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Research article Special Issues

Optimal assignment of infrastructure construction workers

  • Worker assignment is a classic topic in infrastructure construction. In this study, we developed an integer optimization model to help decision-makers make optimal worker assignment plans while maximizing the daily productivity of all workers. Our proposed model considers the professional skills and physical fitness of workers. Using a real-world dataset, we adopted a machine learning method to estimate the maximum working tolerance time for different workers to carry out different jobs. The real-world dataset also demonstrates the effectiveness of our optimization model. Our work can help project managers achieve efficient management and save labor costs.

    Citation: Haoqing Wang, Wen Yi, Yannick Liu. Optimal assignment of infrastructure construction workers[J]. Electronic Research Archive, 2022, 30(11): 4178-4190. doi: 10.3934/era.2022211

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  • Worker assignment is a classic topic in infrastructure construction. In this study, we developed an integer optimization model to help decision-makers make optimal worker assignment plans while maximizing the daily productivity of all workers. Our proposed model considers the professional skills and physical fitness of workers. Using a real-world dataset, we adopted a machine learning method to estimate the maximum working tolerance time for different workers to carry out different jobs. The real-world dataset also demonstrates the effectiveness of our optimization model. Our work can help project managers achieve efficient management and save labor costs.



    Game theory is a mathematical theory studying competitive phenomena. Since John von Neumann proved the basic principles of game theory, modern game theory was formally established [1,2], which has been paid wide attention and applied to biology, economics, computer science, and many other fields. For example, biologists use game theory to predict certain outcomes of evolution. Economists regard the game theory as one of the standard analysis tools of economics.

    The concept of symmetric games is first proposed by John von Neumann in [2]. The symmetry of a game means that all players have the same set of strategies and fair payoffs, that is, the payoffs depend only on the strategies employed, not on who is playing them. Because fair games are more realistic and acceptable, many common games are symmetric games such as the well-known games rock-paper-scissors and prisoner's dilemma. In recent years, many problems about symmetric games have been investigated in [3], [4], [5], and [6]. In addition, based on the definition of symmetric games, the concepts of skew-symmetric games, asymmetric games and the symmetric-based decomposition of finite games have been proposed in [4]. Although the bases of the symmetric game subspace and the skew-symmetric game subspace have been constructed in [4], the vector space structure of the asymmetric game subspace has not been revealed. Therefore, the motivation of this paper is to explore the vector space structure of the asymmetric game subspace and thoroughly solve the problem of symmetric-based decomposition of finite games. In our recent paper [6], a new method to construct a basis of the symmetric game subspace has been proposed, which gives us great inspiration for the study of skew-symmetric games, asymmetric games, and symmetric-based decomposition of finite games.

    In the past decade, the semi-tensor product (STP) of matrices has been successfully applied to game theory by Cheng and his collaborators [7], which enables a game to be expressed in an algebraic form. In this paper, we still use the matrix method based on STP to investigate skew-symmetric games, asymmetric games and symmetric-based decomposition of finite games. First, by the semi-tensor product method based on adjacent transpositions, necessary and sufficient conditions for testing skew-symmetric games are obtained. Then, based on the necessary and sufficient conditions, a basis of the skew-symmetric game subspace is constructed explicitly. In addition, the discriminant equations for skew-symmetric games with the minimum number are derived concretely. According to the construction methods of the basis of the symmetric game subspace in [6] and the basis of the skew-symmetric game subspace in this paper, a basis of the asymmetric game subspace is constructed for the first time. Therefore, the problem of symmetric-based decomposition of finite games is completely solved.

    The rest of this paper is organized as follows: Section 2 gives some preliminaries. Section 3 studies skew-symmetric games and skew-symmetric game subspace. Section 4 studies asymmetric games and solves the problem of symmetric-based decomposition of finite games. Section 5 is a brief conclusion.

    In this section, some necessary preliminaries are given. Firstly, we list the following notations.

    D={0,1}: the set of values of logical variables;

    δik: the i-th column of Ik;

    Δk:={δik:i=1,2,,k};

    δk[i1i2in]:=[δi1kδi2kδink];

    Mm×n: the set of m×n matrices;

    Lm×n:={LMm×n|Col(L)Δm};

    : the left semi-tensor product of matrices;

    1n: the n-dimensional column vector of ones;

    0m×n: the m×n matrix with zero entries;

    Sn: the n-th order symmetric group, i.e., a permutation group that is composed of all the permutations of n things;

    R: the set composed of all the real numbers.

