Citation: Yousaf Khurshid, Muhammad Adil Khan, Yu-Ming Chu. Conformable fractional integral inequalities for GG- and GA-convex functions[J]. AIMS Mathematics, 2020, 5(5): 5012-5030. doi: 10.3934/math.2020322
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Let I⊆R be an interval. Then a real-valued function h:I→R is said to be convex (concave) on the interval I if the inequality
h(tκ1+(1−t)κ2)≤(≥)th(κ1)+(1−t)h(κ2) |
holds for all κ1,κ2∈I and t∈[0,1].
It is well known that convexity (concavity) has wide applications in pure and applied mathematics [1,2,3,4,5,6,7,8,9,10,11,12]. The well known Hermite-Hadamard inequality [13,14,15,16,17,18,19,20] for the convex (concave) function h:I→R can be stated as follows:
h(κ1+κ22)≤(≥)1κ2−κ1∫κ2κ1h(x)dx≤(≥)h(κ1)+h(κ2)2 |
for all κ1,κ2∈I with κ1≠κ2.
Recently, many generalizations, invariants and extensions have been made for the convexity, for example, harmonic-convexity [21,22], exponential-convexity [23,24], s-convexity [25,26], Schur-convexity [27,28,29], strong convexity [30,31,32,33], Hp,q-convexity [34,35,36,37,38], generalized convexity [39], GG- and GA-convexities [40], preinvexity [41] and quasi-convexity [42]. In particular, many remarkable inequalities can be found in the literature [43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58] via the convexity theory.
Niculescu [59,60] defined the GG- and GA-convex functions as follows.
Definition 1.1. (See [59]) A real-valued function h:I→[0,∞) is said to be GG-convex on the interval I if the inequality
h(κt1κ1−t2)≤h(κ1)th(κ2)1−t |
holds for all κ1,κ2∈I and t∈[0,1].
Definition 1.2. (See [60]) A real-valued function h:I→[0,∞) is said to be GA-convex if the inequality
h(κt1κ1−t2)≤th(κ1)+(1−t)h(κ2) |
holds for all κ1,κ2∈I and t∈[0,1].
Ardıç et al. [61] established several novel inequalities (Theorem 1.1) involving the GG- and GA-convex functions via an identity (Lemma 1.1) for differentiable functions.
Lemma 1.1. (See [61]) Let κ1,κ2∈(0,∞) with κ1<κ2 and h:[κ1,κ2]→R be a differentiable function such that h′∈L([κ1,κ2]). Then the identity
κ22h(κ2)−κ21h(κ1)−2∫κ2κ1xh(x)dx | (1.1) |
=(logκ2−logη)∫10(κt2η1−t)3h′(κt2η1−t)dt+(logη−logκ1)∫10(ηtκ1−t1)3h′(ηtκ1−t1)dt |
holds for all η∈[κ1,κ2].
Theorem 1.1. (See [61]) Let κ1,κ2∈(0,∞) with κ1<κ2 and h:[κ1,κ2]→R be a differentiable function such that h′∈L([κ1,κ2]). Then the following statements are true:
(1) If |h′(x)| is GG-convex on [κ1,κ2], then the inequality
|κ22h(κ2)−κ21h(κ1)−2∫κ2κ1xh(x)dx| | (1.2) |
≤(logκ2−logη)L(κ32|h′(κ2)|,η3|h′(η)|)+(logη−logκ1)L(η3|h′(η)|,κ31|h′(κ1)|) |
holds for all η∈[κ1,κ2], where L(κ1,κ2)=(κ2−κ1)/(logκ2−logκ1) is the logarithmic mean of κ1 and κ2.
(2) If ϑ,γ>1 with 1/ϑ+1/γ=1 and |h′(x)|γ is GG-convex on [κ1,κ2], then the inequalities
|κ22h(κ2)−κ21h(κ1)−2∫κ2κ1xh(x)dx| | (1.3) |
≤(logκ2−logη)(L(κ3ϑ2,η3ϑ))1ϑ(L(|h′(κ2)|γ,|h′(η)|γ))1γ |
+(logη−logκ1)(L(η3ϑ,κ3ϑ1))1ϑ(L(|h′(η)|γ,κ31|h′(κ1)|γ))1γ, |
|κ22h(κ2)−κ21h(κ1)−2∫κ2κ1xh(x)dx| | (1.4) |
≤(logκ2−logη)(L(κ3γ2|h′(κ2)|γ,η3γ|h′(η)|γ))1γ |
+(logη−logκ1)(L(η3γ|h′(η)|γ,κ3γ1|h′(κ1)|γ))1γ |
and
|κ22h(κ2)−κ21h(κ1)−2∫κ2κ1xh(x)dx| | (1.5) |
≤(logκ2−logη)(L(κ32,η3))1−1γ(L(κ32|h′(κ2)|γ,η3|h′(η)|γ))1γ |
+(logη−logκ1)(L(η3,κ31))1−1γ(L(η3|h′(η)|γ,κ31|h′(κ1)|γ))1γ |
hold for all η∈[κ1,κ2].
