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Research article

Two-sided jumps risk model with proportional investment and random observation periods

  • These authors contributed equally to this work.
  • Received: 07 May 2023 Revised: 29 June 2023 Accepted: 03 July 2023 Published: 13 July 2023
  • MSC : 65C30, 91B05, 91G05

  • In this paper, we consider a two-sided jumps risk model with proportional investments and random observation periods. The downward jumps represent the claim while the upward jumps represent the random returns. Suppose an insurance company invests all of their surplus in risk-free and risky investments in proportion. In real life, corporate boards regularly review their accounts rather than continuously monitoring them. Therefore, we assume that insurers regularly observe surplus levels to determine whether they will ruin and that the random observation periods are exponentially distributed. Our goal is to study the Gerber-Shiu function (i.e., the expected discounted penalty function) of the two-sided jumps risk model under random observation. First, we derive the integral differential equations (IDEs) satisfied by the Gerber-Shiu function. Due to the difficulty in obtaining explicit solutions for the IDEs, we utilize the sinc approximation method to obtain the approximate solution. Second, we analyze the error between the approximate and explicit solutions and find the upper bound of the error. Finally, we discuss examples of sensitivity analysis.

    Citation: Chunwei Wang, Jiaen Xu, Naidan Deng, Shujing Wang. Two-sided jumps risk model with proportional investment and random observation periods[J]. AIMS Mathematics, 2023, 8(9): 22301-22318. doi: 10.3934/math.20231137

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  • In this paper, we consider a two-sided jumps risk model with proportional investments and random observation periods. The downward jumps represent the claim while the upward jumps represent the random returns. Suppose an insurance company invests all of their surplus in risk-free and risky investments in proportion. In real life, corporate boards regularly review their accounts rather than continuously monitoring them. Therefore, we assume that insurers regularly observe surplus levels to determine whether they will ruin and that the random observation periods are exponentially distributed. Our goal is to study the Gerber-Shiu function (i.e., the expected discounted penalty function) of the two-sided jumps risk model under random observation. First, we derive the integral differential equations (IDEs) satisfied by the Gerber-Shiu function. Due to the difficulty in obtaining explicit solutions for the IDEs, we utilize the sinc approximation method to obtain the approximate solution. Second, we analyze the error between the approximate and explicit solutions and find the upper bound of the error. Finally, we discuss examples of sensitivity analysis.



    Risk theory is a significant area of research in financial mathematics and actuarial science and the two-sided jumps risk model can be traced back to Boucherie et al. [1]. Then, it was further studied and promoted by many scholars. For example, Zhang [2] studied a two-sided jumps risk model and derived the integral differential equation for the expected discount penalty function. Additionally, the Gerber-Shiu function is obtained in a special case (claim amount is exponential distribution). Cheung et al. [3] considered a two-sided jumps renewal risk model. Since ruin may not happen, they studied the joint moments of the total discounted claim costs and benefit costs. In some examples, explicit solutions (ES) are obtained under different cost functions. For further exploration of two-sided jumps, interested readers can refer to relevant literature [4,5,6,7,8].

    Based on the above studies on the two-sided jumps risk model, we defined the surplus process C(t) as

    C(t)=x+ctM1(t)i=1Yi+M2(t)i=1Zi,   t0,  (1.1)

    where x (x0) is the initial surplus, c (c>0) represents the constant rate of premium. Note that the two random components M1(t)i=1Yi and M2(t)i=1Zi in the model are both compound Poisson processes which respectively represent the total claim and aggregate random return at time t. {M1(t)}t0 and {M2(t)}t0 are homogeneous Poisson processes with rate λ1>0 and λ2>0, respectively. The claim sizes are given by the sequence of independent identically distributed (i.i.d.) positive random variables (r.v.'s) {Yi}i=1, the cumulative distribution function (c.d.f.) FY() and probability density function (p.d.f.) fY(), while the random return amount is given by the sequence of i.i.d. positive r.v.'s {Zi}i=1 with c.d.f. FZ() and p.d.f. fZ(). M1(t)=sup{i:T1+T2++Tit} and M2(t)=sup{i:K1+K2++Kit} are defined, where the i.i.d. inter-claim times {Ti}i=1 and the i.i.d. inter-gain times {Ki}i=1 have common exponential distributions with intensities λ1 and λ2 respectively.

