In this article, we study the existence of at least three distinct weak solutions for nonlocal elliptic problems involving p(x)-biharmonic operator. The results are obtained by means of variational methods. We also provide an example in order to illustrate our main abstract results. We extend and improve some recent results.
Citation: Fang-Fang Liao, Shapour Heidarkhani, Shahin Moradi. Multiple solutions for nonlocal elliptic problems driven by p(x)-biharmonic operator[J]. AIMS Mathematics, 2021, 6(4): 4156-4172. doi: 10.3934/math.2021246
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In this article, we study the existence of at least three distinct weak solutions for nonlocal elliptic problems involving p(x)-biharmonic operator. The results are obtained by means of variational methods. We also provide an example in order to illustrate our main abstract results. We extend and improve some recent results.
In this paper we study the existence of at least three distinct weak solutions for the following problem
{T(u)=λf(x,u(x)),in Ω,u=Δu=0,on ∂Ω, (Pfλ) |
where
T(u)=Δ2p(x)u(x)−M(∫Ω|∇u(x)|p(x)dxp(x))Δp(x)u(x)+ρ(x)|u(x)|p(x)−2u(x), |
Ω⊂RN(N≥2) is an open bounded domain with smooth boundary, Δ2p(x)u is the operator defined as Δ(|Δu|p(x)−2Δu) and is called the p(x)-biharmonic which is a generalization of the p-biharmonic, p(x)∈C(¯Ω), ρ(x)∈L∞(Ω), M:[0,+∞)→R is a continuous function such that there are two positive constants m0 and m1 with m0≤M(t)≤m1 for all t≥0, N2<p−:= essinfx∈Ωp(x)≤p+:= esssupx∈Ωp(x)<∞, λ>0 and f:Ω×R→R is an L1-Carathéodory function.
The Kirchhoff equation refers back to Kirchhoff [18] in 1883 in the study on the oscillations of stretched strings and plates, suggested as an extended version of the classical D'Alembert's wave equation by taking into account the effects of the changes in the length of the string during the vibrations. Kirchhoff's equation like problem (Pfλ) model several physical and biological systems where u describes a process which depend on the average of itself. Lions in [23] has proposed an abstract framework for the Kirchhoff-type equations. After the work by Lions, various problems of Kirchhoff-type have been widely investigated, we refer the reader to the papers [7,24,27] and the references therein.
The main interest in studying problem (Pfλ) is given by the presence of the variable exponent p(⋅). Problems involving such kind of growth conditions benefited by a special attention in the last decade since they can model with sufficient accuracy phenomena arising in different branches of science. Two important models where operators involving variable exponents were considered come from the study of electrorheological fluids [8,28] and elastic mechanics [34].
Fourth-order equations have various applications in areas of applied mathematics and physics such as micro-electro-mechanical systems, phase field models of multi-phase systems, thin film theory, thin plate theory, surface diffusion on solids, interface dynamics, flow in Hele-Shaw cells (see [4,6,26]). The fourth-order equation can also describe the static form change of beam or the sport of rigid body. In [22], Lazer and Mckenna have pointed out that this type of nonlinearity furnishes a model to study travelling waves in suspension bridges. Numerous authors investigated the existence and multiplicity of solutions for the problems involving p(x)-biharmonic operators. We refer to [10,12,16,19,21,30,31]. In the last decade, Kirchhoff type equations involving the p(x)-Laplacian have been investigated, for instance see [3,9,13,14,15,17,25].
In this paper, we are interested to discuss the existence of at least three distinct weak solutions for problem (Pfλ). No asymptotic condition at infinity is required on the nonlinear term. In Theorem 3.1 we establish the existence of at least three distinct weak solutions for problem (Pfλ). Theorem 3.3 is a consequence of Theorem 3.1. As a consequence of Theorem 3.3, we obtain Theorem 3.4 for the autonomous case. We present example 3.5 to illustrate Theorem 3.4.