(3) If |h′(x)| is GA-convex on [κ1,κ2], then we have
|κ22h(κ2)−κ21h(κ1)−2∫κ2κ1xh(x)dx| | (1.6) |
≤|h′(κ2)|3[κ32−L(η3,κ32)]+|h′(η)|3[L(η3,κ32)−L(κ31,η3)]+|h′(κ1)|3[L(κ31,η3)−η3] |
for all η∈[κ1,κ2].
(4) If ϑ,γ>1 with 1/ϑ+1/γ=1 and |h′(x)|γ is GA-convex on [κ1,κ2], then one has
|κ22h(κ2)−κ21h(κ1)−2∫κ2κ1xh(x)dx| | (1.7) |
≤(logκ2−logη)1−1γ(L(κ32,η3))1−1γ(|h′(κ2)|γ[κ32−L(η3,κ32)]+|h′(η)|γ[L(η3,κ32)−η3]3)1γ |
+(logη−logκ1)1−1γ(L(η3,κ31))1−1γ(|h′(η)|γ[η3−L(κ31,η3)]+|h′(κ1)|γ[L(κ31,η3)−κ31]3)1γ, |
|κ22h(κ2)−κ21h(κ1)−2∫κ2κ1xh(x)dx| | (1.8) |
≤(logκ2−logη)1−1γϑ1γ(L(κ3(γ−ϑ)γ−12,η3(γ−ϑ)γ−1))γ−1γ(Aγ(κ2,η))1γ |
+(logη−logκ1)1−1γϑ1γ(L(η3(γ−ϑ)γ−1,κ3(γ−ϑ)γ−11))γ−1γ(Aγ(η,κ1))1γ, |
|κ22h(κ2)−κ21h(κ1)−2∫κ2κ1xh(x)dx| | (1.9) |
≤(logκ2−logη)1−1γ(L(κ3γγ−12,η3γγ−1))1−1γ(|h′(κ2)|γ+|h′(η)|γ2)1γ |
+(logη−logκ1)1−1γ(L(η3γγ−1,κ3γγ−11))1−1γ(|h′(η)|γ+|h′(κ1)|γ2)1γ, |
|κ22h(κ2)−κ21h(κ1)−2∫κ2κ1xh(x)dx| | (1.10) |
≤(logκ2−logη)1−1γγ1γ(Aγ(κ2,η))1/γ+(logη−logκ1)1−1γγ1γ(Aγ(η,κ1))1/γ, |
where
Aγ(κ2,η)=|h′(κ2)|γ[κ3γ2−L(η3γ,κ3γ2)]+|h′(η)|γ[L(η3γ,κ3γ2)−η3γ]3 |
and
Aγ(η,κ1)=|h′(η)|γ[η3γ−L(κ3γ1,η3γ)]+|h′(κ1)|γ[L(κ3γ1,η3γ)−κ3γ1]3. |
The conformable fractional derivative Dα(h)(t) [62] of order 0<α≤1 at t>0 for a function h:[0,∞)→R is defined by
Dα(h)(t)=limϵ→0h(t+ϵt1−α)−h(t)ϵ, |
h is said to be α-fractional differentiable if the conformable fractional derivative Dα(h)(t) exists. The conformable fractional derivative at 0 is defined by hα(0)=limt→0+hα(t). If h1 and h2 are α-differentiable at t>0, and κ1,κ2,λ,c∈R are constants, then the conformable fractional derivative satisfies the following formulas
dαdαt(tλ)=λtλ−α,dαdαt(c)=0, |
dαdαt(κ1h1(t)+κ2h2(t))=κ1dαdαt(h1(t))+κ2dαdαt(h2(t)), |
dαdαt(h1(t)h2(t))=h1(t)dαdαt(h2(t))+h2(t)dαdαt(h1(t)), |
dαdαt(h1(t)h2(t))=h2(t)dαdαt(h1(t))−h1(t)dαdαt(h2(t))(h2(t))2 |
and
dαdαt(h1(h2(t)))=h′1(h2(t))dαdαt(h2(t)) |
if h1 differentiable at h2(t). Moreover,
dαdαt(h1(t))=t1−αddt(h1(t)) |
if h1 is differentiable.
