In this paper, we mainly investigate the radial distribution of Julia sets of difference operators of entire solutions of complex differential equation F(z)fn(z)+P(z,f)=0, where F(z) is a transcendental entire function and P(z,f) is a differential polynomial in f and its derivatives. We obtain that the set of common limiting directions of Julia sets of non-trivial entire solutions, their shifts have a definite range of measure. Moreover, an estimate of lower bound of measure of the set of limiting directions of Jackson difference operators of non-trivial entire solutions is given.
Citation: Jingjing Li, Zhigang Huang. Radial distributions of Julia sets of difference operators of entire solutions of complex differential equations[J]. AIMS Mathematics, 2022, 7(4): 5133-5145. doi: 10.3934/math.2022286
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In this paper, we mainly investigate the radial distribution of Julia sets of difference operators of entire solutions of complex differential equation F(z)fn(z)+P(z,f)=0, where F(z) is a transcendental entire function and P(z,f) is a differential polynomial in f and its derivatives. We obtain that the set of common limiting directions of Julia sets of non-trivial entire solutions, their shifts have a definite range of measure. Moreover, an estimate of lower bound of measure of the set of limiting directions of Jackson difference operators of non-trivial entire solutions is given.
In this paper, we investigate the radial distribution of Julia sets of non-trivial entire solutions of equation
F(z)fn(z)+P(z,f)=0, | (1.1) |
where F(z) is a transcendental entire function, P(z,f)=∑sj=1αj(z)fn0j(f′)n1j⋯(f(k))nkj is a differential polynomial in f(z) and its derivatives. The powers n0j,n1j,⋯,nkj are non-negative integers and satisfy γp=min1≤j≤s(∑ki=0nij)≥n. Meromorphic functions αj(z)(j=1,2,⋯,s) are small functions of F(z).
The Nevanlinna theory is an important tool in this paper, and its standard notations as well as well-known theorems can be found in [6,8]. Let f be a meromorphic function in the complex plane. For example, we denote by m(r,f), N(r,f) and T(r,f) the proximity function, counting function of poles and Nevanlinna characteristic function with respect to f, respectively. The order σ(f) and lower order μ(f) are defined by
σ(f)=lim supr→∞log+T(r,f)logr,μ(f)=lim infr→∞log+T(r,f)logr, |
respectively, and the deficiency of the value a is defined by
δ(a,f)=lim infr→∞m(r,1f−a)T(r,f). |
We say that a is a Nevanlinna deficient value of f(z) if δ(a,f)>0. And when a=∞, we have
δ(∞,f)=lim infr→∞m(r,f)N(r,f). |
We define fn,n∈N as the nth iterate of f, that is, f1=f,⋯,fn=f∘(fn−1). The Fatou set F(f) of transcendental meromorphic function f is the subset of the complex plane C, where the iterates fn of f form a normal family. The complement of F(f) in C is called the Julia set J(f) of f. It is well known that F(f) is open, J(f) is closed and non-empty. For an introduction to the dynamics of meromorphic functions, we refer the reader to see Bergweiler's paper [4] and Zheng's book [21].
Suppose that f(z) is a transcendental meromorphic function in C and argz=θ is a ray from the origin. The ray argz=θ(θ∈[0,2π]) is said to be the limiting direction of J(f) if
Ω(θ−ε,θ+ε)∩J(f) |
is unbounded for any ε>0, where Ω(θ−ε,θ+ε)={z∈Cc|argz∈(θ−ε,θ+ε)}. And we define
Δ(f)={θ∈[0,2π)|the rayargz=θ is a limiting direction ofJ(f)}. |
Obviously, Δ(f) is closed and measurable, we use mesΔ(f) to stand for its linear measure.
There are a lot of works around the radial distributions of Julia sets of meromorphic functions, see [2,13,14,15,17,20]. When f is transcendental entire, Baker [2] observed that J(f) cannot be contained in any finite union of straight lines. Furthermore, Qiao [13] proved that mesΔ(f)=2π when μ(f)<1/2 and mesΔ(f)≥π/μ(f) when μ(f)≥1/2, where f(z) is a transcendental entire function with finite lower order. Then, for entire functions with infinite order, what is sufficient condition for the existence of lower bound of the measure of the limit directions?
