
In this paper, the idea of partitioning is used to solve quaternion least squares problem, we divide the quaternion Bisymmetric matrix into four blocks and study the relationship between the block matrices. Applying this relation, the real representation of quaternion, and M-P inverse, we obtain the least squares Bisymmetric solution of quaternion matrix equation AXB=C and its compatable conditions. Finally, we verify the effectiveness of the method through numerical examples.
Citation: Dong Wang, Ying Li, Wenxv Ding. The least squares Bisymmetric solution of quaternion matrix equation AXB=C[J]. AIMS Mathematics, 2021, 6(12): 13247-13257. doi: 10.3934/math.2021766
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In this paper, the idea of partitioning is used to solve quaternion least squares problem, we divide the quaternion Bisymmetric matrix into four blocks and study the relationship between the block matrices. Applying this relation, the real representation of quaternion, and M-P inverse, we obtain the least squares Bisymmetric solution of quaternion matrix equation AXB=C and its compatable conditions. Finally, we verify the effectiveness of the method through numerical examples.
Throughout this paper, the set of positive integers, the real number field and quaternion skew-field are denoted by N, R and Q, respectively, the set of all real column vectors with order t and the set of all real row vectors with order t are denoted by Rt and Rt, respectively, the set of all m×n real matrices and the set of all m×n quaternion matrices are denoted by Rm×n and Qm×n, respectively, the set of all n×n real symmetric matrices, the set of all n×n real Persymmetric matrices, the set of all n×n quaternion Hermitian matrices, the set of all n×n quaternion Persymmetric matrices, and the set of all n×n quaternion Bisymmetric matrices are denoted by SRn×n, PRn×n, HQn×n, PQn×n and BQn×n, respectively, the conjugate of quaternion a is denoted by ˉa, the i−th column of identity matrix In is denoted by δin, the exchange matrix with order k is denoted by Vk, the transpose, the conjugate transpose, M-P inverse of matrix A are denoted by AT, AH and A†, the Kronecker product of matrices is denoted by ⊗, the Frobenius norm of a matrix or Euclidean norm of a vector is denoted by ‖⋅‖.
Block matrix is a common method in matrix theory. By properly dividing the matrix into blocks, a high-order matrix can be transformed into some low-order matrices. At the same time, the structure of the original matrix become simple and clear, which can greatly simplify the operation steps or bring convenience to the theoretical derivation of the matrix. There are many problems can be solved or proved by block matrix. For example, when dealing with more complex constraint problems of matrix equation, it will be easier to discuss the submatrices. In this paper, we will use block matrices to solve quaternion matrix equation.
A quaternion q∈Q is expressed as q=a+bi+cj+dk, where a,b,c,d∈R, and three imaginary units i,j,k satisfy
i2=j2=k2=ijk=−1, ij=−ji=k, jk=−kj=i, ki=−ik=j. |
Quaternion matrix equations and their least squares solutions are widely applied in many fields[1,2,3,4,5]. So many scholars have studied various types solutions of quaternion matrix equations [6,7,8,9,10,14,16,17,18,19,20,21,22,23,24,25]. For example, Ivan I. Kyrchei got the minimum norm least squares solutions of quaternion matrix equations AX=B, XA=B and AXB=D[7]; Zeyad Al-Zhour get the general solutions of three important partitioned quaternions systems[9]; Zhang get the j-self-conjugate least squares solution of quaternion matrix X−AˆXB=C[26]. But some matrices are difficult to be studied because of their complex structure, for example, Bisymmetric. Bisymmetric matrix is widely used in information theory, Markov process, physical engineering and other fields. But the process of studying it is very complicated due to its complex internal structures. So in this paper, we divide the quaternion Bisymmetric matrix into blocks and find out the relationship between the blocks. In addition, we apply it to solve the least squares problem of quaternion matrix equation
AXB=C, | (1.1) |
by the real representation[26]. The specific problem is as follows.
