Citation: Zonghu Xiu, Shengjun Li, Zhigang Wang. Existence of infinitely many small solutions for fractional Schrödinger-Poisson systems with sign-changing potential and local nonlinearity[J]. AIMS Mathematics, 2020, 5(6): 6902-6912. doi: 10.3934/math.2020442
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This article deals mainly with the following fractional Schrödinger-Poisson systems
{(−Δ)su+V(x)u+ϕu=f(x,u),x∈R3,(−Δ)tϕ=u2,x∈R3, | (1.1) |
where (−Δ)α denotes the fractional Laplacian of order α∈(0,1) and V is allowed to be sign-changing. In (1.1), the first equation is a nonlinear fractional Schrödinger equation in which the potential ϕ satisfies a nonlinear fractional Poisson equation. For this reason, system (1.1) is called a fractional Schrödinger-Poisson system, also known as the fractional Schrödinger-Maxwell system, which is not only a physically relevant generalization of the classical NLS but also an important model in the study of fractional quantum mechanics. For more details about the physical background, we refer the reader to [3,4] and the references therein.
It is well known that the fractional Schrödinger-Poisson system was first introduced by Giammetta in [8] and the diffusion is fractional only in the Poisson equation. Afterwards, in [14], the authors proved the existence of radial ground state solutions of (1.1) when V(x)≡0 and nonlinearity f(x,u) is of subcritical or critical growth. Very recently, in [15], the author proved infinitely many solutions via Fountain Theorem for (1.1) and V(x) is positive. However, to the best of our knowledge, for the sign-changing potential case, there are not many results for problem (1.1).
In recent years, the following potential function was discussed: (V1) V(x)∈C(R3,R) and infx∈R3V(x)>−∞, which is called sign-changing potential. It is well known that the Schrödinger equation has already attracted a great deal of interest in the recent years with the above sign-changing potential. Many researchers studied infinitely many solutions for Schrödinger equation with the above sign-changing potential and some different growth conditions on f, see [11,13]. On the basis of the previous work, many authors considered infinitely many solutions for different equations with sign-changing potential and some different growth conditions on f, see [1,5,6,7,10,11,13,18,19,20,21,22] and the references therein. In particular, Bao [7] and Zhou [13] studied infinitely many small solutions for Schrödinger-Poisson equation with sign-changing potential. However, we know that there are few papers which deal with infinitely many small solutions without any growth conditions via dual methods.
Inspired by [7,13], we will study infinitely many small solutions for the problem (1.1) under the following assumptions on V and f:
(V2) There exists a constant d0>0 such that
lim|y|→∞meas({x∈R3:|x−y|≤d0,V(x)≤M})=0,∀M>0. |
(f1) There exists constant δ1>0 and 1<r1<2 such that f∈C(R3×[−δ1,δ1],R) and
|f(x,t)|≤a(x)|t|r1−1,|t|≤δ1,∀x∈R3, |
where a(x)∈L22−r1(R3) is a positive continuous function.
(f2) limt→0f(x,t)t=+∞ uniformly for x∈R3.
(f3) There exists a constant δ2>0 such that f(x,−t)=−f(x,t) for any |t|≤δ2 and all x∈R3.
Note that condition (V2) is usually applied to meet the compact embedding.
Next, we are ready to state the main result of this paper.
Theorem 1.1 Suppose that (V1), (V2) and (f1)–(f3) hold. Then when s∈(34,1), t∈(0,1) satisfying 4s+2t≥3, problem (1.1) has infinitely many solutions {uk} such that
12∫R3|(−Δ)α2uk|2dx+12∫R3V(x)u2kdx+14∫R3ϕtuku2kdx−∫R3F(x,uk)dx≤0 |
and uk→0 as k→∞.
Throughout this paper, C>0 denote various positive constants which are not essential to our problem and may change from line to line.
