n).

    Consider the two limits

    limnthe number of Al in Al+n|Al+n|=limnthe number of Al in Bl+n|Bl+n|=15τ2l+2,

    where || is the assignment function defined in Section 2.1.1. Since the symbolic word of S[τ4,τ3] is B1|A1, the absolute frequency of Al at 0 is the limit 1/(5τ2l+2) above. In the same way, the absolute frequency of Bl at 0 is 1/(5τ2l+1).

    For any integer l1, let Bl be an oriented 1-dimensional branched manifold (see Figure 4 below) in R2, which consists of two circles γl,1 and γl,2 that are tangent to one another at the tangent point Rl. In fact, this branched manifold is the Anderson-Putnam complex [11]. The circumferences of γl,1 and γl,2 are τ2l+1 and τ2l+2, respectively. Given two points ξ and η on the same circle, the oriented length of the arc from ξ to η is denoted by d(ξ,η). Let ml,i(x) denote the point on γl,i such that d(Rl,ml,i(x))=x, i{1,2}.

    Figure 4.  Branched Manifold Bl.

    For any l1, we define the map κl:Bl+1Bl which is illustrated by Figure 5 below:

    Figure 5.  the map κl.

    And the projection πl:RBl is defined by

    πl(x)={ml,1(xαl(x)),      if βl(x)αl(x)=τ2l+1;ml,2(xαl(x)),      if βl(x)αl(x)=τ2l+2.

    On the one hand, since Al+1=AlBl and Bl+1=AlBlBl for all l1, we have κlπl+1=πl. On the other hand, since the projection πl is a covering map from R to Bl and πl(Sl)={Rl}, the preimage (πl)1(y) of each given point y is a point set in R, and S¯B1(x) is the same patch up to translations for any point x in (πl)1(y). Therefore, the value of V is the same on (πl)1(y) by Lemma 2.13. Such property of V allows us to define the potential on Bl by ˆV:=V(πl)1:BlR and the function ˆH:γl,1×γl,1γl,2×γl,2R which maps (ξ,η) to 12d(ξ,η)2+ˆV(ξ).

    Now we construct the minimal configuration.

    Step 1. Fix l=1. For each i{1,2}, let b1,i be a point of γ1,i{R1}, and as in Section 2.2 we extend ˆH acting on the triple segment (R1,b1,i,R1) and obtain:

    ˆH(R1,b1,i,R1)=ˆH(R1,b1,i)+ˆH(b1,i,R1)=12d(R1,b1,i)2+ˆV(R1)+12d(b1,i,R1)2+ˆV(b1,i)=12d(R1,b1,i)2+ˆV(R1)+12(τ2+id(R1,b1,i))2+ˆV(b1,i)=d(R1,b1,i)2τ2+id(R1,b1,i)+V(d(R1,b1,i))+τ4+2i/2+V(0).

    One can easily see that ˆH(R1,b1,i,R1) reaches its minimum at b1,i:=m1,i(τ2+i) which is the antipodal point of R1 on γ1,i since d(R1,b1,i)=τ2+i/2 and the nonnegative potential V vanishes at τ2+i/2. We can then construct a bi-infinite increasing sequence (θ1,n)nZ of R with θ1,0=0 such that

    (θ1,n)nZ=(π1)1({R1,b1,1,b1,2}).

    This is because the pre-image of {R1,b1,1,b1,2} under π1 is a discrete countable subset of R. We thus obtain a configuration (θ1,n)nZ on R which is minimal on each segment [α1(x),β1(x)].

    Step 2. For any l1 and each i{1,2}, we first define the number Nl,i by iteration

    (Nl+1,1Nl+1,2)=(1112)(Nl,1Nl,2),with N1,1=N1,2:=2

    Note that (Nl,1,Nl,2)=(2f2l2,2f2l1), where {fi} is the Fibonacci number defined in Section 2.1.1.

    We now extend ˆH acting on the segment (Rl,bl,i,1,,bl,i,Nl,i1,Rl) where bl,i,1,bl,i,2,,bl,i,Nl,i1 are Nl,i1 different points in γl,i{Rl}, and we require that the subscript j of the point bl,i,j increases along the orientation of the circle γl,i. Then ˆH(Rl,bl,i,1,,bl,i,Nl,i1,Rl) reaches its minimum at (bl,i,1,,bl,i,Nl,i1)=(bl,i,1,,bl,i,Nl,i1).

