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Research article Special Issues

Fixed point for an OgF-c in O-complete b-metric-like spaces

  • In this article, we present the concepts of O-generalized F-contraction of type-(1), type-(2) and prove several fixed point theorems for a self mapping in b- metric-like space. The proved results generalize and extend some of the well known results in the literature. An example to support our result is presented. As an application of our results, we demonstrate the existence of a unique solution to an integral equation.

    Citation: Senthil Kumar Prakasam, Arul Joseph Gnanaprakasam, Ozgur Ege, Gunaseelan Mani, Salma Haque, Nabil Mlaiki. Fixed point for an OgF-c in O-complete b-metric-like spaces[J]. AIMS Mathematics, 2023, 8(1): 1022-1039. doi: 10.3934/math.2023050

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  • In this article, we present the concepts of O-generalized F-contraction of type-(1), type-(2) and prove several fixed point theorems for a self mapping in b- metric-like space. The proved results generalize and extend some of the well known results in the literature. An example to support our result is presented. As an application of our results, we demonstrate the existence of a unique solution to an integral equation.



    As one of the generalizations of metric space, by introducing the conception of metric-like space in 2000, Hitzler [1] gives a valuable contribution to fixed point theory, permitting self-distance to be nonzero, as that can not be possible in metric space. During his studies at the time, he explored the metric-like space under the name "dislocated metric space." Amini-Harandi [2] was the one who renamed the dislocated metric space as metric-like space. Several researchers developed the concept of metric space in many types see [3,4,5,6,7].

    In 2017, Gordji et al. [8] introduced the concept of an orthogonality and presented several fixed-point theorems in an orthogonal metric space. Furthermore, Gordji and Habibi extended more results in generalized orthogonal metric space and ϵ-connected orthogonal metric space; see [9,10]. Hamid Baghain et al. [11] proved fixed-point theorem in orthogonal space via orthogonal F-contraction. In 2018, Senapati [12] initiated the concept of w-distance and proved fixed point results in orthogonal metric space. In 2018, Yamaod et al. [13] came up with the concept of s-orthogonal contraction in b-metric space. In 2019, Gungor et al. [14] changed the distance functions to show more results in orthogonal metric space. Sawangsup and Sintunavarat extended this to an orthogonal concept in O-complete metric space, see [15,16]. The notion of multivalued orthogonal (τ,FT)-contraction in O-complete orthogonal metric space was introduced by Sumit Chandok et al. [17]. Also, Ismat Beg et al. [18] extended the notion of a generalized orthogonal F-Suzuki contraction mapping in O-complete b-metric space. The notion of F-contraction introduced by Wardowski [19] who has proved a fixed point theorem in generalized Banach contraction principle.

    This article, introduces some new concepts of an O-generalized F-contraction and proves fixed point theorems such as new F-contractions in b-metric-like space. Our results primarily generalize and improve the related results in the literature. Moreover, an example and application to the integral equation are given to exhibit the utility of the obtained results.

    Definition 1.1. [19] Let (H,) be a metric space. A self mapping P on H is said to be a F-contraction if ϱ>0 exists such that

    (P,Pγ)>0ϱ+F((P,Pγ))F((,γ)),for all,γH, (1.1)

    where F:[0,)R is a map which holds the following axioms:

    (F1)F is strictly increasing; that is, for all ξ,η[0,)such thatξ<η,F(ξ)<F(η);

    (F2) for every sequence {ξn} of non-negative numbers,

    limn ξn=0limnF(ξn)=;

    (F3) there exists s[0,1] such that limξ0+ξsF(ξ)=0.

    Let us remember from [2], some facts and definitions about b-metric-like space.

    Definition 1.2. [2] A nonempty set H and a function :H×H[0,) satisfies the following conditions holds for all h,k,lH and a constant s>1:

    (1) If (h,k)=0 then h=k;

    (2)(h,k)=(k,h);

    (3)(h,l)s((h,k)+(k,l)).

    The pair of (H,) is called a b-metric-like space.

