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Exploring fractional Advection-Dispersion equations with computational methods: Caputo operator and Mohand techniques

  • This study presented a comprehensive analysis of nonlinear fractional systems governed by the advection-dispersion equations (ADE), utilizing the Mohand transform iterative method (MTIM) and the Mohand residual power series method (MRPSM). By incorporating the Caputo fractional derivative, we enhanced the modeling capability for fractional-order differential equations, accounting for nonlocal effects and memory in the systems dynamics. We demonstrated that both MTIM and MRPSM were effective for solving fractional ADEs, providing accurate numerical solutions that were validated against exact results. The steady-state solutions, complemented by graphical representations, highlighted the behavior of the system for varying fractional orders and showcased the flexibility and robustness of the methods. These findings contributed significantly to the field of computational physics, offering powerful tools for tackling complex fractional-order systems and advancing research in related fields.

    Citation: Azzh Saad Alshehry, Humaira Yasmin, Ali M. Mahnashi. Exploring fractional Advection-Dispersion equations with computational methods: Caputo operator and Mohand techniques[J]. AIMS Mathematics, 2025, 10(1): 234-269. doi: 10.3934/math.2025012

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  • This study presented a comprehensive analysis of nonlinear fractional systems governed by the advection-dispersion equations (ADE), utilizing the Mohand transform iterative method (MTIM) and the Mohand residual power series method (MRPSM). By incorporating the Caputo fractional derivative, we enhanced the modeling capability for fractional-order differential equations, accounting for nonlocal effects and memory in the systems dynamics. We demonstrated that both MTIM and MRPSM were effective for solving fractional ADEs, providing accurate numerical solutions that were validated against exact results. The steady-state solutions, complemented by graphical representations, highlighted the behavior of the system for varying fractional orders and showcased the flexibility and robustness of the methods. These findings contributed significantly to the field of computational physics, offering powerful tools for tackling complex fractional-order systems and advancing research in related fields.



    Many kinds of mathematical models have been developed to assist in the realization of some known physical phenomena. The derivatives of unknown functions are involved in these models, even though they yield differential equations (DEs). Since their development, the DEs have become an essential area of mathematics [1]. Soon after the Newtonian variable equations were developed in the 1670s, Leibniz and the Bernoulli brothers started working on DEs in the early 1680s. As a result, several writers created a variety of applications in engineering and mechanical subjects, which in turn enhanced the Leibnizian legacy and increased its multivariate form in the modern era [1]. Despite being more broad than ordinary differential equations (ODEs), partial differential equations (PDEs) typically require a distinct approach to be solved [2,3,4]. They encompass solving problems involving several independent variables, making them more difficult and complex even when the subject matter is vast and important. In fact, PDE solutions have drawn a lot of attention from scientists since certain phenomena have found a way to be expressed through them [5]. The two most well-known examples of linear PDEs are heat and wave equations, whereas the most well-known examples of nonlinear PDEs include Schrodinger, Poisson, Korteweg-de Vries, water wave, Dirac, Fisher, and Klein-Gordon [6,7,8]. Since many PDE types lack exact solutions, a variety of analytical and numerical techniques are described to introduce approximate solutions for both linear and nonlinear PDEs [9,10]. These techniques include the Laplace transforms (LT) approach [11], Fourier transform technique [12], homotopy perturbation and analysis method [13,14,15], operational calculus method [16], operational matrix method [17], Adomian decomposition method [18], the residual power series (RPS) method [19], and variational iteration method [20]. Fractional-order differential equations have emerged as powerful tools for modeling complex dynamical systems in diverse fields such as fluid mechanics, wave propagation, and control theory. Recent advancements have focused on developing analytical and numerical methods to explore the behavior of these systems. Studies like Alshammari et al. [21] and Qin et al. [22] have highlighted innovative approaches for solving fractional-order nonlinear systems, while others, such as Alderremy et al. [23], have employed series solutions to tackle reaction-diffusion models. The exploration of coupled systems, as presented by Al-Sawalha et al. [24], and soliton solutions for perturbed equations, as investigated by Yasmin et al. [25], demonstrates the breadth of applications for fractional calculus. Furthermore, techniques for controlling fractional evolution equations [26] and analyzing fractional Navier-Stokes equations [27] have significantly advanced the field. Recent works continue to extend these methodologies to electrical engineering [28,29,30], nonlinear control systems [31,32], and predictive modeling [34,35]. These contributions underscore the growing importance and versatility of fractional-order systems in solving real-world problems across various disciplines.

    The advection-dispersion equation (ADE) is derived from the study of particle dispersion and advection occurring simultaneously when particles move in a fluid according to Brownian motion. Since solute transport in anomalous diffusion is faster than the estimated square root of time provided by Baeumer et al. [36], the fractional ADE (FADE) provides a better description of the phenomena of anomalous diffusion of particles in the transport process. Numerous environmental problems have been studied using this equation, including groundwater contamination, chemical solute diffusion, smoke and dust pollution of the atmosphere, and pollutant discharges [37]. Thus, a number of academics are becoming interested in FADE.

    DpΩΨ(Φ,Ω)k a2Ψ(Φ,Ω)Φ2+jΨ(Φ,Ω)Φ=0, where  0<p1. (1.1)

    where Ω is time, Φ is the spatial domain, Ψ is the solute concentration, k, j are the average dispersion coefficient and fluid velocity, and "a" is the parameter that determines the order of the time-fractional derivatives and the space-fractional derivatives. We look at the fractional derivative in the Caputo sense. The generic response expression has parameters that govern the order of fractional derivatives, and these parameters can be varied to produce a variety of outcomes. When p = 1, the fractional equation reduces to the typical ADE. The basic solutions of the ADE over time will be Gaussian densities whose variances and means depend on the values of the macroscopic transport coefficients k and j. The space-time FADE has already been examined by several writers.

    The residual power series method (RPSM) was founded by Omar Abu Arqub [38] in 2013. It is created by combining the Taylor series with the residual error function. An infinite convergence series provides a solution to DEs. The study of fractional-order differential equations continues to gain prominence due to their ability to model systems with memory and hereditary properties. Innovative analytical and numerical methods have been developed to address these equations, such as the iterative techniques presented by Arqub et al. [39] and El-Ajou et al. [40]. Residual power series methods have proven effective for constructing solutions, as demonstrated by Xu et al. [41] and Zhang et al. [42]. Additionally, the analysis of physical models with temporal and spatial memory effects [43,44], as well as bifurcation studies of fractional systems [45], highlights the versatility of fractional calculus in capturing complex dynamics. Recent advancements, including hybrid techniques like Laplace transform combined with power series approaches [46,47,48], further extend the applicability of these methods to nonlinear and multidimensional systems. These contributions underline the significant progress in solving fractional problems across various fields, from physics to engineering.

    In this work, we introduce a novel approach that combines the RPSM with the Mohand transform to approximate solutions to FADEs. It is evident that this computational series provides an accurate solution after only a limited number of iterations, and the resulting series converges rapidly.

    A key challenge with existing methodologies is the computational complexity and the substantial effort required for their implementation. Our contribution is the development of a new iterative approach for solving FADEs, termed the Mohand transform iterative method (MTIM). By incorporating the Mohand transform into this iterative process, we reduce both the computational complexity and the required effort, offering a more efficient solution.

    In this paper, we solve the FADEs using both the Mohand RPSM (MRPSM) and MTIM. Through comparison with other numerical techniques, we demonstrate that these methods outperform existing approaches in terms of accuracy. A detailed comparison analysis of the numerical results further supports the effectiveness and reliability of the proposed methods. The appeal of fractional-order derivatives increases as their value rises, and our algorithms are fast, accurate, user-friendly, and resilient to computational errors. This advancement will aid mathematicians in solving a wide range of PDEs more effectively.

