This paper is concerned with the following planar Schrödinger-Poisson equations
−Δu+V(x)u+(ln|⋅|∗|u|p)|u|p−2u=f(x,u),x∈R2,
where p≥2 is a constant, and V(x) and f(x,u) are continuous, mirror symmetric or rotationally periodic functions. The nonlinear term f(x,u) satisfies a certain monotonicity condition and has critical exponential growth in the Trudinger-Moser sense. We adopted a version of mountain pass theorem by constructing a Cerami sequence, which in turn leads to a ground state solution. Our method has two new insights. First, we observed that the integral ∫R2∫R2ln(|x−y|)|u(x)|p|u(y)|pdxdy is always negative if u belongs to a suitable space. Second, we built a new Moser type function to ensure the boundedness of the Cerami sequence, which further guarantees its compactness. In particular, by replacing the monotonicity condition with the Ambrosetti–Rabinowitz condition, our approach works also for the subcritical growth case.
Citation: Ganglong Zhou. Group invariant solutions for the planar Schrödinger-Poisson equations[J]. Electronic Research Archive, 2023, 31(11): 6763-6789. doi: 10.3934/era.2023341
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This paper is concerned with the following planar Schrödinger-Poisson equations
−Δu+V(x)u+(ln|⋅|∗|u|p)|u|p−2u=f(x,u),x∈R2,
where p≥2 is a constant, and V(x) and f(x,u) are continuous, mirror symmetric or rotationally periodic functions. The nonlinear term f(x,u) satisfies a certain monotonicity condition and has critical exponential growth in the Trudinger-Moser sense. We adopted a version of mountain pass theorem by constructing a Cerami sequence, which in turn leads to a ground state solution. Our method has two new insights. First, we observed that the integral ∫R2∫R2ln(|x−y|)|u(x)|p|u(y)|pdxdy is always negative if u belongs to a suitable space. Second, we built a new Moser type function to ensure the boundedness of the Cerami sequence, which further guarantees its compactness. In particular, by replacing the monotonicity condition with the Ambrosetti–Rabinowitz condition, our approach works also for the subcritical growth case.
The present paper is concerned with the existence of solution to the planar Schrödinger-Poisson equations
−Δu+V(x)u+(ln|⋅|∗|u|p)|u|p−2u=f(x,u),x∈R2, | (1.1) |
where p≥2, V,f are continuous, mirror symmetric or rotationally periodic functions, and f(x,t) has exponential critical growth in the Trudinger-Moser sense ([1]).
In last decades, considerable attention has been paid to the following Schrödinger-Poisson equations:
{−Δu+V(x)u+K(x)ϕ(x)|u|p−2u=f(x,u),x∈R3,−Δϕ=K(x)|u|p,x∈R3 | (1.2) |
with various conditions on the parameters p,N and functions V,K,f. These kinds of equations arise in many contexts of physics, such as, in quantum mechanics [2,3,4] and semiconductor theory[5,6,7,8]. In [5], Eq (1.2) was introduced as a model describing solitary waves for nonlinear stationary equations of Schrödinger type interacting with an electrostatic field where the unknown functions u and ϕ wave function for particles and potential, respectively. Let p∈(1,6] and K∈L∞(R3). For each u∈H1(R3), the second equation in (1.2) determines the Newton potential ϕu in D1,2(R3), i.e.,
ϕu(x):=14π∫R3K(y)|u(y)|p|x−y|dy. |
Many minimization techniques, such as minimizing on a constraint set [9,10] and the Mountain Pass Theorem [11,12,13,14,15], were used in the Eq (1.2).
When K(x)≡0, Eq (1.2) becomes the Schrödinger equation. In this case, there are many results to Eq (1.2) with the dual method if V and f satisfy some certain conditions, such as a positive lower bound on V or a monotonicity condition on f (see [16,17,18,19,20] and references therein).
In the following, let us focus on the two-dimensional case. Stubbe [21] considered the equations
{−Δu+λu+ϕ(x)u=0,x∈R2,Δϕ=u2,x∈R2, | (1.3) |
where λ∈R is a constant. They set up a variational framework for Eq (1.3) with a subspace Z of H1(R2):
Z:={u∈H1(R2):∫R2ln(1+|x|)u2dx<∞}. |
They proved that there exists a unique radial ground state solution for any λ≥0. In addition, they proved that there exists a negative number λ∗, such that for any λ∈(λ∗,0) there are two radial ground states with different L2 norms. Cigolani and Weth [22] considered Eq (1.1) with p=2 and f(x,u)=b|u|σ−2u. Specifically, V∈C(R2,(0,∞)) is Z2 periodic. Using the concentration-compactness theory, they proved that Eq (1.1) has a ground state u∈X2 and a solution sequence {un}n⊂X2, such that limn→∞J(un)=∞. Here,
X2:={u∈H1(R2):∫R2[|∇u|2+V(x)u2+ln(1+|x|)u2]dx<∞} |
and J are the energy functionals associated with Eq (1.1).
Chen and Tang [23] considered Eq (1.1) with p=2, i.e.,
{−Δu+V(x)u+ϕ(x)u=f(x,u),x∈R2,Δϕ=u2,x∈R2, | (1.4) |
where V∈C(R2,[0,∞)) is axially symmetrical and f∈C(R2×R) is of subcritical or critical exponential growth in the sense of Trudinger-Moser. More precisely, we say that f(x,t) has subcritical exponential growth at t=±∞ if it verifies
(F1') For every A>0,
supx∈R2,|s|≤A|f(x,s)|<+∞ | (1.5) |
and
lim|t|→∞|f(x,t)|eαt2=0,uniformly inR2, | (1.6) |
for any α>0;
and the function f(x,t) is said to have the critical exponential growth at t=±∞ if it verifies
(F1) The nonlinearity f satisfies (1.5) and there exists α0>0 such that, for any α>α0, (1.6) holds but
lim|t|→∞|f(x,t)|eαt2=+∞,uniformly inR2for allα<α0. |
This notion of criticality can be referred to [24].
For the critical growth case, Chen and Tang [23] established the existence of a ground state solution for Eq (1.4) by assuming following conditions on V and f:
(V0) V∈C(R,[0,∞)) and lim inf|x|→∞V(x)>0;
(CF1) V(x):=V(x1,x2)=V(|x1|,|x2|) for all x∈R2, f(x,t):=f(x1,x2,t)=f(|x1|,|x2|,t) for all (x,t)∈R2×R;
(CF2) f(x,t)t>0 for all (x,t)∈R2×R∖{0}, and there exists M0>0 and t0>0 such that
F(x,t)≤M0|f(x,t)|,∀x∈R2,|t|≥t0, |
where F(x,t):=∫t0f(x,s)ds;
(CF3) lim inf|t|→∞t2F(x,t)eα0t2>2α20ρ2 uniformly on x∈R2, where ρ∈(0,1/2) satisfying ρ2max|x|≤ρV(x)≤1;
(CF4) f(x,t)−V(x)t|t|3 is non-decreasing on t∈R∖{0}.