    Example 1.3. [7] Let H=R. Define a mapping :R×R[0,) by

    (h,k)=(h+k)2

    for all h,kR. Then (R,) is a b-metric-like space with the coefficient s=2.

    efinition 1.4. [2] Each b-metric-like on H generalizes a topology ϱ on H whose base is the family of open -balls B(h,δ)={kH:|(h,k)(h,h)|<δ} for all hH and δ>0.

    efinition 1.5. [2] Suppose that (H,) be a b-metric-like space. A map P:HH is called continuous at hH, if for every ϵ>0δ>0 such that P(B(h,δ))B(Ph,ϵ). We say that P is continuous on H if P is continuous at all hH.

    efinition 1.6. [7] Let (H,) be a b-metric-like space, {ξn} be a sequence in H and ξH. Then a sequence {ξn}H is said to be converge to a point ξH if, for every ϵ>0 there exists n0N such that (ξn,ξ)<ϵ for all n>n0. The convergence is also represented as

    limnξn=ξorξnξ,asn.

    The concept of an orthogonality was introduced by Gordji, Ramezani, De La Sen and Cho [8] as follows:

    Definition 2.1. [8] Let Hϕ and ⊥⊆H×H be a binary relation. If satisfies the following condition:

    h0H:(hH,hh0)or(hH,h0h),

    then (H,) is called an O-set.

    Example 2.2. [8] Let us make a famous fractal called the Sierpinski Triangle.

    Sierpinski's triangle starts as a shaded triangle of equal lengths in page R×R with vertices (-1, 0), (1, 0) and (0, 3). We split the triangle into four same triangles by connecting the centers of each side together and remove this central triangle. We then repeat this process on the 3 newly created smaller triangles. This process is repeated several times on each newly created smaller triangle to arrive at the displayed picture. A Sierpinski's triangle is created by infinitely repeating this construction process.

    Let H be the set of all (infinite) removed triangles. Define the binary relation on H by ab, for all a,bH if there exists aH, {k:(h,k)afor somehR} give to {k:(h,k)bfor somehR}. According to Figure 1 if {k0:(h0,k0)a0for someh0R}, then a0b for all bH. Proceeding this way, we get

    inf{k:(h,k)aforsomehR}inf{k:(h,k)bforsomehR}.
    Figure 1.  Sierpinski triangle.

    Then (H,) is an O-set.

    Example 2.3. [8] Let (H,) be a metric space and P:HH be a Picard operator, that is, H has a unique fixed point hH and limnPn(k)=hfor allkH. We define the binary relation on H by hk if

    limn(h,Pn(k))=0.

    Then (H,) is an O-set.

    Definition 2.4. [8] Let (H,) be an O-set. A sequence {hn}nN is called an orthogonal sequence (shortly, O-sequence) if

    (nH,hnhn+1)or(nH,hn+1hn).

    Example 2.5. Let H=R and suppose that hk if

    h,k(n+15,n+25),

    for some nZ or h=0.

    It is easy to see that (H,) is an O-set. Define P:HHbyP(h)=[h]. Then P is continuous on H. Because if {hn} is an arbitrary O-sequence in H such that {hn} converges to hH, then the below cases hold:

    Case 1: If hk=0 for all k, then h=0 and P(hk)=0=P(h).

    Case 2: If hk00 for some k0, then there exists mZ such that hk(m+15,m+25) for all kk0. Thus h[m+15,m+25] and P(hk)=m=P(h).

    This means that P is -continuous on H while it is not continuous on H.

    Definition 2.6. [8] Let (H,,) be an orthogonal set with the metric . Then H is called an orthogonal complete (shortly, O-complete) if every Cauchy O-sequence is convergent.

    Example 2.7. Let H=[0,1) and suppose that

    hk{hk15,orh=0.

    Then (H,) is an O-set. Clearly, H with the Euclidian metric is not complete metric space, but it is O-complete. In fact, if {xk} is an arbitrary Cauchy O-sequence in H, then there exists a subsequence {hkn} of {hk} for which {hkn}=0 for all n1 or there exists a monotone subsequence {hkn} of {hk} for which {hkn}15 for all n1. It follows that {hkn} converges to a point h[0,15]H.

    Definition 2.8. [8] Let (H,) be an orthogonal metric space and 0<λ<1. A mapping P:HH is called an orthogonal contraction (shortly O-contraction) with Lipschitz constant λ if, h,kH with hk,

    (Ph,Pk)λ(h,k).

