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A class of fourth-order hyperbolic equations with strongly damped and nonlinear logarithmic terms

  • Received: 01 June 2021 Revised: 01 July 2021 Published: 07 September 2021
  • Primary: 35A01, 35L75; Secondary: 35B40, 35B44

  • In this paper, we study a class of hyperbolic equations of the fourth order with strong damping and logarithmic source terms. Firstly, we prove the local existence of the weak solution by using the contraction mapping principle. Secondly, in the potential well framework, the global existence of weak solutions and the energy decay estimate are obtained. Finally, we give the blow up result of the solution at a finite time under the subcritical initial energy.

    Citation: Yi Cheng, Ying Chu. A class of fourth-order hyperbolic equations with strongly damped and nonlinear logarithmic terms[J]. Electronic Research Archive, 2021, 29(6): 3867-3887. doi: 10.3934/era.2021066

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  • In this paper, we study a class of hyperbolic equations of the fourth order with strong damping and logarithmic source terms. Firstly, we prove the local existence of the weak solution by using the contraction mapping principle. Secondly, in the potential well framework, the global existence of weak solutions and the energy decay estimate are obtained. Finally, we give the blow up result of the solution at a finite time under the subcritical initial energy.



    In this paper, we study the following initial boundary value problem:

    {utt+Δ2uΔut=|u|p2ulog|u|k,xΩ,t>0,u=un=0oru=Δu=0,xΩ,t0,u(x,0)=u0(x),ut(x,0)=u1(x),xΩ, (1)

    where ΩRn is a bound domain with smooth boundary Ω, the vector n is the unit outer normal to Ω and k is a positive real number. p satisfies

    2<p<{2(n2)n4,n>4,+,n4. (2)

    The differential equations studied by many researchers are significant [3,8,36], especially the logarithmic nonlinear problem. The logarithmic nonlinear problem is applied to many branches of physics, such as nuclear physics, optics, and geophysics [5,6,18], and it appears naturally in inflation cosmology and supersymmetric filed theories, quantum mechanics and nuclear physics [4,15]. Fourth-order differential equation with strong damping term has wide application in viscoelastic mechanics and quantum mechanics [7,10,34]. The strong damping term Δut indicates that the stress is proportional not only to the strain in the Hook law, but also to the strain rate in the linearized Kelvin-Voigt material.

    Górka [18] studied the one-dimensional Klein-Gordon equation with logarithmic source terms

    uttuxx=u+εuln|u|2,

    by using Galerkin's method, logarithmic Sobolev inequality and compactness theorem, the existence of weak solutions is obtained. Gazenave and Haraux [9] considered the problem

    uttΔu=uln|u|k, (3)

    they prove the existence and uniqueness of weak solutions in three dimensions. Later, in the case of infinite dimension in reference [25], Lian et al. modified the potential well method and combined with Sobolev inequality to obtain the global existence of the solution and the blow up result under the condition of different initial energy(E(0)<d, E(0)=d, E(0)>d). When uln|u|k in problem (3) becomes |u|pln|u|, the problem is also considered by Lian et al.[26], and they establish the global existence and finite time blow up of solutions at three different energy levels.

    Hiramatus et al.[21] introduced the equation

    uttΔu+u+ut+|u|2u=uln|u|, (4)

    to study the dynamics of Q-ball in theoretical physics. A numerical research was mainly carried out, but there was no theoretical research in that paper. For problem (4), Han [19] obtained the result of global existence of weak solution in three-dimensional bounded domain, and Zhang et al.[42] proved the energy decay estimate in infinite dimension case.

    Al-Gharabli and Messaoudi [1] considered the Neumann problem of weakly damped wave equations with logarithmic source term

    utt+Δ2u+u+ut=kuln|u|, (5)

    in two-dimensional bounded domain, they first obtained the existence of weak solutions by Galerkin method. Secondly, under the framework of potential well, they proved the global existence and exponential decay of weak solutions for all the conditions where(u0,u1)H20×L2 satisfy I(u0)>0 and 0<E(0)<d. In reference [2], h(ut) replaces ut in equation (5), Al-Gharabli and Messaoudi proved the existence and energy decay of solutions in the two-dimensional case.

    For hyperbolic equations with nonlinear damping terms, there have also been extensive studies in recent years. Messaoudi [33] studied the following equation with nonlinear damping terms and polynomial source terms

    utt+Δ2u+a|ut|m2ut=b|u|p2u, (6)

    where a,b>0, m,p>2. First, the author obtained the local existence of the solution by the contraction mapping principle. In addition, the global existence of the solution is proved under the condition of mp, and the blow up results are obtained under the condition of m<p and negative initial energy. After that, Wu and Tsai [38] generalized the result of [33]. Chen and Zhou [13] further studied the problem (6) and proved the global nonexistence of the solution with positive initial energy. Moreover, in the case of linear damping (m=2), they obtained blow up result of the solution even if the initial energy disappears under certain conditions.

    Liu [31] considered the equation

    utt+Δ2u+|ut|m2ut=|u|p2ulog|u|k.