    Definition 2.1 ([7]). Let AMm×n, BMp×q. The left semi-tensor product of A and B is defined as

    AB=(AIαn)(BIαp), (2.1)

    where is the Kronecker product and α=lcm(n,p) is the least common multiple of n and p. When no confusion may arise it is usually called the semi-tensor product (STP).

    If n and p in Definition 2.1 satisfy n=p, the STP is reduced to the traditional matrix product. So, the STP is a generalized operation of the traditional matrix product. Therefore, one can directly write AB as AB.

    Definition 2.2 ([7]). A swap matrix W[m,n]=(wIJij) is an mn×mn matrix, defined as follows:

    Its rows and columns are labeled by double indices. The columns are arranged by the ordered multi-index Id(i1,i2;m,n), and the rows are arranged by the ordered multi-index Id(i2,i1;n,m). The element at the position with row index (I,J) and column index (i,j) is

    wIJij={1,  I=i and J=j,0,  otherwise.

    When m=n, matrix W[m,n] is denoted by W[m].

    Swap matrices have the following properties:

    (IkW[k])(W[k]Ik)(IkW[k])=(W[k]Ik)(IkW[k])(W[k]Ik). (2.2)

    Definition 2.3. ([8]). A finite game is a triple G=(N,S,C), where

    1) N={1,2,,n} is the set of n players;

    2) S=S1×S2××Sn is the set of strategy profiles, where Si={si1,si2,,siki} is the set of strategies of player i;

    3) C={c1,c2,,cn} is the set of payoff functions, where ci:SR is the payoff function of player i.

    Denote the set composed of all the games above by G[n;k1,k2,,kn]. When |Si|=k for each i=1,2,,n, we denote it by G[n;k].

    STP is a convenient tool for investigating games. Given a game GG[n;k], by using the STP method [9], each strategy xi can be written into a vector form xiΔk, and every payoff function ci can be expressed as

    ci(x1,x2,,xn)=Vcinj=1xj,i=1,2,,n, (2.3)

    where nj=1xjΔkn is called the STP form of the strategy profile, and Vci is called the structure vector of ci.

    Definition 2.4 ([10]). A game GG[n;k] is called a symmetric game if for any permutation σSn

    ci(x1,x2,,xn)=cσ(i)(xσ1(1),xσ1(2),,xσ1(n)) (2.4)

    for any i=1,2,,n.

    Definition 3.1 ([4]). A game GG[n;k] is called a skew-symmetric game if for any permutation σSn

    ci(x1,x2,,xn)=sgn(σ)cσ(i)(xσ1(1),xσ1(2),,xσ1(n)) (3.1)

    for any i=1,2,,n.

    The set composed of all the skew-symmetric games in G[n;k] is denoted as K[n;k].

    Lemma 3.1 ([11]). The set of all the adjacent transpositions (r,r+1),1rn1 is generator of the symmetric group Sn.

    In the following, adjacent transpositions (r,r+1),1rn1 are represented as μr.

    Lemma 3.2. Consider GG[n;k]. For any σ1,σ2Sn, if σ1 and σ2 satisfy

    ci(x1,x2,,xn)=sgn(σ)cσ(i)(xσ1(1),xσ1(2),,xσ1(n)) (3.2)

    for any i=1,2,,n and any x1,x2,,xnΔk, the compound permutation σ2σ1 also satisfies (3.2).

    Proof. For any given xiΔk, i=1,2,,n, let yi=xσ11(i). Then

    ci(x1,x2,,xn)=sgn(σ1)cσ1(i)(xσ11(1),xσ11(2),,xσ11(n))=sgn(σ1)cσ1(i)(y1,y2,,yn)=sgn(σ2)sgn(σ1)cσ2(σ1(i))(yσ12(1),yσ12(2),,yσ12(n))=sgn(σ2σ1)cσ2σ1(i)(xσ11(σ12(1)),xσ11(σ12(2)),,xσ11(σ12(n))),

    which implies that σ2σ1 satisfies (3.2).