    To safeguard the interests of all parties involved, especially the insured, insurance companies must make reasonable and effective use of their funds. Insurance companies tend to invest their surplus in a specific portfolio of risk-free and risky asset. As the investment income of insurance companies is becoming more and more important in their total income, it is necessary to consider the risk model of investment factors. For this purpose, we assume that an insurance company allocates a portion of its funds to risk-free investment and another portion to risky investment. Especially, the risk-free investment {Rt}t0 is of the form

    dRt=rRtdt, (1.2)

    where r denotes the interest rate of the risk-free asset, it is easy to know that r is greater than zero. The venture capital {Qt}t0 is defined as follows

    Qt=e(at+σWt), (1.3)

    where a and σ represent the expected rate of return and volatility of the risky asset respectively and both of them are positive. {Wt,t0} is the standard Brownian motion. The risky asset process {Qt}t0 satisfies

    dQtQt=(a+12σ2)dt+σdWt. (1.4)

    Let p (0<p<1) represent the proportion of all surplus invested in the risky asset. The remaining surplus is invested in the risk-free asset. Then, the surplus process of the insurance company can be written as

    dU(t)=pU(t)dQtQt+(1p)U(t)dRtRt+cdtdS1t+dS2t=pσU(t)dWt+(ξU(t)+c)dtdM1(t)i=1Yi+dM2(t)i=1Zi, (1.5)

    where ξ=(a+12σ2r)p+r and the security loading condition is c+λ2E[Z1]>λ1E[Y1].

    It is important to stress that in the above model, the surplus is considered to be observed continuously. But in real life, corporate boards regularly review the balance of their books to determine whether to pay dividends or whether the surplus is zero or less (e.g., Albrecher et al. [9] and [10], Zhuo et al. [11], Cheung and Zhang [12], Peng et al. [13], Zhang et al.[14]). In other words, dividends and surplus are observed in discrete time. So we introduce the random observation periods into the risk model. We assume that the insurer only observes the surplus process at a series of discrete time points {Sk}k=0 where Sk is the k-th observation time. In particular, S0=0, Sk is the time of ruin where k=inf{k1:X(k)<0}. Let Tk=SkSk1 be the k-th time interval between observations. In addition, {Tk}k=0 is assumed to be an i.i.d. sequence where the universal r.v.'s T follows a common exponential distribution with γ>0. At the same time, we assume that {Yi}i=1, {Zi}i=1, {M1(t)}t0, {M2(t)}t0, {Wt,t0} and {Tk}k=0 are mutually independent. Let X(k)=U(Sk) be the surplus level at the k-th observation. We have

    X(k)=X(k1)+SkSk1pσX(s)dWs+SkSk1(ξX(s)+c)dsSkSk1dM1(s)i=1Yi+SkSk1dM2(s)i=1Zi. (1.6)

    Gerber and Shiu [15] first proposed a discounted penalty function for ruin in an insurance risk model. This function has become a very important and powerful analytical tool in risk theory. Scholars studied the expected discounted penalty problem in various risk models. For example, Hu et al. [16] considered a dual risk model under a mixed dividends strategy and gave the general result of the Gerber-Shiu function under periodic observation. Yang et al. [17] studied the perturbed compound Poisson model under the constant barrier dividends strategy and used the Fourier-cosine (COS) method to approximate the expected present value of dividends payments before ruin and the Gerber-Shiu function. More relevant literature can be referred to [18,19,20,21,22,23]. The Gerber-Shiu function of the model (1.5) is defined as follows

    m(x)=E[eδSkω(X(k1),|X(k)|)I(Sk<)|X(0)=x], (1.7)

    where ω(x0,y0), (x00, y00) is a non-negative penalty function, X(k1) represents the instantaneous surplus before ruin, |X(k)| represents the deficit at ruin time, δ>0 is the discounted factor and I() is the indicative function.