Huang and Wang [9,10] considered this problem. They first studied the radial distribution of Julia sets of a solution base of complex linear differential equations and obtained the following result.
Theorem A. [9] Let {f1,f2,⋯,fn} be a solution base of
f(n)+A(z)f=0, | (1.2) |
where A(z) is a transcendental entire function with finite order, and denote E=f1f2⋯fn. Then
mesΔ(E)≥min{2π,πσ(A)}. |
After that, Huang and Wang [10] directly studied the limiting direction of Julia sets of solutions of a class of higher order linear differential equations.
Theorem B. [10] Let Ai(z)(i=0,1,2,⋯,n−1) be entire functions of finite lower order such that A0 is transcendental and m(r,Ai)=o(m(r,A0))(i=1,2,⋯,n−1) as r→∞. Then every non-trivial solution f of the equation
f(n)+An−1f(n−1)+⋯+A0f=0, | (1.3) |
satisfies mesΔ(f)≥{2π,πμ(A0)}.
Since then, inspired by the research of Huang and Wang, many scholars have studied the above problem. Especially, under the hypothesis of Theorem B, Zhang et al.[19] proved that mes(Δ(f)∩(Δ(f(k))))≥min{2π,π/μ(A0)}, where f(k)(k∈N) denote the derivatives for k and f(0)=f.
Theorem C. [19] Let Ai(z)(i=0,1,2,⋯,n−1) be entire functions of finite lower order such that A0 is transcendental and m(r,Ai)=o(m(r,A0))(i=1,2,⋯,n−1) as r→∞. Then every non-trivial solution f of Eq (1.3) satisfies
mes(Δ(f)∩(Δ(f(k)))≥min{2π,π/μ(A0)}, |
where k is a positive integer.
In 2021, Wang et al.[16] introduced the definition of transcendental directions to describe such directions in which f grows fast, and studied the relation between transcendental directions and limiting directions of entire solutions of Eq (1.1).
Theorem D. Suppose that n,k are integers, F(z) is a transcendental entire function of finite lower order, and that P(z,f) is a differential polynomial in f with γp≥n, where all coeffcients αj(j=1,2,⋯,s) are polynomials if μ(F)=0, or all αj(j=1,2,⋯,s) are entire and ρ(r,αj)<μ(F). Then for every nonzero transcendental entire solution f of the differential Eq (1.1), we have TD(f(k))∩TD(F)⊆Δ(f(k)) and
mes(Δ(f(k)))≥mes(TD(f(k))∩TD(F))≥min{2π,πμ(F)}. |
Here, the notation TD(f) denoted by the union of all transcendental directions of f, where a value θ∈[0,2π] is said to be a transcendental direction of f if there exists an unbounded sequence {zn} such that
limn→∞argzn=θandlimn→∞log|f(zn)|log|zn|=+∞. |
In recent years, value distribution in difference analogues of meromorphic functions has become a subject of great interest. The difference analogues of the lemma on the logarithmic derivatives, the Clunie lemma and etc. are applicable to study large classes of difference equations, often by using methods similar to the case of differential equations, see [5,7]. Inspired by Theorem A–D and the progress on the difference analogues of classical Nevanlinna theory of meromorphic functions, it is quite natural to investigate the limit directions of difference operators of meromorphic functions. This paper is an attempt in this direction. Set
E(f)=⋂k∈Z⋂i∈LΔ(f(k)(z+ηi)), |
where k∈Z, f(k) denotes the k−th derivative of f(z) for k≥0 or k−th integra primitive of f(z) for k<0, L is a set of positive integers and {ηi:i∈L} is a countable set of distinct complex numbers.
Theorem 1.1. Suppose that n,k are integers, F(z) is a transcendental entire function of finite lower order, and that P(z,f) is a differential polynomial in f with γp≥n, where all coeffcients αj(j=1,2,⋯,s) are small functions of F(z). Then every non-trivial entire solution f(z) of Eq (1.1) satisfies
mes(E(f))≥min{2π,πμ(F)}. | (1.4) |
Remark 1.1. Clearly, when n=1, F=A0(z) and P(z,f)=f(n)+An−1f(n−1)+⋯+A1f′, then Theorem C is a corollary of Theorem 1.1.