Problem 1. Let A, B, C∈Qn×n, and find out the set of least squares Bisymmetric solutions SBQ, i.e.,
SBQ={X|‖AXB−C‖=min, X∈BQn×n}. |
Find out the minimal form least squares solution XBQ∈SBQ, i.e.,
‖XBQ‖=minX∈SBQ‖X‖. |
This paper is organized as follows. In Section 2, we recall some preliminary results. In Section 3, we find out the relationship between the Bisymmetric matrix, Hermitian and Persymmetric matrix, which will be used to solve Problem 1. In Section 4, we provide numerical algorithms for computing the minimal norm least squares Bisymmetric solutions of (1.1), and provide some experiments with different dimensions. Finally in Section 5, we make some concluding remarks.
Definition 2.1. [17] Let A=(aij)∈Qn×n, A∗=(ˉaji)∈Qn×n, A(∗)=(ˉan−j+1,n−i+1)∈Qn×n. Then A(∗)=VnA∗Vn, in which Vn=[1⋱1].
(1) A∈Qn×n is called Hermitan if A=A∗.
(2) A∈Qn×n is called Persymmetric if A=A(∗).
(3) A∈Qn×n is called Bisymmetric if aij=an−i+1,n−j+1=ˉaji.
Definition 2.2. [26] For A=A1+A2i+A3j+A4k∈Qm×n, its real representation matrix AR is defined as below:
AR≡(A1A2A3A4−A2A1−A4A3−A3A4A1−A2−A4−A3A2A1). |
Now, we denote the i-th row block and column block of AR as ARri, ARci, respectively.
The Frobenius norm of the quaternion matrix A=A1+A2i+A3j+A4k is defined as
‖A‖=√‖A1‖2+‖A2‖2+‖A3‖2+‖A4‖2, |
and it is not difficult to verify ‖A‖=12‖AR‖=‖ARri‖=‖ARci‖, i=1,2,3,4.
The follows are some properties about ARri and ARci which can be used in this paper.
Lemma 2.1. [26] Suppose A, B∈Qm×n, C∈Qn×p, l∈R. The following properties hold.
(1) A=B⇔AR=BR⇔ARri=BRri⇔ARci=BRci, i=1,2,3,4.
(2) (A+B)Rri=ARri+BRri, (A+B)Rci=ARci+BRci, i=1,2,3,4.
(3) (lA)Rri=lARri, (lA)Rci=lARci, i=1,2,3,4.
(4) (AC)Rri=ARriCR, (AC)Rci=ARCRci, i=1,2,3,4.
For the real matrix equation, the 'vec' which arranges each column of a matrix into a vector in order is an important tool, the following result gives the relationship of vec(XR) and vec(XRr1).
Lemma 2.2. [26]Suppose X∈Qm×n. Then vec(XR)=Fvec(XRr1), where
F=(F1F2F3F4)∈R16mn×4mn, |
and
F1=(Im⋯00⋯00⋯00⋯00⋯0−Im⋯00⋯00⋯00⋯00⋯0−Im⋯00⋯00⋯00⋯00⋯0−Im⋯0⋮⋮⋮⋮⋮⋮⋮⋮0⋯Im0⋯00⋯00⋯00⋯00⋯−Im0⋯00⋯00⋯00⋯00⋯−Im0⋯00⋯00⋯00⋯00⋯−Im),F2=(0⋯0Im⋯00⋯00⋯0Im⋯00⋯00⋯00⋯00⋯00⋯00⋯0Im⋯00⋯00⋯0−Im⋯00⋯0⋮⋮⋮⋮⋮⋮⋮⋮0⋯00⋯00⋯Im0⋯00⋯Im0⋯00⋯00⋯00⋯00⋯00⋯00⋯Im0⋯00⋯00⋯−Im0⋯0), |
F3=(0⋯00⋯0Im⋯00⋯00⋯00⋯00⋯0−Im⋯0Im⋯00⋯00⋯00⋯00⋯0Im⋯00⋯00⋯0⋮⋮⋮⋮⋮⋮⋮⋮0⋯00⋯00⋯Im0⋯00⋯00⋯00⋯00⋯−Im0⋯Im0⋯00⋯00⋯00⋯00⋯Im0⋯00⋯0),F4=(0⋯00⋯00⋯0Im⋯00⋯00⋯0Im⋯00⋯00⋯0−Im⋯00⋯00⋯0Im⋯00⋯00⋯00⋯0⋮⋮⋮⋮⋮⋮⋮⋮0⋯00⋯00⋯00⋯Im0⋯00⋯00⋯Im0⋯00⋯00⋯−Im0⋯00⋯00⋯Im0⋯00⋯00⋯0). |
In this section, we will introduce the block matrices of Bisymmetric matrix, then we analyze the relationship between the internal elements of a Bisymmetric quaternion matrix, and solve Problem 1 according to this property and the real representation of quaternion matrix. Since the internal structures of Bisymmetric matrices are different in odd and even cases, we first consider the even case.