    It is verify that every contraction is O-contraction, but the converse is not true. See the following example:

    Example 2.9. [8] Let H=[0,1) and let the metric H on H be the euclidian metric. Define hk if h,k{h,k}, for all h,kH. Let P:HH be a mapping defined by

    P(h)={h2,hHH,0,hHcH.

    Then, it is easy to show that P is an O-contraction on H, but it is not a contraction.

    Definition 2.10. [8] Let (H,) be an orthogonal metric space. A map P:HH is said to be -preserving if PhPk whenever hk.

    In this section, we present an O-generalized F-contraction of type-(1) and type-(2) and prove fixed point theorem for an O-generalized F-contraction of type-(1) and type-(2) maps in an O-b-metric-like space.

    Definition 3.1. Let (H,,) be an O-b-metric-like space. A mapping P:HH is called an O-generalized F-contraction of type-(1) if ϱ>0 and FΛ(be a family of function) such that

    h,kHwithhk(Ph,Pk)>0[12s(h,Ph)<(h,k)ϱ+F((Ph,Pk))tF((Ph,Pk))+aF((h,Ph))+cF((k,Pk))+mF((h,Pk))2s+F((k,Ph))2s], (3.1)

    where t,a,c,m,[0,1] such that t+a+c+m+=1 and 1mc>0.

    Definition 3.2. Let (H,,) be an O-b-metric-like space. A self-mapping P:HH is called an O-generalized F-contraction of type-(2) if ϱ>0 and FΛ such that

    h,kHwithhk(Ph,Pk)>0[ϱ+F((Ph,Pk))tF((h,k))+aF((h,Ph))+cF((k,Pk))+mF((h,Pk)2s)+F((k,Ph)2s)], (3.2)

    where n[0,1)andt,a,m,[0,1],suchthatt+a+c+m+=1,1cm>0.

    Theorem 3.3. Let (H,,) be an O-complete b-metric-like space with an orthogonal element h0 and a map P:HH satisfying the following conditions:

    (i) P is preserving,

    (ii) P is an O-generalized F-contraction of type-(1).

    Then, P has a unique fixed point.

    Proof. Since (H,) is an O-set,

    h0H:(hH,hh0)or(hH,h0h).

    It follows that h0Ph0 or Ph0h0. Let

    h1:=Ph0,h2:=Ph1=P2h0......,hn+1:=Phn=Pn+1h0, (3.3)

    for all nN{0}. If there exists n0N such that (hn0,hn0+1)=0, then h=hn0 is the desired fixed point of H which completes the proof. Consequently, we suppose that 0<(hn,hn+1) for all nN{0}. Since H is -preserving, we have

    hnhn+1orhn+1hn. (3.4)

    This implies that {hn} is an O-sequence. We have

    12s(hn,Phn)<(hn,Phn),nN. (3.5)

    By (3.1), we get

    ϱ+F((Phn,P2hn))tF((hn,Phn))+aF((hn,Phn))+cF((Phn,P2hn))+mF((hn,P2hn))2s+F((Phn,Phn))2s,nN. (3.6)

    Now, we prove that

    (hn+1,Phn+1)<(hn,Phn),nN. (3.7)

    Suppose, on the contrary, that there exists n0N such that (hn0+1,Phn0+1)(hn0,Phn0), due to (3.6), we have

    ϱ+F((Phn0,P2hn0))tF((hn0,Phn0))+aF((hn0,Phn0))+cF((Phn0,P2hn0))+mF((hn0,P2hn0))2s+F((Phn0,Phn0))2stF((hn0,Phn0))+aF((hn0,Phn0))+cF((Phn0,P2hn0))+mF(s(hn0,Phn0)+(s(Phn0,P2hn0)2s+F2s((Phn0,hn0))2stF((hn0,Phn0))+aF((hn0,Phn0))+cF((Phn0,P2hn0))+mF(Phn0,P2hn0)+F((Phn0,hn0)),

    which yields

    ϱ+(1cm)F((Phn0,P2hn0))(t+a+)F((Phn0,hn0))F((Phn0,P2hn0))F((Phn0,hn0))ϱ(1cm),

    which together with (F1) implies (Phn0,P2hn0)<(Phn0,hn0), that is, (hn0+1,Phn0+1)<(Phn0,hn0). It is a contradiction to (hn0+1,Phn0+1)(hn0,Phn0), so (3.3) holds.

