Research article

Multiple solutions for nonlocal elliptic problems driven by p(x)-biharmonic operator

  • In this article, we study the existence of at least three distinct weak solutions for nonlocal elliptic problems involving p(x)-biharmonic operator. The results are obtained by means of variational methods. We also provide an example in order to illustrate our main abstract results. We extend and improve some recent results.

    Citation: Fang-Fang Liao, Shapour Heidarkhani, Shahin Moradi. Multiple solutions for nonlocal elliptic problems driven by p(x)-biharmonic operator[J]. AIMS Mathematics, 2021, 6(4): 4156-4172. doi: 10.3934/math.2021246

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  • In this article, we study the existence of at least three distinct weak solutions for nonlocal elliptic problems involving p(x)-biharmonic operator. The results are obtained by means of variational methods. We also provide an example in order to illustrate our main abstract results. We extend and improve some recent results.



    In this paper we study the existence of at least three distinct weak solutions for the following problem

    {T(u)=λf(x,u(x)),in Ω,u=Δu=0,on Ω,                        (Pfλ)

    where

    T(u)=Δ2p(x)u(x)M(Ω|u(x)|p(x)dxp(x))Δp(x)u(x)+ρ(x)|u(x)|p(x)2u(x),

    ΩRN(N2) is an open bounded domain with smooth boundary, Δ2p(x)u is the operator defined as Δ(|Δu|p(x)2Δu) and is called the p(x)-biharmonic which is a generalization of the p-biharmonic, p(x)C(¯Ω), ρ(x)L(Ω), M:[0,+)R is a continuous function such that there are two positive constants m0 and m1 with m0M(t)m1 for all t0, N2<p:= essinfxΩp(x)p+:= esssupxΩp(x)<, λ>0 and f:Ω×RR is an L1-Carathéodory function.

    The Kirchhoff equation refers back to Kirchhoff [18] in 1883 in the study on the oscillations of stretched strings and plates, suggested as an extended version of the classical D'Alembert's wave equation by taking into account the effects of the changes in the length of the string during the vibrations. Kirchhoff's equation like problem (Pfλ) model several physical and biological systems where u describes a process which depend on the average of itself. Lions in [23] has proposed an abstract framework for the Kirchhoff-type equations. After the work by Lions, various problems of Kirchhoff-type have been widely investigated, we refer the reader to the papers [7,24,27] and the references therein.

    The main interest in studying problem (Pfλ) is given by the presence of the variable exponent p(). Problems involving such kind of growth conditions benefited by a special attention in the last decade since they can model with sufficient accuracy phenomena arising in different branches of science. Two important models where operators involving variable exponents were considered come from the study of electrorheological fluids [8,28] and elastic mechanics [34].

    Fourth-order equations have various applications in areas of applied mathematics and physics such as micro-electro-mechanical systems, phase field models of multi-phase systems, thin film theory, thin plate theory, surface diffusion on solids, interface dynamics, flow in Hele-Shaw cells (see [4,6,26]). The fourth-order equation can also describe the static form change of beam or the sport of rigid body. In [22], Lazer and Mckenna have pointed out that this type of nonlinearity furnishes a model to study travelling waves in suspension bridges. Numerous authors investigated the existence and multiplicity of solutions for the problems involving p(x)-biharmonic operators. We refer to [10,12,16,19,21,30,31]. In the last decade, Kirchhoff type equations involving the p(x)-Laplacian have been investigated, for instance see [3,9,13,14,15,17,25].

    In this paper, we are interested to discuss the existence of at least three distinct weak solutions for problem (Pfλ). No asymptotic condition at infinity is required on the nonlinear term. In Theorem 3.1 we establish the existence of at least three distinct weak solutions for problem (Pfλ). Theorem 3.3 is a consequence of Theorem 3.1. As a consequence of Theorem 3.3, we obtain Theorem 3.4 for the autonomous case. We present example 3.5 to illustrate Theorem 3.4.

    Let X be a nonempty set and Φ,Ψ:XR be two functions. For all r, r1, r2>infXΦ, r2>r1, r3>0, we define

    φ(r):=infuΦ1(,r)(supuΦ1(,r)Ψ(u))Ψ(u)rΦ(u),
    β(r1,r2):=infuΦ1(,r1)supvΦ1[r1,r2)Ψ(v)Ψ(u)Φ(v)Φ(u),
    γ(r2,r3):=supuΦ1(,r2+r3)Ψ(u)r3,
    α(r1,r2,r3):=max{φ(r1),φ(r2),γ(r2,r3)}.