Let X be a nonempty set and Φ,Ψ:X→R be two functions. For all r, r1, r2>infXΦ, r2>r1, r3>0, we define
φ(r):=infu∈Φ−1(−∞,r)(supu∈Φ−1(−∞,r)Ψ(u))−Ψ(u)r−Φ(u), |
β(r1,r2):=infu∈Φ−1(−∞,r1)supv∈Φ−1[r1,r2)Ψ(v)−Ψ(u)Φ(v)−Φ(u), |
γ(r2,r3):=supu∈Φ−1(−∞,r2+r3)Ψ(u)r3, |
α(r1,r2,r3):=max{φ(r1),φ(r2),γ(r2,r3)}. |
We shall discuss the existence of at least three distinct solutions to the problem (Pfλ). Our main tool is based on [1,Theorem 3.3] that we now recall as follows:
Theorem 2.1. Let X be a reflexive real Banach space, Φ:X→R be a convex, coercive and continuously Gâteaux differentiable functional whose Gâteaux derivative admits a continuous inverse on X∗,Ψ:X→R be a continuously Gâteaux differentiable functional whose Gâteaux derivative is compact, such that infXΦ=Φ(0)=Ψ(0)=0 and for every u1,u2∈X such that Ψ(u1)≥0 and Ψ(u2)≥0, one has
infs∈[0,1]Ψ(su1+(1−s)u2)≥0. |
Assume that there are three positive constants r1,r2,r3 with r1<r2, such that
(c1) φ(r1)<β(r1,r2);
(c2) φ(r2)<β(r1,r2);
(c3) γ(r2,r3)<β(r1,r2).
Then for each λ∈(1β(r1,r2),1α(r1,r2,r3)) the functional Φ−λΨ admits three distinct critical points u1,u2,u3 such that u1∈Φ−1(−∞,r1), u2∈Φ−1[r1,r2) and u3∈Φ−1(−∞,r2+r3).
We refer the interested reader to the papers [2,11,20] in which Theorem 2.1 has been successfully used to ensure the existence of at least three solutions for boundary value problems.
Let Ω be a bounded domain of RN, denote:
Lp(x)(Ω):={u:Ω→R measurable and ∫Ω|u(x)|p(x)dx<+∞}. |
We can introduce the norm on Lp(x)(Ω) by:
‖u‖Lp(x)(Ω)=inf{β>0:∫Ω|u(x)β|p(x)dx≤1}. |
Let X be the generalized Lebesgue-Sobolev space Wm,p(x)(Ω) defined by putting Wm,p(x)(Ω) as
Wm,p(x)(Ω)={u∈Lp(x)(Ω)|Dγu∈Lp(x)(Ω), |γ|≤m, m∈Z+}, |
which is equipped with the norm:
‖u‖m,p(x):=∑|γ|≤m|Dγu|p(x) | (2.1) |
γ is the multi-index and |γ| is the order.
The closure of C∞0(Ω) in Wm,p(x)(Ω) is the Wm,p(x)0(Ω). It is well known [5] that, both Lp(x)(Ω) and Wm,p(x)(Ω), with the respective norms, are separable, reflexive and uniformly convex Banach spaces.
Proposition 2.2. [5] Suppose 1p(x)+1p0(x)=1, then Lp0(x)(Ω) and Lp(x)(Ω) are conjugate space, and satisfy the Hölder inequality:
|∫Ωuvdx|≤(1p−+1(p0)−)|u|p(x)|v|p0(x),u∈Lp(x)(Ω), v∈Lp0(x)(Ω). |
We denote X:=W1,p(x)0(Ω)∩W2,p(x)(Ω) and has the norm
‖u‖=inf{σ>0:∫Ω(|u(x)σ|p(x)+|∇u(x)σ|p(x)+|Δu(x)σ|p(x))dx≤1}. |
By [32], ‖⋅‖, ‖⋅‖2,p(⋅) and |Δu|p(⋅) are equivalent norms of X.
A bounded operator T:X→R is said to be compact if T(BX) has compact closure in R.
Proposition 2.3. [31] When p−>N2, Ω⊂R is a bounded region, then X↦C(¯Ω) is a compact embedding.
