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Research article

Nonexistence of asymptotically free solutions for nonlinear Schrödinger system

  • Received: 15 December 2023 Revised: 23 January 2024 Accepted: 23 January 2024 Published: 08 April 2024
  • 35Q55, 35P25, 35B40

  • In this paper, the Cauchy problem for the nonlinear Schrödinger system

    {itu1(x,t)=Δu1(x,t)|u1(x,t)|p1u1(x,t)|u2(x,t)|p1u1(x,t),itu2(x,t)=Δu2(x,t)|u2(x,t)|p1u2(x,t)|u1(x,t)|p1u2(x,t),

    was investigated in d space dimensions. For 1<p1+2/d, the nonexistence of asymptotically free solutions for the nonlinear Schrödinger system was proved based on mathematical analysis and scattering theory methods. The novelty of this paper was to give the proof of pseudo-conformal identity on the nonlinear Schrödinger system. The present results improved and complemented these of Bisognin, Sepúlveda, and Vera(Appl. Numer. Math. 59(9)(2009): 2285–2302), in which they only proved the nonexistence of asymptotically free solutions when d=1,p=3.

    Citation: Yonghang Chang, Menglan Liao. Nonexistence of asymptotically free solutions for nonlinear Schrödinger system[J]. Communications in Analysis and Mechanics, 2024, 16(2): 293-306. doi: 10.3934/cam.2024014

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  • In this paper, the Cauchy problem for the nonlinear Schrödinger system

    {itu1(x,t)=Δu1(x,t)|u1(x,t)|p1u1(x,t)|u2(x,t)|p1u1(x,t),itu2(x,t)=Δu2(x,t)|u2(x,t)|p1u2(x,t)|u1(x,t)|p1u2(x,t),

    was investigated in d space dimensions. For 1<p1+2/d, the nonexistence of asymptotically free solutions for the nonlinear Schrödinger system was proved based on mathematical analysis and scattering theory methods. The novelty of this paper was to give the proof of pseudo-conformal identity on the nonlinear Schrödinger system. The present results improved and complemented these of Bisognin, Sepúlveda, and Vera(Appl. Numer. Math. 59(9)(2009): 2285–2302), in which they only proved the nonexistence of asymptotically free solutions when d=1,p=3.



    In this paper, we consider the following nonlinear Schrödinger system

    {itu1(x,t)=Δu1(x,t)|u1(x,t)|p1u1(x,t)|u2(x,t)|p1u1(x,t),itu2(x,t)=Δu2(x,t)|u2(x,t)|p1u2(x,t)|u1(x,t)|p1u2(x,t), (1.1)

    and the corresponding free (linear) system

    {itv1(x,t)=Δv1(x,t),itv2(x,t)=Δv2(x,t). (1.2)

    Here, xRd(d1),tR,1<p1+2/d.

    It is well known that there are a lot of results on solutions for the nonlinear Schrödinger equation. For instance, for nonlinear Schrödinger equation with harmonic potential

    itu(x,t)+Δu(x,t)|x|2u(x,t)+|u(x,t)|p1u(x,t)=0,

    Shu and Zhang [1] derived a sharp criterion for blow-up and global existence of the solutions by constructing a cross-constrained variational problem and invariant manifolds of the evolution flow. Their results were improved by Xu and his co-authors [2,3]. More precisely, Xu and Liu [2] pointed out the self-contradiction. Xu and Xu [3] derived different sharp criterion and different invariant manifolds that separate the global solutions and blow-up solutions by comparing the different cross-constrained problems. Moreover, they illustrated that some manifolds are empty and compared the three cross-constrained problems and the three depths of the potential wells. The potential well was also used to study the nonlinear Schrödinger equation with more general nonlinearities in [4], in which the global existence and nonexistence where at only the low initial energy level. It is certainly beyond the scope of the present paper to give a comprehensive review for the nonlinear Schrödinger equation. In this regard, we would like to give some references such as [5,6,7,8,9,10,11,12]. Barab [13] considered the perturbed (nonlinear) Schrödinger equation

    itu(x,t)=Δu(x,t)g|u(x,t)|p1u(x,t)

    and the corresponding free (linear) equation

    itv(x,t)=Δv(x,t).

