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Existence of solutions to some quasilinear degenerate elliptic systems with right hand side in a Marcinkiewicz space

  • We prove the existence of a solution to a quasilinear system of degenerate equations, when the datum is in a Marcinkiewicz space. The main assumption asks the off-diagonal coefficients to have support in the union of a geometric progression of squares.

    Citation: Patrizia Di Gironimo, Salvatore Leonardi, Francesco Leonetti, Marta Macrì, Pier Vincenzo Petricca. Existence of solutions to some quasilinear degenerate elliptic systems with right hand side in a Marcinkiewicz space[J]. Mathematics in Engineering, 2023, 5(3): 1-23. doi: 10.3934/mine.2023055

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  • We prove the existence of a solution to a quasilinear system of degenerate equations, when the datum is in a Marcinkiewicz space. The main assumption asks the off-diagonal coefficients to have support in the union of a geometric progression of squares.



    In this article we consider the following quasilinear boundary value problem

    {div(a(x,u(x))Du(x))=f(x),xΩu=0,xΩ (1.1)

    where ΩRn, with n3, f,u:ΩRN, with N2, and a:Ω×RNRN2n2 is a matrix valued function whose entries are aα,βi,j(x,u) with i,j{1,,n} and α,β{1,,N}. Therefore the first line in (1.1) is a system of N equations of the form

    ni=1Di(nj=1Nβ=1aα,βi,j(x,u)Djuβ)=fαα=1,,N. (1.2)

    For the treated problem there is an extensive literature in the scalar case N=1.

    In particular, for the existence of a suitably defined solution, the Reader can refer to the papers [9,10,14,58,69] while, relatively to uniqueness and a priori estimates, we can quote respectively the papers [67] and [3]. For what concerns the regularity of a solution we cite the works [35,38]. Moreover, similar conclusions for the nonlinear case can be found in [2,8,12] and for the anisotropic case in [4,36]. Subsequently the aforementioned results have been extended to the operator with lower order terms too (see also [15,16,17,20,51]). In this context one can also see [7,11,12,24,25,30]. Furthermore, in [37] the right hand side appears in divergence form, that is f=divF and in [1] the biharmonic operator is studied.

    For further regularity results concerning elliptic operators the Reader is invited to refer to the foundamental works [5,6,26,27,28,41,42,43,44,45,46,47,48,64] and the survey [65].

    As it is shown by the De Giorgi's counterexample [29], see also [39,40,49,60,61], the good regularity properties obtained in the scalar case can not be in general extended to the vectorial one, unless new structural assumptions are introduced.

    An existence result of bounded weak solution for nonlinear degenerate elliptic systems is obtained in [55], using a componentwise coercivity condition. In several other papers, conditions on the support of the off-diagonal coefficients aα,βi,j(x) have been used to address different problems. Let us mention that a maximum principle result is obtained in [66] where the assumption is aα,βi,j(x,y)=0 for αβ when yα is large and in [52] where different shapes of support are considered. Hölder continuity of the solutions is proved in [70] for a tridiagonal system, aα,βi,j=0 for β>α. L regularity results are obtained in [53] for an oblique type of support for the coefficients and in [54] for a butterfly support. Measure data problems are faced in [56] and [57] where the support of aα,βi,j(x,y) is contained in squares along the yα=±yβ diagonals.

    These kind of assumptions on the coefficients have been recently employed also to deal with degenerate elliptic systems. In this context there are results on problem (1.1) when the datum fLm, which extend the ones contained in [14] for the scalar case. Namely, in [31] the existence of a bounded solution is proved when m>n2, assuming a butterfly support for the off-diagonal coefficients; moreover in [32] the case of a datum f with an intermediate grade of integrability (m<n2) is treated, thanks to an appropriate choice of the support for the off-diagonal coefficient.

    In this paper we extend to the degenerate vectorial problem (1.1) an existence result concerning degenerate scalar operators, with the datum f in a suitable Marcinkiewicz space, contained in [14,62,63] (see also [21,22]). Since we are dealing with the vectorial case the support of the coefficients is required to have a particular structure. In Section 2 we give the precise notions of degenerate ellipticity and Marcinkiewicz spaces, see respectively (A2) and definition 1, while the assumption on the shape of the support of the coefficients is stated in (A3).

    Also in this context the extension to the vectorial case of the known result in the scalar one is not obvious. Indeed, starting from De Giorgi's counterexample, it is possible to construct an example of an elliptic system with datum fLp for every p<n, whose unique solution is unbounded and has low integrability, see [31] for details on the counterexample.

