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Research article

Asymptotic behavior of solutions of third-order neutral differential equations with discrete and distributed delay

  • Received: 17 October 2019 Accepted: 17 April 2020 Published: 22 April 2020
  • MSC : 34C10, 34C15, 34K11

  • By refining the standard Riccati substitution technique, integral averaging technique and comparison principle, we obtain new oscillation and asymptotic behavior for a class of third-order neutral differential equations with discrete and distributed delay. These criteria dealing with some cases have not been covered by the existing results in the literature. We present many sufficient conditions and related examples in order to illustrate the main results.

    Citation: M. Sathish Kumar, V. Ganesan. Asymptotic behavior of solutions of third-order neutral differential equations with discrete and distributed delay[J]. AIMS Mathematics, 2020, 5(4): 3851-3874. doi: 10.3934/math.2020250

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  • By refining the standard Riccati substitution technique, integral averaging technique and comparison principle, we obtain new oscillation and asymptotic behavior for a class of third-order neutral differential equations with discrete and distributed delay. These criteria dealing with some cases have not been covered by the existing results in the literature. We present many sufficient conditions and related examples in order to illustrate the main results.


    It is prudential to say that mathematical modeling with delay differential equations have drawn clear significance because of their potential applications in diverse fields, which includes biological sciences, physical sciences, gas and fluid mechanics, signal processing, robotics and traffic system, engineering, population dynamics, medicine and the like (see for example [9,16,17]). It is now realized that the oscillation and asymptotic solutions of various classes of differential equation are an important field of investigation and its theory is a lot richer than the qualitative theory of differential equations (see for example [8,10,22]). The problem of oscillatory and nonoscillatory of solutions of various classes of second/third order differential equations with delayed and mixed arguments has been widely investigated in the literature (see for example [2,4,5,6,7,11,12,18,23,24,25,26,27,28,29,30,31,32,33,34]). Various types of techniques appeared for investigations of such equations.

    The purpose of this work, we are concerned with third-order neutral differential equations with discrete and distributed delay

    (a2(t)[(a1(t)z(t))]λ)+q1(t)yλ(tσ1)+q2(t)yλ(t+σ1)=0,

    and

    (a2(t)[(a1(t)z(t))]λ)+dc˜q1(t,ξ)yλ(tξ)dξ+dc˜q2(t,ξ)yλ(t+ξ)dξ=0,

    where z(t)=y(t)+p1(t)y(tτ1)+p2(t)y(t+τ2), c<d and λ1. Now onwards, we assume that, ai(t),pi(t)C([t0,+)), ai(t)>0, pi(t)>0 for i=1,2 and 0pi(t)μi, μ1+μ2<1 where μi are constants, qiC([t0,+),R+), ~qi(t,ξ)C([t0,+)×[c,d], R+) for i=1,2, and not identically zero on [t,+)×[c,d], tt, constants τi0, for i=1,2, and the integral of (E2) is take in the sense of Riemann–Stieltjes.

    Let us recall that, a solution y(t)C([Ty,),R) of (E1) (or (E2)) is a non-trivial or y(t)0 with Tyt0, if the functions zC1([Ty,),R), a1zC2([Ty,),R) and a2[(a1z)]λC1([Ty,),R) for certain Tyt0 which satisfies (E1) (or (E2)). Our attention is restricted to those solutions of (E1) (or (E2)) which exist on half-line [Ty,) and the condition sup{|y(t)|:t>T}>0 satisfies for any Tty. A solution of (E1) (or (E2)), which is nontrivial (proper) for all large t, is called oscillatory if it has no last zero, otherwise, termed nonoscillatory.

    We define the operators,

    L[0]z=z,L[1]z=z,L[2]z=(a1L[1]z),L[3]z=a2[L[2]z]λ,L[4]z=(L[3]z).

    We shall consider the two cases,

    π1[t0,t]=tt0a1/λ2(s)ds,π2[t0,t]=tt0a11(s)ds.
    π1[t0,t]=,π2[t0,t]= as t, (1.1)

    and

    π1[t0,t]<,π2[t0,t]= as t. (1.2)

    Recently, Candan [24] investigated the oscillatory behavior of solutions of (E1) and (E2) by using the Riccati substitution techniques, he presented some new oscillation criteria for (E1) and (E2) by the assumption of condition (1.1). We notice that in [24], no criteria were found for (E1) (or (E2)) to be oscillatory for the assumption of condition (1.2). It would be interesting to improve and extend them in the condition (1.2).

    However, the corresponding result for (E1) (or (E2)) under (1.2) is still missing. In this work, we fill up this gap, also we strengthen and extend the main results of Candan [24] under the condition (1.1) and (1.2) respectively. We present several oscillatory criteria for (E1) and (E2), by applying three Riccati substitution techniques, integral averaging techniques and comparison principles. We present two examples in order to illustrate the main results at the end.

    In this section, we present some basic Lemmas for helping to prove the main results. We use throughout this paper the following notations for convenience and for shortening the equations:

    L[0]σz(t)=z(t+σ),L[1]σz(t)=z(t+σ),L[2]σz(t)=(a1(t+σ)z(t+σ)),L[3]σz(t)=a2(t+σ)[L[2]σz(t)]λ,L[4]σz(t)=(L[3]σz(t)),A(t)=tt0π1[t0,s]a1(s)ds.

    Lemma 2.1. Let λ1, assume u0. Then

    (u1+u2+u3)λ3λ1(uλ1+uλ2+uλ3). (2.1)

    Lemma 2.2. Let λ1, assume u0. Then

    (u1+u2+u3)λ(uλ1+uλ2+uλ3). (2.2)

    Lemma 2.3. If λ>0 and X,Y>0, then

    YvXvλ+1λλλ(1+λ)1+λY1+λXλ. (2.3)

    Lemma 2.4. Assume that (1.1) holds. Furthermore, assume that y is an eventually positive solution of (E1) (or (E2)). Then z for t1[t0,) satisfies, eventually of the following cases:

    (C1):L[0]z(t)>0,L[1]z(t)>0,andL[2]z(t)>0;(C2):L[0]z(t)>0,L[1]z(t)<0,andL[2]z(t)>0;

    and if (1.2) holds, then also

    (C3):L[0]z(t)>0,L[1]z(t)>0,andL[2]z(t)<0.

    Lemma 2.5. Assume that z satisfies (C1) for tt0. Then

    z(t)(L[3]z(t))1/λa1(t)π1[t0,t] (2.4)

    and

    z(t)(L[3]z(t))1/λA(t). (2.5)

    Proof. Since L[4]z(t)0, L[3]z(t) is nondecreasing. Then we have

    a1(t)z(t)a1(t)z(t)a1(t0)z(t0)=tt0a1/λ2(s)L[2]z(s)a1/λ2(s)dsa1/λ2(t)L[2]z(t)π1[t0,t].

    Again integrate, we get

    z(t)(L[3]z(t))1/λtt0π1[t0,s]a1(s)ds=(L[3]z(t))1/λA(t).