    He proved that for a nontrivial, smooth solution u(x,t), if d=1 and 2<p3, then there does not exist any finite energy free solution v(x,t) such that u(x,t)v(x,t)20 as t+. This result is an extension to that one of Strauss [14] in which the same result was proven for 1<p2. Both Barab [13] and Strauss [14] applied the general idea that was originally used by Glassey [15] to prove the analogous result for the nonlinear Klein-Gordon equation to prove their theorems. Tsutsumi and Yajima [16] considered the nonlinear Schrödinger equation with power interactions

    itu(x,t)=12Δu(x,t)+λ|u(x,t)|p1u(x,t)

    in Rd,d2,λ>0. They proved that for any u0(x)Σ with Σ={uL2(Rd);u2+u2+xu2<}, there exists a unique u±L2(Rd) such that the solution u(x,t) with u(x,0)=u0(x) has the free asymptote u± as t±:

    limt±u(x,t)e12itΔu±2=0

    when 1+2/d<p<1+4/(d2). Guo and Tan [17] studied the asymptotic behavior of nonlinear Schrödinger equations with magnetic effect. By following the idea of [13,16], they proved the nonexistence of the nontrivial free asymptotic solutions for 1<p1+2/d and the existence of the nontrivial free asymptotic solutions for 1+2/d<p<1+4/d,d=2,3 under certain conditions, respectively.

    For some systems of Schrödinger equations, some results were also obtained. Hayashi, Li, and Naumkina [18] considered the following system of nonlinear Schrödinger equations with quadratic nonlinearities in two space dimensions

    {itu1(x,t)+12m1Δu1(x,t)=γ¯u1(x,t)u2(x,t),itu2(x,t)+12m2Δu2(x,t)=u21(x,t),

    where γ is a given complex number with |γ|=1. They obtained time decay estimates of small solutions and nonexistence of the usual scattering states for a system. Moreover, they proved stability in time of small solutions in the neighborhood of solutions to a suitable approximate equation. More related results can be found in [19,20]. Nakamura, Shimomura, and Tonegawa [21] investigated the Cauchy problem at infinite initial time of the following coupled system of the Schrödinger equation with cubic nonlinearities in one space dimension

    {itu1(x,t)+12m12xu1(x,t)=F1(u1(x,t),u2(x,t)),itu2(x,t)+12m22xu2(x,t)=F2(u1(x,t),u2(x,t)).

    By constructing modified wave operators for small final data, they studied the global existence and the large time behavior. Cheng, Guo, et al. [22] addressed the global well-posedness and scattering of the two-dimensional cubic focusing nonlinear Schrödinger system. Hayashi, Li, and Naumkin [23] considered the nonlinear Schrödinger system

    {itu1(x,t)+12Δu1(x,t)=F(u1(x,t),u2(x,t)),itu2(x,t)+12Δu2(x,t)=F(u1(x,t),u2(x,t)),

    in d space dimensions, where

    F(u1(x,t),u2(x,t))=2piλ|u1(x,t)u2(x,t)|p1(u1(x,t)u2(x,t))

    is a p-th order local or nonlocal nonlinearity smooth up to order p, with 1<p1+2/d for d2 and 1<p2 for d=1. They proved nonexistence of asymptotically free solutions in the critical and subcritical cases. In this paper, we will prove that there does not exist any finite energy asymptotically free solution of the system (1.1) for d1,1<p1+2/d. Pseudo-conformal identity on the nonlinear Schrödinger system for d1,1<p1+2/d is proven first in this paper, and based on pseudo-conformal identity, we obtain decay estimates of perturbed solutions (see Lemma 2.4). Our results improve and complement that of Bisognin, Sepúlveda, and Vera [24], in which they only proved the nonexistence of asymptotically free solutions when d=1,p=3 for (1.1) by following an idea of Glassey [15].