    According to Definition 3.1, Lemma 3.1 and Lemma 3.2, the following lemma follows:

    Lemma 3.3. Consider GG[n;k]. Game G is a skew-symmetric game if and only if

    ci(x1,x2,,xn)=cμr(i)(xμr(1),xμr(2),,xμr(n)) (3.3)

    for any adjacent transposition μr, 1rn1, i=1,2,,n.

    Proposition 3.1. Consider GG[n;k]. Game G is a skew-symmetric game if and only if

    Vci=Vcμr(i)Tμr,i=1,2,,n,1rn1, (3.4)

    where Tμr=Ikr1W[k]Iknr1.

    Proof. For any i=1,2,,n and any 1rn1, we have

    cμr(i)(xμr(1),xμr(2),,xμr(n))=Vcμr(i)xμr(1)xμr(2)xμr(n)=Vcμr(i)(x1x2xr1)(xr+1xr)(xr+2xn)=Vcμr(i)(x1x2xr1)(W[k]xrxr+1)(xr+2xn)=Vcμr(i)Tμrx1x2xn. (3.5)

    From (2.3) and (3.5), it follows that (3.4) is equivalent to (3.3). Therefore, the proposition is proved.

    Theorem 3.1. Consider GG[n;k]. Game G is a skew-symmetric game if and only if

    [IknTμ1IknTμ2IknTμn1Ikn+Tμ1Ikn+Tμ2Ikn+Tμn2](VG)T=0, (3.6)

    where Tμr=Ikr1W[k]Iknr1, VG=[Vc1Vc2Vcn], and the omitted elements in the coefficient matrix of (3.6) are all zeros.

    Proof. Since (W[k])1=W[k], we have (Tμr)1=Tμr for any 1rn1. Then, the equation Vci=Vcμr(i)Tμr is equivalent to Vcμr(i)=VciTμr. According to Proposition 3.1, G is a skew-symmetric game if and only if

    [IknTμ1IknTμ2IknTμn1B1B2Bn1Bn](VG)T=0, (3.7)

    where

    B1=[Ikn+Tμ2Ikn+Tμ3Ikn+Tμn1],B2=[Ikn+Tμ3Ikn+Tμ4Ikn+Tμn1], (3.8)
    Bn1=[Ikn+Tμ1Ikn+Tμ2Ikn+Tμn3],Bn=[Ikn+Tμ1Ikn+Tμ2Ikn+Tμn2], (3.9)
    Br=[Ikn+Tμ1Ikn+Tμ2Ikn+Tμr2Ikn+Tμr+1Ikn+Tμr+2Ikn+Tμn1]   (3rn2). (3.10)

    Let the coefficient matrix of equation (3.7) be

    [A1A2B0(n2)2kn×kn0(n2)kn×(n1)knBn] (3.11)

    where

    A1=[IknTμ1IknTμ2IknTμn2Ikn], (3.12)
    A2=[0(n2)kn×knTμn1], (3.13)
    B=[B1B2Bn1]. (3.14)

    Since A1 is an invertible matrix, we can perform the following row transformation on the coefficient matrix of (3.7)

    [I(n1)knBA11I(n2)(n1)knI(n2)kn][A1A2B0(n2)2kn×kn0(n2)kn×(n1)knBn]=[A1A20(n2)2kn×(n1)knBA11A20(n2)kn×(n1)knBn], (3.15)

    where

    BA11A2=[(1)n1B1Tμ1Tμ2Tμn1(1)n2B2Tμ2Tμ3Tμn1Bn1Tμn1]. (3.16)

    Let

    F1=In2(Tμn1Tμn2Tμ1),
    Fr=In3(Tμn1Tμn2Tμr),2rn1.

    We perform the following row transformation on matrix BA11A2

    [(1)n1F1(1)n2F2Fn](BA11A2)=[F1B1Tμ1Tμ2Tμn1F2B2Tμ2Tμ3Tμn1Fn1Bn1Tμn1]. (3.17)

    Therefore, the equivalent form of (3.7) is as follows

    [IknTμ1IknTμ2IknTμn1F1B1Tμ1Tμn1F2B2Tμ2Tμn1Fn1Bn1Tμn1Bn](VG)T=0. (3.18)

    From the property of W[k] shown in (2.2), it follows that

    Tμn1Tμr+1TμrTμiTμrTμr+1Tμn1={Tμi1ir2,Tμi1r+1in1. (3.19)

    Then, (3.18) is equivalent to (3.6). Thus, the proof is complete.