    Therefore, {(hn,Phn)} is a decreasing sequence of real numbers which is boundary below. Suppose that A>0 such that

    limn+(hn,Phn)=A=inf{(hn,Phn):nN}.

    Now, we prove A=0. Suppose, conversely A>0. For every ϵ>0, there exists ψN such that

    (hψ,Phψ)=A+ϵ.

    By (F1), we get

    F((hψ,Phψ))=F(A+ϵ). (3.8)

    From (3.5), we get

    12s(hψ,Phψ)<(hψ,Phψ).

    Since P is an O-generalized F-contraction of type-(1), we get

    ϱ+F((Phψ,P2hψ))tF((hψ,Phψ))+aF((hψ,Phψ))+cF((Phψ,P2hψ))+mF((hψ,P2hψ))2s+F((Phψ,Phψ))2stF((hψ,Phψ))+aF((hψ,Phψ))+cF((Phψ,P2hψ))+mF(s(hψ,Phψ))+(s(Phψ,P2hψ))2s+F2s((Phψ,hψ))2stF((hψ,Phψ))+aF((hψ,Phψ))+cF((Phψ,P2hψ))+mF(hψ,Phψ)+F((Phψ,hψ)),

    which implies

    (1c)F((Phψ,P2hψ))(t+a+m+)F(hψ,Phψ)ϱ. (3.9)

    Taking

    c+t+a+m+=1F((Phψ,P2hψ))F((hψ,Phψ))ϱ(1c).

    Since

    12sF((Phψ,P2hψ))F(hψ,Phψ),

    from (3.1), we have

    ϱ+F((P2hψ,P3hψ))tF((Phψ,P2hψ))+aF((Phψ,P2hψ))+cF((P2hψ,P3hψ))+mF((Phψ,P3hψ))2s+F((P2hψ,P2hψ))2stF((Phψ,P2hψ))+aF((Phψ,P2hψ))+cF((P2hψ,P3hψ))+mF(s(Phψ,P2hψ)+(s(P2hψ,P3hψ)2s+F2s((P2hψ,Phψ))2stF((Phψ,P2hψ))+aF((Phψ,P2hψ))+cF((P2hψ,P3hψ))+mF(Phψ,P2hψ)+F((P2hψ,Phψ)).

    This yields

    F((P2hψ,P3hψ))F(Phψ,P2hψ)ϱ(1c).

    Continuing the above process and (3.8), we get

    F((Pnhψ,Pn+1hψ))F(Pn1hψ,Pnhψ)ϱ(1c)F(Pn2hψ,Pn1hψ)2ϱ(1c)....F(hψ,Phψ)nϱ(1c),
    F((Pnhψ,Pn+1hψ))<F(A+ϵ)nϱ(1c). (3.10)

    Letting n+ in (3.10), we get limn+F((Pnhψ,Pn+1hψ))=, which together with (F2) implies limn+(Pnhψ,Pn+1hψ)=0. So, N1N such that (Pnhψ,Pn+1hψ)<A,n>N1, that is, (hψ+n,hψ+n)<A,n>N1, which is a contradiction of A, therefore,

    limn+(hn,Phn)=0. (3.11)

    Now, we prove that

    limn,ψ+(hn,hψ)=0. (3.12)

    Suppose, conversely, ϵ>0 and {p(n)} and {q(n)} of natural numbers such that

    p(n)>q(n)>n,(hp(n),hq(n))ϵand(hp(n)1,hq(n))<ϵ,nN. (3.13)

    Applying the triangle inequality, we get

    (hp(n),hq(n))s(hp(n),hp(n)1)+s(hp(n)1,hq(n))<s(hp(n),hp(n)1)+sϵ=s(Php(n)1,hp(n)1)+sϵ,

    which implies that

    (hp(n),hq(n))<s(Php(n)1,hp(n)1)+sϵ,nN. (3.14)

    Owing to (3.11), there exists N2N such that

    (Php(n)1,hp(n)1)<ϵ,(Php(n),hp(n))<ϵ,(Phq(n),hq(n))<ϵ,n>N2, (3.15)

    which together with (3.14) shows

    (hp(n),hq(n))<2sϵ,n>N2, (3.16)

    hence

    F(hp(n),hq(n))<F(2sϵ),n>N2. (3.17)