Let α∈(0,1] and 0≤κ1<κ2. Then the function h:[κ1,κ2]→R is said to be α-fractional integrable on [κ1,κ2] if the integral
∫κ2κ1h(x)dαx=∫κ2κ1h(x)xα−1dx |
exists and is finite. All α-fractional integrable functions on [κ1,κ2] is denoted by Lα([κ1,κ2]). Note that
Iκ1α(h1)(s)=Iκ11(sα−1h1)=∫sκ1h1(x)x1−αdx |
for all α∈(0,1], where the integral is the usual Riemann improper integral.
Recently, the conformable integrals and derivatives have attracted the attention of many researchers. Anderson [63] established the conformable integral version of the Hermite-Hadamard inequality as follows:
ακα2−κα1∫κ2κ1h(x)dαx≤h(κ1)+h(κ2)2 |
if α∈(0,1] and h:[κ1,κ2]→R is an α-fractional differentiable function such that Dα(h) is increasing. Moreover, if function h is decreasing on [κ1,κ2], then
h(κ1+κ22)≤ακα2−κα1∫κ2κ1h(x)dαx. |
The main purpose of the article is to establish the conformable fractional integral versions of the Hermite-Hadamard type inequality for GG- and GA-convex functions.
In order to establish our main results, we need a lemma which we present in this section.
Lemma 2.1. Let κ1,κ2∈(0,∞) with κ1<κ2, α∈(0,1] and h:[κ1,κ2]→R be an α-fractional differentiable function on (κ1,κ2) such that Dα(h)∈Lα([κ1,κ2]). Then the identity
κ2α2h(κ2)−κ2α1h(κ1)−2α∫κ2κ1xαh(x)dαx | (2.1) |
=(logκ2−logη)∫10(κt2η1−t)3αDα(h)(κt2η1−t)t1−αdt |
+(logη−logκ1)∫10(ηtκ1−t1)3αDα(h)(ηtκ1−t1)t1−αdt |
holds for all η∈[κ1,κ2].
Proof. Integration by parts, we get
I1=∫10(κt2η1−t)3αDα(h)(κt2η1−t)t1−αdt |
=∫10(κt2η1−t)2α+1h′(κt2η1−t)dt. |
Let x=κt2η1−t. Then I1 can be rewritten as
I1=1logκ2−logη∫κ2ηx2αh′(x)dx |
=1logκ2−logη[κα2h(κ2)−ηαh(η)−2α∫κ2ηx2α−1h(x)dx] |
=1logκ2−logη[κα2h(κ2)−ηαh(η)−2α∫κ2ηxαh(x)dαx]. |
Similarly, we have
I2=∫10(ηtκ1−t1)3αDα(h)(ηtκ1−t1)t1−αdt |
=1logη−logκ1[ηαh(η)−κα1h(κ1)−2α∫ηκ1xαh(x)dαx]. |
Multiplying I1 by (logκ2−logη) and I2 by (logη−logκ1), then add them we get the desired identity.
Remark 2.1. Let α=1. Then identity (2.1) reduces to (1.1).
Theorem 2.1. Let κ1,κ2∈(0,∞) with κ1<κ2, α∈(0,1], h:[κ1,κ2]→R be an α-fractional differentiable function on (κ1,κ2) such that Dα(h)∈Lα([κ1,κ2]) and |h′(x)| be a GG-convex function on [κ1,κ2]. Then the inequality
|κ2α2h(κ2)−κ2α1h(κ1)−2α∫κ2κ1xαh(x)dαx| | (2.2) |
≤(logκ2−logη)L(κ2α+12|h′(κ2)|,η2α+1|h′(η)|) |
+(logη−logκ1)L(η2α+1|h′(η)|,κ2α+11|h′(κ1)|) |
holds for all η∈[κ1,κ2].
Proof. It follows from the GG-convexity of the function |h′(x)| on the interval [κ1,κ2] and Lemma 2.1 that
|κ2α2h(κ2)−κ2α1h(κ1)−2α∫κ2κ1xαh(x)dαx| |
≤(logκ2−logη)∫10(κt2η1−t)2α+1|h′(κt2η1−t)|dt |
+(logη−logκ1)∫10(ηtκ1−t1)2α+1|h′(ηtκ1−t1)|dt |
≤(logκ2−logη)∫10(κt2η1−t)2α+1|h′(κ2)|t|h′(η)|1−tdt |
+(logη−logκ1)∫10(ηtκ1−t1)2α+1|h′(η)|t|h′(κ1)|1−tdt |
=(logκ2−logη)L(κ2α+12|h′(κ2)|,η2α+1|h′(η)|) |
+(logη−logκ1)L(η2α+1|h′(η)|,κ2α+11|h′(κ1)|). |
Remark 2.2. Let α=1. Then inequality (2.2) reduces to (1.2).
