Let F be a finite field of characteristic p having q=pn elements and G be an abelian group. In this paper, we determine the structure of the group of units of the group algebra FG, where G is an abelian group of order 17≤|G|≤20.
Citation: Yunpeng Bai, Yuanlin Li, Jiangtao Peng. Unit groups of finite group algebras of Abelian groups of order 17 to 20[J]. AIMS Mathematics, 2021, 6(7): 7305-7317. doi: 10.3934/math.2021428
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Let F be a finite field of characteristic p having q=pn elements and G be an abelian group. In this paper, we determine the structure of the group of units of the group algebra FG, where G is an abelian group of order 17≤|G|≤20.
Let FG be the group algebra of a finite group G over a finite field F and let U(FG) be the group of units of FG. Determining the structure of U(FG) is a classical problem that has already generated considerable interest in the study of group algebra [1,10,12,14]. In recent years, units of a group algebra were also used as a tool to tackle many research problems in some other areas including coding theory [5,6,7,8] and combinatorial number theory [4].
Many researchers have investigated the structure of U(FG) under different conditions. Sandling [17] completely determined U(FG) when G is a finite p-group and F is a field of characteristic p. Creedon [2] and Tang et al. [19] studied the unit groups of group algebras of some small groups. Tang and Gao [18] described the unit group of FG with |G|=12. Maheshwari [11] determined the unit group of group algebras FSL(2,Z3). Monaghan [13] investigated the units of group algebras of non-abelian groups of order 24 over any finite field of characteristic 3. Sahai and Ansari [15] discussed the unit groups of group algebras of some dihedral groups. In a recent paper, Sahai et al. [16] characterized the unit group of FG when G is an abelian group of order at most 16. In this paper we focus our investigation on the group of units of FG of an abelian group G and determine the structure of U(FG) when G is an abelian group of order between 17 and 20.
This paper is organized as follows. In section 2, we provide some preliminary results. Section 3 deals with the unit group of FG when G is a group of prime order (17 or 19). In the last two sections, we determine the structure of U(FG) when |G|=18 and |G|=20, respectively.
Let F be a finite filed of characteristic p having q=pn elements and G be a finite abelian group. Denote by Cn the cyclic group of order n and by Gk the direct sum of k copies of an abelian group G. Let Fn be the direct sum of n copies of F and let Fn be the extension of F of degree n. Let V(FG),ω(FG), and J(FG) be the group of the normalized unit group, the augmentation ideal and the Jacobson radical of FG, respectively. For a subetaoup H of G, we denote by ω(G,H) the left ideal of FG generated by the set {h−1∣h∈H}.
The number of simple components of FG/J(FG) has been given by Ferraz in [3]. An element g∈G is called p-regular, if p∤o(g). In this article we use the same symbols m, η and T as in [3] to represent the least common multiple of the orders of p-regular elements of G, a primitive mth root of unity over the field F, and the set
T={t:η→ηtisanautomorphismofF(η)overF}. |
Let γg be the sum of all conjugates of g∈G. If g is a p-regular element, then the cyclotomic F-class of γg is
SF(γg)={γgt:t∈T}. |
Lemma 2.1. [3,Proposition 1.2] The number of simple components of FG/J(FG) is equal to the number of cyclotomic F-classes in G.
Lemma 2.2. [3,Theorem 1.3] Suppose that Gal(F(η)/F) is cyclic. Let t be the number of cyclotomic F-classes in G. If K1,K2,...,Kt are the simple components of Z(FG/J(FG)) and S1,S2,...,St are the cyclotomic F classes of G, then with a suitable re-ordering of indices,
|Si|=[Ki:F], |
for i=1,2,…,t.
Remark 2.3. By Lemmas 2.1 and 2.2, we conclude that if G is a finite abelian group and p∤|G|, then FG≅⊕tiKi, where Ki's are defined in Lemma 2.2.
We also need the following results.
Lemma 2.4. [16,Lemma 4.1] Let F be a finite field of characteristic p with |F|=q=pn and let G=Cpki, where k,p are distinct primes and i is a positive integer. Let V=1+J(FG). Then
U(FG)≅V×U(FCki), |
and
V≅Cn(p−1)kip. |
Lemma 2.5. [9,Lemma 1.17] Let G be a locally finite p-group, and let F be a field of characteristic p. Then
J(FG)=ω(FG). |
Lemma 2.6. [14,Theorem 7.2.7] Let F be a finite field and let H be a normal subetaoup of G with [G:H]=n<∞. Then
(J(FG))n⊆J(FH)FG⊆J(FG). |
If in addition n≠0 in F, then
J(FG)=J(FH)FG. |
In this section, we describe the structure of U(FG) when the order of the abelian group G is 17 or 19. We need the following two lemmas.