    When dealing with systems of N equations, like (1.2), whose coefficients are only measurable with respect to x, little is known. Most articles are devoted to study existence or regularity of solutions of systems with right hand side fαLm, either when m is large, or when m is small. When m is large, namely m>n2, existence of bounded solutions is obtained in [31].

    When m is small, namely m=1, or even when fα is a measure, existence of solutions have been studied for general systems

    ni=1Di(Aαi(x,u,Du))=fα,α=1,,N, (1.3)

    under structure conditions on Aαi. Namely, in [33] and [34], authors assume that

    0ni=1Aαi(x,y,ξ)((Idb×b)ξ)αi (1.4)

    for every bRN with |b|1. On the other hand, in [71], the author assumes the componentwise sign condition

    0ni=1Aαi(x,y,ξ)ξαi (1.5)

    for every α=1,,N. When N=2, (1.4) implies (1.5): it is enough to take first b=(1,0), then b=(0,1). Note that, in the present paper, we address the quasilinear case

    Aαi(x,y,ξ)=Nβ=1nj=1aα,βi,j(x,y)ξβj; (1.6)

    in this case, as far as one off-diagonal coefficient a˜α,˜β˜i,˜j(x,y) is non zero, then (1.5) is no longer true: it is enough to take α=˜α, ξβj=0 if β{˜α,˜β}, ξ˜αi=0 if i˜i, ξ˜α˜i=1, ξ˜βj=0 if j˜j, ξ˜β˜j=ta˜α,˜β˜i,˜j(x,y)|a˜α,˜β˜i,˜j(x,y)|2 with t. When N=2, failure of (1.5) implies failure of (1.4). We recall that the study of quasilinear systems (1.2) with fαL1 is contained in [57] under the assumption that the support of off-diagonal coefficients is contained in a sequence of squares with side lenght r along the diagonals of the yαyβ plane.

    Concerning existence and regularity of suitable defined solutions of linear ellitptic systems

    ni=1Di(Aαi(x)Du)=fα,α=1,,N,

    with VMO coefficients and datum f=(fα) in a Lebesgue space Lγ with γ(1,2nn+2] (i.e., below the duality exponent) or in a suitable Lorentz-Morrey space one can refer also to [50]. While if f belongs to the natural dual Lebesgue space but the linear operator in not coercive due to the presence of a lower order term, called "drift term",

    ni=1Di[Aαi(x)DuEαi(x)u]=fα(x)

    then existence and regularity results can be found in [19]. The above result has been extended to non linear operator under the so-called Landes condition (similar to (1.4)) with datum being in L1 or in L2nn+2 respectively in [18,23].

    In the present work we address the existence of a regular solution to (1.2) when fα has an intermediate degree of integrability, namely, fαMm with 1<2nn+2θ(n2)<m<n2 and Mm is the Marcinkiewicz space. In this case, the higher degree of integrability of the right hand side fα allows us to weaken the condition on the support of off-diagonal coefficients.

    In the next section we present assumptions on the coefficients and on the datum f and our result. In Section 3 we consider a sequence of approximating non degenerate problems and we prove estimates on their weak solutions; then, with a limit procedure, we get the result for our problem.

    For all i,j{1,,n} and all α,β{1,,N} we assume that aα,βi,j:Ω×RNR satisfies the following conditions:

    (A0) xaα,βi,j(x,y) is measurable and yaα,βi,j(x,y) is continuous;

    (A1) (boundedness of all the coefficients) there exists c>0 such that

    |aα,βi,j(x,y)|c

    for almost every xΩ and for all yRN;

    (A2) (degenerate ellipticity of all the coefficients) there exist constants ν>0 and θ(0,1) such that

    Nα,β=1ni,j=1aα,βi,j(x,y)ξαiξβjνNα=1|ξα|2(1+|yα|)θ,

    for almost every xΩ, for all yRN and ξRN×n;

    (A3) (support of off-diagonal coefficients) there exists L01 such that (A3) and (A3) hold, where

    (A3) (support of off-diagonal coefficients contained in a central square) if aα,βi,j(x,y)0 and 0|yα|<L0, then it holds also 0|yβ|<L0;

    (A3) (support of off-diagonal coefficients contained in the union of a geometric progression of squares) if aα,βi,j(x,y)0 and there exists tN{0} such that 2tL0|yα|<2t+1L0, then it holds also 2tL0|yβ|<2t+1L0.

    Let us remark that from assumption (A2) it follows that we have degeneracy in the α equation when uα is large. In [13] is treated for N=2 the case in which degeneracy in the α equation arises when uβ is large, with βα.

