Metric fixed-point theory has become an essential tool in computer science, communication engineering and complex systems to validate the processes and algorithms by using functional equations and iterative procedures. The aim of this article is to obtain common fixed point results in a bicomplex valued metric space for rational contractions involving control functions of two variables. Our theorems generalize some famous results from literature. We supply an example to show the originality of our main result. As an application, we develop common fixed point results for rational contractions involving control functions of one variable in the context of bicomplex valued metric space.
Citation: Asifa Tassaddiq, Jamshaid Ahmad, Abdullah Eqal Al-Mazrooei, Durdana Lateef, Farha Lakhani. On common fixed point results in bicomplex valued metric spaces with application[J]. AIMS Mathematics, 2023, 8(3): 5522-5539. doi: 10.3934/math.2023278
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Metric fixed-point theory has become an essential tool in computer science, communication engineering and complex systems to validate the processes and algorithms by using functional equations and iterative procedures. The aim of this article is to obtain common fixed point results in a bicomplex valued metric space for rational contractions involving control functions of two variables. Our theorems generalize some famous results from literature. We supply an example to show the originality of our main result. As an application, we develop common fixed point results for rational contractions involving control functions of one variable in the context of bicomplex valued metric space.
The Banach Contraction Principle [7] for ordered metric spaces was given by Ran and Reuring [39]. Subsequently, Nieto and Rodriguez-Lopez [34], Ó Regan and Petrusel [40] and Agarwal et al. [1] extended this work. Popa [36] introduced an implicit relation and proved a fixed-point theorem for the self-mappings on the complete metric spaces. Altun and Simsek [2] presented a generalization of the results in [1,34,36,39] by using implicit relation in ordered metric space as follow:
Theorem 1.1. [2] Let (X,d,⪯) be a partially ordered metric space. Suppose S:X→X is a non-decreasing mapping such that for all x,y∈X with x⪯y
T(d(Sx,Sy),d(x,y),d(x,Sx),d(y,Sy),d(x,Sy),d(y,Sx))≤0, | (1.1) |
where T:[0,∞)6→(−∞,∞). Also suppose that either S is continuous or (X,d,⪯) is regular, if there exists an element x0∈X with x0⪯S(x0), then S admits a fixed point.
We can obtain several contractive conditions from (1.1), for example, defining T:[0,∞)6→(−∞,∞) by
T(x1,x2,x3,x4,x5,x6)=x1−ψ(max{x2,x3,x4,12(x5+x6)}), |
we have the main result presented in [1]. Similarly, if we choose
T(x1,x2,x3,x4,x5,x6)=x1−kx2;k∈[0,1) |
in (1.1), we have the main result presented in [39]. Thus, different definitions of T:[0,∞)6→(−∞,∞) produce different contractive conditions. Moreover, the investigation of fixed points of implicit contractions was done by Popa [37,38], Beg et al. [8,9], Berinde et al. [11,12] and Sedghi [43].
The graphical metric spaces [20], partial metric spaces [31], dualistic partial metric spaces [32], b-metric spaces, multivalued contractions [27,33], α−ψ-contractions [42], F-contractions [25], (ψ,ϕ)-contractions [35] are extensively being used in metric fixed point theory. Motivated by the above discoveries, Huang and Zhang [16] presented the idea of cone metric by replacing the set of positive real numbers with ordered Banach space, and utilized this idea to universalize Banach contraction principle. Huang and Zhang [16] worked with the concept of normal cone, however, Rezapour et al. [41] neglected normality of the cone and improved the various theorems presented by Huang. The idea of cone b-metric space [17] was directly influenced by b-metric space [14]. Huang and Xu [18] applied the cone b-metric axioms to prove some fixed point theorems. For detail readings about cone metric, b-metric and cone b-metric, we suggest [3,13,14,21-23,26,29].
We observe that the implicit relation defined in Popa [37,38], can be generalized to vector spaces. So, in this research paper, motivated by Beg et al. [8,9], Berinde et al. [11,12] and Sedghi [43], we define an ordered implicit relation in a cone b-metric space and contribute a fixed point problem. We answer the proposed problem subject to monotone mappings satisfying an implicit contraction. We solve an homotopy problem and show existence of solution to a Urysohn Integral Equation as applications of the obtained fixed point theorem. The obtained fixed point theorems are independent of the observations presented by Ercan [15]. These observations apply on linear contractions and in this paper, we considered nonlinear contractions (implicit relation involving the contraction mappings). So, the obtained results are real generalizations and could not be followed from known ones in literature.
In this section, we recall cone, cone metric space and some related properties. Let E represent the real Banach space.
Definition 2.1. [19] The set ℵ⊆E is called a cone if and only if the following axioms hold:
(1) ℵ is closed, non empty and ℵ≠{0E};
(2) αv+βw∈ℵ, for all v,w∈ℵ and α,β∈R such that α,β≥0;
(3) ℵ∩(−ℵ)={0E}.
The partial order ⪯ with respect to ℵ is defined as follows:
v⪯w⇔w−v∈ℵforallv,w∈E. |
v≺w serves as v⪯w but v≠w, and v≪w represents that w−v∈ℵ∘(interior of ℵ).
Definition 2.2. [19] The cone ℵ⊆E is normal if for all v,w∈ℵ, there exists S>0 such that,
0E⪯v⪯wimplies‖v‖≤S‖w‖. |
Let ℜ be a partial order in any ordinary set X and ⪯ be a partial order in cone ℵ⊆E. If X⊆E then ℜ and ⪯ would be considered as identical.
Definition 2.3. [19] Let X≠ϕ be a set, and the mapping dc:X×X↦E satisfies the following axioms:
(dc1) dc(x,y)⪰0E, for all x,y∈X and dc(x,y)=0E if and only if x=y;
(dc2) dc(x,y)=dc(y,x);
(dc3) dc(x,ξ)⪯dc(x,y)+dc(y,ξ), for all x,y,ξ∈X.
Then dc is known as a cone metric on X, and (X,dc) is called a cone metric space.