    We shall discuss the existence of at least three distinct solutions to the problem (Pfλ). Our main tool is based on [1,Theorem 3.3] that we now recall as follows:

    Theorem 2.1. Let X be a reflexive real Banach space, Φ:XR be a convex, coercive and continuously Gâteaux differentiable functional whose Gâteaux derivative admits a continuous inverse on X,Ψ:XR be a continuously Gâteaux differentiable functional whose Gâteaux derivative is compact, such that infXΦ=Φ(0)=Ψ(0)=0 and for every u1,u2X such that Ψ(u1)0 and Ψ(u2)0, one has

    infs[0,1]Ψ(su1+(1s)u2)0.

    Assume that there are three positive constants r1,r2,r3 with r1<r2, such that

    (c1) φ(r1)<β(r1,r2);

    (c2) φ(r2)<β(r1,r2);

    (c3) γ(r2,r3)<β(r1,r2).

    Then for each λ(1β(r1,r2),1α(r1,r2,r3)) the functional ΦλΨ admits three distinct critical points u1,u2,u3 such that u1Φ1(,r1), u2Φ1[r1,r2) and u3Φ1(,r2+r3).

    We refer the interested reader to the papers [2,11,20] in which Theorem 2.1 has been successfully used to ensure the existence of at least three solutions for boundary value problems.

    Let Ω be a bounded domain of RN, denote:

    Lp(x)(Ω):={u:ΩR measurable and Ω|u(x)|p(x)dx<+}.

    We can introduce the norm on Lp(x)(Ω) by:

    uLp(x)(Ω)=inf{β>0:Ω|u(x)β|p(x)dx1}.

    Let X be the generalized Lebesgue-Sobolev space Wm,p(x)(Ω) defined by putting Wm,p(x)(Ω) as

    Wm,p(x)(Ω)={uLp(x)(Ω)|DγuLp(x)(Ω), |γ|m, mZ+},

    which is equipped with the norm:

    um,p(x):=|γ|m|Dγu|p(x) (2.1)

    γ is the multi-index and |γ| is the order.

    The closure of C0(Ω) in Wm,p(x)(Ω) is the Wm,p(x)0(Ω). It is well known [5] that, both Lp(x)(Ω) and Wm,p(x)(Ω), with the respective norms, are separable, reflexive and uniformly convex Banach spaces.

    Proposition 2.2. [5] Suppose 1p(x)+1p0(x)=1, then Lp0(x)(Ω) and Lp(x)(Ω) are conjugate space, and satisfy the Hölder inequality:

    |Ωuvdx|(1p+1(p0))|u|p(x)|v|p0(x),uLp(x)(Ω), vLp0(x)(Ω).

    We denote X:=W1,p(x)0(Ω)W2,p(x)(Ω) and has the norm

    u=inf{σ>0:Ω(|u(x)σ|p(x)+|u(x)σ|p(x)+|Δu(x)σ|p(x))dx1}.

    By [32], , 2,p() and |Δu|p() are equivalent norms of X.

    A bounded operator T:XR is said to be compact if T(BX) has compact closure in R.

    Proposition 2.3. [31] When p>N2, ΩR is a bounded region, then XC(¯Ω) is a compact embedding.

    According to 2.3, for each uX, there exists a constant c>0 that depends on p(),N,Ω:

    u=supxΩ|u(x)|cu. (2.2)

    Remark 2.4. We say that f:Ω×RR is an L1-Carathéodory function if

    (a) tf(x,t) is measurable for every tR;

    (b) xf(x,t) is continuous for a.e. xΩ;

    (c) for every ε>0 there exists a function lεL1(Ω) such that for a.e. xΩ,

    sup|t|ε|f(x,t)|lε(x).

    Corresponding to the functions f and M, we introduce the functions F:Ω×RR and ˜M:[0,+)R, respectively, as follows

    F(x,t)=t0f(x,ξ)dξ  for all (x,t)Ω×R,
    ˜M(t)=t0M(ξ)dξ  for all t0.

    We say that uX is a weak solution of problem (Pfλ) if for every vX,

    Ω|Δu(x)|p(x)2Δu(x)Δv(x)dx+M(Ω|u(x)|p(x)p(x)dx)Ω|u(x)|p(x)2u(x)v(x)dx+Ωρ(x)|u(x)|p(x)2u(x)v(x)dxλΩf(x,u(x))v(x)dx=0.