Lemma 3.1. [2,Lemma 4.1] Let F be a finite field of characteristic p with |F|=q=pn, where p is a prime number. Then U(FCkp)=Cnpk−np×Cpn−1.
Lemma 3.2. [16,Lemma 2.2] Let F be a finite field of characteristic p with |F|=q=pn. If p∤k, then
FCk≅{Fk,ifq≡1modk;F⊕Fk−122,ifq≡−1modkandkisodd;F2⊕Fk−222,ifq≡−1modkandkiseven. |
Now we can state our first result.
Theorem 3.3. Let F be a finite field of characteristic p with |F|=q=pn. Then
U(FC17)≅{C16n17×C17n−1,ifp=17;C17pn−1,ifq≡1mod17;Cpn−1×C8p2n−1,ifq≡−1mod17;Cpn−1×C2p8n−1,ifq≡±2,±8mod17;Cpn−1×C4p4n−1,ifq≡±4mod17;Cpn−1×Cp16n−1,ifq≡±3,±5,±6,±7mod17. |
Proof. If p=17, applying Lemma 3.1 with k=1, we get
U(FC17)=C16n17×C17n−1. |
Next we assume that p≠17. Let C17=⟨x⟩. Obviously, m=17.
We divide the rest of the proof into several cases according to the value of q module 17.
Case 1. q≡±1mod17. By Lemma 3.2, we obtain that
U(FC17)≅{C17pn−1,ifq≡1mod17;Cpn−1×C8p2n−1,ifq≡−1mod17. |
Case 2. q≡±2,±8mod17. It is easy to verify that
T={1,2,4,8,9,13,15,16}mod17. |
By an easy calculation we obtain that
SF(γ1)={γ1},SF(γx)={γx,γx2,γx4,γx8,γx9,γx13,γx15,γx16},SF(γx3)={γx3,γx5,γx6,γx7,γx10,γx11,γx12,γx14}. |
It follows from Remark 2.3 that
FC17≅F⊕F28. |
So
U(FC17)≅Cpn−1×C2p8n−1. |
Case 3. q≡±4mod17. Then
T={1,4,13,16}mod17, |
and thus,
SF(γ1)={γ1},SF(γx)={γx,γx4,γx13,γx16},SF(γx2)={γx2,γx8,γx9,γx15},SF(γx3)={γx3,γx5,γx12,γx14},SF(γx6)={γx6,γx7,γx10,γx11}. |
It follows from Remark 2.3 that FC17≅F⊕F44. Therefore,
U(FC17)≅Cpn−1×C4p4n−1. |
Case 4. q≡±3,±5,±6,±7mod17. Then
T={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16}mod17. |
Thus,
SF(γ1)={γ1},SF(γx)={γx,γx2,γx3,γx4,γx5,γx6,γx7,γx8,γx9,γx10,γx11,γx12,γx13,γx14,γx15,γx16}. |
As above, we obtain that FC17≅F⊕F16, and thus
U(FC17)≅Cpn−1×Cp16n−1. |
This completes the proof.
Using a similar method as in the proof of Theorem 3.3, we obtain the following result.
Theorem 3.4. Let F be a finite field of characteristic p with |F|=q=pn. Then
U(FC19)≅{C18n19×C19n−1,ifp=19;C19pn−1,ifq≡1mod19;Cpn−1×C9p2n−1,ifq≡−1mod19;Cpn−1×Cp18n−1,ifq≡2,3,10,13,14,15mod19;Cpn−1×C2p9n−1,ifq≡4,5,6,9,16,17mod19;Cpn−1×C6p3n−1,ifq≡7,11mod19;Cpn−1×C3p6n−1,ifq≡8,12mod19. |
In this section, we deal with the unit group of FG, when |G|=18. Note that if G is an abelian group of 18, then G≅C18 or G≅C3⊕C6. We need a few lemmas.