    Lemma 2.6 (See [24]). Assume that z is a solution of (E1) which satisfies (C2) in Lemma 2.4. Furthermore,

    t4a11(v)va1/λ2(u)(u(q1(s)+q2(s))ds)1/λdudv=. (2.6)

    Then, there is limtz(t)=0.

    Lemma 2.7 (See [24]). Assume that z is a solution of (E2) which satisfies (C2) in Lemma 2.4. Furthermore,

    t4a11(v)va1/λ2(u)(uba(~q1(s,ξ)+~q2(s,ξ))dξds)1/λdudv=. (2.7)

    Then, there is limtz(t)=0.

    In this section, we will establish several oscillation criteria for (E1). The following notations for convenience and for shortening the equations:

    P1(t)=min{q1(t),q1(tτ1),q1(t+τ2)},P2(t)=min{q2(t),q2(tτ1),q2(t+τ2)},P(t)=P1(t)+P2(t),B(t)=tt0sdua1/λ2(u)a1(s)ds.

    Let S0={(t,s):as<t<+}, S={(t,s):ast<+} the continuous function H(t,s), H:SR belongs to the class function

    (ⅰ) H(t,t)=0 for tt0 and H(t,s)>0 for (t,s)S0,

    (ⅱ) H(t,s)s0, (t,s)S0 and some locally integrable function h(t,s) such that

    sH(t,s)H(t,s)m(s)m(s)=h(t,s)(H(t,s))λλ+1m(s)for all (t,s)S0.

    Theorem 3.1. Let (1.1) hold and σ1τ1. If there exists an m(t)C1([t0,),R+) such that (2.6) and

    lim supt1H(t,t3)tt3[H(t,s)m(s)P(s)3λ11+μλ1+μλ2(λ+1)λ+1(|h(t,s)|a1(sσ1)m(s)π1[t0,sσ1])λ]ds=, (3.1)

    then every solution y(t) of (E1) is either oscillatory or tends to 0.

    Proof. Suppose that (E1) has a nonoscillatory solution y. Without loss of generality, we may take y(t)>0, y(tτ1)>0, y(t+τ2)>0, y(tσ1)>0 and y(t+σ1)>0 for tt1t0. Since y(t)>0 for all tt1, in view of (E1), we have

    L[4]z(t)=q1(t)yλ(tσ1)q2(t)yλ(t+σ1)0. (3.2)

    Assumption of (1.1), by Lemma 2.4 there exists two cases (C1) and (C2). If (C2) holds, then by Lemma 2.6, limtz(t)=0. If (C1) holds.

    L[4]z(t)+q1(t)yλ(tσ1)+q2(t)yλ(t+σ1)+μλ1L[4]τ1z(t)+μλ1q1(tτ1)yλ(tτ1σ1)+μλ1q2(tτ1)yλ(tτ1+σ1)+μλ2L[4]τ2z(t)+μλ2q1(t+τ2)yλ(t+τ2σ1)+μλ2q2(t+τ2)yλ(t+τ2+σ1)=0. (3.3)

    Furthermore, from Lemma 2.1, we get

    q1(t)yλ(tσ1)+μλ1q1(tτ1)yλ(tτ1σ1)+μλ1q1(t+τ2)yλ(t+τ2σ1)P1(t)3λ1zλ(tσ1). (3.4)

    Similarly, we get

    q2(t)yλ(t+σ1)+μλ2q2(tτ1)yλ(tτ1+σ1)+μλ2q2(t+τ2)yλ(t+τ2+σ1)P2(t)3λ1zλ(t+σ1). (3.5)

    Substituting (3.4), (3.5) into (3.3), we have

    L[4]z(t)+μλ1L[4]τ1z(t)+μλ2L[4]τ2z(t)+P1(t)3λ1zλ(tσ1)+P2(t)3λ1zλ(t+σ1)0. (3.6)

    Using the fact of L[1]z(t)>0, we obtain

    L[4]z(t)+μλ1L[4]τ1z(t)+μλ2L[4]τ2z(t)+P(t)3λ1zλ(tσ1)0. (3.7)

    Define

    w1(t)=m(t)L[3]z(t)zλ(tσ1). (3.8)

    We obtain w1(t)>0, then

    w1(t)=m(t)L[3]z(t)zλ(tσ1)+m(t)L[4]z(t)zλ(tσ1)λm(t)L[3]z(t)z(tσ1)zλ+1(tσ1). (3.9)

    By Lemma (2.5), one gets z(tσ1)a1/λ2(t)a1(tσ1)π1[t0,tσ1]L[2]z(t). Therefore

    w1(t)m(t)L[3]z(t)zλ(tσ1)+m(t)L[4]z(t)zλ(tσ1)λm(t)aλ+1λ2(t)π1[t0,tσ1]L[2]z(t)z(tσ1)zλ+1(tσ1)a1(tσ1). (3.10)

    Using (3.8) in (3.10), we obtain

    w1(t)(m(t))+m(t)w1(t)+m(t)L[4]z(t)zλ(tσ1)λ(w1(t))λ+1λπ1[t0,tσ1](m(t))1/λa1(tσ1). (3.11)

    Next, define

    w2(t)=m(t)L[3]τ1z(t)zλ(tσ1). (3.12)

    We obtain w2(t)>0, then

    w2(t)=m(t)L[3]τ1z(t)zλ(tσ1)+m(t)L[4]τ1z(t)zλ(tσ1)λm(t)L[3]τ1z(t)z(tσ1)zλ+1(tσ1). (3.13)

    By Lemma (2.5), one gets z(tσ1)a1/λ2(tτ1)a1(tσ1)π1[t0,tσ1]L[2]τ1z(t) and using (3.12) in (3.13), we have

    w2(t)(m(t))+m(t)w2(t)+m(t)L[4]τ1z(t)zλ(tσ1)λ(w2(t))λ+1λπ1[t0,tσ1](m(t))1/λa1(tσ1). (3.14)

    Finally, define

    w3(t)=m(t)L[3]τ2z(t)zλ(tσ1). (3.15)

    We obtain w3(t)>0, then

    w3(t)=m(t)L[3]τ2z(t)zλ(tσ1)+m(t)L[4]τ2z(t)zλ(tσ1)λm(t)L[3]τ2z(t)z(tσ1)zλ+1(tσ1). (3.16)

    By Lemma 2.5, one gets z(tσ1)a1/λ2(t+τ2)a1(tσ1)π1[t0,tσ1]L[2]τ2z(t) and using (3.15) in (3.16), we get

    w3(t)(m(t))+m(t)w3(t)+m(t)L[4]τ2z(t)zλ(tσ1)λ(w3(t))λ+1λπ1[t0,tσ1](m(t))1/λa1(tσ1). (3.17)