    When 2m<p and the initial energy E(0)<d, the author obtained the global existence of weak solution and decay estimate. When the initial energy is negative, the author proved the blow-up results at finite time.

    Gazzola and Squassina [17] studied the following damped semilinear wave equation

    uttΔuωΔut+μut=|u|p2u.

    For the initial energy E(0)<d, the authors obtained the global existence of the weak solution. In addition, when ω=0, they obtained the finite time blow up result at any arbitrarily high initial energy.

    On the basis of reference [17], Lian and Xu [28] studied the following semilinear wave equation with logarithmic source term

    uttΔuωΔut+μut=uln|u|,

    the author studied the global existence, asymptotic behavior and the blow up results under the conditions of subcritical initial energy and critical initial energy respectively. Under the condition of ω=0 and E(0)>0, the author obtained the blow up results at infinite time.

    Recently, Yang et al.[40] investigated a class of fourth order strongly damped nonlinear wave equations

    uttΔu+Δ2uαΔut=f(u),

    they comprehensively investigated the global existence, long-time behavior and finite time blow up of the solution at three different initial energy levels. Zeng and Zhao [41] considered the Cauchy problem of a Keller-Segel type chemotaxis model with logarithmic sensitivity and logistic growth, and obtain similar results. In [14], Di considered the initial boundary value problem of the fourth order wave equation with an internal nonlinear source |u|ρu, they proved the global existence and uniqueness of the regular solution and the weak solution respectively, and studied the explicit decay rate estimation of energy. Liu and Zhou [32] considered the local well-posedness of solutions to the initial boundary value problem for fourth-order plate equations with Hardy-Hénon potential and polynomial nonlinearity, and also studied the global existence and finite time blow-up results of solutions.

    After looking up these literatures on the dynamic behavior of logarithmic term, it is not difficult to find that the estimates of power-type nonlinear term cannot be directly generalized to logarithmic nonlinear term. When the logarithmic source term is uln|u|, the logarithmic Sobolev inequality is usually used to deal with such problem. In this paper, the non-linear logarithmic source term |u|p2ulog|u|k brings us some difficulties, here we cannot apply logarithmic Sobolev inequality. In addition, the hyperbolic equation is different from the parabolic equation. The parabolic equation with strong damping term has been extensively studied by many authors, and a large number of results have been obtained [11,20,27,29,37,39,43]. Specially, Chen and Xu [12] studied the initial boundary value problem of infinitely degenerate semilinear pseudo-parabolic equations with logarithmic nonlinear terms, and obtained the global existence, blow up and the asymptotic behavior of the solution. However, in this paper, for the fourth order hyperbolic equation, the emergence of logarithmic term and strong damping term prevent us from obtaining the blow up result of the solution. Here, we use the potential well method and some new techniques to obtain the existence of solution, estimate of energy decay, and blow up results.

    This paper is organized as follows: In Section 2, we introduce some mathematical symbols, basic definitions and important lemmas needed for theorem proof. In Section 3, we prove the local existence of the weak solution of the problem (1). In Section 4, we give the global existence of the solution and energy decay. In the last Section, we obtain the result of the blow up at a finite time.

    In this section, we first introduce some of the notation used in this paper. The norm of Lp(Ω) is denoted by p, where 1p. We define the following space for further discussion

    H={H20(Ω)foru=0andun=0onΩ,H10(Ω)H2(Ω)foru=0andΔu=0onΩ.

    Naturally, by Poincaré's inequality [30], Δ2 is the equivalent norm of H. Besides, , represents the duality pairing between H2(Ω) and H.

    Let us introduce some of the required functionals.

    E(t)=12ut22+12Δu221pΩ|u|plog|u|kdx+kp2upp, (7)
    J(u)=12Δu221pΩ|u|plog|u|kdx+kp2upp, (8)
    I(u)=Δu22Ω|u|plog|u|kdx. (9)

    By (8) and (9), we have

    J(u)=1pI(u)+(121p)Δu22+kp2upp. (10)

    We define the Nehari manifold

    N={uH{0}:I(u)=0}.

    The depth of potential well is defined as

    d=infuNJ(u), (11)

    by Lemma 2.8, we know that d satisfies

    dM:=(p22p)r2, (12)

    where r is the positive constant defined in Lemma 2.7.

    The potential well (stable set) W and the outer space of potential well (unstable set) V are defined as follows:

    W:={uH|I(u)>0,J(u)<d}{0},
    V:={uH|I(u)<0,J(u)<d}.

    Now, we give the definition of weak solution to problem(1).

    Definition 2.1. The function u=u(x,t) is called a weak solution of the problem(1) on Ω×[0,T), if uC([0,T],H)C1([0,T],L2(Ω))C2([0,T],H2(Ω)), utL2(0,T;H10(Ω)), and there holds

    utt,v+ΩΔuΔvdx+Ωutvdx=Ω|u|p2ulog|u|kvdx,

    for any vH, t[0,T), where u(x,0)=u0(x) in H, ut(x,0)=u1(x) in L2(Ω).

    Next, we state our main results of this paper as follows:

    Theorem 2.2. (Local existence) Suppose that u0H, u1(x)L2(Ω). Then there exist a T>0 such that problem(1) admits a unique weak solution u on [0,T] satisfying

    uC([0,T],H)C1([0,T],L2(Ω))C2([0,T],H2(Ω)).

