
In this paper, we considered the M/G/1 queueing system with multiple phases of operation. First, we have proven the existence and uniqueness of the time-evolving solution for this queueing system. Second, by calculating the spectral distribution of the system operator, we proved that the solution converged at most strongly to its steady-state (static) solution. We also discussed the compactness of the system's corresponding semigroup. Additionally, we investigated the asymptotic behavior of dynamic indicators. Finally, to demonstrate the exponential convergence of the solution, we conducted some numerical analysis.
Citation: Nurehemaiti Yiming. Dynamic analysis of the M/G/1 queueing system with multiple phases of operation[J]. Networks and Heterogeneous Media, 2024, 19(3): 1231-1261. doi: 10.3934/nhm.2024053
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In this paper, we considered the M/G/1 queueing system with multiple phases of operation. First, we have proven the existence and uniqueness of the time-evolving solution for this queueing system. Second, by calculating the spectral distribution of the system operator, we proved that the solution converged at most strongly to its steady-state (static) solution. We also discussed the compactness of the system's corresponding semigroup. Additionally, we investigated the asymptotic behavior of dynamic indicators. Finally, to demonstrate the exponential convergence of the solution, we conducted some numerical analysis.
Queueing systems with multiple phases of operation are very useful in manufacturing systems, transportation systems, financial systems, etc.; see [1,2,3,4]. For example, in automobile manufacturing, raw materials first enter the stamping workshop for stamping and forming. Continuing with the welding assembly in the welding workshop is the second stage, then carry out surface treatment such as painting, is the third stage. Finally, the final assembly and quality inspection are carried out. In the airport boarding process, passengers first queue up at the check-in counter to complete check-in procedures, including checking in luggage. Then, queue up through the security checkpoint for security checks, is the second stage. Finally, they queue up at the boarding gate to wait for boarding. In hospital medical systems, patients first queue up at the registration counter to register. Then, the second stage is to go to the waiting area of the corresponding department to queue up for the doctor's diagnosis. If further examinations are needed, such as blood tests, X-rays, etc., one needs to queue outside the examination department to wait for the examination, which is the third stage. Finally, they take the examination results and return to the doctor for diagnosis or treatment, such as prescribing medication, intravenous infusion, etc.
In this paper, we consider the M/G/1 queueing system with multiple phases of operation, where M means that customer arrival follows a Poisson process, G represents the service rate of the server follows a general distribution, 1 indicates the number of servers in the system. Therefore, the M/G/1 queue is a single-server queue where customers arrive according to a Poisson process, and service times are independent and identically distributed general random variables. The process of establishing a mathematical model for the queuing system is as follows:
There are n+1 phases in this system, 0 is the idle period, and s(s=1,2,⋯,n) are the operational phases. We assume that N(t) denotes the number of customers in the system at time t, J(t) denotes the phase in which the system operates at time t, Rs(t)(s=1,2,⋯,n) represents the elapsed service time of the customer currently receiving service during phase s, Fs(x)=Prob{Rs(t)≤x}(s=1,2,⋯,n) denotes the probability distribution function corresponding to Rs(t), and μs(x)dx is the service completion rate of the server in the interval (x,x+dx] if the system is in phase s and satisfies μs(x)≥0 and ∫∞0μs(x)dx=∞. The service time of the any two phases of service are mutually independent. Based on the properties of conditional probability and differentiation, we have
μs(x)dx=Prob{x<Rs(t)≤x+dx|Rs(t)>x}=−d(1−Fs(x))1−Fs(x). |
Then, from this and Fs(0)=0, we obtain the probability distribution function of the service time of the server in the phase s,
Fs(x)=1−e−∫x0μs(τ)dτ. |
According to the definition of probability distribution function, we know that Fs(x)≥0 and limx→∞Fs(x)=1. Therefore,
μs(x)≥0,∫∞0μs(x)dx=∞. |