    From (3.8), (3.10) and (3.15), we have

    w1(t)+μλ1w2(t)+μλ2w3(t)m(t)[L[4]z(t)+μλ1L[4]τ1z(t)+μλ2L[4]τ2z(t)zλ(tσ1)]+[(m(t))+m(t)w1(t)λ(w1(t))λ+1λπ1[t0,tσ1](m(t))1/λa1(tσ1)]+μλ1[(m(t))+m(t)w2(t)λ(w2(t))λ+1λπ1[t0,tσ1](m(t))1/λa1(tσ1)]+μλ2[(m(t))+m(t)w3(t)λ(w3(t))λ+1λπ1[t0,tσ1](m(t))1/λa1(tσ1)]. (3.18)

    Using (3.7) in (3.18), we have

    w1(t)+μλ1w2(t)+μλ2w3(t)m(t)P(t)3λ1+[(m(t))+m(t)w1(t)λ(w1(t))λ+1λπ1[t0,tσ1](m(t))1/λa1(tσ1)]+μλ1[(m(t))+m(t)w2(t)λ(w2(t))λ+1λπ1[t0,tσ1](m(t))1/λa1(tσ1)]+μλ2[(m(t))+m(t)w3(t)λ(w3(t))λ+1λπ1[t0,tσ1](m(t))1/λa1(tσ1)], (3.19)

    that is,

    m(t)P(t)3λ1w1(t)μλ1w2(t)μλ2w3(t)+(m(t))+m(t)w1(t)λπ1[t0,tσ1](m(t))1/λa1(tσ1)(w1(t))λ+1λ+μλ1[(m(t))+m(t)w2(t)λπ1[t0,tσ1](m(t))1/λa1(tσ1)(w2(t))λ+1λ]+μλ2[(m(t))+m(t)w3(t)λπ1[t0,tσ1](m(t))1/λa1(tσ1)(w3(t))λ+1λ]. (3.20)

    Multiply H(t,s) and integrate (3.20) from t3 to t, one can get that

    tt3H(t,s)m(s)P(s)3λ1dstt3H(t,s)w1(s)dsμλ1tt3H(t,s)w2(s)dsμλ2tt3H(t,s)w3(s)ds+tt3H(t,s)(m(s))+m(s)w1(s)dstt3H(t,s)λπ1[t0,sσ1](m(s))1/λa1(sσ1)(w1(s))λ+1λds+μλ1tt3H(t,s)(m(s))+m(s)w2(s)dsμλ1tt3H(t,s)λπ1[t0,sσ1](m(s))1/λa1(sσ1)(w2(s))λ+1λds+μλ2tt3H(t,s)(m(s))+m(s)w3(s)dsμλ2tt3H(t,s)λπ1[t0,sσ1](m(s))1/λa1(sσ1)(w3(s))λ+1λds. (3.21)

    Thus, we obtain

    tt3H(t,s)m(s)P(s)3λ1dsH(t,t3)w1(t3)+μλ1H(t,t3)w2(t3)+μλ2H(t,t3)w3(t3)tt3[sH(t,s)H(t,s)m(s)m(s)]w1(s)dstt3H(t,s)λπ1[t0,sσ1](m(s))1/λa1(sσ1)(w1(s))λ+1λdsμλ1tt3[sH(t,s)H(t,s)m(s)m(s)]w2(s)dsμλ1tt3H(t,s)λπ1[t0,sσ1](m(s))1/λa1(sσ1)(w2(s))λ+1λdsμλ2tt3[sH(t,s)H(t,s)m(s)m(s)]w3(s)dsμλ2tt3H(t,s)λπ1[t0,sσ1](m(s))1/λa1(sσ1)(w3(s))λ+1λds. (3.22)

    Then

    tt3H(t,s)m(s)P(s)3λ1dsH(t,t3)w1(t3)+μλ1H(t,t3)w2(t3)+μλ2H(t,t3)w3(t3)+tt3[|h(t,s)|(H(t,s))λλ+1m(s)w1(s)H(t,s)λπ1[t0,sσ1](m(s))1/λa1(sσ1)(w1(s))λ+1λ]ds+μλ1tt3[|h(t,s)|(H(t,s))λλ+1m(s)w2(s)H(t,s)λπ1[t0,sσ1](m(s))1/λa1(sσ1)(w2(s))λ+1λ]ds+μλ2tt3[|h(t,s)|(H(t,s))λλ+1m(s)w3(s)H(t,s)λπ1[t0,sσ1](m(s))1/λa1(sσ1)(w3(s))λ+1λ]ds. (3.23)

    Setting Y=|h(t,s)|(H(t,s))λλ+1m(s), X=H(t,s)λπ1[t0,sσ1](m(s))1/λa1(sσ1) and u=wi(t) for i=1,2,3. By using the Lemma 2.3, we conclude that

    1H(t,t3)tt3[H(t,s)m(s)P(s)3λ11+μλ1+μλ2(λ+1)λ+1(|h(t,s)|a1(sσ1)m(s)π1[t0,sσ1])λ]dsw1(t3)+μλ1w2(t3)+μλ2w3(t3) (3.24)

    which contradicts condition (3.20).

    Theorem 3.2. Let (1.1) hold and τ1σ1. If there exists an m(t)C1([t0,),R+) such that (2.6) and

    lim supt1H(t,t3)tt3[H(t,s)m(s)P(s)3λ11+μλ1+μλ2(λ+1)λ+1(|h(t,s)|a1(sτ1)m(s)π1[t0,sτ1])λ]ds=, (3.25)

    then every solution y(t) of (E1) is either oscillatory or tends to 0.

    Proof. Suppose that (E1) has a nonoscillatory solution y. Without loss of generality, we may take y(t)>0, y(tτ1)>0, y(t+τ2)>0, y(tσ1)>0 and y(t+σ1)>0 for tt1t0. Assumption of (1.1), by Lemma 2.4 there exists two cases (C1) and (C2). If (C2) holds, then by Lemma 2.6, limtz(t)=0. We only consider (C1), by using the fact that z(t)>0 and τ1σ1, we obtain that Using the fact of L[1]z(t)>0, we obtain

    L[4]z(t)+μλ1L[4]τ1z(t)+μλ2L[4]τ2z(t)+P(t)3λ1zλ(tτ1)0. (3.26)

    Next, we categorize the functions as w1(t)=m(t)L[3]z(t)zλ(tτ1), w2(t)=m(t)L[3]τ1z(t)zλ(tτ1) and w3(t)=m(t)L[3]τ2z(t)zλ(tτ1) respectively. The rest of the proof is similar to that of Theorem 3.1, therefore, it is omitted.

    Theorem 3.3. Let (1.2) hold and σ1τ1. If there exists an m(t)C1([t0,),R+) such that (2.6),

    t3[m(s)P(s)3λ1(1+μλ1+μλ2)((m(s))+(λ+1))λ+1(a1(sσ1)m(s)π1[t0,sσ1])λ]ds=, (3.27)

    and

    t3[πλ(s+τ2)P(s)3λ1(s+σ1t2dua1(u))λ(λ1+λ)1+λ(1+μλ1)a2(s)+μλ2a2(s+τ2+σ1)a1+1λ2(s)πλ(s+τ2)]ds=, (3.28)

    where (m(t))+=max{0,m(t)}, π(t)=t+σ1a1/λ2(s)ds, then every solution y(t) of (E1) is either oscillatory or tends to 0.

