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Research article Special Issues

On a hyperbolic-parabolic chemotaxis system

  • Stability of steady state solutions associated with initial and boundary value problems of a coupled fluid-reaction-diffusion system in one space dimension is analyzed. It is shown that under Dirichlet-Dirichlet type boundary conditions, non-trivial steady state solutions exist and are locally stable when the system parameters satisfy certain constraints.

    Citation: Hongyun Peng, Kun Zhao. On a hyperbolic-parabolic chemotaxis system[J]. Mathematical Biosciences and Engineering, 2023, 20(5): 7802-7827. doi: 10.3934/mbe.2023337

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  • Stability of steady state solutions associated with initial and boundary value problems of a coupled fluid-reaction-diffusion system in one space dimension is analyzed. It is shown that under Dirichlet-Dirichlet type boundary conditions, non-trivial steady state solutions exist and are locally stable when the system parameters satisfy certain constraints.



    Chemotaxis is a phenomenon describing the influence of environmental chemical substances on the motion of various cells. Chemotaxis widely exists in various biological phenomena, such as cells aggregation [1], embryonic development [2], vascular network formation [3,4], etc. This paper is concerned with the following hyperbolic-parabolic chemotaxis system describing vasculogenesis

    {tρ+(ρu)=0,t(ρu)+(ρuu)+P(ρ)=αρu+βρΦ,τtΦ=dΔΦaΦ+bρ, (1.1)

    where (x,t)Ω×(0,). The model (1.1) was proposed in [5] to reproduce key features of experiments of in vitro formation of blood vessels showing that cells randomly spreading on a gel matrix autonomously organize to a connected vascular network (more extensive modeling details can be found in [6]), where the unknowns ρ=ρ(x,t)0 and u=u(x,t)Ω denote the density and velocity of endothelial cells, respectively, and Φ=Φ(x,t)0 denotes the concentration of the chemoattractant secreted by the endothelial cells. The convection term (ρuu) models the cell movement persistence (inertial effect), P(ρ) is the cell-density dependent pressure function accounting for the fact that closely packed cells resist to compression due to the impenetrability of cellular matter, αρu corresponds to a damping (friction) force with coefficient α>0 as a result of the interaction between cells and the underlying substratum and the quantity |β|>0 measures the intensity of cell response to the chemical concentration gradient, where β>0 (resp. β<0) means the chemotaxis is attractive (resp. repulsive) (cf. [7,8]). In this paper, we consider attractive chemotaxis. τ0 and d>0 are the relaxation time scale and diffusion coefficient of the chemoattractant, respectively, and the positive constants a and b denote the death and secretion rates of the chemoattractant, respectively. In the literature (cf. [9]), some parabolic-hyperbolic chemotaxis models with different structures than (1.1) have also been studied.

    Chavanis and Sire obtained through asymptotic analysis in [10] that when the damping coefficient β is large, the solution of (1.1) converges to the solution of the Keller-Segel model. Subsequently, this has also been verified from the mathematical analysis in [11]. Natalini et al. in [12] numerically studied the difference and connection between the model (1.1) and the Keller-Segel chemotaxis model. By adding a viscous term Δu to the second equation of (1.1), the linear stability of the constant ground state [ˉρ,0,ˉΦ] was obtained in [13] under the condition

    bP(ˉρ)aαˉρ>0. (1.2)

    When the initial value [ρ0,u0,Φ0][Hs(Rd)]d+2(s>d/2+1) is a small perturbation of the constant ground state [ˉρ,0,ˉΦ] with ˉρ>0 sufficiently small, it was shown in [14,15] that the system (1.1) admits global strong solutions without vacuum converging to [ˉρ,0,ˉΦ] with an algebraic rate (1+t)34 as t. In [16], when the pressure function P satisfies (1.2), the authors removed the limitation that the density is sufficiently small, obtained the global existence of classical solutions to (1.1), and improved the decay rates of the solutions. Subsequently, in [17], the authors also proved that the system (1.1) in R admits nonlinear diffusion waves which are stable against a small perturbation. Recently in [18], the well-posedness of global classical solutions to the Cauchy problem of (1.1) is established in homogeneous hybrid Besov spaces.

    All the studies above are on the Cauchy problem of (1.1), and the problem becomes more complicated when boundary effects are considered. Subsequently, the stationary solutions of (1.1) with vacuum (bump solutions) in a bounded interval with zero-flux boundary condition were constructed in [19,20]. Recently, the stability of transition layer solutions of (1.1) on R+=[0,) was established in [21]. An interesting question is whether the stability of non-constant stationary solutions of (1.1) can be considered in bounded regions. In the following, we will consider the hyperbolic-parabolic chemotaxis system (1.1) on I=[0,1] with P=A0ρ2:

    {ρt+(ρu)x=0,xI, t>0,ρut+ρuux+2A0ρρx=αρu+βρΦx,xI, t>0,τΦt=dΦxxaΦ+bρ,xI, t>0;(ρ,u,Φ)(x,0)=(ρ0,u0,Φ0)(x),xI;u|x=0,x=1=0,Φ|x=0,x=1=0,t>0, (1.3)

    where A0 is a positive constant. In this paper, we shall first use delicate analysis to show that the system (1.3) has a unique non-constant stationary solution. Then we show that the stationary solution is locally asymptotically stable when the system parameters satisfy certain constraints.

    To identify the stationary solution associated with the initial-boundary value problem (1.3), we first note that because of the dissipation mechanism induced by linear damping and the boundary condition for u, it is reasonable to expect that the equilibrium velocity is zero. Denote respectively the equilibrium density and concentration by ˆρ and ˆΦ. Taking into account the zero equilibrium velocity, we see that ˆρ and ˆΦ satisfy

    {2A0ˆρˆρx=βˆρˆΦx,xI, t>0,dˆΦxxaˆΦ+bˆρ=0,xI, t>0;ˆΦ|x=0,x=1=0,t>0. (2.1)

    Lemma 2.1. The boundary value problem (2.1) admits a unique solution (ˆρ,ˆΦ). Moreover, dˆρ(x)dx and d2ˆρ(x)dx2 are small, when d is large while a, b, A0, and β are fixed.

    Proof. The first equation of (2.1) implies 2A0ˆρ=βˆΦ+ˆC, for some constant ˆC which is to be determined later. Substituting ˆρ=β2A0ˆΦ+ˆC2A0 into the second equation of (2.1), we have

    dˆΦxxaˆΦ+bβ2A0ˆΦ+bˆC2A0=0. (2.2)

    Let

    Λbβ2aA02dA0,ˆDbˆCbβ2aA0,ΨˆΦˆD. (2.3)

    Then we derive from (2.2) that

    ΨxxΛΨ=0. (2.4)

    Now we discuss the three cases regarding the sign of Λ.