    An overview of the Mohand transform (MT) and its key concepts will be given below to lay the groundwork for this process.

    Definition 2.1. The MT is defined by the integral equation:

    M{Ψ(Ω)}=s20esΩΨ(Ω)dΩ=Φ(s)

    Definition 2.2. The inverse MT is given by:

    Ψ(Ω)=M1{Φ(s)}=12πic+ici1s2esΩΦ(s)ds,cR

    where M1 is the inverse operator of MT.

    Definition 2.3. [50]: The MT equation has the following fractional derivative:

    M[Ψp(Ω)]=spR(s)n1k=0Ψk(0)sk(p+1), 0<pn

    Definition 2.4. Some of the features relating to MT are as follows:

    1. M[Ψ(Ω)]=sR(s)s2R(0),

    2. M[Ψ(Ω)]=s2R(s)s3R(0)s2R(0),

    3. M[Ψn(Ω)]=snR(s)sn+1R(0)snR(0)snRn1(0).

    Lemma 2.1. Ψ(Φ,Ω) denotes the exponential order function. The equation M[R(s)]=Ψ(Φ,Ω) describes the MT in this context.

    M[DrpΩΨ(Φ,Ω)]=srpR(s)r1j=0sp(rj)1DjpΩΨ(Φ,0),0<p1, (2.1)

    where Φ=(Φ1,Φ2,,Φp)Rp, pN, and DrpΩ=DpΩ.DpΩ..DpΩ(rtimes)

    Proof. Using mathematical induction, it is feasible to verify Eq 2.1. The subsequent results are obtained when r=1 is placed into Eq 2.1:

    M[D2pΩΨ(Φ,Ω)]=s2pR(s)s2p1Ψ(Φ,0)sp1DpΩΨ(Φ,0).

    The definition 2.3 indicates that Eq 2.1 is valid for r=1. When r=2 is substituted into Eq 2.1, we get:

    M[D2prΨ(Φ,Ω)]=s2pR(s)s2p1Ψ(Φ,0)sp1DpΩΨ(Φ,0). (2.2)

    Using Eq 2.2 left-hand side (L.H.S), the resulting expression is achieved.

    L.H.S=M[D2pΩΨ(Φ,Ω)]. (2.3)

    Equation 2.3 can also be written as:

    L.H.S=M[DpΩΨ(Φ,Ω)]. (2.4)

    Assume

    z(Φ,Ω)=DpΩΨ(Φ,Ω). (2.5)

    Hence, Eq 2.4 becomes

    L.H.S=M[DpΩz(Φ,Ω)]. (2.6)

    The Caputo derivative leads to the modification of Eq 2.6.

    L.H.S=M[J1pz(Φ,Ω)]. (2.7)

    The Riemann-Liouville (R-L) integral for MT is given by Eq 2.7, from which more details can be derived:

    L.H.S=M[z(Φ,Ω)]s1p. (2.8)

    By employing the differentiability characteristic of the MT, the subsequent expression of Eq 2.8 is derived:

    L.H.S=spZ(Φ,s)z(Φ,0)s1p, (2.9)

    Equation 2.5 is employed to obtain the following outcome.

    Z(Φ,s)=spR(s)Ψ(Φ,0)s1p,

    In this case, M[z(Ω,Φ)]=Z(Φ,s). Thus, Eq 2.9 is modified to the following form:

    L.H.S=s2pR(s)Ψ(Φ,0)s12pDpΩΨ(Φ,0)s1p, (2.10)

    For r=K, both Eqs 2.1 and 2.10 are consistent. Suppose that for r=K, Eq 2.1 is true. So, put r=K in Eq 2.1

    M[DKpΩΨ(Φ,Ω)]=sKpR(s)K1j=0sp(Kj)1DjpΩDjpΩΨ(Φ,0), 0<p1. (2.11)

    Finally, we have to show that Eq 2.1 is true for r=K+1. We may write Eq 2.1 as:

    M[D(K+1)pΩΨ(Φ,Ω)]=s(K+1)pR(s)Kj=0sp((K+1)j)1DjpΩΨ(Φ,0). (2.12)

    The following outcome is obtained by examining the left side of Eq 2.12.

    L.H.S=M[DKpΩ(DKpΩ)]. (2.13)

    Let

    DKpΩ=g(Φ,Ω).

    From Eq 2.13, we obtain:

    L.H.S=M[DpΩg(Φ,Ω)]. (2.14)

    Eq 2.14 can yield the subsequent outcome by employing the R-L integral and the Caputo derivative.

    L.H.S=spM[DKpΩΨ(Φ,Ω)]g(Φ,0)s1p. (2.15)

    By utilizing Eq 2.11, it is feasible to get Eq 2.15.

    L.H.S=srpR(s)r1j=0sp(rj)1DjpΩΨ(Φ,0), (2.16)

    This result was obtained by solving the Eq 2.16.

    L.H.S=M[DrpΩΨ(Φ,0)].

    It is proved that Eq 2.1 is true for r=K+1. Therefore, Eq 2.1 is valid for all positive integers when the mathematical induction method is applied.

    Lemma 2.2. Let the function Ψ(Φ,Ω) be exponential order and the MT be Ψ(Φ,Ω) is M[Ψ(Φ,Ω)]=R(s). Then, the following is the MT representation in the multiple fractional Taylor series (MFTS) form:

    R(s)=r=0r(Φ)srp+1,s>0, (2.17)

    where, Φ=(s1,Φ2,,Φp)Rp, pN.

    Proof. Suppose this form of Taylor's series:

    Ψ(Φ,Ω)=0(Φ)+1(Φ)ΩpΓ[p+1]++2(Φ)Ω2pΓ[2p+1]+. (2.18)

    We obtain the following outcome when MT is applied on Eq 2.18:

    M[Ψ(Φ,Ω)]=M[0(Φ)]+M[1(Φ)ΩpΓ[p+1]]+M[1(Φ)Ω2pΓ[2p+1]]+

    When the MT's features are utilized, the following results are obtained:

    M[Ψ(Φ,Ω)]=0(Φ)1s+1(Φ)Γ[p+1]Γ[p+1]1sp+1+2(Φ)Γ[2p+1]Γ[2p+1]1s2p+1

    As a result, an MT-specific form of Taylor's series is produced, denoted as Eq 2.17.

    Lemma 2.3. M[Ψ(Φ,Ω)]=R(s) is the new form of Taylor's series 2.17, which is used to represent the multiple fractional power series (MFPS).

    0(Φ)=limssR(s)=Ψ(Φ,0). (2.19)

    Proof. The modified new form of Taylor's series is as follows:

    0(Φ)=sR(s)1(Φ)sp2(Φ)s2p (2.20)

    The required solution, which can be determined as limx, is implemented through Eq 2.19 and a short computation, as illustrated in 2.20.

    Theorem 2.4. Consider the function M[Ψ(Φ,Ω)], then the R(s) denoted in MFPS form is given below:

    R(s)=r=0r(Φ)srp+1, s>0,

    where Φ=(Φ1,Φ2,,Φp)Rp and pN. Then, we have

    r(Φ)=DrprΨ(Φ,0),

    where, DrpΩ=DpΩ.DpΩ..DpΩ(rtimes).

    Proof. Consider the Taylor series:

    1(Φ)=sp+1R(s)sp0(Φ)2(Φ)sp3(Φ)s2p (2.21)

    Taking lims of Eq 2.21 to deduce:

    1(Φ)=lims(sp+1R(s)sp0(Φ))lims2(Φ)splims3(Φ)s2p

    we get the following equality by taking the limit:

    1(Φ)=lims(sp+1R(s)sp0(Φ)). (2.22)

    Lemma 2.1 and Eq 2.22 are used to get the following outcome:

    1(Φ)=lims(sM[DpΩΨ(Φ,Ω)](s)). (2.23)

    Eq 2.23 is further modified using Lemma 2.2:

    1(Φ)=DpΩΨ(Φ,0).