We assume that, in phase s, the arrivals occur according to a Poisson process of rate λs>0. In the idle period, the Poisson arrival rate is λ0>0; upon arrival, the system moves to some operative phase s with probability qs, and the customer service upon arrival begins immediately, where qs>0 and ∑ns=1qs=1. Then, according to the definition of Poisson process and exponential distribution, we have
Prob{N(t)=k,J(t)=s}=(λst)kk!e−λst,t≥0,k≥0,s=0,1,⋯,n, | (1.1a) |
Prob{arriving one customer within the Δt time in phase s}=λsΔt+o(Δt),s=1,2,⋯,n, | (1.1b) |
Prob{arriving two or more customers within the Δt time in phase s}=o(Δt),s=1,2,⋯,n, | (1.1c) |
Prob{the server completing one service within the Δt time in phase s}=μs(x)Δt+o(Δt),s=1,2,⋯,n, | (1.1d) |
Prob{the server completing two or more services within the Δt time in phase s}=o(Δt),s=1,2,⋯,n, | (1.1e) |
where o(Δt) denotes the infinitesimal quantity of Δt. Clearly, the process {(N(t),J(t),Rs(t)):t≥0} is a continuous-time Markov process with state space
Γ={(0,0)}∪{(k,s,x)|k=1,2,⋯;s=1,2,⋯,n,x≥0}. |
We define
p0,0(t)=Prob{N(t)=0,J(t)=0}, | (1.2a) |
pk,s(x,t)dx=Prob{N(t)=k,J(t)=s,x≤Rs(t)<x+dx}. | (1.2b) |
Then, consider the changes in the system during Δt time. Based on the formula of total probability, the properties of Markov processes, and the above Eqs (1.1a)–(1.2b), we have (for convenience, assuming Δx is the same as Δt)
p0,0(t+Δt)=Prob{within the t+Δt,no customers in the system and the service desk being idle}=Prob{at time t,no customers in the system, during Δt no customers arriving and the system is idle}+Prob{at time t there is one customer in the system, during Δt no customers arriving, server completing one service within Δt in phase 1}+Prob{at time t there is one customer in the system, during Δt no customers arriving, server completing one service within Δt in phase 2}+⋯+Prob{at time t there is one customer in the system, during Δt no customers arriving, server completing one service within Δt in phase n}+o(Δt)=p0,0(t)(1−λ0Δt)+∫∞0p1,1(x,t)μ1(x)dxΔt(1−λ1Δt)+∫∞0p1,2(x,t)μ2(x)dxΔt(1−λ2Δt)+⋯+∫∞0p1,n(x,t)μn(x)dxΔt(1−λnΔt)+o(Δt), | (1.3a) |
p1,s(x+Δt,t+Δt)=Prob{at time t+Δt, there is one customer in the system, the elapsed service time of the customer currently receiving service during phase s is x+Δt}=Prob{at time t,there is one customer in the system and the servicetime that has passed is x, no customers arrived withinΔt and the server did not complete the service in phase s}+o(Δt)=p1,s(x,t)(1−λsΔt)(1−μs(x)Δt)+o(Δt),,1≤s≤n, | (1.3b) |
pk,s(x+Δt,t+Δt)=Prob{at time t+\Delta t , there are k customers in the system, the elapsed service time of the customer currently receiving service during phase s is x+Δt}=Prob{at time t,there are k customers in the system and the servicetime that has passed is x,no customers arrived withinΔt and the server did not complete the service in phase s}+Prob{at time t,there are k−1 customers in the system and the service time that has passed is x,one customer arrived inΔt and the server did not complete the service in phases}+o(Δt)=pk,s(x,t)(1−λsΔt)(1−μs(x)Δt)+pk−1,s(x,t)λsΔt(1−μs(x)Δt)+o(Δt),s=1,2,⋯,n;k≥2. | (1.3c) |
We consider the boundary conditions as follows:
p1,s(0,t+Δt)Δt=Prob{at time t+Δt,there is one customer in the systemin phase s and the service has not started yet}=Prob{at time t,the system is in idle state, buthas just reached one customer and the system has jumped from idle state to phase s}+Prob{at time t,there are two customers in the system in phase s and the server has just completed one service within Δt}+o(Δt)=p0,0(t)qsΔt+∫∞0p2,s(x,t)μs(x)dxΔt+o(Δt),,1≤s≤n, | (1.4a) |
pk,s(0,t+Δt)Δt=Prob{at time t+Δt,there are k customers in the systemin phase s and the service has not yet started}=Prob{at time t,there are k+1 customersin the system in phase s and the serverjust completes one service within Δt time}+o(Δt)=∫∞0pk+1,s(x,t)μs(x)dxΔt+o(Δt),,1≤s≤n. | (1.4b) |
Assume that the initial values
p0,0(0)=g0,0≥0,andpk,s(x,0)=gk,s(x)≥0,k≥1,s=1,2,⋯,n, | (1.5) |
satisfy
g0,0+n∑s=1∞∑k=1∫∞0gk,s(x)dx=1. |
Based on Eqs (1.2a)–(1.5) and the definition of partial differential derivatives, we obtain the following integro-partial differential equations [3]:
{dp0,0(t)dt=−λ0p0,0(t)+n∑s=1∫∞0p1,s(x,t)μs(x)dx,∂tp1,s(x,t)+∂xp1,s(x,t)=−[λs+μs(x)]p1,s(x,t),∂tpk,s(x,t)+∂xpk,s(x,t)=−[λs+μs(x)]pk,s(x,t)+λspk−1,s(x,t),k≥2,p1,s(0,t)=qsλ0p0,0(t)+∫∞0p2,s(x,t)μs(x)dx,pk,s(0,t)=∫∞0pk+1,s(x,t)μs(x)dx,k≥2,p0,0(0)=g0,0≥0,pk,s(x,0)=gk,s(x)≥0,k≥1,1≤s≤n. | (1.6) |
In [3], several static indices for the system (1.6) such as the static queue length and static sojourn time distribution of an arbitrary customer were developed under the following static hypothesis:
● limt→∞p0,0(t)=p0,0,
● limt→∞pk,s(⋅,t)=pk,s(⋅),k≥1,1≤s≤n.