Recently, Cao et al. [25] considered the equations
−Δu+V(x)u+(ln|⋅|∗|u|p)|u|p−2u=b|u|σ−2u,x∈R2, | (1.7) |
where σ≥2p,b≥0 and V∈C(R2,(0,∞)) are Z2 periodic. With a similar method in [22], they obtained the existence of a positive ground state solution of Eq (1.7) in Xp, where
Xp:={u∈H1(R2):∫R2[|∇u|2+V(x)u2+ln(1+|x|)|u|p]dx<∞}. |
Here, we will prove the existence of a nontrivial solution to Eq (1.1), not only for all p≥2, but also for general nonlinearities f and potentials V.
To describe our main results, we introduce the following notations: Let us view R2 as C, let k∈N,k≥2 and we say that v∈Pk if v(ze2πi/k)=v(z) over C. We define
Ek,p:=Xp∩Pk,Vk,1:=C(C)∩Pk |
Fk,1:={f∈C(C×R):f(⋅,t)∈Pk,∀t∈R}. |
We say that v is mirror symmetric denoted by v∈M if v(¯z)=v(z) in C. Let
Tk,p:=Ek,p∩M,Vk,2:=Vk,1∩M, |
Fk,2:={f∈Fk,1:f(⋅,t)∈M,∀t∈R}. |
Finally, we write the associated functional of Eq (1.1) in the following form
Φ(u)=12‖u‖2+14pπ∫R2∫R2ln(|x−y|)|u(x)|p|u(y)|pdxdy−∫R2F(x,u)dx, | (1.8) |
and the associated Nehari manifold of the functional (1.8) is
N1:={u∈Ek,p∖{0}:⟨Φ′(u),u⟩=0},N2:={u∈Tk,p∖{0}:⟨Φ′(u),u⟩=0}. | (1.9) |
Our main result is stated as follows.
Theorem 1.1. Let p≥2, V and f satisfy (V0),(F1) and the following conditions
(VF)V∈Vk,1andf∈Fk,1 with k≥4 or V∈Vk,2andf∈Fk,2 with k≥2;
(F2)f(x,t)t≥0 for all (x,t)∈R2×R∖{0}, and there exists M0>0 and t0>0 such that F(x,t)≤M0|f(x,t)| for x∈R2, |t|≥t0;
(F3) There exists q∈R such that lim inf|t|→∞|t|qF(x,t)eα0t2=+∞;
(F4)gp(x,t) is non-decreasing on t∈(−∞,0) and t∈(0,∞), where
gp(x,t):={f(x,t)−V(x)t|t|2p−1,p=2,f(x,t)−μV(x)t|t|2p−1,p>2 |
for some μ<1.
(F5) If p=2, f(x,t)=o(t) as t→0 uniformly on R2; and if p>2, f(x,t)=O(ts0) with s0>1 as t→0 uniformly on R2.
Then, Eq (1.1) has a nontrivial solution ˉu. Moreover, if V∈Vk,1 and f∈Fk,1, then ˉu∈Ek,p satisfies
Φ(ˉu)=minN1Φ; |
if V∈Vk,2 and f∈Fk,2, then ˉu∈Tk,p satisfies
Φ(ˉu)=minN2Φ. |
Remark 1.2. Comparing to [23, Theorem 4], we have weakened the assumptions (CF1)–(CF3) to (VF) and (F2)–(F3), respectively. More precisely,
● (CF1) means V∈V2,2 and f∈F2,2, hence, it is a special case of (VF);
● The condition (F3) is less restrictive than (CF3) for the behavior of f at infinity;
● (F2) improves slightly (CF2) where f(x,t)t>0 is replaced by f(x,t)t≥0;
Here is an example of f, which satisfies (VF) and (F1)–(F5), but not (CF3). Let θ>0,p0≥p,q0>2 and
f0(x,t)={θeα0t2(2α0t2−q0)tq0+1,t≥√p0+q0α0,θep0+q0(2p0+q0)αp0+q0/20(p0+q0)p0+q0/2t2p0−1,0≤t<√p0+q0α0 |
with odd extension to t<0. Finally, it seems that [23] used implicitly f(t)=o(t) as t→0 with p=2 in (F5) (see the proof of Lemma 2.6 there).
Our approach works also for the subcritical case.
Theorem 1.3. Let p≥2, V and f satisfy (V0), (VF), (F1'), (F5) and the following condition:
(F4') f(x,t)t>0 for all (x,t)∈R2×(R∖{0}) and there exists ν∈(2,∞),t1∈(0,∞) such that
f(x,t)t≥νF(x,t),∀x∈R2,|t|≥t1; |
Furthermore, if p>2, we assume that
Mt1<(12−1μ)γ2, |
where
Mt1=sup(x,t)∈R2×[−t1,t1]∖{0}F(x,t)t2andγ=infu∈Xp‖u‖‖u‖H1(R2)>0. |
Then, Eq (1.1) has a nontrivial solution ˉu. Moreover, ˉu∈Ek,p if V∈Vk,1 and f∈Fk,1, and ˉu∈Tk,p if V∈Vk,2 and f∈Fk,2.
This paper is organized as follows: In Section 2, we present some basic results; in particular we show that the energy functional corresponding to the nonlocal term is non positive, which is our key observation and different from the available results, see Lemma 2.3. In Section 3, we prove a mountain pass type theorem using a new test function, see Lemma 3.2 below. In Sections 4 and 5, we give the proof of Theorems 1.1 and 1.3, respectively.
In this section, we will give some preliminary definitions and basic facts about inequalities, such as the Moser-Trudinger inequality, the energy estimate of the nonlocal term. In the following, the letter C denotes generic positive constants and ‖⋅‖q denotes the standard norm in Lq(R2).
The function space Xp is a Banach space equipped with the norm
‖u‖Xp:=‖u‖+‖u‖∗, | (2.1) |
where
‖u‖∗:=(∫R2ln(1+|x|)|u|pdx)1p; | (2.2) |
while
‖u‖:=(∫R2[|∇u|2+V(x)u2]dx)12 | (2.3) |
is induced by the scalar product
⟨u,v⟩:=∫R2(∇u⋅∇v+V(x)uv)dx. | (2.4) |
We will use the following bilinear functionals (see [21]):
A1(u,v):=∫R2∫R2ln(1+|x−y|)u(x)v(y)dxdy; | (2.5) |
A2(u,v):=∫R2∫R2ln(1+1|x−y|)u(x)v(y)dxdy; | (2.6) |
A0(u,v):=A1(u,v)−A2(u,v)=∫R2∫R2ln(|x−y|)u(x)v(y)dxdy. | (2.7) |
By the Hardy-Littlewood-Sobolev inequality (see [26]), there exists C>0 such that for any u,v∈L4/3(R2),
|A2(u,v)|≤∫R2∫R21|x−y|u(x)v(y)dxdy≤C‖u‖43‖v‖43. | (2.8) |
Corresponding to (2.5)–(2.7), we define
Ii(u):=Ai(|u|p,|u|p),i=0,1,2. | (2.9) |
The following bound for I2(u) is a direct consequence of (2.8):
|I2(u)|≤C‖u‖2p4p3,∀u∈L4p3(R2),∀p≥1. | (2.10) |
We can rewrite the associated functional of Eq (1.1) in the following form
Φ(u)=12‖u‖2+14pπI0(u)−∫R2F(x,u)dx. | (2.11) |
Next, we state several lemmas.