    Note that (A3) and (A3) are always fulfilled when α=β. On the contrary, when αβ, (A3) forces the support of aα,βi,j(x,y) to be contained in the union of infinite squares along the diagonals, see grey region in Figure 1.

    Figure 1.  Assumption (A3).

    On f we assume that it belongs to the Marcinkiewicz space Mm(Ω,RN), with

    2nn+2θ(n2)<m<n2.

    For the convenience of the Reader, we recall the definition of Marcinkiewicz spaces, also known as weak Lebesgue spaces.

    Definition 2.1. Let m be a positive number. We say that a measurable function f:ΩR belongs to the Marcinkiewicz space Mm(Ω,R) if there exists a positive constant c sucht that

    |{xΩ:|f(x)|>t}|<ctm,t>0; (2.1)

    in such a case we set

    Mm(f,Ω)=(inf{c>0suchthat(2.1)holds})1m.

    Mm(Ω,RN) is the space of functions f=(f1,,fN) such that fiMm(Ω,R) for each i. Moreover Mm(f)=Nα=1Mm(fα).

    We recall some properties on Marcinkiewicz spaces:

    Lm(Ω)Mm(Ω)Lmε(Ω),m>1,0<εm1 (2.2)

    and

    E|f|dxMm(f,Ω)|E|11m,fMm(Ω),EΩ. (2.3)

    For more details on Marcinkiewicz space see [10,68].

    Let us explicitly remark that, being 0<θ<1, from (2.2) it follows that

    fL2nn+2(Ω),fMm(Ω)withm>2nn+2θ(n2). (2.4)

    Under our set of assumptions we prove the following theorem:

    Theorem 2.1. Assume (A0), (A1), (A2), (A3), with n3. If fMm(Ω,RN), with 2nn+2θ(n2)<m<n2, then there exists uW1,20(Ω,RN)Mr(Ω,RN), with

    r=nm(1θ)n2m, (2.5)

    weak solution of the problem (1.1), that is such that

    ΩNα,β=1ni,j=1aα,βi,j(x,u(x))Djuβ(x)Diφα(x)dx=ΩNα=1fα(x)φα(x)dx (2.6)

    for all φW1,20(Ω,RN).

    We set for all kN

    ˜aα,βi,j,k(x,y)=aα,βi,j(x,y)+1kδα,βδi,j

    with

    δi,j={1ifi=j0ifij.

    We consider the following family of approximating problems

    {ni=1Di(nj=1Nβ=1˜aα,βi,j,k(x,uk)Djuβk)=fα,xΩuk=0,xΩ. (˜Pk)

    We want to show the existence of a weak solution for each problem (˜Pk), that is a function ukW1,20(Ω,RN) such that

    ΩNα,β=1ni,j=1˜aα,βi,j,k(x,uk(x))Djuβk(x)Diφα(x)dx=ΩNα=1fα(x)φα(x)dx (3.1)

    for all φW1,20(Ω,RN).

    Let us first show some properties of the coefficients ˜aα,βi,j,k. From assumption (A1) it follows that

    |˜aα,βi,j,k(x,y)|c+1. (˜A1)

    Using assumption (A2) we have the following non degenerate ellipticity condition

    Nα,β=1ni,j=1˜aα,βi,j,k(x,y)ξαiξβj==Nα,β=1ni,j=1aα,βi,j(x,y)ξαiξβj+1kNα,β=1ni,j=1δα,βδi,jξαiξβjνNα=1|ξα|2(1+|yα|)θ+1k|ξ|2. (3.4)

    Now let us show that for all fMm(Ω,RN), with m>2nn+2θ(n2), the linear operator

    F:W1,20(Ω,RN)RvΩNα=1fα(x)vα(x)dx

    is continuous. Indeed, using Hölder inequality, (2.4) and Sobolev embedding, we have for a suitable constant C>0

    |F(v)|=|ΩNα=1fα(x)vα(x)dx|Nα=1Ω|fα(x)vα(x)|dxNα=1fαL2nn+2vαL2nn2CNα=1fαL2nn+2vW1,20(Ω,RN)

    and the continuity of F is proved. Therefore we can apply the surjectivity result of Leray-Lions, see [59], and we have the existence of a weak solution uk for the problem (˜Pk), that is, there exists ukW1,20(Ω,RN) such that (3.1) holds true for every φW1,20(Ω,RN).