According to 2.3, for each u∈X, there exists a constant c>0 that depends on p(⋅),N,Ω:
‖u‖∞=supx∈Ω|u(x)|≤c‖u‖. | (2.2) |
Remark 2.4. We say that f:Ω×R→R is an L1-Carathéodory function if
(a) t↦f(x,t) is measurable for every t∈R;
(b) x↦f(x,t) is continuous for a.e. x∈Ω;
(c) for every ε>0 there exists a function lε∈L1(Ω) such that for a.e. x∈Ω,
sup|t|≤ε|f(x,t)|≤lε(x). |
Corresponding to the functions f and M, we introduce the functions F:Ω×R→R and ˜M:[0,+∞)→R, respectively, as follows
F(x,t)=∫t0f(x,ξ)dξ for all (x,t)∈Ω×R, |
˜M(t)=∫t0M(ξ)dξ for all t≥0. |
We say that u∈X is a weak solution of problem (Pfλ) if for every v∈X,
∫Ω|Δu(x)|p(x)−2Δu(x)Δv(x)dx+M(∫Ω|∇u(x)|p(x)p(x)dx)∫Ω|∇u(x)|p(x)−2∇u(x)∇v(x)dx+∫Ωρ(x)|u(x)|p(x)−2u(x)v(x)dx−λ∫Ωf(x,u(x))v(x)dx=0. |
Proposition 2.5. [5] Let J(u)=∫Ω|u|p(x)dx for each u∈Lp(x)(Ω), we have
(1) |u|p(x)<1(=1;>1)⇔J(u)<1(=1;>1);
(2) |u|p(x)≥1⟹|u|p−p(x)≤J(u)≤|u|p+p(x);
(3) |u|p(x)≤1⟹|u|p+p(x)≤J(u)≤|u|p−p(x);
(4) |u|p(x)⟶0⇔J⟶0.
Now for every u∈X, we define I(u):=Φ(u)−λΨ(u) where
Φ(u)=∫Ω|Δu(x)|p(x)p(x)dx+˜M(∫Ω|∇u(x)|p(x)p(x)dx)+∫Ωρ(x)|u(x)|p(x)p(x)dx, | (2.3) |
and
Ψ(u)=∫ΩF(x,u(x))dx. | (2.4) |
For our convenience, set
ρ0=minx∈Ωρ(x),M−=min{1,m0,ρ0}andM+=max{1,m1,ρ∞}. |
Proposition 2.6. Let T=Φ′:X→X∗ be the operator defined by
T(u)(v)=∫Ω|Δu(x)|p(x)−2Δu(x)Δv(x)dx+M(∫Ω|∇u(x)|p(x)p(x)dx)∫Ω|∇u(x)|p(x)−2∇u(x)∇v(x)dx+∫Ωρ(x)|u(x)|p(x)−2u(x)v(x) |
for every u,v∈X. Then T admits a continuous inverse on X∗.
Proof. For any u∈X∖{0},
lim‖u‖→∞⟨T(u),u⟩‖u‖=lim‖u‖→∞∫Ω|Δu(x)|p(x)dx+M(∫Ω∇u(x)|p(x)p(x)dx)∫Ω|∇u(x)|p(x)dx+∫Ωρ(x)|u(x)|p(x)dx‖u‖≥lim‖u‖→∞M−‖u‖p−‖u‖=lim‖u‖→∞M−‖u‖p–1, |
since p−>1, it follows that the map T is coercive. Since T is the Fréchet derivative of Φ, it follows that T is continuous and bounded. Using the elementary inequality [29]
|x−y|γ≤2γ(|x|γ−2x−|y|γ−2y)(x−y)if γ≥2, |
for all (x,y)∈RN×RN, N≥1, we obtain for all u,v∈X such that u≠v,
⟨T(u)−T(v),u−v⟩>0, |
which means that T is strictly monotone. Thus T is injective. Consequently, thanks to Minty-Browder theorem [33], the operator T is a surjection and admits an inverse mapping. Thus it is sufficient to show that T−1 is continuous. For this, let (vn)∞n=1 be a sequence in X∗ such that vn→v in X∗. Let un and u in X such that
T−1(vn)=unandT−1(v)=u. |
By the coercivity of T, we conclude that the sequence (un) is bounded in the reflexive space X. For a subsequence, we have un→˜u in X, which implies
limn→∞⟨T(un)−T(u),un−˜u⟩=limn→∞⟨fn−f,un−˜u⟩=0. |
Therefore, by the continuity of T, we have
un→˜uin XandT(un)→T(˜u)=T(u)in X∗. |
Moreover, since T is an injection, we conclude that u=˜u.