    Case I. If Λ=0 (i.e., bβ=2aA0), (2.2) can be written directly as

    ˆΦxx+bˆC2dA0=0.

    Then we obtain ˆΦ(x)=bˆC2dA0(x22+Ax+B) for some constants A and B. Since ˆΦ=0 when x=0 and x=1, we can deduce that ˆΦ(x)=bˆC4dA0(x2x) for all x[0,1]. This implies

    ˆρ(x)=bβˆC8dA20(x2x)+ˆC2A0. (2.5)

    Since the total cellular mass is conserved under the zero velocity boundary condition, we can show that

    10ˆρ(x)dx=bβˆC48dA20+ˆC2A0=10ρ0(x)dx.

    This implies, if the initial total mass is positive,

    0<A010ρ0(x)dx<ˆC<4A010ρ0(x)dx, (2.6)

    when d>0 is sufficiently large while the other parameters are fixed. Taking into consideration that ρ represents the cell density, we should require ˆρ(x)>0 for all x[0,1]. Moreover, the reader will see from the asymptotic analysis presented below that ˆρ needs to be bounded from above and below away from zero, in order to obtain the stability of the non-constant stationary solution. Combining (2.5) and (2.6), and noting xx214 for all x[0,1], we see that

    0<1410ρ0(x)dx<ˆρ(x)<410ρ0(x)dx,x[0,1], (2.7)

    when d is relatively large compared with the other parameters. This gives us the desired property of the equilibrium density.

    Meanwhile, in the asymptotic analysis we will require dˆρ(x)dx and d2ˆρ(x)dx2 to be relatively small compared with ˆρ. To fulfill such a requirement, we observe that

    dˆρ(x)dx=bβˆCx4dA20+bβˆC8dA200,asd,d2ˆρ(x)dx2=bβˆC4dA200,asd.

    Hence, in the case Λ=0, the smallness of dˆρ(x)dx and d2ˆρ(x)dx2 can be realized, when d is sufficiently large, while a, b, A0 and β are fixed.

    Case II. When Λ>0, let λ=Λ. Then we have from (2.4) that Ψ(x)=Aeλx+Beλx for some constants A and B, which implies ˆΦ(x)=Aeλx+Beλx+ˆD. Using the boundary conditions, we can show that

    ˆΦ(x)=ˆDeλ+1(eλ+1eλxeλ(1x)). (2.8)

    Since ˆρ=β2A0ˆΦ+ˆC2A0, we obtain

    ˆρ(x)=βˆD2A0(eλ+1)(eλ+1eλxeλ(1x))+ˆC2A0.

    Using the conservation of total mass again, we can show that

    10ˆρ(x)dx=βˆD(λeλ+λ2eλ+2)2A0(eλ+1)λ+ˆC2A0=10ρ0(x)dx.

    Recalling the definition of ˆD (see (2.3)), we have

    ˆC[bβ(λeλ+λ2eλ+2)(bβ2aA0)(eλ+1)λ+1]=2A010ρ0(x)dx,

    which yields

    ˆC=2A0(10ρ0(x)dx)[bβbβ2aA0f1(λ)+1]1,

    where

    f1(λ)=λeλ+λ2eλ+2(eλ+1)λ.

    Therefore,

    ˆρ(x)=ˆC2A0[bβbβ2aA0g1(λ;x)+1],

    where

    g1(λ;x)=eλ+1eλxeλ(1x)eλ+1. (2.9)

    To guarantee ˆρ is bounded from above and below away from zero, we first note f1(λ)(0,1) for λ(0,) and limλ0f1(λ)=0. Second, observe that since a>0, b>0, A0>0 and d>0, then Λ>0 if and only if bβ>2aA0>0. This implies bβbβ2aA0>0. Hence, when a, b, A0 and β are fixed, there exists a small number λ0>0 such that

    1<bβbβ2aA0f1(λ)+1<2,λ(0,λ0).

    This implies

    A010ρ0(x)dx<ˆC<2A010ρ0(x)dx,λ(0,λ0). (2.10)

    Moreover, note that for all x[0,1], it holds that

    0g1(λ;x)g1(λ;1/2)=(eλ21)2eλ+10,asλ0.

    Therefore, there exists a small number λ1>0 such that

    1<bβbβ2aA0g1(λ;x)+1<2,x[0,1],λ(0,λ1),

    which implies

    ˆC2A0<ˆρ(x)<ˆCA0,x[0,1],λ(0,λ1).

    In view of (2.10), we see that

    1210ρ0(x)dx<ˆρ(x)<210ρ0(x)dx,x[0,1],λ(0,min{λ0,λ1}). (2.11)

    Since λ=Λ=bβ2aA02dA0, the smallness of λ can be realized when d is sufficiently large, while a, b, A0 and β are fixed. We also observe that

    dˆρ(x)dx=ˆC2A0bβbβ2aA0λeλx+λeλ(1x)eλ+10,asλ0,d2ˆρ(x)dx2=ˆC2A0bβbβ2aA0λ2eλxλ2eλ(1x)eλ+10,asλ0.

    Hence, the smallness of dˆρ(x)dx and d2ˆρ(x)dx2 can be realized when λ is sufficiently small, or equivalently, when d is large while a, b, A0 and β are fixed.

    Case III. When Λ<0, let λ=Λ. Then we have ˆΦ(x)=Acosλx+Bsinλx+ˆD. Using the boundary conditions, we get A+ˆD=0 and Acosλ+Bsinλ+ˆD=0. Note that B is uniquely determined if λkπ (kN). In this case, we have A=ˆD and B=cosλ1sinλˆD. Hence, ˆΦ is given by

    ˆΦ(x)=ˆD(cosλ1sinλsinλxcosλx+1).

    Following the same spirit as in Case II, we can show that

    ˆρ(x)=ˆC2A0[bβbβ2aA0g2(λ;x)+1], (2.12)

    where

    g2(λ;x)=sinλsinλcosλx+cosλsinλxsinλxsinλ,

    and the constant ˆC is given by

    ˆC=2A0(10ρ0(x)dx)[bβbβ2aA0f2(λ)+1]1,

    where

    f2(λ)=λsinλ2+2cosλλsinλ.

    Note that Λ<0 if and only if bβ<2aA0, and

    bβbβ2aA0{>0ifa>0andβ<0,<0ifa>0andβ>0. (2.13)

    The function f2(λ) satisfies

    limλ0f2(λ)=0andf2(λ)=2(cosλ1)(λsinλ)λ2sin2λ.

    These imply when λ is sufficiently close to zero, f2(λ)<0 is sufficiently small. Regarding the two cases in (2.13), we can show that there exists a small number λ2>0, such that for all λ(0,λ2),

    [bβbβ2aA0f2(λ)+1]{(0.5,1)ifa>0andβ<0,(1,2)ifa>0andβ>0.