Lemma 2.1. (i) Let u∈H1(R2), then for any α>0,
∫R2(eαu2−1)dx<∞. |
(ii) Given M>0, α∈(0,4π), there exists a constant C(M,α) such that for all u∈H1(R2) satisfying ‖∇u‖2≤1, ‖u‖2≤M, there holds
∫R2(eαu2−1)dx<C(M,α). |
The statements (i) and (ii) of the above lemma were first established by [27, Lemma 1] and [1, Lemma 2.1], respectively (see also [28,29]).
Lemma 2.2. Assume that V and f satisfy (V0),(F1)(or (F1′)),(F5). Then, Ii,Φ∈C1(Xp,R) and
⟨I′i(u),v⟩=2pAi(|u|p,|u|p−2uv),i=1,2⟨Φ′(u),v⟩=⟨u,v⟩+12πA0(|u|p,|u|p−2uv)−∫R2f(x,u)vdx. | (2.12) |
For the sake of completeness, we present a proof of Lemma 2.2 in the appendix. The following lemma is our first key observation.
Lemma 2.3. For any u∈Xp, we have I0(u)≤0.
Proof. First, let u∈C∞0(R2) with supp(u)⊂B12(0). Then
I0(u)=∫B12(0)∫B12(0)ln(|x−y|)|u(x)|p|u(y)|pdxdy≤0. |
Consider now u∈C∞0(R2,R). Take R>0 such that supp(u)⊂BR(0) and let w(x)=u(2Rx), so supp(w)⊂B12(0) and ϕw(x):=14R2ϕu(2Rx). Hence,
12πI0(u)=∫BR(0)∫BR(0)ln(|x−y|)|u(x)|p|u(y)|pdxdy=16R4∫B12(0)∫B12(0)ln(|x−y|)|w(x)|p|w(y)|pdxdy≤0. |
We conclude by the density argument. For any R>0, let φR(r) be a C∞0 cut-off function such that 0≤φ≤1, φR≡1 on [0,R] and φR≡0 on [R+1,∞). Let η be the standard mollifier and ηδ(x):=1δ2η(xδ), where δ>0. Given ϵ>0, since √Vu∈L2(R2),[ln(1+|⋅|)]1/pu∈Lp(R2), [30, Pages 264 and 714], we can choose δ small enough such that
‖φ1δ(|⋅|)u−u‖Xp<ϵ,‖ηδ∗[φ1δ(|⋅|)u]−φ1δ(|⋅|)u‖Xp<ϵ. |
Therefore, for any u∈Xp, there exists {un}n⊂C∞0(R2) such that limn→∞‖un−u‖Xp=0. By the fact I0=I1−I2 and Lemma 2.2, we conclude that I0(u)≤0.
Corollary 2.4. Assume that V and f satisfy (V0) and (F1)(or (F4′)). Then
limt→∞Φ(tω)=−∞,∀ω∈Xp∖{0}. |
Proof. For any ω∈Xp∖{0}, there exists δ>0 such that m{|ω(x)|≥δ}>0. For a critical case, by Lemma 2.3 and (F1), one has
Φ(tω)=t22‖ω‖2+t44pπI0(ω)−∫R2F(x,tω)dx≤t22‖ω‖2−C∫{|ω(x)|≥δ}eα0δ2t2/2dx→−∞,ast→∞. |
For a subcritical case, we choose large enough R>0 such that m(G)>0, where
G:={|ω(x)|≥δ}∩BR(0). |
By (F4') and choosing M:=‖ω‖2m(G)>0, there exists tM>0 such that
|F(x,tw)|≥Mt2,∀x∈G,|t|≥tM, |
which together with Lemma 2.3 implies
Φ(tω)=t22‖ω‖2+t44pπI0(ω)−∫R2F(x,tω)dx≤t22‖ω‖2−t2Mm(G)=−t22‖ω‖2→−∞ |
as t→∞, and we complete the proof.
The following lemma is inspired by [31, Lemma 2.2].
Lemma 2.5. Assume that V and f satisfy (V0) and (VF). Then there exists Ck>0 such that
A1(|u|p,|v|p)≥Ck‖u‖p∗‖v‖pp,∀u,v∈Ek,p. | (2.13) |
In particular, since Tk,p⊂Ek,p, (2.13) holds for u,v∈Tk,p.
Proof. Let Ω1:={(x1,x2)∈R2:xi≥0}, Ω2=−Ω1. For any x∈Ω1 and y∈Ω2, one has
|x−y|2=|x|2+|y|2−2x⋅y≥|x|2+|y|2. |
Then, it follows from the definition of Ek,p and k≥4 that
A1(|u|p,|v|p)=∫R2∫R2ln(1+|x−y|)|u(x)|p|v(y)|pdxdy≥∫Ω2|v(y)|pdy∫Ω1ln(1+|x−y|)|u(x)|pdx≥∫Ω2|v(y)|pdy∫Ω1ln(1+|x|)|u(x)|pdx≥1k2∫R2|v(y)|pdy∫R2ln(1+|x|)|u(x)|pdx≥Ck‖u‖p∗‖v‖pp,∀u,v∈Ek,p, |
so we obtain (2.13).
In this section, we will quote a version of Mountain Pass Theorem and prepare the proof of Theorems 1.1 and 1.3.
Lemma 3.1. Let Y be a real Banach space and I∈C1(Y,R). Let S be a closed subset of Y, which disconnects Y into distinct connected Y1 and Y2. Suppose further that I(0)=0 and
(i) 0∈Y1, and there exists α>0 such that I|S≥α,
(ii) There is e∈Y2 such that I(e)≤0.
Then, I possesses a Cerami sequence with c≥α>0 given by
c=infγ∈Γmaxt∈[0,1]I(γ(t)), |
where
Γ={γ∈C([0,1],X):γ(0)=0,γ(1)=e}, |
and a Cerami sequence means a sequence {un}⊂X such that
I(un)→c,‖I′(un)‖Y′(1+‖un‖Y)→0. |
The proof of the above lemma can be found in [32, Theorem 3]. We state another result that serves as a bridge between the mountain pass structure (see Lemma 3.3) and Theorem 1.1.