Fix x0∈Ω and choose s>0 such that B(x0,s)⊂Ω, where B(x0,s) denotes the ball with center at x0 and radius of s. Put
Θ1:=2πN2Γ(N2)∫ss2|12(N+1)s3r−24Ns2+9(N−1)s1r|p(x)rN−1dr, |
Θ2:=∫B(x0,s)∖B(x0,s2)[N∑i=1(12(xi−x0i)s3−24(xi−x0i)s2+9(xi−x0i)sℓ)2]p(x)2dx, |
where ℓ=dist(x,x0)=√∑Ni=1(xi−x0i)2 and
Θ3:=2πN2Γ(N2)[(s2)NN+∫ss2|4s3r3−12s2r2+9sr−1|p(x)rN−1dr], |
Γ denotes the Gamma function, and
L:=Θ1+Θ2+Θ3. |
Theorem 3.1. Assume that there exist positive constants θ1,θ2, θ3 and η≥1 with θ1<p−√Lcη, η<min{p+√p−M−p+cp−M+Lθp−p+2,θ2} and θ2<θ3 such that
(A1) f(x,t)≥0 for each (x,t)∈¯Ω∖B(x0,s2)×[−θ3,θ3];
(A2)
max{∫Ωsup|t|≤θ1F(x,t)dxθp−1, ∫Ωsup|t|≤θ2F(x,t)dxθp−2, ∫Ωsup|t|≤θ3F(x,t)dxθp−3−θp−2} |
<p−M−p+cp−M+L∫B(x0,s2)F(x,η)dx−∫Ωsup|t|≤θ1F(x,t)dxηp+. |
Then for every
λ∈(M+Lp−ηp+∫B(x0,s2)F(x,η)dx−∫Ωsup|t|≤θ1F(x,t)dx, |
M−p+cp−min{θp−1∫Ωsup|t|≤θ1F(x,t)dx,θp−2∫Ωsup|t|≤θ2F(x,t)dx,θp−3−θp−2∫Ωsup|t|≤θ3F(x,t)dx}), |
problem (Pfλ) has at least three weak solutions u1, u2 and u3 such that
maxx∈Ω|u1(x)|<θ1, maxx∈Ω|u2(x)|<θ2andmaxx∈Ω|u3(x)|<θ3. |
Proof. Our goal is to apply Theorem 2.1 to the problem (Pfλ). We consider the auxiliary problem
{T(u)=λˆf(x,u(x)),x∈Ω,u=Δu=0,x∈∂Ω, (Pˆfλ) |
where ˆf:Ω×R→R is an L1-Carathéodory function defined as
ˆf(x,ξ)={f(x,0),if ξ<−θ3,f(x,ξ),if −θ3≤ξ≤θ3,f(x,θ3),if ξ>θ3. |
If a weak solution of the problem (Pˆfλ) satisfies the condition −θ3≤u(x)≤θ3 for every x∈Ω, then, clearly it turns to be also a weak solution of (Pfλ). Therefore, it is enough to show that our conclusion holds for (Pfλ). We define functionals Φ and Ψ as given in (2.3) and (2.4), respectively. Let us prove that the functionals Φ and Ψ satisfy the required conditions in Theorem 2.1. It is well known that Ψ is a differentiable functional whose differential at the point u∈X is
Ψ′(u)(v)=∫Ωf(x,u(x))v(x)dx |
for every v∈X, as well as it is sequentially weakly upper semicontinuous. Recalling (2.1), we have
Φ(u)≥1p+∫Ω|Δu(x)|p(x)dx+m0(∫Ω|∇u(x)|p(x)p(x)dx)+∫Ωρ(x)|u(x)|p(x)dx≥M−p+‖u‖p− |
for all u∈X with ‖u‖>1, which implies Φ is coercive. Moreover, Φ is continuously differentiable whose differential at the point u∈X is