Next, we recall the Jackson difference operator
Dqf(z)=f(qz)−f(z)qz−z,z∈C∖{0},q∈C∖{0,1}. |
For k∈N∪{0}, the Jackson k-th difference operator is denoted by
D0qf(z):=f(z),Dkqf(z):=Dq(Dk−1qf(z)). |
Clearly, if f is differentiable,
limq→1Dkqf(z)=f(k)(z). |
Therefore, a natural question arises: for Eq (1.1), if we consider the Jackson difference operators of f, does the conclusion mes(⋂k∈N∪{0}Δ(Dkqf(z)))≥min{2π,πμ(F)} still hold? Set R(f)=⋂k∈N∪{0}Δ(Dkqf(z)), where q∈(0,+∞)∖{1} and Dkqf(z) denotes the k−th Jackson difference operators of f(z). Our result can be stated as follows.
Theorem 1.2. Under the hypothesis of Theorem 1.1, we have
mesR(f)≥min{2π,πμ(F)} | (1.5) |
for every non-trivial entire solution f(z) of Eq (1.1).
Before introducing lemmas and completing the proof of Theorems, we recall the Nevanlinna characteristic in an angle, see [8,11]. Assuming 0<α<β<2π, k=π/(β−α), we denote
Ω(α,β)={z∈C|argz∈(α,β)}, |
Ω(α,β,r)={z∈C|z∈Ω(α,β),|z|<r}, |
Ω(r,α,β)={z∈C|z∈Ω(α,β),|z|>r}, |
and use ¯Ω(α,β) to denote the closure of Ω(α,β).
Let f(z) be meromorphic on the angular ¯Ω(α,β), we define
Aα,β(r,f)=kπ∫r1(1tk−tkr2k){log+|f(teiα)|+log+|f(teiβ)|}dtt,Bα,β(r,f)=2kπrk∫βαlog+|f(reiθ)|sink(θ−α)dθ,Cα,β(r,f)=2∑1<|bv|<r(1|bv|k−|bv|kr2k)sink(βv−α), |
where bv=|bv|eiβv(v=1,2,⋯) are the poles of f(z) in ¯Ω(α,β), counting multiplicities. The Nevanlinna angular characteristic function is defined by
Sα,β(r,f)=Aα,β(r,f)+Bα,β(r,f)+Cα,β(r,f). |
Especially, we use σα,β(f)=lim supr→∞logSα,β(r,f)logr to denote the order of Sα,β(r,f).
Lemma 2.1. [3] If f is a transcendental entire function, then the Fatou set of f has no unbounded multiply connected component.
Lemma 2.2. [20] Suppose f(z) is analytic in Ω(r0,θ1,θ2), U is a hyperbolic domain and f:Ω(r0,θ1,θ2)→U. If there exists a point a∈∂U∖{∞} such that CU(a)>0, then there exists a constant d>0 such that for sufficiently small ε>0, we have
|f(z)|=O(|z|d),z∈Ω(r0,θ1+ε,θ2−ε),|z|→∞. |
Remark 2.1. The open set W is called a hyperbolic domain if ¯C∖W has greater than two points. For an a∈C∖W, we set
CW(a)=inf{λW(z)|z−a|:∀z∈W}, |
where λW(z) is the hyperbolic density on W. It is well known that if every component of W is simply connected, then CW(a)≥12.
Before stating the following lemma, we recall the definition of R-set. Suppose that the set B(zn,rn)={z∈C:|z−zn|<rn}, if ∑∞n=1rn<∞,zn→∞, then we call ⋃∞n=1B(zn,rn) a R-set. Obviously, set {|z|:z∈⋃∞n=1B(zn,rn)} is set of finite linear measure.