    In the next Lemma 3.1, arguing as in [14], we prove that the sequence {uk}kN is bounded in W1,20(Ω,RN)Mr(Ω,RN). We first recall the following elementary inequalities that will be used in the proof of Lemma 3.1. We have

    Mα=1apαM(Mα=1aα)p, (3.2)
    (Mα=1aα)pMpMα=1(aα)p, (3.3)
    Mα=1(aαbα)(Mα=1aα)(Mα=1bα), (3.4)

    provided aα,bα0 for all α{1,,M} and p>0.

    Lemma 3.1. Assume that fMm(Ω,RN) with 2nn+2θ(n2)<m<n2 and let uk be a weak solution of (˜Pk). Then the sequences ukW1,20(Ω,RN) and Mr(uk,Ω), with r given in (2.5), are bounded by a positive constant which depends only on L0, θ, m, n, N, ν, |Ω| and Mm(f,Ω).

    Proof. For any tN{0} and for L01 given by assumption (A3), we define the following functions

    G2tL0(s)={0if|s|2tL0s2tL0s|s|if|s|>2tL0

    and

    T2tL0(s)={sif2tL0s2tL02tL0ifs>2tL02tL0ifs<2tL0.

    We consider as test function in (3.1) the function φtW1,20(Ω,RN) defined as

    φt=(φ1t,,φNt)=(T2tL0(G2tL0(u1k)),,T2tL0(G2tL0(uNk))). (3.5)

    We introduce the sets

    Aαk,2tL0={xΩ:|uαk|2tL0}andBαk,2tL0={xΩ:2tL0|uαk|<2t+1L0}.

    For all α{1,,N} we have

    suppφαtAαk,2tL0,|φαt|2tL0andDiφαt=DiuαkIBαk,2tL0, (3.6)

    where IB(x)=1 if xB and IB(x)=0 otherwise. Moreover, using (A3), we have

    aα,βi,j(x,uk(x))IBαk,2tL0(x)=aα,βi,j(x,uk(x))IBαk,2tL0(x)IBβk,2tL0(x). (3.7)

    Indeed, if aα,βi,j(x,uk(x))=0 or xBαk,2tL0, then the (3.7) is obvious. If aα,βi,j(x,uk(x))0 and xBαk,2tL0, that is 2tL0|uαk|<2t+1L0, then for (A3) we have 2tL0|uβk|<2t+1L0 so that xBβk,2tL0.

    From (3.6), (3.7) and (A2) we have

    Nα,β=1ni,j=1˜aα,βi,j,k(x,uk(x))Djuβk(x)Diφαt(x)==Nα,β=1ni,j=1(aα,βi,j(x,uk(x))+1kδα,βδi,j)Djuβk(x)Diuαk(x)IBαk,2tL0(x)==Nα,β=1ni,j=1aα,βi,j(x,uk(x))Djuβk(x)IBβk,2tL0(x)Diuαk(x)IBαk,2tL0(x)++Nα=1ni=11k|Diuαk(x)|2IBαk,2tL0νNα=1|Duαk(x)IBαk,2tL0(x)|2(1+|uαk(x)|)θ. (3.8)

    Then, replacing in the left side of (3.1) the test function (3.5) and using (3.8), we get

    ΩNα,β=1ni,j=1˜aα,βi,j,k(x,uk(x))Djuβk(x)Diφαt(x)dxνNα=1Bαk,2tL0|Duαk(x)|2(1+|uαk(x)|)θdxνNα=1Bαk,2tL0|Duαk(x)|2(1+2t+1L0)θdx=ν(1+2t+1L0)θNα=1Bαk,2tL0|Duαk(x)|2dx. (3.9)

    Combining (3.9) with (3.1), we get

    Nα=1Bαk,2tL0|Duαk(x)|2dx(1+2t+1L0)θνΩNα=1fα(x)φαt(x)dx==(1+2t+1L0)θνNα=1Aαk,2tL0fα(x)φαt(x)dx. (3.13)

    Using Sobolev's embedding and (3.10) we have

    (Aαk,2tL0|φαt(x)|2dx)22=(Ω|φαt(x)|2dx)22CSΩ|Dφαt(x)|2dx=CSΩni=1|Diφαt(x)|2dx==CSΩni=1|Diuαk(x)IBαk,2tL0|2dx=CSBαk,2tL0ni=1|Diuαk(x)|2dx==CSBαk,2tL0|Duαk(x)|2dx, (3.11)

    where CS is the Sobolev embedding constant. Summing on α in (3.11) and using (3.10), we have

    Nα=1(Aαk,2tL0|φαt(x)|2dx)22CSNα=1Bαk,2tL0|Duαk(x)|2dxCS(1+2t+1L0)θνNα=1Aαk,2tL0fα(x)φαt(x)dx. (3.12)