Theorem 2.2. Let κ1,κ2∈(0,∞) with κ1<κ2, ϑ,γ>1 with 1/ϑ+1/γ=1, α∈(0,1], h:[κ1,κ2]→R be an α-fractional differentiable function on (κ1,κ2) such that Dα(h)∈Lα([κ1,κ2]) and |h′(x)|γ be a GG-convex function on [κ1,κ2]. Then the inequality
|κ2α2h(κ2)−κ2α1h(κ1)−2α∫κ2κ1xαh(x)dαx| | (2.3) |
≤(logκ2−logη)(L(κ(2α+1)ϑ2,η(2α+1)ϑ))1ϑ(L(|h′(κ2)|γ,|h′(η)|γ))1γ |
+(logη−logκ1)(L(η(2α+1)ϑ,κ(2α+1)ϑ1))1ϑ(L(|h′(η)|γ,|h′(κ1)|γ))1γ |
holds for all η∈[κ1,κ2].
Proof. From Lemma 2.1, the property of the modulus, GG-convexity of |h′|γ and Hölder inequality we clearly see that
|κ2α2h(κ2)−κ2α1h(κ1)−2α∫κ2κ1xαh(x)dαx| |
≤(logκ2−logη)∫10(κt2η1−t)2α+1|h′(κt2η1−t)|dt |
+(logη−logκ1)∫10(ηtκ1−t1)2α+1|h′(ηtκ1−t1)|dt |
≤(logκ2−logη)(∫10(κt2η1−t)(2α+1)ϑdt)1ϑ(∫10|h′(κt2η1−t)|γdt)1γ |
+(logη−logκ1)(∫10(ηtκ1−t1)(2α+1)ϑdt)1ϑ(∫10|h′(ηtκ1−t1)|γdt)1γ |
≤(logκ2−logη)(∫10(κt2η1−t)(2α+1)ϑdt)1ϑ(∫10|h′(κ2)|γt|h′(η)|(1−t)γdt)1γ |
+(logη−logκ1)(∫10(ηtκ1−t1)(2α+1)ϑdt)1ϑ(∫10|h′(η)|γt|h′(κ1)|(1−t)γdt)1γ |
=(logκ2−logη)(L(κ(2α+1)ϑ2,η(2α+1)ϑ))1ϑ(L(|h′(κ2)|γ,|h′(η)|γ))1γ |
+(logη−logκ1)(L(η(2α+1)ϑ,κ(2α+1)ϑ1))1ϑ(L(|h′(η)|γ,|h′(κ1)|γ))1γ. |
Remark 2.3. Let α=1. Then inequality (2.3) reduces to (1.3).
Theorem 2.3. Let κ1,κ2∈(0,∞) with κ1<κ2, γ>1, α∈(0,1], h:[κ1,κ2]→R be an α-fractional differentiable function on (κ1,κ2) such that Dα(h)∈Lα([κ1,κ2]) and |h′(x)|γ be a GG-convex function on [κ1,κ2]. Then the inequality
|κ2α2h(κ2)−κ2α1h(κ1)−2α∫κ2κ1xαh(x)dαx| | (2.4) |
≤(logκ2−logη)(L(κ(2α+1)γ2|h′(κ2)|γ,η(2α+1)γ|h′(η)|γ))1γ |
+(logη−logκ1)(L(η(2α+1)γ|h′(η)|γ,κ(2α+1)γ1|h′(κ1)|γ))1γ |
holds for all η∈[κ1,κ2].
