Research article

Existence of two homoclinic solutions for a nonperiodic difference equation with a perturbation

  • Received: 25 November 2020 Accepted: 18 February 2021 Published: 25 February 2021
  • MSC : 39A12, 39A23

  • In the present paper, with the combination of a compactness lemma and variational techniques, we establish a sufficient condition to guarantee the existence of two nontrivial homoclinic solutions for a nonperiodic fourth-order difference equation with a perturbation. Our result generalizes and improves some known results.

    Citation: Yuhua Long. Existence of two homoclinic solutions for a nonperiodic difference equation with a perturbation[J]. AIMS Mathematics, 2021, 6(5): 4786-4802. doi: 10.3934/math.2021281

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  • In the present paper, with the combination of a compactness lemma and variational techniques, we establish a sufficient condition to guarantee the existence of two nontrivial homoclinic solutions for a nonperiodic fourth-order difference equation with a perturbation. Our result generalizes and improves some known results.



    It is well-known that homoclinic solutions play an important role in analyzing the chaos of dynamical systems. Hence, it is significative to deal with homoclinic solutions of dynamical systems. In the present paper, let Z and R be the set of integers and real numbers, respectively. For parameter λ>0, we investigate the existence of two nontrivial homoclinic solutions for the following nonperiodic fourth-order difference equation

    Δ4u(t2)+ωΔ2u(t1)+a(t)u(t)=f(t,u(t))+λh(t)|u(t)|p2u(t),tZ. (1.1)

    Here ω is a given constant, 1p<2. f(t,u):Z×RR is continuous in u and F(t,u)u=f(t,u). a(t):ZR and h(t):ZR+. Let Δu(t)=u(t+1)u(t) be the forward difference operator and define Δ0u(t)=u(t), Δiu(t)=Δ(Δi1u(t)) for i1. As usual, we say that a solution u={u(t)} of (1.1) is homoclinic (to 0) if lim|t|+u(t)=0. In addition, if u(t)0, then u is called a nontrivial homoclinic solution.

    Difference equations possess theoretical background and practical significance. For example, [1] proposes a Dirichlet boundary value problem of difference equation to represent the amplitude of the motion of every particle in the string, [2] uses difference equations to study the impact of dispersal of a two-patch SIR disease model and [3] studies Wolbachia infection in mosquito population based on discrete models. Consequently, difference equations have attracted many researchers' attentions and rich results are obtained. To mention a few, [4,5,6] establish criteria for the existence and multiplicity of solutions, [7,8,9,10,11] focus on sign-changing solutions and [12,13,14,15,16,17,18] deal with homoclinic solutions or heteroclinic solutions.

    Consider (1.1), it has been put forward as a discrete mathematical model for the study of pattern formation in physics and mechanics and deeply studied. For example, [19,20] investigate sign-changing of a special case of (1.1) by the invariant sets of descending flow. As mention to homoclinic solutions, which play an important role in analyzing the chaos of dynamical systems, there are many publications such as [21] studies (1.1) in a special form with periodic assumption and [22,23] prove that some special kind of (1.1) admits one nontrivial homoclinic solution. To the best of our knowledge, as considering homoclinic solutions for fourth order difference equations similar to (1.1), in the most known results of the existence of one non-zero homoclinic solution usually depend on periodic conditions or on the multiplicity with assumption of odevity on nonlinear terms. Meanwhile, using a compactness lemma and variational techniques, we achieve two nontrivial homoclinic solutions for (1.1) not only with neither periodic conditions nor odd-even requirements on nonlinear terms, but also with a perturbation. In some sense that our result improves and extends some known results.

    Let constants c0 be given in Lemma 2.2 and cs be the best constant for the embedding of a Hilbert space X, which is defined in Section 2, in Ls, 2s<+ and q(t):ZR+ with maxtZ{q(t)}=q>c0c22. Write

    μ=inf{uE:uE,+t=q(t)u2(t)=1}. (1.2)

    Remark 1.1. μ defined as (1.2) is reasonable. We state the proof of it in Lemma 3.2.