    From (2.4) we have fL2nn+2(Ω) and, by Sobolev immersion, we have also φtL2=L2nn2. Then, using the Hölder inequality with exponents 2nn+2 and 2nn2=2 and applying (2.3) to the function |fα|2nn+2M(n+2)m2n(Ω), we deduce for all α=1,,n

    Aαk,2tL0fα(x)φαt(x)dx(Aαk,2tL0|fα(x)|2nn+2)n+22n(Aαk,2tL0|φαt(x)|2dx)12Mm(fα,Ω)|Aαk,2tL0|n+22n(12n(n+2)m)(Aαk,2tL0|φαt(x)|2dx)12. (3.13)

    From (3.12) and (3.13) it follows that

    Nα=1(Aαk,2tL0|φαt(x)|2dx)22CS(1+2t+1L0)θνNα=1Mm(fα,Ω)|Aαk,2tL0|mn+2m2n2nm(Aαk,2tL0|φαt(x)|2dx)12C1(2tL0)θNα=1|Aαk,2tL0|mn+2m2n2nm(Aαk,2tL0|φαt(x)|2dx)12,

    where C1 is a constant depending only on Cs, ν, Mm(f,Ω).

    Now, using last inequality and (3.3), (3.4), (3.2), we have

    (Nα=1Aαk,2tL0|φαt(x)|2dx)22N22Nα=1(Aαk,2tL0|φαt(x)|2dx)22N22C1(2tL0)θNα=1|Aαk,2tL0|mn+2m2n2nm(Aαk,2tL0|φαt(x)|2dx)12N22C1(2tL0)θ(Nα=1|Aαk,2tL0|mn+2m2n2nm)[Nα=1(Aαk,2tL0|φαt(x)|2dx)12]N1+22C1(2tL0)θ(Nα=1|Aαk,2tL0|mn+2m2n2nm)(Nα=1Aαk,2tL0|φαt(x)|2dx)12;

    Therefore

    (Nα=1Aαk,2tL0|φαt(x)|2dx)12N1+22C1(2tL0)θNα=1|Aαk,2tL0|mn+2m2n2nm. (3.14)

    Since φαt=T2tL0(G2tL0(uαk)), for all tN{0}, we have

    (Aαk,2tL0|φαt(x)|2dx)12(Aαk,2t+1L0|φαt(x)|2dx)12==(Aαk,2t+1L0(2tL0)2dx)12=2tL0|Aαk,2t+1L0|12;

    Then, summing on α and using (3.2) we have

    (Nα=1Aαk,2tL0|φαt(x)|2dx)121NNα=1(Aαk,2tL0|φαt(x)|2dx)121NNα=12tL0|Aαk,2t+1L0|12. (3.15)

    From (3.14) and (3.15) it follows that

    1NNα=12tL0|Aαk,2t+1L0|12N1+22C1(2tL0)θNα=1|Aαk,2tL0|mn+2m2n2nm

    and then

    Nα=1|Aαk,2t+1L0|121(2tL0)1θN2+22C1Nα=1|Aαk,2tL0|mn+2m2n2nm.

    From the last inequality and using (3.3) and (3.2) we have

    (Nα=1|Aαk,2t+1L0|)12N12Nα=1|Aαk,2t+1L0|121(2tL0)1θN2+32C1Nα=1|Aαk,2tL0|mn+2m2n2nm1(2tL0)1θN3+32C1(Nα=1|Aαk,2tL0|)mn+2m2n2nm;

    Therefore

    Nα=1|Aαk,2t+1L0|C2(2tL0)(1θ)2(Nα=1|Aαk,2tL0|)mn+2m2nm(n2), (3.16)

    where C2 is a positive constant depending only on N, n, CS, ν and Mm(f,Ω).

    Let us set

    γ=mn+2m2nm(n2)(0,1)

    and let us remark that for r given in (2.5) the following equality holds

    r(1θ)2=rγ. (3.17)

    Now, for all h>0 and for r given in (2.5), let us define

    ρ(h)=hrNα=1|Aαk,h|. (3.18)

    For all tN{0}, it follows from (3.16) that

    ρ(2t+1L0)=(2t+1L0)rNα=1|Aαk,2t+1L0|2r(2tL0)rC2(2tL0)(1θ)2(Nα=1|Aαk,2tL0|)mn+2m2nm(n2)==2rC2(2tL0)rγ(Nα=1|Aαk,2tL0|)γ==2rC2((2tL0)rNα=1|Aαk,2tL0|)γ=2rC2[ρ(2tL0)]γ.