Φ′(u)(v)=∫Ω|Δu(x)|p(x)−2Δu(x)Δv(x)dx+M(∫Ω|∇u(x)|p(x)p(x)dx)∫Ω|∇u(x)|p(x)−2∇u(x)∇v(x)dx+∫Ωρ(x)|u(x)|p(x)−2u(x)v(x)dx |
for every v∈X, while Proposition 2.6 gives that Φ′ admits a continuous inverse on X∗. Furthermore, Φ is sequentially weakly lower semicontinuous. Therefore, we observe that the regularity assumptions on Φ and Ψ, as requested of Theorem 2.1, are verified. Define w by setting
w(x):={0if x∈¯Ω∖B(x0,s)η(4s3ℓ3−12s2ℓ2+9sℓ−1)if x∈B(x0,s)∖B(x0,s2)dif x∈B(x0,s2). | (3.1) |
It is easy to see that w∈X and,
∂w(x)∂xi={0if x∈¯Ω∖B(x0,s)∪B(x0,s2)η(12ℓ(xi−x0i)s3−24(xi−x0i)s2+9s(xi−x0i)ℓ)if x∈B(x0,s)∖B(x0,s2) |
and
∂2w(x)∂x2i={0if x∈¯Ω∖B(x0,s)∪B(x0,s2)η(12s3(xi−x0i)2+ℓ2ℓ−24s2+9sℓ2−(xi−x0i)2ℓ3)if x∈B(x0,s)∖B(x0,s2), |
and so that
N∑i=1∂2w(x)∂x2i={0if x∈¯Ω∖B(x0,s)∪B(x0,s2)η(12l(N+1)s3−24Ns2+9sN−1ℓ)if x∈B(x0,s)∖B(x0,s2). |
It is easy to see that w∈X and, in particular, since
∫Ω|Δw(x)|pdx≤ηp+2πN2Γ(N2)∫ss2|12(N+1)s3r−24Ns2+9(N−1)s1r|p(x)rN−1dr, |
∫Ω|∇w(x)|pdx=∫B(x0,s)∖B(x0,s2)[N∑i=1η2(12l(xi−x0i)s3−24(xi−x0i)s2+9s(xi−x0i)l)2]p(x)2dx |
≤ηp+ |
×∫B(x0,s)∖B(x0,s2)[N∑i=1(12l(xi−x0i)s3−24(xi−x0i)s2+9s(xi−x0i)l)2]p(x)2dx |
and
∫Ω|w(x)|pdx≤ηp+2πN2Γ(N2)((s2)NN+∫ss2|4s3r3−12s2r2+9sr−1|p(x)rN−1dr). |
In particular, one has
M−Lp+ηp−≤1p+(Θ1ηp−+m0Θ2ηp−+ρ0Θ3ηp−)≤Φ(w)≤1p−(Θ1ηp++m1Θ2ηp++ρ∞Θ3ηp+)≤M+Lp−ηp+. |
On the other hand, bearing (A1) in mind, from the definition of Ψ, we infer
Ψ(w)=∫ΩF(x,w(x))dx≥∫B(x0,s2)F(x,η)dx. |
Choose r1=M−p+(θ1c)p−, r2=M−p+(θ2c)p− and r3=M−p+(θp−3−θp−2cp−). From the conditions
θ1<p−√Lcη, p−√p+M+Lp−M−cηp+p−<θ2 |
and θ2<θ3, we achieve r1<Φ(w)<r2 and r3>0. For all u∈X with Φ(u)<r1, taking (2.1) and (2.2) into account, one has
‖u‖≤max{(p+r1)1p+,(p+r1)1p−}. |
So, thanks to the embedding X↪C0(¯Ω), one has ‖u‖∞<θ1. From the definition of r1, it follows that
Φ−1(−∞,r1)={u∈X;Φ(u)<r1}⊆{u∈X;|u|∞≤θ1}. |
Hence, one has
supu∈Φ−1(−∞,r1)∫ΩF(x,u(x))dx≤∫Ωsup|t|≤θ1F(x,t)dx. |
As above, we can obtain that
supu∈Φ−1(−∞,r2)∫ΩF(x,u(x))dx≤∫Ωsup|t|≤θ2F(x,t)dx |
and
supu∈Φ−1(−∞,r2+r3)∫ΩF(x,u(x))dx≤∫Ωsup|t|≤θ3F(x,t)dx. |
Therefore, since 0∈Φ−1(−∞,r1) and Φ(0)=Ψ(0)=0, one has
φ(r1)=infu∈Φ−1(−∞,r1)(supu∈Φ−1(−∞,r1)Ψ(u))−Ψ(u)r1−Φ(u)≤supu∈Φ−1(−∞,r1)Ψ(u)r1=supu∈Φ−1(−∞,r1)∫ΩF(x,u(x))dxr1≤∫Ωsup|t|≤θ1F(x,t)dxM−p+(θ1c)p−, |