    The outline of the paper is as follows. In Section 2, we shall give some useful lemmas, which plays a pivotal role in proving the main results. In Section 3, we first give and prove nonexistence of asymptotically free solutions for (1.1) if d2,1<p1+2/d, and d=1,1<p2(see Theorem 3.1). Second, we present the nonexistence of asymptotically free solutions for (1.1) if d=1,2<p3(see Theorem 3.2).

    Throughout this paper, for each q[1,), we denote by the norm uq the usual spatial Lq(Rd)-norm and the dual variable is denoted by q so that 1/q+1/q=1. The alphabet c is a generic positive constant, which may be different in various positions. For convenience, denote

    Lq:=Lq(Rd),H1:=H1(Rd),
    dx:=Rddx,u:=u(t)=u(x,t),u:=supessxRd|u(x)|.

    Definition 2.1. A solution (u1,u2) to (1.1) is asymptotically free if there exist L2-solutions (v1±,v2±), decaying sufficiently rapidly, such that

    u1(t)v1±(t)2+u2(t)v2±(t)20,as t±.

    Remark 2.2. In this paper, we only focus on the solutions for t>0. The case t<0 can be handled similarly.

    Before going further, let us give some preliminary lemmas, which are used to prove our main results. The first lemma is easily proved by following Lemma 2 in [13]. Here we omit the process.

    Lemma 2.3. If (v1,v2) is a smooth solution to (1.2) with 0v1(x,0)L1L2,0v2(x,0)L1L2,2q, then

    (i) there exists a constant c=c(v1(0)q,v2(0)q) such that

    v1(t)q+v2(t)qctd(q2)/2q,t>0.

    (ii) there exist positive constants B=B(d,q,v1(0),v2(0)) and T0=T0(v1(0),v2(0)) such that

    v1(t)q+v2(t)qBtd(q2)/2q,tT0.

    When q=, the power of t is d/2.

    Lemma 2.4. If (u1,u2) is a smooth solution to (1.1) with 1<p1+4/d, u1(x,0),u2(x,0)H1Lp+1, and xu1(x,0)2+xu2(x,0)2<, then there exists c>0 depending on initial data such that

    (|u1|p+1+|u2|p+1+|u1|p1|u2|2+|u2|p1|u1|2)dxctd(p1)/2,t>0.

    Proof. We borrow some ideas from Lemma 3 in [13] to prove this lemma.

    First, let us prove the following pseudo-conformal identity

    ddt[|xu12itu1|2+|xu22itu2|2+8t2p+1(|u1|p+1+|u2|p+1+|u1|p1|u2|2+|u2|p1|u1|2)]dx=4t[4d(p1)]p+1(|u1|p+1+|u2|p+1+|u1|p1|u2|2+|u2|p1|u1|2)dx. (2.1)

    Let r=|x|,uki=kui=uixk with i=1,2,k=1,2,,d, multiply (1.1) by 2r¯ru1,2r¯ru2 with rui=uir,i=1,2, integrate the real part over Rd, and the use integration by parts, then

    2Reikxk(¯uk1tu1+¯uk2tu2)dx=2Rer(¯ru1Δu1+¯ru2Δu2)dx2p+1rr(|u1|p+1+|u1|p1|u2|2+|u2|p+1+|u2|p1|u1|2)dx=(d2)(|u1|2+|u2|2)dx+2dp+1(|u1|p+1+|u1|p1|u2|2+|u2|p+1+|u2|p1|u1|2)dx. (2.2)

    Note that

    2Reikxk(¯uk1tu1+¯uk2tu2)dx=Re[ikxk(¯uk1tu1uk1¯tu1+¯uk2tu2uk2¯tu2)dx]=ddtRe[ikxk(t(¯uk1u1)k(u1¯tu1)+t(¯uk2u2)k(u2¯tu2))dx]=ddtRe[ir(¯ru1u1+¯ru2u2)dx]+Re[id(u1¯tu1+u2¯tu2)dx].