Theorem 3.1. Let X∈BQ2n×2n, and X is divided into four parts with the same dimension
X=(XaXbXcXd), |
where Xa and Xd are two Hermitian matrices, Xb Xc are two Persymmetric matrices, satisfy
Xa=VnXdVn, | (3.1) |
Xb=VnXcVn. | (3.2) |
Proof. The proof of (3.1) and (3.2) are similar, so we only prove (3.1).
Let X=[xaxbxcxd]∈Q2n×2n, and (xijk)=xk∈Qn×n, k=a, b, c, d, ″Xij" and ″xijk" are the element of ith row and jth column in X and xk, respectively, 1≤i,j≤n, then
Vn(xijd)Vn=(xn−i+1,n−j+1d), and xn−i+1,n−j+1d=X2n−i+1,2n−j+1. |
If X is an Bisymmetry matrix, then
(xija)=(Xij)=(X2n−i+1,2n−j+1)=(xn−i+1,n−j+1d)=Vn(xijd)Vn, |
(3.1) holds.
Obviously, the study of Bisymmetry matrix is transformed into Hermitian matrix and Persynmetric matrix by Theorem 3.1. In order to simplify the operation, we extract independent elements in Hermitian matrix and Persynmetric matrix.
Definition 3.1. For X∈Rn×n, let
α1=(x11,⋯,xn1), α2=(x22,⋯,xn2), ⋯, αn−1=(x(n−1)(n−1),xn(n−1)), αn=xnn.
β1=(x21,⋯,xn1), β2=(x32,⋯,xn2), ⋯, βn−2=(x(n−1)(n−2),xn(n−2)), βn−1=(xn(n−1)).
α′1=(x1n,⋯,xnn), α′2=(x2(n−1),⋯,xn(n−1)), ⋯, αn−1=(x(n−1)2,xn2), α′n=xn1.
β′1=(x2n,⋯,xnn), β′2=(x3(n−1),⋯,xn(n−1)), ⋯, β′n−2=(x(n−1)3,xn3), β′n−1=(xn2).
and
ved1(X)=(α1,⋯,αn)T, ved2(X)=(α′1,⋯,α′n)T, |
ved3(X)=(β1,⋯,βn−1)T, ved4(X)=(β′1,⋯,β′n−1)T. |
The following theorem introduces the relationship of independent elements and 'vec' of Hermitian matrix and Persymmetric matrix, respectively.