    In summary, the constant ˆC satisfies

    A010ρ0(x)dx<ˆC<4A010ρ0(x)dx,λ(0,λ2). (2.14)

    For g2(λ;x), we can show that

    g2(λ;0)=0=g2(λ;1),dg2(λ;x)dx=λ(cosλ(1x)cosλx)sinλ,d2g2(λ;x)dx2=λ2(sinλ(1x)+sinλx)sinλ, (2.15)

    which imply dg2(λ;x)dx=0 when x=0.5, and g2(λ;x) is convex for x[0,1] when λ>0 is sufficiently small. These tell us g2(λ;x)0 for x[0,1] and

    |g2(λ;x)|g2(λ;0.5)=sec0.5λ1,

    when λ>0 is sufficiently small. Hence, there exists a small number λ3>0, such that for all x[0,1],

    [bβbβ2aA0g2(λ;x)+1]{(0.5,1)ifa>0andβ<0,(1,2)ifa>0andβ>0.

    Therefore,

    ˆC4A0<ˆρ(x)<ˆCA0,x[0,1],λ(0,λ3). (2.16)

    Combining (2.14) and (2.16), we see that

    1410ρ0(x)dx<ˆρ(x)<410ρ0(x)dx,x[0,1],λ(0,min{λ2,λ3}).

    In addition, we see from (2.12) and (2.15) that

    |dˆρ(x)dx|0and|d2ˆρ(x)dx2|0asλ0.

    Thus, the smallness of the derivatives of ˆρ can be realized when λ>0 is sufficiently small. Combining the conclusions of the above three cases, we have completed the proof of Lemma 2.1.

    With the preliminary discussions in §2.1, we now state the main results for (1.3). We first introduce some notations for convenience.

    Notation 2.1. Throughout this paper, we use L2, Hs, and L to denote the norms of the standard Lebesgue space L2((0,1)), Hilbert space Hs((0,1)), and Sobolev space L((0,1)), respectively. The total energy, of order sN, of the function f is denoted by

    f(t)2ssk=0(ktf)(t)2Hsk. (2.17)

    In addition, we use (f1,f2,...,fn)2 to denote f12+f22+fn2, where denotes either L2, Hs, L, or s, whenever it is applicable. Unless otherwise specified, C will denote a generic positive constant which is independent of time. The value of the constant may vary line by line according to the context.

    Theorem 2.2. Consider the initial-boundary value problem (1.3), where the parameters satisfy α>0, τ0, d>0, A0>0, a>0, b>0, and βR. Suppose the initial data satisfy ρ0(x)>0 for all x[0,1], (ρ0,u0)[H2((0,1))]2, Φ0H4((0,1)), and are compatible with the boundary conditions. Assume further that there is a small constant ε0>0, such that (u0,ρ0ˆρ)2H2+Φ0ˆΦ2H4ε0, and there is a large constant d0>0, such that the diffusion coefficient dd0. Then there exists a unique solution to (1.3), which satisfies

    (˜ρ,u)(t)22+2k=0(kt˜Φ)(t)2H42k+t0((˜ρ,u)(τ)22+˜Φ(τ)2H4+˜Φt(τ)2H3+˜Φtt(τ)2H1)dτC,t>0,

    where ˜ρ=ρˆρ, ˜Φ=ΦˆΦ, and the constant C>0 is independent of t>0. Moreover, there are positive constants η1 and η2 which are independent of t>0, such that

    (˜ρ,u)(t)22+2k=0(kt˜Φ)(t)2H42kη1eη2t,t>0.

    We prove Theorem 2.2 by applying L2-based energy methods. First of all, it should be mentioned that the local well-posedness of classical solutions to (3.3) can be established by using some classical approaches in the literature, see e.g., [22,23], and we omit the details to simplify the presentation. The bulk of this paper is devoted to deriving the a priori estimates of the local solution, in order to extend it to a global one. We begin the proof with reformulating the first and second equations in (1.3) by using the sound speed transformation to obtain a symmetric hyperbolic system. Note that the boundary data of the spatial derivatives of the solution are unknown. Hence, the direct energy method (differentiating with respect to x, then performing L2-type estimates) is not accessible for the problem under consideration. One of the key steps in the proof is to reduce the estimate of the total (spatial and temporal) derivatives to the temporal ones only, using an iteration scheme based on the structure of the equations. Moreover, note that in the hyperbolic portion of the system, only the dissipation of u appears on the right-hand side of the second equation. We recover the dissipation mechanism of ρ by essentially working a wave-type equation of the function.

    In this section, we give a proof of Theorem 2.2. The proof consists of three major steps: 1) apply the sound speed transformation to symmetrize the first two equations in (1.3); 2) reduce the estimate of the total (spatial and temporal) derivatives of the solution to the temporal ones only; 3) perform L2-based energy estimates. We first present the symmetrization process.

    Since the principle part of the first two equations in (1.3) is hyperbolic, one needs to introduce an appropriate new variable to symmetrize these two equations, after which one can carry out L2-based energy estimates. For this purpose, we let σ=22A0ρ be the sound speed. Then the initial-boundary value problem (1.3) can be written in terms of σ, in the regime of classical solutions, as

    {2σt+2uσx+σux=0,xI, t>0,2ut+2uux+σσx=2αu+2βΦx,xI, t>0,8τA0Φt=8dA0Φxx8aA0Φ+bσ2,xI, t>0;(σ,u,Φ)(x,0)=(22A0ρ0,u0,Φ0)(x),xI;u|x=0,x=1=0,Φ|x=0,x=1=0,t>0. (3.1)

    To perform asymptotic analysis, leading to the global dynamics of the solution to (3.1), we need to write the system of equations in (3.1) in terms of the perturbed variables around the stationary solution. Since the stationary solution satisfies (2.1), letting ˆσ=22A0ˆρ, we can show that

    {ˆσˆσx=2βˆΦx,8dA0ˆΦxx8aA0ˆΦ+bˆσ2=0. (3.2)

    Letting ˜σ=σˆσ and ˜Φ=ΦˆΦ, we update (3.1) by using (3.2) as

    {2˜σt+2u˜σx+˜σux+2uˆσx+ˆσux=0,xI, t>0,2ut+2uux+˜σ˜σx+˜σˆσx+ˆσ˜σx=2αu+2β˜Φx,xI, t>0,8τA0˜Φt=8dA0˜Φxx8aA0˜Φ+b(˜σ+2ˆσ)˜σ,xI, t>0;(˜σ,u,˜Φ)(x,0)=(22A0ρ022A0ˆρ,u0,Φ0ˆΦ)(x),xI;u|x=0,x=1=0,˜Φ|x=0,x=1=0,t>0. (3.3)

    The energy estimates derived in the rest of this section are based on the a priori assumption:

    esssupt[0,T]X(t)esssupt[0,T](˜σ,u,˜Φ)(t)22ε2, (3.4)

    where T>0 denotes the lifespan of the local solution and ε>0 is a small number to be determined later. Note the smallness of ε can be realized by the smallness assumption of the initial perturbation in Theorem 2.2 and the local well-posedness theory. We will focus on deriving the time-independent a priori estimates of the local solution under (3.4), which, when combined with standard continuation argument, will generate the global well-posedness and long-time behavior of the solution in one stroke.