    Proof. Suppose that (E1) has a nonoscillatory solution y. Without loss of generality, we may take y(t)>0, y(tτ1)>0, y(t+τ2)>0, y(tσ1)>0 and y(t+σ1)>0 for tt1t0. Since y(t)>0 for all tt1. Assumption of (1.2), by Lemma 2.4 there exists three cases (C1), (C2) and (C3). If case (C1) and (C2) holds, using the similar proof of ([24], Theorem 2.1) by using Lemma 2.1, we get the conclusion of Theorem 3.3.

    If case (C3) holds, z(tσ1)<0 for tt1. The facts that z(t)<0, c+d0 and (3.6), we obtain

    L[4]z(t)+μλ1L[4]τ1z(t)+μλ2L[4]τ2z(t)+P(t)3λ1zλ(t+σ1)0. (3.29)

    Define

    w(t)=L[3]z(t)(a1(t+σ1)z(t+σ1))λ. (3.30)

    We obtain w(t)<0 for tt2. Noting that L[3]z(t) is decreasing, we obtain

    a2(s)[L[2]z(s)]λa2(t)[L[2]z(t)]λ (3.31)

    for stt2. Dividing (3.31) by a2(s) and integrating from t+σ1 to l(lt), we get

    a1(l)z(l)a1(t+σ1)z(t+σ1)+a1/λ2(t)[L[2]z(t)]lt+σ1a1/λ2(s)ds.

    letting l, we get

    1a1/λ2(t)[L[2]z(t)]a1(t+σ1)z(t+σ1)π(t), (3.32)

    for tt2. From (3.30), we have

    1w(t)πλ(t)0. (3.33)

    By (3.2) we have a1(t+σ1)z(t+σ1)a1(t)z(t). Differentiating (3.30) gives,

    w(t)(L[3]z(t))(a1(t+σ1)z(t+σ1))λλa2(t)[L[2]z(t)a1(t+σ1)z(t+σ1)]λ+1. (3.34)

    Using (3.30) in (3.34), we have

    w(t)L[4]z(t)(a1(t+σ1)z(t+σ1))λλw1+1λ(t)a1/λ2(t). (3.35)

    Again, we define

    w(t)=L[3]τ1z(t)(a1(t+σ1)z(t+σ1))λ. (3.36)

    We obtain w(t)<0 and w(t)w(t) for tt2. By (3.33), we obtain

    1w(t)πλ(t)0. (3.37)

    By (3.2) we have a1(t+σ1)z(t+σ1)a1(tτ1)z(tτ1). Differentiating (3.36) gives,

    w(t)(L[3]τ1z(t))(a1(t+σ1)z(t+σ1))λλa2(t)[L[2]τ1z(t)a1(t+σ1)z(t+σ1)]λ+1. (3.38)

    Using (3.36) in (3.38), we have

    w(t)L[4]τ1z(t)(a1(t+σ1)z(t+σ1))λλw1+1λ(t)a1/λ2(t). (3.39)

    Finally, we define a function

    w(t)=L[3]τ2z(t)(a1(t+τ2+σ1)z(t+τ2+σ1))λ. (3.40)

    We obtain w(t)<0 and w(t)=w(t+τ2) for tt2. By (3.33), we obtain

    1w(t)πλ(t+τ2)0. (3.41)

    By (3.2) we have a1(t+τ2+σ1)z(t+τ2+σ1)a1(t+τ2)z(t+τ2). Differentiating (3.40) gives,

    w(t)(L[3]τ2z(t))(a1(t+σ1)z(t+σ1))λλa2(t)[L[2]τ2z(t)a1(t+τ2+σ1)z(t+τ2+σ1)]λ+1. (3.42)

    Using (3.40) in (3.42), we have

    w(t)L[4]τ2z(t)(a1(t+σ1)z(t+σ1))λλw1+1λ(t)a1/λ2(t). (3.43)

    From (3.35), (3.39), (3.43) and (3.29) which implies

    w(t)+μλ1w(t)+μλ2w(t)P(t)3λ1zλ(t+σ1)(a1(t+σ1)z(t+σ1))λλw1+1λ(t)a1/λ2(t)μλ1λw1+1λ(t)a1/λ2(t)μλ2λw1+1λ(t)a1/λ2(t) (3.44)

    In case (C3), (a1(t)z(t))<0 we seen that

    z(t)a1(t)z(t)tt21a1(s)ds. (3.45)

    Using (3.45) in (3.44), we get

    w(t)+μλ1w(t)+μλ2w(t)P(t)3λ1(t+σ1t2dsa1(s))λλw1+1λ(t)a1/λ2(t)μλ1λw1+1λ(t)a1/λ2(t)μλ2λw1+1λ(t)a1/λ2(t). (3.46)

    Multiplying πλ(t+τ2) and integrating from t3(t3>t2) to t, yields

    πλ(t+τ2)w(t)πλ(t3+τ2)w(t3)+πλ(t+τ2)μλ1w(t)πλ(t3+τ2)μλ1w(t3)+πλ(t+τ2)μλ2w(t)πλ(t3+τ2)μλ2w(t3)λtt3[πλ1(s+τ2)(w(s))a1/λ2(s+τ2)πλ(s+τ2)(w(s))1+1λa1/λ2(s)]dsλμλ1tt3[πλ1(s+τ2)(w(s))a1/λ2(s+τ2)πλ(s+τ2)(w(s))1+1λa1/λ2(s)]dsλμλ2tt3[πλ1(s+τ2)(w(s))a1/λ2(s+τ2)πλ(s+τ2)(w(s))1+1λa1/λ2(s)]ds+tt3πλ(s+τ2)P(s)3λ1(s+σ1t2dua1(u))λds0. (3.47)

    Applying Lemma 2.3, we conclude that

    tt3[πλ(s+τ2)P(s)3λ1(s+σ1t2dua1(u))λ(λ1+λ)1+λ(1+μλ1)a2(s)+μλ2a2(s+τ2+σ1)a1+1λ2(s)πλ(s+τ2)]ds[πλ(t+τ2)w(t)+μλ1πλ(t+τ2)w(t)+μλ2πλ(t+τ2)w(t)] (3.48)

    Using the fact of πλ(t+τ2)πλ(t) in (3.33), (3.37), (3.41) and (3.48) imply that

    tt3[πλ(s+τ2)P(s)3λ1(s+σ1t2dua1(u))λ(λ1+λ)1+λ(1+μλ1)a2(s)+μλ2a2(s+τ2+σ1)a1+1λ2(s)πλ(s+τ2)]ds1+μλ1+μλ2. (3.49)

    a contradiction to (3.28).