    From (3.13) and (3.15), we get

    12s(hp(n),Php(n))<ϵ2s<(hp(n),hq(n)),n>N2. (3.18)

    Using the triangle inequality, we have

    ϵ(hp(n),hp(n))s(hp(n),hp(n)+1)+s2(hp(n)+1,hq(n)+1)+s2(hq(n)+1,hq(n)). (3.19)

    Letting n+ in (3.23), by (3.11), we obtain ϵs2limn+inf(hp(n)+1,hq(n)+1), hence, there exists N3N, such that (hp(n)+1,hq(n)+1)>0 for n>N3 that is, (hp(n),hq(n))>0 for n>N3. By (1.1) and (3.17), we have

    ϱ+F((Php(n),Phq(n)))tF((hp(n),hq(n))+aF(hp(n),Php(n))+cF((hq(n),Phq(n)))+mF(hp(n),Phq(n))2s)+F(hq(n),Php(n))2stF((hp(n),hq(n)))+aF(hp(n),Php(n))+cF((hq(n),Phq(n)))+mF((hp(n),hq(n)))+((hq(n),Phq(n)))2+F((hq(n),hp(n)))+((hp(n),Php(n)))2, (3.20)

    for n>max{N2,N3}.

    Taking (3.15)–(3.17) into account, (3.20) yields

    ϱ+F((Php(n),Phq(n)))<tF(2sϵ)+aF(hp(n),Php(n))+cF((hq(n),Phq(n))+mF(2sϵ+ϵ2)+F(2sϵ+ϵ2), (3.21)

    for n>max{N2,N3}.

    Letting n+ in (3.21), we obtain

    limn,+F((Php(n),Phq(n)))=,

    which yields limn,+F((Php(n),Phq(n))=0, which together with

    (hp(n),hq(n))s(hp(n),hp(n)+1)+s2(hp(n)+1,hq(n)+1)+s2(hq(n)+1,hq(n)),

    shows limn,+(hp(n),hq(n))=0, which is contradiction to (3.13), so (3.5) holds, therefore {hn} is a Cauchy O-sequence in H. Since (H,) is an O-complete, there exists γH such that

    (γ,γ)=limn+(hn,γ)=limn,ψ+(hn,hψ)=0. (3.22)

    It is easy to prove the fact satisfies,

    (hn,Phn)2s<(hn,γ)or(Phn,P2hn)2s<(Phn,γ). (3.23)

    Suppose, conversely that there exists ψ0N such that

    (hψ0,Phψ0)2s(hψ0,γ)and(Phψ0,P2hψ0)2s(Phψ0,γ). (3.24)

    By (3.3) and (3.24), we get

    (hψ0,Phψ0)2ss(hψ0,γ)+s(γ,Phψ0)(hψ0,Phψ0)2+(Phψ0,P2hψ0)2<(hψ0,Phψ0)2+(Phψ0,P2hψ0)2=(hψ0,Phψ0).

    This is a contradiction. Hence (3.23) holds and there exists γH such that

    ϱ+F((Phn,Pγ))tF((hn,γ))+aF((hn,Phn))+cF((γ,Pγ))+mF((hn,Pγ)2s)+F((γ,Phn)2s), (3.25)

    or

    ϱ+F((P2hn,Pγ))tF((Phn,γ))+aF((Phn,P2hn))+cF((γ,Pγ)+mF((Phn,Pγ)2s)+F((γ,P2hn)2s). (3.26)

    Now, we discuss the below cases.

    Case 1: Suppose that (3.25) holds. From (3.25), we have

    ϱ+F((Phn,Pγ))tF((hn,γ))+aF((hn,Phn))+cF((γ,Pγ)+mF((hn,γ)+(γ,Pγ)2)+F((γ,hn)+(hn,Phn)2). (3.27)

    Owing to (3.11) and (3.22), for some ϵ0>0, there exists N4N such that

    (γ,hn)<ϵ0and(hn,Phn)<ϵ0, (3.28)

    for N>N4.