    Remark 1.1. In particular, if δ=0 and ω(x0,y0)=1, m(x) is converted to the ruin probability ψ(x)=P(Sk<|X(0)=x). In addition, we assume that m(x) is fully smooth.

    To show the innovativeness of our research more intuitively, we compared our work with some relevant studies (see Table 1).

    Table 1.  Comparison table of relevant literature contributions.
    Research paper risk model numerical method random observation
    two-sided jumps investment Gerber-Shiu function
    (2005)Yuen and Wang [18]
    (2011)Albrecher et al. [10]
    (2013)Chen and Ou [19]
    (2013)Dong and Liu [4]
    (2018)Cheung et al. [3]
    (2018)Zhuo et al. [11]
    (2018)Zhang et al. [14]
    (2020)Palmowski and Vatamidou [7]
    (2021)Zhang [8]
    (2022)Yang et al. [17]
    (2022)Martín-González et al. [6]
    (2023)Hu et al. [16]
    (2023)Wang et al. [23]
    Our work

     | Show Table
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    From the perspective of the research on two-sided jumps, compared with the literature [3,4,6,7,8] in Table 1, we consider investing the funds of insurance companies to obtain greater returns. From the perspective of investment [14,18,19,23], the model we consider is more realistic, that is, surplus can only be observed at random observation times to determine whether to pay dividends or whether the surplus is zero or less. Most current studies [10,11,14,16] involving random observations do not consider random returns (upward jumps). We consider a more complex two-sided jumps model and solve it numerically using the sinc method.

    This article is organized as follows. In Section 2, we derive the IDEs and boundary conditions satisfied by the Gerber-Shiu function. In Section 3, we obtain the approximate solution (AS) of IDEs by the sinc numerical method. In Section 4, we discuss some examples of sensitivity analysis.

    It is important to note that if a claim occurs before the observation time, the surplus may be less than zero and cannot be observed. Thus, the domain of m(x) is extended to R even though time 0 is usually declared as an observation time. In addition, m(x) behaves differently when x is greater than and less than 0. For convenience, we denote

    m(x)={m1(x),x<0,m2(x),x0.

    Then, we get the following.

    Theorem 2.1. Assume that FY and FZ have a general continuous cumulative distribution function. Then, for any <x<0, m1(x) satisfies the integral differential equation

    12p2x2σ2m1(x)+(ξx+c)m1(x)(δ+γ+λ1+λ2)m1(x)+γω2(x)+λ2[x0m1(x+z)dFZ(z)+xm2(x+z)dFZ(z)]+λ10m1(xy)dFY(y)=0 (2.1)

    and for 0x<, m2(x) satisfies the integral differential equation

    12p2x2σ2m2(x)+(ξx+c)m2(x)(δ+λ1+λ2)m2(x)+λ1[x0m2(xy)dFY(y)+xm1(xy)dFY(y)]+λ20m2(x+z)dFZ(z)=0. (2.2)

    The following boundary conditions are satisfied

    limum1(x)=γδ+γ; (2.3)
    limum2(x)=0. (2.4)

    Proof. In the small interval (0, dt] and discussing whether the first time observation time occurs whether the first time claim occurs or whether the first time random return occurs. For <x<0, we get

    m1(x)=eδdt{(1γdt)P0E[m1(ht)]+γdtP0E[ω2(ht)]+(1γdt)P1E[m1(htY1)]+(1γdt)P2E[E[m1(ht+Z1)|Z1(0,ht)]+E[m2(ht+Z1)|Z1(ht,)]]} (2.5)

    and for 0x< we have

    m2(x)=eδdt{(1γdt)P0E[m2(ht)]+γdtP0E[m2(ht)]+(1γdt)P1[E[m2(htY1)|Y1(0,ht)]+E[m1(htY1)|Y1(ht,)]]+(1γdt)P2E[m2(ht+Z1)]} (2.6)

    where

    ht=x+pxσdWt+(ξx+c)dt, (2.7)
    P0=P(T1>dt,K1>dt)=1(λ1+λ2)dt+o(dt), (2.8)
    P1=P(T1dt,K1>dt)=λ1dt+o(dt), (2.9)
    P2=P(T1>dt,K1dt)=λ2dt+o(dt). (2.10)

    By Itˆo formula, we have

    E[mi(ht)]=E[mi(x)+htmi(x)+12(ht)2mi(x)]+o(t),  (i=1,2). (2.11)

    Substituting Eqs (2.7)–(2.11) into (2.5) and (2.6) respectively and letting dt approach 0. Finally, the IDEs (2.1) and (2.2) are obtained.