Lemma 2.3. [10] Let z=rexp(iψ),r0+1<r and α≤ψ≤β, where 0<β−α≤2π. Suppose that n(≥2) is an integer, and that f(z) is analytic in Ω(r0,α,β) with σα,β<∞. Choose α<α1<β1<β. Then, for every ε∈(0,βj−αj2)(j=1,2,...,n−1) outside a set of linear measure zero with
αj=α+j−1∑s=1εsandβj=β+j−1∑s=1εs,(j=2,3,...,n−1) |
there exist K>0 and M>0 only depending f, ε1,...,εn−1 and Ω(αn−1,βn−1), and not depending on z such that
|f′(z)f(z)|≤KrM(sink(ψ−α))−2 |
and
|f(n)(z)f(z)|≤KrM(sink(ψ−α)n−1∏j=1sinkj(ψ−αj))−2 |
for all z∈Ω(αn−1,βn−1) outside an R-set H, where k=π/(β−α) and kεj=π/(βj−αj(j=1,2,...,n−1)).
Remark 2.2. Mokhon′ko [12] proved that Lemma 2.2 holds when n = 1; Wu[18] proved that the case of n=2; and Huang and Wang[10] proved that the case of n>2.
Lemma 2.4. [21] Suppose that f(z) is a meromorphic function on Ω(α−ε,β+ε) for ε>0 and 0<α<β<2π. Then
Aα,β(r,f′f)+Bα,β(r,f′f)≤K(log+Sα−ε,β+ε(r,f)+loglogr+1), |
for r>1 possibly except a set with finite linear measure.
Lemma 2.5. [1] Let f(z) be a transcendental meromorphic function with positive order and finite lower order μ, and have one deficient value a. Let Λ(r) be a positive function with Λ(r)=o(T(r,f)) as r→∞. Then for any fixed sequence of Pólya peaks {rn} of order λ>0,μ(f)≤λ≤σ(f), we have
lim infrn→∞mesDΛ(rn,a)≥min{2π,4λarcsin√δ(a,f)2}, |
where DΛ(rn,a) is defined by
DΛ(rn,∞)={θ∈[0,2π):log+|f(reiθ)|>Λ(r)T(r,f)}, |
and for finite a
DΛ(rn,a)={θ∈[0,2π):log+1|f(reiθ)−a|>Λ(r)T(r,f)}. |
Clearly, every nontrivial entire solution f of Eq (1.1) is transcendental. Suppose on the contary that mesE(f)<σ:=min{2π,π/μ(F}. Then ξ:=σ−mesE(f)>0. For every i∈L and k∈Z, Δ(f(k)(z+ηi)) is closed, and so E(f) is closed. Denoted by S:=[0,2π)∖E(f) the complement of E(f). Then S is open and contains at most countably many open intervals. Therefore, we can choose finitely many open intervals Ii=(αi,βi)(i=1,2,...,m) in S such that
mes(S∖m⋃i=1Ii)<ξ4. | (3.1) |
For every θi∈Ii, there exist mθi∈L and kθi∈Z such that argz=θi is not a limiting direction of the Julia set of some f(kθi)(z+ηmθi), where mθi∈L and kθi∈Z only depending on θi. Then there exists some angular domain Ω(θi−ζθi,θi+ζθi) such that
(θi−ζθi,θi+ζθi)⊂IiandΩ(r,θi−ζθi,θi+ζθi)∩J(f(kθi)(z+ηmθi))=∅ | (3.2) |
for sufficiently large r, where ζθi>0 is a constant only depending on θi. Hence, ⋃θi∈Ii(θi−ζθi,θi+ζθi) is an open covering of [αi+ε,βi−ε] with 0<ε<min{(βi−αi)/6,i=1,2,...,m}. By Heine-Borel theorem, we can choose finitely many θij, such that
[αi+ε,βi−ε]⊂pi⋃j=1(θij−ζθij,θij+ζθij). |
From (3.2) and Lemma 2.1, there exist a related rij and an unbounded Fatou component Uij of F(f(kθij)(z+ηmθij)) such that Ω(rij,θij−ζθij,θij+ζθij)⊂Uij, see [3]. We take an unbounded and connected closed section Γij on boundary ∂Uij such that C∖Γij is simply connected. Clearly, C∖Γij is hyperbolic and open. By remark 2.1, there exists a a∈C∖Γij such that CC∖Γij(a)≥1/2. Since the mapping f(kθij)(z+ηmθij):Ω(rij,θij−ζθij,θij+ζθij)→C∖Γij is analytic, it follows from Lemma 2.2 that there exists a positive constant d1 such that
|f(kθij)(z+ηmθij)|=O(|z|d1)as|z|→∞ | (3.3) |
for z∈Ω(rij,θij−ζθij+ε,θij+ζθij−ε). Selecting r∗ij>rij such that z−ηmθij∈Ω(rij,θij−ζθij+ε,θij+ζθij−ε), when z∈Ω(r∗ij,θij−ζθij+2ε,θij+ζθij−2ε). Thus,
|f(kθij)(z)|=O(|z−ηmθij|d1)=O(|z|d1)as|z|→∞ | (3.4) |
holds for z∈Ω(r∗ij,θij−ζθij+2ε,θij+ζθij−2ε).