    The rest of the proof consists of two major steps which are contained in two subsections. As was discussed in §2.1, the stationary solution takes on different forms, depending on the sign of bβ2aA0. In the analysis presented below, we shall focus on the case when bβ2aA0>0, in which the stationary solution is given by (2.8)–(2.9). The other case, i.e., bβ2aA00, can be proved in exactly the same fashion, and we omit the details for brevity.

    We first deal with the case of τ>0 in §3.2 and §3.3. The proof of the case of τ=0 will be sketched in §3.4. We begin with the reduction of the total derivatives of the solution to (3.3).

    Lemma 3.1. Let (˜σ,u,˜Φ) be the local solution to the IBVP (3.3) with τ>0 up to some finite time T>0. Assume (3.4) holds for some small ε>0. Then, under the conditions of Theorem 2.2, there exists a constant D0>1, which is independent of t, such that

    X(t)D0X1(t):=D0(˜σt,˜σtt,u,ut,utt,˜Φx,˜Φxt,˜Φtt)(t)2L2. (3.5)

    Proof. Step 1. We first derive a Poincaré-type inequality for ˜σ. From the discussions in §2.1 we infer that when the diffusion coefficient is sufficiently large, the stationary solution ˆρ satisfies (2.11). Denote the spatial integral of ρ0 by ¯ρ (which is positive by the assumptions of Theorem 2.2). Then we have

    12¯ρ<ˆρ<2¯ρ. (3.6)

    According to the definition of ˆσ, we know

    2A0¯ρ<ˆσ<4A0¯ρ. (3.7)

    Note that by definition,

    ˜σ=σˆσ=22A0(ρˆρ)=22A0ρˆρρ+ˆρ. (3.8)

    Since ρ0 is sufficiently close to ˆρ (by assumptions of Theorem 2.2) and ˆρ>12¯ρ>0, from the local well-posedness theory we know ρ(x,t) is positive within the lifespan of the local solution. Using such information, we deduce from (3.8) and (3.6) that

    |˜σ|22A0ˆρ|ρˆρ|4A0¯ρ|ρˆρ|,

    which implies

    ˜σL24A0¯ρρˆρL2. (3.9)

    Since ρˆρ is mean-free, it can be shown that

    ρˆρL2(ρˆρ)xL2. (3.10)

    Since

    ρˆρ=σ2ˆσ28A0=˜σ(˜σ+2ˆσ)8A0,

    we have

    (ρˆρ)x=˜σx(˜σ+2ˆσ)8A0+˜σ(˜σx+2ˆσx)8A0,

    which implies

    (ρˆρ)xL2(˜σL+2ˆσL)˜σxL28A0+(˜σxL+2ˆσxL)˜σL28A0. (3.11)

    Using (3.11), we update (3.10) as

    ρˆρL2(˜σL+2ˆσL)˜σxL28A0+(˜σxL+2ˆσxL)˜σL28A0. (3.12)

    Substituting (3.12) into (3.9), we arrive at

    ˜σL212A0¯ρ[(˜σL+2ˆσL)˜σxL2+(˜σxL+2ˆσxL)˜σL2]12A0¯ρ[(2˜σH1+8A0¯ρ)˜σxL2+(2˜σxH1+2ˆσxL)˜σL2]12A0¯ρ[(2ε+8A0¯ρ)˜σxL2+(2ε+2ˆσxL)˜σL2], (3.13)

    where we used the 1D Sobolev inequality: fL2fH1, (3.4) and (3.7). Since

    ˆσx=2A0ˆρˆρx,

    using (3.6), we can show that

    ˆσxL2A0¯ρˆρxL. (3.14)

    From the discussions in §2.1 we know when d is large enough, ˆρxL is sufficiently small. In this case, we denote (3.14) by

    ˆσxLδ, (3.15)

    where the constant δ decreases as d increases. Using (3.15), we update (3.13) as

    ˜σL212A0¯ρ[(2ε+8A0¯ρ)˜σxL2+(2ε+2δ)˜σL2].

    This implies when ε and δ are sufficiently small, such that

    (2ε+2δ)A0¯ρ, (3.16)

    it holds that

    ˜σL292˜σxL2+12˜σL2.

    Hence,

    ˜σL29˜σxL2. (3.17)

    Step 2. From the first equation of (3.3) we see that

    ux=2˜σ+ˆσ(˜σt+u˜σx+uˆσx). (3.18)

    Using (3.7), Sobolev embedding, (3.4), and (3.16), we deduce that

    ˜σ+ˆσLˆσL˜σL2A0¯ρ2˜σH12A0¯ρ2εA0¯ρ. (3.19)

    Using (3.19), we deduce from (3.18) that

    ux2L212A0¯ρ(˜σt2L2+u2L˜σx2L2+ˆσx2Lu2L2). (3.20)

    Since u satisfies the zero boundary condition, it can be shown that

    uL2uxL2. (3.21)

    Using Sobolev embedding, (3.4), (3.15) and (3.21), we update (3.20) as

    ux2L212A0¯ρ(˜σt2L2+2ε2˜σx2L2+δ2ux2L2). (3.22)

    Now, from the second equation of (3.3) we see that

    ˜σx=1˜σ+ˆσ(2ut+2uux+˜σˆσx+2αu2β˜Φx). (3.23)

    Using (3.19), we can show that

    ˜σx2L25A0¯ρ(4ut2L2+4u2Lux2L2+ˆσx2L˜σ2L2+4α2u2L2+4β2˜Φx2L2). (3.24)

    Using (3.17), we update (3.24) as

    ˜σx2L25A0¯ρ(4ut2L2+8ε2ux2L2+81δ2˜σx2L2+4α2u2L2+4β2˜Φx2L2). (3.25)

    Taking the sum of (3.22) and (3.25) gives us

    ux2L2+˜σx2L21A0¯ρ[20ut2L2+12˜σt2L2+20α2u2L2+20β2˜Φx2L2+(40ε2+12δ2)ux2L2+(24ε2+405δ2)˜σx2L2].

    When ε and δ are sufficiently small, we conclude that

    ux2L2+˜σx2L2C(ut,˜σt,u,˜Φx)2L2. (3.26)

    Step 3. Taking t to (3.18), we obtain

    uxt=2˜σ+ˆσ(˜σtt+ut˜σx+u˜σxt+utˆσx)+2˜σt(˜σ+ˆσ)2(˜σt+u˜σx+uˆσx).