    With the above notations, now we establish our main result:

    Theorem 1.1. Let h(t):ZR+ with maxtZ{h(t)}=h>0. Assume a(t):ZR and there exists a constant a1 such that ω2a1 and

    0<a1a(t)+,as|t|+. (1.3)

    Further, for i1, suppose f(t,u):Z×RR is continuous in u and the following assumptions hold:

    (F1)f(t,u)0 for all u<0, tZ and there exists b(t):ZR+ with maxtZ{b(t)}=b<c0c222 such that

    limu0+f(t,u)ui=b(t)tZ,

    and

    f(t,u)uib(t)u>0,tZ;

    (F2)

    limu+f(t,u)ui=q(t)tZ;

    (F3) there exist two constants θ>2 and c0c22(θ2)4θ<d0<c0c22(θ2)2θ, such that

    F(t,u)1θf(t,u)ud0u2,u>0,tZ. (1.4)

    Then either (i)i=1 and μ<1 or (ii)i>1, there exists Λ0>0 such that (1.1) admits at least two distinct homoclinic solutions for every λ(0,Λ0).

    Remark 1.2. The assumptions in Theorem 1.1 are feasible. For example, take b(t)=c0c224 for all tZ. It follows that 0<maxtZ{b(t)}=c0c224<c0c222. Let

    f(t,u)={12πb(t)uiarctan(u+626+2),ifu0,foralltZ;0,ifu<0,foralltZ; (1.5)

    then

    F(t,u)={12πb(t)u0xiarctan(x+626+2)dx,ifu0,foralltZ;0,ifu<0,foralltZ.

    Consequently,

    limu0+f(t,u)ui=limu0+12πb(t)arctan(u+626+2)uiui=b(t)tZ,

    and

    limu+f(t,u)ui=limu+12πb(t)arctan(u+626+2)uiui=6b(t)=3c0c222:=q(t)>c0c22tZ,

    which means the assumptions (F1) and (F2) are satisfied.

    Moreover, from the expression of F(t,u), for all tZ and u0, we have

    F(t,u)=12πb(t)u0xiarctan(x+626+2)dx=12πb(t)xi+1i+1arctan(x+626+2)12πb(t)1i+1u0xi+11+(x+626+2)2dx.

    Obviously, xi+11+(x+626+2)2>0 for x>0, which follows that u0xi+11+(x+626+2)2dx0. Then one can verify that condition (F3) is satisfied.

    Remark 1.3. Our result improves and generalizes some known results. For example, similarly, [23] gives that there exists one homoclinic solution for the following difference equation

    Δ2(φp(Δ2u(t2)))aΔ(φp(Δu(t1)))+λV(t)φp(u(t))=f(t,u(t)). (1.6)

    (1.1) can be regarded as a special case of (1.6) when p=2. Our result Theorem 1.1 points out that (1.1) has at least two nontrivial homoclinic solutions. Meanwhile, according to [23], (1.1) possesses one homoclinic solution. Therefore, our result improves the result in [23] in some sense.

    The organization of the paper is as follows: After this introduction, we present some basic lemmas and establish the corresponding variational functional to (1.1) in Section 2. Section 3 provides the detailed proof of our main result.

    In this section, we give some notations and basic lemmas to prepare for the proof of our main result Theorem 1.1.

    Denote u={u(t)}tZ=(,u(t),,u(1),u(0),u(1),,u(t),). Let the set of all two-sided sequences S={u={u(t)}:u(t)R,tZ}, then S is a vector space with au+bv={au(t)+bv(t)} for u,vS, a,bR. Define a subspace E of S as

    E={uS:+t=[|Δ2u(t1)|2ω|Δu(t1)|2+a(t)|u(t)|2]<+}.

    For any u,vE, define

    <u,v>E=+t=[Δ2u(t1)Δ2v(t1)ωΔu(t1)Δv(t1)+a(t)u(t)v(t)].

    For later use, we define another Hilbert space (X,<u,v>X), where

    X={uS:+t=[|Δ2u(t1)|2+|Δu(t1)|2+|u(t)|2]<+}

    and, for any u,vX, the inner product is given by

    <u,v>X=+t=[Δ2u(t1)Δ2v(t1)+Δu(t1)Δv(t1)+u(t)v(t)].

    Then the corresponding norm is

    uX=<u,u>X=(+t=[|Δ2u(t1)|2+|Δu(t1)|2+|u(t)|2])1/2,u,vX.