    We see that the key of solving equation (3.6) is computing the solution space of the following linear equation:

    [Ikn+Tμ1Ikn+Tμ2Ikn+Tμn2]x=0, (3.20)

    where x is the kn-dimensional unknown vector. Considering

    [Ikn+Tμ1Ikn+Tμ2Ikn+Tμn2]=[Ikn+W[k]Ikn2Ikn+IkW[k]Ikn3Ikn+Ikn3W[k]Ik]=[Ikn1+W[k]Ikn3Ikn1+IkW[k]Ikn4Ikn1+Ikn3W[k]]Ik, (3.21)

    we only need to solve the linear equations as follows:

    [Ikn1+W[k]Ikn3Ikn1+IkW[k]Ikn4Ikn1+Ikn3W[k]]x=0, (3.22)

    where x is the kn1-dimensional unknown vector. Let x=(xl1l2ln1) be arranged by the ordered multi-index Id(i1,i2,,in1;k,k,,k), that is,

    x=(x1111,x1112,,x111k,x1121,x1122,,x112k,,xkkk1,xkkk2,,xkkkk)T. (3.23)

    Then, by the property of W[k], vector x is a solution of (3.22) if and only if, for any 1l1,l2,,ln1k, the following equations hold:

    xl1l2l3ln1=xl2l1l3ln1,xl1l2l3ln1=xl1l3l2ln1,xl1l2l3ln1=xl1ln3ln1ln2, (3.24)

    i.e.

    xl1l2ln1=sgn(π)xπ(l1l2ln1),πSn1. (3.25)

    Thus, for any 1rn2, if lr=lr+1, then

    xl1lrlrlr+2ln1=xl1lrlrlr+2ln1,

    that is,

    xl1lrlrlr+2ln1=0.

    Therefore, all the free variables of the linear equations (3.22) are

    xl1l2ln1,1l1<l2<<ln1k, (3.26)

    whose number is Cn1k. That is, the dimension of the solution space of linear equations (3.22) is Cn1k.

    For every given repeatable combination s1s2sn1,(1s1s2sn1k), denote by Ps1s2sn1 the set composed of all the repeatable permutation of s1s2sn1. For example, P122={122,212,221}. For every given unrepeatable combination l1l2ln1,(1l1<l2<<ln1k), denote by Rl1l2ln1 the set composed of all the unrepeatable permutation of l1l2ln1. For example, R123={123,132,213,231,312,321}. Let

    Q=(1s1s2sn1kPs1s2sn1)(1l1<l2<<ln1kRl1l2ln1).

    Then, any permutation in Q is a repeated permutation.

    Lemma 3.4. For every given unrepeatable combination l1l2ln1(1l1<l2<<ln1k), define a vector θl1l2ln1=x with the form (3.23) by

    xt1t2tn1={sgn(t1t2tn1),  t1t2tn1Rl1l2ln1,0,  otherwise.

    Then the set

    {θl1l2ln1| 1l1<l2<<ln1k} (3.27)

    is a basis of the solution space ˉXn1 of (3.22). For every l1l2ln1 (1l1<l2<<ln1k), we define |Rl1l2ln1|1 number of vectors νr1r2rn1l1l2ln1=x with r1r2rn1Rl1l2ln1 and r1r2rn1l1l2ln1 by

    xt1t2tn1={1,t1t2tn1=l1l2ln1,sgn(t1t2tn1),t1t2tn1=r1r2rn1,0,otherwise.

    We define |Q| number of vectors λh1h2hn1=x (h1h2hn1Q) by

    xt1t2tn1={1,  t1t2tn1=h1h2hn1,0,  otherwise.

    Then the set of νr1r2rn1l1l2ln1 (1l1<l2<<ln1k,r1r2rn1Rl1l2ln1,r1r2rn1l1l2ln1) and λh1h2hn1 (h1h2hn1Q) is a basis of the orthogonal complementary space ˉXn1. Denote by MW the matrix whose columns are composed of a basis of subspace W. Then the linear system (3.22) is equivalent to MTˉXn1x=0.