Case 1. Suppose kθij≥0. By integration, we have
|f(kθij−1)(z)|=∫z0|f(kθij)(γ)||dγ|+ckθij, | (3.5) |
where ckθij is is a constant, and the integral path is the segment of a straight line from 0 to z. From this and (3.4), we can deduce |f(kθij−1)(z)|=O(|z|d1+1) for z∈Ω(r∗ij,θij−ζθij+2ε,θij+ζθij−2ε). Repeating the discussion kθij times, we can obtain
|f(z)|=O(|z|d1+kθij),z∈Ω(r∗ij,θij−ζθij+2ε,θij+ζθij−2ε). | (3.6) |
From the definition of angular characteristic, we have
Sθij−ζθij+2ε,θij+ζθij−2ε(r,f)=O(logr). | (3.7) |
Case 2. Suppose kθij<0. For any angular Ω(α,β), we have
Sα,β(f(kθij+1))≤Sα,β(r,f(kθij+1)f(kθij))+Sα,β(r,f(kθij)). | (3.8) |
By Lemma 2.4, we obtain
Sα,β(r,f(kθij+1)f(kθij))≤K1(log+Sα+ϵ,β−ϵ(r,f(kθij))+logr+1), | (3.9) |
where ϵ=ε|kθij|, K1 is a positive constant. Combining (3.4), (3.8) and (3.9), we easy to have
Sθij−ζθij+2ε+ϵ,θij+ζθij−2ε−ϵ(r,f(kθij+1))=O(logr). | (3.10) |
Similar to the above, repeating the discussion |kθij| times, we get
Sθij−ζθij+3ε,θij+ζθij−3ε(r,f)=O(logr). | (3.11) |
This means that whatever kθij is positive or not, we always have
Sθij−ζθij+3ε,θij+ζθij−3ε(r,f)=O(logr). | (3.12) |
Therefore, σθij−ζθij+3ε,θij+ζθij−3ε<∞. According to Lemma 2.3, there exist two constants K>0 and N>0 such that
|f(s)(z)f(z)|≤KrN,s=1,2,⋯,k. | (3.13) |
for all z∈Ω(r∗ij,θij−ζθij+3ε,θij+ζθij−3ε) outside a R-set H. Next, we define
Λ(r)=max{√logr,√T(r,αj)}√T(r,F). | (3.14) |
Since T(r,αj)=S(r,F) and F is transcendental, we obtain
Λ(r)=o(T(r,F))andT(r,αj)=o(Λ(r))(j=1,2,⋯,s). |
Since F is entire, ∞ is a deficient value of F and δ(∞,F)=1. By Lemma 2.5, there exists an increasing and unbounded sequence {rn} such that
mesDΛ(rn)≥σ−ξ/4, | (3.15) |
where
DΛ(r):=DΛ(r,∞)={θ∈[−π,π):log+|F(reiθ)|>Λ(r)}, | (3.16) |
and all rn∉{|z|:z∈H}. Clearly,
mes((m⋃i=1Ii)∩DΛ(rn))=mes(S∩DΛ(rn))−mes((S∖m⋃i=1Ii)∩DΛ(rn))≥mes(DΛ(rn))−mesE(f)−mes(S∖m⋃i=1Ii)≥σ−ξ4−mesE(f)−ξ4=ξ2. | (3.17) |
Let Mij=(θij−ζθij+3ε,θij+ζθij−3ε), then
mes(m⋃i=1pi⋃j=1Mij)≥mes(m⋃i=1Ii)−(3m+6ν)ε, |
where ν=∑mi=1pi. Choosing ε small enough, we can deduce