φ(r2)≤supu∈Φ−1(−∞,r2)Ψ(u)r2=supu∈Φ−1(−∞,r2)∫ΩF(x,u(x))dxr2≤∫Ωsup|t|≤θ2F(x,t)dxM−p+(θ2c)p−, |
and
γ(r2,r3)≤supu∈Φ−1(−∞,r2+r3)Ψ(u)r3=supu∈Φ−1(−∞,r2+r3)∫ΩF(x,u(x))dxr3≤∫Ωsup|t|≤θ3F(x,t)dxM−p+(θp−3−θp−2cp−). |
On the other hand, for each u∈Φ−1(−∞,r1) one has
β(r1,r2)≥∫B(x0,s2)F(x,η)dx−∫Ωsup|t|≤θ1F(x,t)dxΦ(w)−Φ(u)≥∫B(x0,s2)F(x,η)dx−∫Ωsup|t|≤θ1F(x,t)dxM+Lp−ηp+. |
Due to (A2) we get
α(r1,r2,r3)<β(r1,r2). |
Therefore, (b1) and (b2) of Theorem 2.1 are verified. Finally, we verify that Φ−λΨ satisfies the assumption 2 of Theorem 2.1. Let u1 and u2 be two local minima for Φ−λΨ. Then u1 and u2 are critical points for Φ−λΨ, and so, they are weak solutions of the problem (Pfλ). Since we assumed f is nonnegative, for fixed λ>0, we have λf(k,su1+(1−s)u2)≥0 for all s∈[0,1], and consequently, Ψ(su1+(1−s)u2)≥0 for every s∈[0,1]. Hence, Theorem 2.1 implies that for every
λ∈(M+Lp−ηp+∫B(x0,s2)F(x,η)dx−∫Ωsup|t|≤θ1F(x,t)dx, |
M−p+cp−min{θp−1∫Ωsup|t|≤θ1F(x,t)dx,θp−2∫Ωsup|t|≤θ2F(x,t)dx,θp−3−θp−2∫Ωsup|t|≤θ3F(x,t)dx}), |
the functional Φ−λΨ has three critical points ui, i=1,2,3, in X such that Φ(u1)<r1, Φ(u2)<r2 and Φ(u3)<r2+r3, that is,
maxx∈Ω|u1(x)|<θ1, maxx∈Ω|u2(x)|<θ2andmaxx∈Ω|u3(x)|<θ3. |
Then, taking into account the fact that the solutions of the problem (Pfλ) are exactly critical points of the functional Φ−λΨ we have the desired conclusion.
Remark 3.2. If f is non-negative, then the weak solution ensured in Theorem 3.1 is non-negative. Indeed, let u0 be the weak solution of the problem (Pfλ) ensured in Theorem 3.1, then u0 is nonnegative. Arguing by a contradiction, assume that the set A={x∈Ω:u0(x)<0} is non-empty and of positive measure. Put ˉv(x)=min{0,u0(x)} for all x∈Ω. Clearly, ˉv∈X and one has
∫Ω|Δu0(x)|p(x)−2Δu0(x)Δˉv(x)dx+M(∫Ω|∇u0(x)|p(x)p(x)dx)∫Ω|∇u0(x)|p(x)−2∇u0(x)∇ˉv(x)dx+∫Ωρ(x)|u0(x)|p(x)−2u0(x)ˉv(x)dx−λ∫Ωf(x,u0(x))ˉv(x)dx=0 |
for every ˉv∈X. Thus we have
0≤M−‖u‖(A)≤∫A|Δu0(x)|p(x)+M(∫A|∇u0(x)|p(x)p(x)dx)∫A|∇u0(x)|p(x)dx+∫Aρ(x)|u0(x)|p(x)dx=λ∫Af(x,u0(x))u0(x)dx≤0, |
i.e.,
‖u0‖(A)≤0 |
which contradicts with this fact that u0 is a non-trivial weak solution. Hence, the set A is empty, and u0 is positive.