    If x, the ruin happens at the first observation time S1 and the time interval between observations obeys the exponential distribution of the parameter γ then the limit condition (2.3) can be obtained by using the definition of m(x); if x, ruin does not happen at all. Thus, condition (2.4) is satisfied. This completes the proof.

    Remark 2.1. Due to the smoothness of m(x), we obtain m1(0)=m2(0+). Refer to the analysis by Albrecher et al. [9], when x=0, simultaneous Eqs (2.3) and (2.4) can obtain cm1(0)=cm2(0+)+γm1(0). Therefore, m(x) is generally non differentiable.

    Since Frank Stenger [24] developed the sinc numerical method, it has been widely concerned and applied in numerical analysis such as [23,25,26]. The ES of Eqs (2.1) and (2.2) are difficult to obtain theoretically. So, we change our thinking and find the AS by numerical method. At present, the numerical methods for solving IDEs include the sinc method, finite element method, COS method, finite difference method and so on. In the sinc approximation method, the error between the approximate solution and the exact solution reaches exponential order convergence through exponential transformation (see [24]). At the same time, sinc function approximates the boundary value problem and oscillation problem well, see [27]. So, for our study we adopted the sinc method.

    Define one-to-one mapping of RR, let ς(z)=log(z+1+z2) where zR. For h>0, the sinc grid points zk (k=0,±1,±2,) are denoted by

    zk=ς1(kh)=ekhekh2, (k=0,±1,±2,).

    We apply the sinc method step to rearrange the Eqs (2.1) and (2.2) into

    12p2x2σ2m(x)+(ξx+c)m(x)(δ+γI(x<0)+λ1+λ2)m(x)+γω(x)I(x<0)+λ10m(xy)dFY(y)+λ20m(x+z)dFZ(z)=0. (3.1)

    Using the property of convolution, the Eq (3.1) can be further expressed as

    12p2x2σ2m(x)+(ξx+c)m(x)(δ+γI(x<0)+λ1+λ2)m(x)+γω(x)I(x<0)+λ1xm(y)fY(xy)dy+λ2xm(z)fZ(zx)dz=0. (3.2)

    Furthermore,

    limxm(x)=γδ+γ;limxm(x)=0.

    According to Definition 1.5.2 in reference [25] or Definition 1 in reference [19], it can be seen that

    g(x)=m(t1)+ζ(x)m(t2)1+ζ(x)

    where ζ(x)=eς(x)=x+1+x2. When t1=, t2, set

    H(x)=m(x)g(x)=m(x)γ(δ+γ)[1+x+1+x2]. (3.3)

    Then, H(x)Lˆα,τ,ˆd(ς) so

    m(x)=H(x)+g(x)=H(x)+γ(δ+γ)[1+x+1+x2], (3.4)
    m(x)=H(x)+g(x)=H(x)γ[1+x1+x2](δ+γ)[1+x+1+x2]2, (3.5)
    m(x)=H(x)+g(x)=H(x)γ[1+x+1+x2(1+x2)322(1+x1+x2)2](δ+γ)[1+x+1+x2]3. (3.6)

    Substituting (3.4)–(3.6) into (3.2), we have

    β0(x)H(x)+β1(x)H(x)+β2(x)H(x)+λ1xfY(xy)H(y)dy+λ2xfZ(zx)H(z)dz+R(x)=0 (3.7)

    where β0(x)=p2x2σ22, β1(x)=(ξx+c), β2(x)=(δ+γI(x<0)+λ1+λ2),

    R(x)=β0(x)g(x)+β1(x)g(x)+β2(x)g(x)+γω(x)I(x<0)+λ1xg(y)fY(xy)dy+λ2xg(z)fZ(zx)dz. (3.8)

    When x goes to or , the limit of H(x) is zero.