    Substitute i¯tu1,i¯tu2 in (1.1), then the above identity can be transferred to

    2Reikxk(¯uk1tu1+¯uk2tu2)dx=ddtIm[r(ru1¯u1+ru2¯u2)dx]+d(|u1|2+|u2|2+|u1|p+1+|u1|p1|u2|2+|u2|p+1+|u2|p1|u1|2)dx. (2.3)

    Combine (2.2) and (2.3), then

    ddtIm[r(ru1¯u1+ru2¯u2)dx]=2(|u1|2+|u2|2)dxd(p1)p+1(|u1|p+1+|u1|p1|u2|2+|u2|p+1+|u2|p1|u1|2)dx. (2.4)

    Multiply by 2¯u1,2¯u2 in (1.1) and take the imaginary part to obtain

    ddt(|u1(t)|2+|u2(t)|2)=Im[2(¯u1u1+¯u2u2)]. (2.5)

    Multiply (2.5) by |x|2 and integrate over Rd to achieve

    ddt(|xu1(t)|2+|xu2(t)|2)=4Im[r(ru1¯u1+ru2¯u2)dx]. (2.6)

    Let us multiply (2.4) by 4t to give

    ddt{4tIm[r(ru1¯u1+ru2¯u2)dx]}4Im[r(ru1¯u1+ru2¯u2)dx]=ddt[4t2(|u1|2+|u2|2)dx]+4t2ddt(|u1|2+|u2|2)dx4d(p1)p+1t(|u1|p+1+|u1|p1|u2|2+|u2|p+1+|u2|p1|u1|2)dx.

    Further, make full use of (2.6) and the law of conservation of energy, then

    ddt[|xu1(t)|2+|xu2(t)|2+4t2(|u1|2+|u2|2)Re4tir(ru1¯u1+ru2¯u2)]dx=ddt[8t2p+1(|u1|p+1+|u1|p1|u2|2+|u2|p+1+|u2|p1|u1|2)dx]+16tp+1(|u1|p+1+|u1|p1|u2|2+|u2|p+1+|u2|p1|u1|2)dx4d(p1)p+1t(|u1|p+1+|u1|p1|u2|2+|u2|p+1+|u2|p1|u1|2)dx,

    which yields (2.1) directly.

    Second, we aim to give the Gronwall argument. Integrate for (2.1) over [0,t], then

    8t2p+1(|u1|p+1+|u2|p+1+|u1|p1|u2|2+|u2|p1|u1|2)dxxu1(0)22+xu2(0)22+4[4d(p1)]p+1×t0τ(|u1|p+1+|u2|p+1+|u1|p1|u2|2+|u2|p1|u1|2)dxdτ.

    Therefore,

    t2(|u1|p+1+|u2|p+1+|u1|p1|u2|2+|u2|p1|u1|2)dxλ+4d(p1)2t1τ(|u1|p+1+|u2|p+1+|u1|p1|u2|2+|u2|p1|u1|2)dxdτ, (2.7)

    where

    λ=p+18(xu1(0)22+xu2(0)22)+4d(p1)2×10τ(|u1|p+1+|u2|p+1+|u1|p1|u2|2+|u2|p1|u1|2)dxdτ.

    The law of conservation of energy implies

    u122+u222+2p+1(|u1|p+1+|u2|p+1+|u1|p1|u2|2+|u2|p1|u1|2)dx=u1(0)22+u2(0)22+2p+1×(|u1(0)|p+1+|u2(0)|p+1+|u1(0)|p1|u2(0)|2+|u2(0)|p1|u1(0)|2)dx.