Theorem 3.2. For A∈SRn×n, B∈PRn×n, C and D are constructed by letting the diagonal elements of A and anti diagonal element of B be 0, respectively, then
vec(A)=W1ved1(A), vec(B)=W2ved2(B), vec(C)=W3ved3(C), vec(D)=W4ved4(D), |
in which
W1=(δ1nδ2nδ3n⋯δn−1nδnn00⋯00⋯0000δ1n0⋯00δ2nδ3n⋯δn−1nδnn⋯00000δ1n⋯000δ2n⋯00⋯000⋮⋮⋮⋮⋮⋮⋮⋮⋮⋮⋮⋮000⋯δ1n000⋯δ2n0⋯δn−1nδnn000⋯0δ1n00⋯0δ2n⋯0δn−1nδnn),W2=(000⋯0δ1n00⋯0δ2n⋯0δn−1nδnn000⋯δ1n000⋯δ2n0⋯δn−1nδnn⋮⋮⋮⋮⋮⋮⋮⋮⋮⋮⋮⋮00δ1n⋯000δ2n⋯00⋯0000δ1n0⋯00δ2nδ3n⋯δn−1nδnn⋯000δ1nδ2nδ3n⋯δn−1nδnn00⋯00⋯000), |
W3=(δ2nδ3n⋯δn−1nδnn0⋯00⋯0−δ1n0⋯00δ3n⋯δn−1nδnn⋯00−δ1n⋯00−δ2n⋯00⋯0⋮⋮⋮⋮⋮⋮⋮⋮00⋯−δ1n00⋯−δ2n0⋯δnn00⋯0−δ1n0⋯0−δ2n⋯−δn−1n),W4=(00⋯0−δ1n0⋯0−δ2n⋯−δn−1n00⋯−δ1n00⋯−δ2n0⋯δnn⋮⋮⋮⋮⋮⋮⋮⋮0−δ1n⋯00−δ2n⋯00⋯0−δ1n0⋯00δ3n⋯δn−1nδnn⋯0δ2nδ3n⋯δn−1nδnn0⋯00⋯0). |
Next, we give the relationship between 'vec' of a matrix and its four blocks.
Theorem 3.3. Let X=(XaXbXcXd)∈Qn×n, Xa∈Qk×k, k≤n, then
vec(X)=P′(vec(Xa)vec(Xc)vec(Xb)vec(Xd)), |
in which P′=diag(P1,P2), and
P1=(δ1n⋯δkn⋯0⋯0δk+1n⋯δnn⋯0⋯0⋮⋮⋮⋮⋮⋮⋮⋮0⋯0⋯δ1n⋯δkn0⋯0⋯δk+1n⋯δnn)∈Rnk×nk,
P2=(δ1n⋯δkn⋯0⋯0δk+1n⋯δnn⋯0⋯0⋮⋮⋮⋮⋮⋮⋮⋮0⋯0⋯δ1n⋯δkn0⋯0⋯δk+1n⋯δnn)∈Rn(n−k)×n(n−k).
Theorem 3.2 and Theorem 3.3 can be obtained by direct verification, so we omit the concrete proving process.
Theorem 3.4. Let A, B, C∈Q2n×2n, denote ˜A=(BR⊗ARr1)FP′KLW, in which
P=diag(P′,P′,P′,P′), K=diag(K1, K1, K1, K1), K1=diag(In2,In2,VT⊗V,VT⊗V), L=diag(L1, L1, L1, L1),
L1=(In200In20In2In20), W=diag(W1,W2,W3,W4,W3,W4,W3,W4), we can obtain
SHQ={X|ved(X)=((ved1(X1a)ved2(X1c))⋮(ved3(X4a)ved4(X4c))),ved(X)=˜A†vec(CRr1)+(I4n2−2n−˜A†˜A)y, ∀y∈R4n2−2n}. | (3.3) |
And then, the minimal norm least squares Bisymmetric solution XBQ of (1.1) satisfies
ved(XBQ)=˜A†vec(CRr1). | (3.4) |
Proof. By Lemma 2.1, we get
‖AXB−C‖=‖ARr1XRBR−CRr1‖=‖(BR⊗ARr1)vec(XR)−vec(CRr1)‖=‖(BR⊗ARr1)Fvec(XRr1)−vec(CRr1)‖. |
Let XRr1=(X1X2X3X4), and Xi=(XiaXibXicXid).