    Proposition 2.5. [5] Let J(u)=Ω|u|p(x)dx for each uLp(x)(Ω), we have

    (1) |u|p(x)<1(=1;>1)J(u)<1(=1;>1);

    (2) |u|p(x)1|u|pp(x)J(u)|u|p+p(x);

    (3) |u|p(x)1|u|p+p(x)J(u)|u|pp(x);

    (4) |u|p(x)0J0.

    Now for every uX, we define I(u):=Φ(u)λΨ(u) where

    Φ(u)=Ω|Δu(x)|p(x)p(x)dx+˜M(Ω|u(x)|p(x)p(x)dx)+Ωρ(x)|u(x)|p(x)p(x)dx, (2.3)

    and

    Ψ(u)=ΩF(x,u(x))dx. (2.4)

    For our convenience, set

    ρ0=minxΩρ(x),M=min{1,m0,ρ0}andM+=max{1,m1,ρ}.

    Proposition 2.6. Let T=Φ:XX be the operator defined by

    T(u)(v)=Ω|Δu(x)|p(x)2Δu(x)Δv(x)dx+M(Ω|u(x)|p(x)p(x)dx)Ω|u(x)|p(x)2u(x)v(x)dx+Ωρ(x)|u(x)|p(x)2u(x)v(x)

    for every u,vX. Then T admits a continuous inverse on X.

    Proof. For any uX{0},

    limuT(u),uu=limuΩ|Δu(x)|p(x)dx+M(Ωu(x)|p(x)p(x)dx)Ω|u(x)|p(x)dx+Ωρ(x)|u(x)|p(x)dxulimuMupu=limuMup1,

    since p>1, it follows that the map T is coercive. Since T is the Fréchet derivative of Φ, it follows that T is continuous and bounded. Using the elementary inequality [29]

    |xy|γ2γ(|x|γ2x|y|γ2y)(xy)if γ2,

    for all (x,y)RN×RN, N1, we obtain for all u,vX such that uv,

    T(u)T(v),uv>0,

    which means that T is strictly monotone. Thus T is injective. Consequently, thanks to Minty-Browder theorem [33], the operator T is a surjection and admits an inverse mapping. Thus it is sufficient to show that T1 is continuous. For this, let (vn)n=1 be a sequence in X such that vnv in X. Let un and u in X such that

    T1(vn)=unandT1(v)=u.

    By the coercivity of T, we conclude that the sequence (un) is bounded in the reflexive space X. For a subsequence, we have un˜u in X, which implies

    limnT(un)T(u),un˜u=limnfnf,un˜u=0.

    Therefore, by the continuity of T, we have

    un˜uin XandT(un)T(˜u)=T(u)in X.

    Moreover, since T is an injection, we conclude that u=˜u.

    Fix x0Ω and choose s>0 such that B(x0,s)Ω, where B(x0,s) denotes the ball with center at x0 and radius of s. Put

    Θ1:=2πN2Γ(N2)ss2|12(N+1)s3r24Ns2+9(N1)s1r|p(x)rN1dr,
    Θ2:=B(x0,s)B(x0,s2)[Ni=1(12(xix0i)s324(xix0i)s2+9(xix0i)s)2]p(x)2dx,

    where =dist(x,x0)=Ni=1(xix0i)2 and

    Θ3:=2πN2Γ(N2)[(s2)NN+ss2|4s3r312s2r2+9sr1|p(x)rN1dr],

    Γ denotes the Gamma function, and

    L:=Θ1+Θ2+Θ3.

    Theorem 3.1. Assume that there exist positive constants θ1,θ2, θ3 and η1 with θ1<pLcη, η<min{p+pMp+cpM+Lθpp+2,θ2} and θ2<θ3 such that

    (A1) f(x,t)0 for each (x,t)¯ΩB(x0,s2)×[θ3,θ3];

    (A2)

    max{Ωsup|t|θ1F(x,t)dxθp1, Ωsup|t|θ2F(x,t)dxθp2, Ωsup|t|θ3F(x,t)dxθp3θp2}
    <pMp+cpM+LB(x0,s2)F(x,η)dxΩsup|t|θ1F(x,t)dxηp+.