    Similarly as before, since pre-image (πl)1({Rl,bl,i,j1jNl,i1}) is a discrete countable subset of R, we can obtain a bi-infinite increasing sequence (θl,n)nZ on R with θl,0=0 which is minimal on each segment [αl(x),βl(x)].

    Step 3. By the two steps above we get a sequence of configurations (θm)mZ+=((θm,n)nZ)mZ+ (see Figure 6 for numerical simulations of equilibrium configurations with m=5). In the subsequent two sections, we will show that this sequence is in a compact subset of RZ and its accumulation point with respect to m+ is a minimal configuration with rotation number (3τ+1)/2.

    Figure 6.  The red points are the graph of (θ5,n)n[50,50] and the green line is y=(3τ+1)/2x.

    Proposition 1 ([4]). Let (θ1,,θn) be a minimal segment and let I be an interval in [θ1,θn], then there exists an integer mZ+{0} such that for any pair of disjoint intervals I1=I+u1 and I2=I+u2 in [θ1,θn] which satisfy that for each θ in I and k=1,2:

    SB1(θ)+uk=SB1(θ+uk)

    the cardinality Card(Ik(θ1,,θn)){m,m+1,m+2} for k=1,2.

    Corollary 1. For each l1 and i=1,2, let uRZ be a minimal configuration(resp. let (up,,uq) be a minimal segment), then for any two connected component I1,I2 of π1l(γl,i)(resp. any two connected component I1,I2 of π1l(γl,i) which does not intersect (,up][uq,+)), we have

    |Card(uI1)Card(uI2)|2

    (resp.

    |Card((up,,uq)I1)Card((up,,uq)I2)|2).

    Lemma 3.2. For each l1, (θl,n)nZ has rotation number (3τ+1)/2.

    Proof. Let nl,i be the number of times πl([θl,0,θl,n]) covers completely the circle γl,i. Then

    nl,1τ2l+1+nl,2τ2l+2θl,nθl,0nl,1τ2l+1+nl,2τ2l+2+2τ2l+2

    and

    nl,1Nl,1+nl,2Nl,2nnl,1Nl,1+nl,2Nl,2+2Nl,2.

    Thus

    nl,1τ2l+1+nl,2τ2l+2nl,1Nl,1+nl,2Nl,2+2Nl,2θl,nnnl,1τ2l+1+nl,2τ2l+2+2τ2l+2nl,1Nl,1+nl,2Nl,2.

    Then the rotation number ρl of (θl,n)nZ is the limit (if exists):

    limn+nl,1τ2l+1+nl,2τ2l+2nl,1Nl,1+nl,2Nl,2.

    When n goes to + the quantity

    nl,inl,1τ2l+1+nl,2τ2l+2

    goes to the absolute frequency of Al if i=1 or of Bl if i=2. Hence

    ρl=1Freq0(Al)Nl,1+Freq0(Bl)Nl,2=3τ+12.

    Lemma 3.3. There exists M>0 such that for any l1, nZ, we have

    θl,n+1θl,nM.

    Proof. Let M(m)=2|Bm|=2τ2m+3, where m2. Suppose by contradiction that there exist l(m) and n(m) such that

    θl(m),n(m)+1θl(m),n(m)>M(m).

    Then there exists minimal segment

    (θl(m),n1,,θl(m),n(m),θl(m),n(m)+1,,θl(m),n2)

    such that

    γm,iπm([θl(m),n(m),θl(m),n(m)+1]) for some i.

    Let nl(m),i be the number of times πm1([θl(m),0,θl(m),n]) covers completely the circle γm1,i. Since κm1(γm,i)=Bm1, let κm1 act on each side then we have

    Bm1πm1([θl(m),n(m),θl(m),n(m)+1]).

    By Corollary 1, for each connected component Im1,i of π1m1(γm1,i), we have

    |Card(θl(m)Im1,i)|2.

    Since θl(m) has rotation number (3τ+1)/2, for all m2, we have

    (3τ+1)/2=limn+θl(m),nnlimn+nl(m),1τ2m1+nl(m),2τ2m2(nl(m),1+1)+2(nl(m),2+1)=τ2m1limn+nl(m),1+τnl(m),22nl(m),1+2nl(m),2+4.

    Notice that limn+nl(m),1+τnl(m),22nl(m),1+2nl(m),2+4 equals either 1/2 or τ/2 and so the right side of the inequality goes to + when m+, which is impossible.

    By Lemma 3.3, for each l1, the distance |θl,n+1θl,n| is bounded for all nZ. Therefore, all the configurations ((θm,n)nZ)mZ+ are contained in a compact subset of RZ, which guarantees that there exists at least one accumulation point as m+. We denote by (θ,n)nZ any of these accumulation points.