Lemma 3.2. Assume that V and f satisfy (V0), (F1) and (F3)–(F5). Then there exists n0∈N such that
maxt≥0Φ(tωn0)<2πα0, | (3.1) |
where
ωn(x)={√lnn√2π−qln(lnn)2√2πlnn,0≤|x|≤(lnn)q/2/n;ln(1/|x|)√2πlnn,(lnn)q/2/n≤|x|≤1;0,|x|≥1. |
Proof. Without loss of generality, we can fix q≥2. Direct computation yields
‖ωn‖2≤∫B1|∇ωn|2dx+V1∫B1ω2ndx=1−qln(lnn)2lnn+δn, | (3.2) |
where δn=O(1lnn) as n→∞. By (F3), there exists t0>0 such that
|t|qF(x,t)eα0t2≥1,∀|t|≥t0. | (3.3) |
There are three cases for the value of t.
Case (i): 0≤t≤√3πα0. For large n, then it follows from (3.2) and Lemma 2.3 that
Φ(tωn)=t22‖ωn‖2+t2p2pI0(ωn)−∫R2F(x,tωn)dx≤1+δn2t2≤7π4α0. | (3.4) |
Case (ii): √3πα0≤t≤√8πα0. For large n, we have tωn(x)≥t0 for x∈B(lnn)q/2/n. Then it follows from (3.2), (3.3) and Lemma 2.3 that
Φ(tωn)=t22‖ωn‖2+t2p2pI0(ωn)−∫R2F(x,tωn)dx≤1+δn2t2−qln(lnn)4lnnt2−2q/2π1+q/2(lnn)qn2tqTq/2neα02πt2Tn≤1+δn2t2−qln(lnn)4lnnt2−αq/20π(lnn)q2qn2Tq/2neα02πt2Tn=:φn(t), | (3.5) |
where
Tn:=lnn−qln(lnn)+q2ln2(lnn)4lnn. |
Let tn>0 be the unique maximum of φn in R+, then (as n→∞)
t2n=4πα0[1+(q−1)ln(lnn)2lnn+O(1lnn)] | (3.6) |
and
φn(t)≤φn(tn)=1+δn2t2n−qln(lnn)4lnnt2n+O(1lnn). | (3.7) |
Combining (3.5)–(3.7), one has
Φ(tωn)≤φn(tn)=2πα0−ln(lnn)2lnn+O(1lnn). | (3.8) |
Case (iii): t≥√8πα0. As in the above case (ii), we have
Φ(tωn)≤1+δn2t2−2q/2π1+q/2(lnn)qn2tqTq/2neα02πt2Tn≤1+δn2t2−2q/2π1+q/2(lnn)qtqTq/2nexp[2(α04πt2−1)Tn]≤4π(1+δn)α0−αq/20π(lnn)q/22qn2≤0 | (3.9) |
for large n. To get the third inequality, we used the fact that the function
1+δn2t2−2q/2π1+q/2(lnn)qtqTq/2nexp[2(α04πt2−1)Tn] |
is decreasing on t≥√8πα0 when n is large enough. Combining the conclusions for cases (i)–(iii), the proof is completed.
Now we show the existence of the Cerami sequence.
Lemma 3.3. Assume that V and f satisfy (V0), (VF), (F1)(or (F1′) and (F4′)) and (F5). Then there exists a constant ˜c∈(0,supt≥0Φ(tωn0)] and a Cerami sequence {un}⊂Ek,p such that
Φ(un)→˜c,‖Φ′(un)‖X′p(1+‖un‖Xp)→0. | (3.10) |
Proof. Applying the Sobolev embedding theorem for given s∈[2,∞), there exists γs>0 such that
‖u‖s≤γs‖u‖,∀u∈Xp. | (3.11) |
By (F1) (or (F1')) and (F5) for any ϵ>0, there exists some constant Cϵ>0 such that
|F(x,t)|≤ϵt2+Cϵ(e3α0t2/2−1)|t|3,∀(x,t)∈R2×R. | (3.12) |
On the other hand, in view of Lemma 2.1, one has
∫R2(e3α0u2−1)dx≤C,∀‖u‖≤√πα0. | (3.13) |
Let ϵ=14γ22 from (3.11)–(3.13), and there holds
∫R2F(x,u)dx≤14‖u‖2+C3‖u‖3,∀‖u‖≤√πα0. | (3.14) |
Hence, it follows from (2.11) and (3.14) that if ‖u‖≤√πα0,
Φ(u)=12‖u‖2+14pπ(I1(u)−I2(u))−∫R2F(x,u)dx≥14‖u‖2−C3‖u‖3−C4‖u‖2p. | (3.15) |
Therefore, there exists κ0>0 and 0<ρ<√πα0 such that
Φ(u)≥κ0,∀u∈S:={u∈Ek,p:‖u‖=ρ}. | (3.16) |
By (V0), (F1) (or (F4')) and Corollary 2.4, we have limt→∞Φ(tωn0)=−∞, and then we can choose t∗>0 such that e=t∗ωn0∈Y2:={u∈Ek,p:‖u‖>ρ} and Φ(e)<0. Let Y1:={u∈Ek,p:‖u‖≤ρ}, then in view of Lemma 3.1, one deduces that there exists ˜c∈[κ0,supt≥0Φ(tωn0)] and a Cerami sequence {un}⊂Ek,p satisfying (3.10).
The proof of Theorem 1.1 is based on the following lemmas. As in Lemma 2.5, we only consider the Ek,p case.
Lemma 4.1. Assume that V and f satisfy (V0),(VF),(F1),(F4) and (F5), then we have
(i) Let m1:=infN1Φ(u), then there exists a constant c∗∈(0,m1] and a sequence {un}⊂Ek,p satisfying
Φ(un)→c∗,‖Φ′(un)‖X′p(1+‖un‖Xp)→0. | (4.1) |
(ii) For any u∈Ek,p∖{0}, there exists a unique tu>0 such that tuu∈N1. Moreover, we have
m1=infEk,p∖{0}maxt≥0Φ(tu). |
Proof. We will prove that
Φ(u)=maxt≥0Φ(tu),∀u∈N1 | (4.2) |
and then we can get the statement (i). Indeed, if (4.2) holds the same as [33, Lemma 3.2], we can choose vk∈N1 such that
m1≤Φ(vk)≤m1+1k,k∈N. |
For any vk, similarly to Lemma 3.3, we can obtain a Cerami sequence {uk,n}n⊂Ek,p such that
Φ(uk,n)→ck,‖Φ′(uk,n)‖X′p(1+‖un‖Xp)→0,∀k∈N |
with ck∈(0,supt≥0Φ(tvk)]. By (4.2) and the diagonal rule, we can verify (4.1), and now we prove (4.2). By (2.11) and (2.12), one has
Φ(u)−Φ(tu)=1−t22‖u‖2+1−t2p4pπI0(u)+∫R2[F(x,tu)−F(x,u)]dx=1−t2p2p⟨Φ′(u),u⟩+t2p−pt2+p−12p‖u‖2+∫R2[1−t2p2pf(x,u)u+F(x,tu)−F(x,u)]dx=1−t2p2p⟨Φ′(u),u⟩+t2p−pt2+p−12p‖u‖2+∫R2∫1t[f(x,u)−V(x)u|u|2p−1−f(x,su)−V(x)su|su|2p−1]s2p−1|u|2p−1udsdx≥1−t2p2p⟨Φ′(u),u⟩+t2p−pt2+p−12p‖u‖2. | (4.3) |
According to the fact u∈N1 and mint≥0(t2p−pt2+p−1) attained at t=1, then (4.2) holds.