    Then for every

    λ(M+Lpηp+B(x0,s2)F(x,η)dxΩsup|t|θ1F(x,t)dx,
    Mp+cpmin{θp1Ωsup|t|θ1F(x,t)dx,θp2Ωsup|t|θ2F(x,t)dx,θp3θp2Ωsup|t|θ3F(x,t)dx}),

    problem (Pfλ) has at least three weak solutions u1, u2 and u3 such that

    maxxΩ|u1(x)|<θ1, maxxΩ|u2(x)|<θ2andmaxxΩ|u3(x)|<θ3.

    Proof. Our goal is to apply Theorem 2.1 to the problem (Pfλ). We consider the auxiliary problem

    {T(u)=λˆf(x,u(x)),xΩ,u=Δu=0,xΩ,                         (Pˆfλ)

    where ˆf:Ω×RR is an L1-Carathéodory function defined as

    ˆf(x,ξ)={f(x,0),if ξ<θ3,f(x,ξ),if θ3ξθ3,f(x,θ3),if ξ>θ3.

    If a weak solution of the problem (Pˆfλ) satisfies the condition θ3u(x)θ3 for every xΩ, then, clearly it turns to be also a weak solution of (Pfλ). Therefore, it is enough to show that our conclusion holds for (Pfλ). We define functionals Φ and Ψ as given in (2.3) and (2.4), respectively. Let us prove that the functionals Φ and Ψ satisfy the required conditions in Theorem 2.1. It is well known that Ψ is a differentiable functional whose differential at the point uX is

    Ψ(u)(v)=Ωf(x,u(x))v(x)dx

    for every vX, as well as it is sequentially weakly upper semicontinuous. Recalling (2.1), we have

    Φ(u)1p+Ω|Δu(x)|p(x)dx+m0(Ω|u(x)|p(x)p(x)dx)+Ωρ(x)|u(x)|p(x)dxMp+up

    for all uX with u>1, which implies Φ is coercive. Moreover, Φ is continuously differentiable whose differential at the point uX is

    Φ(u)(v)=Ω|Δu(x)|p(x)2Δu(x)Δv(x)dx+M(Ω|u(x)|p(x)p(x)dx)Ω|u(x)|p(x)2u(x)v(x)dx+Ωρ(x)|u(x)|p(x)2u(x)v(x)dx

    for every vX, while Proposition 2.6 gives that Φ admits a continuous inverse on X. Furthermore, Φ is sequentially weakly lower semicontinuous. Therefore, we observe that the regularity assumptions on Φ and Ψ, as requested of Theorem 2.1, are verified. Define w by setting

    w(x):={0if x¯ΩB(x0,s)η(4s3312s22+9s1)if xB(x0,s)B(x0,s2)dif xB(x0,s2). (3.1)

    It is easy to see that wX and,

    w(x)xi={0if   x¯ΩB(x0,s)B(x0,s2)η(12(xix0i)s324(xix0i)s2+9s(xix0i))if   xB(x0,s)B(x0,s2)

    and

    2w(x)x2i={0if   x¯ΩB(x0,s)B(x0,s2)η(12s3(xix0i)2+224s2+9s2(xix0i)23)if   xB(x0,s)B(x0,s2),

    and so that

    Ni=12w(x)x2i={0if   x¯ΩB(x0,s)B(x0,s2)η(12l(N+1)s324Ns2+9sN1)if   xB(x0,s)B(x0,s2).

    It is easy to see that wX and, in particular, since

    Ω|Δw(x)|pdxηp+2πN2Γ(N2)ss2|12(N+1)s3r24Ns2+9(N1)s1r|p(x)rN1dr,
    Ω|w(x)|pdx=B(x0,s)B(x0,s2)[Ni=1η2(12l(xix0i)s324(xix0i)s2+9s(xix0i)l)2]p(x)2dx
    ηp+
    ×B(x0,s)B(x0,s2)[Ni=1(12l(xix0i)s324(xix0i)s2+9s(xix0i)l)2]p(x)2dx

    and

    Ω|w(x)|pdxηp+2πN2Γ(N2)((s2)NN+ss2|4s3r312s2r2+9sr1|p(x)rN1dr).

    In particular, one has

    MLp+ηp1p+(Θ1ηp+m0Θ2ηp+ρ0Θ3ηp)Φ(w)1p(Θ1ηp++m1Θ2ηp++ρΘ3ηp+)M+Lpηp+.

    On the other hand, bearing (A1) in mind, from the definition of Ψ, we infer

    Ψ(w)=ΩF(x,w(x))dxB(x0,s2)F(x,η)dx.