    Then, according to the Theorems 1.5.13, 1.5.14 and 1.5.20 in reference [25] we can get

    xfY(xy)H(y)dyNj=MNi=MωiAijUj, (3.9)
    xfZ(zx)H(z)dzNj=MNi=MωiBijUj, (3.10)
    H(x)˜H(x)=Nj=MUjS(j,h)ς(x), (3.11)

    where Aij and Bij are (i,j) elements of the matrix A=XF(S)X1 and B=YF(S)Y1, respectively, and S is a diagonal matrix. Uj represents an approximate estimate of H(uj).

    Substituting (3.9), (3.10) and (3.11) into Eq (3.7) then using the sinc grid points xk tends to x, we get

    Nj=M{β0(xk)ς(xk)δ(1)jkh+β0(xk)(ς(xk))2δ(2)jkh2+β1(xk)ς(xk)δ(1)jkh+β2(xk)δ(0)jk+λ1Ni=Mωi(xk)Aij+λ2Ni=Mωi(xk)Bij}Uj=R(xk),   k=M,,N (3.12)

    where

    δ(0)jk=[S(j,h)ς(z)]|z=zk={0, kj,1, k=j,δ(1)jk=hddς[S(j,h)ς(z)]|z=zk={(1)kjkj, kj,0,        k=j,δ(2)jk=h2d2dς2[S(j,h)ς(z)]|z=zk={2(1)kj(kj)2, kj,π23,       k=j.

    Multiply the Eq (3.12) by h2(ς(xk))2, we have

    Nj=M{β0(xk)δ(2)jk+h[β0(xk)ς(xk)(ς(xk))2+β1(xk)ς(xk)]δ(1)jk+h2β2(xk)(ς(xk))2δ(0)jk+h2(ς(xk))2[λ1Ni=Mωi(xk)Aij+λ2Ni=Mωi(xk)Bij]}Uj=h2R(xk)(ς(xk))2. (3.13)

    Since

    δ(0)jk=δ(0)kj,    δ(1)jk=δ(1)kj,    δ(2)jk=δ(2)kj,    ς(xk)(ς(xk))2=(1ς(xk)),

    the formula (3.13) can be turned into

    Nj=M{β0(xk)δ(2)kj+h[β0(xk)(1ς(xk))β1(xk)ς(xk)]δ(1)kj+h2β2(xk)(ς(xk))2δ(0)kj+h2(ς(xk))2[λ1Ni=Mωi(xk)Aij+λ2Ni=Mωi(xk)Bij]}Uj=h2R(xk)(ς(xk))2. (3.14)

    Set I(m)=[δ(m)kj](M+N+1)×(M+N+1), m=0,1,2. We rewrite Eq (3.14) as

    CU=R (3.15)

    where

    U=(UM,,UN)T,R=(h2R(xM)(ς(xM))2,,h2R(xN)(ς(xN))2),C=β0I(2)+hDm(β0(1ς)β1ς)I(1)+h2Dm(β2(ς)2)I(0)+h2λ1Dm(1(ς)2)ΩmA   +h2λ2Dm(1(ς)2)ΩmB.

    We continue to use the definition of Ωm in Chen and Ou [19].

    Solving Eq (3.15), we get the expression of the approximate solution of m(x):

    m(x)˜m(x)=˜H(x)+γ(δ+γ)[1+x+1+x2]=Nl=MUlS(j,h)ς(x)+γ(δ+γ)[1+x+1+x2]. (3.16)

    In this subsection, since what we obtain is the sinc approximation solution (AS) of the IDEs. It is necessary to analyze the error between the AS and the ES by referring to relevant literature (refer to [24] and [28]). We finally found the upper limit of the error. In addition, depending on the actual situation the initial surplus x is often greater than zero. So, in this section we will proceed under the condition of x>0. Multiply the Eq (3.7) by 1β0(x), we set

    G(x)=λ1β0(x)xfY(xy)H(y)dyλ2β0(x)xfZ(zx)H(z)dzR(x)β0(x),

    so we have

    H(x)+˜β1(x)H(x)+˜β2(x)H(x)=G(x) (3.17)

    where ˜β1(x)=β1(x)β0(x), ˜β2(x)=β2(x)β0(x).