Next, we consider statement (ii). Let u∈Ek,p∖{0} be fixed and ζ(t):=Φ(tu) on [0,∞). By the definition (2.11),
ζ′(t)=0⟺t2‖u‖2+t2p2πI0(u)−∫R2f(x,tu)tudx=0⟺tu∈N1. |
Using (3.15), (F1) and Lemma 2.3, one has ζ(0)=0, ζ(t)>0 for t>0 small and ζ(t)<0 for t large. Therefore maxt∈(0,∞)ζ(t) is achieved at some tu>0 so that ζ′(tu)=0 and tuu∈N1. Now, we claim that tu is unique. In fact, for any given u∈Ek,p∖{0}, let t1,t2>0 such that ζ′(t1)=ζ′(t2)=0. By (4.3), taking t=t2t1 and t=t1t2 respectively, it implies
Φ(t1u)≥Φ(t2u)+t21g(t2/t1)2p‖u‖2andΦ(t2u)≥Φ(t1u)+t22g(t1/t2)2p‖u‖2, |
where g(t):=t2p−pt2+p−1. Therefore, we must have t1=t2, since g(s)>0 for any s>0, s≠1.
Lemma 4.2. Assume that V and f satisfy (V0),(VF),(F1),(F4) and (F5). Then any sequence satisfying (4.1) is bounded w.r.t. ‖⋅‖.
Proof. We only consider the case p>2. The case p=2 is obtained by [23, Lemma 2.11]. First, we prove that
12pf(x,t)t−F(x,t)≥μ(1−p)2pV(x)t2,∀t∈R. | (4.4) |
Indeed, by (F4), there holds
F(x,t)−μ2V(x)t2=∫t0[f(x,τ)−μV(x)τ]dτ≤∫t0f(x,t)−μV(x)t|t|2p−1|τ|2p−2τdτ=f(x,t)t−μV(x)t22p. |
By (4.4), one has
c∗+o(1)=Φ(un)−12p⟨Φ′(un),un⟩=(12−12p)‖un‖2+∫R2(12pf(x,un)un−F(x,un))dx≥(12−12p)‖un‖2−(12−12p)μ∫R2V(x)u2ndx≥(p−1)(1−μ)2p‖un‖2. | (4.5) |
Here, we also used (2.11), (2.12) and (4.1). Therefore, we complete the proof.
Proof of Theorem 1.1 completed. Applying Lemmas 4.1 and 4.2, we deduce that there exists a sequence {un}⊂Ek,p satisfying (4.1) and ‖un‖≤C<∞. Now, we prove
∫R2f(x,un)undx≤C. | (4.6) |
Indeed, let p≥2, and by (2.11), (2.12) and (4.1) there holds
c∗+o(1)=Φ(un)−p+μ(1−p)2p⟨Φ′(un),un⟩≥(p−1)μ2p‖un‖2−(p−1)μ2p∫R2V(x)u2ndx+(1−p)(1−μ)4pπI0(un)+(p−1)(1−μ)2p∫R2f(x,un)undx≥(p−1)(1−μ)2p∫R2f(x,un)undx, |
hence (4.6) holds true. Next, we complete the proof of Theorem 1.1 in three steps.
Step 1: {un} is bounded in Ek,p.
We first prove that δ0:=lim supn→∞‖un‖p>0. Suppose the contrary δ0=0, then from the Gagliardo-Nirenberg inequality (see [34, Page 125]):
‖un‖ss≤Cs‖un‖θp‖∇un‖1−θ2, | (4.7) |
where 2≤p<t<∞,θ=pt. Hence, un→0 in Lη(R2) for η∈(2,+∞). Given any ε∈(0,M0C10/t2), we choose Mε>M0C10/ε, then it follows from (F2) and (4.6) that
∫|un|≥MεF(x,un)dx≤M0∫|un|≥Mε|f(x,un)|dx≤M0Mε∫|un|≥Mεf(x,un)undx<ε. | (4.8) |
Applying (F5), one has
∫|un|≤MεF(x,un)dx≤{Cε‖un‖22=o(1),p=2,Cε‖un‖s+1s+1=o(1),p>2 | (4.9) |
and
∫|un|≤1f(x,un)undx≤{C‖un‖22=o(1),p=2,C‖un‖s+1s+1=o(1),p>2. | (4.10) |
By the arbitrariness of ε>0, we deduce from (F2), (4.8) and (4.9) that
∫R2F(x,un)dx=o(1). | (4.11) |
Hence, by (2.10) we have
0≤I2(un)≤C‖un‖2p4p3=o(1). | (4.12) |
By Lemmas 3.2 and 3.3, we know that ˉε:=13(1−α0˜c2π)>0, which together with (2.11), (3.10), (4.11), (4.12) and the fact I1(un)≥0 implies
‖un‖2=2˜c−12pπI1(un)+12pπI2(un)+o(1)≤2˜c+o(1)=4πα0(1−3ˉε)+o(1). | (4.13) |
Now, let d∈(1,pp−1) satisfy
(1+ˉε)(1−3ˉε)d1−ˉε<1. | (4.14) |
By (F1), there exists C>0 such that
|f(x,t)|d≤C[eα0(1+ˉε)dt2−1],∀x∈R2,|t|≥1. | (4.15) |
It follows from (4.13)–(4.15) and Lemma 2.1 that
∫|un|≥1|f(x,un)|ddx≤C∫R2[eα0(1+ˉε)du2n−1]dx=C∫R2[eα0(1+ˉε)d‖un‖2(un/‖un‖)2−1]dx≤C. | (4.16) |
As d′=dd−1>p, using (4.16) there holds
∫|un|≥1f(x,un)undx≤[∫|un|≥1|f(x,un)|qdx]1/d‖un‖d′=o(1). | (4.17) |
Combining (2.10)–(2.12), (3.10), (4.10) and (4.17), we arrive at
˜c+o(1)=Φ(un)−12⟨Φ′(un),un⟩=−(14π−14pπ)I1(un)+(14π−14pπ)I2(un)+∫R2[12f(x,un)un−F(x,un)]dx≤o(1). | (4.18) |
This contradiction shows that δ0>0. Now, from (2.10), (4.5) and Lemma 2.3, one has
I1(un)≤I2(un)≤C, |
which, together with Lemma 2.5, implies that ‖un‖∗ is bounded and {un} is bounded in Ek,p.
Step 2: Φ′(ˉu)=0 in E′k,p and Φ(ˉu)=m1.