    Choose r1=Mp+(θ1c)p, r2=Mp+(θ2c)p and r3=Mp+(θp3θp2cp). From the conditions

    θ1<pLcη, pp+M+LpMcηp+p<θ2

    and θ2<θ3, we achieve r1<Φ(w)<r2 and r3>0. For all uX with Φ(u)<r1, taking (2.1) and (2.2) into account, one has

    umax{(p+r1)1p+,(p+r1)1p}.

    So, thanks to the embedding XC0(¯Ω), one has u<θ1. From the definition of r1, it follows that

    Φ1(,r1)={uX;Φ(u)<r1}{uX;|u|θ1}.

    Hence, one has

    supuΦ1(,r1)ΩF(x,u(x))dxΩsup|t|θ1F(x,t)dx.

    As above, we can obtain that

    supuΦ1(,r2)ΩF(x,u(x))dxΩsup|t|θ2F(x,t)dx

    and

    supuΦ1(,r2+r3)ΩF(x,u(x))dxΩsup|t|θ3F(x,t)dx.

    Therefore, since 0Φ1(,r1) and Φ(0)=Ψ(0)=0, one has

    φ(r1)=infuΦ1(,r1)(supuΦ1(,r1)Ψ(u))Ψ(u)r1Φ(u)supuΦ1(,r1)Ψ(u)r1=supuΦ1(,r1)ΩF(x,u(x))dxr1Ωsup|t|θ1F(x,t)dxMp+(θ1c)p,
    φ(r2)supuΦ1(,r2)Ψ(u)r2=supuΦ1(,r2)ΩF(x,u(x))dxr2Ωsup|t|θ2F(x,t)dxMp+(θ2c)p,

    and

    γ(r2,r3)supuΦ1(,r2+r3)Ψ(u)r3=supuΦ1(,r2+r3)ΩF(x,u(x))dxr3Ωsup|t|θ3F(x,t)dxMp+(θp3θp2cp).

    On the other hand, for each uΦ1(,r1) one has

    β(r1,r2)B(x0,s2)F(x,η)dxΩsup|t|θ1F(x,t)dxΦ(w)Φ(u)B(x0,s2)F(x,η)dxΩsup|t|θ1F(x,t)dxM+Lpηp+.

    Due to (A2) we get

    α(r1,r2,r3)<β(r1,r2).

    Therefore, (b1) and (b2) of Theorem 2.1 are verified. Finally, we verify that ΦλΨ satisfies the assumption 2 of Theorem 2.1. Let u1 and u2 be two local minima for ΦλΨ. Then u1 and u2 are critical points for ΦλΨ, and so, they are weak solutions of the problem (Pfλ). Since we assumed f is nonnegative, for fixed λ>0, we have λf(k,su1+(1s)u2)0 for all s[0,1], and consequently, Ψ(su1+(1s)u2)0 for every s[0,1]. Hence, Theorem 2.1 implies that for every

    λ(M+Lpηp+B(x0,s2)F(x,η)dxΩsup|t|θ1F(x,t)dx,
    Mp+cpmin{θp1Ωsup|t|θ1F(x,t)dx,θp2Ωsup|t|θ2F(x,t)dx,θp3θp2Ωsup|t|θ3F(x,t)dx}),

    the functional ΦλΨ has three critical points ui, i=1,2,3, in X such that Φ(u1)<r1, Φ(u2)<r2 and Φ(u3)<r2+r3, that is,

    maxxΩ|u1(x)|<θ1, maxxΩ|u2(x)|<θ2andmaxxΩ|u3(x)|<θ3.

    Then, taking into account the fact that the solutions of the problem (Pfλ) are exactly critical points of the functional ΦλΨ we have the desired conclusion.