mes((m⋃i=1pi⋃j=1Mij)∩DΛ(rn))≥ξ4. |
Thus, there exists an open interval Mi0j0 of all Mij such that for every k,
mes(Mi0j0∩DΛ(rn))>ξ4ν>0. | (3.18) |
Let G=Mi0j0∩DΛ(rn). Then by (3.16), we have
∫Glog+|F(rneiθ)|dθ≥ξ4νΛ(rn). | (3.19) |
On the other hand, from (1.1), we have
|F(z)|=s∑j=1|αj(z)(f′f)n1j(f″f)n2j⋯(f(k)f)nkjfn0j+n1j+⋯+nkj−n|. | (3.20) |
Since n0j+n1j+⋯+nkj−n≥0 and substituting (3.4)–(3.13) into Eq (1.1), we obtain
∫Glog+|F(rneiθ)|dθ≤∫G(s∑j=1log+|αj(rneiθ)|)dθ+O(logrn)≤s∑j=1m(rn,αj)+O(logrn)≤s∑j=1T(rn,αj)+O(logrn). | (3.21) |
Combining (3.19) and (3.21), it is found that
ξ4νΛ(rn)≤s∑j=1T(rn,αj)+O(logrn), | (3.22) |
which is impossible since T(r,αj)=o(Λ(r))(j=1,...,s) as r→∞. Therefore,
mes(E(f))≥min{2π,πμ(F)}. |
In the following, we shall obtain the assertion by reduction to contraction. Assuming that mesR(f)<τ=min{2π,πμ(F)}, so υ=τ−mesR(f)>0. Since Δ(Dkqf(z)) is closed, clearly S=[0,2π)∖R(f) is open, so it consists of at most countably many open intervals. We can choose finitely many open intervals Ii=(αi,βi)(i=1,2,⋯,s)⊂S satisfying
mes(S∖s⋃i=1Ii)<υ4. |
For every θi∈Ii, argz=θi is not a limiting direction of the Julia set of Dkqf(z) for some k∈N∪{0}. Then there exists an angular domain Ω(θi−ϕθi,θi+ϕθi) such that
(θi−ϕθi,θi+ϕθi)⊂IiandΩ(θi−ϕθi,θi+ϕθi)∩Δ(Dkqf(z))=∅, | (4.1) |
where ϕθi>0 is a constant only depending on θi. Take 0<ε<min{(βi−αi)/6,i=1,2,⋯,s}, then ⋃θi∈Ii(θi−ϕθi,θi+ϕθi) is an open covering of [αi+ε,βi−ε]. By Heine-Borel theorem, we can choose finitely many θij, such that
[αi+ε,βi−ε]⊂si⋃j=1(θij−ϕθij,θij+ϕθij). |
From (4.1) and Lemma 2.1, there exists an unbounded Fatou component U of F(Dkqf(z)) such that Ω(θi−ϕθi,θi+ϕθi)⊂U. Taking an unbounded connected set Γ⊂∂U and the mapping Dkqf(z):Ω(θi−ϕθi,θi+ϕθi)→C∖Γ is analytic. Since C∖Γ is simply connected, then for arbitrary a∈Γ∖{∞}, we have CC∖Γ(a)≥12. Thus, for sufficiently small ε>0, there exists a constant d2>0 such that
|Dkqf(z)|=O(|z|d2),z∈Ω(α∗ij,β∗ij), | (4.2) |
where α∗ij=θij−ϕθij+ε and β∗ij=θij+ϕθij−ε.