    By employing the lims and using Taylor series once more, we deduce:

    2(Φ)=s2p+1R(s)s2p0(Φ)sp1(Φ)3(Φ)sp

    Lemma 2.2 is used to obtain:

    2(Φ)=limss(s2pR(s)s2p10(Φ)sp11(Φ)). (2.24)

    In a specific way, we use Eq 2.3 and Lemma 2.1 to make the following changes in Eq 2.24:

    2(Φ)=D2pΩΨ(Φ,0).

    Using the same process, we can get:

    3(Φ)=limss(M[D2pΩΨ(Φ,p)](s)).

    To obtain the final result, we use Lemma 2.3:

    3(Φ)=D3pΩΨ(Φ,0).

    Generally,

    r(Φ)=DrpΩΨ(Φ,0).

    Proved.

    The following theorem contains a description and illustration of the concepts that affect the convergence of the modified version of Taylor's series.

    Theorem 2.5. In Lemma 2.2, a formula for MFTS is provided and can be expressed as follows: M[Ψ(Ω,Φ)]=R(s). When |saM[D(K+1)pΩΨ(Φ,Ω)]|T, for all s>0 and 0<p1, the residual HK(Φ,s) of the new MFTS satisfied the inequality:

    |HK(Φ,s)|Ts(K+1)p+1, s>0.

    Proof. Consider M[DrpΩΨ(Φ,Ω)](s) is defined on s>0 for r=0,1,2,,K+1 and suppose |sM[DΩK+1Ψ(Φ,Ω)]|T. This relationship can be found by employing the revised Taylor's series:

    HK(Φ,s)=R(s)Kr=0r(Φ)srp+1. (2.25)

    Theorem 2.4 is employed to transform Eq 2.25.

    HK(Φ,s)=R(s)Kr=0DrpΩΨ(Φ,0)srp+1. (2.26)

    To resolve this problem, multiply both sides by s(K+1)a+1 in order to obtain:

    s(K+1)p+1HK(Φ,s)=s(s(K+1)pR(s)Kr=0s(K+1r)p1DrpΩΨ(Φ,0)). (2.27)

    Lemma 2.1 is applied to Eq 2.27 to obtain the subsequent result:

    s(K+1)p+1HK(Φ,s)=sM[D(K+1)pΩΨ(Φ,Ω)]. (2.28)

    Calculating the absolute value of Eq 2.28 yields the following:

    |s(K+1)p+1HK(Φ,s)|=|sM[D(K+1)pΩΨ(Φ,Ω)]|. (2.29)

    The subsequent result is obtained by using the condition from Eq 2.29.

    Ts(K+1)p+1HK(Φ,s)Ts(K+1)p+1. (2.30)

    From Eq 2.30, we get.

    |HK(Φ,s)|Ts(K+1)p+1.

    In this way, a novel condition for the series' convergence is established.

    This section outlines the process of constructing the MT with RPSM in order to provide an approximate solution to PDEs.

    Step 1: Consider the PDE:

    DpΩΨ(Φ,Ω)+ϑ(Φ)N(Ψ)δ(Φ,Ψ)=0, (3.1)

    Step 2: Taking the MT of Eq 3.1 to obtain:

    M[DpΩΨ(Φ,Ω)+ϑ(Φ)N(Ψ)δ(Φ,Ψ)]=0, (3.2)

    Using Lemma 2.1, we can get the following result:

    R(s)=q1j=0DjΩΨ(Φ,0)sjp+1ϑ(Φ)Y(s)sjp+F(Φ,s)sjp, (3.3)

    where, M[δ(Φ,Ψ)]=F(Φ,s),M[N(Ψ)]=Y(s).

    Step 3: Solving Eq 3.3, we deduce:

    R(s)=r=0r(Φ)srp+1, s>0,

    Step 4: Now, use the following procedure to obtain the solution:

    0(Φ)=limssR(s)=Ψ(Φ,0),

    Utilize Theorem 2.5 to get the subsequent result:

    1(Φ)=DpΩΨ(Φ,0),2(Φ)=D2pΩΨ(Φ,0),w(Φ)=DwpΩΨ(Φ,0),

    Step 5: To get the Kth truncated series R(s), apply the following formula:

    RK(s)=Kr=0r(Φ)srp+1, s>0,RK(s)=0(Φ)s+1(Φ)sp+1++w(Φ)swp+1+Kr=w+1r(Φ)srp+1,

    Step 6: Determine the following by calculating the Mohand residual function (MRF) from 3.3 separately of the Kth-truncated Mohand residual function:

    MRes(Φ,s)=R(s)q1j=0DjΩΨ(Φ,0)sjp+1+ϑ(Φ)Y(s)sjpF(Φ,s)sjp,

    and

    MResK(Φ,s)=RK(s)q1j=0DjΩΨ(Φ,0)sjp+1+ϑ(Φ)Y(s)sjpF(Φ,s)sjp. (3.4)

    Step 7: Instead of its expansion form, Eq 3.4 can be formulated in terms of RK(s).

    MResK(Φ,s)=(0(Φ)s+1(Φ)sp+1++w(Φ)swp+1+Kr=w+1r(Φ)srp+1)q1j=0DjΩΨ(Φ,0)sjp+1+ϑ(Φ)Y(s)sjpF(Φ,s)sjp. (3.5)

    Step 8: Multiplying sKp+1 with Eq 3.5:

    sKp+1MResK(Φ,s)=sKp+1(0(Φ)s+1(Φ)sp+1++w(Φ)swp+1+Kr=w+1r(Φ)srp+1q1j=0DjΩΨ(Φ,0)sjp+1+ϑ(Φ)Y(s)sjpF(Φ,s)sjp). (3.6)

    Step 9: Taking lims of Eq 3.6 to obtain:

    limssKp+1MResK(Φ,s)=limssKp+1(0(Φ)s+1(Φ)sp+1++w(Φ)swp+1+Kr=w+1r(Φ)srp+1q1j=0DjΩΨ(Φ,0)sjp+1+ϑ(Φ)Y(s)sjpF(Φ,s)sjp).

    Step 10: K(Φ) values can be obtained using Eq 3.6.

    lims(sKp+1MResK(Φ,s))=0,

    where K=1+w,2+w,.

    Step 11: The Kth-approximation of Eq 3.3 is obtained by substituting K(Φ) with a K-truncated series of R(s).

    Step 12: The final solution ΨK(Φ,Ω) is obtained using the inverse operator of MT.

    Consider the following PDE:

    DpΩΨ(Φ,Ω)=Υ(Ψ(Φ,Ω),DΩΦΨ(Φ,Ω),D2ΩΦΨ(Φ,Ω),D3ΩΦΨ(Φ,Ω)), 0<p,Ω1, (3.7)

    Initial conditions

    Ψ(k)(Φ,0)=hk, k=0,1,2,,m1, (3.8)

    with Ψ(Φ,Ω) denoting the function that we are required to identify, while Υ(Ψ(Φ,Ω),DΩΦΨ(Φ,Ω),D2ΩΦΨ(Φ,Ω),D3ΩΦΨ(Φ,Ω)) are nonlinear or linear operators of Ψ(Φ,Ω),DΩΦΨ(Φ,Ω),D2ΩΦΨ(Φ,Ω) and D3ΩΦΨ(Φ,Ω). The expression that follows is obtained by applying the MT to both sides of Equation 3.7.