    Theorem 2.3. (Global existence and decay estimate) Assume (2) holds, if u0H, u1L2(Ω), E(0)M and I(u0)0, then the problem(1) admits a global weak solution uL(0,;H) with utL2(0,;H10(Ω)). Furthermore, there exists a positive constant K0 such that the energy functional E(t) satisfies the following polynomial decay estimate:

    E(t)K01+t,forallt[0,). (13)

    In particular, if E(0)<min{M,p22p(eμkC2p+μ)2p+μ2} and 0<μ<2p, then there exist positive constants K1 and K2, such that the E(t) satisfies the exponential decay estimate as follows:

    E(t)K1eK2t,forallt[0,), (14)

    where M is the positive constant defined in (12).

    Theorem 2.4. (Blow up) Assume u0H{0}, u1L2(Ω) satisfy E(0)<d, I(u0)<0, then the solution u of problem (1) blows up in finite time.

    To prove our main results, we need to introduce some lemmas.

    Let (2) holds, by Sobolev's embedding theorem [16], we know that upCpΔu2, where Cp is the optimal embedding constant of HLp(Ω), i.e. Cp=supuH{0}upΔu2. We define

    α={2nn4p,n>4,,n4,

    for any α[0,α), then HLp+α(Ω). And we denote Cp+α by C.

    Lemma 2.5. Let uH{0}, then

    (1)limλ0+J(λu)=0,limλ+J(λu)=;

    (2) There exists a unique λ>0 such that ddλJ(λu)|λ=λ=0, and J(λu) is increasing on λ(0,λ), decreasing on λ(λ,+);

    (3) I(λu){>0,λ(0,λ)<0,λ(λ,+) and I(λu)=0.

    Proof. The proof of this lemma can refer to [24]. Here, we omit it.

    From Lemma 2.5, it is easy to see that Nehari manifold is not empty and the definition of d is meaningful.

    Lemma 2.6. Assume (2) holds. Let uH{0}, α(0,α) and

    r(α)=(αkCp+α)1p+α2,

    then we have

    (i) if 0<Δu2r(α), then I(u)>0.

    (ii) if I(u)0, then Δu2>r(α).

    Proof. For any constant y>0, we have logy<y. Combined with Sobolev embedding inequality, through a direct calculation, we obtain

    I(u)=Δu22Ω|u|plog|u|kdx>Δu22kαup+αp+αΔu22kαCp+αΔup+α2=kαCp+αΔu22(r(α)p+α2Δup+α22). (15)

    By the above inequality, it is easy to know that (i) and (ii) hold.

    Lemma 2.7. Combined with the notation in Lamma 2.6, we have

    0<r:=supα(0,α)r(α)=supα(0,α)(αkCp+α)1p+α2r:=supα(0,α)(αkBp+α)1p+α2|Ω|αp(p+α2)<,

    where, |Ω| is the measure of Ω, and B=Cp is the optimal embedding constant.

    Proof. Obviously, if r exists, we have r>0. So we just have to prove r(α)<ρ(α), r exists and r<, where

    ρ(α)=(αkBp+α)1p+α2|Ω|αp(p+α2).

    For any uH{0}, using the Hölder inequality, we have

    up|Ω|αp(p+α)up+α.

    Noticing that C=Cp+α, B=Cp, we get

    C=supuH{0}up+αΔu2|Ω|αp(p+α)supuH{0}upΔu2|Ω|αp(p+α)B.

    Hence,

    (αkCp+α)1p+α2(αkBp+α)1p+α2|Ω|αp(p+α2),

    that is, r(α)<ρ(α).

    Next, we prove r exists and r<, the proof is divided into two cases.

    Case1. If n>4, then α(0,α)=(0,2nn4p). Since ρ(α) is continuous on [0,2nn4p], we have r exists and

    r=supα(0,2nn4p)ρ(α)maxα[0,2nn4p]ρ(α)<.

    Case2. If n4, then α(0,+). We define

    h(α):=log[ρ(α)]=(1p+α2)[logαlogk(p+α)logB]+αp(p+α2)log|Ω|,α(0,+),

    thus,

    h(α)=p2+pα2p+pαlogkpαlogα+2pαlogB+pαlog|Ω|2αlog|Ω|pα(p+α2)2.

    Let

    g(α)=p2+pα2p+pαlogkpαlogα+2pαlogB+pαlog|Ω|2αlog|Ω|,

    then,

    g(α)=p+plogkplogαp+2plogB+plog|Ω|2log|Ω|=plogkB2|Ω|12pα,

    which shows that g(α) is strictly increasing on (0,kB2|Ω|12p), and strictly decreasing on (kB2|Ω|12p,).

    On the one hand, it is easy to see that

    limα0+g(α)=p22p>0.

    On the other hand, we can get that

    limα+g(α)=p22p+pα(1+logkB2|Ω|12plogα)=.