Before stating this section, we first notice the following fact: by (V1), we can conclude that there exists a constant V0 such that ˜V(x):=V(x)+V0>0 for all x∈R3. Let ˜f(x,u)=f(x,u)+V0u and consider the following new equation
{(−Δ)su+˜V(x)u+ϕu=˜f(x,u),x∈R3,(−Δ)tϕ=u2,x∈R3. | (2.1) |
It is easy to check that the hypotheses (V1), (V2) and (f1)–(f3) still hold for ˜V and ˜f provided that those hold for V and f. In what follows, we just need to study the equivalent Eq (2.1). Therefore, throughout this section, we make the following assumption instead of (V1)(˜V1)˜V(x)∈C(R3,R) and infx∈R3˜V(x)>0.
To this end, we define the Gagliardo seminorm by
[u]α,p=(∫R3∫R3|u(x)−u(y)|p|x−y|N+αpdxdy)1p, |
where u:R3→R is a measurable function.
On the one hand, we define fractional Sobolev space by
Wα,p(R3)={u∈Lp(R3):uis measurable and[u]α,p<∞} |
endowed with the norm
‖u‖α,p=([u]pα,p+‖u‖pp)1p, | (2.2) |
where
‖u‖p=(∫R3|u(x)|pdx)1p. |
If p=2, the space Wα,2(R3) is an equivalent definition of the fractional Sobolev spaces based on the Fourier analysis, that is,
Hα(R3):=Wα,2(R3)={u∈L2(R3):∫R3(1+|ξ|2α)|˜u|2dξ<∞}, |
endowed with the norm
‖u‖Hα=(∫R3|ξ|2α|˜u|2dξ+∫R3|u|2dξ)12, |
where ˜u denotes the usual Fourier transform of u. Furthermore, we know that ‖⋅‖Hα is equivalent to the norm
‖u‖Hα=(∫R3|(−Δ)α2u|2dx+∫R3u2dx)12. |
Let Ω⊆R3 and Lp(Ω), 1≤p≤+∞ be a Lebesgue space, the norm in Lp(Ω) is denoted by |⋅|p,Ω. Let Hα0(Ω), Ω⊂R3, and Hα(R3) denote the usual fractional Sobolev spaces (see [9]). Under the assumption (˜V1), our working space is defined by
E={u∈Hα(R3):∫R3˜V(x)u2dx<∞} | (2.3) |
and
E(Ω)={u∈Hα0(Ω):∫Ω˜V(x)u2dx<∞}. |
Thus, E is a Hilbert space with the inner product
(u,v)EV=∫R3(|ξ|2α˜u(ξ)˜v(ξ)+˜u(ξ)˜v(ξ))dξ+∫R3˜V(x)u(x)v(x)dx, |
(u,v)E,Ω=∫Ω(|ξ|2α˜u(ξ)˜v(ξ)+˜u(ξ)˜v(ξ))dξ+∫Ω˜V(x)u(x)v(x)dx, |
and the norm
‖u‖EV=(∫R3(|ξ|2α|˜u(ξ)|2+|˜u(ξ)|2)dξ+∫R3˜V(x)u2(x)dx)12, |
‖u‖E,Ω=(∫Ω(|ξ|2α|˜u(ξ)|2+|˜u(ξ)|2)dξ+∫Ω˜V(x)u2(x)dx)12, |
Moreover, ‖⋅‖EV and ‖u‖E,Ω are equivalent to the following norms
‖u‖:=‖u‖E=(∫R3|(−Δ)α2u|2dx+∫R3˜V(x)u2dx)12, |
and
‖u‖E,Ω=(∫Ω|(−Δ)α2u|2dx+∫Ω˜V(x)u2dx)12, |
where the corresponding inner product are
(u,v)E=∫R3((−Δ)α2u(−Δ)α2v+˜V(x)uv)dx. |
and
(u,v)E,Ω=∫Ω((−Δ)α2u(−Δ)α2v+˜V(x)uv)dx. |
The homogeneous Sobolev space Dα,2(R3) is defined by
Dα,2(R3)={u∈L2∗α(R3):|ξ|α˜u(ξ)∈L2(R3)}, |
which is the completion of C∞0(R3) under the norm
‖u‖Dα,2=(∫R3|(−Δ)α2u|2dx)12=(∫R3|ξ|2α|˜u(ξ)|2dξ)12, |
endowed with the inner product
(u,v)Dα,2=∫R3(−Δ)α2u(−Δ)α2vdx. |
Then Dα,2(R3)↪L2∗α(R3), that is, there exists a constant C0>0 such that
‖u‖2∗α≤C0‖u‖Dα,2. | (2.4) |
Next, we give the following lemmas which discuss the continuous and compact embedding for E↪Lp(R3) for all p∈[2,2∗α]. In the rest of paper, we use the norm ‖⋅‖ in E. Motivated by Lemma 3.4 in [16], we can prove the following Lemma 2.1 in the same way. Here we omit it.