    Therefore we obtain that there exists a constant C3=max(1,2rC2)1, depending only on N, n, CS, ν, Mm(f,Ω), θ and m such that, for all tN{0}, we have

    ρ(2t+1L0)C3[ρ(2tL0)]γ

    and, arguing by induction, it follows that

    ρ(2sL0)Cs1h=0γh3[ρ(L0)]γsC+h=0γh3[ρ(L0)]γs,sN. (3.19)

    Being γ<1 and ρ(L0)0, the elementary inequality

    [ρ(L0)]γs1+ρ(L0),sN (3.20)

    holds. Using the notation C4=C+h=0γh3=C11γ3 and putting together (3.19) and (3.20), we have

    ρ(2sL0)C4(1+ρ(L0)),sN, (3.21)

    where C41 is a constant depending only on N, n, CS, ν, Mm(f,Ω), θ and m.

    Using (3.21), we want to prove that there exists a constant C5 depending only on N, n, CS, ν, Mm(f,Ω), θ, m, L0 and |Ω| such that

    ρ(h)=hrNα=1|Aαk,h|C5,hL0. (3.22)

    Indeed, for h[L0,2L0], we have

    ρ(h)=hrNα=1|Aαk,h|(2L0)rNα=1|Ω|=(2L0)rN|Ω|. (3.23)

    For all h2L0 there exists sN and w[L0,2L0) such that h=2sw. Then, using (3.21) and (3.23), we have for all h2L0

    ρ(h)=ρ(2sw)=(2sw)rNα=1|Aαk,2sw|(2s+1L0)rNα=1|Aαk,2sL0|=2r(2sL0)rNα=1|Aαk,2sL0|==2rρ(2sL0)2rC4(1+ρ(L0))2rC4(1+(2L0)rN|Ω|):=C5. (3.24)

    From (3.23) and (3.24) follows (3.22).

    For all hL0, using (3.22), we have

    Nα=1|{xΩ:|uαk|>h}|Nα=1|Aαk,h|=ρ(h)hrC5hr; (3.25)

    for h(0,L0) we have

    Nα=1|{xΩ:|uαk|>h}|Nα=1|Ω|=NΩN|Ω|Lr0Lr0<N|Ω|Lr0hr. (3.26)

    Then, setting C6=max(C5,N|Ω|Lr0), from (3.25) and (3.26), we get

    Nα=1|{xΩ:|uαk|>h}|C6hr,h>0,

    proving the boundness of the sequence {uk}kN in Mr(Ω).

    It remains to prove that the sequence {uk}kN is bounded in W1,20(Ω,RN).

    From (3.10), for all tN{0}, we have

    Nα=1Ω|Duαk(x)|2dx=Nα=1{|uαk|<L0}|Duαk(x)|2dx+Nα=1{|uαk|L0}|Duαk(x)|2dx==Nα=1{|uαk|<L0}|Duαk(x)|2dx++t=0Nα=1{2tL0|uαk|<2t+1L0}|Duαk(x)|2dx==Nα=1{|uαk|<L0}|Duαk(x)|2dx++t=0Nα=1Bαk,2tL0|Duαk(x)|2dxNα=1{|uαk|<L0}|Duαk(x)|2dx++t=0(1+2t+1L0)θνNα=1Aαk,2tL0fα(x)φαt(x)dx. (3.27)

    Now we estimate the right hand side of (3.27).

    Observing that |φαt(x)|2tL0, for all x and for all tN{0}, and using (2.3), we have

    Aαk,2tL0fα(x)φαt(x)dx2tL0Aαk,2tL0|fα(x)|dx2tL0Mm(fα,Ω)|Aαk,2tL0|11m2tL0Mm(f,Ω)|Aαk,2tL0|11m.

    Summing on α=1,..,N the previous inequality, by (3.2), the definition of ρ in (3.18) and (3.22), we get

    Nα=1Aαk,2tL0fα(x)φαt(x)dx2tL0Mm(f,Ω)Nα=1|Aαk,2tL0|11m2tL0Mm(f,Ω)N(Nα=1|Aαk,2tL0|)11m=2tL0Mm(f,Ω)N(ρ(2tL0)(2tL0)r)11mC11m52tL0Mm(f,Ω)N(2tr)11mLr(11m)0==C11m5Mm(f,Ω)N(21r(11m))tL1r(11m)0.