    M[Ψ(Φ,Ω)]=1sp(m1k=0Ψ(k)(Φ,0)s1p+k+M[Υ(Ψ(Φ,Ω),DΩΦΨ(Φ,Ω),D2ΩΦΨ(Φ,Ω),D3ΩΦΨ(Φ,Ω))]), (3.9)

    The inverse MT gives the subsequent result in this case:

    Ψ(Φ,Ω)=M1[1sp(m1k=0Ψ(k)(Φ,0)s1p+k+M[Υ(Ψ(Φ,Ω),DΩΦΨ(Φ,Ω),D2ΩΦΨ(Φ,Ω),D3ΩΦΨ(Φ,Ω))])]. (3.10)

    The MTIM gives the infinite series solution as given below.

    Ψ(Φ,Ω)=i=0Ψi. (3.11)

    The operators Υ(Ψ,DΩΦΨ,D2ΩΦΨ,D3ΩΦΨ) decompose as given below:

    Υ(Ψ,DΩΦΨ,D2ΩΦΨ,D3ΩΦΨ)=Υ(Ψ0,DΩΦΨ0,D2ΩΦΨ0,D3ΩΦΨ0)+i=0(Υ(ik=0(Ψk,DΩΦΨk,D2ΩΦΨk,D3ΩΦΨk))Υ(i1k=1(Ψk,DΩΦΨk,D2ΩΦΨk,D3ΩΦΨk))). (3.12)

    By substituting the values of Eq 3.11 and Eq 3.12 in Eq 3.10, the subsequent equation can be obtained.

    i=0Ψi(Φ,Ω)=M1[1sp(m1k=0Ψ(k)(Φ,0)s2p+k+M[Υ(Ψ0,DΩΦΨ0,D2ΩΦΨ0,D3ΩΦΨ0)])]+M1[1sp(M[i=0(Υik=0(Ψk,DΩΦΨk,D2ΩΦΨk,D3ΩΦΨk))])]M1[1sp(M[(Υi1k=1(Ψk,DΩΦΨk,D2ΩΦΨk,D3ΩΦΨk))])] (3.13)
    Ψ0(Φ,Ω)=M1[1sp(m1k=0Ψ(k)(Φ,0)s2p+k)],Ψ1(Φ,Ω)=M1[1sp(M[Υ(Ψ0,DΩΦΨ0,D2ΩΦΨ0,D3ΩΦΨ0)])],Ψi+1(Φ,Ω)=M1[1sp(M[i=0(Υik=0(Ψk,DΩΦΨk,D2ΩΦΨk,D3ΩΦΨk))])]M1[1sp(M[(Υi1k=1(Ψk,DΩΦΨk,D2ΩΦΨk,D3ΩΦΨk))])], i=1,2,. (3.14)

    The following expression can be used to obtain the i-terms of Eq 3.7 analytically:

    Ψ(Φ,Ω)=m1i=0Ψi. (3.15)

    Suppose the following time FADE:

    DpΩΨ(Φ,Ω)a2Ψ(Φ,Ω)Φ2+Ψ(Φ,Ω)Φ=0, where  0<p1. (4.1)

    Initial condition

    Ψ(Φ,0)=eΦ, (4.2)

    and exact solution

    Ψ(Φ,Ω)=e(a+1)ΩΦ. (4.3)

    Eq 4.2 and the MT are used to get the following result from Eq 4.1.

    Ψ(Φ,s)eΦsasp[2Ψ(Φ,s)Φ2]+1sp[Ψ(Φ,s)Φ]=0. (4.4)

    The kth terms of the series that are truncated are:

    Ψ(Φ,s)=eΦs+kr=1fr(Φ,s)srp+1,  r=1,2,3,4. (4.5)

    Residual Mohand function is given by:

    MΩRes(Φ,s)=Ψ(Φ,s)eΦsasp[2Ψ(Φ,s)Φ2]+1sp[Ψ(Φ,s)Φ]=0, (4.6)

    and the kth-MRFs as:

    MΩResk(Φ,s)=Ψk(Φ,s)eΦsasp[2Ψk(Φ,s)Φ2]+1sp[Ψk(Φ,s)Φ]=0. (4.7)

    The following procedures should be implemented to determine the value of fr(Φ,s) for r=1,2,3,...: replace the rth-Mohand residual function Eq 4.7 for the rth-truncated series Eq 4.5, and multiply the expression by srp+1 for solving the relation, lims(srp+1)MΩResΨ,r(Φ,s))=0 for r=1,2,3,. Some terms that we obtain are as follows:

    f1(Φ,s)=(a+1)eΦ, (4.8)
    f2(Φ,s)=(a+1)2eΦ, (4.9)
    f3(Φ,s)=(a+1)3eΦ, (4.10)
    f4(Φ,s)=(a+1)4eΦ, (4.11)

    and so on.

    To obtain the desired result, the function fr(Φ,s) should be substituted into Eq (4.5).

    Ψ(Φ,s)=eΦs+(a+1)eΦsp+1+(a+1)2eΦs2p+1+(a+1)3eΦs3p+1+(a+1)4eΦs4p+1+. (4.12)

    Apply the inverse operator of MT to obtain the final solution:

    Ψ(Φ,Ω)=eΦ+(a+1)ΩpeΦΓ(p+1)+(a+1)2Ω2peΦΓ(2p+1)+(a+1)3Ω3peΦΓ(3p+1)+(a+1)4Ω4peΦΓ(4p+1)+. (4.13)

    Suppose the following time FADE:

    DpΩΨ(Φ,Ω)=a2Ψ(Φ,Ω)Φ2Ψ(Φ,Ω)Φ, where  0<p1. (4.14)

    Initial condition

    Ψ(Φ,0)=eΦ. (4.15)

    Apply the MT on Eq 4.14:

    M[DpΩΨ(Φ,Ω)]=1sp(m1k=0Ψ(k)(Φ,0)s2p+k+M[a2Ψ(Φ,Ω)Φ2Ψ(Φ,Ω)Φ)]). (4.16)

    Apply the inverse operator of MT on Eq 4.16:

    Ψ(Φ,Ω)=M1[1sp(m1k=0Ψ(k)(Φ,η,0)s2p+k+M[a2Ψ(Φ,Ω)Φ2Ψ(Φ,Ω)Φ])]. (4.17)

    Iteratively utilize the MT to get the following result:

    Ψ0(Φ,Ω)=M1[1sp(m1k=0Ψ(k)(Φ,0)s2p+k)]=M1[Ψ(Φ,0)s2]=eΦ.

    Eq 4.14 is solved using the R-L integral to obtain:

    Ψ(Φ,Ω)=eΦ+M[a2Ψ(Φ,Ω)Φ2Ψ(Φ,Ω)Φ]. (4.18)

    Some of the terms that the MITM method produce are as follows:

    Ψ0(Φ,Ω)=eΦ, (4.19)
    Ψ1(Φ,Ω)=(a+1)ΩpeΦΓ(p+1), (4.20)
    Ψ2(Φ,Ω)=(a+1)2Ω2peΦΓ(2p+1), (4.21)
    Ψ3(Φ,Ω)=(a+1)3Ω3peΦΓ(3p+1), (4.22)
    Ψ4(Φ,Ω)=(a+1)4Ω4peΦΓ(4p+1). (4.23)

    The final solution is:

    Ψ(Φ,Ω)=Ψ0(Φ,Ω)+Ψ1(Φ,Ω)+Ψ2(Φ,Ω)+Ψ3(Φ,Ω)+Ψ4(Φ,Ω)+, (4.24)
    Ψ(Φ,Ω)=eΦ+(a+1)ΩpeΦΓ(p+1)+(a+1)2Ω2peΦΓ(2p+1)+(a+1)3Ω3peΦΓ(3p+1)+(a+1)4Ω4peΦΓ(4p+1)+. (4.25)