From the perspective of partial differential equations, the above hypothesis implies the following two hypotheses:
● (H1): The system (1.6) admits a time-evolving solution.
● (H2): The aforementioned time-evolving solution converges to its static.
In this article, we investigate the aforementioned static hypothesis, that is, (H1) and (H2), and consider the asymptotic behavior of the dynamic indices of the system (1.6). It is worth noting that when n=1, system (1.6) becomes the classical M/G/1 queuing system [5], and a detailed dynamic analysis of this classical queuing system was conducted in [6,7,8,9,10]. Gupur et al. [6] studied the well-posedness of the queueing system [5] and obtained the strong convergence of the solution of the system when the service rate is constant. When the service rate is a bounded function, similar results to [6] are obtained by [7]. In [8,9,10], the exponential convergence of the solution of the queueing system [5] was studied. Therefore, our results include the above findings.
In the study of partial differential equations, many solutions of partial differential equations can function as semigroups in Banach space. By studying the properties of semigroups, important properties such as the existence, uniqueness, and stability of solutions to partial differential equations can be obtained; see [11,12,13,14,15]. In this article, first, we convert the system (1.6) into an abstract Cauchy problem in a natural state Banach space. Then, using the semigroup theory on Banach spaces, we show that the system operator generates a positive C0−semigroup of contractions on the state space. Consequently, we verify that the system (1.6) admits a unique positive time-evolving solution, which shows that (H1) holds under certain conditions.
Second, we investigate the asymptotic behavior of the solution. To this aim, we need to know the spectrum of the system operator; see [16,17,18]. For example, in order to study the asymptotic stability of multilayer thermal wave systems, Avalos et al. [16] conducted spectral analysis on the system and found that the system operator had no spectral points on the imaginary axis. Drogoul and Veltz [17] proved that 0 is the unique spectral point of the spike neural network operator on the imaginary axis, thus obtaining the exponential stability of the system. In [18], it was proved that 0 is the point spectrum of the system operator of the queuing system and is the unique spectral point, thus obtaining the solution corresponding to this queuing system that strongly converges to its static solution.
Moreover, it is a challenge to find spectrum on the imaginary axis. Here, we apply Greiner's [19] boundary perturbation method to fully describe the spectral distribution of the system operator on the imaginary axis. If the service rates are constants, then we obtain that the system operator of the system (1.6) has uncountable eigenvalues on the left-half complex plane. Consequently, these spectral results imply that the time-evolving solution of system (1.6) at most strongly converges to its static solution. In other words, (H2) holds only in the context of strong convergence.
Finally, we discuss the asymptotic behavior of the dynamic indices of the system (1.6). By using cone theory and positive operator theory, we prove that the time-evolving queue length of the system (1.6) converges to its static queue length under some conditions. This asymptotic result includes the result of [3].
The remaining part of this article is organized as follows. In the next section, we rewrite the system (1.6) as an abstract Cauchy problem in a Banach space and provide the well-posedness. In Section 3, we provide a complete asymptotic behavior of the solution of system (1.6). In Section 4, we discuss the dynamic indices of the system (1.6). To demonstrate the exponential convergence of the solution, we conduct some numerical analysis in Section 5. We conclude this article in the last section.