    Finally, we establish new comparison theorems for (E1) under the case when (1.2) holds.

    Theorem 3.4. Let (1.2), (2.6) hold and σ1>τ1, σ1>τ2. If the first-order differential inequality

    ψ(t)+P1(t)3λ1Aλ(tσ1)1+μλ1+μλ2ψ(tσ1+τ1)0 (3.50)

    for tt0, has no positive nonincreasing solution and the first-order differential inequality

    ψ(t)P2(t)3λ1Bλ(t+σ1)1+μλ1+μλ2ψ(tτ2+σ1)0 (3.51)

    for tt0, has no positive nondecreasing solution. Then Eq. (E1) oscillatory.

    Proof. Suppose that (E1) has a nonoscillatory solution y. Without loss of generality, we may take y(t)>0, y(tτ1)>0, y(t+τ2)>0, y(tσ1)>0 and y(t+σ1)>0 for tt1t0. Since y(t)>0 for all tt1. Assumption of (1.2), by Lemma 2.4, there exists three cases (C1), (C2) and (C3). If case (C2) hold, the proof is follows from Lemma 2.6.

    If case (C1) holds, we have L[2]z(t)>0, from (3.6), we obtain

    L[4]z(t)+μλ1L[4]τ1z(t)+μλ2L[4]τ2z(t)+P1(t)3λ1zλ(tσ1)0. (3.52)

    By Lemma 2.5, one gets z(tσ1)(L[3]σ1z(t))1/λA(tσ1) and using in (3.52), we have

    (L[3]z(t)+μλ1L[3]τ1z(t)+μλ2L[3]τ2z(t))+P1(t)3λ1L[3]σ1z(t)Aλ(tσ1)0. (3.53)

    Now, set

    ψ(t)=L[3]z(t)+μλ1L[3]τ1z(t)+μλ2L[3]τ2z(t).

    Then ψ(t)>0 and the fact that L[3]z(t) is nonincreasing, we have

    ψ(t)L[3]τ1z(t)(1+μλ1+μλ2). (3.54)

    Using (3.54) and (3.53), we see that ψ(t) is a nonincreasing positive solution of the first order differential inequality

    ψ(t)+P1(t)3λ1Aλ(tσ1)1+μλ1+μλ2ψ(tσ1+τ1)0, (3.55)

    which is contradiction to (3.50).

    If case (C3) holds, we have L[2]z(t)<0, from (3.6), we obtain

    L[4]z(t)+μλ1L[4]τ1z(t)+μλ2L[4]τ2z(t)+P2(t)3λ1zλ(t+σ1)0. (3.56)

    Since L[3]z(t) is nondecreasing. Then we get

    L[3]z(s)L[3]z(t) for all stt1t0.

    Integrating above inequality from t to l, we get

    a1(l)z(l)a1(t)z(t)+lta1/λ2(t)L[2]z(t)a1/λ2(s)dsa1(t)z(t)+(L[3]z(s))1/λltdsa1/λ2(s).

    Letting l, we get

    a1(t)z(t)(L[3]z(s))1/λtdsa1/λ2(s).

    Again integrating, we get

    z(t)(L[3]z(t))1/λtt0tdua1/λ2(u)a1(s)ds=(L[3]z(t))1/λB(t). (3.57)

    From 3.57, one gets z(t+σ1)(L[3]σ1z(t))1/λB(t+σ1) and using in (3.56), we have

    (L[3]z(t)+μλ1L[3]τ1z(t)+μλ2L[3]τ2z(t))P2(t)3λ1L[3]σ1z(t)Bλ(t+σ1)0. (3.58)

    Now, set

    ψ(t)=L[3]z(t)+μλ1L[3]τ1z(t)+μλ2L[3]τ2z(t).

    Then ψ(t)>0, ψ(t)0 and the fact that L[3]z(t) is nondecreasing, we have

    ψ(t)L[3]τ2z(t)(1+μλ1+μλ2). (3.59)

    Using (3.59) and (3.58), we see that ψ(t) is a nonincreasing positive solution of the first order differential inequality

    ψ(t)P2(t)3λ1Bλ(t+σ1)1+μλ1+μλ2ψ(tτ2+σ1)0 (3.60)

    which is contradiction to (3.51).

    Corollary 3.5. Let (1.2), (2.6) hold and σ1>τ1, σ1>τ2. If

    lim inftttσ1+τ1P1(s)Aλ(sσ1)ds>3λ1e(1+μλ1+μλ2) (3.61)

    and

    lim inftttτ2+σ1P2(s)Bλ(s+σ1)ds>3λ1e(1+μλ1+μλ2) (3.62)

    hold, then Eq. (E1) oscillatory.

    Proof. The proof follows from Theorem 3.4 and ([10], Theorem 2.1.1), and the details are omitted.

    Example 3.6. Consider the third order differential equation

    ((((y(t)+e23y(t2)+e3y(t+1))))3/2)+3e34(53)3/2y3/2(t2)+3e34(53)3/2y3/2(t+2)=0. (3.63)

    Compared with (E1), we can see that a1(t)=a2(t)=1, p1(t)=e23, p2(t)=e13, q1(t)=3e34(53)3/2, q2(t)=3e34(53)3/2, λ=3/2, τ1=2, τ2=1 and σ1=2. By taking m(t)=1, H(t,s)=(ts)2, we obtain h(t,s)=(3st)(ts)1/5. It is easy to verify that all conditions of Theorem 3.1 are satisfied. Therefore, all the solutions of (3.63) is either oscillates or tends to 0 and y(t)=et is a such solution of (3.63).

    Example 3.7. Consider the third order differential equation

    [t2(y(t)+k1y(tτ1)+k2y(t+τ2))]+k3ty(tσ1)+k4y(t+σ1)=0,t1. (3.64)

    Compared with (E1), we can see that a1(t)=1, a2(t)=t2, p1(t)=k1, p2(t)=k2, q1(t)=k3t, q2(t)=k4, λ=1 and k1, k2, k3, k4 are nonnegative constants. It is easy to verify that all conditions of Corollary 3.5 are satisfied and hence all solutions of equation (3.64) are oscillatory.

    In this section, we will establish several oscillation criteria for (E2). For convenience, we define,

    Q1(t,ξ)=min{˜q1(t,ξ),˜q1(tτ1,ξ),˜q1(t+τ2,ξ)},Q2(t,ξ)=min{˜q2(t,ξ),˜q2(tτ1,ξ),˜q2(t+τ2,ξ)},Q(t,ξ)=Q1(t,ξ)+Q2(t,ξ).

    Theorem 4.1. Let (1.1) holds and c+d0, bτ1. If there exists an m(t)C1([t0,),R+) such that (2.7) and

    lim supt1H(t,t3)tt3[H(t,s)m(s)dcQ(s,ξ)dξ3λ11+μλ1+μλ2(λ+1)λ+1(|h(t,s)|a1(sd)m(s)π1[t0,sd])λ]ds=, (4.1)

    then every solution y(t) of (E2) is either oscillatory or tends to 0.