Proof. It follows from Lemma 2.1 that
|κ2α2h(κ2)−κ2α1h(κ1)−2α∫κ2κ1xαh(x)dαx| |
≤(logκ2−logη)∫10(κt2η1−t)2α+1|h′(κt2η1−t)|dt |
+(logη−logκ1)∫10(ηtκ1−t1)2α+1|h′(ηtκ1−t1)|dt. |
Let ϑ>1 such that ϑ−1+γ−1=1. Then making use of the Hölder integral inequality and the GG-convexity of |h′|γ, we get
|κ2α2h(κ2)−κ2α1h(κ1)−2α∫κ2κ1xαh(x)dαx| |
≤(logκ2−logη)(∫10dt)1ϑ(∫10(κt2η1−t)(2α+1)γ|h′(κt2η1−t)|γdt)1γ |
+(logη−logκ1)(∫10dt)1ϑ(∫10(ηtκ1−t1)(2α+1)γ|h′(ηtκ1−t1)|γdt)1γ |
≤(logκ2−logη)(∫10dt)1ϑ(∫10(κt2η1−t)(2α+1)γ|h′(κ2)|γt|h′(η)|(1−t)γdt)1γ |
+(logη−logκ1)(∫10dt)1ϑ(∫10(ηtκ1−t1)(2α+1)γ|h′(η)|γt|h′(κ1)|(1−t)γdt)1γ |
=(logκ2−logη)(L(κ(2α+1)γ2|h′(κ2)|γ,η(2α+1)γ|h′(η)|γ))1γ |
+(logη−logκ1)(L(η(2α+1)γ|h′(η)|γ,κ(2α+1)γ1|h′(κ1)|γ))1γ. |
Remark 2.4. Let α=1. Then inequality (2.4) reduces to (1.4).
Theorem 2.4. Let κ1,κ2∈(0,∞) with κ1<κ2, γ>1, α∈(0,1], h:[κ1,κ2]→R be an α-fractional differentiable function on (κ1,κ2) such that Dα(h)∈Lα([κ1,κ2]) and |h′(x)|γ be a GG-convex function on [κ1,κ2]. Then the inequality
|κ2α2h(κ2)−κ2α1h(κ1)−2α∫κ2κ1xαh(x)dαx| | (2.5) |
≤(logκ2−logη)(L(κ(2α+1)2,η(2α+1)))1−1γ(L(κ(2α+1)2|h′(κ2)|γ,η(2α+1)|h′(η)|γ))1γ |
+(logη−logκ1)(L(η(2α+1),κ(2α+1)1))1−1γ(L(η(2α+1)|h′(η)|γ,κ(2α+1)1|h′(κ1)|γ))1γ |
holds whenever η∈[κ1,κ2].
Proof. From the GG-convexity of |h′|γ, power mean inequality, the property of the modulus and Lemma 2.1 we clearly see that
|κ2α2h(κ2)−κ2α1h(κ1)−2α∫κ2κ1xαh(x)dαx| |
≤(logκ2−logη)∫10(κt2η1−t)2α+1|h′(κt2η1−t)|dt |
+(logη−logκ1)∫10(ηtκ1−t1)2α+1|h′(ηtκ1−t1)|dt |
≤(logκ2−logη)(∫10(κt2η1−t)2α+1dt)1−1γ(∫10(κt2η1−t)2α+1|h′(κt2η1−t)|γdt)1γ |
+(logη−logκ1)(∫10(ηtκ1−t1)2α+1dt)1−1γ(∫10(ηtκ1−t1)2α+1|h′(ηtκ1−t1)|γdt)1γ |
≤(logκ2−logη)(∫10(κt2η1−t)2α+1dt)1−1γ(∫10(κt2η1−t)2α+1|h′(κ2)|γt|h′(η)|(1−t)γdt)1γ |
+(logη−logκ1)(∫10(ηtκ1−t1)2α+1dt)1−1γ(∫10(ηtκ1−t1)2α+1|h′(η)|γt|h′(κ1)|(1−t)γdt)1γ |
=(logκ2−logη)(L(κ(2α+1)2,η(2α+1)))1−1γ(L(κ(2α+1)2|h′(κ2)|γ,η(2α+1)|h′(η)|γ))1γ |
+(logη−logκ1)(L(η(2α+1),κ(2α+1)1))1−1γ(L(η(2α+1)|h′(η)|γ,κ(2α+1)1|h′(κ1)|γ))1γ. |
Remark 2.5. Let α=1. Then inequality (2.5) reduces to (1.5).
Theorem 2.5. Let κ1,κ2∈(0,∞) with κ1<κ2, α∈(0,1], h:[κ1,κ2]→R be an α-fractional differentiable function on (κ1,κ2) such that Dα(h)∈Lα([κ1,κ2]) and |h′(x)| be a GA-convex function on [κ1,κ2]. Then the inequality
|κ2α2h(κ2)−κ2α1h(κ1)−2α∫κ2κ1xαh(x)dαx| | (2.6) |
≤|h(κ2)|2α+1[κ2α+12−L(η2α+1,κ2α+12)]+|h′(η)|2α+1[L(η2α+1,κ2α+12)−L(κ2α+11,η2α+1)] |
+|h′(κ1)|2α+1[L(κ2α+11,η2α+1)−η2α+1] |
holds for each η∈[κ1,κ2].