Example 2.4. [6] Let X=R, E=R2, and ℵ={(x,y)∈E:x,y≥0}⊂R2. Define the mapping dc:X×X→E by
dc(x,y)=(∣x−y∣,α∣x−y∣), |
where α≥0 is to be taken as a constant. Then dc defines a cone metric on X.
Proposition 2.5. [6] Suppose that (X,dc) is a cone metric space, with cone ℵ. Then for w,ζ,ξ∈E, we have
(1) If w⪯βw and β∈[0,1), then w=0E.
(2) If 0E⪯w≪ζ for each 0E≪ζ, then w=0E.
(3) If w⪯ζ and ζ≪ξ, then w≪ξ.
Definition 2.6. [19] Let X be a non-empty set and x,y,υ∈X. The mapping c:X×X↦E satisfying the following axioms:
(cb1) 0E⪯c(x,y) and c(x,y)=0E if and only if x=y;
(cb2) c(x,y)=c(y,x);
(cb3) c(x,υ)⪯s[c(x,ξ)+c(ξ,υ)] for s≥1,
is known as a b-cone metric on X, and (X,c) is called a cone b-metric space.
Example 2.7. [6] Let E=R2, ℵ={(x,y)∈E:x,y≥0}⊂R2, X={1,2,3,4}. Define the mapping c:X×X→E by
c(x,y)={(|x−y|−1,|x−y|−1)ifx≠y0Eifx=y, |
and the partial order on E by
v⪯wifandonlyifv−w∈ℵforallv,w∈E. |
Then (X,c) is a cone b-metric space for s=65. We note that c(1,2)≻c(1,4)+c(4,2), this shows that c is not a cone metric.
Remark 2.8. Every cone metric space is a cone b-metric space, but converse is not true in general as seen in Example 2.7.
Definition 2.9. [10] Let E be a real Banach space and (X,c) be a cone b-metric space. Then for every ϵ∈E with 0E≪ϵ, we have the following information.
(1) A sequence {xn} is said to be a Cauchy sequence, if there exists a natural number K∈N so that c(xn,xm)≪ϵ for all n,m≥K.
(2) A sequence {xn} is said to be a convergent sequence (converging to x∈X), if there exists K∈N so that c(xn,x)≪ϵ for all n≥K.
(3) A cone b-metric space (X,c) is complete if each Cauchy sequence converges in X.
Let (E,‖.‖) be a real Banach space and B(E,E) be a space of all bounded linear operators S:E→E such that ‖S‖1<1 and ‖.‖1 is taken as usual norm in B(E,E).
Following the implicit relations presented in [4,5,8,9,11,12], we define a new ordered implicit relation as follows:
Definition 3.1. Let (E,‖.‖) be a real Banach space. The relation L:E6→E is said to be an ordered implicit relation, if it is continuous on E6 and satisfies the following axioms:
(L1) v1⪯υ1, v5⪯υ5 and v6⪯υ6
implies L(υ1,v2,v3,v4,υ5,υ6)⪯L(v1,v2,v3,v4,v5,v6);
(L2) if L(v1,v2,v2,v1,α[v1+v2],0E)⪯0E
or,
if L(v1,v2,v1,v2,0E,α[v1+v2])⪯0E, then there exists S∈B(E,E) such that v1⪯S(v2) (for all v1,v2∈E) and α≥1;
(L3) L(αv,0E,0E,v,αv,0E)≻0E whenever ‖v‖>0 and α≥1.
Let G={L:E6→E|LsatisfiesconditionsL1,L2,L3}.
Example 3.2. Let ⪯ be a partial order with respect to cone ℵ as defined in Section 2 and (E,‖.‖), be a real Banach space. For vi∈E(i=1to6), α>2 and γ>1, we define the relation L:E6→E by
L(v1,v2,v3,v4,v5,v6)=αv1−{v5+γv6}. |
Then L∈G. Indeed
(L1): Let v1⪯γ2, v5⪯γ5 and v6⪯γ6, then γ5−v5∈ℵ and γ6−v6∈ℵ, we show that L(v1,v2,v3,v4,v5,v6)−L(γ1,v2,v3,v4,γ5,γ6)∈ℵ. Consider,
L(v1,v2,v3,v4,v5,v6)−L(γ1,v2,v3,v4,γ5,γ6)=αγ1−{v5+γv6}−αγ1+{γ5+γγ6}=γ5−v5+γ(γ6−v6)∈ℵ. |
Thus, L(γ1,v2,v3,v4,γ5,γ6)⪯L(v1,v2,v3,v4,v5,v6).
(L2): Let v1,v2,v3∈E be such that 0E⪯v1,0E⪯v2. If L(v1,v2,v2,v1,s[v1+v2],0E)⪯0E then, we have −αv1+s{v1+v2}∈ℵ.
So,sv2−(α−s)v1∈ℵ.implies | (3.1) |
v2−(α−s)sv1∈ℵ. | (3.2) |
If v1=0E, then v2∈ℵ (by (3.1)). Thus, there exists T:E→E defined by T(v2)=ηv2 (where η=s) such that ∥T∥=s>1 (not possible). Now if v1≠0E, then, (3.2) implies v2⪯s(α−s)v1. So for α2>s≥1, there exists T:E→E defined by T(v2)=ηv2 (η=s(α−s) is a scalar) such that v1⪯T(v2), for α>2.
(L3): Let v∈E be such that ‖v‖>0 and consider, 0E⪯L(sv,0E,0E,v,sv,0E) then (αs−1)v∈ℵ, which hold whenever ‖v‖>0.
Example 3.3. Let L1,L2,L3:E6→E be defined by
(i) L1(v1,v2,v3,v4,v5,v6)=αv1−v2;α<1.
(ii) L2(v1,v2,v3,v4,v5,v6)=v3−α{v3+v4}−(1−α)βv5;α<12,β∈R.
(iii) L3(v1,v2,v3,v4,v5,v6)=v1+v5−α{v2+v4};α>12.
Then Li defines an ordered implicit relation for each i=1,2,3.