    Proof. Suppose that (E2) has a nonoscillatory solution y. Without loss of generality, we may take y(t)>0, y(tτ1)>0, y(t+τ2)>0, y(tξ)>0 and y(t+ξ)>0 for tt1t0 and ξ[c,d]. Since y(t)>0 for all tt1, in view of (E2), we have

    L[4]z(t)=dc˜q1(t,ξ)yλ(tξ)dξdc˜q2(t,ξ)yλ(t+ξ)dξ0. (4.2)

    Assumption of (1.1), by Lemma 2.4 there exists two cases (C1) and (C2). If (C2) holds, then by Lemma 2.7, limtz(t)=0. If (C1) holds.

    L[4]z(t)+dc˜q1(t,ξ)yλ(tξ)dξ+dc˜q2(t,ξ)yλ(t+ξ)dξ+μλ1L[4]τ1z(t)+μλ1dc˜q1(tτ1,ξ)yλ(tτ1ξ)dξ+μλ1dc˜q2(tτ1,ξ)yλ(tτ1+ξ)dξ+μλ2L[4]τ2z(t)+μλ2dc˜q1(t+τ2,ξ)yλ(t+τ2ξ)dξ+μλ2dc˜q2(t+τ2,ξ)yλ(t+τ2+ξ)dξ=0. (4.3)

    Furthermore, from Lemma 2.1, we have

    ˜q1(t,ξ)yλ(tξ)+μλ1˜q1(tτ1,ξ)yλ(tτ1ξ)+μλ1˜q1(t+τ2,ξ)yλ(t+τ2ξ)Q1(t,ξ)3λ1zλ(tξ). (4.4)

    Similarly, we get

    ˜q2(t,ξ)yλ(t+ξ)+μλ2˜q2(tτ1,ξ)yλ(tτ1+ξ)+μλ2˜q2(t+τ2,ξ)yλ(t+τ2+ξ)Q2(t,ξ)3λ1zλ(t+ξ). (4.5)

    Substituting (4.4), (4.5) into (4.3), we have

    L[4]z(t)+μλ1L[4]τ1z(t)+μλ2L[4]τ2z(t)+dcQ1(t,ξ)dξ3λ1zλ(tξ)+dcQ2(t,ξ)dξ3λ1zλ(t+ξ)0. (4.6)

    Using the fact of L[1]z(t)>0 and c+d0, we have

    L[4]z(t)+μλ1L[4]τ1z(t)+μλ2L[4]τ2z(t)+dcQ(t,ξ)dξ3λ1zλ(td)0. (4.7)

    Define a function

    w1(t)=m(t)L[3]z(t)zλ(td). (4.8)

    We obtain w1(t)>0, then

    w1(t)=m(t)L[3]z(t)zλ(td)+m(t)L[4]z(t)zλ(td)λm(t)L[3]z(t)z(td)zλ+1(td). (4.9)

    By Lemma (2.5), one gets z(td)a1/λ2(t)a1(td)π1[t0,td]L[2]z(t). Therefore

    w1(t)m(t)L[3]z(t)zλ(td)+m(t)L[4]z(t)zλ(td)λm(t)aλ+1λ2(t)π1[t0,td]L[2]z(t)z(td)zλ+1(td)a1(td). (4.10)

    Using (4.8) in (4.10), we have

    w1(t)(m(t))+m(t)w1(t)+m(t)L[4]z(t)zλ(td)λ(w1(t))λ+1λπ1[t0,td](m(t))1/λa1(td). (4.11)

    Next, define

    w2(t)=m(t)L[3]τ1z(t)zλ(td). (4.12)

    We obtain w2(t)>0, then

    w2(t)=m(t)L[3]τ1z(t)zλ(td)+m(t)L[4]τ1z(t)zλ(td)λm(t)L[3]τ1z(t)z(td)zλ+1(td). (4.13)

    By Lemma (2.5), one gets z(td)a1/λ2(tτ1)a1(td)π1[t0,td]L[2]τ1z(t) and using (4.12) in (4.13), we have

    w2(t)(m(t))+m(t)w2(t)+m(t)L[4]τ1z(t)zλ(td)λ(w2(t))λ+1λπ1[t0,td](m(t))1/λa1(td). (4.14)

    Finally, define

    w3(t)=m(t)L[3]τ2z(t)zλ(td). (4.15)

    We obtain w3(t)>0, then

    w3(t)=m(t)L[3]τ2z(t)zλ(td)+m(t)L[4]τ2z(t)zλ(td)λm(t)L[3]τ2z(t)z(td)zλ+1(td). (4.16)

    By Lemma 2.5, one gets z(td)a1/λ2(t+τ2)a1(td)π1[t0,td]L[2]τ2z(t) and using (4.15) in (4.16), we have

    w3(t)(m(t))+m(t)w3(t)+m(t)L[4]τ2z(t)zλ(td)λ(w3(t))λ+1λπ1[t0,td](m(t))1/λa1(td). (4.17)

    From (4.8), (4.10) and (4.15), we have

    w1(t)+μλ1w2(t)+μλ2w3(t)m(t)[L[4]z(t)+μλ1L[4]τ1z(t)+μλ2L[4]τ2z(t)zλ(td)]+[(m(t))+m(t)w1(t)λ(w1(t))λ+1λπ1[t0,td](m(t))1/λa1(td)]+μλ1[(m(t))+m(t)w2(t)λ(w2(t))λ+1λπ1[t0,td](m(t))1/λa1(td)]+μλ2[(m(t))+m(t)w3(t)λ(w3(t))λ+1λπ1[t0,td](m(t))1/λa1(td)]. (4.18)

    Using (4.7) in (4.18), we have

    w1(t)+μλ1w2(t)+μλ2w3(t)m(t)dcQ(t,ξ)dξ3λ1+[(m(t))+m(t)w1(t)λ(w1(t))λ+1λπ1[t0,td](m(t))1/λa1(td)]+μλ1[(m(t))+m(t)w2(t)λ(w2(t))λ+1λπ1[t0,td](m(t))1/λa1(td)]+μλ2[(m(t))+m(t)w3(t)λ(w3(t))λ+1λπ1[t0,td](m(t))1/λa1(td)], (4.19)

    that is,

    m(t)dcQ(t,ξ)dξ3λ1w1(t)μλ1w2(t)μλ2w3(t)+(m(t))+m(t)w1(t)λπ1[t0,td](m(t))1/λa1(td)(w1(t))λ+1λ+μλ1[(m(t))+m(t)w2(t)λπ1[t0,td](m(t))1/λa1(td)(w2(t))λ+1λ]+μλ2[(m(t))+m(t)w3(t)λπ1[t0,td](m(t))1/λa1(td)(w3(t))λ+1λ]. (4.20)