    Using similar arguments as in Step 1, we can derive the following estimate:

    uxt2L232A0¯ρ[˜σtt2L2+(2ε2+δ2)ut2L2+2ε2˜σxt2L2]+48A20¯ρ2(2ε4+ε2+ε2δ2)˜σt2L2. (3.27)

    Taking t to (3.23), we can show that

    ˜σxt2L248A0¯ρ[4utt2L2+8ε2ut2L2+8ε2uxt2L2+δ2˜σt2L2+4α2ut2L2+4β2˜Φxt2L2]+80A20¯ρ2(8ε4+4ε2+ε2δ2+4α2ε2+4β2ε2)˜σt2L2. (3.28)

    Taking the sum of (3.27) and (3.28), we have

    uxt2L2+˜σxt2L216A0¯ρ[2˜σtt2L2+12utt2L2+(28ε2+2δ2+12α2)ut2L2+3δ2˜σt2L2+12β2˜Φxt2L2+24ε2uxt2L2+4ε2˜σxt2L2]+16A20¯ρ2(46ε4+23ε2+8ε2δ2+20α2ε2+20β2ε2)˜σt2L2.

    When ε and δ are sufficiently small, there holds that

    uxt2L2+˜σxt2L2C(utt,˜σtt,ut,˜σt,˜Φxt)2L2. (3.29)

    Step 4. Taking x to (3.18) and using Poincaré inequality for u, we can derive the following estimate:

    uxx2L220A0¯ρ(˜σxt2L2+(2ε2+δ2+ˆσxx2L)ux2L2+2ε2˜σxx2L2)+24A20¯ρ2(2ε2+δ2)(˜σt2L2+(2ε2+δ2)ux2L2). (3.30)

    Note that

    ˆσxx=2A0ˆρˆρxx2A02ˆρˆρ(ˆρx)2.

    From the discussions in §2.1 we know that ˆρx and ˆρxx are small when d is large. Hence, as in (3.15), we may assume ˆσxxLδ, as well. Then, we update (3.30) as

    uxx2L2C(˜σxt2L2+˜σt2L2+ux2L2+ε2˜σxx2L2). (3.31)

    Next, taking x to (3.23) and using (3.17), we can show that

    ˜σxx2L2C(uxt2L2+ut2L2+ux2L2+˜σx2L2+˜Φxx2L2+˜Φx2L2+ε2uxx2L2). (3.32)

    Taking the sum of (3.31) and (3.32) gives us

    uxx2L2+˜σxx2L2C(uxt2L2+˜σxt2L2+ut2L2+˜σt2L2+ux2L2+˜σx2L2+˜Φxx2L2+˜Φx2L2+ε2(˜σxx2L2+uxx2L2)). (3.33)

    It is clear that when ε is small, we can update (3.33) as

    uxx2L2+˜σxx2L2C(uxt2L2+˜σxt2L2+(ux2L2+˜σx2L2)+ut2L2+˜σt2L2+˜Φxx2L2+˜Φx2L2). (3.34)

    By (3.26) and (3.29), we further update (3.34) as

    uxx2L2+˜σxx2L2C(utt2L2+˜σtt2L2+ut2L2+˜σt2L2+u2L2+˜Φxt2L2+˜Φx2L2+˜Φxx2L2). (3.35)

    Step 5. Since ˜Φ and ˜Φt satisfy the zero boundary condition, it follows from Poincaré inequality that

    ˜Φ2L2˜Φx2L2and˜Φt2L2˜Φxt2L2. (3.36)

    Moreover, using (3.36), (3.17) and (3.26), we can deduce from the third equation of (3.3) that

    ˜Φxx2L2C(˜Φxt,˜Φx,ut,˜σt,u)2L2. (3.37)

    Substituting (3.37) into (3.35), we get

    uxx2L2+˜σxx2L2C(utt,˜σtt,ut,˜σt,u,˜Φxt,˜Φx)2L2. (3.38)

    Combining (3.17), (3.26), (3.29), (3.36), (3.37) and (3.38), we arrive at (3.5). This completes the proof of the lemma.

    In this subsection, we examine the quantity X1(t) defined in (3.5) and derive the desired energy estimates, along with the exponential decaying of the perturbed solution.

    Lemma 3.2. Let (˜σ,u,˜Φ) be the local solution to the IBVP (3.3) with τ>0 up to some finite time T>0. Then under the conditions of Theorem 2.2, the quantity

    (˜σ,u)(t)22+2k=0(kt˜Φ)(t)2H42k+t0((˜σ,u)(τ)22+˜Φ(τ)2H4+˜Φt(τ)2H3+˜Φtt(τ)2H1)dτ

    is uniformly bounded with respect to t>0, and (˜σ,u)(t)22+2k=0(kt˜Φ)(t)2H42k decays exponentially rapidly to zero as t.

    Proof. Step 1. Taking L2 inner product of the first equation in (3.3) with ˜σ, we have

    ddt˜σ2L2=210u˜σx˜σdx10˜σ2uxdx210uˆσx˜σdx10ˆσux˜σdx=210uˆσx˜σdx10ˆσux˜σdx, (3.39)

    where we used the zero boundary condition for u. Taking L2 inner product of the second equation in (3.3) with u gives us

    ddtu2L2+2αu2L2=210u2uxdx10˜σ˜σxudx10˜σˆσxudx10ˆσ˜σxudx+2β10˜Φxudx=10˜σ˜σxudx10˜σˆσxudx10ˆσ˜σxudx+2β10˜Φxudx. (3.40)

    Taking the sum of (3.39) and (3.40), we obtain

    ddt(˜σ2L2+u2L2)+2αu2L2=210uˆσx˜σdx10˜σ˜σxudx+2β10˜Φxudx(2ˆσxL+˜σxL)uL2˜σL2+2β˜ΦxL2uL2. (3.41)

    Since, by Young's inequality,

    2β˜ΦxL2uL2αu2L2+α1β2˜Φx2L2,

    we update (3.41) as

    ddt(˜σ2L2+u2L2)+αu2L2(2ˆσxL+˜σxL)uL2˜σL2+α1β2˜Φx2L2.

    By Sobolev embedding and Cauchy-Schwarz inequality, we can show that

    ddt(˜σ2L2+u2L2)+αu2L2(δ+212ε)(u2L2+˜σ2L2)+α1β2˜Φx2L2, (3.42)

    where we used (3.15) and (3.4).