    Theorem 3.4. The configuration (θ,n)nZ is a minimal configuration with rotation number (3τ+1)/2.

    Proof. It is easy to show that (θ,n)nZ is minimal. In fact, for any finite segment (θ,j,,θ,k),k>j which is a limit point of minimal segments of (θm,n)kn=j as m+, it is straightforward to show that this segment is also minimal.

    We just need to show its rotation number is (3τ+1)/2. Let n,l,i be the number of times πl([θ,0,θ,n]) covers completely the circle γl,i. Then

    n,l,1τ2l+1+n,l,2τ2l+2θ,nθ,0n,l,1τ2l+1+n,l,2τ2l+2+2τ2l+2

    and by Corollary 1, we have

    n,l,1(Nl,12)+n,l,2(Nl,22)nn,l,1(Nl,1+2)+n,l,2(Nl,2+2)+2(Nl,2+2).

    Thus

    n,l,1τ2l+1+n,l,2τ2l+2n,l,1(Nl,1+2)+n,l,2(Nl,2+2)+2(Nl,2+2)θ,nnn,l,1τ2l+1+n,l,2τ2l+2+2τ2l+2n,l,1(Nl,12)+n,l,2(Nl,22).

    When n goes to +, the quantity

    n,l,in,l,1Nl,1+n,l,2Nl,2

    goes to the absolute frequency of Al if i=1 and of Bl if i=2. Then for every l1, the rotation number ρ of (θ,n)nZ satisfies

    1Freq0(Al)(Nl,1+2)+Freq0(Bl)(Nl,2+2)ρ1Freq0(Al)(Nl,12)+Freq0(Bl)(Nl,22).

    Let l+, and we obtain

    ρ=3τ+12.

    In this section, we will first find an equilibrium configuration (ui)iZ with rotation number (3τ+1)/2 satisfying

    (Δu)i+V(ui)=0, (9)

    where Δ denotes the discrete Laplacian. Then a specific calculation of such configuration will be given.

    To start with, let h:ZR be defined by

    h(i)=3τ+12i

    and let g:ZR be defined by

    g(i)=argminxS|xh(i)|={αh(i) if 2h(i)αh(i)+βh(i)βh(i) if 2h(i)>αh(i)+βh(i).

    Since the distance between any pair of adjacent points in S is 1 or τ, the closed ball with diameter τ centered at h(i) must contain some point of S, which means that |g(i)h(i)|τ/2 for all iZ. Now we start to find an equilibrium configuration in our context. First we reduce the existence of equilibria to a fixed point of a contraction mapping on a closed neighborhood of (g(i))iZ with the metric δ(u,u):=supiZ|uiui|. More precisely, we consider a space Π defined by

    Π:={u:|uig(i)|τ62 for all iZ}

    and a mapping Φ on Π defined by

    Φ:ΠΠ,u(1128(Δu)i+g(i))iZ.

    Notice that for all uΠ, we have

    |(Δu)i||(Δu)i(Δg)i|+|(Δg)i|4supiZ|uig(i)|+2τ64τ31.

    Thus, we get |Φ(u)ig(i)|=1128|(Δu)i|τ62, so the mapping Φ is well defined. Moreover, Φ is a contraction mapping since

    |Φ(u)iΦ(u)i|=1128|(Δu)i(Δu)i|132supiZ|uiui|.

    Hence by the contraction mapping principle, Φ has a unique fixed point u satisfying

    ui=1128(Δu)i+g(i)iZ. (10)

    Now it only remains to show that formula (10) and (9) are equivalent. In fact, the above fixed point u satisfies min{|uix|xS}=|uig(i)|τ/621/4 for all iZ, and hence V(ui)=ddx(64(xg(i))2+160/27)|x=ui=128(uig(i)). Then we can obtain (9) by multiplying by 128 on both sides of (10), by which we can conclude that u is an equilibrium configuration. What's more, since |uig(i)|τ62 and |g(i)h(i)|<τ/2 hold for all iZ, the rotation number of u is (3τ+1)/2, the same as the slope of h.

    In conclusion, we have obtained

    Theorem 3.5. The configuration u is an equilibrium configuration with rotation number θ.

    Next, let's calculate the equilibrium configuration u we constructed. Let α=1/128, then (10) is equivalent to

    αui1+(12α)ui+αui+1=aiiZ.