    Given the monotonicity of g(α), it is easy to see that there is a unique α(kB2|Ω|12p,) such that g(α)=0. Hence, g(α)>0 for α(0,α), g(α)<0 for α(α,), h(α) attains its maximum at α=α. Therefore,

    r=supα(0,+)ρ(α)=eh(α)<.

    From Lemma 2.6 and Lemma 2.7, it is not difficult to get the following corollary.

    Corollary 1. Assume (2) holds. Let uH{0}, we have

    (i) if 0<Δu2r, then I(u)>0;

    (ii) if I(u)0, then Δu2r,

    where r is defined in Lemma 2.7.

    Lemma 2.8. Assume (2) holds, we have

    dM:=(p22p)r2, (16)

    where r is defined in Lemma 2.7.

    Proof. By the definition of d, we know uN, then I(u)=0. Combined with (10) and (ii) of Corollary 1, we get

    J(u)=(121p)Δu22+kp2upp(p22p)r2,

    thus, (16) holds.

    From the previous definition of E(t), we have the following energy equation

    E(t)+t0ut22dτ=E(0). (17)

    Lemma 2.9. If u0H, u1L2(Ω), p>2, E(0)<d and u is a weak solution of problem(1) on [0,T), then

    (i) if I(u0)>0, then uW;

    (ii) if I(u0)<0, then uV.

    Proof. By the definition of E(t), J(u) with (17), we have

    12ut22+J(u)12u122+J(u0)<d. (18)

    (i) By contradiction, we assume that there exists t0[0,T), such that u(t)W on [0,t0)and u(t0)W. By the continuity of J(u) and I(u), we have

    J(u(t0))=dorI(u(t0))=0.

    Obviously, J(u(t0))=d is impossible. If I(u(t0))=0 holds, by the definition of d, then J(u(t0))d, which is contradictive with (18). Thus, uW. (ii) The proof is similar to (i), which we omit here.

    In this part, we prove the local existence and uniqueness of weak solution. To prove the local existence of weak solution, firstly, we need to introduce the following lemmas.

    Lemma 3.1. [22] For any ε>0, there exists a constant A>0, such that the function

    j(s)=|s|p2log|s|,p>2

    satisfies

    |j(s)|A+|s|p2+ε.

    Here, for every T>0, we consider the space

    H=C([0,T],H)C1([0,T],L2(Ω)

    endowed with the norm

    u2H=maxt[0,T](Δu22+ut22)

    Lemma 3.2. For every T>0, uH and every initial data (u0,u1)H×L2(Ω), there exists a unique solution vC([0,T],H)C1([0,T],L2(Ω)C2([0,T],H2(Ω)) with vtL2([0,T],H10(Ω)), which solves the linear problem

    {vtt+Δ2vΔvt=|u|p2ulog|u|k,xΩ,t>0,v=vn=0orv=Δv=0xΩ,t0,v(x,0)=u0(x),vt(x,0)=u1(x),xΩ. (19)

    Proof. Applying Garlerkin's method, for every h1, let Wh=span{w1,w2,,wh}, where {wj} is the orthonormal complete system of eigenfunctions of Δ in H such that wj2=1 for all j. According to their multiplicity of

    Δwj+λjwj=0,

    we denote the related eigenvalues repeated by λj. Let

    uh0=hj=1(Ωu0wjdx)wj,uh1=hj=1(Ωu1wjdx)wj,

    so that uh0Wh, uh1Wh, uh0u0 in H and uh1u1 in L2(Ω) as h. For all h1, we seek h functions γh1,,γhhC2[0,T] such that

    vh(t)=hj=1γhj(t)wj (20)

    solves the problem

    {Ω[¨vh(t)+Δ2vhΔ˙vh|u|p2ulog|u|k]η=0,vh(0)=uh0,˙vh(0)=uh1. (21)

    where ηWh and t0. Taking η=wj for j=1,,h in (21), we obtain the following Cauchy problem for a linear ordinary differential equation with unknown γhj:

    {¨γhj(t)+λ2jγhj(t)+λj˙γhj(t)=ψj(t),γhj(0)=Ωu0wjdx,˙γhj(0)=Ωu1wjdx. (22)

    where ψj(t)=Ω|u|p2ulog|u|kwjdxC[0,T]. For all j, the above Cauchy problem has a unique local solution γhjC2[0,T], which implies a unique vh defined by (20) satisfying (21).

    Let η=˙vh(t) in (21), integrating over [0,t][0,T], we get

    ˙vh(t)22+Δvh(t)22+2t0˙vh(t)22dτ=uh122+Δuh022+2t0Ω|u|p2ulog|u|k˙vhdxdτ, (23)

    for every h1. We estimate the last term in the right-hand side of (23). Using Hölder's inequality, we have

    2t0Ω|u|p2ulog|u|k˙vhdxdτ2t0Ω||u|p2ulog|u|k||˙vh|dxdτ2t0|u|p2ulog|u|kpp1˙vhpdτ. (24)

    Using the fact |xp1logx|(e(p1))1 for 0<x<1, while xμlogx(eμ)1 for x1,μ>0. Choosing μ>0 such that p(p1+μ)p1<2nn2<2=2nn4, by a direct calculation and Sobolev inequality, we have

    Ω||u|p2ulog|u|k|pp1dx={xΩ:|u|<1}||u|p2ulog|u|k|pp1dx+{xΩ:|u|1}||u|p2ulog|u|k|pp1dxkpp1(e(p1))pp1|Ω|+kpp1(eμ)pp1{xΩ:|u|1}|u|p(p1+μ)p1dxC+CΔup(p1+μ)p12C, (25)

    here, it is needs to be noted that C in the text is a general constant, and the C in each row and even in the same row is differemt.