    It is not difficult to get that

    λλ:=c(p)(xu1(0)22+xu2(0)22+u1(0)22+u2(0)22+η),

    where

    η:=(|u1(0)|p+1+|u2(0)|p+1+|u1(0)|p1|u2(0)|2+|u2(0)|p1|u1(0)|2)dx,

    and c(p) is a positive constant depending on p.

    By recalling the condition in Lemma 2.4, (2.7) can be rewritten as

    F(t)λ+t1β(τ)F(τ)dτ,

    where for t1,

    F(t)=t2(|u1|p+1+|u2|p+1+|u1|p1|u2|2+|u2|p1|u1|2)dx,
    β(t)=4d(p1)2t.

    Since F and β are continuous on [1,), Gronwall's lemma indicates that

    t2(|u1|p+1+|u2|p+1+|u1|p1|u2|2+|u2|p1|u1|2)dxλet14d(p1)2τdτ,t>1.

    We can simplify it to get that

    (|u1|p+1+|u2|p+1+|u1|p1|u2|2+|u2|p1|u1|2)dxλtd(p1)2,t>1.

    Further, for all t, (|u1|p+1+|u2|p+1+|u1|p1|u2|2+|u2|p1|u1|2)dx is bounded uniformly. Therefore, there exists a constant

    c=c(p,xu1(0)2,xu2(0)2,u1(0)2,u2(0)2,u1(0)p+1,u2(0)p+1)

    such that

    [(|u1|p+1+|u2|p+1+|u1|p1|u2|2+|u2|p1|u1|2)dx]1p+1ctd(p1)/2(p+1),t>0.

    Lemma 2.5. If 1p<, (eitΔh1,eitΔh2) is a nontrivial free solution, then

    t(p1)d2eitΔ(|h1|p+1+|h2|p+1+|h1|p1|h2|2+|h2|p1|h1|2)dx

    is bounded away from zero for large t.

    Proof. Hölder's inequality yields

    (|x|<kteitΔ(|h1|2+|h2|2)dx)p+12(kt)d(p1)2eitΔ(|h1|p+1+|h2|p+1+|h1|p1|h2|2+|h2|p1|h1|2)dx.

    Obviously, it suffices to bound the left side of the above inequality away from zero. Set

    eitΔh1+eitΔh2=(4πit)d2e|xy|2/4iteitΔ[h1(y,0)+h2(y,0)]dy,

    by a direct computation, then

    limt|x|<kt(|eitΔh1|2+|eitΔh2|2)dx=|ξ|<k/2[|F(eitΔh1(ξ,0))|2+|F(eitΔh2(ξ,0))|2]dξ,

    where F(eitΔh1(ξ,0)),F(eitΔh2(ξ,0)) are the Fourier transform of the initial datum.

    It is noted that (eitΔh1,eitΔh2) is nontrivial and there is a k for which the limit does not vanish. This proof is completed.

    In this section, we prove the main results by considering the following two cases.

    Case 1: d2,1<p1+2/d, and d=1,1<p2.

    Case 2: d=1,2<p3.

    First, let us prove nonexistence of asymptotically free solutions for (1.1) under case 1. The following theorem is obtained.

    Theorem 3.1. For d2,1<p1+2/d and d=1,1<p2, if (u1,u2) is a solution of (1.1), then for all (h1,h2)L2×L2,

    u1(t)eitΔh12+u2(t)eitΔh22

    does not go to zero as t+.

    Proof. Suppose that there exists (h1,h2)L2×L2 such that

    u1(t)eitΔh12+u2(t)eitΔh220,as t+. (3.1)

    Since the operator eitΔ is dense and unitary in L2, we can assume h1,h2S(Schwartz space) to get

    ddt[(eitΔu1)¯h1+(eitΔu2)¯h2]dx=[eitΔ¯h1i(|u1|p1u1+|u2|p1u1)+eitΔ¯h2i(|u1|p1u2+|u2|p1u2)]dx=[¯eitΔh1i(|u1|p1u1+|u2|p1u1)+¯eitΔh2i(|u1|p1u2+|u2|p1u2)]dx.