    Step 2. Taking t to the three equations in (3.3), we have

    {2˜σtt+2ut˜σx+2u˜σxt+˜σtux+˜σuxt+2utˆσx+ˆσuxt=0,2utt+2utux+2uuxt+˜σt˜σx+˜σ˜σxt+˜σtˆσx+ˆσ˜σxt=2αut+2β˜Φxt,8τA0˜Φtt=8dA0˜Φxxt8aA0˜Φt+2b(˜σ+ˆσ)˜σt. (3.43)

    Taking L2 inner product of the first equation in (3.43) with ˜σt, we have

    ddt˜σt2L2=210ut˜σx˜σtdx210u˜σxt˜σtdx10˜σ2tuxdx10˜σuxt˜σtdx210utˆσx˜σtdx10ˆσuxt˜σtdx=10˜σxut˜σtdx+10˜σut˜σxtdx10utˆσx˜σtdx+10ˆσut˜σxtdx. (3.44)

    Taking L2 inner product of the second equation in (3.43) with ut, we obtain

    ddtut2L2+2αut2L2=210uxu2tdx210uuxtutdx10˜σt˜σxutdx10˜σ˜σxtutdx10˜σtˆσxutdx10ˆσ˜σxtutdx+2β10˜Φxtutdx=10uxu2tdx10˜σt˜σxutdx10˜σ˜σxtutdx10˜σtˆσxutdx10ˆσ˜σxtutdx+2β10˜Φxtutdx. (3.45)

    Taking the sum of (3.44) and (3.45), we arrive at

    ddt(˜σt2L2+ut2L2)+2αut2L2=210(˜σx+ˆσx)ut˜σtdx10uxu2tdx+2β10˜Φxtutdx2(˜σxL+ˆσxL)utL2˜σtL2+uxLut2L2+2β˜ΦxtL2utL2.

    Similar to (3.42), it can be shown that

    ddt(˜σt2L2+ut2L2)+αut2L2(δ+212ε)(ut2L2+˜σt2L2)+2εut2L2+α1β2˜Φxt2L2. (3.46)

    In completely the same fashion, we can show that

    ddt(˜σtt2L2+utt2L2)+αutt2L2(δ+2ε)(utt2L2+˜σtt2L2)+32ε(utt2L2+uxt2L2+˜σtt2L2+˜σxt2L2)+α1β2˜Φxtt2L2. (3.47)

    Step 3. Taking L2 inner product of the third equation in (3.3) with ˜Φxx, we have

    ddt(4τA0˜Φx2L2)+8dA0˜Φxx2L2+8aA0˜Φx2L2=b10(˜σ+2ˆσ)˜σ˜Φxxdx2b(˜σL+ˆσL)˜σL2˜ΦxxL2. (3.48)

    By Cauchy-Schwarz inequality, we update (3.48) as

    ddt(4τA0˜Φx2L2)+8dA0˜Φxx2L2+8aA0˜Φx2L2b2dA0(˜σL+ˆσL)2˜σ2L2+dA0˜Φxx2L22b2dA0(˜σ2L+ˆσ2L)˜σ2L2+dA0˜Φxx2L2,

    which implies, by (3.7),

    ddt(˜Φx2L2)+7d4τ˜Φxx2L2+2aτ˜Φx2L2b2τdA20(8A0¯ρ+ε2)˜σ2L2. (3.49)

    Similarly, by taking L2 inner product of the third equation in (3.43) with ˜Φxxt, we can show that

    ddt(˜Φxt2L2)+7d4τ˜Φxxt2L2+2aτ˜Φxt2L2b2τdA20(8A0¯ρ+ε2)˜σt2L2. (3.50)

    Moreover, taking t to the third equation in (3.43), then taking L2 inner product of the resulting equation with ˜Φtt, it can be shown that

    ddt(˜Φtt2L2)+7d4τ˜Φxtt2L2+2aτ˜Φtt2L2b2τA0˜σtH1˜σtL2˜ΦttL2+b2τdA20(8A0¯ρ+ε2)˜σtt2L2. (3.51)

    For the first term on the right-hand side of (3.51), we have

    b2τA0˜σtH1˜σtL2˜ΦttL2b2τA0˜σtH1˜σtL2˜ΦxttL2b22τdA20˜σt2H1˜σt2L2+d4τ˜Φxtt2L2,

    where we applied Poincaré inequality. Then we update (3.51) as

    ddt(˜Φtt2L2)+3d2τ˜Φxtt2L2+2aτ˜Φtt2L2b22τdA20˜σt2H1˜σt2L2+b2τdA20(8A0¯ρ+ε2)˜σtt2L2. (3.52)

    Step 4. Taking the sum of (3.42), (3.46), and (3.47) gives us

    ddt((˜σ,˜σt,˜σtt,u,ut,utt)2L2)+α(u,ut,utt)2L2(δ+42ε)X(t)+α1β2(˜Φx,˜Φxt,˜Φxtt)2L2. (3.53)

    Taking the sum of (3.49), (3.50) and (3.52), we obtain

    ddt((˜Φx,˜Φxt,˜Φtt)2L2)+3d2τ(˜Φxx,˜Φxxt,˜Φxtt)2L2b2τdA20(8A0¯ρ+ε2)X(t), (3.54)

    where we threw away the non-negative terms involving a. Taking the sum of (3.53) and (3.54), and using the definition of X1(t) (c.f. (3.5)), we obtain

    ddt(˜σ(t)2L2+X1(t))+α(u,ut,utt)2L2+3d2τ(˜Φxx,˜Φxxt,˜Φxtt)2L2(δ+42ε)X(t)+b2τdA20(8A0¯ρ+ε2)X(t)+α1β2(˜Φx,˜Φxt,˜Φxtt)L2. (3.55)

    Note that by Poincaré inequality, we have ˜ΦxL2˜ΦxxL2 and ˜ΦxtL2˜ΦxxtL2. Hence, using the assumption that d>0 is sufficiently large, we update (3.55) as

    ddt(˜σ(t)2L2+X1(t))+α(u,ut,utt)2L2+dτ(˜Φxx,˜Φxxt,˜Φxtt)2L2(δ+42ε)X(t)+b2τdA20(8A0¯ρ+ε2)X(t). (3.56)

    Again, by Poincaré inequality, we deduce from (3.56) that

    ddt(˜σ(t)2L2+X1(t))+α(u,ut,utt)2L2+d2τ(˜Φx,˜Φxt,˜Φtt,˜Φxx,˜Φxxt,˜Φxtt)2L2(δ+42ε)X(t)+b2τdA20(8A0¯ρ+ε2)X(t). (3.57)

    Step 5. Taking L2 inner product of the first equation in (3.43) with ˜σ, we obtain

    ddt(10˜σ˜σtdx)+˜σt2L2=1210(2ut˜σx+2u˜σxt+˜σtux+˜σuxt+2utˆσx+ˆσuxt)˜σdx. (3.58)

    For the integral involving the first five integrands on the right-hand side of (3.58), we can show that

    |1210(2ut˜σx+2u˜σxt+˜σtux+˜σuxt+2utˆσx)˜σdx|12(˜σL+ˆσxL)X(t)12(2ε+δ)X(t). (3.59)

    For the integral of the last integrand, using integration by parts, we have

    |1210ˆσuxt˜σdx|=12|10(ˆσxut˜σ+ˆσut˜σx)dx|δ4X(t)+A0¯ρ(ut2L2+˜σx2L2). (3.60)

    Similar to (3.25), we can derive the following estimate:

    ˜σx2L25A0¯ρ(4ut2L2+8ε2u2L2+81δ2˜σx2L2+4α2u2L2+4β2˜Φx2L2). (3.61)

    Since δ is small, we update (3.61) as

    ˜σx2L2C(ut2L2+u2L2+˜Φx2L2). (3.62)

    Substituting (3.62) into (3.60), we obtain

    |1210ˆσuxt˜σdx|δ4X(t)+D1(ut,u,˜Φx)2L2, (3.63)

    where the constant D1 depends only on A0, ¯ρ. Substituting (3.59) and (3.63) into (3.58) gives us

    ddt(10˜σ˜σtdx)+˜σt2L2(22ε+34δ)X(t)+D1(ut,u,˜Φx)2L2.