    By the Sobolev embedding theorem, we have ˙vhpC˙vh2. Combined with Young's inequality, (24) yields

    2t0Ω|u|p2ulog|u|k˙vhdxdτ2t0|u|p2ulog|u|kpp1˙vhpdτ2Ct0˙vh2dτCT+t0˙vh22dτ. (26)

    Recalling the convergence of uh0 and uh1, by (23) and (26), we obtain

    ˙vh(t)22+Δvh(t)22+t0˙vh(t)22dτC, (27)

    for every h1, where C is independent of h. By this uniform estimate, we have

    {vh} is bounded in L([0,T],H);

    {˙vh} is bounded in L([0,T],L2(Ω))L2([0,T],H10(Ω));

    {¨vh} is bounded in L2([0,T],H2(Ω)).

    Thus, up to a subsequence, we could pass to the limit in (21) satisfying above regularity. Then a weak local solution of problem (19) can be obtained.

    Uniqueness follows arguing for contradiction, if v and w were two solutions of (19) which have the same initial date, by subtracting the equations and testing with vtwt, we could get

    vtwt22+ΔvΔw22+2t0Ω|vtwt|2dxdτ=0,

    which yields w=v. The proof of the lemma is complete.

    Now, we begin to prove Theorem 2.2.

    Proof of Theorem 2.2. For any uH, u0H, u1L2(Ω), let

    R2:=2(u122+Δu022).

    For any T>0, we consider

    UT={uH:u(0)=u0,ut(0)=u1,uHR}.

    By Lemma 3.2, for any uUT we could define v=Φ(u), where v is the unique solution of problem (19). We claim that, for a suitable T>0, Φ is a contractive map satisfying Φ(UT)UT. Given uUT, the corresponding solution v=Φ(u) satisfies the energy identity for all t(0,T] as follows

    vt22+Δv22+2t0vt22dτu122+Δu022+2t0|u|p1log|u|kpp1vtpdτ. (28)

    Now we estimate the last term of (28), we get

    2t0|u|p1log|u|kpp1vtpdτCt0|u|p1log|u|k2pp1dτ+2t0vt22dτCt0|kpp1(e(p1))pp1|Ω|+CΔup(p1+μ)p12|2(p1)pdτ+2t0vt22dτCT(1+R2(p1+μ))+2t0vt22dτ. (29)

    Substituting (29) into (28), we obtain

    vt22+Δv22R22+CT(1+R2(p1+μ)).

    Choosing T>0 small enough, such that CT(1+R2(p1+μ))R22. Hence, Φ(u)HR, that is Φ(UT)UT.

    Next, we show that Φ is contractive in UT. Namely, For any u1,u2UT, there exists 0<δ<1, such that

    Φ(u1)Φ(u2)Hδu1u2H.

    Let u1,u2UT, v1=Φ(u1), v2=Φ(u2) and z=v1v2, then z is the unique solution to the following problem

    {ztt+Δ2zΔzt=|u1|p2u1log|u1|k|u2|p2u2log|u2|k,z(x,0)=0,zt(x,0)=0. (30)

    Multiplying both sides of (30) by zt, and integrating over (0,t)×Ω, we get

    zt22+Δz22+2t0zt22dτ=2t0Ω(|u1|p2u1log|u1|k|u2|p2u2log|u2|k)ztdxdτ.

    Using Lagrange Theorem, for 0<θ<1, combined with Lemma 3.1, we have

    ||u1|p2u1log|u1|k|u2|p2u2log|u2|k|=k|1+(p1)log|θu1+(1θ)u2|||θu1+(1θ)u2|p2|u1u2|k|θu1+(1θ)u2|p2|u1u2|+k(p1)A|u1u2|+k(p1)|θu1+(1θ)u2|p2+ε|u1u2|k|u1+u2|p2|u1u2|+k(p1)A|u1u2|+k(p1)|u1+u2|p2+ε|u1u2|.

    Since u1,u2UT, utilizing Hölder's inequality and Sobolev embedding theorem, we have

    Ω||u1+u2|p2|u1u2||2dx(Ω|u1+u2|2(p1)dx)p2p1(Ω|u1u2|2(p1)dx)1p1C(u12(p1)2(p1)+u22(p1)2(p1))p2p1u1u222(p1)C(u12(p1)H+u22(p1)H)p2p1u1u22HCR2(p2)u1u22H. (31)

    Choosing ε>0 small enough, such that ˉp=2(p1)+2ε(p1)p2<2nn4, by a calculation similar to (31), we obtain

    Ω||u1+u2|p2+ε|u1u2||2dx(Ω|u1+u2|2(p2+ε)(p1)p2dx)p2p1(Ω|u1u2|2(p1)dx)1p1C(Ω|u1+u2|2(p1)+2ε(p1)p2dx)p2p1u1u222(p1)C(u1ˉpˉp+u2ˉpˉp)p2p1u1u222(p1)CRˉp(p2)p1u1u22H. (32)

    From the above calculation, we can deduce

    |u1|p2u1log|u1|k|u2|p2u2log|u2|k22C(R2(p2)+1+Rˉp(p2)p1)u1u22H.