    In what follows, let

    Ls={uS:uLs=(+t=|u(t)|s)1s<+}

    denote the space of functions whose s-th powers are summable on Z and

    uL=suptZ|u(t)|<+.

    Thus the following embedding between Ls spaces holds,

    LqLp,uLpuLq,1qp.

    Now we start to consider the variational functional of (1.1). Define a functional J:ER as

    J(u)=12+t=[Δ2u(t1)Δ2u(t1)ωΔu(t1)Δu(t1)+a(t)u(t)u(t)]+t=F(t,u(t))λ+t=h(t)|u(t)|p. (2.1)

    Then the continuity of f indicates that JC1(E,R) and, for any u,vE, its derivative is expressed as

    <J(u),v>E=+t=[Δ2u(t1)Δ2v(t1)ωΔu(t1)Δv(t1)+a(t)u(t)v(t)]+t=f(t,u(t))v(t)λ+t=h(t)|u(t)|p2u(t)v(t),

    which means that uE is a critical point of J if and only if u is a homoclinic solution of (1.1).

    Recall the definition of Cerami sequence and the variant version of the mountain pass theorem from critical point theory, which are helpful for us to seek critical points of (2.1).

    Definition 2.1. Let JC1(E,R). A sequence {un}E is called a Cerami sequence ((C)c sequence for short) for J if J(un)c for some cR and (1+un)J(un)0 as n. If any (C)c sequence for J possesses a convergent subsequence, then J satisfies the (C)c condition.

    Lemma 2.1. (Mountain pass theorem) ([24]) Let E be a real Banach space with its dual space E, and suppose that IC1(E,R) satisfies

    max{I(0),I(e)}μ<ηinfu=ρI(u),

    for some μ<η, ρ>0 and eE with e>ρ. Let ˆcη be characterized by

    ˆc=infγΓmax0τ1I(γ(τ)),

    where Γ={γC([0,1],E):γ(0)=0,γ(1)=e} is the set of continuous paths joining 0 and e, then there exists a sequence {un}E such that

    I(un)ˆcηand(1+unE)I(un)E0,asn.

    Remark 2.1. Similar to [23], Lemma 2.1 allows us to find a (C)c sequence for J.

    In the following, we establish some compactness conditions.

    Lemma 2.2. Suppose a(t)a1>0 and ω<2a1, then for any uE

    +t=[Δ2u(t1)Δ2u(t1)ωΔu(t1)Δu(t1)+a(t)u(t)u(t)]c0u2X (2.2)

    is true for some constant c0>0.

    Proof. Since ω<2a1, we divide it into two cases.

    Case 1. ω<0. Take c0=min{ω,a1,1}, obviously,

    +t=[|Δ2u(t1)|2ω|Δu(t1)|2+a(t)|u(t)|2]c0+t=[|Δ2u(t1)|2+|Δu(t1)|2+|u(t)|2]

    which implies that (2.2) is true.

    Case 2. 0ω<2a1. In this case, it is easy to get ω2<4a1, then there exists k(0,3) satisfying

    3>k1ω2a1+(ω+2a11)2+3(ω+1)2.

    Hence,

    k2+2k(ω+2a11)3(ω+1)20. (2.3)

    Consider

    g(ξ):=ξ4+(13(ω+1)k)ξ2+(1+3(a11)k)ξR. (2.4)

    Denote

    :=(13(ω+1)k)24(1+3(a11)k),

    then (2.3) ensures

    0,

    which indicates that

    g(ξ)0,ξR.

    Therefore, for k(0,3), we have

    (ω+1)ξ2a1+1k3(1+ξ2+ξ4),ξR. (2.5)

    Analogous to [25], for any u(t)X, we take

    u(t)=tZeiζtˉu(ζ),

    then

    Δu(t1)=(1eiζ)tZeiζtˉu(ζ)andΔ2u(t1)=(1eiζ)2tZeiζtˉu(ζ).

    Denote ξ=1eiζφ(ζ), then ζ=φ1(ξ). Now we have

    u(t)=tZeiζtˉu(ζ)=tZeiφ1(ξ)tˉu(φ1(ξ))ˆu(ξ)

    and

    Δu(t1)=ξˆu(ξ),Δ2u(t1)=ξ2ˆu(ξ).