    Therefore,

    T0[¯eitΔh1i(|u1|p1u1+|u2|p1u1)+¯eitΔh2i(|u1|p1u2+|u2|p1u2)]dxdt (3.2)

    has a limit as T. In fact, as T, we obtain

    [¯h1eiTΔu1(T)+¯h2eiTΔu2(T)]dx=(h1¯h1+h2¯h2)dx+[¯h1(eiTΔu1(T)h1)+¯h2(eiTΔu2(T)h2)]dx0.

    On the other hand, one has

    |[i(|u1|p1u1+|u2|p1u1)¯eitΔh1+i(|u1|p1u2+|u2|p1u2)¯eitΔh2ieitΔ(|h1|p+1+|h2|p+1+|h1|p1|h2|2+|h2|p1|h1|2)]dx|(u12+u22+h12+h22)p1(h12+h22)2p×(eitΔh1+eitΔh2)p1(u1(t)eitΔh12+u2(t)eitΔh22).

    Since

    u12+u22h12+h22,as t,
    (eitΔh1+eitΔh2)p1|t|(p1)d2(h11+h21)p1,

    (3.1) combined with

    eitΔ(|h1|p+1+|h2|p+1+|h1|p1|h2|2+|h2|p1|h1|2)dxLemma2.5ct(p1)d2,

    obtains

    [i(|u1|p1u1+|u2|p1u1)¯eitΔh1+i(|u1|p1u2+|u2|p1u2)¯eitΔh2]dxc2t(p1)d2.

    The righthand side of the above inequality is not integrable, which is a contradiction since (3.2) has a limit as T.

    This completes the proof of this theorem.

    In the light of Definition 2.1, we easily get the nonexistence of asymptotically free solutions for (1.1) under case 1. In what follows, let us illustrate the nonexistence of asymptotically free solutions for (1.1) under case 2.

    Theorem 3.2. If d=1,2<p3, then the only smooth, asymptotically free solution to (1.1) is identically zero.

    Proof. Assume (u1,u2) is a smooth, asymptotically free solution to (1.1), then there exists a smooth L2-solution (v1,v2) of (1.2) such that

    u1(t)v1(t)2+u2(t)v2(t)20,as t+, (3.3)
    v1(t)+v2(t)=O(t1/2),as t+, (3.4)

    Let us combine the conservation of the L2-norm and (3.3) to show

    u1(t)2+u2(t)2=v1(t)2+v2(t)2A,t. (3.5)

    We are now in a position to prove

    v1(0)=0,v2(0)=0.

    Let us prove by contradiction. Assume v1(0)0,v2(0)0. Using (3.4), then

    v1(t)+v2(t)ct1/2,t>T1T0, (3.6)

    where T0 is as in Lemma 2.3. For t>T1, define

    H(t)=[u1¯v1+u2¯v2]dx.

    Differentiate H with respect to t, substitute from (1.1) and (1.2) for tu1,tu2,tv1 and tv2, respectively, and integrate by parts to get

    N(t):=dH(t)dt=[i¯v1(|u1|p1u1+|u2|p1u1)+i¯v2(|u1|p1u2+|u2|p1u2)]dx.

    Let us add and subtract

    i(|v1|p+1+|v1|p1|v2|2+|v2|p+1+|v2|p1|v1|2)dx,

    and then take the imaginary part to give

    ImN(t)=(|v1|p+1+|v1|p1|v2|2+|v2|p+1+|v2|p1|v1|2)dx+Re[¯v1(|u1|p1u1+|u2|p1u1)+¯v2(|u1|p1u2+|u2|p1u2)]dxRe(|v1|p+1+|v1|p1|v2|2+|v2|p+1+|v2|p1|v1|2)dx.