By the definition of Jackson k−th difference operator,
|Dkqf(z)|=|Dk−1qf(qz)−Dk−1qf(z)||qz−z|=O(|z|d2),z∈Ω(α∗ij,β∗ij). | (4.3) |
Therefore,
|Dk−1qf(qz)−Dk−1qf(z)|=O(|z|d2+1),z∈Ω(α∗ij,β∗ij). | (4.4) |
Thus, there exists a positive constants C such that
|Dk−1qf(qz)−Dk−1qf(z)|≤C(|z|d2+1),z∈Ω(α∗ij,β∗ij). | (4.5) |
Case 1. Suppose q∈(0,1). If |z| is sufficiently large, there exists a positive integer r such that (1q)r≤|z|≤(1q)r+1. Therefore, 1≤|qrz|≤1q. Then there exists a positive constant M1 such that |Dk−1qf(qrz)|≤M1 for all z∈{z|1≤|qrz|≤1q}. Using inequality (4.5) repeatedly, we have
|Dk−1qf(z)−Dk−1qf(qz)|≤C(|z|d2+1),|Dk−1qf(qz)−Dk−1qf(q2z)|≤C(|qz|d2+1),⋯|Dk−1qf(qr−1z)−Dk−1qf(qrz)|≤C(|qr−1z|d2+1). | (4.6) |
Taking the sum of all inequalities, we obtain
|Dk−1qf(z)|≤|Dk−1qf(z)−Dk−1qf(qz)|+|Dk−1qf(qz)−Dk−1qf(q2z)|+⋯+|Dk−1qf(qr−1z)−Dk−1qf(qrz)|+|Dk−1qf(qrz)|≤C(|z|d2+1)+C(|qz|d2+1)+⋯+C(|qr−1z|d2+1)+M1≤rC(1+qd2+1+⋯+q(r−1)(d2+1))|z|d2+1+M1=O(|z|d2+1),z∈Ω(α∗ij,β∗ij). | (4.7) |
Thus,
|Dk−1qf(z)|=O(|z|d2+1),z∈Ω(α∗ij,β∗ij). | (4.8) |
Repeating the operations from (4.2) to (4.8), we get
|f(z)|=O(|z|d2+k−1),z∈Ω(α∗ij,β∗ij). | (4.9) |
Case 2. Suppose q∈(1,+∞). Obviously, there exists a positive integer t such that qt≤|z|≤qt+1 for sufficiently large |z|. And this is exactly 1≤|zqt|≤q. Therefore, there exists a positive constant M2 such that |Dk−1qf(zqt)|≤M2 for all z∈{z|1≤|zqt|≤q}.
Using inequality (4.5) repeatedly, we have
|Dk−1qf(z)−Dk−1qf(zq)|≤C(|zq|d2+1),|Dk−1qf(zq)−Dk−1qf(zq2)|≤C(|zq2|d2+1),⋯|Dk−1qf(zqt−1)−Dk−1qf(zqt)|≤C(|zqt|d2+1). | (4.10) |
Taking the sum of all inequalities, we obtain
|Dk−1qf(z)|≤|Dk−1qf(z)−Dk−1qf(zq)|+|Dk−1qf(zq)−Dk−1qf(zq2)|+⋯+|Dk−1qf(zqt−1)−Dk−1qf(zqt)|+|Dk−1qf(zqt)|≤C(|zq|d2+1)+C(|zq2|d2+1)+⋯+C(|zqt|d2+1)+M2≤tC(1qd2+1+1q2(d2+1)+⋯+1qt(d2+1))|z|d2+1+M2=O(|z|d2+1),z∈Ω(α∗ij,β∗ij). | (4.11) |
Therefore,
|Dk−1qf(z)|=O(|z|d2+1),z∈Ω(α∗ij,β∗ij). | (4.12) |
Similarly, we can deduce
|f(z)|=O(|z|d2+k−1),z∈Ω(α∗ij,β∗ij), | (4.13) |
which implies that
Sα∗ij,β∗ij(r,f)=O(logr). | (4.14) |
By the similar proof in (3.12) to (3.22), we can get a contradiction. Therefore,
mesR(f)≥min{2π,πμ(F)}. |
The work was supported by NNSF of China (No.11971344).
The authors declare no conflict of interest.
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