    From this inequality it follows that

    +t=0(1+2t+1L0)θνNα=1Aαk,2tL0fα(x)φαt(x)dx+t=0(1+2t+1L0)θνC11m5Mm(f,Ω)N(21r(11m))tL1r(11m)0==C11m5Mm(f,Ω)NL1r(11m)0ν+t=0(1+2t+1L0)θ(21r(11m))tC11m5Mm(f,Ω)NL1r(11m)0ν+t=0(2t+2L0)θ(21r(11m))t==C11m5Mm(f,Ω)NL1r(11m)0ν+t=022θ2tθLθ0(21r(11m))t==C11m5Mm(f,Ω)N22θL1r(11m)+θ0ν+t=0(2θ+1r(11m))t. (3.28)

    Since 2nn+2θ(n2)<m<n2, it results that θ+1r(11m)<0 and the series in the right side of the last inequality converges; we have

    +t=0(1+2t+1L0)θνNα=1Aαk,2tL0fα(x)φαt(x)dxC7, (3.29)

    where C7 is a positive constant depending only on n,N,m,θ,ν,Mm(f,Ω),|Ω|,CS,L0.

    Now, let us prove that Nα=1{|uαk|<L0}|Duαk(x)|2dx is bounded.

    To this aim we use ψ=(ψ1,...,ψN)=(TL0(u1k),...,TL0(uNk)) as a test function in the weakly formulation (3.1) of problem (˜Pk). Observing that

    Diψα=DiuαkIBαk,0(x)

    where Bαk,0={xΩ:0|uαk(x)|<L0}, we have

    ΩNα=1fα(x)ψα(x)dx=ΩNα,β=1ni,j=1˜aα,βi,j,k(x,uk(x))Djuβk(x)Diψα(x)dx==ΩNα,β=1ni,j=1(aα,βi,j(x,uk(x))+1kδα,βδi,j)Djuβk(x)Diuαk(x)IBαk,0dx==ΩNα,β=1ni,j=1aα,βi,j(x,uk(x))Djuβk(x)Diuαk(x)IBαk,0dx++ΩNα=1ni=11k|Diuαk(x)|2IBαk,0dxΩNα,β=1ni,j=1aα,βi,j(x,uk(x))Djuβk(x)Diuαk(x)IBαk,0dx. (3.30)

    From (A3), we get

    aα,βi,j(x,uk(x))IBαk,0=aα,βi,j(x,uk(x))IBαk,0(x)IBβk,0(x). (3.31)

    Combining (3.30), (3.31) and (A2), we deduce that

    ΩNα=1fα(x)ψα(x)dxΩNα,β=1ni,j=1aα,βi,j(x,uk(x))Djuβk(x)Diuαk(x)IBαk,0dx==ΩNα,β=1ni,j=1aα,βi,j(x,uk(x))Djuβk(x)IBβk,0(x)Diuαk(x)IBαk,0(x)dxΩνNα=1|Duαk(x)|2IBαk,0(x)(1+|uαk(x)|)θdxν(1+L0)θNα=1Bαk,0|Duαk|2dx. (3.32)

    From (3.32) and (2.3), it follows that

    Nα=1Bαk,0|Duαk|2dx(1+L0)θνΩNα=1fα(x)ψα(x)dx(1+L0)θL0νNα=1Ω|fα(x)|dx(1+L0)θL0νNα=1Mm(f,Ω)|Ω|11m==(1+L0)θL0NνMm(f,Ω)|Ω|11m. (3.33)

    Therefore, combining (3.27), (3.29) and (3.33), we have

    Nα=1Ω|Duαk(x)|2dxNα=1{|uαk|<L0}|Duαk(x)|2dx++t=0(1+2t+1L0)θνNα=1Aαk,2tL0fα(x)φαt(x)dxC7+(1+L0)θL0NνMm(f,Ω)|Ω|11m:=C8,

    where C8 is a positive constant depending only on n,N,m,θ,ν,Mm(f,Ω),|Ω|,CS,L0, and the boundedness of uk in W1,20(Ω,RN) is proved.

    Proof of Theorem 2.1

    Proof. Let uk be a solution of (˜Pk). Lemma 3.1 states that the sequence of {uk} is uniformly bounded in Mr(Ω,RN) and in W1,20(Ω,RN). Then there exists a positive constant C such that Mr(uk,Ω)C and ukW1,20(Ω,RN)C for all kN. Being {uk} bounded in W1,20(Ω,RN) there exists a subsequence {ukλ} weakly converging in W1,20(Ω,RN) to a function uW1,20(Ω,RN). Moreover, by Rellich-Kondrachov embedding Theorem, Sobolev space W1,20(Ω,RN) is compactly embedded in L2(Ω,RN); then, there exists a subsequence, not relabeled, also in the sequel, strongly converging to u in L2. From L2 convergence we get pointwise convergence almost everywhere, up to a further subsequence. Briefly we write

    ukλuinW1,20(Ω),ukλuinL2(Ω),ukλ(x)u(x)almosteverywhereinΩ,Mr(uk,Ω)C,ukλW1,20(Ω,RN)C. (3.34)