In the next section, we employ this implicit relation in association with a few other conditions to construct an iterative sequence and hence to answer the following fixed-point problem:
"find p∈(X,c) such that f(p)=p" where T∈B(E,E), I:E→E an identity operator, L∈G and f:X→X satisfies (3.3), for all comparable x,y∈Xands≥1.
(I−T)(c(x,f(x)))⪯sc(x,y)implies |
L(c(f(x),f(y)),c(x,y),c(x,f(x)),c(y,f(y)),c(x,f(y)),c(y,f(x)))⪯0E. | (3.3) |
The following assertion is essential in the sequel.
Remark 3.4. If S∈B(E,E), then Neumann series I+S+S2+⋯+Sn+⋯ converges whenever ‖S‖1<1 and diverge if ‖S‖1>1. Also for ‖S‖1<1 there exists μ>0 so that ‖S‖1<μ<1 and ‖Sn‖1≤μn<1.
Popa[36] applied implicit type contractive conditions on a self-mapping to establish some fixed point results. Altun and Simsek [2] extended the research work in [36] to partially ordered metric spaces. Nazam et al. [30] have further generalized the results given in [2] by using the concept of the cone metric space [19]. In this section, we shall address the proposed fixed-point problem that generalizes the results in [2,30,36]. For that purpose, we have the following theorem.
Theorem 4.1. Let (X,c) be a complete cone b-metric space with ℵ⊂E as a cone and f:X→X. If T∈B(E,E), I:E→E is an identity operator and L∈G such that, for all comparable elements x,y∈X and s≥1, we have
(I−T)(c(x,f(x)))⪯sc(x,y)implies |
L(c(f(x),f(y)),c(x,y),c(x,f(x)),c(y,f(y)),c(x,f(y)),c(y,f(x)))⪯0E. | (4.1) |
If,
(1) There exists x0∈X, so that x0ℜf(x0);
(2) For all x,y∈X, xℜy implies f(x)ℜf(y);
(3) The sequence {xn} satisfies xn−1ℜxn and xn→p, then xnℜp for all n∈N.
Then, there exists a point p∈X such that p=f(p).
Proof. Suppose that x0∈X be an arbitrary point such that x0ℜf(x0). We construct a sequence {xn} by f(xn−1)=xn taking x0 as an initial guess. Since, x0ℜx1, by assumption (2) we have x1ℜx2, x2ℜx3 ⋯ xn−1ℜxn. Since, x0ℜx1, by (4.1) we have
(I−T)(c(x0,f(x0)))=(I−T)(c(x0,x1))⪯sc(x0,x1)implies |
L(c(f(x0),f(x1)),c(x0,x1),c(x0,f(x0)),c(x1,f(x1)),c(x0,f(x1)),0E)⪯0E, |
that is,
L(c(x1,x2),c(x0,x1),c(x0,x1),c(x1,x2),c(x0,x2),0E)⪯0E. | (4.2) |
By triangle property of the cone b-metric, we have
c(x0,x2)⪯s[c(x0,x1)+c(x1,x2)]. |
Rewriting (4.2) and using condition (L1), we get:
L(c(x1,x2),c(x0,x1),c(x0,x1),c(x1,x2),s[c(x0,x1)+c(x1,x2)],0E)⪯0E. |
By using (L2), there exists K∈B(E,E) with ‖K‖1<1 such that
c(x1,x2)⪯K(c(x0,x1)). |
Again since, x1ℜx2, by (4.1) we obtain
(I−T)(c(x1,f(x1)))=(I−T)(c(x1,x2))⪯sc(x1,x2)implies |
L(c(f(x1),f(x2)),c(x1,x2),c(x1,f(x1)),c(x2,f(x2)),c(x1,f(x2)),c(x2,f(x1)))⪯0E, |
that is,
L(c(x2,x3),c(x1,x2),c(x1,x2),c(x2,x3),c(x1,x3),0E)⪯0E. |
By (cb3), we have
c(x1,x3)⪯s[c(x1,x2)+c(x2,x3)] |
using (L1) we get
L(c(x2,x3),c(x1,x2),c(x1,x2),c(x2,x3),s[c(x1,x2)+c(x2,x3)],0E)⪯0E. |
By (L2) there exists K∈B(E,E) with ‖K‖1<1 such that
c(x2,x3)⪯K(c(x1,x2))⪯K2(c(x0,x1)). |
Now keeping in view the above pattern and with the relation xnℜxn+1 n≥1, we can construct a sequence {xn} so that xn+1=f(xn) and
(I−T)(c(xn−1,f(xn−1)))=(I−T)(c(xn−1,xn))⪯sc(xn−1,xn) |
implies
c(xn,xn+1)⪯K(c(xn−1,xn))⪯K2(c(xn−2,xn−1))⪯⋯⪯Kn(c(x0,x1)). |
For ℏ,n∈N and s≥1, consider
c(xn+ℏ,xn)⪯s[c(xn+ℏ,xn+ℏ−1)+c(xn+ℏ−1,xn)]⪯sc(xn+ℏ,xn+ℏ−1+s2[c(xn+ℏ−1,xn+ℏ−2)+c(xn+ℏ−2,xn)]⪯sc(xn+ℏ,xn+ℏ−1)+s2c(xn+ℏ−1,xn+ℏ−2)+......+s(ℏ−1)c(xn+1,xn)⪯sKn+ℏ−1(c(x0,x1))+s2Kn+ℏ−2(c(x0,x1))+......+s(ℏ−1)Kn(c(x0,x1))=sKn+ℏ((sK−1)ℏ−1−1)s−K(c(x0,x1))+s(ℏ−1)Kn(c(x0,x1))⪯sℏKn+1s−K(c(x0,x1))+s(ℏ−1)Kn(c(x0,x1)). |
Since ‖K‖1<1, so, Kn→0E as n→∞ (Remark 3.4). Hence, limn→∞c(xn,xm)=0E, this shows that {xn} is a Cauchy sequence in X. Since, (X,c) is a complete cone b-metric space, so there exists p∈X so that xn→p for large n, alternately, for a given 0≪ϵ, there is a natural number N2 so that
c(xn,p)≪ϵforalln≥N2. |
Now since xn−1ℜxn and xn→p, by the assumption (3), we have xnℜp for all n∈N. We claim that,
(I−T)(c(xn,f(xn)))⪯sc(xn,p). |
Suppose on the contrary that
(I−T)(c(xn,f(xn)))≻sc(xn,p)and |
(I−T)(c(xn+1,f(xn+1)))≻sc(xn+1,p)forn∈N. |
By (cb3) and (4.1), we get
c(xn,f(xn))⪯s[c(xn,p)+c(p,xn+1)]≺s[1s(I−T)(c(xn,f(xn)))+1s(I−T)c(xn+1,f(xn+1)))]≺[(I−T)(c(xn,f(xn)))+(I−T)T(c(xn,f(xn)))]≺(I−T)(I+T)(c(xn,f(xn)))≺(I−T2)(c(xn,f(xn))). |
Thus,
T2(c(xn,f(xn)))≺0E, |
which leads to a contradiction. So, for each n≥1 and s≥1, we get
(I−T)(c(xn,f(xn)))⪯sc(xn,p), |
thus, by (4.1), we have
L(c(f(xn),f(p)),c(xn,p),c(xn,f(xn)),c(p,f(p)),c(xn,f(p)),c(p,f(xn)))⪯0E. | (4.3) |
We need to show that ‖c(p,f(p))‖=0. If ‖c(p,f(p))‖>0, then we have the following information.