Lemma 2.1 E is continuously embedded into Lp(R3) for 2≤p≤2∗α:=63−2α and compactly embedded into Lp(R3) for all s∈[2,2∗α).
Lemma 2.2 ([[9], Theorem 6.5]) For any α∈(0,1), Dα,2(R3) is continuously embedded into L2∗α(R3), that is, there exists Sα>0 such that
(∫R3|u|2∗αdx)22∗α≤Sα∫R3|(−Δ)α2u|2dx∀u∈Dα,2(R3). |
Next, let α=s∈(0,1). Using Hölder's inequality, it follows from Lemma 2.1 and Lemma 2.2 that for every u∈E and s,t∈(0,1), we have
∫R3u2vdx≤(∫R3|u|123+2tdx)3+2t6(∫R3|v|2∗tdx)12∗t≤γ123+2tS12t‖u‖2‖v‖Dt,2, | (2.5) |
where we used the following embedding
E↪L123+2t(R3)if2t+4s≥3. |
By the Lax-milgram theorem, there exists a unique ϕtu∈Dt,2(R3) such that
∫R3v(−Δ)tϕtudx=∫R3(−Δ)t2ϕtu(−Δ)t2vdx=∫R3u2vdx,v∈Dt,2(R3). | (2.6) |
Hence, ϕtu satisfies the Poisson equation
(−Δ)tϕtu=u2,x∈R3. |
Moreover, ϕtu has the following integral expression
ϕtu(x)=ct∫R3u2(y)|x−y|3−2tdy,x∈R3, |
which is called t-Riesz potential, where
ct=π−322−2tΓ(32−2t)Γ(t). |
Thus ϕtu(x)≥0 for all x∈R3, from (2.2) and (2.6), we have
‖ϕtu‖Dt,2≤S12t‖u‖2L123+2t≤C1‖u‖2if2t+4s≥3. | (2.7) |
Therefore, by Hölder's inequality and Lemma 2.1 and Lemma 2.2, there exist ˜C1>0, ˜C2>0 such that
∫R3ϕtuu2dx≤(∫R3|ϕtu|2∗tdx)12∗t(∫R3|u|123+2tdx)3+2t6≤˜C1‖ϕtu‖Dt,2‖u‖2≤˜C2‖u‖4. |
Now, we define a cut-off function h∈C(R,R) such that 0≤h(t)≤1, h(−t)=h(t) for all t∈R, h(t)≡1 for all |t|≤d, h(t)≡0 for all |t|≥2d and h is decreasing in [d,2d], where 0<d≤12min{δ1,δ2,1}. Let
fh(x,u)=f(x,u)h(u),∀(x,u)∈R3×R, | (2.8) |
and
Fh(x,u)=∫u0fh(x,t)dt,∀(x,u)∈R3×R. | (2.9) |
Consider the following modified fractional Schrödinger-Poisson system
{(−Δ)su+˜V(x)u+ϕu=fh(x,u),x∈R3,(−Δ)tϕ=u2,x∈R3. | (2.10) |
and define the cut-off functional by
Jh(u)=12∫R3(|(−Δ)s2u|2+˜V(x)|u|2)dx+14∫R3ϕtuu2dx−∫R3Fh(x,u)dx. |
Moreover, the derivative of J is
⟨J′h(u),v⟩=∫R3((−Δ)s2u(−Δ)s2v+˜V(x)uv+ϕtuuv−f(x,u)v)dx,∀u,v∈E. | (2.11) |
Then u∈E, satisfies |u|≤l, is a critical point of the functional Jh, u is a weak solution of (1.1). Since the embedding E(Ω)↪Lr(Ω) is continuous, where r∈[2,2∗s] and Ω⊂R3, then there exists a constant ϱr such that |u|r,Ω≤ϱr‖u‖E,Ω. By Lemma 2.1, we know that E(Ω)↪Lp(Ω) is compact for all p∈[2,2∗s). Similar to [7], the energy functional Jh:E→R is well defined and of class C1(E,R). Obviously, it can be proved that if u is a critical point of Jh, then the pair (u,ϕtu) is a solution of system (1.1).