    Table 1 presents the error comparison between the solutions obtained using the MRPSM and the MTIM for the function Ψ(Φ,Ω). This comparison highlights the accuracy of both methods, where the error values demonstrate that the MTIM and MRPSM provide very close approximations to the exact solution, with MTIM showing slightly lower error in most cases. Figure 1 displays the exact and approximate solutions of Ψ(Φ,Ω), for p=1 and Ω=0.1. Panel (a) presents the exact solution, providing a clear benchmark for comparison, while panel (b) shows the approximate solution obtained using the proposed methods. The graphical comparison indicates that the approximation closely matches the exact solution, highlighting the effectiveness of the methods in capturing the underlying dynamics of the system. Figure 2 offers a side-by-side comparison of the exact and approximate solutions of Ψ(Φ,Ω), for p=1 and Ω=0.1. Panel (a) shows the exact solution, while panel (b) illustrates the approximate solution. The slight deviations between the two solutions in the graph are due to the inherent approximation process, but the overall agreement between them emphasizes the reliability and accuracy of both MRPSM and MTIM. Figure 3 presents a 3D graphical representation of the approximate solution for p of Ψ(Φ,Ω), for Ω=0.1. The 3D plot effectively illustrates how the solution varies with respect to both, providing a visual understanding of the solution's behavior for varying fractional orders. The surface plot reveals smooth transitions and complex interactions between the variables, demonstrating the robustness of the methods in handling fractional-order differential equations. Figure 4 shows a 2D graphical representation of the approximate solution for different values of p of Ψ(Φ,Ω), for Ω=0.1 is presented for multiple fractional orders. The 2D plots highlight how the solution's shape changes with different values of p, providing further insight into the dynamics of fractional systems. The consistency in the graphs demonstrates the stability of the methods over varying parameters. Overall, the graphical results confirm the accuracy and reliability of the MRPSM and MTIM in approximating solutions to the FADEs, providing a comprehensive visual understanding of the solution behavior across different conditions.

    Table 1.  MRPSM and MTIM solution absolute error with exact solution for Ψ(Φ,Ω) of problem 1.
    MRPSM MRPSM MRPSM MRPSM MRPSM MTIM
    Ω Φ Errorp=0.1 Errorp=0.2 Errorp=0.3 Errorp=0.4 Errorp=0.5 Errorp=0.5
    0.01 0 1.8771808 0.8154997 0.4094808 0.2235174 0.1262354 0.1262354
    1 0.6905762 0.3000055 0.1506395 0.0822274 0.0464394 0.0464394
    2 0.2540487 0.1103658 0.0554172 0.0302497 0.0170841 0.0170841
    3 0.0934593 0.0406013 0.0203868 0.0111282 0.0062848 0.0062848
    4 0.0343817 0.0149363 0.0074999 0.0040938 0.0023120 0.0023120
    5 0.0126483 0.0054947 0.0027590 0.0015060 0.0008505 0.0008505
    0.05 0 2.6258573 1.4029278 0.7966979 0.4774295 0.2945283 0.2945283
    1 0.9659989 0.5161082 0.2930888 0.1756365 0.1083509 0.1083509
    2 0.3553711 0.1898656 0.1078213 0.0646130 0.0398600 0.0398600
    3 0.1307337 0.0698476 0.0396652 0.0237698 0.0146637 0.0146637
    4 0.0480942 0.0256955 0.0145920 0.0087444 0.0053944 0.0053944
    5 0.0176928 0.0094528 0.0053681 0.0032168 0.0019845 0.0019845
    0.10 0 3.0338831 1.8058633 1.0962378 0.6851275 0.4362119 0.4362119
    1 1.1161032 0.6643399 0.4032833 0.2520443 0.1604734 0.1604734
    2 0.4105914 0.2443970 0.1483596 0.0927219 0.0590348 0.0590348
    3 0.1510481 0.0899086 0.0545784 0.0341104 0.0217177 0.0217177
    4 0.0555675 0.0330755 0.0200782 0.0125485 0.0079895 0.0079895
    5 0.0204421 0.0121678 0.0073863 0.0046163 0.0029391 0.0029391

     | Show Table
    DownLoad: CSV
    Figure 1.  Graphical representation of approximate solution and exact solution for different values of p of Ψ(Φ,Ω) for Ω=0.1.
    Figure 2.  Graphical representation of approximate solution and exact solution for different values of p of Ψ(Φ,Ω) for Ω=0.1.
    Figure 3.  Graphical representation of approximate solution and exact solution for p=0.9 of Ψ(Φ,Ω) for Ω=0.1.
    Figure 4.  2D comparison of approximate solution for different values of p of Ψ(Φ,Ω) for Ω=0.1.

    Table 2 provides a solution comparison for the fractional order p of Ψ(Φ,Ω) using both the MRPSM and the MTIM for Ω=0.1. The comparison reveals that both methods yield highly similar results, with slight variations depending on the fractional order p. This table reinforces the reliability and accuracy of both methods in approximating the solution, showing that both MRPSM and MTIM are effective in solving fractional-order differential equations. Figure 5 illustrates the solutions of Ψ(Φ,Ω) for p=1 and Ω=0.1 using both MRPSM and MTIM. Panel (a) shows the MRPSM solution, while panel (b) presents the MTIM solution. Both graphs exhibit nearly identical solution profiles, demonstrating the consistency between the two methods. The solutions are smooth and exhibit the expected characteristics of the FADEs, confirming that both methods provide accurate approximations. Figure 6 provides a side-by-side comparison of the MRPSM and MTIM solutions for Ψ(Φ,Ω) for p=1 and Ω=0.1. Panel (a) shows the MRPSM solution, while panel (b) shows the MTIM solution. The visual comparison reinforces the earlier finding that both methods produce nearly identical results, validating that MTIM and MRPSM are robust and reliable for this problem. The solutions' close agreement further suggests that either method can be used for efficient computation of FADEs.

    Table 2.  MRPSM and MTIM solution absolute error with exact solution for Ψ(Φ,Ω) of problem 1.
    MRPSM MRPSM MRPSM MRPSM MRPSM MTIM
    Ω Φ Errorp=0.6 Errorp=0.7 Errorp=0.8 Errorp=0.9 Errorp=1.0 Errorp=1.0
    0.01 0 0.0711952 0.0387171 0.0191468 0.0072487 1.344480×1012 1.344480×1012
    1 0.0261912 0.0142432 0.0070437 0.0026666 4.946598×1013 4.946598×1013
    2 0.0096352 0.0052397 0.0025912 0.0009810 1.819377×1013 1.819377×1013
    3 0.0035446 0.0019276 0.0009532 0.0003608 6.694644×1014 6.694644×1014
    4 0.0013039 0.0007091 0.0003506 0.0001327 2.463307×1014 2.463307×1014
    5 0.0004797 0.0002608 0.0001290 0.0000488 9.061328×1015 9.061328×1015
    0.05 0 0.1816240 0.1080370 0.0583301 0.0240053 4.232785×109 4.232785×109
    1 0.0668158 0.0397445 0.0214584 0.0088310 1.557154×109 1.557154×109
    2 0.0245802 0.0146212 0.0078941 0.0032487 5.728452×1010 5.728452×1010
    3 0.0090425 0.0053788 0.0029040 0.0011951 2.107380×1010 2.107380×1010
    4 0.0033265 0.0019787 0.0010683 0.0004396 7.752618×1011 7.752618×1011
    5 0.0012237 0.0007279 0.0003930 0.0001617 2.852028×1011 2.852028×1011
    0.10 0 0.2767880 0.1693540 0.0940604 0.0398121 1.367088×107 1.3670887×107
    1 0.1018250 0.0623018 0.0346029 0.0146460 5.029238×108 5.0292383×108
    2 0.0374592 0.0229195 0.0127297 0.0053879 1.850153×108 1.8501533×108
    3 0.0137805 0.0084316 0.0046829 0.0019821 6.806333×109 6.8063339×109
    4 0.0050695 0.0031018 0.0017227 0.0007291 2.503910×109 2.5039103×109
    5 0.0018649 0.0011411 0.0006337 0.0002682 9.211371×1010 9.2113713×1010

     | Show Table
    DownLoad: CSV
    Figure 5.  (a) Exact solution and (b) approximate solution of Ψ(Φ,Ω) for p=1 and Ω=0.1.
    Figure 6.  (a) Exact solution and (b) approximate solution comparison of Ψ(Φ,Ω) for p=1 and Ω=0.1.