We choose the state Banach space of system (1.6) as follows:
X={(p1,p2,⋯,pn)|p1=(p0,0,p1,1,p2,1,⋯),ps=(p1,s,p2,s,⋯),2≤s≤n,p0,0∈R,pk,s∈L1[0,∞),‖(p1,p2,⋯,pn)‖=|p0,0|+∑ns=1∑∞k=1‖pk,s‖L1[0,∞)<∞}. |
Define the maximal operator of the system (1.6) by
Am(p1,p2,⋯,pn)=((−λ0p0,0+∑ns=1φsp1,sB1p1,1λ1p1,1+B1p2,1λ1p2,1+B1p3,1⋮),(B2p1,2λ2p1,2+B2p2,2λ2p2,2+B2p3,2λ2p3,2+B2p4,2⋮),⋯,(Bnp1,nλnp1,n+Bnp2,nλnp2,n+Bnp3,nλnp3,n+Bnp4,n⋮)), |
with domain
D(Am)={(p1,p2,⋯,pn)∈X∣dpk,sdx∈L1[0,∞),n∑s=1∞∑k=1‖dpk,sdx‖L1[0,∞)<∞}, |
where pk,s are absolutely continuous functions, k≥1,1≤s≤n, and
{Bsv=−dv(x)dx−[λs+μs(x)]v(x),v∈W1,1[0,∞),φsf=∫∞0f(x)μs(x)dx,f∈L1[0,∞). |
We choose the boundary space as ∂X=l1×l1×⋯×l1⏟n and define boundary operators Ψ,Φ:D(Am)→∂X of the system (1.1a) by
Ψ(p1,p2,⋯,pn)=((p1,1(0)p2,1(0)⋮),(p1,2(0)p2,2(0)⋮),⋯,(p1,n(0)p2,n(0)⋮)), |
Φ(p1,p2,⋯,pn)=((q1λ0p0,0+φ1p2,1φ1p3,1φ1p4,1⋮),(q2λ0p0,0+φ2p2,2φ2p3,2φ2p4,2⋮),⋯,(qnλ0p0,0+φnp2,nφnp3,nφnp4,n⋮)). |
Now, we introduce the system operator (AΦ,D(AΦ)) of the system (1.6) by
{AΦ(p1,p2,⋯,pn)=Am(p1,p2,⋯,pn),D(AΦ)={(p1,p2,⋯,pn)∈D(Am)|Ψ(p1,p2,⋯,pn)=Φ(p1,p2,⋯,pn)}. | (2.1) |
Then, the system (1.6) can be written as an abstract Cauchy problem in the Banach space X:
{d(p1,p2,⋯,pn)(⋅,t)dt=AΦ(p1,p2,⋯,pn)(⋅,t),t∈(0,∞),(p1,p2,⋯,pn)(⋅,0)=(g1(⋅),g2(⋅),⋯,gn(⋅)), | (2.2) |
where g1(⋅)=(g0,0,g1,1(⋅),g2,1(⋅),⋯),gs(⋅)=(g1,s(⋅),g2,s(⋅),⋯),s=2,3,⋯,n.
Theorem 2.1. Let AΦ be defined by Eq (2.1). If μs(x)≤¯μs=supx∈[0,∞)μs(x)<∞(1≤s≤n), then AΦ generates a positive C0−semigroup eAΦt of contractions on X.
Proof. For self contained and conciseness, we only sketch the proof of Theorem 2.1. To start, we divided operator AΦ into three parts AΦ=A+U+E, where
A(p1,⋯,pn)=((−λ0p0,0−dp1,1dx−dp2,1dx⋮),(−dp1,2(x)dx−dp2,2(x)dx−dp3,2(x)dx⋮),⋯⋯,(−dp1,n(x)dx−dp2,n(x)dx−dp3,n(x)dx⋮)), |
D(A)={(p1,⋯,pn)∈X|dpk,s(x)dx∈L1[0,∞),pk,s(x)are absolutelycontinuous functions andps(0)=Γ0,sp1+∫∞0Γ1,spsdx,k≥1;1≤s≤n}, |
where
Γ1,1=(e−x000⋯q1λ0e−x0μ10⋯000μ1⋯⋮⋮⋮⋮⋱), |
Γ0,s=(qsλ00⋯000⋯⋮⋮⋮⋱),Γ1,s=(0μs0⋯00μs⋯000⋯⋮⋮⋮⋱),2≤s≤n. |
U(p1,⋯,pn)=((0−(λ1+μ1)p1,1(x)−(λ1+μ1)p2,1(x)+λ1p1,1(x)−(λ1+μ1)p3,1(x)+λ1p2,1(x)⋮),(−(λ2+μ2)p1,2(x)−(λ2+μ2)p2,2(x)+λ2p1,2(x)−(λ2+μ2)p3,2(x)+λ2p2,2(x)⋮),⋯⋯,(−(λn+μn)p1,n(x)−(λn+μn)p2,n(x)+λnp1,n(x)−(λn+μn)p3,n(x)+λnp2,n(x)⋮)), |
E(p1,⋯,pn)=(∑ns=1μs∫∞0p1,s(x)dx0⋮), |
D(U)=X,D(E)=X. |
We can verify that ‖(γI−A)−1‖<1γ−M0 for all γ>M0=max{¯μ1,¯μ2,⋯,¯μn}, where I represents the identity operator. Moreover, it is easy to prove that D(A) is dense in X. Then, using the Helle-Yosida theorem (see [20,Theorem 4.20]), we obtain that A generates a C0−semigroup. Due to the operators U and E being linear bounded, with perturbation theory of the semigroup, we know that AΦ generates a C0−semigroup eAΦt. Thus, we complete the proof of this theorem.