    Let T be a tridiagonal operator defined by

    Tei=αei1+(12α)ei+αei+1,iZ

    where {ei:iZ} is the orthonormal basis of the sequence space. Consider the truncation matrix

    Tn=(12αα000α12αα000α12α0000012αα000α12α)n×n,

    which is invertible by [9][Theorem 3.1]. And {T1nen}, {T1nen} are bounded due to [4][Corollary 6.2]. Then using [12][Theorem 3.1], we have

    u=limn+T12n+1yn,

    where yn=(g(n),,g(0),,g(n))T is the truncation of (g(i))iZ.

    Remark 5. (i) In fact, the method of finding equilibrium configurations in this article can be applied to all h satisfying |(Δh)i|<. For example, let

    h1(i)={i2,    if  i0,i2,   ifi<0.

    In this case, limi±h1(i)/i=± and hence the equilibrium configuration has no rotation number.

    (ii) See Figure 7 for numerical simulations of equilibrium configurations with or without rotation numbers.

    Figure 7.  The configuration T12n+1yn for h and h1 when n=500.

    The following theorem is a special case of [16][Theorem 1].

    Theorem 3.6. Let h:ZR satisfy |(Δh)i|<foralliZ. Then there exists a λ0 such that for any λ>λ0, there exists an equilibrium configuration u of type h with respect to

    Hλ(ξ,η)=12(ξη)2+λV(ξ). (11)

    Remark 6. The original paper [3] considers the notion of anti-integrable limits for the classical periodic Frenkel-Kontorova models and obtains the same types of equilibrium configurations. The authors also show the chaotic properties of these "exotic" equilibrium configurations.

    Moreover, in our context, we could show that there also exist non-minimal equilibrium configurations:

    Theorem 3.7. Let h:ZR satisfy |(Δh)i|<foralliZ. Then there exists λ0,λ1R satisfying λ1>λ0 such that for any λ>λ0, there exists an equilibrium configuration u of type h with respect to Hλ(ξ,η). In particular, if λ>λ1, the equilibrium configuration obtained above is non-minimal.

    To show Theorem 3.7, we just need a lemma:

    Lemma 3.8. For any λ>4/ζ(0), if u is an equilibrium configuration with respect to Hλ and each component ui lies in the quadratic part of V (that is, for each ui, there exists a neighborhood U of ui such that V|U is a quadratic function on U), then u is non-minimal.

    Remark 7. For the function V defined in Section 2.3, it is easy to see that a point x lies in the quadratic part of V if and only if minyS|xy|<1/4, where S is the Fibonacci quasicrystal.

    Proof. Fix λ and u that meet the conditions. Since each component ui lies in the quadratic part of V, we can regard the sequence g(i) as the closest local maximum point of V to ui. Notice that

    (Δu)i+λV(ui)=0 (12)

    and V(g(i))=0 for all iZ, then there exists some index i0 such that ui0g(i0). Otherwise (Δu)i=λV(ui)=λV(g(i))=0 and thus ui+1ui is a positive constant for all iZ. Since each ui=g(i) as a local maximum point of V is contained in the Fibonacci chain S, and the distance between any two points in S has the form mτ+n1, we suppose that ui+1ui=mτ+n1 for some nonnegative integers m and n. That is, the corresponding symbolic word of the geometric word S[ui,ui+1] contains m a-letters and n b-letters. Then the frequency of the letter a in w is equal to m/(m+n), which is rational. However, the frequency of the letter a in S is 1/τ, which was calculated in the proof of Lemma 2.6. Without loss of generality, suppose that i0=0. In order to show that u is non-minimal, we show that (u1,u0,u1) is non-minimal. That is, we find a u0:=u0(λ,u) such that

    Hλ(u1,u0)+Hλ(u0,u1)<Hλ(u1,u0)+Hλ(u0,u1). (13)

    Before we give the value of u0, there are some relations among u0,g(0) and ˉu:=(u1+u1)/2. Since u0 lies in the quadratic part of V, from Taylor's formula and the condition of λ, we have

    λV(u0)=λV(g(0))(u0g(0))=λζ(0)(u0g(0)){<4(u0g(0))     if  u0>g(0);>4(u0g(0))     if u0<g(0). (14)

    Then from (12) and (14), we know that

    ˉu=u0+λV(u0)2{<u0+2g(0)    if u0>g(0);>u0+2g(0)    if u0<g(0). (15)

    That is,

    |u0g(0)|<|ˉug(0)|. (16)

    And from (15) we can see that the sign of u0g(0) is different from the sign of ˉug(0), thus we have

    |ˉug(0)|<|ˉuu0|. (17)

    Now, we discuss three different cases and give the value of u0 in each case.