The next work is removing the repeated elements in vec(X).
vec(XRr1)=vec(X1aX1b⋯X4aX4bX1cX1d⋯X4cX4d)=(vec(X1aX1bX1cX1d)⋮vec(X4aX4bX4cX4d))=(P′(vec(X1a)vec(X1c)vec(X1b)vec(X1d))⋮P′(vec(X4a)vec(X4c)vec(X4b)vec(X4d)))=P((vec(X1a)vec(X1c)vec(VX1cV)vec(VX1aV))⋮(vec(X4a)vec(X4c)vec(VX4cV)vec(VX4aV)))=P(K1(vec(X1a)vec(X1c)vec(X1c)vec(X1a))⋮K1(vec(X4a)vec(X4c)vec(X4c)vec(X4a)))=PK((vec(X1a)vec(X1c)vec(X1c)vec(X1a))⋮(vec(X4a)vec(X4c)vec(X4c)vec(X4a)))=PK(L1(vec(X1a)vec(X1c))⋮L1(vec(X4a)vec(X4c)))=PKL((vec(X1a)vec(X1c))⋮(vec(X4a)vec(X4c)))=PKLW((ved1(X1a)ved2(X1c))⋮(ved3(X4a)ved4(X4c))). |
Thus
‖AXB−C‖=min, |
if and only if
‖˜Aved(X)−vec(CRr1)‖=min. |
For the real matrix equation
˜Aved(X)=vec(CRr1). |
According to the classical matrix theory, its least squares solutions can be represented as
ved(X)=˜A†vec(CRr1)+(I4n2−2n−˜A†˜A)y, ∀y∈R4n2−2n. |
Corollary 3.5. Let A, B, C∈Qn×n, (1.1) is compatible over BQn×n if and only if
(˜A˜A†−I16n2)vec(CRr1)=0. | (3.5) |
Moreover, if (3.5) holds, the solution set of (1.1) over BQn×n is
~SBQ={X∣ved(X)=˜A†vec(CRr1)+(I2n2−n−˜A†˜A)y, ∀y∈R2n2−n}, | (3.6) |
in which ˜A and ved(X) are described in Theorem 3.4.
Proof. (1.1) has a solution X if and only if
‖AXB−C‖=0. |
By Theorem 3.4 and the properties of the M-P inverse, we get
‖AXB−C‖=‖˜A˜A†˜Aved(X)−vec(CRr1)‖=‖˜A˜A†vec(CRr1)−vec(CRr1)‖=‖(˜A˜A†−I16n2)vec(CRr1)‖. |
Therefore for XBQ∈SBQ, we obtain
‖AXB−C‖=0⟺‖(˜A˜A†−I16n2)vec(CRr1)‖=0⟺(˜A˜A†−I16n2)vec(CRr1)=0. |
Thus (1.1) is compatible over BQn×n if and only if
(˜A˜A†−I16n2)vec(CRr1)=0. |
Moreover, according to the classical matrix theory, the solution XBQ satisfies
ved(XBQ)=˜A†vec(CRr1)+(I4n2−2n−˜A†˜A)y, y∈R4n2−2n. |
So the formula (3.9) holds.
Next, we discuss the case of odd Bisymmetric dimension.
By studying the odd dimensional Bisymmetric matrix, we find that for any X∈BQ(2n−1)×(2n−1), after dividing X into four blocks, X1∈Qn×n, X2∈Qn×(n−1), X3∈Q(n−1)×n, X4∈Q(n−1)×(n−1). Since Xi(i=1,2,3,4) do not have the same order. So we add the new n−th row between the original n−th row and the original (n+1)−th row, and add the new n−th column between the original n−th column and the original (n+1)−th column, then we can get the new matrix X′∈BQ2n×2n.
We can use Theorem 3.4 to solve the problem. Finally, we delete the added elements.
Define some matrices: (i) Z1=[0,I(n−1)]∈R(n−1)×n; (ii) Z2∈Rn×n is n×n zeros matrix; (iii) Z3∈R(n−1)×n is (n−1)×n zeros matrix.
Theorem 3.6. Let X∈BQ(2n−1)×(2n−1), then
(vec(X1)vec(X3)vec(X2)vec(X4))=E1(vec(X′1)vec(X′3)vec(X′2)vec(X′4)), |
where
E1=(H1H2H3H4), H1=In2,H2=(Z1⋱Z1)∈R(n−1)n×n2, |
H3=(Z2In⋮⋱Z2In)∈R(n−1)n×n2, H4=(Z3Z1⋮⋱Z3Z1)∈R(n−1)2×n2. |
The next work is to deal with independent elements.