Lemma 4.1. [2] Let F be a finite field of characteristic p with |F|=q=pn. Then
U(FC2)≅{Cn2×C2n−1,ifp=2;C2pn−1,ifp≠2. |
Lemma 4.2. [16,Theorem 3.6] Let F be a finite field of characteristic p with |F|=q=pn. Then
U(FC9)≅{C4n3×C2n9×C3n−1,ifp=3;C9pn−1,ifq≡1mod9;Cpn−1×C4p2n−1,ifq≡−1mod9;Cpn−1×Cp2n−1×Cp6n−1,ifq≡2,−4mod9;C3pn−1×C2p3n−1,ifq≡−2,4mod9. |
Lemma 4.3. [16,Theorem 3.7] Let F be a finite field of characteristic p with |F|=q=pn. Then
U(FC23)≅{C8n3×C3n−1,ifp=3;C9pn−1,ifq≡1mod3;Cpn−1×C4p2n−1,ifq≡−1mod3. |
We now state our result on U(FC18).
Theorem 4.4. Let F be a finite field of characteristic p with |F|=q=pn. Then
(1) If p=2, then
U(FC18)≅{C9n2×C92n−1,ifq≡1mod9;C9n2×C2n−1×C422n−1,ifq≡−1mod9;C9n2×C2n−1×C22n−1×C26n−1,ifq≡2,−4mod9;C9n2×C32n−1×C223n−1,ifq≡−2,4mod9. |
(2) If p=3, then
U(FC18)≅C8n3×C4n9×C23n−1. |
(3) If p∤6, then
U(FC18)≅{C18pn−1,ifq≡1mod18;C2pn−1×C8p2n−1,ifq≡−1mod18;C2pn−1×C2p2n−1×C2p6n−1,ifq≡5,11mod18;C6pn−1×C4p3n−1,ifq≡7,13mod18. |
Proof. Let C18=⟨x⟩ and V=1+J(FC18).
(1) If p=2, then applying Lemma 2.4 to G=C18, we obtain
U(FC18)≅V×U(FC9), |
and
V≅C9n2. |
By Lemma 4.2, we obtain
U(FC18)≅{C9n2×C92n−1,ifq≡1mod9;C9n2×C2n−1×C422n−1,ifq≡−1mod9;C9n2×C2n−1×C22n−1×C26n−1,ifq≡2,−4mod9;C9n2×C32n−1×C223n−1,ifq≡−2,4mod9. |
(2) Suppose p=3. Let C2=⟨x9⟩={1,ˉb} and C9=⟨x2⟩=⟨ˉa⟩.
Note that
[C18:C9]=2≠0∈F. |
By Lemmas 2.5 and 2.6,
J(FC18)=J(FC9)FC18=ω(FC9)FC18=ω(C18,C9), |
and
FC18/J(FC18)≅FC2. |
From the ring epimorphism
FC18→FC2, |
we deduce a group epimorphism
φ:U(FC18)→U(FC2), |
and
kerφ=V=1+J(FC18)=1+ω(FC9)FC18=1+ω(C18,C9). |
The ring monomorphism
FC2→FC18 |
given by
α0+α1ˉb→α0+α1ˉb |
induces a group monomorphism
σ:U(FC2)→U(FC18). |
And we can verify that φσ=1U(FC2). Thus U(FC18) is an extension of U(FC2) by V. So
U(FC18)≅V×U(FC2). |
By Lemma 4.1 we have U(FC2)≅C23n−1. We next determine V.
Note that
α=∑17i=0aixi∈J(FC18)=ω(FC9)FC18=ω(C18,C9)ifandonlyif∑8j=0a2j+i=0,i=0,1. |
If α∈J(FC18), a straight forward computation shows that
α3=∑5i=0(a3i+a36+i+a312+i)x3i, |
and
α9=∑1i=0∑8j=0a92j+ix9i=0. |
It follows that V=1+J(FC18) is an abelian 3-group with exponent dividing 9. Let
V≅Cℓ13×Cℓ29. |
It remains to determine ℓ1 and ℓ2.
Since dimF(V)=dimF(J(FC18))=dimF(FC18/FC2)=16, we have |V|=316n. So ℓ1+2ℓ2=16n. Let
S={α∈J(FC18)|α3=0,and∃β∈ω(FC9)suchthatα=β3}. |
Then
S={Σ1i=0(a3ix3i+a3i+6x3i+6+(2a3i+2a3i+6)x3i+12):aj∈F}. |
It follows that |S|=34n, and thus ℓ2=4n. So ℓ1=8n and hence
V≅C8n3×C4n9. |
Therefore,
U(FC18)≅C8n3×C4n9×C23n−1. |
(3) If p∤6, then m=18.