c(f(xn),f(p))⪯s[c(f(xn),p)+c(p,f(p))]limn→∞c(f(xn),f(p))⪯slimn→∞[c(xn+1,p)+c(p,f(p))]=sc(p,f(p)),and |
c(xn,f(p))⪯s[c(xn,p)+c(p,f(p))]limn→∞c(xn,f(p))⪯slimn→∞[c(xn,p)+c(p,f(p))]limn→∞c(xn,f(p))⪯sc(p,f(p)). |
In view of the condition (L1) and (4.3), we have
L(s(c(p,f(p))),0E,0E,c(p,f(p)),s(c(p,f(p))),0E)⪯0E. |
This contradicts the condition (L3). Thus, ‖c(p,f(p))‖=0. So, c(p,f(p))=0E, and hence p=f(p).
Remark 4.2. If the operator L:E6→E is defined by
L(x1,x2,x3,x4,x5,x6)=x1−ψ(max{x2,x3,x4,12(x5+x6)}),forallxi∈E |
where, ψ:E→E is a non-decreasing operator satisfying limn→∞ψn(v)=0E. Then Theorem (4.1), generalizes the corresponding result in [1]. If we define L:E6→E by
L(x1,x2,x3,x4,x5,x6)=x1−kx2;k∈[0,1) |
in Theorem (4.1), we obtain a generalization of the corresponding result in [39]. Thus, different definitions of L:E6→E produce different ordered contractive conditions. Moreover, Theorem (4.1) generalizes the results in Popa [37,38], Beg et al. [8,9], Berinde et al. [11,12].
The following theorem is for decreasing self-mappings.
Theorem 4.3. Let (X,c) be a complete cone b-metric space with ℵ⊂E as a cone and f:X→X. Let T∈B(E,E), I:E→E be an identity operator, L∈G so that, for all comparable elements x,y∈X and s≥1
(I−T)(c(x,f(x)))⪯sc(x,y)implies |
L(c(f(x),f(y)),c(x,y),c(x,f(x)),c(y,f(y)),c(x,f(y)),c(k,f(x)))⪯0E. | (4.4) |
If,
(1) There exists x0∈X, so that f(x0)ℜx0;
(2) For all x,y∈X, xℜy implies f(y)ℜf(x);
(3) The sequence {xn} satisfies xn−1ℜxn and xn→x∗, then xnℜx∗ for all n∈N.
Then, there exists a point x∗∈X such that x∗=f(x∗).
Proof. Let x0∈X be arbitrary satisfying assumption (1). We define a sequence {xn} by xn=f(xn−1) for all n. As x1=f(x0)ℜx0 and by condition (2) x1=f(x0)ℜf(x1)=x2 and repeated implementation of hypothesis (2) leads to have xnℜxn−1. Since, x=x1ℜx0, by (4.4), we get
(I−T)(c(f(x0),x0)=(I−T)(c(x1,x0))⪯sc(x1,x0)implies |
L(c(f(x1),f(x0)),c(x1,x0),c(x1,f(x1)),c(x0,f(x0)),c(x1,f(x0)),c(x0,f(x1)))⪯0E |
⇒L(c(x1,x2),c(x0,x1),c(x1,x2),c(x0,x1),0,c(x0,x2))⪯0E. |
By (cb3), we have
c(x0,x2)⪯s[c(x0,x1)+c(x1,x2)] |
and then using L1, we obtain
L(c(x1,x2),c(x0,x1),c(x1,x2),c(x0,x1),0E,s[c(x0,x1)+c(x1,x2)]⪯0E. |
By (L2), there exists K∈B(E,E) with ‖K‖1<1 such that
c(x1,x2)⪯K(c(x0,x1)). |
Again since, x=x1ℜx2, by (4.4)
(I−T)(c(x1,f(x1))=(I−T)(c(x1,x2))⪯sc(x1,x2)implies |
L(c(f(x1),f(x2)),c(x1,x2),c(x1,f(x1)),c(x2,f(x2)),c(x1,f(x2)),c(x2,f(x1)))⪯0E |
⇒L(c(x2,x3),c(x1,x2),c(x1,x2),c(x2,x3),c(x1,x3),0E)⪯0E. |
By (cb3), (L1) and (L2), we get
c(x2,x3)⪯T(c(x1,x2))⪯T2(c(x0,x1)). |
By following same steps, we can construct a sequence {xn} such that
c(xn,xn+1)⪯K(c(xn−1,xn))⪯K2(c(xn−2,xn−1))⪯⋯⪯Kn(c(x0,x1)). |
Hence copying the arguments for the proof of Theorem 4.1, we get x∗=f(x∗).