    Hence, for some δ<1 as long as T is sufficiently small, we have

    zt22+Δz22CT(1+R2(p2)+Rˉp(p2)p1)u1u22H<δu1u22H.

    That is,

    Φ(u1)Φ(u2)2H=v1v22Hδu1u22H.

    So by the contraction mapping principle, we can conclude that problem (1) admits a unique solution.

    In this section, we prove Theorem 2.3, which is divided into 4 steps.

    Proof of Theorem 2.3. Step 1. Global existence for the case of E(0)<M and I(u0)0.

    By the definition of E(t) and (10), we know that 0J(u0)E(0)<M, and combine with Lemma 2.8, then we have respectively

    (i) If E(0)=0 and I(u0)0, then this implies that (u0,u1)=(0,0), which is a trivial case;

    (ii) If 0<E(0)<Md and I(u0)=0, then it contradicts with the definition of potential depth d.

    Hence, we only need to consider the case of 0<E(0)<Md and I(u0)>0.

    Let {wj(x)} be a system of base functions in H. We construct the following approximate solutions to problem (1)

    um(x,t)=mj=1gjm(t)wj(x),m=1,2,...,

    satisfying

    umtt,wj+(Δum,Δwj)+(umt,wj)=Ω|um|p2umlog|um|kwjdx,j=1,2,...,m (33)
    u0m=um(x,0)=mj=1gjm(0)wj(x)u0stronglyinH, (34)
    u1m=umt(x,0)=mj=1gjmt(0)wj(x)u1stronglyinL2(Ω). (35)

    Now, multiplying (33) by gjmt(t), summing for j, and integrating over [0,t], we can compute

    Em(t)+t0umt22dτ=Em(0),0t<+, (36)

    for sufficiently large m. Since E(0)<Md and I(u0)>0, by (34) and (35), for sufficiently large m, we conclude that Em(0)<Md and I(u0m)>0. By the argument in the proof of Lemma 2.9, for sufficiently large m and 0t<, we have um(t)W. Hence, combined with (10), we have

    dM>Em(t)>J(um)>(121p)Δum22+kp2umpp,

    for sufficiently large m and 0t<. So it follows that

    Δum22<2pMp2,umpp<p2Mk, (37)
    t0umt22dτ<M. (38)

    By (37), (38), there exist functions u and a subsequence of {um}m=1 which we still denote it by {um}m=1 such that

    umuweaklystarinL(0,;H), (39)
    umtutweaklyinL2(0,;H10(Ω)), (40)

    By Aubin-Lions-Simon Lemma (see [35], Corollary 4), we get

    umustronglyinC(0,;H10(Ω)),

    so, umu a.e. (x,t)Ω×[0,), m+. This implies

    |um|p2umlog|um|k|u|p2ulog|u|k,a.e.(x,t)Ω×[0,+). (41)

    On the other hand, from (41), (25) and Lions Lemma (see [30], Lemma 1.3, p.12), we have

    |um|p2umlog|um|k|u|p2ulog|u|kweaklystarinL(0,;Lpp1(Ω)). (42)

    Integrating (33) with respect to t we obtain

    (umt,wj)+t0(Δum,Δwj)dτ+(um,wj)=(u1m,wj)+(u0m,wj)+t0(|um|p2umlog|um|k,wj)dτ, (43)

    therefore, up to a subsequence, by (39)-(42), we could pass to the limit in (43). Moreover, from(34) and (35), we get u(x,0)=u0 in H and ut(x,0)=u1 in L2(Ω). Then we have a global weak solution u(x,t) to problem(1).

    Step 2. Global existence for the case of E(0)=M and I(u0)0.

    By Lemma 2.8, we know dM. If E(0)=M<d, then the problem (1) has a global weak solution, which is similar to the proof of step 1. If E(0)=M=d, we consider two cases I(u0)=0 and I(u0)>0.

    (i) E(0)=M=d, I(u0)=0

    From the definition of d, we have J(u0)d. However, 12u122+J(u0)=E(0)=d, it follows that J(u0)<d. So case (1) is impossible.

    (ii) E(0)=M=d, I(u0)>0

    In order to prove the global existence result of problem (1), we first choose a sequence {γm}m=1(0,1) such that limmγm=1. Then we considering the following problem

    {utt+Δ2uΔut=|u|p2ulog|u|k,(x,t)Ω×(0,T),u=un=0,(x,t)Ω×(0,T),u(x,0)=u0m,ut(x,0)=u1m,xΩ, (44)

    where u0m=γmu0, u1m=γmu1. Since I(u0)>0, it follows from Lemma 2.5 that λ>1.