    Suppose the following time FADE:

    DpΩΨ(Φ,Ω)a2Ψ(Φ,Ω)Φ2+Ψ(Φ,Ω)Φ=0, where  0<p1. (4.26)

    Initial condition

    Ψ(Φ,0)=Φ3Φ2, (4.27)

    Eq 4.27 and the MT is used to get the following result from Eq (4.26).

    Ψ(Φ,s)Φ3Φ2sasp[2Ψ(Φ,s)Φ2]+1sp[Ψ(Φ,s)Φ]=0. (4.28)

    The kth terms of the series that are truncated are:

    Ψ(Φ,s)=Φ3Φ2s+kr=1fr(Φ,s)srp+1,  r=1,2,3,4. (4.29)

    Residual Mohand function is given by:

    MΩRes(Φ,s)=Ψ(Φ,s)Φ3Φ2sasp[2Ψ(Φ,s)Φ2]+1sp[Ψ(Φ,s)Φ]=0, (4.30)

    and the kth-MRFs as:

    MΩResk(Φ,s)=Ψk(Φ,s)Φ3Φ2sasp[2Ψk(Φ,s)Φ2]+1sp[Ψk(Φ,s)Φ]=0. (4.31)

    The following procedures should be implemented to determine the value of fr(Φ,s) for r=1,2,3,...: replace the rth-Mohand residual function Eq 4.31 for the rth-truncated series Eq 4.29, and multiply the expression by srp+1 for solving the relation, lims(srp+1)MΩResΨ,r(Φ,s))=0 for r=1,2,3,. Some terms that we obtain are as follows:

    f1(Φ,s)=a(6Φ2)+Φ(23Φ), (4.32)
    f2(Φ,s)=12a+6Φ2, (4.33)
    f3(Φ,s)=6, (4.34)
    f4(Φ,s)=0, (4.35)

    and so on.

    To obtain the desired result, the function fr(Φ,s) should be substituted into Eq (4.29).

    Ψ(Φ,s)=Φ3Φ2s+a(6Φ2)+Φ(23Φ)sp+1+12a+6Φ2s2p+16s3p+1+0s4p+1+. (4.36)

    Apply the inverse operator of MT to obtain the final solution:

    Ψ(Φ,Ω)=(Φ1)Φ2+(a(6Φ2)+Φ(23Φ))ΩpΓ(p+1)2(6a3Φ+1)Ω2pΓ(2p+1)6Ω3pΓ(3p+1)+. (4.37)

    Suppose the following time FADE:

    DpΩΨ(Φ,Ω)=a2Ψ(Φ,Ω)Φ2Ψ(Φ,Ω)Φ, where  0<p1. (4.38)

    Initial condition

    Ψ(Φ,0)=Φ3Φ2. (4.39)

    Apply the MT on Eq 4.38:

    M[DpΩΨ(Φ,Ω)]=1sp(m1k=0Ψ(k)(Φ,0)s2p+k+M[a2Ψ(Φ,Ω)Φ2Ψ(Φ,Ω)Φ)]). (4.40)

    Apply the inverse operator of MT on Eq 4.40:

    Ψ(Φ,Ω)=M1[1sp(m1k=0Ψ(k)(Φ,η,0)s2p+k+M[a2Ψ(Φ,Ω)Φ2Ψ(Φ,Ω)Φ])]. (4.41)

    Iteratively utilize the MT to get the following result:

    Ψ0(Φ,Ω)=M1[1sp(m1k=0Ψ(k)(Φ,0)s2p+k)]=M1[Ψ(Φ,0)s2]=Φ3Φ2.

    Eq 4.38 is solved using the R-L integral to obtain:

    Ψ(Φ,Ω)=Φ3Φ2+M[a2Ψ(Φ,Ω)Φ2Ψ(Φ,Ω)Φ]. (4.42)

    Some of the terms that the MITM method produces are as follows:

    Ψ0(Φ,Ω)=Φ3Φ2, (4.43)
    Ψ1(Φ,Ω)=(a(6Φ2)+Φ(23Φ))ΩpΓ(p+1), (4.44)
    Ψ2(Φ,Ω)=2(6a3Φ+1)Ω2pΓ(2p+1), (4.45)
    Ψ3(Φ,Ω)=6Ω3pΓ(3p+1), (4.46)
    Ψ4(Φ,Ω)=0. (4.47)

    The final solution is:

    Ψ(Φ,Ω)=Ψ0(Φ,Ω)+Ψ1(Φ,Ω)+Ψ2(Φ,Ω)+Ψ3(Φ,Ω)+Ψ4(Φ,Ω)+, (4.48)
    Ψ(Φ,Ω)=(Φ1)Φ2+(a(6Φ2)+Φ(23Φ))ΩpΓ(p+1)2(6a3Φ+1)Ω2pΓ(2p+1)6Ω3pΓ(3p+1)+. (4.49)

    Figure 7 presents a 3D graphical representation of the approximate solution for Ψ(Φ,Ω) for p=1 and Ω=0.1 constant. The 3D plot effectively demonstrates how the solution changes as the fractional order p varies. The surface reveals the intricate relationships between p and the solution, showcasing how the solution becomes more complex with increasing fractional order. This 3D representation highlights the flexibility of the methods in handling different fractional orders.

    Figure 7.  Graphical representation of approximate solution for different values of p of Ψ(Φ,Ω) for Ω=0.1.

    Figure 8 shows a 2D graphical representation of the approximate solution for varying fractional orders p of Ψ(Φ,Ω) for Ω=0.1. The 2D plots provide a clearer view of the solutions dependence on the fractional order p, allowing for an intuitive understanding of how the solution evolves as p changes. These plots help visualize the impact of fractional derivatives on the solution and demonstrate the power of both MRPSM and MTIM in modeling fractional systems. Figure 9, graphical representation of approximate solution for different values of p of Ψ(Φ,Ω) for Ω=0.1. Figure 10, (a) MRPSM solution and (b) MTIM solution of Ψ(Φ,Ω) for p=1 and Ω=0.1. Figure 11, (a) MRPSM solution and (b) MTIM solution comparison of Ψ(Φ,Ω) for p=1 and Ω=0.1. Table 3, the approximate solution comparison for the fractional order p of Ψ(Φ,Ω) for Ω=0.1 of problem 2. Table 4, the approximate solution comparison for the fractional order p of Ψ(Φ,Ω) for Ω=0.1 of problem 2.