    Thanks to (2.5), there has

    +t=[|Δ2u(t1)|2ω|Δu(t1)|2+a(t)|u(t)|2]+t=[|Δ2u(t1)|2ω|Δu(t1)|2+a1|u(t)|2]=+ξ=(ξ4+ξ2+1(ω+1)ξ2+a11)|ˆu(ξ)|2+ξ=(ξ4+ξ2+1k3(ξ4+ξ2+1))|ˆu(ξ)|2=(1k3)+ξ=(ξ4+ξ2+1)|ˆu(ξ)|2=(1k3)u2X. (2.6)

    Choose c0=1k3>0, then (2.6) leads to u2Ec0u2X, that is, (2.2) holds for 0ω<2a1. Therefore, Lemma 2.2 is true and the proof is completed.

    With the help of Lemma 2.2, we obtain that <u,u>E is positive for all nonzero uE and E is a Hilbert space. Here and hereafter, we write

    u2E=+t=[|Δ2u(t1)|2ω|Δu(t1)|2+a(t)|u(t)|2].

    Now we state the main compactness lemma and present its proof in detail.

    Lemma 2.3. Let (1.3) hold and ω<2a1. Then, for 2s+, E is compactly embedded in Ls.

    Proof. First, we prove Lemma 2.3 holds for s=2.

    Define

    α(A)=inf|t|>Aa(t),A[0,+).

    From (1.3), α(A) increases and α(A)+ as |t|+.

    Let K be a bounded subset of E. It follows that, if uK, there exists a constant M>0 such that uEM. Thanks to (2.2), we have

    u2X1c0u2EM2c0andu2L2M2c0,uK.

    Hence, we have

    +t=a(t)|u(t)|2=+t=[|Δ2u(t1)|2ω|Δu(t1)|2+a(t)|u(t)|2|Δ2u(t1)|2+ω|Δu(t1)|2]+t=[|Δ2u(t1)|2ω|Δu(t1)|2+a(t)|u(t)|2+|ω||Δu(t1)|2]M2+|ω|+t=|Δu(t1)|2M2+4|ω|+t=|u(t)|2M2+|ω|4M2c0.

    Write ˆbM2+|ω|4M2c0. For any ϵ>0, take A0 large enough such that

    4ˆbα(A0)<ϵ22. (2.7)

    Since KE is bounded by M, there are u1,u2,,umK such that for any uK, there exists some ul (1lm) satisfying

    A0t=A0|u(t)ul(t)|ϵ2 (2.8)

    Combining (2.7) with (2.8), it yields

    +t=|u(t)ul(t)|2=|t|A0|u(t)ul(t)|2+|t|>A0|u(t)ul(t)|2 (2.9)
    ϵ22+|t|>A0a(t)α(A0)|u(t)ul(t)|2<ϵ22+4ˆbα(A0)<ϵ2

    which implies uulL20.

    Next we verify that our claim is true for s=+. Notice that for any nN, TZ, 2kN and uE, thanks to the Newton-Lebnitz formula of indefinite summation and step by step summation [26], we have

    t1s=T[(sT)n+1(tT)nΔu(s)]=(tT)u(t)t1s=T[u(s+1)Δ(sT)n+1(tT)n]

    and

    T+k1s=t[(T+ks)n+1(T+kt)nΔu(s)]=(T+kt)u(t)T+k1s=t[u(s+1)Δ(T+ks)n+1(T+kt)n].

    Hence, for all TtT+k1, we have

    ku(t)=t1s=T[(sT)n+1(tT)nΔu(s)+u(s+1)Δ(sT)n+1(tT)n]+T+k1s=t[(T+ks)n+1(T+kt)nΔu(s)+u(s+1)Δ(T+ks)n+1(T+kt)n].