Theorem 3.3. Assume that there exist positive constants θ1, θ4 and η≥1 with θ1<min{ηp+p−,p−√Lcη} and η<min{p+√p−M−2cp−p+M+Lθp−p+4,θ4} such that
(A3) f(x,t)≥0 for each (x,t)∈¯Ω∖B(x0,s2)×[−θ4,θ4];
(A4)
max{∫Ωsup|t|≤θ1F(x,t)dxθp−1, 2∫Ωsup|t|≤θ4F(x,t)dxθp−4}<p−M−p+cp−M+L+p−M−∫B(x0,s2)F(x,η)dxηp+. |
Then for every
λ∈Λ′:=((p+cp−M+L+p−M−)ηp+p−p+cp−∫B(x0,s2)F(x,η)dx,M−p+cp−min{θp−1∫Ωsup|t|≤θ1F(x,t)dx,θp−42∫Ωsup|t|≤θ4F(x,t)dx}), |
problem (Pfλ) has at least three weak solutions u1, u2 and u3 such that
maxx∈Ω|u1(x)|<θ1, maxx∈Ω|u2(x)|<1p−√2θ4andmaxx∈Ω|u3(x)|<θ4. |
Proof. Choose θ2=1p−√2θ4 and θ3=θ4. So, from (A4) one has
∫Ωsup|t|≤θ2F(x,t)dxθp−2=2∫Ωsup|t|≤1p−√2θ4F(x,t)dxθp−4≤2∫Ωsup|t|≤θ4F(x,t)dxθp−4<p−M−p+cp−M+L+p−M−∫B(x0,s2)F(x,η)dxηp+, | (3.2) |
and
∫Ωsup|t|≤θ3F(x,t)dxθp−3−θp−2=2∫Ωsup|t|≤θ4F(x,t)dxθp−4<p−M−p+cp−M+L+p−M−∫B(x0,s2)F(x,η)dxηp+. | (3.3) |
Moreover, since θ1<ηp+p−, from (A4) we have
p−M−p+cp−M+L∫B(x0,s2)F(x,η)dx−∫Ωsup|t|≤θ1F(x,t)dxηp+>p−M−p+cp−M+L∫B(x0,s2)F(x,η)dxηp+−p−M−p+cp−M+L∫Ωsup|t|≤θ1F(x,t)dxθp−1>p−M−p+cp−M+L(∫B(x0,s2)F(x,η)dxηp+−p−M−p+cp−M+L+p−M−∫B(x0,s2)F(x,η)dxηp+)=p−M−p+cp−M+L+p−M−∫B(x0,s2)F(x,η)dxηp+. |
Hence, from (A4), (3.2) and (3.3), it is easy to observe that the assumption (A2) of Theorem 3.1 is satisfied, and it follows the conclusion.
The following result is a consequence of Theorem 3.3.
Theorem 3.4. Let f:Ω×R→R be a continuous function such that ξf(x,ξ)>0 for all (x,ξ)∈Ω×R∖{0}. Assume that
(A5) limξ→0f(x,ξ)|ξ|p−−1=lim|ξ|→+∞f(x,ξ)|ξ|p−−1=0.
Then for every λ>¯λ where
¯λ=p+cp−M+L+p−M−p−p+cp−max{infη≥1ηp+∫B(x0,s2)F(x,η)dx; infη≤−1(−η)p+∫B(x0,s2)F(x,η)dx}, |
problem (Pfλ) possesses at least four distinct non-trivial solutions.
Proof. Set
f1(x,ξ)={f(x,ξ),if (x,ξ)∈Ω×[0,+∞),0,otherwise, |
and
f2(x,ξ)={−f(x,−ξ),if (x,ξ)∈Ω×[0,+∞),0,otherwise, |
and define F1(x,ξ):=∫ξ0f1(x,t)dt for every (x,ξ)∈Ω×R. Fix λ>λ∗, and let η≥1 such that λ>(p+cp−M+L+p−M−)ηp+p−p+cp−∫B(x0,s2)F(x,η)dx. From
limξ→0f1(x,ξ)|ξ|p−−1=lim|ξ|→+∞f1(x,ξ)|ξ|p−−1=0, |
there is θ1>0 such that
θ1<min{ηp+p−,p−√Lcη} and ∫ΩF1(x,θ1)dxθp−1<M−λp+cp−, |
and θ4>0 such that
η<min{p+√p−M−2p+cp−M+Lθp−p+4,θ4} |
and
∫ΩF1(x,θ4)dxθp−4<M−2λp+cp−. |
Then, (A4) in Theorem 3.3 is satisfied,
λ∈((p+cp−M+L+p−M−)ηp+p−p+cp−∫B(x0,s2)F1(x,η)dx,M−p+cp−min{θp−1∫Ωsup|t|≤θ1F1(x,t)dx,θp−42∫Ωsup|t|≤θ4F1(x,t)dx}). |
Hence, the problem (Pf1λ) admits two positive solutions u1, u2, which are positive solutions of the problem (Pfλ). Next, arguing in the same way, from
limξ→0f2(x,ξ)|ξ|p−−1=lim|ξ|→+∞f2(x,ξ)|ξ|p−−1=0, |
we ensure the existence of two positive solutions u3, u4 for the problem (Pf2λ). Clearly, −u3, −u4 are negative solutions of the problem (Pfλ) and the conclusion is achieved.