    With the help of (3.27) and (3.28), we get

    ϱ+F((Phn,Pγ))tF((hn,γ))+aF((hn,Phn))+cF((γ,Pγ))+mF(ϵ0+(γ,Pγ)2)+F(ϵ0),

    for N>N4. Taking n+ in the above equation, we have limn+F((Phn,Pγ))= which yields

    limn+(Phn,Pγ)=0. (3.29)

    On the other hand, we have

    (γ,Pγ)s(γ,Phn)+s(Phn,Pγ)=s(γ,hn+1)+s(Phn,Pγ).

    By letting n+ in the above inequality, by (3.22) and (3.29), we get (γ,Pγ)=0, it means γ=Pγ. Thus γ is a fixed point of P.

    Case 2: Let (3.26) hold. From (3.26), we have

    F((P2hn,Pγ))<ϱ+F((P2hn,Pγ))tF((Phn,γ))+aF((Phn,P2hn))+cF((γ,Pγ))+mF((Phn,Pγ)2s)+F((γ,P2hn)2s)tF((hn,γ))+aF((hn,Phn))+cF((γ,Pγ))+mF((Phn,γ)+(γ,Pγ)2)+F((γ,Phn)+(Phn,P2hn)2)=tF((hn+1,γ))+aF((hn+1,Phn+1))+cF((γ,Pγ)+mF((hn+1,γ)+(γ,Pγ)2)+F((γ,hn+1)+(hn+1,Phn+1)2). (3.30)

    From (3.28) and (3.30) yield

    F((P2hn,Pγ))<tF((hn+1,γ))+aF((hn+1,Phn+1))+cF((γ,Pγ))+mF(ϵ0+(γ,Pγ)2)+F(ϵ0),

    for N>N4.

    Taking n+ in the above equation, we get limn,+F((P2hn,Pγ))= which yields

    limn,+((P2hn,Pγ))=0. (3.31)

    On the other way, we have

    (γ,Pγ)s(γ,P2hn)+s(P2hn,Pγ)=s(γ,hn+2)+s(P2hn,Pγ).

    By letting n+ in the above inequality, by (3.22) and (3.31), we get (γ,Pγ)=0, it means γ=Pγ. Thus γ is the fixed point of P and the proof is over.

    Let P have two fixed points are h,kH and suppose that Pnh=hk=Pnk,nN. By choice of h0 we obtain

    (h0handh0k)or(kh0andhh0).

    Since H is - preserving, we have

    (Pnh0PnhandPnh0Pnk)or(PnkPnh0andPnhPnh0),nN.

    Now

    (h,k)=(Pnh,Pnk)(Pnh,Pnh0)+(Pnh0,Pnk).

    As n, we obtain (h,k)0. Thus h=k. Hence P has a unique fixed point.

    Theorem 3.4. Let (H,) be an O-complete b-metric-like space and a map P:HH satisfying the following conditions:

    (i) P is preserving,

    (ii) P is an O-generalized F-contraction of type-(2),

    (iii) if (Ph,Ph)(h,h).

    Then P has a unique fixed point.

    Proof. As in the proof of Theorem 3.3, choosing h0H, we construct sequence {hn} by hn=Phn=Pnh0 and we can suppose

    0<(hn,Phn)=(Phn1,Phn),nN. (3.32)

    From (3.31) and (3.2), we have

    ϱ+F((Phn1,Phn))tF((hn1,hn))+aF((hn1,Phn1))+cF((hn,Phn))+mF((hn1,Phn)2s)+F((hn,Phn1)2s). (3.33)

    We claim

    (hn,Phn)<(hn1,Phn1),nN+. (3.34)

    Suppose, conversely that n0N such that (hn0,Phn0)(hn01,Phn01), which together with (3.32) yields

    ϱ+F((hn0,Phn0))=ϱ+F((Phn01,Phn0))tF((hn01,hn0))+aF((hn01,Phn01))+cF((hn0,Phn0))+mF((hn01,Phn0)2s+F((hn0,Phn01)2s)tF((hn01,hn0))+aF((hn01,Phn01))+cF((hn0,Phn0))+mF(s(hn01,hn0)+s(hn0,Phn0)2s+F(s(hn0,hn01)+s(hn01,Phn01)2s)=tF((hn01,Phn01))+aF((hn01,Phn01))+cF((hn0,Phn0))+mF(s(hn01,Phn01)+s(hn0,Phn0)2s+F(s(Phn01,hn01)+s(hn01,Phn01)2s)tF((hn01,Phn01))+aF((hn01,Phn01))+cF((hn0,Phn0))+mF((hn0,Phn0))+F((hn01,Phn01)). (3.35)