The following theorem encapsulate the statements of Theorem 4.1 and Theorem 4.3.
Theorem 4.4. Let (X,c) be a complete cone b-metric space with ℵ⊂E as a cone and f:X→X be monotone mapping. Let T∈B(E,E), I:E→E be an identity operator. If there exists L∈G so that, for all comparable x,y∈X and s≥1
(I−T)(c(x,f(x)))⪯sc(x,y)implies |
L(c(f(x),f(y)),c(x,y),c(x,f(x)),c(y,f(y)),c(x,f(y)),c(k,f(x)))⪯0E, | (4.5) |
and,
(1) There exists x0∈X, so that x0ℜf(x0) or f(x0)ℜx0,
(2) The sequence {xn} satisfies xn−1ℜxn and xn→a∗, then xnℜa∗ for all n∈N.
Then, there exists a point a∗∈X such that a∗=f(a∗).
Proof. Proof is obvious.
Remark 4.5. We can get a unique fixed point in Theorem 4.1, Theorem 4.3 and Theorem 4.4 by taking an additional condition, "for each pair x,y∈X, we have either an upper bound or lower bound." (2). The cone is assumed as non-normal.
We illustrate above theorems with the help of the following examples.
Example 5.1. Let E=C1R[0,1], and ‖ζ‖=‖ζ‖∞+‖ˊζ‖∞,ℵ={ζ∈E:ζ(t)>0,t∈[0,1]}. For each K≥1, take ζ=x and y=x2K. By definition ‖ζ‖=1 and ‖y‖=2k+1. Clearly ζ⪯y, and K‖ζ‖ ≤‖y‖. Hence ℵ is a non-normal cone. Define the operator T:E→E by
(Tζ)(t)=12∫t0ζ(s)ds.Thus,Tislinearandboundedasshownbelow. |
(T(aζ+by))(t)=12∫t0(aζ+by)(s)ds=a2∫t0ζ(s)ds+b2∫t0y(s)ds,and |
‖Tnζ‖≤‖ζ‖n+12(n+1)!foreachn≥1. |
So
‖(Tnζ)‖∞≤12(n+1)!. |
‖(Tnζ)′‖∞≤‖ζ‖n2(n)!≤12(n)!forn≥1. |
‖(Tnζ)‖=‖(Tnζ)‖∞+‖(Tnζ)′‖∞≤12(n+1)!+12(n)!forn≥1 |
‖(Tnζ)‖=0whenn≥n1forn1∈N. |
Hence T∈B(E,E). Let X={1,2,3} and f:X→X defined by f(1)=f(2)=1 and f(3)=2, then f is increasing with respect to usual order. Define the mapping c by
c(x1,x2)={0ifx1=x2ζ3ifx1,x2∈{1,2};ζ∈Eζ8otherwise. |
ζ3=c(1,2)≻c(1,3)+c(3,2)=ζ8+ζ8, |
since triangular inequality does not hold, so c is not a cone metric space, but one can check that c is a cone b-metric space for s=43. Now, for x=1 and y=2 (x≤y), we have
c(x,y)=ζ3=c(y,f(x))=c(y,f(y)) |
c(x,f(x))=0E=c(f(x),f(y))=c(x,f(y)). |
For x=2 and y=3
c(x,y)=ζ8,c(x,f(x))=ζ3=c(f(x),f(y)) |
c(x,f(y))=0E,c(y,f(x)=ζ8=c(y,f(y)). |
For α>2 and γ>163, define
L(c(f(x),f(y)),c(x,y),c(x,f(x)),c(y,f(y)),c(x,f(y)),c(y,f(x)))=αc(f(x),f(y))−[c(x,f(y))+γc(y,f(x)]. |
Clearly
(I−T)c(x,f(x))⪯sc(x,y)implies |
αc(f(x),f(y))⪯c(x,f(y))+γc(y,f(x). |
Thus, by Theorem 4.1, f has a fixed point which is given by f(1)=1.
Remark 5.2. Since, c is not a cone metric, this shows that Theorem 4.1 does not hold in a cone metric space. The Example 5.1 also endorses the choice of cone b-metric space for this paper.
In the following, we have some consequences of the main results given above.
Corollary 5.3. Let (X,c) be a complete cone b-metric space with ℵ⊂E as a cone and f:X→X. If T∈B(E,E), I:E→E an identity operator and there exist L∈G so that, for all comparable elements x,y∈X and s≥1
(I−T)(c(x,f(x)))⪯sc(x,y)implies |
c(f(x),f(y))⪯T(c(x,y)), | (5.1) |
and,
(1) x∈X so that x0ℜf(x0) or f(x0)ℜx0;
(2) For all x,y∈X, xℜy implies f(x)ℜf(y) or f(y)ℜf(x);
(3) The sequence {xn} satisfies xn−1ℜxn and xn→b∗, then xnℜb∗ for all n∈N.
Then, there exists a point b∗∈X such that b∗=f(b∗).
Proof. Define L as in Example 3.3 (i), and the operator T:E→E by T(v)=αv for all v∈E and 0≤α<1, then T∈B(E,E and application of Theorem 4.4 provide the proof.
Corollary 5.4. Let (X,c) be a complete cone b-metric space with ℵ⊂E as a cone and f:X→X. If T∈B(E,E), I:E→E an identity operator and there exist L∈G so that, for any comparable x,y∈X and s≥1
(I−T)(c(x,f(x)))⪯sc(x,y)implies |
c(f(x),f(y))⪯1sT(c(x,y)), | (5.2) |
and,
(1) x∈X so that x0ℜf(x0) or f(x0)ℜx0;
(2) For all x,y∈X, xℜy implies f(x)ℜf(y) or f(y)ℜf(x);
(3) The sequence {xn} satisfies xn−1ℜxn and xn→r∗, then xnℜr∗ for all n∈N.