    Assumption 3.1. We set ˜β1/ς, 1/((ς)) and ˜β2/(ς)2 belong to H(D), that G/(ς)2Lˆα(D) and the Eq (3.17) has a unique solution HLˆα(D).

    Theorem 3.2. Let Assumption 3.1 be satisfied, H represent the ES of (3.17), ˜H denote the AS satisfying (3.16) and U=(UM,,UN))T represent the ES of Eq (3.15). There exists a constant ˜c (˜c>0) independent of N, such that

    supxΓ|H(x)˜H(x)|˜cN5/2e(πdˆαN). (3.18)

    Proof. Let

    ϑN(x)=Nk=MH(xk)S(k,h)ς(x), (3.19)

    using the triangle inequality, it is easy to get

    |H(x)˜H(x)||H(x)ϑN(x)|+|ϑN(x)˜H(x)|. (3.20)

    Based on the Theorem 4.2.5 of [24], there exists a constant c that is greater than zero and independent of N and then by Assumption 3.1, HLˆα(D), we can get

    supxΓ|H(x)ϑN(x)|cN1/2e(πdˆαN). (3.21)

    In inequality (3.20), |ϑN(x)˜H(x)| satisfies the following relation

    |ϑN(x)˜H(x)|=|Nj=M[H(xj)Uj]S(j,h)ς(x)γ(δ+γ)[1+x+1+x2]|Nj=M|H(xj)Uj||S(j,h)ς(x)|(Nj=M|H(xj)Uj|2)(Nj=M|S(j,h)ς(x)|2)(Nj=M|H(xj)Uj|2)=HU. (3.22)

    Similar to Theorem 7.2.6 of [24], if xΓ then kZ|S(k,h)ς(x)|2=1, we have

    HU=C1C(HU)=C1[CHR]C1CHRcN5/2e(πdˆαN) (3.23)

    where c is independent of N. Therefore, the inequality (3.18) is finally obtained by combining formulas (3.19)–(3.23).

    Through formulas (3.4), (3.16) and (3.18), we get

    supxΓ|m(x)˜m(x)|˜cN5/2e(πdˆαN). (3.24)

    In this section, we assume that the p.d.f. fZ(z) of the random return is given by fZ(z)=μ2eμ2yI(y>0). While the p.d.f. of the claim amount fY(y) follows an exponential or lognormal distribution commonly used in actuarial research [29,30].

    For this part, fY(y) is defined as

    fY(y)={μ1eμ1y,0<y<,0,        <y0.

    The formula (3.8) is converted to

    R(x)=β0(x)g(x)+β1(x)g(x)+β2(x)g(x)+γω(x)I(x<0)+λ1xg(y)μ1eμ1(xy)dy+λ2xg(z)μ2eμ2(zx)dz. (4.1)

    Then, we describe the effects of parameters p, σ and γ on the ruin probability ψ(x). For investigation purposes, the basic parameters are set as follows in the following examples unless otherwise specified: δ=0, a=0.5, c=0.4, r=0.06, λ1=5, λ2=1, μ1=5, μ2=1.

    Example 4.1. In the case that the amount of claim follows the exponential distribution, we consider the influence of the investment ratio p on the ruin probability. Set parameters γ=3, σ=0.8. As shown in Figure 1, it is easy to see that when insurance companies put more of their surplus in risky asset, their ruin probability will fluctuate greatly. Some data are shown in Table 2.