    For v1,v2, apply Lemma 2.3(ⅱ), then

    ImN(t)Bt(p1)/2I,t>T1. (3.7)

    Here,

    I=|Re[¯v1(|u1|p1u1+|u2|p1u1)+¯v2(|u1|p1u2+|u2|p1u2)]dxRe(|v1|p+1+|v1|p1|v2|2+|v2|p+1+|v2|p1|v1|2)dx|.

    Next, we need to prove that

    I=o(t(p1)/2),as t,

    so that

    ImN(t)ct(p1)/2>0

    for all large t.

    We use the Minkowski inequality and the mean value theorem to give

    I|[(|u1|p1+|u2|p1)(|v1|p1+|v2|p1)](u1¯v1+u2¯v2)dx|+|(|v1|p1+|v2|p1)[¯v1(u1v1)+¯v2(u2v2)]dx|c(|u1|p2+|u2|p2)(|u1v1|+|u2v2|)(|u1|+|u2|)(|v1|+|v2|)dx+c(|v1|p2+|v2|p2)(|u1v1|+|u2v2|)(|u1|+|u2|)(|v1|+|v2|)dx+(|v1|p1+|v2|p1)(|u1v1|+|u2v2|)(|v1|+|v2|)dx:=J1+J2+J3.

    For J3, using Hölder's inequality, (3.6), and (3.5), one obtains

    J3c(v1(t)p1+v2(t)p1)(u1(t)v1(t)2+u2(t)v2(t)2)(v1(t)2+v2(t)2)ctp12(u1(t)v1(t)2+u2(t)v2(t)2).

    Recall (3.3), then

    J3=o(tp12). (3.8)

    For J1, using Hölder's inequality, Lemma 2.3(ⅰ), and Lemma 2.4, we get

    J1c(u1(t)v1(t)2+u2(t)v2(t)2)×[(|u1|p+1+|u2|p+1+|u1|p1|u2|2+|u2|p1|u1|2)dx]p1p+1×(v12(p+1)/(3p)+v22(p+1)/(3p))c(u1(t)v1(t)2+u2(t)v2(t)2)t(p1)/2.

    Recall (3.3), then

    J1=o(tp12).

    Similarly,

    J2=o(tp12).

    Recall (3.8), then

    IJ1+J2+J3=o(tp12),as t.

    This estimate together with (3.7) implies that there exist T>max{1,T1} and a positive constant C such that

    ImN(t)Ct(p1)/2,tT.

    Let us fix C and T, let K be a positive integer, and integrate this inequality over TtKT to deduce

    KTTddtImH(t)dtKTTCt(p1)/2dtKTTCt1dt.

    Therefore,

    ImH(KT)ImH(T)ClnK,

    It follows from the definition of H(t) and Schwarz's inequality that

    |ImH(t)||H(t)|=|[u1(t)¯v1(t)+u2(t)¯v2(t)]dx|(u1(t)2+u2(t)2)(v1(t)2+v2(t)2)(3.5)=A2,t>T.

    Further,

    ClnK|ImH(KT)|+|ImH(T)|2A2.

    Let us choose K>e2A2/C to show contradiction. In conclusion, v1(0)=0,v2(0)=0. Hence, by (3.5), we get that u1(t)=0,u2(t)=0 in L2 for all t. The smoothness of u1,u2 implies u1(x,t)=0,u2(x,t)=0.

    The proof of this theorem is completed.

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.

    This work is supported by the Natural Science Foundation of Jiangsu Province(BK20230946, BK20221497) and the Fundamental Research Funds for Central Universities(B230201033, 423139). The authors are grateful to the anonymous reviewers for their valuable comments and suggestions to improve the quality of the paper.

    The authors declare there is no conflict of interest.



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