Let Γk denote the family of closed symmetric subsets A of E such that 0∉A and the genus γ(A)≥k. For more details on genus, we refer the readers to [23]. To prove the existence of infinitely many solutions, we mainly apply the following critical point theorem established in [2].
Lemma 2.3 [2] Let E be an infinite dimensional Banach space and Jh∈C1(E,R) an even functional with Jh(0)=0. Suppose that Jh satisfies
(J1)Jh is bounded from below and satisfies (PS) condition.
(J2) For each k∈N, there exists an Ak∈Γk such that supu∈AkJh(u)<0.
Then there exists a critical point sequence {uk} such that Jh(uk)≤0 and limk→∞uk=0.
In order to prove our main result by Lemma 2.3, we need the following lemmas.
Lemma 2.4 Assume that a sequence {un}⊂E, un⇀u in E as n→∞ and {‖un‖} be a bounded sequence. Then, as n→∞, we have
∫R3(ϕtunun−ϕtuu)(un−u)dx→0. | (2.12) |
Proof. Take a sequence {un}⊂E such that un⇀u in E as n→∞ and {‖un‖} is a bounded sequence. By Lemma 2.1, we have un→u in Lp(R3) where 2≤p<2∗s, and un→u a.e. on R3. Hence supn∈N‖un‖<∞ and ‖u‖ is finite. Since s∈(34,1), then we know that E↪L62s(R3) holds. Hence by (2.4) and (2.7), we have
|∫R3(ϕtunun−ϕtuu)(un−u)dx|≤(∫R3(ϕtunun−ϕtuu)2dx)12(∫R3(un−u)2dx)12≤√2[∫R3(|ϕtunun|2+|ϕtuu|2)]12‖un−u‖2≤C3(‖ϕtun‖22∗s‖un‖262s+‖ϕtu‖22∗s‖u‖262s)12‖un−u‖2≤C3(‖un‖4+‖u‖4)12‖un−u‖2→0,asn→∞. |
This completes the proof of this lemma.
Lemma 2.5 Suppose that (V1), (V2) and (f1), (f2) hold. Then Jh is bounded from below and satisfies the (PS) condition on E.