    Proof. For any 1l1<l2<<ln1k, sgn(l1l2ln1)=1. From the equivalent equations (3.25) and the free variables shown by (3.26), it follows that the set of θl1l2ln1 (1l1<l2<<ln1k) is a basis of the solution space ˉXn1. By the construction of νr1r2rn1l1l2ln1 and λh1h2hn1, it is straightforward to see that each νr1r2rn1l1l2ln1 and each λh1h2hn1 are orthogonal to ˉXn1. The total number of νr1r2rn1l1l2ln1 is

    1l1<l2<<ln1k(|Rl1l2ln1|1)=1l1<l2<<ln1k|Rl1l2ln1|Cn1k.

    The total number of λh1h2hn1 is

    1s1s2sn1k|Ps1s2sn1|1l1<l2<<ln1k|Rl1l2ln1|
    =kn11l1<l2<<ln1k|Rl1l2ln1|.

    Then the total number of νr1r2rn1l1l2ln1 and λh1h2hn1 is kn1Cn1k, i.e. kn1dim(ˉXn1). Therefore, we conclude that the set of νr1r2rn1l1l2ln1 (1l1<l2<<ln1k,r1r2rn1Rl1l2ln1,r1r2rn1l1l2ln1) and λh1h2hn1 (h1h2hn1Q) is a basis of ˉXn1. Then, the linear system (3.22) is equivalent to MTˉXn1x=0.

    According to the above basis of the solution space of linear equations (3.22), we can construct a basis of skew-symmetric game subspace K[n;k].

    Theorem 3.2. The dimension of the skew-symmetric game subspace K[n;k] is kCn1k. A basis of K[n;k] is composed of the columns of matrix

    [(1)n1W[kn1,k](1)n2IkW[kn2,k](1)n3Ik2W[kn3,k](1)2Ikn3W[k2,k]Ikn2W[k]Ikn](MˉXn1Ik), (3.28)

    where MˉXn1 is composed of the basis of the solution space of (3.22). Moreover, the linear equations with the minimum number to test skew-symmetric games in K[n;k] are

    [IknTμ1IknTμ2IknTμn1MTˉXn1Ik](VG)T=0, (3.29)

    where the omitted elements in the coefficient matrix of (3.29) are all zeros.

    Proof. By Theorem 3.1 and Lemma 3.4, we can easily get the dimension of skew-symmetric game subspace K[n;k] is kCn1k. Using MˉXn1 whose columns are composed of a basis of the solution space of (3.22), we get a basis of the solution space of (3.6) as follows:

    [(1)n1Tμ1Tμn1(MˉXn1Ik)(1)n2Tμ2Tμn1(MˉXn1Ik)(1)n3Tμ3Tμn1(MˉXn1Ik)Tμn1(MˉXn1Ik)MˉXn1Ik]. (3.30)

    By the property of swap matrices shown in (2.2), we have

    TμsTμs+1Tμn1=Iks1W[kns,k]

    for each 1sn1. Then, (3.30) is equivalent to (3.28). That is, the set of the columns of matrix (3.28) is a basis of K[n;k]. Since (3.29) is equivalent to (3.6) and the coefficient matrix of (3.29) has a full row rank, the equations in (3.29) have the minimum number for testing skew-symmetric games in K[n;k].

    Remark 3.1. The coefficient matrix of (3.29) has nknkCn1k number of rows and each row has at most two nonzero elements. Since Cn1kkn1, (n1)knnknkCn1knkn. Therefore, the computational complexity is just O(nkn) due to

    limnnkn(n1)kn=limnnn1=1.

    Definition 4.1 ([4]). A game GG[n;k] is called an asymmetric game if its structure vector

    VG[S[n;k]K[n;k]].

    The set of asymmetric games is denoted by E[n;k].

    Lemma 4.1 ([6]). The dimension of the symmetric game subspace S[n;k] is kCn1k+n2. A basis of S[n;k] is composed of the columns of matrix

    [W[kn1,k]IkW[kn2,k]Ik2W[kn3,k]Ikn2W[k]Ikn](MXn1Ik), (4.1)

    where Xn1 is the solution space of linear equations

    [Ikn1W[k]Ikn3Ikn1IkW[k]Ikn4Ikn1Ikn3W[k]]x=0, (4.2)

    and MXn1 is the matrix composed of a basis of Xn1.