    Figure 1.  Ruin probability ψ(x) when ˆd=ˆα=π4, τ=π8, N=10, γ=3 and σ=0.8.
    Table 2.  When p=0.2 and p=0.8, ruin probability ψ(x) under different x.
    x=-5 -4 -3 -2 -1 0 1 2 3 4 5
    p=0.2 0.93 0.89 0.86 0.89 0.87 0.46 0.41 0.23 0.11 0.08 0.08
    p=0.8 0.93 0.86 0.83 0.91 0.93 0.30 0.47 0.23 0.06 0.04 0.08

     | Show Table
    DownLoad: CSV

    Example 4.2. In the case that the amount of claim follows the exponential distribution, we consider the effect of the parameter σ on ψ(x). Set parameters γ=3, p=0.2. As can be seen from Figure 2, the greater the volatility σ of risky asset the larger the fluctuation of the ruin probability curve. Some data are shown in Table 3.

    Figure 2.  Ruin probability ψ(x) when ˆd=ˆα=π4, τ=π8, N=10, γ=3 and p=0.2.
    Table 3.  When σ=0.2 and σ=0.8, ruin probability ψ(x) under different x.
    x=-5 -4 -3 -2 -1 0 1 2 3 4 5
    σ=0.2 0.93 0.90 0.88 0.88 0.85 0.50 0.39 0.23 0.13 0.09 0.09
    σ=0.8 0.93 0.89 0.86 0.89 0.87 0.46 0.41 0.23 0.11 0.08 0.08

     | Show Table
    DownLoad: CSV

    Example 4.3. In the case that the amount of claim follows the exponential distribution, we consider the influence of the random observation parameter γ on the ruin probability. Set parameters σ=0.8, p=0.2. As can be seen from Figure 3, when the initial surplus is small the parameter γ has a significant effect on the ruin probability. When x is large enough, this effect is obviously weakened. Some data are shown in Table 4.

    Figure 3.  Ruin probability ψ(x) when ˆd=ˆα=π4, τ=π8, N=10, σ=0.8 and p=0.2.
    Table 4.  When γ=3 and γ=5, ruin probability ψ(x) under different x.
    x=-5 -4 -3 -2 -1 0 1 2 3 4 5
    γ=3 0.93 0.89 0.86 0.89 0.87 0.46 0.41 0.23 0.11 0.08 0.08
    γ=5 0.94 0.90 0.88 0.92 0.91 0.47 0.44 0.25 0.11 0.08 0.09

     | Show Table
    DownLoad: CSV

    As can be seen from Examples 4.1–4.3, the effects of several factors on the ruin probability is considered: the investment ratio p, the volatility of risky assets σ, and the random observation parameter γ. First, when insurance companies allocate a larger portion of their surplus to risky assets, it implies the possibility of achieving higher returns. However, this also leads to significant fluctuations in the ruin probability. This demonstrates the coexistence of danger and opportunity. Furthermore, an increase in the volatility of risky assets indicates the potential for greater profits (resulting in a smaller ruin probability). Conversely, it also implies the risk of greater losses (leading to a larger ruin probability). This is also realistic. Last, a shorter random observation interval (larger γ) corresponds to a higher ruin probability, whereas a longer random observation interval (smaller γ) corresponds to a lower ruin probability.

    In this section, fY(y) is assumed to follow the lognormal distribution of the parameter (μ3,2v2), where μ3 is the mean value of lnY and 2v2 is the variance of lnY. So fY(y) is defined as

    fY(y)={12πvye(lnyμ3)24v2,0<y<,0,                 <y0.

    Then,

    fY(uy)={12πv(uy)e[ln(uy)μ3]24v2,<y<u,0,                         uy<.

    At this point, the Eq (3.8) is converted to

    R(x)=β0(x)g(x)+β1(x)g(x)+β2(x)g(x)+γω(x)I(x<0)+λ1xg(y)12πv(xy)e[ln(xy)μ3]24v2dy+λ2xg(z)μ2eμ2(zx)dz. (4.2)

    The following examples are discussed under δ=0, a=0.5, c=0.4, r=0.06, λ1=5, λ2=1, μ1=5, μ2=1, μ3=0.08, v=0.03, γ=3.