    Case 1.: If |ˉug(0)|1/2, where 1/2 is half of the minimal distance between two adjacent local maximum points of V. Let u0=ˉu. Consider the function F(x)=12(u1x)2+12(xu1)2. F(x) is a quadratic function and takes minimum at ˉu. Hence,

    12(u1u0)2+12(u0u1)212(u1u0)2+12(u0u1)2. (18)

    Since |ˉug(0)|1/2 and V is increasing on the interval [g(0)1/2,g(0)], decreasing on the interval [g(0),g(0)+1/2], and especially, strictly monotone on its quadratic parts, by (16), we have

    V(u0)<V(u0). (19)

    Multiply both sides of the inequality (19) by λ and add the inequality (18), then we have (13).

    Case 2.: If ˉug(0)>1/2. Let u0=g(0)+1/3, where 1/3 is the radius of each bump of V. Then

    V(u0)=0V(u0). (20)

    By (17), we have

    |ˉuu0|=|ˉug(0)1/3|<|ˉug(0)|<|ˉuu0|.

    Then using the monotonicity of F(x), we have

    12(u1u0)2+12(u0u1)2<12(u1u0)2+12(u0u1)2. (21)

    Multiply both sides of the inequality (20) by λ and add the inequality (21), then we have (13).

    Case 3.: If ˉug(0)<1/2, let u0=g(0)1/3. The rest of the proof is the same as the one in Case 2.

    Proof of Theorem 3.7. For any h with |(Δh)i|< for all iZ, Theorem 3.6 ensures the existence of equilibrium configuration of type h with respect to Hλ for any λ larger than some λ0. Let λ12=max{λ0,4/ζ(0)}. Then for any λ>λ12, the equilibrium configuration u whose existence is proved in Theorem 3.6 is non-minimal by Lemma 3.8, as long as we have that each ui lies in the quadratic part of V.

    To solve the problem of whether each ui can lie in the quadratic part of V, let us see the proof of Theorem 3.6 carefully. In our example of V, a sufficient condition is that the radius of the space that the contraction mapping is smaller than 1/4. A possible construction of the contraction is

    Πλ={u:|uig(i)|2max{|a|,|b|}+supiZ|(Δh)i|λζ(0)4 for all iZ},
    Φλ:ΠλΠλ,u(1λζ(0)(Δu)i+g(i))iZ.

    For all uΠλ, since

    |(Δu)i||(Δu)i(Δg)i|+|(Δg)i(Δh)i|+|(Δh)i|4supiZ|uig(i)|+4supiZ|g(i)h(i)|+supiZ|(Δh)i|42max{|a|,|b|}+supiZ|(Δh)i|λζ(0)4+4max{|a|,|b|}2+supiZ|(Δh)i|=λζ(0)2max{|a|,|b|}+supiZ|(Δh)i|λζ(0)4,

    we get

    |Φλ(u)ig(i)|=|1λζ(0)(Δu)i|2max{|a|,|b|}+supiZ|(Δh)i|λζ(0)4,

    which means that Φλ is well-defined. Φλ is a contraction mapping because

    |Φλ(u)iΦλ(u)i|=1λζ(0)|(Δu)i(Δu)i|4λζ(0)supiZ|uiui|.

    Let the radius of Πλ be smaller than 1/4, and we get a restriction on λ:

    λ>42max{|a|,|b|}+supiZ|(Δh)i|+1ζ(0)

    Hence, let

    λ1=max{λ12,42max{|a|,|b|}+supiZ|(Δh)i|+1ζ(0)},

    and then for any λ>λ1, there exists a non-minimal equilibrium configuration of type h with respect to Hλ.

    Proof of item (ii) of Theorem 1.1. By Theorem 3.5, to show the item (ii) of Theorem 1.1, it suffices to show that u is non-minimal with respect to Hλ in (11) when λ=1.

    In fact, by the definition of the function ζ, we have 4/ζ(0)=1/32<1. Due to Theorem 3.5, we have that u is an equilibrium configuration with respect to H1=H. Since uΠ={u:|uig(i)|τ62 for all iZ}, we know that each component ui lies in the quadratic part of V. Using Lemma 3.8, u is non-minimal.

    The authors would like to thank the anonymous referees for the valuable comments and suggestions on the manuscript. We also thank Prof. R. de la Llave for a very careful reading of the manuscript and many suggestions which helped improve a lot the presentation and exposition.



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