We divide the following proof into several cases according to the value of q module 18.
Case 3.1. q≡±1mod18. By Lemma 3.2, we can get
U(FC18)≅{C18pn−1,ifq≡1mod18;C2pn−1×C8p2n−1,ifq≡−1mod18. |
Case 3.2. q≡5,11mod18. Then T={1,5,7,13,11,17}mod18. It follows from Remark 2.3 that
SF(γ1)={γ1}, SF(γx9)={γx9},SF(γx)={γx,γx5,γx7,γx11,γx13,γx17},SF(γx2)={γx2,γx4,γx8,γx10,γx14,γx16},SF(γx3)={γx3,γx15}, SF(γx6)={γx6,γx12}. |
Therefore,
FC18≅F2⊕F22⊕F26. |
So
U(FC18)≅C2pn−1×C2p2n−1×C2p6n−1. |
Case 3.3. q≡7,13mod18. Then T={1,7,13}mod18. Thus,
SF(γ1)={γ1}, SF(γx3)={γx3},SF(γx6)={γx6}, SF(γx9)={γx9},SF(γx12)={γx12}, SF(γx15)={γx15},SF(γx)={γx,γx7,γx13}, SF(γx2)={γx2,γx8,γx14},SF(γx4)={γx4,γx10,γx16}, SF(γx5)={γx2,γx11,γx17}. |
Therefore,
FC18≅F6⊕F43. |
Thus
U(FC18)≅C6pn−1×C4p3n−1. |
This completes the proof.
Next we determine the structure of U(F(C3×C6)).
Theorem 4.5. Let F be a finite field of characteristic p with |F|=q=pn and let G=C3×C6.
(1) If p=2, then
U(FG)≅{C9n2×C92n−1,ifq≡1mod3;C9n2×C2n−1×C422n−1,ifq≡−1mod3. |
(2) If p=3, then
U(FG)≅C16n3×C23n−1. |
(3) If p∤6, then
U(FG)≅{C18pn−1,ifq≡1mod6;C2pn−1×C8p2n−1,ifq≡−1mod6. |
Proof. Let G=⟨x,y∣x3=y6=1,xy=yx⟩ and V=1+J(FG).
(1) If p=2, then let H=⟨y3⟩. We know that [G:H]=9≠0∈F. By Lemmas 2.5 and 2.6,
J(FG)=J(FH)FG=ω(FH)FG=ω(G,H), |
and
FG/J(FG)≅F(C3×C3). |
From the ring epimorphism
FG→F(C3×C3), |
we deduce a group epimorphism
φ:U(FG)→U(F(C3×C3)), |
and
kerφ=V=1+J(FG)=1+ω(G,H). |
The ring monomorphism
F(C3×C3)→FG, |
induces a group monomorphism
σ:U(F(C3×C3))→U(FG). |
It is not hard to show that φσ=1U(F(C3×C3)). Thus U(FG) is an extension of U(F(C3×C3)) by V. So
U(FG)≅V×U(F(C3×C3)). |
By Lemma 4.3 we have
U(FC23)≅{C92n−1,q≡1mod3;C2n−1×C422n−1,q≡−1mod3. |
We next determine V. It is clear that
α=2∑i=05∑j=0a6i+jxiyj∈ω(G,H) |
if and only if
ai+a3+i=0,i=0,1,2,6,7,8,12,13,14. |
A straight forward calculation gives that α2=0. Thus, it is not hard to show that dimF(J(FG))=9, and V≅C9n2. Therefore
U(FG)≅{C9n2×C92n−1,ifq≡1mod3;C9n2×C2n−1×C422n−1,ifq≡−1mod3. |
(2) If p=3, then let H=⟨x⟩×⟨y2⟩. We know [G:H]=2≠0∈F. As in the proof of (1) we can show that
U(FG)≅V×U(FC2). |
By Lemma 4.1 we have U(FC2)≅C23n−1. We next determine V. It is clear that
α=∑2i=0∑5j=0a6i+jxiyj∈ω(FH) if and only if ∑8i=0a2i+j=0, j=0,1. |
It is not hard to show that α3=0. Thus we obtain that dimF(J(FG))=16, and V≅C16n3. Therefore,
U(FG)≅C16n3×C23n−1. |
(3) If p∤6, then m=6.