Example 3.5. Let Ω={(x,y)∈R2:x2+y2≤9}. Consider the problem
{Δ2p(x,y)u(x)−M(∫Ω|∇u(x)|p(x,y)dxp(x))Δp(x,y)u(x)+|u(x)|p(x,y)−2u(x)=λf(x,y,u),(x,y)∈Ω,u=Δu=0,(x,y)∈∂Ω, |
where M(t)=32+sin(t)2 for each t∈[0,∞), p(x,y)=x2+y2+4 for all (x,y)∈Ω and
f(x,y,t)={5(x2+y2)t4,if t≤1,(x,y)∈Ω,(x2+y2)5√t,if t>1,(x,y)∈Ω. |
By the expression of f, we have
F(x,y,t)={(x2+y2)t5,if t≤1,(x,y)∈Ω,(x2+y2)(10√t−9),if t>1,(x,y)∈Ω. |
Direct calculations give M−=1, M+=2, p−=4 and p+=13. It is clear that
limξ→0f(x,ξ)|ξ|3=lim|ξ|→+∞f(x,ξ)|ξ|3=0. |
Hence, by applying Theorem 3.4, there is λ∗>0 such that for each λ>λ∗, the problem possesses at least four distinct non-trivial solutions.
As a special case, we present a simple consequence of Theorem 3.3 when f dose not depend upon x. To be precise, consider the following problem
{T(u)=λf(u(x)),x∈Ω,u=Δu=0,x∈∂Ω | (3.4) |
where f:R→R is a continues function.
Put
F(t)=∫t0f(ξ)dξ for all t∈R. |
Theorem 3.6. Assume that there exist positive constants θ1,θ2, θ3 and η≥1 with θ1<p−√Lcη, η<min{p+√p−M−p+cp−M+Lθp−p+2,θ2} and θ2<θ3 such that
(A7) f(t)≥0 for each t∈[−θ3,θ3];
(A8)
max{F(θ1)θp−1, F(θ2)θp−2, F(θ3)θp−3−θp−2}<p−M−p+cp− meas(Ω)M+L meas(B(x0,s2))F(η)− meas(Ω)F(θ1)ηp+. |
Then for every
λ∈(M+Lp−ηp+ meas(B(x0,s2))F(η)− meas(Ω)F(θ1),M−p+cp− meas(Ω)min{θp−1F(θ1),θp−2F(θ2),θp−3−θp−2F(θ3)}), |
problem (Pfλ) has at least three weak solutions u1, u2 and u3 such that
maxx∈Ω|u1(x)|<θ1, maxx∈Ω|u2(x)|<θ2andmaxx∈Ω|u3(x)|<θ3. |
Theorem 3.7. Assume that there exist positive constants θ1, θ4 and η≥1 with θ1<min{ηp+p−,p−√Lcη} and
η<min{p+√p−M−2p+cp−M+Lθp−p+4,θ4} |
such that
(A9) f(t)≥0 for each t∈[−θ4,θ4];
(A10)
max{F(θ1)θp−1, 2F(θ4)θp−4}< meas(B(x0,s2))p−M− meas(Ω)(p+cp−M+L+p−M−)F(η)ηp+. |
Then for every
λ∈Λ′:=((p+cp−M+L+p−M−)ηp+p−p+cp− meas(B(x0,s2))F(η),M−p+cp− meas(Ω)min{θp−1F(θ1),θp−42F(θ4)}), |
problem (Pfλ) has at least three weak solutions u1, u2 and u3 such that
maxx∈Ω|u1(x)|<θ1, maxx∈Ω|u2(x)|<1p−√2θ4andmaxx∈Ω|u3(x)|<θ4. |
All authors confirm that there are no competing interests between them.
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