    Example 4.4. In the case that the amount of claim follows the lognormal distribution, we consider the effect of the investment ratio p on ψ(x). Set parameters γ=3, σ=0.8. As shown in Figure 4, it is not difficult to see that when insurance companies put more of their surplus in risky asset their ruin probability curve fluctuates greatly. Some data are shown in Table 5.

    Figure 4.  Ruin probability ψ(x) when ˆd=ˆα=π4, τ=π8, N=10, γ=3 and σ=0.8.
    Table 5.  When p=0.2 and p=0.8, ruin probability ψ(x) under different x.
    x=-5 -4 -3 -2 -1 0 1 2 3 4 5
    p=0.2 0.86 0.82 0.80 0.82 0.77 0.57 0.77 0.42 0.19 0.11 0.09
    p=0.8 0.86 0.79 0.76 0.85 0.86 0.44 0.94 0.47 0.14 0.06 0.09

     | Show Table
    DownLoad: CSV

    Example 4.5. In the case that the amount of claim follows the lognormal distribution, we consider the effect of the parameter σ on ψ(x). Set parameters γ=3, p=0.2. As can be seen from Figure 5, the larger the parameter σ of risky asset the greater the fluctuation of the ruin probability will be. Some data are shown in Table 6.

    Figure 5.  Ruin probability ψ(x) when ˆd=ˆα=π4, τ=π8, N=10, γ=3 and p=0.2.
    Table 6.  When σ=0.2 and σ=0.8, ruin probability ψ(x) under different x.
    x=-5 -4 -3 -2 -1 0 1 2 3 4 5
    σ=0.2 0.87 0.83 0.81 0.81 0.76 0.61 0.71 0.42 0.20 0.12 0.10
    σ=0.8 0.86 0.82 0.80 0.82 0.77 0.57 0.77 0.42 0.19 0.11 0.09

     | Show Table
    DownLoad: CSV

    Example 4.6. In the case that the amount of claim follows the lognormal distribution, we consider the influence of the random observation parameter γ on the ruin probability. Set parameters σ=0.8, p=0.2. As can be seen from Figure 6, the different values of parameter γ have obvious influence on the ruin probability. Some data are shown in Table 7.

    Figure 6.  Ruin probability ψ(x) when ˆd=ˆα=π4, τ=π8, N=10, σ=0.8 and p=0.2.
    Table 7.  When γ=3 and γ=5, ruin probability ψ(x) under different x.
    x=-5 -4 -3 -2 -1 0 1 2 3 4 5
    γ=3 0.86 0.82 0.80 0.82 0.77 0.57 0.77 0.42 0.19 0.11 0.09
    γ=5 0.89 0.83 0.81 0.88 0.86 0.39 0.68 0.35 0.11 0.06 0.08

     | Show Table
    DownLoad: CSV

    From the Examples 4.4–4.6, the impact of parameters p,σ and γ on the ruin probability is comparable to that in the case of exponential distribution. Nevertheless, it is noteworthy that when the claim amount follows a lognormal distribution the ruin probability exhibits higher sensitivity to variations in the aforementioned parameters.

    This paper considers a two-sided jumps risk model with random observation periods and proportional investment. Through the review of the existing literature, we observe that most studies by scholars focus on classical or dual risk models. We wondered if we could combine the random jump components in the two models, that is, consider both upward and downward jumps in one model. Following this idea, we find that the two-sided jumps risk model not only has important practical significance but also has been studied by more and more scholars. In addition to the studies already mentioned in the paper, readers can also refer to the literature [31,32,33,34,35,36]. However, to the best of our knowledge no one has ever introduced a random observation period and invested the surplus of an insurance company under this model (two-sided jumps) and the complexity of the model greatly increases the difficulty of processing. To solve this problem, we use the sinc numerical method to find its SA. While there is inevitably some error between the SA and the ES, we provide an upper bound for the error ensuring that it remains within an acceptable range. Perhaps in further research in the future, the ES of the model will be solved.

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.

    The research was supported by the National Natural Science Foundation of China (No. 71801085).

    All authors declare no conflicts of interest in this paper.



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