    Multiply both sides H(t,s) and integrate (4.51) from t3 to t, one can get that

    tt3H(t,s)m(s)dcQ(s,ξ)dξ3λ1dstt3H(t,s)w1(s)dsμλ1tt3H(t,s)w2(s)dsμλ2tt3H(t,s)w3(s)ds+tt3H(t,s)(m(s))+m(s)w1(s)dstt3H(t,s)λπ1[t0,sd](m(s))1/λa1(sd)(w1(s))λ+1λds+μλ1tt3H(t,s)(m(s))+m(s)w2(s)dsμλ1tt3H(t,s)λπ1[t0,sd](m(s))1/λa1(sd)(w2(s))λ+1λds+μλ2tt3H(t,s)(m(s))+m(s)w3(s)dsμλ2tt3H(t,s)λπ1[t0,sd](m(s))1/λa1(sd)(w3(s))λ+1λds. (4.21)

    Thus, we obtain

    tt3H(t,s)m(s)dcQ(s,ξ)dξ3λ1dsH(t,t3)w1(t3)+μλ1H(t,t3)w2(t3)+μλ2H(t,t3)w3(t3)tt3[sH(t,s)H(t,s)m(s)m(s)]w1(s)dstt3H(t,s)λπ1[t0,sd](m(s))1/λa1(sd)(w1(s))λ+1λdsμλ1tt3[sH(t,s)H(t,s)m(s)m(s)]w2(s)dsμλ1tt3H(t,s)λπ1[t0,sd](m(s))1/λa1(sd)(w2(s))λ+1λdsμλ2tt3[sH(t,s)H(t,s)m(s)m(s)]w3(s)dsμλ2tt3H(t,s)λπ1[t0,sd](m(s))1/λa1(sd)(w3(s))λ+1λds. (4.22)

    Then

    tt3H(t,s)m(s)dcQ(s,ξ)dξ3λ1dsH(t,t3)w1(t3)+μλ1H(t,t3)w2(t3)+μλ2H(t,t3)w3(t3)+tt3[|h(t,s)|(H(t,s))λλ+1m(s)w1(s)H(t,s)λπ1[t0,sd](m(s))1/λa1(sd)(w1(s))λ+1λ]ds+μλ1tt3[|h(t,s)|(H(t,s))λλ+1m(s)w2(s)H(t,s)λπ1[t0,sd](m(s))1/λa1(sd)(w2(s))λ+1λ]ds+μλ2tt3[|h(t,s)|(H(t,s))λλ+1m(s)w3(s)H(t,s)λπ1[t0,sd](m(s))1/λa1(sd)(w3(s))λ+1λ]ds. (4.23)

    Setting Y=|h(t,s)|(H(t,s))λλ+1m(s), X=H(t,s)λπ1[t0,sd](m(s))1/λa1(sd) and u=wi(t) for i=1,2,3. By using the Lemma 2.3, we conclude that

    1H(t,t3)tt3[H(t,s)m(s)dcQ(s,ξ)dξ3λ11+μλ1+μλ2(λ+1)λ+1(|h(t,s)|a1(sd)m(s)π1[t0,sd])λ]dsw1(t3)+μλ1w2(t3)+μλ2w3(t3) (4.24)

    which contradicts condition (4.51).

    Theorem 4.2. Let (1.1) holds and c+d0, cτ1. If there exists an m(t)C1([t0,),R+) such that (2.7) and

    lim supt1H(t,t3)tt3[H(t,s)m(s)dcQ(s,ξ)dξ3λ11+μλ1+μλ2(λ+1)λ+1(|h(t,s)|a1(s+c)m(s)π1[t0,s+c])λ]ds=, (4.25)

    then every solution y(t) of (E2) is either oscillatory or tends to 0.

    Proof. Suppose that (E2) has a nonoscillatory solution y. Without loss of generality, we may take y(t)>0, y(tτ1)>0, y(t+τ2)>0, y(tξ)>0 and y(t+ξ)>0 for tt1t0 and ξ[c,d]. Assumption of (1.1), by Lemma 2.4 there exists two cases (C1) and (C2). If (C2) holds, then by Lemma 2.7, limtz(t)=0. We only consider (C1), by using the fact that z(t)>0 and cτ1, we obtain that Using the fact of L[1]z(t)>0, we obtain

    L[4]z(t)+μλ1L[4]τ1z(t)+μλ2L[4]τ2z(t)+dcQ(t,ξ)dξ3λ1zλ(t+c)0. (4.26)

    Next, we categorize the functions as w1(t)=m(t)L[3]z(t)zλ(t+c), w2(t)=m(t)L[3]τ1z(t)zλ(t+c) and w3(t)=m(t)L[3]τ2z(t)zλ(t+c) respectively. The rest of the proof is similar to that of Theorem 4.1, therefore, it is omitted.

    Theorem 4.3. Let (1.2) holds and bτ1 (or bτ1). If there exists an m(t)C1([t0,),R+) such that (2.7),

    t3[m(s)dcQ(s,ξ)dξ3λ1(1+μλ1+μλ2)((m(s))+(λ+1))λ+1(a1(sd)m(s)π1[t0,sd])λ]ds=, (4.27)

    and

    t3[πλ(s+τ2)dcQ(s,ξ)dξ3λ1(s+dt2dua1(u))λ(λ1+λ)1+λ(1+μλ1)a2(s)+μλ2a2(s+τ2+d)a1+1λ2(s)βλ(s+τ2)]ds=, (4.28)

    where β(t)=t+da1/λ2(s)ds, then every solution y(t) of (E2) is either oscillatory or tends to 0.

    Proof. Suppose that (E1) has a nonoscillatory solution y. Without loss of generality, we may take y(t)>0, y(tτ1)>0, y(t+τ2)>0, y(tξ)>0 and y(t+ξ)>0 for tt1t0 and ξ[c,d]. Since y(t)>0 for all tt1. Assumption of (1.2), by Lemma 2.4 there exists three cases (C1), (C2) and (C3). If case (C1) and (C2) holds, using the similar proof of ([24], Theorem 2.3) by using Lemma 2.1, we get the conclusion of Theorem 4.3

    If case (C3) holds, z(td)<0 for tt1. The facts that z(t)<0, c+d0 and (4.6), we obtain

    L[4]z(t)+μλ1L[4]τ1z(t)+μλ2L[4]τ2z(t)+dcQ(t,ξ)dξ3λ1zλ(t+d)0. (4.29)

    Define

    w(t)=L[3]z(t)(a1(t+d)z(t+d))λ. (4.30)

    We obtain w(t)<0 for tt2. Noting that L[3]z(t) is decreasing, we obtain

    a2(s)[L[2]z(s)]λa2(t)[L[2]z(t)]λ (4.31)

    for stt2. Dividing (4.31) by a2(s) and integrating from t+d to l(lt), we get

    a1(l)z(l)a1(t+d)z(t+d)+a1/λ2(t)[L[2]z(t)]lt+da1/λ2(s)ds.