If q≡1mod6, then T={1}mod6. Thus,
SF(γx)={γx}, ∀x∈G. |
So
FG≅F18. |
Therefore,
U(FG)≅C18pn−1. |
If q≡−1mod6, then T={1,5}mod6. Thus,
SF(γ1)={γ1}, SF(γy3)={γy3},SF(γy)={γy,γy5}, SF(γy2)={γy2,γy4},SF(γxy)={γxy,γx2y5}, SF(γxy2)={γxy2,γx2y4},SF(γxy3)={γxy3,γx2y3}, SF(γx2y)={γx2y,γxy5},SF(γx2y2)={γx2y2,γxy4}, SF(γx)={γx,γx2}. |
Therefore,
FG≅F2⊕F82. |
Thus
U(FG)≅C2pn−1×C8p2n−1. |
This completes the proof.
In this section, we investigate the unit group of FG when |G|=20. Since G is an abelian group of 20, G≅C20 or G≅C2⊕C10.
Lemma 5.1. [16,Theorem 2.3] Let F be a finite field of characteristic p with |F|=q=pn. Then
U(FC5)≅{C4np×Cpn−1,ifp=5;C5pn−1,ifq≡1mod5;Cpn−1×Cp4n−1,ifq≡±2mod5;Cpn−1×C2p2n−1,ifq≡−1mod5. |
Lemma 5.2. [16,Theorem 3.1] Let F be a finite field of characteristic p with |F|=q=pn. Then
U(FC4)≅{Cn2×Cn4×C2n−1,ifp=2;C4pn−1,ifq≡1mod4;C2pn−1×Cp2n−1,ifq≡−1mod4. |
Lemma 5.3. [16,Theorem 3.2] Let F be a finite field of characteristic p with |F|=q=pn. Then
U(FC22)≅{C3n2×C2n−1,ifp=2;C4pn−1,ifp≠2. |
The next two theorems provide complete characterizations of the structures of U(FC20) and U(F(C2⊕C10)), respectively. As their proofs are very much similar to those of Theorem 4.4 and Theorem 4.5, we omit the detailed computation and state only the results.
Theorem 5.4. Let F be a finite field of characteristic p with |F|=q=pn.
(1) If p=2, then
U(FC20)≅{C5n4×C5n2×C52n−1,ifq≡1mod5;C5n4×C5n2×C2n−1×C24n−1,ifq≡±2mod5;C5n4×C5n2×C2n−1×C222n−1,ifq≡−1mod5. |
(2) If p=5, then
U(FC20)≅{C16n5×C45n−1,ifq≡1mod4;C16n5×C25n−1×C52n−1,ifq≡−1mod4. |
(3) If p≠2 and p≠5, then
U(FC20)≅{C20pn−1,ifq≡1mod20;C2pn−1×C9p2n−1,ifq≡−1mod20;C2pn−1×Cp2n−1×C4p4n−1,ifq≡3,7mod20;C4pn−1×C4p4n−1,ifq≡13,17mod20;C4pn−1×C8p2n−1,ifq≡9mod20;C10pn−1×C5p2n−1,ifq≡11mod20. |
Theorem 5.5. Let F be a finite field of characteristic p with |F|=q=pn and let G=C2×C10.
(1) If p=2, then
U(FG)≅{C15n2×C52n−1,ifq≡1mod5;C15n2×C2n−1×C24n−1,ifq≡±2mod5;C15n2×C22n−1,ifq≡−1mod5. |
(2) If p=5, then
U(FG)≅C16n5×C45n−1. |
(3) If p≠2 and p≠5, then
U(FG)≅{C20pn−1,ifq≡1mod10;C4pn−1×C8p2n−1,ifq≡−1mod10;C4pn−1×C4p4n−1,ifq≡3,7mod10. |
The authors would like to thank the referees for very useful suggestions and for pointing out the work of R. Sandling to them. This research was supported in part by the Scientific research project of Tianjin Municipal Education Commission (Grant No. 2018KJ252), and was also supported in part by a Discovery Grant from the Natural Sciences and Engineering Research Council of Canada (Grant No. RGPIN 2017-03093).
All authors declare no conflicts of interest in this paper.
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1. | Namatchivayam Umapathy Sivaranjani, Elumalai Nandakumar, Gaurav Mittal, Rajendra Kumar Sharma, Unit Group of the Group Algebra $\mathbb{F}_qGL(2,7)$, 2024, 1829-1163, 1, 10.52737/18291163-2024.16.3-1-14 |