In the following theorem, we associate the vec of X∈BQ(2n−1)×((2n−1)) with the vec of a newly constructed matrix X′∈BQ2n×2n.
Theorem 3.7. Let X∈BQ(2n−1)×(2n−1), we can obtain
vec(XRr1)=vec(X1aX1b⋯X4aX4bX1cX1d⋯X4cX4d)=PE(vec(X′1aX′1cX′1bX′1d)⋮vec(X′4aX′4cX′4bX′4d)), |
in which E=(E1E1E1E1),
Proof.
vec(XRr1)=vec(X1aX1b⋯X4aX4bX1cX1d⋯X4cX4d)=(P′vec(X1aX1cX1bX1d)⋮P′vec(X4aX4cX4bX4d))=(E1vec(X′1aX′1cX′1bX′1d)⋮E1vec(X′4aX′4cX′4bX′4d))=PE(vec(X′1aX′1cX′1bX′1d)⋮vec(X′4aX′4cX′4bX′4d)). |
Theorem 3.8. Let A, B, C∈BQ(2n−1)×(2n−1), denote ˜˜A=(BR⊗ARr1)FPEKLWG, in which G=(G1G2G2G2),G1=(In(n+1)/2G3In(n−1)/2), G2=(In(n−1)/2G4I(n−1)(n−2)/2),G3=((δn(n+1)2n(n+1)2)T⋮(δ(n+i)(n+1−i)2n(n+1)2)T⋮(δnn(n+1)2)T),G4=G3(n−1), the role of G is to delete added elements. We can obtain
SBQ={X|ved(X)=((ved1(X1a)ved2(X1c))⋮(ved3(X4a)ved4(X4c))),ved(X)=˜˜A†vec(CRr1)+(I4n2−6n+3−˜A†˜A)y, ∀y∈R4n2−6n+3}. |
And then, the minimal norm least squares Bisymmetric solution XBQ of (1.1) satisfies
ved(XBQ)=˜˜A†vec(CRr1). | (3.7) |
Corollary 3.9. Let A, B, C∈Q(2n−1)×(2n−1), (1.1) is compatible over BQ(2n−1)×(2n−1), if and only if
(˜˜A˜˜A†−I16n2)vec(CRr1)=0. | (3.8) |
Moreover, if (3.8) holds, the solution set of (1.1) over BQ(2n−1)×(2n−1) is
~SBQ={X∣ved(X)=˜˜A†vec(CRr1)+(I4n2−6n+3−˜˜A†˜˜A)y, ∀y∈R4n2−6n+3}, | (3.9) |
in which ˜˜A and ved(X) are described in Theorem 3.8.
In this section, we propose the corresponding algorithms based on the discussion in Section 3.
Algorithm 4.1. (For Problem 1)
(1) Input A, B, C∈Qn×n, output\ ARr1, BR, CRr1.
(2) Input F, P, E, K, L, W, G, output the matrix ˜A or ˜˜A.
(3) Output the minimal norm least squares solution XBQ according to (3.4) or (3.7).
Example. The following tables are the test of different dimensions of the minimal norm least squares solution of Problems 1 according to Algorithm 4.1. The specific steps are as follows: first, generating the appropriate A, B and X of the corresponding structure randomly in MATLAB, and calculate C=AXB, then use the method in this paper to calculate the numerical solution, and then compute the error between the real solution and the numerical solution. As shown in Figure 1.The below figure shows the effectiveness of the method in Section 3.
In this paper, we use internal relations between block Bisymmetric matrices, the real representation of quaternion matrix and the properties of M-P inverse to study the least squares Bisymmetric solution of AXB=C. We obtain the least squares Bisymmetric solution of this quaternion matrix equation and its compatable conditions. This method is effective and it is more convenient to analyze the problems of solution with special structures of quaternion matrix equation.
This work is supported by the Natural Science Foundation of Shandong under grant ZR2020MA053.
The authors declare that there is no conflict of interest.
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