    Hence, we get

    I(u0m)=I(γmu0)>0,
    J(u0m)=J(γmu0)<J(u0),

    and

    0<Em(0)=12u1m22+J(u0m)<12u122+J(u0)=E(0)=M=d.

    Using the similar arguments as previous step 1, we find that problem (44) admits a global weak solution um which satisfies

    umL(0,;H),umtL2(0,;H10(Ω))

    and

    umtt,υ+(Δum,Δυ)+(umt,υ)=Ω|um|p2umlog|um|kυdx,j=1,2,...,m,

    for any υH, and for a.e. 0t<. The remainder of the proof can be processed similarly as previous step 1. Hence, u is a global weak solution for problem (1).

    Step 3. Polynomial decay estimate of energy for the case of E(0)M and I(u0)0.

    Firstly, by (10), (17) and I(u)0, we obtain

    E(0)=E(t)+t0ut22dτ=12ut22+1pI(u)+p22pΔu22+kp2upp+t0ut22dτ12ut22+p22pΔu22+kp2upp+t0ut22dτ. (45)

    A combination of (45) and E(0)M, we have

    t0ut22dτ1λ1t0ut22dτ<Mλ1, (46)

    where λ1 is the first eigenvalue of the following problem:

    {Δϕ(x)=λϕ(x),xΩ,ϕ(x)=0,xΩ,

    for ϕ(x)H10(Ω). Next, multiplying the first equation of problem (1) by u and integrating over Ω×(0,t). Using Young inequality, we have

    t0I(u)dτ=t0(utt,u)dτt0(ut,u)dτ=Ωutudx+Ωu1u0dx+t0ut22dτ+12u02212u2212u2H10+12ut22+t0ut22dτ+12u122+12u02H10C212u2H+12ut22+t0ut22dτ+12u122+12u02H10, (47)

    where C1 stand by the best constant in the embedding HH10(Ω). Using (45), (46) and uL(0,T;H), then (47) implies that

    t0I(u)dτC,for0<t<+. (48)

    From I(u)0, we know that there exists a λ1 such that I(λu)=0. On the other hand, we have

    0=I(λu)=λ2Δu22λpΩ|u|plog|u|kdxkλplogλupp=λpI(u)(λpλ2)Δu22kλplogλupp.

    Hence, we obtain

    I(u)=(11λp2)Δu22+klogλupp.

    Combining the above equation with (48), we obtain

    t0Δu22dτC, (49)

    and

    t0uppdτC. (50)

    Differentiating E(t) and using Eq.(1), we can compute

    E(t)=Ω|ut|2dx0.

    Since

    ddt[(1+t)E(t)]=(1+t)E(t)+E(t)E(t), (51)

    then integrating (51) over (0,t), we have

    (1+t)E(t)E(0)+t0E(t)dτ=E(0)+12t0ut22dτ+1pt0I(u)dτ+(121p)t0Δu22dτ+kp2t0uppdτ. (52)

    Thus, applying E(0)M, (46), (48), (49) and (50) to (52), we can derive that there exists a positive constants K0 such that the energy functional E(t) satisfies the following polynomial decay estimation:

    E(t)K01+t,forallt[0,+).

    Step 4. Exponential decay estimate of energy for the case of E(0)<min{M,p22p(eμkC2p+μ)2p+μ2}.

    We define

    L(t)=E(t)+ϵΩuutdx+ϵ2Ω|u|2dx, (53)

    for any 0t<, where ϵ is a positive constant to be specified later. By the Young inequality, we can easily know that there exist two positive constant α1 and α2 such that

    α1E(t)L(t)α2E(t),forallt[0,+). (54)

    that is to say, L(t) and E(t) are equivalent.

    By taking the time derivative of the function L(t), using Eq.(1), we get

    L(t)=E(t)+ϵΩ|ut|2dx+ϵΩuuttdx+ϵΩuutdx=Ω|ut|2dx+ϵΩ|ut|2dxϵΩ|Δu|2dx+ϵΩ|u|plog|u|kdx=βϵE(t)+βϵ2ut22+βϵ2Δu22βϵpΩ|u|plog|u|kdx+βϵkp2uppΩ|Δut|2dx+ϵΩ|ut|2dxϵΩ|Δu|2dx+ϵΩ|u|plog|u|kdxβϵE(t)+(βϵ2+ϵλ1)ut22+(βϵ2ϵ)Δu22+(ϵβϵp)Ω|u|plog|u|kdx+βϵkp2upp. (55)

    By virtue of the Sobolev embedding inequality and (45), we obtain

    Ω|u|plog|u|kdx{xΩ:|u|1}|u|plog|u|kdxk(eμ)1{xΩ:|u|1}|u|p+μdxk(eμ)1up+μp+μk(eμ)1C2p+μΔup+μ2k(eμ)1C2p+μ(2pE(0)p2)p+μ22Δu22, (56)

    and

    uppCp3Δup2Cp3(2pE(0)p2)p22Δu22, (57)

    where C2, C3 are the Sobolev constant satisfying up+μC2Δu2, upC3Δu2. Substituting (56) and (57) into (55), we get

    L(t)βϵE(t)+(βϵ2+ϵλ1)ut22+ϵ{β2+kβCp3p2(2pE(0)p2)p22+kC2p+μeμ(2pE(0)p2)p+μ221kβC2p+μepμ(2pE(0)p2)p+μ22}Δu22. (58)

    Since E(0)<p22p(eμkC2p+μ)2p+μ2, we have

    kC2p+μeμ(2pE(0)p2)p+μ221<0.