    Next, taking t to the first equation in (3.43), then taking L2 inner product of the resulting equation with ˜σt, we get

    ddt(10˜σt˜σttdx)+˜σtt2L2=1210(2ut˜σx+2u˜σxt+˜σtux+˜σuxt+2utˆσx+ˆσuxt)t˜σtdx. (3.64)

    For the integral involving the first five integrands on the right-hand side of (3.64), using integration by parts, we can show that

    1210(2ut˜σx+2u˜σxt+˜σtux+˜σuxt+2utˆσx)t˜σtdx=1210(2˜σxutt+4ut˜σxt+ux˜σtt+2˜σtuxt+2ˆσxutt)˜σtdx+1210(2u˜σxtt+˜σuxtt)˜σtdx=1210(˜σxutt+4ut˜σxtux˜σtt+2˜σtuxt+2ˆσxutt)˜σtdx1210(2u˜σtt+˜σutt)˜σxtdx.

    Similar to (3.59), we have

    |1210(2ut˜σx+2u˜σxt+˜σtux+˜σuxt+2utˆσx)t˜σtdx|(˜σxL+uxL+˜σtL+utL+˜σL+uL+ˆσxL)X(t)(23ε+δ)X(t). (3.65)

    For the integral of the last integrand on the right-hand side of (3.64), we deduce that

    |1210ˆσuxtt˜σtdx|=12|10(ˆσxutt˜σt+ˆσutt˜σxt)dx|δ4X(t)+A0¯ρ(utt2L2+˜σxt2L2).

    According to (3.27) and (3.28), we know

    ˜σxt2L2C(utt,ut,˜Φxt)2L2+Cεuxt2L2+C(ε+δ)˜σt2L2 (3.66)

    and

    uxt2L2C˜σtt2L2+C(ε+δ)(ut,˜σt)2L2+Cε˜σxt2L2. (3.67)

    Substituting (3.67) into (3.66), we obtain

    ˜σxt2L2C(utt,ut,˜Φxt)2L2+Cε˜σtt2L2+C(ε+δ)˜σt2L2+Cε˜σxt2L2. (3.68)

    When ε is sufficiently small, we update (3.68) as

    ˜σxt2L2C(utt,ut,˜Φxt)2L2+Cε˜σtt2L2+C(ε+δ)˜σt2L2. (3.69)

    Substituting (3.65) and (3.69) into (3.64), we arrive at

    ddt(10˜σt˜σttdx)+˜σtt2L2(23ε+54δ)X(t)+C(utt,ut,˜Φxt)2L2+Cε˜σtt2L2+C(ε+δ)˜σt2L2. (3.70)

    When ε and δ are sufficiently small, we update (3.70) as

    ddt(10(˜σ˜σt+˜σt˜σtt)dx)+12(˜σt,˜σtt)2L2(23ε+54δ)X(t)+D2(utt,ut,u,˜Φx,˜Φxt)2L2. (3.71)

    We observe from (3.27), (3.28), and (3.62) that when ε and δ are sufficiently small, the constant D2 depends only on A0, ¯ρ, α, and β.

    Step 6. Note that the dissipations in (3.57) and (3.71) contain a quantity that is equivalent to X1(t) defined in (3.5). Hence, we shall make a coupling of (3.57) and (3.71) to close the overall energy estimates to capture the global dynamics of the perturbed solution. However, direct summation of (3.57) and (3.71) is problematic, as some leading terms are standing on the right-hand side of (3.71) and the summation of the terms inside the time derivatives does not cover the total H2-norm of ˜σ. To overcome such a technical difficulty, we shall require d>0 to be large enough, such that

    4τD2d12, (3.72)

    and let

    χ=max{2, 2D2α1}. (3.73)

    Dividing (3.71) by χ, we get

    ddt(10(˜σ˜σt+˜σt˜σtt)χdx)+12χ(˜σt,˜σtt)2L21χ(23ε+54δ)X(t)+D2χ(utt,ut,u,˜Φx,˜Φxt)2L2. (3.74)

    Taking the sum of (3.57) and (3.74) gives us

    ddt(V(t))+W(t)θX(t), (3.75)

    where

    V(t)˜σ(t)2L2+X1(t)10(˜σ˜σt+˜σt˜σtt)χdx,W(t)α(u,ut,utt)2L2+d2τ(˜Φx,˜Φxt,˜Φtt,˜Φxx,˜Φxxt,˜Φxtt)2L2+12χ(˜σt,˜σtt)2L2,D2χ(utt,ut,u,˜Φx,˜Φxt)2L2,θδ+42ε+b2τdA20(8A0¯ρ+ε2)X(t)+1χ(23ε+54δ).

    Note that under (3.72) and (3.73),

    D2χ(utt,ut,u,˜Φx,˜Φxt)2L2=D2χ(utt,ut,u)2L2+D2χ(˜Φx,˜Φxt)2L2α2(utt,ut,u)2L2+d4τ(˜Φx,˜Φxt)2L2. (3.76)

    Hence, it follows from the definition of X1(t) that

    W(t)α2(u,ut,utt)2L2+d4τ(˜Φx,˜Φxt,˜Φtt)2L2+12χ(˜σt,˜σtt)2L2+d2τ(˜Φxx,˜Φxxt,˜Φxtt)2L2D3X1(t)+d2τ(˜Φxx,˜Φxxt,˜Φxtt)2L2, (3.77)

    where

    D3=min{α2, d4τ, 12χ}.