    On the other hand, owing to aθ+bθ(a+b)θ holds for a,b0 and θ1, it follows

    t1s=T|(sT)n+1(tT)nΔu(s)|+T+k1s=t|(T+ks)n+1(T+kt)nΔu(s)|1(tT)n(t1s=T|(sT)n+1|2)1/2(t1s=T|Δu(s)|2)1/2+1(T+kt)n(T+k1s=t|(T+ks)n+1|2)1/2(T+k1s=t|Δu(s)|2)1/2=12n+3(tT)3/2(t1s=T|Δu(s)|2)1/2+12n+3(T+kt)3/2(T+k1s=t|Δu(s)|2)1/212n+3[(tT)3/2+(T+kt)3/2](T+k1s=T|Δu(s)|2)1/2k3/22n+3(T+k1s=T|Δu(s)|2)1/2. (2.10)

    In view of a+b2a+b (a,b0), similar to (2.10), we have

    t1s=T|u(s+1)Δ(sT)n+1(tT)n|+T+k1s=t|u(s+1)Δ(T+ks)n+1(T+kt)n|2k(n+1)2n+1(T+k1s=T|u(s+1)|2)1/2. (2.11)

    Therefore, for all TtT+k1 and 2kN, with the aid of (2.10) and (2.11), we have

    |u(t)|k2n+3(T+k1s=T|Δu(s)|2)1/2+2kn+12n+1(T+k1s=T|u(s+1)|2)1/2, (2.12)

    which implies that

    |u(t)v(t)|k2n+3(|s|A|Δ(u(s)v(s))|2)1/2+2(n+1)k(2n+1)(|s|A|u(s+1)v(s+1)|2)1/2k2n+3[(+s=|Δu(s)|2)1/2+(+s=|Δv(s)|2)1/2]+2(n+1)k(2n+1)(|s|>Aa(s)|u(s+1)v(s+1)|2α(A))1/2=4Mk2n+3+2(n+1)k(2n+1)2ˆbα(A)

    holds for any u,vK, A>0 and all |t|>A. For any ϵ>0, take first n large enough such that

    4Mk2n+3<ϵ2.

    Notice that 2kN, then, for any ϵ>0, choose A0 large enough such that

    2(n+1)k(2n+1)2ˆbα(A0)<ϵ2.

    Therefore, we can draw a conclusion that

    max|t|>A0|u(t)v(t)|<ϵ,u,vK. (2.13)

    By the same method of (2.8), it follows that

    max|t|A0|u(t)ul(t)|<ϵ. (2.14)

    Combing (2.13) with (2.14), we obtain

    uulL<ϵ. (2.15)

    Finally, we accomplish the proof of Lemma 2.3 by verifying it is correct for 2<s<+. Given an arbitrary uE, there has

    +t=|u(t)|s=+t=(|u(t)|s2|u(t)|2)maxtN|u(t)|s2+t=|u(t)|2=us2Lu2L2, (2.16)

    which implies that K is precompact in Ls. Combing (2.9), (2.15) and (2.16), we complete the proof of Lemma 2.3 immediately.

    In this section, we intend to prove the main result at length. Now we are in the position to state the following several lemmas which guarantee that the functional J, defined by (2.1), has the mountain pass geometry at first.

    Lemma 3.1. Let a(t) and ω satisfy the assumptions in Theorem 1.1 and the conditions (F1) and (F2) hold. Then there exist Λ0>0 and constants ρ,η>0 such that

    J(u)|uE=ρη>0

    for every λ(0,Λ0).

    Proof. For every ϵ>0, notice that the condition (F1) implies that there exists a constant δ>0 such that f(t,s)(b+ϵ)si(b+ϵ)s holds for 0<s<δ. From (F2), limsf(t,s)si=q(t) leads to limsf(t,s)si+1=0, which implies that there exists a constant M>0 big sufficiently such that f(t,s)si+1ϵ, that is, f(t,s)ϵsi+1 with s>M. Further, since f(t,s) is continuous, it is not difficult to choose a constant C such that f(t,s)si+1C for δsM. Therefore,

    f(t,s)(b+ϵ)s+ϵsi+1+Csi+1,sR, (3.1)

    which indicates that there exist Cϵ>0 and ri+2 such that

    F(t,s)b+ϵ2s2+Cϵr|s|r,sR. (3.2)

    For 2r<+, let cr be the best constants for the embedded of X in Lr. With the aid of Lemma 2.2, we get

    urEcr20urXcr20crrurLr,

    that is,

    urLr1cr20crrurE.