    Taking β>0 small sufficiently such that

    β2+kβCp3p2(2pE(0)p2)p22+kC2p+μeμ(2pE(0)p2)p+μ221<0.

    Now, choosing ϵ>0 small sufficiently such that

    βϵ2+ϵλ1<0.

    Thus, combining with (54), we have

    L(t)βεE(t)βεα2L(t). (59)

    Integrating (59) over (0,t), we can deduce that there exist K1=L(0)α1 and K2=βεα2 such that

    E(t)K1eK2t,forallt[0,+).

    This completes the proof of Theorem 2.3.

    In this section, we prove Theorem 2.4, which implies that the solution u of problem (1) blow up in finite time. Firstly, we need to introduce the following lemma.

    Lemma 5.1. [23] Let F(t) be a positive C2 function satisfying the inequality

    F(t)F(t)(1+α)[F(t)]20,

    for some α>0. If F(0)>0 and F(0)>0, then there exists a time TF(0)αF(0) such that limtTF(t)=.

    Now, let us prove the theorem 2.4.

    Proof of Theorem 2.4. By contradiction, we suppose that u is global. For any T>0, we consider the auxiliary function F:[0,T]R+ defined by

    F(t)=u22+t0u22dτ+(Tt)u022+b(t+T0)2, (60)

    where b>0 and T0>0, which will be specified later.

    Obviously, F(t)>0 for any t[0,T]. Through a direct calculation, we obtain

    F(t)=2Ωuutdx+2t0Ωuutdxdτ+2b(t+T0),
    F(t)=2Ω|ut|2dx+2Ωuttudx2ΩuΔutdx+2b=2Ω|ut|2dx+2Ωu[|u|p2ulog|u|kΔ2u]dx+2b=2Ω|ut|2dx+2Ω|u|plog|u|kdx2Ω|Δu|2dx+2b=2ut222I(u)+2b.

    Using Schwarz's inequality and Young inequality, we have

    (F(t))24=(Ωuutdx+t0Ωuutdxdτ+b(t+T0))2(u22+t0u22dτ+b(t+T0)2)(ut22+t0ut22dτ+b)F(t)(ut22+t0ut22dτ+b).

    Hence,

    F(t)F(t)p+24[F(t)]2F(t)(F(t)(p+2)(ut22+t0ut22dτ+b))=F(t)(2Ω|ut|2dx+2Ω|u|plog|u|kdx2Ω|Δu|2dx(p+2)ut22(p+2)t0ut22dτpb)
    =F(t)(put222Δu22+2Ω|u|plog|u|kdx(p+2)t0ut22dτpb). (61)

    Let

    ξ(t)=put222Δu22+2Ω|u|plog|u|kdx(p+2)t0ut22dτpb,

    by the definition of E(t) and (17), we have

    ξ(t)=(p2)Δu222pE(t)(p+2)t0ut22dτ+2kpupppb=(p2)Δu222pE(0)+(p2)t0ut22dτ+2kpupppb. (62)

    From I(u0)<0 and Lemma 2.9, we know uV, which implies that I(u)<0. By Lemma 2.5, there exists a λ(0,1) such that I(λu)=0. Hence, we have

    (p22p)Δu22+kp2uppJ(λu)d. (63)

    Combined with (63), we get

    ξ(t)=(p2)Δu222pE(0)+(p2)t0ut22dτ+2kpupppb(p2)Δu222pE(0)+2kpupppb2pd2pE(0)pb. (64)

    Choosing b>0 sufficiently small such that 0<b2d2E(0), we have ξ(t)0.

    Thus, by the above discussion, we obtain

    F(t)F(t)p+24[F(t)]20.

    By the definition of F(t), F(0)=u022+Tu022+bT20>0, we choose T0 sufficiently large, which satisfies

    T0>(p2)(u022+u122)+4u0222(p2)b, (65)

    thus, F(0)=2bT0+2Ωu0u1dx2bT0u022u122>0.

    According to Lemma 5.1, we conclude that

    limtTF(t)=, (66)

    for

    T4F(0)(p2)F(0)=2bT02+2u022+2Tu022(p2)(bT0+Ωu0u1dx).

    Hence, we deduce that

    T2bT02+2u022(p2)(bT0+Ωu0u1dx)2u022. (67)

    By (60), (66) and (67), we have

    limtTu22=,

    which contradicts the assumption of u being global. Hence, the solution u of problem (1) blow up in finite time. This completes the proof of Theorem 2.4.

    We are very grateful to the anonymous referees for their valuable suggestions that improved the article. The work is supported by the fund of the "Thirteen Five" Scientific and Technological Research Planning Project of the Department of Education of Jilin Province in China [number JJKH20190547KJ and JJKH20200727KJ].



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