    Since χ2, from the definition of V(t) we see that

    V(t)(˜σ,˜σt,˜σtt)2L214(˜σ2L2+2˜σt2L2+˜σtt2L2)+(u,ut,utt,˜Φx,˜Φxt,˜Φtt)2L2=14(3˜σ2L2+2˜σt2L2+3˜σtt2L2)+(u,ut,utt,˜Φx,˜Φxt,˜Φtt)2L212(˜σ,˜σt,˜σtt,u,ut,utt,˜Φx,˜Φxt,˜Φtt)2L2=12˜σ2L2+12X1(t). (3.78)

    Using Lemma 3.1 and (3.77), we update (3.75) as

    ddt(V(t))+D3X1(t)+d2τ(˜Φxx,˜Φxxt,˜Φxtt)2L2θD0X1(t),

    Since δ0 as d, from the definition of θ we see that θ0 as ε0 and d. Hence, when ε is sufficiently small and d is sufficiently large, it holds that

    ddt(V(t))+D32X1(t)+d2τ(˜Φxx,˜Φxxt,˜Φxtt)2L20. (3.79)

    Integrating (3.79) with respect to t, we obtain

    V(t)+t0(D32X1(t)+d2τ(˜Φxx,˜Φxxt,˜Φxtt)(t)2L2)V(0). (3.80)

    Since, according to (3.78) and Lemma 3.1, 12X1(t)V(t)X(t)D0X1(t), the estimate (3.80) yields

    (˜σ,u,˜Φ)(t)22+t0((˜σ,u,˜Φ)(τ)22+(˜Φxxt,˜Φxtt)(τ)2L2)dτD4,t>0, (3.81)

    where the constant D4 is independent of t. Moreover, using the third equation in (3.3) and Poincaré inequality, we can show that

    ˜Φxxx2L2(˜Φxt,˜Φx,˜σx,˜σ)2L2, (3.82)
    ˜Φxxxx2L2(˜Φxxt,˜Φxx,˜σxx,˜σx,˜σ)2L2(˜Φtt,˜Φt,˜σt)2L2, (3.83)
    ˜Φxxxt2L2(˜Φxtt,˜Φxt,˜σxt,˜σt)2L2.

    Hence, it follows from (3.81), (3.82), and (3.83) that

    (˜σ,u)(t)22+2k=0(kt˜Φ)(t)2H42k+t0((˜σ,u)(τ)22+˜Φ(τ)2H4+˜Φt(τ)2H3+˜Φtt(τ)2H1)dτD5,t>0,

    for some constant D5 which is independent of t.

    To derive the exponential decaying of the perturbation, we note that by dropping the non-negative term d2τ(˜Φxx,˜Φxxt,˜Φxtt)(t)2L2 from the left-hand side of (3.79), and using the equivalency of V(t) and X1(t), it holds that

    ddt(V(t))+D32D0V(t)0,

    which yields the exponential decaying of V(t), and hence of X(t). Moreover, the exponential decaying of 2k=0(kt˜Φ)(t)2H42k follows from the decaying of X(t) and (3.82)–(3.83). This completes the proof of Lemma 3.2.

    In this subsection, we mainly consider the case of τ=0 in (3.3):

    {2˜σt+2u˜σx+˜σux+2uˆσx+ˆσux=0,xI, t>0,2ut+2uux+˜σ˜σx+˜σˆσx+ˆσ˜σx=2αu+2β˜Φx,xI, t>0,8dA0˜Φxx8aA0˜Φ+b(˜σ+2ˆσ)˜σ=0,xI, t>0;(˜σ,u)(x,0)=(22A0ρ022A0ˆρ,u0)(x),xI;u|x=0,x=1=0,˜Φ|x=0,x=1=0,t>0. (3.84)

    In this case, instead of X(t) defined by (3.4), we let

    Y(t)(˜σ,u)(t)22,

    and derive the a priori estimates based on the assumptions that (1) Y(t) is sufficiently small within the lifespan of the local solution, and (2) the diffusion coefficient d is sufficiently large.

    First, by using the third equation in (3.85), we can modify the proof of Lemma 3.1 to get the qualitative equivalency of Y(t) and (˜σt,˜σtt,u,ut,utt)(t)2L2. Indeed, using Sobolev embedding, (3.7), (3.16) and Poincaré inequality, it can be shown that

    8dA0˜Φx2L2+8aA0˜Φ2L2b˜σ+ˆσL˜σL2˜ΦL25bA0¯ρ˜σL2˜ΦxL2Cd˜σ2L2+4dA0˜Φx2L2,

    which implies

    ˜Φx2L2Cd2˜σ2L2Cd2˜σx2L2, (3.85)

    where we also used (3.17). Substituting (3.85) into (3.25), we obtain

    ˜σx2L2C(ut2L2+ε2ux2L2+δ2˜σx2L2+α2u2L2+d2˜σx2L2). (3.86)

    Taking the sum of (3.86) and (3.22) gives us

    ˜σx2L2+ux2L2C[ut2L2+u2L2+˜σt2L2+(ε2+δ2)ux2L2+(ε2+δ2+d2)˜σx2L2].

    Hence, when ε and δ are sufficiently small and d is sufficiently large, such that the coefficients in front of ux2L2 and ˜σx2L2 are smaller than 12, there holds that

    ˜σx2L2+ux2L2C(ut2L2+u2L2+˜σt2L2). (3.87)

    Similarly, it follows from the elliptic equation that

    ˜Φxt2L2Cd2˜σt2L2and˜Φxx2L2Cd2˜σx2L2, (3.88)

    by using which we can show that

    uxt2L2+˜σxt2L2C(utt,˜σtt,ut,˜σt)2L2,

    and

    uxx2L2+˜σxx2L2C(utt,˜σtt,ut,˜σt,u)2L2.

    Hence,

    Y(t)Y1(t)(˜σt,˜σtt,u,ut,utt)(t)2L2.

    Regarding Lemma 3.2, it follows from the elliptic equation that

    ˜ΦxttL2ε2d2˜σt2L2+1d2˜σtt2L2. (3.89)

    Similar to (3.53), by using (3.85), (3.87), (3.88), and (3.89), we can derive the following estimate:

    ddt((˜σ,˜σt,˜σtt,u,ut,utt)2L2)+α(u,ut,utt)2L2O(ε,δ,d1)Y(t). (3.90)

    Similar to (3.71) and using the modified estimates in this section, it can be shown that

    ddt(10(˜σ˜σt+˜σt˜σtt)dx)+12(˜σt,˜σtt)2L2O(ε,δ,d1)Y(t)+O(1)(utt,ut,u)2L2. (3.91)

    By coupling (3.90) and (3.91) together, and using the smallness of ε, δ and the largeness of d, we can derive the exponential decaying of Y1(t), and hence equivalently of Y(t). Moreover, it follows from the elliptic equation that

    2k=0(kt˜Φ)(t)2H4k˜σ(t)22,

    which yields the exponential decaying of ˜Φ in the corresponding topology. Thus, the proof of Theorem 2.2 is completed.

    The authors are grateful to four referees for their valuable comments, which greatly improved the exposition of our paper. H.Y. Peng was partially supported by the National Natural Science Foundation of China (No. 12271112). The research of K. Zhao was partially supported by the Simons Foundation's Collaboration Grant for Mathematicians (No. 413028).

    The authors declare there is no conflict of interest.



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