We can assume by [25, Lemma 2.3] and passing to a subsequence again if necessary, that un⇀ˉu in Ek,p, un→ˉu a.e. on R2 and
un→ˉuinLs(R2), |
where s∈[2,∞) if p=2 and s∈(2,∞) if p>2. First, we need prove that
limn→∞∫R2F(x,un)dx=∫R2F(x,ˉu)dxandlimn→∞∫R2f(x,un)ˉudx=∫R2f(x,ˉu)ˉudx. | (4.19) |
Since (4.6) and the condition (F1), (F2) and (F5) hold the same as [23, Assertions 2 and 3], (4.19) still holds. Next, we prove that
limn→∞I2(un)=I2(ˉu). | (4.20) |
Indeed, noting that un→ˉu in L4p3(R2) by [35, Lemma A.1], there exists w0∈L4p3(R2) such that
|un(x)|≤w0(x)and|ˉu(x)|≤w0(x), |
a.e., for a subsequence if necessary, which together with the Lebesgue dominated convergence theorem and Hardy-Littlewood-Sobolev inequality implies
|I2(un)−I2(ˉu)|≤|A2(|un|p,|un|p−|ˉu|p)|+|A2(|un|p−|ˉu|p,|ˉu|p)|=o(1) | (4.21) |
as n→∞ and (4.20) is proved. Now, we claim that
Φ(ˉu)=m1,⟨Φ′(ˉu),ˉu⟩⟨X′p,Xp⟩=0. | (4.22) |
Indeed, similar as (4.20), we also have
A2(|un|p,|un|punˉu)−A2(|ˉu|p,|ˉu|p)=o(1). | (4.23) |
By [25, Lemma 3.3], one has
A1(|un|p,|un|p−2ˉu(un−ˉu))=o(1), |
which together with (3.10), (4.19) and Fatou's Lemma implies
o(1)=⟨Φ′(un),ˉu⟩⟨X′p,Xp⟩=⟨un,ˉu⟩+12πA1(|un|p,|un|p−2unˉu)−12πA2(|un|p,|un|p−2ˉu2)−∫R2f(x,un)ˉudx+o(1)≥⟨Φ′(ˉu),ˉu⟩⟨X′p,Xp⟩+o(1). | (4.24) |
Hence, we can obtain
⟨Φ′(ˉu),ˉu⟩⟨X′p,Xp⟩≤0. | (4.25) |
Since ˉu≠0, by Lemma 4.1 there exists ˉt∈(0,1] such that ˉtˉu∈N1. By (3.10), (4.4) and (4.25), the weak lower semi-continuity of norm, Lemma 4.1, the condition (F4) and Fatou's Lemma, we have
m1≥c∗=limn→∞[Φ(un)−12p⟨Φ′(un),un⟩⟨X′p,Xp⟩]=limn→∞{(12−12p)‖∇un‖22+∫R2[12pf(x,un)un−F(x,un)+p−12pV(x)u2n]dx}≥(12−12p)‖∇ˉu‖22+∫R2[12pf(x,ˉu)ˉu−F(x,ˉu)+p−12pV(x)ˉu2]dx=Φ(ˉu)−12p⟨Φ′(ˉu),ˉu⟩⟨X′p,Xp⟩≥Φ(ˉtˉu)−ˉt2p2p⟨Φ′(ˉu),ˉu⟩⟨X′p,Xp⟩≥m1−ˉt2p2p⟨Φ′(ˉu),ˉu⟩⟨X′p,Xp⟩≥m1, | (4.26) |
which implies (4.22) and
limn→∞Φ(un)=m1. | (4.27) |
By (4.19), (4.20), (4.22) and (4.27) and the weak lower semi-continuity of norm and Fatou's Lemma, one has
o(1)=Φ(un)−Φ(ˉu)=‖un‖2−‖ˉu‖2+14pπ[I1(un)−I1(ˉu)]+o(1), | (4.28) |
which implies
limn→∞‖un−ˉu‖=0andlimn→∞I1(un)=I1(ˉu). | (4.29) |
Hereafter, we claim that
A1(|un|p,|vn|p)→0,asn→∞, | (4.30) |
where |vn|p:=|un|p−2|un−ˉu|2. Indeed, we have
A1(|un|p,|vn|p)=I1(un)−2A1(|un|p,|un|p−2(un−ˉu)ˉu)−A1(|un|p,|un|p−2ˉu2). |
Then, we estimate
|A1(|un|p,|un|p−2(un−ˉu)ˉu)|≤‖un‖pp∫R2|un|p−2|un−ˉu||ˉu|dx+‖un‖p∗‖un‖p−2p‖un−ˉu‖p‖ˉu‖p≤‖un‖pp∫R2|un|p−2|un−ˉu||ˉu|ln(1+|x|)dx+on(1). | (4.31) |
For any ϵ>0, there exists Rϵ>0 such that
h(Rϵ):=(∫R2∖BRϵ(0)|ˉu|pln(1+|x|)dx)1/p<ϵ. |
Now, we split
∫R2|un|p−2|un−ˉu||ˉu|ln(1+|x|)dx=dn(Rϵ)+en(Rϵ), |
where
dn(Rϵ):=∫BRϵ(0)|un|p−2|un−ˉu||ˉu|ln(1+|x|)dx≤Rϵ‖un‖p−2p‖un−ˉu‖p‖ˉu‖p≤ϵ |
for large enough n and
en(Rϵ):=∫R2∖BRϵ(0)|un|p−2|un−ˉu||ˉu|ln(1+|x|)dx≤‖un−u‖∗‖un‖p−2∗(∫R2∖BRϵ(0)|ˉu|pln(1+|x|)dx)1/p≤Ch(Rϵ)≤Cϵ, |
which together with (4.31) implies
limn→∞A1(|un|p,|un|p−2(un−ˉu)u)=0. |
Hence, by Fatou's Lemma, we have
lim supn→∞A1(|un|p,|vn|p)≤lim supn→∞I1(un)−lim infn→∞A1(|un|p,|un|p−2ˉu2)≤lim supn→∞I1(un)−I1(ˉu). |
Since I1(un)→I1(ˉu) and A1(|un|p,|vn|p)≥0, we conclude with (4.30). Finally, by [25, Lemma 3.2] we obtain ‖un−ˉu‖∗→0, which together with (4.27) and (4.29) implies
limn→∞‖un−ˉu‖Xp=0andΦ(ˉu)=m1. |
Step 3: Φ′(ˉu)=0 in X′p.
By using the group action on the space Xp, we will conclude Φ′(ˉu)=0. Let G⊂O(2) be a finite group of transforms acting on Xp, where O(2) denotes the group of orthogonal transformations in R2. The action of G on the space Xp is a continuous map (see [35, Definition 1.27]):
G×Xp→Xp:[τ,u]→τ(u)=u∘τ. |
Assume that φ∈C1(Xp,R) is invariant by G; that is, φ(w∘τ)=φ(w) for any τ∈G, w∈Xp. Let u be a critical point of φ in Xp,G, where
Xp,G:={u∈Xp:τu=u,∀τ∈G}. |
Then φ′(u)=0 in X′p. In fact, given any v∈Xp, we define
ˉv=1#(G)∑τ∈Gτv, |
where #(G) denotes the cardinal of G. For any τ0∈G, since G⊂O(2), we have
τ0ˉv=τ0[1#(G)∑τ∈Gτv]=1#(G)∑τ∈Gτ0τv=ˉv, |
which implies ˉv∈Xp,G. Therefore, one has
0=⟨φ′(u),ˉv⟩=1#(G)∑τ∈G⟨φ′(u),τv⟩=1#(G)∑τ∈G⟨φ′(u)∘τ−1,v⟩=1#(G)∑τ∈G⟨φ′(u∘τ−1)∘τ−1,v⟩=⟨φ′(u),v⟩. |
For the second line, we used the fact u∈Xp,G, so we have φ′(u)=0 in X′p.