    By (3.35) which implies that

    ϱ+(1cm)F((hn0,Phn0))(t+a+)F((hn01,Phn01)),

    which shows

    F((hn0,Phn0))F((hn01,Phn01))ϱ(1cm). (3.36)

    Applying (3.36) and F(1), we have (hn0,Phn0)<(hn01,Phn01), this is a contradiction. Hence, (3.34) holds.

    Applying(3.2) and (3.34), we obtain

    ϱ+F((hn,Phn))=ϱ+F((Phn1,Phn))tF((hn1,hn))+aF((hn1,Phn1))+cF((hn,Phn))+mF((hn1,Phn)2s)+F((hn,Phn1)2s)tF((hn1,hn))+aF((hn1,Phn1))+cF((hn,Phn))+mF((hn1,hn))+F((hn,hn1))=tF((hn1,Phn1))+aF((hn1,Phn1))+cF((hn,Phn))+mF((hn1,Phn1))+F((Phn1,hn1)),

    which yields

    F((hn,Phn))F((hn1,Phn1))ϱ(1c).

    Continuing this process, we get

    F((hn,Phn))F((h0,Ph0))nϱ(1c). (3.37)

    Letting n+, (3.37) shows limn+F((hn,Phn))=, hence

    limn+((hn,Phn))=0. (3.38)

    Now, we prove

    limn,ψ+((hn,hψ))=0. (3.39)

    Suppose, conversely, ϵ>0 and sequences {p(n)} and {q(n)} of natural numbers such that

    p(n)>q(n)>n,(hp(n),hq(n))ϵand(hp(n)1,hq(n))<ϵ,nN. (3.40)

    Applying the triangle inequality, we get

    (hp(n)1,hq(n)1)s(hp(n)1,hq(n))+s(hq(n),hq(n)1)<s(hq(n),hq(n)1)+sϵ=s(Phq(n)1,hq(n)1)+sϵ,

    which implies that

    (hp(n)1,hq(n)1)<s(Phq(n)1,hq(n)1)+sϵ,n>N. (3.41)

    Owing to (3.38), there exists N1N such that

    (hp(n)1,Php(n)1)<ϵ,(hq(n)1,Phq(n)1)<ϵ,n>N1, (3.42)

    which together with (3.41) shows

    (hp(n)1,hq(n)1)<2sϵ,n>N1, (3.43)

    hence

    F((hp(n)1,hq(n)1))<F(2sϵ),n>N1. (3.44)

    From (3.40), we get

    ϵ(hp(n),hq(n))=(Php(n)1,Phq(n)1),n>N1,

    which together with (3.2) yields

    ϱ+F((Php(n)1,Phq(n)1))tF((hp(n)1,hq(n)1))+aF((hp(n)1,Php(n)1))+cF((hq(n)1,Phq(n)1))+mF((hp(n)1,Phq(n)1)2s)+F((hq(n)1,Php(n)1)2s)tF((hp(n)1,hq(n)1))+aF((hp(n)1,Php(n)1))+cF((hq(n)1,Phq(n)1))+mF((hp(n)1,hq(n)1)+(hq(n)1,Phq(n)1)2)+F(((hq(n)1,hp(n)1)+(hp(n)1,Php(n)1))2), (3.45)

    for all n>N1.

    Taking (3.42)–(3.44) into account, (3.45) yields

    ϱ+F((Php(n)1,Phq(n)1))<tF(2sϵ)+aF(hp(n)1,Php(n)1)+cF(hq(n)1,Phq(n)1)+mF(2sϵ+ϵ2)+F(2sϵ+ϵ2). (3.46)

    Taking n+ in (3.46), we get

    limn+F((Php(n)1,Phq(n)1))=,

    which yields limn+((Php(n)1,Phq(n)1))=0, by F(2), that is, limn+(hp(n),hq(n))=0, which is contradiction to (3.40), so (3.39) holds, therefore, {hn} is a Cauchy O-sequence in H. Since (H,) is an O-complete, there exists γH such that

    (γ,γ)=limn+(hn,γ)=limn,ψ+(hn,hψ)=0. (3.47)

    Since P is O-continuous, we have

    (Pγ,Pγ)=limn+(Phn,Pγ)=limn+(hn+1,Pγ). (3.48)

    Due to (Pγ,Pγ)(γ,γ), from (3.47) and (3.48), we have

    limn+(hn,Pγ)=0. (3.49)

    Since (γ,Pγ)(γ,hn)+(hn,Pγ), by (3.49), we get (γ,Pγ)=0, which gives γ=Pγ, therefore, P has a fixed point.