    Figure 8.  Graphical representation of approximate solution for different values of p of Ψ(Φ,Ω) for Ω=0.1.
    Figure 9.  Graphical representation of approximate solution for different values of p of Ψ(Φ,Ω) for Ω=0.1.
    Figure 10.  (a) MRPSM solution and (b) MTIM solution of Ψ(Φ,Ω) for p=1 and Ω=0.1.
    Figure 11.  (a) MRPSM solution and (b) MTIM solution comparison of Ψ(Φ,Ω) for p=1 and Ω=0.1.
    Table 3.  The approximate solution comparison for the fractional order p of Ψ(Φ,Ω) for Ω=0.1 of problem 2.
    Φ MRPSMp=0.1 MRPSMp=0.2 MRPSMp=0.3 MRPSMp=0.4 MRPSMp=0.5 MTIMp=0.5
    0.1 -4.2739432 -2.2705525 -1.1345749 -0.5412512 -0.2480652 -0.2480652
    0.2 -3.7877746 -1.9446238 -0.9241210 -0.4101038 -0.1696735 -0.1696735
    0.3 -3.3597029 -1.6679266 -0.7551737 -0.3138778 -0.1206913 -0.1206913
    0.4 -2.9837281 -1.4344608 -0.6217331 -0.2465733 -0.0951186 -0.0951186
    0.5 -2.6538501 -1.2382265 -0.5177991 -0.2021903 -0.0869554 -0.0869554
    0.6 -2.3640690 -1.0732237 -0.4373717 -0.1747287 -0.0902017 -0.0902017
    0.7 -2.1083848 -0.9334523 -0.3744510 -0.1581885 -0.0988575 -0.0988575
    0.8 -1.8807974 -0.8129124 -0.3230370 -0.1465699 -0.1069227 -0.1069227
    0.9 -1.6753069 -0.7056040 -0.2771295 -0.1338726 -0.1083975 -0.1083975
    1.0 -1.4859133 -0.6055270 -0.2307288 -0.1140968 -0.0972817 -0.0972817

     | Show Table
    DownLoad: CSV
    Table 4.  The approximate solution comparison for the fractional order p of Ψ(Φ,Ω) for Ω=0.1 of problem 2.
    Φ MRPSMp=0.6 MRPSMp=0.7 MRPSMp=0.8 MRPSMp=0.9 MRPSMp=1.0 MTIMp=1.0
    0.1 -0.1089106 -0.0451462 -0.0171733 -0.0058199 -0.0020000 -0.0020000
    0.2 -0.0649407 -0.0234443 -0.0098919 -0.0079637 -0.0104000 -0.0104000
    0.3 -0.0458382 -0.0229178 -0.0208205 -0.0259612 -0.0328000 -0.0328000
    0.4 -0.0456031 -0.0375666 -0.0439590 -0.0538126 -0.0632000 -0.0632000
    0.5 -0.0582355 -0.0613906 -0.0733075 -0.0855179 -0.0956000 -0.0956000
    0.6 -0.0777353 -0.0883899 -0.1028658 -0.1150770 -0.1239999 -0.1239999
    0.7 -0.0981026 -0.1125645 -0.1266341 -0.1364899 -0.1424000 -0.1424000
    0.8 -0.1133373 -0.1279144 -0.1386123 -0.1437566 -0.1448000 -0.1448000
    0.9 -0.1174395 -0.1284395 -0.1328005 -0.1308772 -0.1252000 -0.1252000
    1.0 -0.1044091 -0.1081400 -0.1031985 -0.0918517 -0.0776000 -0.0776000

     | Show Table
    DownLoad: CSV

    Suppose the following time FADE:

    DpΩΨ(Φ,Ω)a2Ψ(Φ,Ω)Φ2+Ψ(Φ,Ω)Φ=0, where  0<p1. (4.50)

    Initial condition

    Ψ(Φ,0)=cos(Φ), (4.51)

    Eq 4.51 and the MT are used to get the following result from Eq 4.50.

    Ψ(Φ,s)cos(Φ)sasp[2Ψ(Φ,s)Φ2]+1sp[Ψ(Φ,s)Φ]=0. (4.52)

    The kth terms of the series that are truncated are:

    Ψ(Φ,s)=cos(Φ)s+kr=1fr(Φ,s)srp+1,  r=1,2,3,4. (4.53)

    Residual Mohand function is given by:

    MΩRes(Φ,s)=Ψ(Φ,s)cos(Φ)sasp[2Ψ(Φ,s)Φ2]+1sp[Ψ(Φ,s)Φ]=0, (4.54)

    and the kth-MRFs as:

    MΩResk(Φ,s)=Ψk(Φ,s)cos(Φ)sasp[2Ψk(Φ,s)Φ2]+1sp[Ψk(Φ,s)Φ]=0. (4.55)

    The following procedures should be implemented to determine the value of fr(Φ,s) for r=1,2,3,...: replace the rth-Mohand residual function Eq 4.55 for the rth-truncated series Eq 4.53, and multiply the expression by srp+1 for solving the relation, lims(srp+1)MΩResΨ,r(Φ,s))=0 for r=1,2,3,. Some terms that we obtain are as follows:

    f1(Φ,s)=sin(Φ)acos(Φ), (4.56)
    f2(Φ,s)=(a21)cos(Φ)2asin(Φ), (4.57)
    f3(Φ,s)=(3a21)sin(Φ)a(a23)cos(Φ), (4.58)
    f4(Φ,s)=(a46a2+1)cos(Φ)4a(a21)sin(Φ), (4.59)

    and so on.

    To obtain the desired result, the function fr(Φ,s) should be substituted into Eq 4.53.

    Ψ(Φ,s)=cos(Φ)s+sin(Φ)acos(Φ)sp+1+(a21)cos(Φ)2asin(Φ)s2p+1+(3a21)sin(Φ)a(a23)cos(Φ)s3p+1+(a46a2+1)cos(Φ)4a(a21)sin(Φ)s4p+1+. (4.60)

    Apply the inverse operator of MT to obtain the final solution:

    Ψ(Φ,Ω)=cos(Φ)+Ωp(sin(Φ)acos(Φ))Γ(p+1)+Ω2p((a21)cos(Φ)2asin(Φ))Γ(2p+1)+Ω4p((a46a2+1)cos(Φ)4a(a21)sin(Φ))Γ(4p+1)Ω3p(a((a23)cos(Φ)3asin(Φ))+sin(Φ))Γ(3p+1)+. (4.61)

    Suppose the following time FADE:

    DpΩΨ(Φ,Ω)=a2Ψ(Φ,Ω)Φ2Ψ(Φ,Ω)Φ, where  0<p1. (4.62)

    Initial condition

    Ψ(Φ,0)=cos(Φ). (4.63)

    Apply the MT on Eq 4.62:

    M[DpΩΨ(Φ,Ω)]=1sp(m1k=0Ψ(k)(Φ,0)s2p+k+M[a2Ψ(Φ,Ω)Φ2Ψ(Φ,Ω)Φ)]). (4.64)

    Apply the inverse operator of MT on Eq 4.64:

    Ψ(Φ,Ω)=M1[1sp(m1k=0Ψ(k)(Φ,η,0)s2p+k+M[a2Ψ(Φ,Ω)Φ2Ψ(Φ,Ω)Φ])]. (4.65)

    Iteratively utilize the MT to get the following result:

    Ψ0(Φ,Ω)=M1[1sp(m1k=0Ψ(k)(Φ,0)s2p+k)]=M1[Ψ(Φ,0)s2]=cos(Φ).