    Let

    A=[W[kn1,k]IkW[kn2,k]Ik2W[kn3,k]Ikn2W[k]Ikn](MXn1Ik), (4.3)
    B=[(1)n1W[kn1,k](1)n2IkW[kn2,k](1)n3Ik2W[kn3,k]Ikn2W[k]Ikn](MˉXn1Ik). (4.4)

    It is easy to check that

    [W[kn1,k]IkW[kn2,k]Ik2W[kn3,k]Ikn2W[k]Ikn]T[(1)n1W[kn1,k](1)n2IkW[kn2,k](1)n3Ik2W[kn3,k]Ikn2W[k]Ikn]=ni=1(Iki1W[k,kni])((1)niIki1W[kni,k])=ni=1(1)niIkn (4.5)

    Since the number of odd permutations of any combination is the same as the number of even permutations, according to the construction of a basis of Xn1 in [6], we have

    ATB=(MTXn1Ik)(ni=1(1)niIkn)(MˉXn1Ik)=ni=1(1)ni(MTXn1MˉXn1Ik)=0p×q, (4.6)

    where p=kCn1k+n2,q=kCn1k. That is, S[n;k] and K[n;k] are orthogonal. Therefore,

    G[n;k]=S[n;k]K[n;k]E[n;k]. (4.7)

    So far, we have constructed a basis of the symmetric game subspace and that of the skew-symmetric game subspace, respectively. Next, according to the two bases, we investigate the vector space structure of the asymmetric game subspace.

    Consider the following linear equations

    [ATBT]x=0, (4.8)

    where A and B are shown in (4.3) and (4.4), composed of the bases of S[n;k] and K[n;k], respectively. Therefore, (4.8) is the discriminant equation with the minimum number for asymmetric games, and a basis of the solution space of (4.8) is also a basis of the asymmetric game subspace E[n;k].

    Construct matrices MXn1 and MˉXn1 as follows:

    MXn1=[η1η2ηβηβ+1ηα], MˉXn1=[θ1θ2θβ], (4.9)

    where α=Cn1k+n2, β=Cn1k, and

    1iβ,1l1<l2<<ln1k,s.t.ηi=ηl1l2ln1,  θi=θl1l2ln1, (4.10)
    β+1iα,1l1l2ln1k,andl1l2ln1Q,s.t.ηi=ηl1l2ln1. (4.11)

    Let

    x=[(x1)T, (x2)T,,(xn)T]TRnkn,

    where xjRkn. Then, (4.8) is equivalent to

    {nj=1[(ηTi+(1)nj+1θTi)Ik](Ikj1W[k,knj   ])xj=0,nj=1[(ηTi+(1)njθTi)Ik](Ikj1W[k,knj   ])xj=0,(1iβ) (4.12)

    and

    nj=1(ηTiIk)(Ikj1W[k,knj])xj=0(β+1iα). (4.13)

    According to the construction of ηi=ηl1l2ln1 and θi=θl1l2ln1 (1iβ), we conclude that (4.12) is equivalent to

    {t1t2tn1   R l1l2ln1sgn(t1t2tn1   )=1   1jnjisoddxjt1t2tj1   lntj+1tn1+t1t2tn1   R l1l2ln1sgn(t1t2tn1   )=1   1jnjisevenxjt1t2tj1   lntj+1tn1=0,t1t2tn1   R l1l2ln1sgn(t1t2tn1   )=1   1jnjisoddxjt1t2tj1   lntj+1tn1+t1t2tn1   R l1l2ln1sgn(t1t2tn1   )=1   1jnjisevenxjt1t2tj1   lntj+1tn1=0 (4.14)

    for any 1l1<l2<<ln1k, 1lnk, and (4.13) is equivalent to

    t1t2tn1   P l1ln1   1jnxjt1t2tj1   lntj+1tn1=0 (4.15)

    for any 1l1l2ln1k, l1l2ln1Q and any 1lnk.

    We first construct two sets of solution vectors of (4.14):

    {μl1l2ln;1t1t2tn1;   j},  {μl1l2ln;1t1t2tn1;   j}.

    If n is odd, let

    μl1l2ln;1t1t2tn1;j=[(x1)T, (x2)T,,(xn)T]TRnkn

    with each xp=(xpr1r2rn),

    xpr1r2rn={1,p=n,r1r2rn=l1l2ln,1,p=j,r1r2rn=t1t2tj1lntjtn1,0,otherwise, (4.16)

    where 1l1<l2<<ln1k, 1lnk, t1t2tn1Rl1ln1, 1jn satisfy one of following conditions:

    (i) j=n, t1t2tn1l1l2ln1 and (1)j+1=sgn(t1t2tn1),

    (ii) jn, (1)j+1=sgn(t1t2tn1).