    Together with (3.1), for all uE, one can obtain

    +t=F(t,u(t))b+ϵ2+t=|u(t)|2+Cϵr+t=|u(t)|r=b+ϵ2u2L2+CϵrurLrb+ϵ2c0c22u2E+Cϵrcr20crrurE.

    Therefore,

    J(u)=12u2E+t=F(t,u(t))λ+t=h(t)|u(t)|p12u2Eb+ϵ2c0c22u2ECϵrcr20crrurEλcp20cpphupE=upE[12(1b+ϵc0c22)u2pECϵrcr20crrurpEλcp20cpph]. (3.3)

    By the last equation in (3.3), select ϵ=c0c222b>0 and denote t=uE0, we define

    g(t)=14t2pCϵrcr20crrtrp.

    Since r>2 and 1p<2, it is easy to find that g(t) will get its maximum value at t=(rcr20crr(2p)4Cϵ(rp))1r2ρ>0. Hence

    maxt0g(t)=g(ρ)=r24(rp)((2p)rcr20crr4(rp)Cϵ)2pr2M>0.

    Combing with (3.3), it yields that there exists Λ0=Mcp20cpph>0 such that we can find a constant η>0 which satisfies J(u)|uE=ρη for every λ(0,Λ0).

    Lemma 3.2. Let ρ and Λ0 be defined in Lemma 3.1. Suppose that the conditions (F1) and (F2) hold, then for every λ(0,Λ0) there exists eE with eE>ρ such that J(e)<0 holds for either i=1 and μ<1 or i>1.

    Proof. We give the proof in two cases.

    Case Ⅰ. If i=1 and μ<1, we first declare μ, defined as (1.2), is reasonable. Let uE satisfy +t=q(t)u2(t)=1. Then

    1=+t=q(t)u2(t)q+t=u2(t)=qu2L2,

    which means that u2L21q. In view of Lemma 2.2, we get

    u2Ec0u2Xc0c22u2L2c0c22q>0.

    Thus μc0c22q>0. Aim to get μ is attainable, let {un}E be a minimizing sequence of (1.2), then {un} is bounded and satisfies +t=q(t)u2n(t)=1. Choose a subsequence of {un}, without loss of generality, still denoted by {un}. In view of Lemma 2.3, there exists ϕ1E such that unϕ1 weakly in E and unϕ1 strongly in L2. Hence

    +t=q(t)u2n(t)+t=q(t)ϕ21(t)asn,and+t=q(t)ϕ21(t)=1.

    Therefore,

    μ+t=[(Δ2ϕ1(t1))2ω(Δϕ1(t1))2+a(t)ϕ21(t)]limninf+t=[(Δ2un(t1))2ω(Δun(t1))2+a(t)u2n(t)]=μ,

    which indicates that μ=+t=[(Δ2ϕ1(t1))2ω(Δϕ1(t1))2+a(t)ϕ21(t)]=ϕ12E.

    Since μ<1, it is not difficult to choose 0φE with +t=q(t)φ2(t)=1 such that φE<1. Using the given condition (F2), we have

    lims+J(sφ)s2=12φ2Elims++t=F(t,sφ(t))s2lims+λs2+t=h(t)|sφ(t)|p12φ2Elims++t=F(t,sφ(t))s2=12φ2E+t=lims+f(t,sφ(t))φ(t)2s=12φ2E+t=lims+f(t,sφ(t))φ(t)2sφ(t)φ(t)=12φ2E12+t=q(t)φ2(t)=12(φ2E1)<0,

    which tells us that J(sφ) as s+. Then there exists eE with eE>ρ such that J(e)<0.

    Case Ⅱ. If i>1, in view of q(t):ZR+, we find there exists ψE such that

    +t=q(t)ψi+1(t)>0.

    In the same manner as Case Ⅰ, we have

    lims+J(sψ)si+1=lims+12sψ2E+t=F(t,sψ(t))λ+t=h(t)|sψ(t)|psi+1lims+ψ2E2si1lims++t=F(t,sψ(t))si+1=lims+ψ2E2si11i+1+t=q(t)ψi+1(t)1i+1+t=q(t)ψi+1(t)<0.

    Therefore, there exists eE with eE>ρ such that J(e)<0. The proof is completed.