The two cases in Theorem 1.1 are direct consequences of the above discussion. Indeed, let G1 be the subgroup of O(2) generated by z↦ze2πi/k, then Xp,G1=Ek,p. If G2 is generated by z↦ze2πi/k and z↦ˉz, Xp,G2=Tk,p, so Φ′(ˉu)=0 in X′p.
We prove Theorem 1.3 in three steps for subcritical case and the Ambrosetti-Rabinowitz condition (F4'). As in the proof of Theorem 1.1, we only consider the function space Ek,p.
Step 1: ‖un‖ is bounded.
We only consider the case p>2. Same as critical case, the case p=2 can be obtained by [23, Lemma 2.11]. Applying Lemma 3.3 and (5.1), there exists a sequence {un}⊂Ek,p satisfying (3.10). By (3.10) and (F4'), we can choose a constant λ0∈(1ν,12−Mt1γ2) and then we have
˜c+o(1)=Φ(un)−λ0⟨Φ′(un),un⟩=(12−λ0)‖un‖2+12π(12p−λ0)I0(un)+∫R2(λ0f(x,un)un−F(x,un))dx≥(12−λ0)‖un‖2−∫{|un|<t1}F(x,un)dx+(λ0−1ν)∫‖un‖≥t1f(x,un)undx≥(12−Mt1γ2−λ0)‖un‖2, | (5.1) |
and then ‖un‖ is bounded.
Step 2: {un} is bounded in Ek,p.
As in the proof of the critical case, we first prove δ0:=lim supn→∞‖un‖p>0. Suppose the contrary δ0=0. Denoting M∗:=supn‖un‖ and M∗∗:=supn‖un‖2. By (F1') and (F5), choosing α∈(0,p−1pM2∗), one has
|f(x,t)|≤˜c2M2∗∗|t|+C(eαt2−1),∀(x,t)∈R2×R. | (5.2) |
By (5.2) and Lemma 2.1, we have
∫R2f(x,un)undx≤˜c2M2∗∗‖un‖22+C∫R2(eαu2n−1)|un|dx≤˜c2+C[∫R2(epp−1αu2n−1)dx]p−1p‖un‖p=˜c2+C[∫R2(epp−1α‖un‖2(u2n/‖un‖2)−1)dx]p−1p‖un‖p≤˜c2+o(1). | (5.3) |
Hence, by (5.3) and Lemma 3.3, we know
˜c+o(1)=Φ(un)−12⟨Φ′(un),un⟩=−p−14pπI1(un)+p−14pπI2(un)+∫R2[12f(x,un)un−F(x,un)]dx≤˜c2+o(1). | (5.4) |
This contradiction shows that δ0>0. Now, from (2.10), (5.1) and Lemma 2.3, one has
I1(un)≤I2(un)≤C, |
which, together with Lemma 2.5, implies that ‖un‖∗ is bounded and {un} is bounded in Ek,p.
Step 3: Φ′(ˉu)=0 in X′p.
We may assume by [25, Lemma 2.3] and passing to a subsequence again if necessary, that un⇀ˉu in Ek,p, un→ˉu, a.e., on R2 and
un→ˉuinLs(R2), |
where s∈[2,∞) if p=2 and s∈(2,∞) if p>2. Let M:=supn‖∇un‖2. By (F1'), we can choose α>0 small enough such that M2<4πα. Therefore, there is β>p big enough such that M2ββ−1<4πα. Without loss of generality, we may assume that s0∈(1,2) in (F5). Then, it follows (F5) and Lemma 2.1 that
∫R2|f(x,un)(un−ˉu)|dx≤∫{|un|<1}|f(x,un)(un−ˉu)|dx+∫{|un|≥1}|f(x,un)(un−ˉu)|dx≤C‖un‖2‖un−ˉu‖22−s0+C‖un−ˉu‖β=o(1). | (5.5) |
Similarly, one has
∫R2|f(x,ˉu)(un−ˉu)|dx=o(1). | (5.6) |
Furthermore, it follows from (2.9), (2.10) and the Hölder inequality that
A2(|un|p,|un|p−2un(un−ˉu))=o(1),A2(|ˉu|p,|ˉu|p−2ˉu(un−ˉu))=o(1). | (5.7) |
By [25, Lemma 3.3], we have
A1(|un|p,|un|p−2ˉu(un−ˉu))=o(1),A1(|ˉu|p,|ˉu|p−2ˉu(un−ˉu))=o(1). | (5.8) |
Combining (2.11), (2.12), (3.10), and (5.5)–(5.8), there holds
o(1)=⟨Φ′(un)−Φ′(ˉu),un−ˉu⟩⟨X′p,Xp⟩=‖un−ˉu‖2+12πA1(|un|p,|un|p−2(un−ˉu)2)+12πA1(|un|p,|un|p−2ˉu(un−ˉu))−12πA1(|ˉu|p,|ˉu|p−2ˉu(un−ˉu))+12πA2(|ˉu|p,|ˉu|p−2ˉu(un−ˉu))−12πA2(|un|p,|un|p−2un(un−ˉu))+∫R2f(x,ˉu)(un−ˉu)dx−∫R2f(x,un)(un−ˉu)dx+o(1)≥‖un−ˉu‖2+o(1). | (5.9) |
By (2.10), (5.9) and Lemma 2.1, we have
A2(|un|p,|vn|p)=o(1),⟨un,un−ˉu⟩=o(1),∫R2f(x,un)(un−ˉu)dx=o(1), | (5.10) |
where |vn|p:=|un|p−2|un−ˉu|2 for every n∈N. By (3.10) and (5.10), one has
o(1)=⟨Φ′(un),un−ˉu⟩⟨X′p,Xp⟩=12πA1(|un|p,|vn|p)−12πA2(|un|p,|vn|p)+⟨un,un−ˉu⟩+∫R2f(x,un)(un−ˉu)dx=12πA1(|un|p,|vn|p)+o(1) |
which, together with Lemma 2.5, implies
limn→∞(‖vn‖p+‖vn‖∗)→0. | (5.11) |
From (5.11) and [25, Lemma 3.3], one has
‖un−ˉu‖p∗=∫R2ln(1+|x|)(|un−ˉu|p−2−|un|p−2)|un−ˉu|2dx+o(1)≤12‖un−ˉu‖p∗+C∫R2ln(1+|x|)|ˉu|p−2|un−ˉu|2dx+o(1)=12‖un−ˉu‖p∗+o(1), | (5.12) |
where we used the following inequality
||a+b|p−2−|b|p−2|≤12|b|p−2+C|a|p−2, |
and C is independent of a,b∈R. Combining with (5.9), we have un→ˉu in Ek,p. Hence, 0<˜c=limn→∞Φ(un)=Φ(ˉu) and Φ′(ˉu)=0 in E′k,p. We conclude that Φ′(ˉu)=0 in X′p, as in the proof of step 3 of Theorem 1.1.