    Remark 3.2. If f is non-negative, then the weak solution ensured in Theorem 3.1 is non-negative. Indeed, let u0 be the weak solution of the problem (Pfλ) ensured in Theorem 3.1, then u0 is nonnegative. Arguing by a contradiction, assume that the set A={xΩ:u0(x)<0} is non-empty and of positive measure. Put ˉv(x)=min{0,u0(x)} for all xΩ. Clearly, ˉvX and one has

    Ω|Δu0(x)|p(x)2Δu0(x)Δˉv(x)dx+M(Ω|u0(x)|p(x)p(x)dx)Ω|u0(x)|p(x)2u0(x)ˉv(x)dx+Ωρ(x)|u0(x)|p(x)2u0(x)ˉv(x)dxλΩf(x,u0(x))ˉv(x)dx=0

    for every ˉvX. Thus we have

    0Mu(A)A|Δu0(x)|p(x)+M(A|u0(x)|p(x)p(x)dx)A|u0(x)|p(x)dx+Aρ(x)|u0(x)|p(x)dx=λAf(x,u0(x))u0(x)dx0,

    i.e.,

    u0(A)0

    which contradicts with this fact that u0 is a non-trivial weak solution. Hence, the set A is empty, and u0 is positive.

    Theorem 3.3. Assume that there exist positive constants θ1, θ4 and η1 with θ1<min{ηp+p,pLcη} and η<min{p+pM2cpp+M+Lθpp+4,θ4} such that

    (A3) f(x,t)0 for each (x,t)¯ΩB(x0,s2)×[θ4,θ4];

    (A4)

    max{Ωsup|t|θ1F(x,t)dxθp1, 2Ωsup|t|θ4F(x,t)dxθp4}<pMp+cpM+L+pMB(x0,s2)F(x,η)dxηp+.

    Then for every

    λΛ:=((p+cpM+L+pM)ηp+pp+cpB(x0,s2)F(x,η)dx,Mp+cpmin{θp1Ωsup|t|θ1F(x,t)dx,θp42Ωsup|t|θ4F(x,t)dx}),

    problem (Pfλ) has at least three weak solutions u1, u2 and u3 such that

    maxxΩ|u1(x)|<θ1, maxxΩ|u2(x)|<1p2θ4andmaxxΩ|u3(x)|<θ4.

    Proof. Choose θ2=1p2θ4 and θ3=θ4. So, from (A4) one has

    Ωsup|t|θ2F(x,t)dxθp2=2Ωsup|t|1p2θ4F(x,t)dxθp42Ωsup|t|θ4F(x,t)dxθp4<pMp+cpM+L+pMB(x0,s2)F(x,η)dxηp+, (3.2)

    and

    Ωsup|t|θ3F(x,t)dxθp3θp2=2Ωsup|t|θ4F(x,t)dxθp4<pMp+cpM+L+pMB(x0,s2)F(x,η)dxηp+. (3.3)

    Moreover, since θ1<ηp+p, from (A4) we have

    pMp+cpM+LB(x0,s2)F(x,η)dxΩsup|t|θ1F(x,t)dxηp+>pMp+cpM+LB(x0,s2)F(x,η)dxηp+pMp+cpM+LΩsup|t|θ1F(x,t)dxθp1>pMp+cpM+L(B(x0,s2)F(x,η)dxηp+pMp+cpM+L+pMB(x0,s2)F(x,η)dxηp+)=pMp+cpM+L+pMB(x0,s2)F(x,η)dxηp+.

    Hence, from (A4), (3.2) and (3.3), it is easy to observe that the assumption (A2) of Theorem 3.1 is satisfied, and it follows the conclusion.

    The following result is a consequence of Theorem 3.3.

    Theorem 3.4. Let f:Ω×RR be a continuous function such that ξf(x,ξ)>0 for all (x,ξ)Ω×R{0}. Assume that

    (A5) limξ0f(x,ξ)|ξ|p1=lim|ξ|+f(x,ξ)|ξ|p1=0.

    Then for every λ>¯λ where

    ¯λ=p+cpM+L+pMpp+cpmax{infη1ηp+B(x0,s2)F(x,η)dx; infη1(η)p+B(x0,s2)F(x,η)dx},

    problem (Pfλ) possesses at least four distinct non-trivial solutions.

    Proof. Set

    f1(x,ξ)={f(x,ξ),if (x,ξ)Ω×[0,+),0,otherwise,

    and

    f2(x,ξ)={f(x,ξ),if (x,ξ)Ω×[0,+),0,otherwise,

    and define F1(x,ξ):=ξ0f1(x,t)dt for every (x,ξ)Ω×R. Fix λ>λ, and let η1 such that λ>(p+cpM+L+pM)ηp+pp+cpB(x0,s2)F(x,η)dx. From

    limξ0f1(x,ξ)|ξ|p1=lim|ξ|+f1(x,ξ)|ξ|p1=0,

    there is θ1>0 such that

    θ1<min{ηp+p,pLcη} and ΩF1(x,θ1)dxθp1<Mλp+cp,

    and θ4>0 such that

    η<min{p+pM2p+cpM+Lθpp+4,θ4}

    and

    ΩF1(x,θ4)dxθp4<M2λp+cp.