Then, there exists a point r∗∈X such that r∗=f(r∗).
Proof. Define the operator T:E→E by T(v)=v for all v∈E and following the proof of Corollary 5.3, we receive the result.
The following examples illustrates Corollary 5.3 and Corollary 5.4.
Example 5.5. Let E=(R,‖⋅‖) be a real Banach space. Define ℵ={x∈R:x≥0}, then, it is a cone in E. Let X={12,23,34,45}, define f:X→X so that, f(23)=f(34)=45 and f(12)=f(45)=12, then f is deceasing with respect to usual order. Let T∈B(E,E) be defined by T(x)=x2. Define the mapping c by
c(x1,x2)={0.3if(x1,x2)=(12,23)0.1if(x1,x2)=(12,45)0.01if(x1,x2)=(12,34)0.8if(x1,x2)=(34,45),(x1,x2)=(23,34)or(x1,x2)=(23,45)∣x1−x2∣otherwise. |
Observe that:
0.8=c(23,34)≥c(23,12)+c(12,34)=0.3+0.01=0.31 |
0.8=c(34,45)≥c(34,12)+c(12,45)=0.01+0.1=0.11. |
So (cb3) holds for s=10, and c is a cone b-metric, but not a cone metric, as (dc3) does not hold. Consider x=12 and y=23. Then
c(f(x),f(y))=c(x,f(y))=0.1,c(x,f(x))=0 |
c(x,y)=c(y,f(x))=0.3,c(y,f(y))=0.8 |
(I−T)c(x,f(x))=0. |
Now take x=23 and y=34. Then
c(f(x),f(y))=0,c(x,y)=c(x,f(x))=0.8 |
(I−T)c(x,f(x))=0.4,sc(x,f(x))=10(0.8)=8. |
For x=34 and y=45. Then
c(f(x),f(y))=0.1,c(x,y)=c(x,f(x))=0.8 |
(I−T)c(x,f(x))=0.4,sc(x,f(x))=10(0.8)=8. |
Thus, for all x,y∈X such that x≤y, we have
(I−T)(c(x,f(x)))⪯sc(x,y)impliesc(f(x),f(y))⪯T(c(x,y)). |
Hence, Corollary 5.3 holds for all comparable x,y∈X. Notice that 12 is a fixed point of f.
Remark 5.6. Since, c is not a cone metric, this shows that Corollary 5.3 does not hold in a cone metric space. The Example 5.5 also endorses the choice of cone b-metric space for this paper.
Example 5.7. Consider E=(R,‖⋅‖) be a real Banach space. Define ℵ={x∈R:x≥0}, then, it is a cone in E. Take X={0,1,2}, and f:X→X, f(0)=f(2)=0, f(1)=2. Define the mapping c by
c(x1,x2)={0ifx1=x23ifx1,x2∈{1,2}10ifx1,x2∈{0,1}0.5otherwise. |
Notice that:
10=c(0,1)≥c(0,2)+c(2,1)=0.5+3=3.5. |
For s=3, c is a cone b-metric space, but not cone metric space, as (dc3) does not hold. Define T(x)=x2 Consider x=0, y=1. Then
c(x,y)=10,c(f(x),f(y))=0.5,c(x,f(x))=0 |
Tc(x,y)=102=5,Tsc(x,y)=53=1.6667. |
Take x=1, y=2. Then
c(x,y)=3,c(f(x),f(y))=0.5,c(x,f(x))=3 |
Tc(x,y)=32=1.5,Tsc(x,y)=1.53=0.5 |
(I−T)c(x,f(x))=0.25. |
Clearly for all x,y∈X,
(I−T)c(x,f(x))⪯sc(x,y) |
implies
c(f(x),f(y))⪯1sT(c(x,y)). |
So for all values of x,y∈X, the Corollary 5.4 holds. Here 0 is a fixed point of f.
This section consists of a homotopy theorem as an application of Corollary 5.4.
Theorem 6.1. Let (E,‖.‖) be a real Banach space with ℵ⊂E taken as a cone and (X,c) be a complete cone b-metric space with open set U⊂X. Suppose that T∈B(E,E) such that ‖T‖1<1 with T(ℵ)⊂ℵ. If the mapping h:¯U×[0,1]→X admits conditions of Corollary 5.4 in the first variable and
(1) x≠h(x,θ) for each x∈∂U (∂U represents the boundary of U in X);
(2) There exists M≥0 so that
‖c(h(x,μ1),h(x,μ2))‖≤M|μ1−μ2| |
for some x∈¯U and μ1,μ2∈[0,1];
(3) For any x∈U there is y∈X such that ‖c(x,y)‖≤r, then xℜy, here r represents radius of U.
Then, whenever h(⋅,0) possesses a fixed point in U, h(⋅,1) also possesses a fixed point in U.