The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.
This work is partially supported by National Natural Science Foundation of China, No. 12071189. Thanks to the reviewers for their valuable suggestions and comments. The author would like to express the sincere gratitude to his tutors, professors Dong Ye and Feng Zhou, for their valuable guidance and insights that helped to improve the paper.
The authors declare there are no conflicts of interest.
In this section, we give the proof of Lemma 2.2. For any u∈Xp, we denote Ψ(u):=∫R2F(x,u)dx. In fact, we just need to prove Ψ∈C1(Xp,R), and the readers can refer to [25, Lemma 2.3] for the rest. First, given any u,v∈Xp, for almost every x∈R2
limt→0F(x,u(x)+tv(x))−F(x,u(x))t=f(x,u(x))v(x). |
On the other hand, we can choose a large enough number t1>0 such that
|f(x,t)|≤e(α0+1)t2−1,∀|t|≥t1. |
By (F1), (F5) and Lemma 2.1, one has, for any u∈Xp,
∫R2|f(x,u)|2dx=∫{|u|≤t1}|f(x,u)|2dx+∫{|u|≥t1}|f(x,u)|2dx≤C‖u‖22+∫R2(e(α0+1)u2−1)dx≤C. |
Then, for any u∈Xp, f(x,u)∈L2(R2), it implies that the Gateaux derivative Ψ′g(u) exists and Ψ′g(u)∈X′p.
Now let {un}⊂Xp, ‖un−ˉu‖Xp→0. Hence, un→ˉu in H1(R2). Let us prove Ψ′(ˉu)=limn→∞Ψ′(un). It suffices to prove
limn→∞sup‖v‖Xp=1|∫R2[f(x,un)−f(x,ˉu)]vdx|=0. |
Define that M:=supn‖∇un‖2, then we prove this lemma in two cases.
Special case: M≤√π2α0.
For any given ε∈(0,1), we choose large enough Rε>0 such that
‖v‖Lp(BcR)≤‖v‖Lp(BcRε)≤ε[ln(1+Rε)]1/p‖v‖Lp(BcRε)≤ε‖v‖Xp,∀R≥Rε |
and
‖ˉu‖L2(BcR)≤‖ˉu‖L2(BcRε)≤ε,∀R≥Rε. |
By Lemma 2.1 and α0≤π2M2, it is easy to verify that there is a C0>0 such that ‖u‖4≤C0‖u‖Xp for all u∈Xp and
∫BRε|f(x,un)|2dx+∫BRε|f(x,un)|2|un|dx≤C,∀n. |
Now, we claim that
lim supn→∞{‖f(x,un)−f(x,ˉu)‖2+‖un−ˉu‖2}≤Cε. | (A1) |
The proof of (A1) is in spirit of [36, Lemma 2.1]. As L2(BRε) is a Hilbert space, we need only to prove
lim supn→∞∫BRε(|f(x,un)|2−|f(x,ˉu)|2)dx≤Cε |
for the first part of (A1). Let M′ be large enough such that
∫{|un|≥M′}∩BRε|f(x,un)|2dx=∫{|un|≥M′}∩BRε|f(x,un)|2|un||un|dx≤C0M′≤ε. |
By the dominated convergence theorem and Fatou's Lemma, one has
|∫BRε(|f(x,un)|2−|f(x,ˉu)|2)|≤∫{|un|≥M′}∩BRε|f(x,un)|2|un|M′dx+∫{|u|≥M′}∩BRε|f(x,un)|2|ˉu|M′dx+∫BRεhn(x)dx=2ε+on(1), |
where hn(x):=||f(x,un(x))|2χ{|un|<M′}∩BRε−|f(x,ˉu(x))|2χ{|un|<M′}∩BRε|, and we use the fact
|hn(x)|≤{|f(x,ˉu(x))|2,|un|≥M′,sup{|f(x,t)|:x∈¯BRε,|t|<M′}+|f(x,ˉu(x))|2,|un|<M′. |
Therefore, we get (A1). By (A1), for large n, one has
|∫R2[f(x,un)−f(x,ˉu)]vdx|≤∫BRε|f(x,un)−f(x,ˉu)||v|dx+∫BRcε|f(x,un)−f(x,ˉu)||v|dx≤1γε‖v‖Xp+Cγ(‖un−ˉu‖2+2‖ˉu‖L2(BRcε))‖v‖Xp+22/pC(∫R2[exp(p′αu2n)−1+exp(p′αˉu2)−1]dx)1/p′ε‖v‖Xp≤Cε‖v‖Xp, |
where 1p+1p′=1 and γ:=infu∈X‖u‖‖u‖H1(R2)>0 (see [31, Lemma 2.1]).
General case: M>0.
For any R>0, let φR(r) be a C∞0 cut-off function such that 0≤φ≤1, φR≡1 on [0,R] and φR≡0 on [R+1,∞). Let δ>0 (to be determined later), we can choose large enough bounded domain BR(0) and its bounded open coverage {Ωℓ}ℓ≤Nc which has a partition of unity wℓ(1≤ℓ≤Nc) such that\\
‖φR−1(|x|)ˉu(x)−ˉu(x)‖≤δ; |
BR(0)⊂⋃1≤ℓ≤NcΩℓ,Nc∑ℓ=1wℓ(x)=1,∀x∈BR(0); |
wℓ∈C1c(Ωℓ),|∇wℓ|≤C,∀ℓ; |
∫Ωℓ|ψℓ|2dx≤δ,∫Ωℓ|ψℓ,n|2dx≤δ,∀n,ℓ; |
∫Ωℓ|∇ψℓ|2dx≤δ,∫Ωℓ|∇ψℓ,n|2dx≤δ,∀n,ℓ; |
where
ψℓ(x)=φR(|x|)wℓˉu,ψℓ,n(x)=φR(|x|)wℓun. |
Choosing δ>0 small enough and repeating now the proof of the special case, we can prove
∫BcR(0)|[f(x,un)−f(x,ˉu)]v|dx≤Cε‖v‖X |
and
∫Ωℓ|[f(x,un)−f(x,ˉu)]v|dx≤Cε‖v‖X,∀ℓ. |
Therefore, one has
|∫R2[f(x,un)−f(x,ˉu)]vdx|≤∫BcR(0)|(f(x,un)−f(x,ˉu))v|dx+Nc∑ℓ=1∫Ωi|(f(x,un)−f(x,ˉu))v|dx≤(Nc+1)Cε‖v‖X. |
So we obtain Lemma 2.2.
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