    Then, (A4) in Theorem 3.3 is satisfied,

    λ((p+cpM+L+pM)ηp+pp+cpB(x0,s2)F1(x,η)dx,Mp+cpmin{θp1Ωsup|t|θ1F1(x,t)dx,θp42Ωsup|t|θ4F1(x,t)dx}).

    Hence, the problem (Pf1λ) admits two positive solutions u1, u2, which are positive solutions of the problem (Pfλ). Next, arguing in the same way, from

    limξ0f2(x,ξ)|ξ|p1=lim|ξ|+f2(x,ξ)|ξ|p1=0,

    we ensure the existence of two positive solutions u3, u4 for the problem (Pf2λ). Clearly, u3, u4 are negative solutions of the problem (Pfλ) and the conclusion is achieved.

    Example 3.5. Let Ω={(x,y)R2:x2+y29}. Consider the problem

    {Δ2p(x,y)u(x)M(Ω|u(x)|p(x,y)dxp(x))Δp(x,y)u(x)+|u(x)|p(x,y)2u(x)=λf(x,y,u),(x,y)Ω,u=Δu=0,(x,y)Ω,

    where M(t)=32+sin(t)2 for each t[0,), p(x,y)=x2+y2+4 for all (x,y)Ω and

    f(x,y,t)={5(x2+y2)t4,if t1,(x,y)Ω,(x2+y2)5t,if t>1,(x,y)Ω.

    By the expression of f, we have

    F(x,y,t)={(x2+y2)t5,if t1,(x,y)Ω,(x2+y2)(10t9),if t>1,(x,y)Ω.

    Direct calculations give M=1, M+=2, p=4 and p+=13. It is clear that

    limξ0f(x,ξ)|ξ|3=lim|ξ|+f(x,ξ)|ξ|3=0.

    Hence, by applying Theorem 3.4, there is λ>0 such that for each λ>λ, the problem possesses at least four distinct non-trivial solutions.

    As a special case, we present a simple consequence of Theorem 3.3 when f dose not depend upon x. To be precise, consider the following problem

    {T(u)=λf(u(x)),xΩ,u=Δu=0,xΩ (3.4)

    where f:RR is a continues function.

    Put

    F(t)=t0f(ξ)dξ for all tR.

    Theorem 3.6. Assume that there exist positive constants θ1,θ2, θ3 and η1 with θ1<pLcη, η<min{p+pMp+cpM+Lθpp+2,θ2} and θ2<θ3 such that

    (A7) f(t)0 for each t[θ3,θ3];

    (A8)

    max{F(θ1)θp1, F(θ2)θp2, F(θ3)θp3θp2}<pMp+cp meas(Ω)M+L meas(B(x0,s2))F(η) meas(Ω)F(θ1)ηp+.

    Then for every

    λ(M+Lpηp+ meas(B(x0,s2))F(η) meas(Ω)F(θ1),Mp+cp meas(Ω)min{θp1F(θ1),θp2F(θ2),θp3θp2F(θ3)}),

    problem (Pfλ) has at least three weak solutions u1, u2 and u3 such that

    maxxΩ|u1(x)|<θ1, maxxΩ|u2(x)|<θ2andmaxxΩ|u3(x)|<θ3.

    Theorem 3.7. Assume that there exist positive constants θ1, θ4 and η1 with θ1<min{ηp+p,pLcη} and

    η<min{p+pM2p+cpM+Lθpp+4,θ4}

    such that

    (A9) f(t)0 for each t[θ4,θ4];

    (A10)

    max{F(θ1)θp1, 2F(θ4)θp4}< meas(B(x0,s2))pM meas(Ω)(p+cpM+L+pM)F(η)ηp+.

    Then for every

    λΛ:=((p+cpM+L+pM)ηp+pp+cp meas(B(x0,s2))F(η),Mp+cp meas(Ω)min{θp1F(θ1),θp42F(θ4)}),

    problem (Pfλ) has at least three weak solutions u1, u2 and u3 such that

    maxxΩ|u1(x)|<θ1, maxxΩ|u2(x)|<1p2θ4andmaxxΩ|u3(x)|<θ4.

    All authors confirm that there are no competing interests between them.



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