Proof. Let
B={t∈[0,1]|x=h(x,t);forx∈U}. |
Define the partial order ⪯ in E by u⪯v ⇔ ‖u‖≤‖v‖ for all u,v∈E. Clearly 0∈B, since h(.,0) possesses a fixed point in U. So B≠ϕ, In consideration of c(x,h(x,θ))=c(x,y), (I−T)(c(x,h(x,θ)))⪯sc(x,y) for all xℜy and s≥1, by Corollary 5.4, we get
c(h(x,θ),h(y,θ))⪯1sT(c(x,y)). |
Firstly, we prove that B is closed in [0,1]. For this, let {θn}∞n=1⊆B with θn→θ∈[0,1] as n→∞. It is necessary to prove that θ∈B. Since, θn∈B for n∈N, there exists xn∈U with xn=h(xn,θn). Since, h(⋅,θ) is monotone, so, for n,m∈N, we have xmℜxn. Since for s≥1
(I−T)(c(xn,h(xm,θm)))=(I−T)(c(xn,xm))⪯sc(xn,xm), |
we have
c(h(xn,θm),h(xm,θm))⪯1sT(c(xnxm)), |
and
c(xn,xm)=c(h(xn,θn),h(xm,θm))⪯s[c(h(xn,θn),h(xn,θm))+c(h(xn,θm),h(xm,θm))]‖c(xn,xm)‖≤sM|θn−θm|+ss‖T(c(xn,xm))‖‖c(xn,xm)‖≤sM1−‖T‖[|θn−θm|]. |
As {θn}∞n=1 is a Cauchy sequence in [0,1], we have
limn,m→∞c(xn,xm)=0E. |
So {xn} is a Cauchy sequence in X. As X is a complete cone b-metric space, so we have x∈¯U such that limn→∞c(xn,x)≪ϵ. Hence xnℜx for all n∈N. By triangle property, we have
c(x,h(x,θ))⪯s[c(x,xn)+c(xn,h(x,θ))]⪯sc(x,xn)+s2[c(xn,h(xn,θ))+c(h(xn,θ),h(x,θ))]⪯sc(x,xn)+s2[c(h(xn,θn),h(xn,θ))+c(h(xn,θ),h(x,θ))]‖c(x,h(x,θ))‖≤‖sc(x,xn)‖+s2M|θn−θ|+s2s‖T(c(xn,x))‖. |
Thus, c(x,h(x,θ))=0 as n→∞. So θ∈B, hence B is closed in [0,1]. Now we show that B is open in [0,1]. Let θ1∈B, so, there exists x1∈U such that h(θ1,x1)=x1. As U is open, we have r>0 so that B(x1,r)⊆U. Consider
l=‖c(x1,∂U)‖=inf{‖c(x1,ξ)‖:ξ∈∂U}. |
Then r=l>0. Given ϵ>0 such that ω<(1−‖T‖)lsM for s≥1. Let θ∈(θ1−ω,θ1+ω). Then
x∈¯B(x1,r)={x∈X:‖c(x,x1)‖≤r},sothatxℜx1. |
Consider
c(h(x,θ),x1)=c(h(x,θ),h(x1,θ1)⪯s[c(h(x,θ),h(x,θ1)+c(h(x,θ1),h(x1,θ1)]‖c(h(x,θ),x1)‖≤sM|θ1−θ|+ss‖T(c(x1,x))‖≤sMω+‖T‖l=sMω+‖T‖l<l. |
Thus, for each θ∈(θ1−ω,θ1+ω), h(⋅,θ):¯B(x,r)→¯B(x,r) has a fixed point in ¯U by applying Corollary 5.4. Hence θ∈B for any θ∈(θ1−ω,θ1+ω) and so B is open in [0,1]. Thus, B is open as well as closed in [0,1] and by connectedness, B=[0,1]. Hence h(⋅,1) has a fixed point in U.
In this section, we use the homotopy to describe the process of aging of human body. The aging process is considered by choosing suitable values for the time parameters t of the homotopy a(t,x). The values of the parameters t and x in the function a(t,x) are adjusted to control the process of the aging. For example, if t∈[0,1], and there is a homotopy a(t,x) from f(x) to g(x) such that a(0,x)=f(x) and a(1,x)=g(x) then the body is only one year old. Thus, if t∈[l,n], where n>l, and there is a continuous function a(t,x) called homotopy from one function from f(x) to w(x) satisfying the condition a(l,x)=f(x) and a(n,x)=w(x), then the body is described as being n years old. It is observed that for the interval t∈[l,n], the supremum a(n,x)=y(x) is the actual age of the body. Topologically the infant is equal to the adult since the infant continuously grows into the adult. The study found an algebraic way of relating homotopy to the process of aging of human body. The compact connected human body with boundary is assumed to be topologically equivalent to a cylinder X=S×I, where S is a circle and I=[0,α]. The initial state of the body X=S×I is the topological shape of the infant. The aging process, called homotopy, is the family of continuous functions a(t,x) on the interval I=[0,α]. It is an increasing sequence of the function a(t,x) of the body X. The homotopy relates the topological shape of the infant to the topological shape of the adult. For the human body X, let x∈X and t∈I define the growth of the body and the age of the body respectively. Since the final age of the human body is not known let t=∞ represent the final age of the body such that t∈[θ,∞] denotes the age interval of the body from t=θ to t=∞. The time t=∞ is the age threshold value of the human body. The aging process for all t∈[0,∞] is the family or the sequence of the functions a(t,x) such that a(0,x)=f(x) and a(∞,x)=y(x).
Theorem 7.1. Let X=S×I be a cylinder. Let a(t,x) be a homotopy related to the process of aging of human body. Then, whenever a(0,x) possesses a fixed point in X, Then, a(∞,x) also possesses a fixed point in X.
Proof. Since, the human body is compact connected and bounded, so, human body is topologically equivalent to a cylinder X=S×I. It is known that continuous reshaping of a cylinder possesses many invariant points. Thus, whenever a(0,x) possesses a fixed point in X, Then, a(∞,x) possesses a fixed point in X.
In this section, we will apply Theorem 4.1 for the existence of the unique solution to UIE:
ℓ(ℏ)=f(ℏ)+∫IRK1(ℏ,s,ℓ(s))ds. | (8.1) |
This integral equation encapsulates both Volterra Integral Equation (VIE) and Fredholm Integral Equation (FIE), depending upon the region of integration (IR). If IR =(a,x) where a is fixed, then UIE is VIE and for IR =(a,b) where a,b are fixed, UIE is FIE. In the literature, one can find many approaches to find a unique solution to UIE (see [24,28,44] and references therein). We are interested to use a fixed-point technique for this purpose. The fixed-point technique is simple and elegant to show the existence of a unique solution to further mathematical models.