    Similarly, let

    μl1l2ln;1t1t2tn1;j=[(x1)T, (x2)T,,(xn)T]TRnkn,

    with each xp=(xpr1r2rn),

    xpr1r2rn={1,p=n,r1r2rn=˜l1˜l2˜ln1ln,1,p=j,r1r2rn=t1t2tj1lntjtn1,0,otherwise, (4.17)

    where t1t2tn1 and j satisfy one of the following conditions:

    (i) j=n, t1t2tn1˜l1˜l2˜ln1=l2l1l3ln1 and (1)j=sgn(t1tn1),

    (ii) jn, (1)j=sgn(t1t2tn1).

    If n is even, let

    μl1l2ln;1t1t2tn1;j=[(x1)T, (x2)T,,(xn)T]TRnkn,

    with

    xpr1r2rn={1,p=n,r1r2rn=l1l2ln,1,p=j,r1r2rn=t1t2tj1lntjtn1,0,otherwise, (4.18)

    where 1l1<l2<<ln1k, 1lnk, t1t2tn1Rl1l2ln1, 1jn satisfying one of the following conditions,

    (i) j=n, t1t2tn1l1l2ln1 and (1)j=sgn(t1t2tn1),

    (ii) jn, (1)j=sgn(t1t2tn1),

    Similarly, let

    μl1l2ln;1t1t2tn1;j=[(x1)T, (x2)T,,(xn)T]TRnkn,

    with

    xpr1rn={1,p=n,r1r2rn=˜l1˜l2˜ln1ln,1,p=j,r1r2rn=t1t2tj1lntjtn1,0,otherwise, (4.19)

    where t1t2tn1 and j satisfy one of following conditions:

    (i) j=n, t1t2tn1˜l1˜l2˜ln1=l2l1l3ln1 and (1)j+1=sgn(t1t2tn1),

    (ii) jn, (1)j+1=sgn(t1t2tn1).

    Then we construct a set of solution vectors of (4.15):

    {γl1l2lnt1t2tn1;j}.

    Let

    γl1l2lnt1t2tn1;j=[(x1)T, (x2)T,,(xn)T]TRnkn

    with

    xpr1rn={1,p=n,r1r2rn=l1l2ln,1,p=j,r1r2rn=t1t2tj1lntjtn1,0,otherwise, (4.20)

    where 1l1l2ln1k, l1l2ln1Q, 1lnk, t1t2tn1Pl1l2ln1, 1jn satisfy one of the following conditions:

    (i) j=n, t1t2tn1l1l2ln1,

    (ii) jn.

    Theorem 4.1. The sets {μl1l2ln;1t1t2tn1;j}, {μl1l2ln;1t1t2tn1;j} and {γl1l2lnt1t2tn1;j} form a basis of the asymmetric game subspace E[n;k].

    Proof. According to the construction method of μl1l2ln;1t1t2tn1;j, μl1l2ln;1t1t2tn1;j and γl1l2lnt1t2tn1;j, all the vectors in {μl1l2ln;1t1t2tn1;j}, {μl1l2ln;1t1t2tn1;j} and {γl1l2lnt1t2tn1;j} are linearly independent and satisfy both (4.14) and (4.15). Moreover, we have

    |{μl1l2ln;1t1t2tn1;j}|=|{μl1l2ln;1t1t2tn1;j}|=1l1<l2<<ln1kk(nRl1l2ln121)=1l1<l2<<ln1kk(nRl1l2ln12)kCn1k.
    |{γl1l2lnt1t2tn1;j}|=1l1l2ln1kl1l2ln1Qk(nPl1l2ln11)=1l1l2ln1kl1l2ln1Qk(nPl1l2ln1)(kCn1k+n2kCn1k).

    So,

    {μl1l2ln;1t1t2tn1;   j}+{μl1l2ln;1t1t2tn1;   j}+{γl1l2lnt1t2tn1;   j}=21l1<l2<<ln1kk(nRl1l2ln12)2kCn1k+1l1l2ln1kl1l2ln1   Qk(nPl1l2ln1)(kCn1k+n2kCn1k)=1l1<l2<<ln1kk(nRl1l2ln1)+1l1l2ln1kl1l2ln1   Qk(nPl1l2ln1)kCn1k+n2kCn1k=nknkCn1k+n2kCn1k=nkndim(S[n;k])dim(K[n;k]).