Proof. It follows from the GA-convexity of |h′(x)| and Lemma 2.1 that
|κ2α2h(κ2)−κ2α1h(κ1)−2α∫κ2κ1xαh(x)dαx| |
≤(logκ2−logη)∫10(κt2η1−t)2α+1|h′(κt2η1−t)|dt |
+(logη−logκ1)∫10(ηtκ1−t1)2α+1|h′(ηtκ1−t1)|dt |
≤(logκ2−logη)∫10(κt2η1−t)2α+1[t|h′(κ2)|+(1−t)|h′(η)|]dt |
+(logη−logκ1)∫10(ηtκ1−t1)2α+1[t|h′(η)|+(1−t)|h′(κ1)|]dt |
=|h′(κ2)|2α+1[κ2α+12−L(η2α+1,κ2α+12)]+|h′(η)|2α+1[L(η2α+1,κ2α+12)−L(κ2α+11,η2α+1)] |
+|h′(κ1)|2α+1[L(κ2α+11,η2α+1)−η2α+1]. |
Remark 2.6. Let α=1. Then inequality (2.6) becomes (1.6).
Theorem 2.6. Let κ1,κ2∈(0,∞) with κ1<κ2, α∈(0,1], γ>1, h:[κ1,κ2]→R be an α-fractional differentiable function on (κ1,κ2) such that Dα(h)∈Lα([κ1,κ2]) and |h′(x)|γ be a GA-convex function on [κ1,κ2]. Then the inequality
|κ2α2h(κ2)−κ2α1h(κ1)−2α∫κ2κ1xαh(x)dαx| | (2.7) |
≤(logκ2−logη)1−1γ(L(κ(2α+1)2,η(2α+1)))1−1γ |
×(|h′(κ2)|γ[κ2α+12−L(η2α+1,κ2α+12)]+|h′(η)|γ[L(η2α+1,κ2α+12)−η2α+1]2α+1)1γ |
+(logη−logκ1)1−1γ(L(η(2α+1),κ(2α+1)1))1−1γ |
×(|h′(η)|γ[η2α+1−L(κ2α+11),η2α+1]+|h′(κ1)|γ[L(κ2α+11,η2α+1)−κ2α+11]2α+1)1γ |
holds for any η∈[κ1,κ2].
Proof. From the GA-convexity of |h′|γ, power mean inequality, the property of the modulus and Lemma 2.1, one has
|κ2α2h(κ2)−κ2α1h(κ1)−2α∫κ2κ1xαh(x)dαx| |
≤(logκ2−logη)∫10(κt2η1−t)2α+1|h′(κt2η1−t)|dt |
+(logη−logκ1)∫10(ηtκ1−t1)2α+1|h′(ηtκ1−t1)|dt |
≤(logκ2−logη)(∫10(κt2η1−t)2α+1dt)1−1γ(∫10(κt2η1−t)2α+1|h′(κt2η1−t)|γdt)1γ |
+(logη−logκ1)(∫10(ηtκ1−t1)2α+1dt)1−1γ(∫10(ηtκ1−t1)2α+1|h′(ηtκ1−t1)|γdt)1γ |
≤(logκ2−logη)(∫10(κt2η1−t)2α+1dt)1−1γ(∫10(κt2η1−t)2α+1[t|h′(κ2)|γ+(1−t)|h′(η)|γ]dt)1γ |
+(logη−logκ1)(∫10(ηtκ1−t1)2α+1dt)1−1γ(∫10(ηtκ1−t1)2α+1[t|h′(η)|γ+(1−t)|h′(κ1)|γ]dt)1γ |
=(logκ2−logη)1−1γ(L(κ(2α+1)2,η(2α+1)))1−1γ |
×(|h′(κ2)|γ[κ2α+12−L(η2α+1,κ2α+12)]+|h′(η)|γ[L(η2α+1,κ2α+12)−η2α+1]2α+1)1γ |
+(logη−logκ1)1−1γ(L(η(2α+1),κ(2α+1)1))1−1γ |
×(|h′(η)|γ[η2α+1−L(κ2α+11),η2α+1]+|h′(κ1)|γ[L(κ2α+11,η2α+1)−κ2α+11]2α+1)1γ. |
Remark 2.7. Let α=1. Then inequality (2.7) reduces to (1.7).