Let IR be a set of finite measure and L2IR={ℓ|∫IR|ℓ(s)|2ds<∞}. Define the norm ‖.‖:L2IR→[0,∞) by
‖ℓ‖2=√∫IR|ℓ(s)|2ds,forallℓ,ȷ∈L2IR. |
An equivalent norm can be defined as follows:
‖ℓ‖2,ν=√sup{e−ν∫IRα(s)ds∫IR|ℓ(s)|2ds},forallℓ∈L2IR,ν>1. |
Then E=(L2IR,‖.‖2,ν) is a Banach space. Let A={ℓ∈L2IR:ℓ(s)>0foralmosteverys} be a cone in E. The cone b-metric cν associated to norm ‖.‖2,ν is given by cν(ℓ,ȷ)=ℓ‖ℓ−ȷ‖22,ν for all ℓ,ȷ∈A. Define a partial order ⪯ on E by
a⪯υifandonlyifa(s)υ(s)≥υ(s),foralla,υ∈E. |
Then (E,⪯,cν) is a complete cone b-metric space. Let
(A1) The kernel K1:IR×IR×R→R satisfies Carathéodory conditions and
|K1(ℏ,s,ℓ(s))|≤w(ℏ,s)+e(ℏ,s)|ℓ(s)|;w,e∈L2(IR×IR),e(ℏ,s)>0. |
A2) The function f:IR→[1,∞) is continuous and bounded on IR.
(A3) There exists a positive constant C such that
supℏ∈IR∫IR|K1(ℏ,s)|ds≤C. |
(A4) For any ℓ0∈L2IR, there is ℓ1=R(ℓ0) such that ℓ1⪯ℓ0 or ℓ0⪯ℓ1.
(A4′) The sequence {ℓn} satisfies ℓn−1⪯ℓn and ℓn→p, then ℓn⪯p for all n∈N.
(A5) There exists a non-negative and measurable function q:IR×IR→R such that
α(ℏ):=∫IRq2(ℏ,s)ds≤1ν |
and integrable over IR with
|K1(ℏ,s,ℓ(s))−K1(ℏ,s,ȷ(s))|≤q(ℏ,s)|ℓ(s)−ȷ(s)| |
for all ℏ,s∈IR and ℓ,ȷ∈E with ℓ⪯ȷ.
Theorem 8.1. Suppose that the mappings f and K1 mentioned above satisfy the conditions (A1)–(A5), then the UIE (8.1) has a unique solution.
Proof. Define the mapping R:E→E, in accordance with the above-mentioned notations, by
(Rℓ)(ℏ)=f(ℏ)+∫IRK1(ℏ,s,ℓ(s))ds. |
The operator R is ⪯-preserving:
Let ℓ,ȷ∈E with ℓ⪯ȷ, then ℓ(s)ȷ(s)≥ȷ(s). Since, for almost every ℏ∈ IR,
(Rℓ)(ℏ)=f(ℏ)+∫IRK1(ℏ,s,ℓ(s))ds≥1, |
this implies that (Rℓ)(ℏ)(Rȷ)(ℏ)≥(Rȷ)(ℏ). Thus, (Rℓ)⪯(Rȷ).
Self-operator:
The conditions (A1) and (A3) imply that R is continuous and compact mapping from A to A (see [24,Lemma 3]).
By (A4), for any ℓ0∈A there is ℓ1=R(ℓ0) such that ℓ1⪯ℓ0 or ℓ0⪯ℓ1 and using the fact that R is ⪯-preserving, we have ℓn=Rn(ℓ0)) with ℓn⪯ℓn+1 or ℓn+1⪯ℓn for all n≥0. We will check the contractive condition of Theorem 4.1 in the next lines. By (A5) and Holder inequality, we have
ℓ|(Rℓ)(ℏ)−(Rȷ)(ℏ)|2=ℓ|∫IRK1(ℏ,s,ℓ(s))ds−∫IRK1(ℏ,s,ȷ(s))ds|2⪯ℓ(∫IR|K1(ℏ,s,ℓ(s))−K1(ℏ,s,ȷ(s))|ds)2⪯ℓ(∫IRq(ℏ,s)|ℓ(s)−ȷ(s)|ds)2⪯ℓ∫IRq2(ℏ,s)ds⋅∫IR|ℓ(s)−ȷ(s)|2ds=ℓα(ℏ)∫IR|ℓ(s)−ȷ(s)|2ds. |
This implies, by integrating with respect to ℏ,
ℓ∫IR|(Rℓ)(ℏ)−(Rȷ)(ℏ)|2dℏ⪯ℓ∫IR(α(ℏ)∫IR|ℓ(s)−ȷ(s)|2ds)dℏ=ℓ∫IR(α(ℏ)eν∫IRα(s)ds⋅e−ν∫IRα(s)ds∫IR|ℓ(s)−ȷ(s)|2ds)dℏ⪯ℓ‖ℓ−ȷ‖22,ν∫IRα(ℏ)eν∫IRα(s)dsdℏ⪯ℓ1ν‖ℓ−ȷ‖22,νeν∫IRα(s)ds. |
Thus, we have
ℓe−ν∫IRα(s)ds∫IR|(Rℓ)(ℏ)−(Rȷ)(ℏ)|2dℏ⪯ℓ1ν‖ℓ−ȷ‖22,ν. |
This implies that
ℓ‖Rℓ−Rȷ‖22,ν⪯ℓ1ν‖ℓ−ȷ‖22,ν. |
That is,
cν(Rℓ,Rȷ)⪯1νcν(ℓ,ȷ). |
Thus, defining L:E6→E by
L(x1,x2,x3,x4,x5,x6)=x1−kx2;k∈[0,1), |
we have
L(c(Rℓ,Rȷ),c(ℓ,ȷ),c(ℓ,Rℓ),c(ȷ,Rȷ),c(ℓ,Rȷ),c(ȷ,Rℓ))⪯0E. |
Hence, by Theorem 4.1, the operator R has a unique fixed point. This means that the UIE (8.1) has a unique solution.
The ordered implicit relation in relation with implicit contraction is useful to obtain fixed point theorems that unify many corresponding fixed point theorems. These results can be applied to show the existence of the solutions to DE's and FDE's. The ordered implicit relation can be generalized to orthogonal implicit relation. The study of fixed point theorems is valid in cone metric spaces and hence in the cone b-metric spaces for the nonlinear contractions.
The authors declare that they have no competing interests.
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