Proof. By (V1), (V2), (f1), f2) and the definition of h, we can get
|Fh(x,v)|≤a(x)r1|v|r1+V02v2,∀(x,v)∈(R3,R). |
For any given v∈E, let Ω={x∈R3:|v|≤1}. By Hölder's inequality and the definition of Jh, one has
Jh(v)=12‖v‖2+14∫R3ϕtvv2dx−∫R3Fh(x,v)dx≥C2‖v‖2E,Ω+14∫R3ϕtvv2dx−∫ΩFh(x,v)dx≥C2‖v‖2E,Ω−∫Ω(a(x)r1|v|r1+V02v2)dx≥C2‖v‖2E,Ω−∫Ω(a(x)r1|v|r1+V02vr1)dx≥C2‖v‖2E,Ω−1r1|a(x)|22−r1,Ω‖v‖r12,Ω−V02‖v‖r1r1,Ω≥C2‖v‖2E,Ω−ϱr12r1|a(x)|22−r1,R3‖v‖r1E,Ω−V0ϱr1r12‖v‖r1E,Ω, | (2.13) |
which implies that Jh is bounded from below by r1∈(1,2). Next we prove Jh satisfies the (PS) condition. Let {vn}⊂E be any (PS) sequence of Jh, that is, {Jh(vn)} is bounded and J′h(vn)→0. For each n∈N, set Ωn={x∈R3:|vn|≤1}. Then by (2.13), we have
C≥Jh(vn)≥C2‖vn‖2E,Ωn−ϱr12r1|a(x)|22−r1,R3‖vn‖r1E,Ωn−V0ϱr1r12‖vn‖r1E,Ωn, |
which implies that ‖vn‖E,Ωn≤C and C is independent of n. Thus
12∫Ωn|(−Δ)s2vn|2dx+12∫Ωn˜V(x)v2ndx+14∫Ωnϕtvnv2ndx=Jh(vn)+∫ΩnFh(x,vn)dx≤C+ϱr12r1|a(x)|22−r1,R3‖vn‖r1E,Ωn+V0ϱr1r12‖vn‖r1E,Ωn≤C, | (2.14) |
where C is independent of n. Similarly
Jh(vn)=12∫R3|(−Δ)s2vn|2dx+12∫R3˜V(x)v2ndx+14∫R3ϕtvnv2ndx−∫R3Fh(x,vn)dx≥12∫R3∖Ωn|(−Δ)s2vn|2dx+12∫R3∖Ωn˜V(x)v2ndx+14∫R3∖Ωnϕtvnv2ndx−∫ΩnFh(x,vn)dx. |
Therefore,
12∫R3∖Ωn|(−Δ)s2vn|2dx+12∫R3∖Ωn˜V(x)v2ndx+14∫R3∖Ωnϕtvnv2ndx≤Jh(vn)+∫ΩnFh(x,vn)dx≤C+ϱr12r1|a(x)|22−r1,R3‖vn‖r1E,Ωn+V0ϱr1r12‖vn‖r1E,Ωn≤C, | (2.15) |
where C is independent of n. Combining (2.14) with (2.15), we have
S2n:=12∫R3|(−Δ)s2vn|2dx+12∫R3˜V(x)v2ndx+14∫R3ϕtvnv2ndx |
is bounded independent of n. Hence, as in the proof of Lemma 3.1 in [12], we have
C‖vn‖≤12∫R3|(−Δ)s2vn|2dx+12∫R3˜V(x)v2ndx≤S2n≤C, |
which implies that {vn} is bounded in E. Going if necessary to a subsequence, we can assume vn⇀v in E. Since the embedding E↪Lp(R3) is compact, then vn→v in Lp(R3) for all 2≤p<2∗s and vn→v a.e. on R3.
By (f2) and Hölder's inequality, we have
|∫R3(fh(x,vn)−fh(x,v))(vn−v)dx|≤∫R3(|a(x)||vn|r1+V0|vn|+|a(x)||v|r1+V0|v|)|vn−v|dx≤C2(|a(x)|22−r1,R3‖vn‖r12,R3+V0‖vn‖2,R3+|a(x)|22−r1,R3‖v‖r12,R3+V0‖v‖2,R3)‖vn−v‖2,R3=on(1). | (2.16) |
On the other hand, by Lemma 2.4, we get that
∫R3(ϕtvnvn−ϕtvv)(vn−v)dx→0, asn→∞. | (2.17) |
Hence together with (2.16) and (2.17), we get
on(1)=⟨J′h(vn)−J′h(v),vn−v⟩=‖vn−v‖2+∫R3(ϕtvnvn−ϕtvv)(vn−v)dx−∫R3(fh(x,vn)−fh(x,v))(vn−v)dx≥C3‖vn−v‖2+on(1). |
This implies vn→v in E and this completes the proof.