    letting l, we get

    1a1/λ2(t)[L[2]z(t)]a1(t+d)z(t+d)π(t),tt2. (4.32)

    From (4.30), we have

    1w(t)βλ(t)0. (4.33)

    By (4.2) we have a1(t+d)z(t+d)a1(t)z(t). Differentiating (4.30) gives,

    w(t)(L[3]z(t))(a1(t+d)z(t+d))λλa2(t)[L[2]z(t)a1(t+d)z(t+d)]λ+1. (4.34)

    Using (4.30) in (4.34), we have

    w(t)L[4]z(t)(a1(t+d)z(t+d))λλw1+1λ(t)a1/λ2(t). (4.35)

    Next, we define

    w(t)=L[3]τ1z(t)(a1(t+d)z(t+d))λ. (4.36)

    We obtain w(t)<0 and w(t)w(t) for tt2. By (4.33), we obtain

    1w(t)βλ(t)0. (4.37)

    By (3.2) we have a1(t+d)z(t+d)a1(tτ1)z(tτ1). Differentiating (4.36) gives,

    w(t)(L[3]τ1z(t))(a1(t+d)z(t+d))λλa2(t)[L[2]τ1z(t)a1(t+d)z(t+d)]λ+1. (4.38)

    Using (4.36) in (4.38), we have

    w(t)L[4]τ1z(t)(a1(t+d)z(t+d))λλw1+1λ(t)a1/λ2(t). (4.39)

    Finally, We define a function

    w(t)=L[3]τ2z(t)(a1(t+τ2+d)z(t+τ2+d))λ. (4.40)

    We obtain w(t)<0 and w(t)=w(t+τ2) for tt2. By (4.33), we obtain

    1w(t)βλ(t+τ2)0. (4.41)

    By (4.2) we have a1(t+τ2+d)z(t+τ2+d)a1(t+τ2)z(t+τ2). Differentiating (4.40) gives,

    w(t)(L[3]τ2z(t))(a1(t+d)z(t+d))λλa2(t)[L[2]τ2z(t)a1(t+τ2+d)z(t+τ2+d)]λ+1. (4.42)

    Using (4.40) in (4.42), we have

    w(t)L[4]τ2z(t)(a1(t+d)z(t+d))λλw1+1λ(t)a1/λ2(t). (4.43)

    From (4.35), (4.39), (4.43) and (4.29) which implies

    w(t)+μλ1w(t)+μλ2w(t)dcQ(t,ξ)dξ3λ1zλ(t+d)(a1(t+d)z(t+d))λλw1+1λ(t)a1/λ2(t)μλ1λw1+1λ(t)a1/λ2(t)μλ2λw1+1λ(t)a1/λ2(t) (4.44)

    In case (C3), (a1(t)z(t))<0 we seen that

    z(t)a1(t)z(t)tt2dsa1(s). (4.45)

    Using (4.45) in (4.44), we get

    w(t)+μλ1w(t)+μλ2w(t)dcQ(t,ξ)dξ3λ1(t+dt2dsa1(s))λλw1+1λ(t)a1/λ2(t)μλ1λw1+1λ(t)a1/λ2(t)μλ2λw1+1λ(t)a1/λ2(t) (4.46)

    Multiplying βλ(t+τ2) and integrating from t3(t3>t2) to t, yields

    βλ(t+τ2)w(t)βλ(t3+τ2)w(t3)+βλ(t+τ2)μλ1w(t)βλ(t3+τ2)μλ1w(t3)+βλ(t+τ2)μλ2w(t)βλ(t3+τ2)μλ2w(t3)λtt3[βλ1(s+τ2)(w(s))a1/λ2(s+τ2)βλ(s+τ2)(w(s))1+1λa1/λ2(s)]dsλμλ1tt3[βλ1(s+τ2)(w(s))a1/λ2(s+τ2)βλ(s+τ2)(w(s))1+1λa1/λ2(s)]dsλμλ2tt3[βλ1(s+τ2)(w(s))a1/λ2(s+τ2)βλ(s+τ2)(w(s))1+1λa1/λ2(s)]ds+tt3βλ(s+τ2)dcQ(s,ξ)dξ3λ1(s+dt2dua1(u))λds0. (4.47)

    Applying Lemma 2.3, we conclude that

    tt3[βλ(s+τ2)dcQ(s,ξ)dξ3λ1(s+dt2dua1(u))λ(λ1+λ)1+λ(1+μλ1)a2(s)+μλ2a2(s+τ2+d)a1+1λ2(s) βλ(s+τ2)]ds[βλ(t+τ2)w(t)+μλ1βλ(t+τ2)w(t)+μλ2βλ(t+τ2)w(t)] (4.48)

    Using the fact of βλ(t+τ2)βλ(t) in (4.33), (4.37), (4.41) and (4.48) imply that

    tt3[βλ(s+τ2)dcQ(s,ξ)dξ3λ1(s+dt2dua1(u))λ(λ1+λ)1+λ(1+μλ1)a2(s)+μλ2a2(s+τ2+d)a1+1λ2(s)βλ(s+τ2)]ds1+μλ1+μλ2. (4.49)

    a contradiction to (4.28).

    Example 4.4. Consider a third-order differential equation

    (12(y(t)+(1/3)y(tπ/4)+(2/3)y(t+π/2)))+π0y(tξ)dξ+32π0y(t+ξ)dξ=0, (4.50)

    Compared with (E2), we can see that c=0, d=π, a1(t)=1/2, a2(t)=1, p1(t)=13, p2(t)=23, ˜q1(t,ξ)=˜q2(t,ξ)=1, λ=1, τ1=π/4 and τ2=π/2. By taking m(t)=1, we obtain

    12t4vu2πdsdudv=

    and we take H(t,s)=(ts)2 then h(t,s)=(3st)(ts)1/5 and 0<μ1+μ2<1, we see that

    lim supt1(tt3)2tt3[2π(ts)21+μ1+μ28((3st)(ts)1/5sπt0)λ]ds=. (4.51)

    Since all the conditions of Theorem 4.1 hold, (4.50) is either oscillates or tends to 0.

    In this paper, we have used Riccati substitution techniques, integral averaging technique and some new oscillation and asymptotic theorems for (E1) and (E2) under the conditions (1.1) and (1.2) have been established. Additionally, we established new comparison theorem that permit to study properties of (E1) regardless under the conditions (1.2). The results obtained indicated that it improved theorems reported by Candan [24]. Similar results can be presented under the assumption that λ1. In this case, using Lemma 2.2, one has to simply replace 3λ1 by 1 and proceed as above. In literature, very few works has been paid in the research activities related to qualitative behavior of solutions of various types of stochastic differential equations, see the recent works [1,3,13,14,15,19,20,21]. The results of this paper could be extended to the stochastic differential equations with time delay in further research.

    The authors would like to thank the anonymous reviewers for their valuable suggestions on improving the content of this article.

    The authors declare there are no conflicts of interest.



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