    Let h,kH be two fixed point of P and suppose that Pnh=hk=Pnk,nN. By choice of h0H we obtain

    (h0handh0k)or(kh0andhh0).

    Since H is - preserving, we have

    (Pnh0PnhandPnh0Pnk)or(PnkPnh0andPnhPnh0),nN.

    Now

    (h,k)=(Pnh,Pnk)(Pnh,Pnh0)+(Pnh0,Pnk).

    As n, we get (h,k)0. Thus h=k. Hence, P has a unique fixed point.

    Let H=[0,D]. Let Q=C(H,R) be the real valued continuous functions with H. Consider the following equation

    ζ(Q)=D0(Q,β)Ω(β,ζ(β))dβ,Q[0,D], (4.1)

    where

    (a) Ω:H×RR is continuous;

    (b) :H×H is continuous and measurable at βH, QH;

    (c) (Q,β)0, Q,βH and D0(Q,β)dβ1, QH.

    Theorem 4.1. Assume that the conditions (a)(c) hold. Suppose that there exists ι>0 such that

    Ω(v,ζ(Q))+Ω(v,ξ(Q))eι(ζ(Q)+ξ(Q)),

    for every QH and ζ,ξC(H,R). Then (4.1) has a unique solution in C(H,R).

    Proof. Let Q={wC(H,R):w(h)>0,hH}. Define the orthogonal relation on Q by

    ζξζ(h)ξ(h)ζ(h)orζ(h)ξ(h)ξ(h),hH.

    Define a function :Q×Q[0,) by

    (ζ,ξ)=ζ(Q)+ξ(Q),

    ζ,ξQ. Thus, (Q,) is a O-b-metric-like space and also a O-complete O-b-metric-like space. Define D:C(H,R)C(H,R) by

    Dζ(Q)=D0(Q,β)Ω(β,ζ(Q)),Q[0,D].

    Now, we show that Q is -preserving. For each ζ,ξQ with ζξ and hI, we have

    Dζ(Q)=D0(Q,β)Ω(β,ζ(Q))1.

    It follows that [(Dζ)(h)][(Dξ)(h)](Dξ)(h) and so (Dζ)(h)(Dξ)(h). Then, Q is -preserving.

    Now, to show that Q is O-generalized F-contraction of type-(1). Let ζ,ξQ with ζξ. Suppose that D(ζ)D(ξ). For every ζ[0,D], we have

    (Dζ,Dξ)=Dζ(Q)+Dξ(Q)=D0(Q,β)(Ω(β,ζ(β))+Ω(β,ξ(β)))dβD0(Q,β)(Ω(β,ζ(β))+Ω(β,ξ(β)))dβD0(Q,β)eł(ζ(Q)+ξ(Q))dβeι(ζ(Q)+ξ(Q))D0(Q,β)dβeι(ζ(Q)+ξ(Q))=eι(ζ,ξ).

    Therefore,

    ι+ln((Dζ,Dξ))ln((ζ,ξ)).

    Letting F(Q)=ln(Q), we get

    ι+F((Dζ,Dξ))F((ζ,ξ)),

    for all ζ,ξQ. Therefore, by Theorem 3.3, Q has a unique fixed point. Hence, there is a unique solution for (4.1).

    In this paper, we proved fixed point theorems for an O-generalized F-contraction of types in an O-complete b-metric like space. We also given an example to manifest the authenticity of the obtained results. As application of our main results, we looked into the solution to the integral equation.

    The authors S. Haque and N. Mlaiki would like to thank Prince Sultan University for paying the publication fees for this work through TAS LAB.

    The authors declare no conflicts of interest.



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