Similar to the proof of Lemma 3.2 in [7] and Lemma 3.2 in [17], we can get the following lemma.
Lemma 2.6. For any k∈N, there exists a closed symmetric subsets Ak⊂E such that the genus γ(Ak)≥k and supv∈AkJ(v)<0.
Proof. Let En be any n-dimensional subspace of E. Since all norms are equivalent in a finite dimensional space, there is a constant β=β(En) such that
‖v‖≤β‖v‖2 |
for all v∈En, where ‖⋅‖2 is the usual norm of L2(R3).
Next, we claim that there exists a constant M>0 such that
12∫R3|v|2dx≥∫|v|>l|v|2dx | (2.18) |
for all v∈En and ‖v‖≤M. In fact, if (2.18) is false, then exists a sequence {vk}⊂En∖{0} such that vk→0 in E and
12∫R3|vk|2dx<∫|vk|>l|vk|2dx |
for all k∈N. Let uk=vk‖vk‖2,R3. Then
12<∫|vk|>l|uk|2dx, for allk∈N. | (2.19) |
On the other hand, we can assume that uk→u in E since En is finite dimensional. Hence uk→u in L2(R3). Moreover, it can be deduced from vk→0 in E that
meas{x∈R3:|vk|>l}→0, k→∞. |
Therefore,
∫|vk|>l|uk|2dx≤2∫R3|uk−u|2+∫|vk|>lu2dx→0, k→∞ |
which contradicts (2.19) and hence (2.18) holds. By (f1), we can choose a l small enough such that
f(x,v)≥18(12+14Stϱ4123+2t)βv2. |
for all x∈R3 and 0≤v≤2l. This inequality implies that
Fh(x,v)=F(x,v)≤4(12+14Stϱ4123+2t)βv2. | (2.20) |
The assumption (f3) implies Fh(x,v) is even in v. Thus, by (2.20), we have
Jh(v)=12∫Ω|(−Δ)s2v|2dx+12∫Ω˜V(x)v2dx+14∫Ωϕtvv2dx−∫ΩFh(x,v)dx≤12‖v‖2+14Stϱ4123+2t‖v‖4−∫|v|≤lFh(x,|v|)dx≤12‖v‖2+14Stϱ4123+2t‖v‖2−4(12+14Stϱ4123+2t)β2∫|v|≤l|v|2dx=(12+14Stϱ4123+2t)‖v‖2−4(12+14Stϱ4123+2t)β2(∫R3|v|2dx−∫|v|>l|v|2dx)≤−(12+14τ2∗τ4125)‖v‖2 |
for all v∈En with ‖v‖≤min{M,1}. Let 0<ρ≤min{M,1} and An={v∈En:‖v‖=ρ}. We conclude that γ(An)≥n and
supv∈AnJh(v)≤−(12+14Stϱ4123+2t)ρ2<0. |
This completes the proof.
Proof of Theorem 1.1. By (f1)-(f3), we know that Jh is even and Jh(0)=0. Furthermore, Lemmas 2.5 and 2.6 imply that Jh has a critical sequence {vn} such that Jh(vn)≤0 and vn→0 as n→∞. Thus, we get by Lemma 2.3 that problem (1.1) has infinitely many small solutions. This completes the proof.
We consider a class of fractional Schrödinger-Poisson systems with sign-changing potential. According to the assumptions, we construct an equivalent new system. By dual method and the critical point theorem, we proved the existence of infinitely many small solutions.
The authors sincerely thank the reviewers' important comments and suggestions. This work is supported by Hainan Natural Science Foundation (No.2019RC168), the National Natural Science Foundation of China (Grant No.11861028), the Advanced Talents Foundation of QAU (Grant No. 6631115047, 6631117028).
The authors declare that they have no conflict interests.
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