    Therefore, {μl1l2ln;1t1t2tn1  ;   j}, {μl1l2ln;1t1t2tn1  ;   j} and {γl1l2lnt1t2tn1  ;   j} form a basis of E[n;k].

    Remark 4.1. We have given the bases of skew-symmetric game subspace K[n;k] and asymmetric game subspace E[n;k]. In our recently published paper [6], a basis of symmetric game subspace S[n;k] has also been given. Let the bases of S[n;k], K[n;k], E[n;k] be {α1,α2,,αs}, {β1,β2,,βt}, {γ1,γ2,,γl} respectively, where s=kCn1k+n2, t=kCn1k, l=nknkCn1k+n2kCn1k. For any GG[n;k], there are real numbers p1,,ps,q1,,qt,r1,,rl such that

    VG=p1α1++psαs+q1β1++ptβt+r1γ1++rlγl.

    Thus, [p1,,ps,q1,,qt,r1,,rl]T is a solution of equation

    [αT1αTsβT1βTtγT1γTl]x=VTG. (4.21)

    Since the coefficient matrix of (4.21) is a nonsingular matrix and each row has less than 3n! nonzero elements, the computational complexity of game decomposition is less than or equal to O(n!nkn).

    Example 4.1. Consider G[3;2]. If 1l1<l22, we have l1=1,l2=2. Then MˉX2=[0, 1, 1 0]T. If 1l1l22, then l1l2=11, l1l2=12 or l1l2=22. Therefore,

    MX2=[100010010001].

    According to (3.28), a basis of K[3;2] is composed of the columns of matrix

    [W[22,2]I2W[2,2]I23](MˉX2I2) (4.22)

    According to (4.1), a basis of S[3;2] is composed of the columns of matrix

    [W[22,2]I2W[2,2]I23](MX2I2) (4.23)

    According (4.18)-(4.20), the basis of E[3;2] and all non-zero elements in each vector are as follows:

    μ121,112;1,x3121=1,x1112=1;
    μ121,121;2,x3121=1,x2211=1;
    μ122,112;1,x3122=1,x1212=1;
    μ122,121;2,x3122=1,x2221=1;
    μ121,112;2,x3211=1,x2112=1;
    μ121,121;1,x3211=1,x1121=1;
    μ122,112;2,x3212=1,x2122=1;
    μ122,121;1,x3212=1,x1221=1;
    γ11111;1,x3111=1,x1111=1;
    γ11111;2,x3111=1,x2111=1;
    γ11211;1,x3112=1,x1211=1;
    γ11211;2,x3112=1,x2121=1;
    γ22122;1,x3221=1,x1122=1;
    γ22122;2,x3221=1,x2212=1;
    γ22222;1,x3222=1,x1222=1;
    γ22222;2,x3222=1,x2222=1.

    It is easy to verify that the basis of E[3;2] are orthogonal to the columns of the matrices shown in (4.22) and (4.23).

    This paper mainly investigates skew-symmetric game, asymmetric game and the problem of symmetric-based decomposition of finite games. By the semi-tensor product of matrices method with adjacent transpositions, necessary and sufficient conditions for testing skew-symmetric games are obtained. Based on the necessary and sufficient conditions of skew-symmetric games, a basis of skew-symmetric game subspace is constructed explicitly. In addition, the discriminant equations for skew-symmetric games with the minimum number are derived concretely, which reduce the computational complexity. Benefiting from the construction methods of the bases of symmetric game subspace and skew-symmetric game subspace given by us, a basis of asymmetric game subspace is constructed for the first time. Then, any game in G[n;k] can be linear represented by the bases of symmetric game subspace, skew-symmetric game subspace and asymmetric game subspace given by this paper and our previous work. Therefore, the problem of symmetric-based decomposition of finite games is completely solved. Some other kind of games can also be investigated in the frame of semi-tensor product of matrices [12,13,14,15]. We will try to generalize the obtained results in our future work.

    The research work is supported by NNSF of China under Grant 62103194, Natural Science Foundation of Shandong Province of China under Grant ZR2020QA028.

    The authors declare no conflict of interest.



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