    Now, we pass to the limit as λ+, in the weak formulation of problem (˜Pk), written when k=kλ, to prove that u solves problem (2.6). More precisely, we verify that for all φW1,20(Ω,RN)

    limλ+ΩNα,β=1ni,j=1˜aα,βi,j,kλ(x,ukλ(x))Djuβkλ(x)Diφα(x)dx==ΩNα,β=1ni,j=1aα,βi,j(x,u(x))Djuβ(x)Diφα(x)dx.

    To this aim, we estimate

    |ΩNα,β=1ni,j=1˜aα,βi,j,kλ(x,ukλ(x))Djuβkλ(x)Diφα(x)dx+ΩNα,β=1ni,j=1aα,βi,j(x,u(x))Djuβ(x)Diφα(x)dx||ΩNα,β=1ni,j=1[aα,βi,j(x,ukλ(x))aα,βi,j(x,u(x))]Djuβkλ(x)Diφα(x)dx|++|ΩNα,β=1ni,j=1aα,βi,j(x,u(x))[Djuβkλ(x)Djuβ(x)]Diφα(x)dx|++|ΩNα=1ni=11kλDiuαkλ(x)Diφα(x)dx|:==Ikλ+IIkλ+IIIkλ.

    We obtain the result by proving that Ikλ,IIkλ,IIIkλ tend to zero as λ+. We start to estimate Ikλ. Using Hölder inequality and boundedness of the sequence {ukλ} in W1,20(Ω) we have

    Ikλ=|ΩNα,β=1ni,j=1[aα,βi,j(x,ukλ(x))aα,βi,j(x,u(x))]Djuβkλ(x)Diφα(x)dx|Nα,β=1ni,j=1(Ω|aα,βi,j(x,ukλ(x))aα,βi,j(x,u(x))|2|Diφα(x)|2dx)12DjuβkλL2CNα,β=1ni,j=1(Ω|aα,βi,j(x,ukλ(x))aα,βi,j(x,u(x))|2|Diφα(x)|2dx)12. (3.35)

    For any i,j=1,,n and for any α,β=1,,N, using pointwise convergence in (3.34) and continuity of functions yaα,βi,j(x,y) we have that

    |aα,βi,j(x,ukλ(x))aα,βi,j(x,u(x))|2|Diφα(x)|20asλ+;

    moreover from (A1) we get

    |aα,βi,j(x,ukλ(x))aα,βi,j(x,u(x))|2|Diφα(x)|2(|aα,βi,j(x,ukλ(x))|+|aα,βi,j(x,u(x))|)2|Diφα(x)|2(c+c)2|Diφα(x)|2L1(Ω);

    therefore, by dominated convergence theorem, we obtain that

    (Ω|aα,βi,j(x,ukλ(x))aα,βi,j(x,u(x))|2|Diφα(x)|2dx)120asλ+.

    The above limit and (3.35) imply that Ikλ tends to zero as λ+.

    Observing that uβkλuβ in W1,20(Ω), for any i,j=1,,n and for any α,β=1,,N, we have

    Ωaα,βi,j(x,u(x))[Djuβkλ(x)Djuβ(x)]Diφα(x)dx0asλ+,

    hence IIkλ tends to zero as λ+.

    Using Hölder inequality and (3.34), it results that

    IIIkλ=|ΩNα=1ni=11kλDiuαkλ(x)Diφα(x)dx|1kλNα=1ni=1DiuαkλL2DiφαL21kλnNCφW1,20(Ω,RN).

    Passing to the limit as λ+, we obtain that IIIkλ tends to zero and the proof is completed.

    We acknowledge the support of GNAMPA, INdAM, MIUR, UNⅣAQ. S. Leonardi has been supported by Piano della Ricerca di Ateneo 2020-2022–PIACERI: Project MO.S.A.I.C. "Monitoraggio satellitare, modellazioni matematiche e soluzioni architettoniche e urbane per lo studio, la previsione e la mitigazione delle isole di calore urbano", Project EEEP & DLaD. S. Leonardi is member of the Gruppo Nazionale per l'Analisi Matematica, la Probabilità e le loro Applicazioni (GNAMPA) of the Istituto Nazionale di Alta Matematica (INdAM), codice CUP_E55F22000270001.

    The authors declare no conflict of interest.



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