Theorem 2.7. Let κ1,κ2∈(0,∞) with κ1<κ2, ϑ,γ>1 with 1/ϑ+1/γ=1, α∈(0,1], h:[κ1,κ2]→R be an α-fractional differentiable function on (κ1,κ2) such that Dα(h)∈Lα([κ1,κ2]) and |h′(x)|γ be a GA-convex function on [κ1,κ2]. Then the inequality
|κ2α2h(κ2)−κ2α1h(κ1)−2α∫κ2κ1xαh(x)dαx| | (2.8) |
≤(logκ2−logη)1−1γϑ1γ(L(κ(γ−ϑ)(2α+1)γ−12,η(γ−ϑ)(2α+1)γ−1))γ−1γ(Aγ(κ2,η))1γ |
+(logη−logκ1)1−1γϑ1γ(L(η(γ−ϑ)(2α+1)γ−1,κ(γ−ϑ)(2α+1)γ−11))γ−1γ(Aγ(η,κ1))1γ |
holds for any η∈[κ1,κ2], where
Aγ(κ2,η)=|h′(κ2)|γ[κγ(2α+1)2−L(ηγ(2α+1),κγ(2α+1)2)]+|h′(η)|γ[L(ηγ(2α+1),κγ(2α+1)2)−ηγ(2α+1)]2α+1, |
Aγ(η,κ1)=|h′(η)|γ[ηγ(2α+1)−L(κγ(2α+1)1,ηγ(2α+1))]+|h′(κ1)|γ[L(κγ(2α+1)1,ηγ(2α+1))−κγ(2α+1)1]2α+1. |
Proof. It follows from Lemma 2.1, the GA-convexity of |h′|γ, power mean inequality, Hölder integral inequality and the property of the modulus that
|κ2α2h(κ2)−κ2α1h(κ1)−2α∫κ2κ1xαh(x)dαx| |
≤(logκ2−logη)∫10(κt2η1−t)2α+1|h′(κt2η1−t)|dt |
+(logη−logκ1)∫10(ηtκ1−t1)2α+1|h′(ηtκ1−t1)|dt |
≤(logκ2−logη)(∫10(κ(2α+1)t2η(2α+1)(1−t))γ−ϑγ−1dt)γ−1γ |
×(∫10(κ(2α+1)t2η(2α+1)(1−t))ϑ|h′(κt2η1−t)|γdt)1γ |
+(logη−logκ1)(∫10(η(2α+1)tκ(2α+1)(1−t)1)γ−ϑγ−1dt)γ−1γ |
×(∫10(η(2α+1)tκ(2α+1)(1−t)1)ϑ|h′(ηtκ1−t1)|γdt)1γ |
≤(logκ2−logη)(∫10(κ(2α+1)t2η(2α+1)(1−t))γ−ϑγ−1dt)γ−1γ |
×(∫10(κ(2α+1)t2η(2α+1)(1−t))ϑ[t|h′(κ2)|γ+(1−t)|h′(η)|γ]dt)1γ |
+(logη−logκ1)(∫10(η(2α+1)tκ(2α+1)(1−t)1)γ−ϑγ−1dt)γ−1γ |
×(∫10(η(2α+1)tκ(2α+1)(1−t)1)ϑ[t|h′(η)|γ+(1−t)|h′(κ1)|γ]dt)1γ |
=(logκ2−logη)1−1γϑ1γ(L(κ(γ−ϑ)(2α+1)γ−12,η(γ−ϑ)(2α+1)γ−1))γ−1γ(Aγ(κ2,η))1γ |
+(logη−logκ1)1−1γϑ1γ(L(η(γ−ϑ)(2α+1)γ−1,κ(γ−ϑ)(2α+1)γ−11))γ−1γ(Aγ(η,κ1))1γ. |
Remark 2.8. Let α=1. Then inequality (2.8) becomes (1.8).
Theorem 2.8. Let κ1,κ2∈(0,∞) with κ1<κ2, γ>1, α∈(0,1], h:[κ1,κ2]→R be an α-fractional differentiable function on (κ1,κ2) such that Dα(h)∈Lα([κ1,κ2]) and |h′(x)|γ be a GA-convex function on [κ1,κ2]. Then the inequality
|κ2α2h(κ2)−κ2α1h(κ1)−2α∫κ2κ1xαh(x)dαx| | (2.9) |
≤(logκ2−logη)1−1γ(L(κγ(2α+1)γ−12,ηγ(2α+1)γ−1))1−1γ(A(|h′(κ2)|γ,|h′(η)|γ))1γ |
+(logη−logκ1)1−1γ(L(ηγ(2α+1)γ−1,κγ(2α+1)γ−11))1−1γ(A(|h′(η)|γ,|h′(κ1)|γ))1γ |
holds for any η∈[κ1,κ2].