    Eq 4.62 is solved using the R-L integral to get:

    Ψ(Φ,Ω)=cos(Φ)+M[a2Ψ(Φ,Ω)Φ2Ψ(Φ,Ω)Φ]. (4.66)

    Some of the terms that the MITM method produces are as follows:

    Ψ0(Φ,Ω)=cos(Φ), (4.67)
    Ψ1(Φ,Ω)=Ωp(sin(Φ)acos(Φ))Γ(p+1), (4.68)
    Ψ2(Φ,Ω)=Ω2p((a21)cos(Φ)2asin(Φ))Γ(2p+1), (4.69)
    Ψ3(Φ,Ω)=Ω3p(a((a23)cos(Φ)3asin(Φ))+sin(Φ))Γ(3p+1), (4.70)
    Ψ4(Φ,Ω)=Ω4p((a46a2+1)cos(Φ)4a(a21)sin(Φ))Γ(4p+1). (4.71)

    The final solution is:

    Ψ(Φ,Ω)=Ψ0(Φ,Ω)+Ψ1(Φ,Ω)+Ψ2(Φ,Ω)+Ψ3(Φ,Ω)+Ψ4(Φ,Ω)+, (4.72)
    Ψ(Φ,Ω)=cos(Φ)+Ωp(sin(Φ)acos(Φ))Γ(p+1)+Ω2p((a21)cos(Φ)2asin(Φ))Γ(2p+1)Ω3p(a((a23)cos(Φ)3asin(Φ))+sin(Φ))Γ(3p+1)+Ω4p((a46a2+1)cos(Φ)4a(a21)sin(Φ))Γ(4p+1)+. (4.73)

    Figure 12, graphical representation of approximate solution for different values of p of Ψ(Φ,Ω) for Ω=0.1. Figure 13, graphical representation of approximate solution for different values of p of Ψ(Φ,Ω) for Ω=0.1. Figure 14, comparison of approximate solution for different values of p of Ψ(Φ,Ω) for Ω=0.1. Figure 15, (a) MRPSM solution and (b) MTIM solution of Ψ(Φ,Ω) for p=1 and Ω=0.1. Figure 16, (a) MRPSM solution and (b) MTIM solution comparison of Ψ(Φ,Ω) for p=1 and Ω=0.1. Table 5, the approximate solution comparison for the fractional order p of Ψ(Φ,Ω) for Ω=0.1 of problem 3. Table 6, the approximate solution comparison for the fractional order p of Ψ(Φ,Ω) for Ω=0.1 of problem 3.

    Figure 12.  Graphical representation of approximate solution for different values of p of Ψ(Φ,Ω) for Ω=0.1.
    Figure 13.  Graphical representation of approximate solution for different values of p of Ψ(Φ,Ω) for Ω=0.1.
    Figure 14.  Comparison of approximate solution for different values of p of Ψ(Φ,Ω) for Ω=0.1.
    Figure 15.  (a) MRPSM solution and (b) MTIM solution of Ψ(Φ,Ω) for p=1 and Ω=0.1.
    Figure 16.  (a) MRPSM solution and (b) MTIM solution comparison of Ψ(Φ,Ω) for p=1 and Ω=0.1.
    Table 5.  The approximate solution comparison for the fractional order p of Ψ(Φ,Ω) for Ω=0.1 of problem 3.
    Φ MRPSMp=0.1 MRPSMp=0.2 MRPSMp=0.3 MRPSMp=0.4 MRPSMp=0.5 MTIMp=0.5
    1 0.7263668 0.7249992 0.7448338 0.7512493 0.7395935 0.7395935
    2 -0.0400597 0.0523319 0.0460541 -0.0085039 -0.0779225 -0.0779225
    3 -0.7696556 -0.6684490 -0.6950675 -0.7604387 -0.8237969 -0.8237969
    4 -0.7916336 -0.7746611 -0.7971473 -0.8132296 -0.8122762 -0.8122762
    5 -0.0857873 -0.1686533 -0.1663335 -0.1183409 -0.0539524 -0.0539524
    6 0.6989314 0.5924135 0.6174065 0.6853498 0.7539749 0.7539749
    7 0.8410559 0.8088181 0.8335058 0.8589331 0.8687013 0.8687013
    8 0.2099174 0.2815990 0.2832837 0.2428172 0.1847476 0.1847476
    9 -0.6142181 -0.5045209 -0.5273881 -0.5965436 -0.6690621 -0.6690621
    10 -0.8736444 -0.8267866 -0.8531818 -0.8874451 -0.9077392 -0.9077392

     | Show Table
    DownLoad: CSV
    Table 6.  The approximate solution comparison for the fractional order p of Ψ(Φ,Ω) for Ω=0.1 of problem 3.
    Φ MRPSMp=0.6 MRPSMp=0.7 MRPSMp=0.8 MRPSMp=0.9 MRPSMp=1.0 MTIMp=1.0
    1 0.7163360 0.6885956 0.6611363 0.6364310 0.6154248 0.6154248
    2 -0.1452003 -0.2036107 -0.2516376 -0.2899815 -0.3200728 -0.3200728
    3 -0.8732402 -0.9086184 -0.9330571 -0.9497864 -0.9612970 -0.9612970
    4 -0.7984270 -0.7782464 -0.7566282 -0.7363620 -0.7187091 -0.7187091
    5 0.0104562 0.0676417 0.1154411 0.1540702 0.1846566 0.1846566
    6 0.8097261 0.8513404 0.8813745 0.9028510 0.9182499 0.9182499
    7 0.8645375 0.8523206 0.8369761 0.8215547 0.8076084 0.8076084
    8 0.1244970 0.0696812 0.0230658 -0.0150751 -0.0455444 -0.0455444
    9 -0.7300053 -0.7770228 -0.8120511 -0.8378450 -0.8568240 -0.8568240
    10 -0.9133442 -0.9093356 -0.9005720 -0.8903040 -0.8803435 -0.8803435

     | Show Table
    DownLoad: CSV

    In summary, the graphical results in Figures 12 to 16 further confirm the accuracy and effectiveness of the MRPSM and MTIM methods in solving FADEs. Both methods provide consistent and reliable solutions, and the visualizations of the solutions in both 2D and 3D formats offer valuable insights into the behavior of fractional-order systems. These results demonstrate the power of the proposed methods in solving complex fractional-order differential equations.

    In this study, we have effectively applied the MTIM and the MRPSM to solve the nonlinear FADEs. By incorporating the Caputo operator, we have enhanced the modeling of systems characterized by complex behaviors, improving the understanding of fractional-order differential equations. Our results demonstrate that both MTIM and MRPSM provide accurate approximate solutions that closely align with the exact ones, as shown by the accompanying tables and figures. These methods offer a robust framework for investigating the nonlinear behaviors of fractional systems, which are prevalent in physical sciences, engineering, and other fields. The inclusion of fractional derivatives defined by the Caputo operator introduces an added layer of complexity, enabling a more precise representation of nonlocal behaviors in the systems studied. The graphical analyses further confirm the utility of these methods in computational physics, where precise and efficient solutions are invaluable. Overall, this work contributes to advancing the field of fractional calculus, offering novel techniques for scholars working with nonlinear systems. The approaches presented here lay the groundwork for future research and exploration in this area.

    A.S.A: Conceptualization, Visualization, Funding, Data curation, Resources, Writing-review & editing; H. Y.: Formal analysis, Project administration, Data curation, validation; A. M. M.: Investigation, Validation, Resources, Software. All authors have read and agreed to the published version of the manuscript.

    Princess Nourah bint Abdulrahman University Researchers Supporting Project number (PNURSP2025R183), Princess Nourah bint Abdulrahman University, Riyadh, Saudi Arabia. This work was supported by the Deanship of Scientific Research, Vice Presidency for Graduate Studies and Scientific Research, King Faisal University, Saudi Arabia (GrantKFU242968).

    The authors declare that they have no conflict of interest.

    Princess Nourah bint Abdulrahman University Researchers Supporting Project number (PNURSP2025R183), Princess Nourah bint Abdulrahman University, Riyadh, Saudi Arabia. This work was supported by the Deanship of Scientific Research, Vice Presidency for Graduate Studies and Scientific Research, King Faisal University, Saudi Arabia (GrantKFU242968).

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.



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