    Notice Lemma 3.1 and Lemma 3.2 show that J meets all conditions in Lemma 2.1, hence J possesses a (C)c sequence {un}E for the mountain pass level β which is defined by

    β=infγΓmax0t1J(γ(t))

    and Γ={γC([0,1],E)|γ(0)=0,γ(1)=e}.

    In the following, we set out to look for homoclinic solutions for (1.1). Denote Bρ={uE:uE<ρ}, where ρ is given by Lemma 3.1. We first seek for a critical point of J by showing J attains a local minimum for small λ.

    Lemma 3.3. Let ρ and Λ0 be defined in Lemma 3.1. Assume a(t), ω and h(t) satisfy Theorem 1.1 and (F1) hold. Then, for λ(0,Λ0), (1.1) possesses a homoclinic solution u0E such that

    J(u0)=inf{J(u)|uˉBρ}<0.

    Proof. Since h(t):ZR+, it is convenient to select ζE such that +t=h(t)|ζ(t)|p>0. For κ>0 small enough, (F1) induces F(t,κζ(t))>0 is correct for all tZ. Then for 1p<2, one has

    J(κζ)=12κζ2E+t=F(t,κζ(t))λ+t=h(t)|κζ(t)|p=κ22ζ2E+t=F(t,κζ(t))λκp+t=h(t)|ζ(t)|pκ22ζ2Eλκp+t=h(t)|ζ(t)|p<0

    Write minf{J(u):u¯Bρ}, then m<0. Thus there exists a minimizing sequence {un}E such that J(un)m and J(un)0 as n. Therefore, Lemma 2.3 ensures that J admits a critical point u0E which satisfies J(u0)=0 and J(u0)=m<0.

    In view of Lemma 3.3, it is necessary for us to show that there exists another ˉuE such that J(ˉu)=0 and ˉuu0 to accomplish the proof of Theorem 1.1.

    Proof of Theorem 1.1. We complete the proof in two steps.

    Step 1. The (C)c sequence {un}E of J, defined by

    J(un)β>0and(1+unE)J(un)E0,asn,

    is bounded. Let n be large enough. By the condition (F3) and Lemma 3.1, it follows that

    β+1J(un)1θ<J(un),un>=(121θ)un2E+t=[F(t,un(t))1θf(t,un(t))un(t)]λ(11θ)+t=h(t)|un(t)|pθ22θun2Ed0+t=u2n(t)λ(11θ)h+t=|un(t)|pθ22θun2Ed0un2L2λ(11θ)hunpLpθ22θun2Ed0c0c22un2Eλ(11θ)hcp20cppunpE=(θ22θd0c0c22)un2Eλ(11θ)hcp20cppunpE<(θ22θc0c22(θ2)4θc0c22)un2Eλ(11θ)hcp20cppunpE=θ24θun2Eλ(11θ)hcp20cppunpE. (3.4)

    Obviously, for θ>2 and p<2, (3.4) implies unE is bounded for all λ(0,Λ0).

    Step 2. Now it is time for us to verify that J has another critical point ˉu which satisfies J(ˉu)=0 and J(ˉu)=β>0. Since the (C)c sequence {un}E of J is bounded, from Lemma 2.3, there exists ˉuE satisfying, up to a subsequence,

    unˉuweakly inE,unˉustrongly inL2.

    Together with the Hölder inequality, it follows that

    +t=[f(t,un(t))f(t,ˉu(t))](un(t)ˉu(t))0,asn,

    and

    +t=[h(t)(|un(t)|p2un(t)|ˉu(t)|p2ˉu(t))](un(t)ˉu(t))0,asn.

    On the other hand, the definition of J(u) indicates that

    unˉu2E=<J(un)J(ˉu),unˉu>E+t=[f(t,un(t))f(t,ˉu(t))](un(t)ˉu(t))λ+t=[h(t)(|un(t)|p2un(t)|ˉu(t)|p2ˉu(t))](un(t)ˉu(t)).

    Hence unˉu strongly in E. Moreover, J(ˉu)=β>0 and ˉu is another homoclinic solution of (1.1). Consequently, u0 and ˉu are two distinct homoclinic solutions of (1.1). And the proof of Theorem 1.1 is finished.

    The author sincerely thanks the handling editor and the anonymous referees for their valuable comments and suggestions.

    All authors declare no conflicts of interest in this paper.



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