Proof. From Lemma 2.1, the GG-convexity of |h′|γ, Hölder inequality and the property of the modulus, we have
|κ2α2h(κ2)−κ2α1h(κ1)−2α∫κ2κ1xαh(x)dαx| |
≤(logκ2−logη)∫10(κt2η1−t)2α+1|h′(κt2η1−t)|dt |
+(logη−logκ1)∫10(ηtκ1−t1)2α+1|h′(ηtκ1−t1)|dt |
≤(logκ2−logη)(∫10(κt2η1−t)2α+1dt)1−1γ(∫10|h′(κt2η1−t)|γdt)1γ |
+(logη−logκ1)(∫10(ηtκ1−t1)2α+1dt)1−1γ(∫10|h′(ηtκ1−t1)|γdt)1γ |
≤(logκ2−logη)(∫10(κt2η1−t)2α+1dt)1−1γ(∫10[t|h′(κ2)|γ+(1−t)|h′(η)|γ]dt)1γ |
+(logη−logκ1)(∫10(ηtκ1−t1)2α+1dt)1−1γ(∫10[t|h′(η)|γ+(1−t)|h′(κ1)|γ]dt)1γ |
=(logκ2−logη)1−1γ(L(κγ(2α+1)γ−12,ηγ(2α+1)γ−1))1−1γ(A(|h′(κ2)|γ,|h′(η)|γ))1γ |
+(logη−logκ1)1−1γ(L(ηγ(2α+1)γ−1,κγ(2α+1)γ−11))1−1γ(A(|h′(η)|γ,|h′(κ1)|γ))1γ. |
Remark 2.9. Let α=1. Then inequality (2.9) leads to (1.9).
Theorem 2.9. Let κ1,κ2∈(0,∞) with κ1<κ2, γ>1, α∈(0,1], h:[κ1,κ2]→R be an α-fractional differentiable function on (κ1,κ2) such that Dα(h)∈Lα([κ1,κ2]) and |h′(x)|γ be a GA-convex function on [κ1,κ2]. Then the inequality
|κ2α2h(κ2)−κ2α1h(κ1)−2α∫κ2κ1xαh(x)dαx| | (2.10) |
≤(logκ2−logη)1−1γγ1γBγ(κ2,η)+(logη−logκ1)1−1γγ1γBγ(η,κ1) |
holds for any η∈[κ1,κ2], where
Bγ(κ2,η)=(|h′(κ2)|γ[κγ(2α+1)2−L(ηγ(2α+1),κγ(2α+1)2)]+|h′(η)|γ[L(ηγ(2α+1),κγ(2α+1)2)−ηγ(α+1)]2α+1)1γ, |
Bγ(η,κ1)=(|h′(η)|γ[ηγ(2α+1)−L(κγ(2α+1)1,ηγ(2α+1))]+|h′(κ1)|γ[L(κγ(2α+1)1,ηγ(2α+1))−κγ(α+1)1]2α+1)1γ. |
Proof. It follows from Lemma 2.1, the GA-convexity of |h′|γ, power mean inequality and property of the modulus that
|κ2α2h(κ2)−κ2α1h(κ1)−2α∫κ2κ1xαh(x)dαx| |
≤(logκ2−logη)∫10(κt2η1−t)2α+1|h′(κt2η1−t)|dt |
+(logη−logκ1)∫10(ηtκ1−t1)2α+1|h′(ηtκ1−t1)|dt |
≤(logκ2−logη)(∫10dt)1−1γ(∫10(κt2η1−t)2α+1|h′(κt2η1−t)|γdt)1γ |
+(logη−logκ1)(∫10dt)1−1γ(∫10(ηtκ1−t1)2α+1|h′(ηtκ1−t1)|γdt)1γ |
≤(logκ2−logη)(∫10dt)1−1γ(∫10(κt2η1−t)2α+1[t|h′(κ2)|γ+(1−t)|h′(η)|γ]dt)1γ |
+(logη−logκ1)(∫10dt)1−1γ(∫10(ηtκ1−t1)2α+1[t|h′(η)|γ+(1−t)|h′(κ1)|γ]dt)1γ |
=(logκ2−logη)1−1γγ1γBγ(κ2,η)+(logη−logκ1)1−1γγ1γBγ(η,κ1). |
Remark 2.10. Let α=1. Then inequality (2.10) reduces to (1.10).
We have generalized the Hermite-Hadamard type inequalities for GG- and GA-convex functions established by Ardıç, Akdemir and Yıdız in [61] to the conformable fractional integrals. Our ideas and approach may lead to a lot of follow-up research.
The authors would like to thank the anonymous referees for their valuable comments and suggestions, which led to considerable improvement of the article.
The work was supported by the Natural Science Foundation of China (Grant Nos. 61673169, 11971142, 11701176, 11626101, 11601485).
The authors declare no conflict of interest.
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