Next, we investigate the isometry of eAΦt. It is easy to obtain that X∗, the dual space of X, is as follows:
X∗={(p∗1,⋯,p∗n)|p∗1=(p∗0,0,p∗1,1,p∗2,1,⋯),p∗s=(p∗1,s,p∗2,s,⋯),2≤s≤n,p∗0,0∈R,p∗k,s∈L∞[0,∞),‖(p∗1,⋯,p∗n)‖=sup{sup|p∗0,0|,supk≥11≤s≤n‖p∗k,s‖L∞[0,∞)}<∞}. |
If we take a set X+={(p1,p2,⋯,pn)∈X∣p0,0≥0,pk,s(⋅)≥0,k≥1,1≤s≤n} in X, then, Theorem 2.1 ensures eAΦtX+⊂X+. Now, for any (p1,p2,⋯,pn)∈D(AΦ)∩X+, we choose
(p∗1,p∗2,⋯,p∗n)=‖(p1,p2,⋯,pn)‖((1⋮),(1⋮),⋯,(1⋮)). |
It is not difficult to calculate that for (p∗1,p∗2,⋯,p∗n)∈X∗ and (p1,p2,⋯,pn)∈X+, we have
⟨(p1,p2,⋯,pn),(p∗1,p∗2,⋯,p∗n)⟩=‖(p1,p2,⋯,pn)‖[p0,0+n∑s=1∞∑k=1∫∞0pk,s(x)dx]=‖(p1,p2,⋯,pn)‖2. |
This shows that (p∗1,p∗2,⋯,p∗n)∈Q(p1,p2,⋯,pn), where
Q(p1,p2,⋯,pn)={(p∗1,p∗2,⋯,p∗n)∈X∗|⟨(p1,p2,⋯,pn),(p∗1,p∗2,⋯,p∗n)⟩=‖(p1,p2,⋯,pn)‖2=‖(p∗1,p∗2,⋯,p∗n)‖2}. |
In addition, we obtain for (p1,p2,⋯,pn)∈D(AΦ) and (p∗1,p∗2,⋯,p∗n)∈Q(p1,p2,⋯,pn) that
⟨AΦ(p1,p2,⋯,pn),(p∗1,p∗2,⋯,p∗n)⟩=‖(p1,p2,⋯,pn)‖×{−λ0p0,0+n∑s=1∫∞0p1,s(x)μs(x)dx+n∑s=1∞∑k=2∫∞0λspk−1,s(x)dx+n∑s=1∞∑k=1∫∞0[−dpk,s(x)dx−(λs+μs(x))pk,s(x)]dx}=0. | (2.3) |
Then, Eq (2.3) implies that AΦ is conservative with respect to Q(⋅). Theorem 3.6.1 of [21] stated that: Assume that AΦ is densely defined, conservative with respect to Q(⋅):D(AΦ)→X∗ and (γI−AΦ)D(AΦ)=X for some γ>0. Then, for some g∈D((AΦ)2), the corresponding semigroup to Cauchy problem (2.2) is isometric. Hence, we obtain the following result.
Theorem 2.2. Let μs(⋅) satisfy μs(x)≤supx∈[0,∞)μs(x)<∞,1≤s≤n. If the initial value (p1,p2,⋯,pn)(⋅,0)=(g1(⋅),g2(⋅),⋯,gn(⋅)) of the system (2.2) belongs to D(A2Φ), then semigroup eAΦt is isometric for (g1(⋅),g2(⋅),⋯,gn(⋅)). That is,
‖eAΦt(g1(⋅),g2(⋅),⋯,gn(⋅))‖=‖(g1(⋅),g2(⋅),⋯,gn(⋅))‖,t∈[0,∞). | (2.6) |
By combining Theorems 2.1 and 2.2, we obtain the main result in this section.
Theorem 2.3. Let μs(⋅) satisfy μs(x)≤supx∈[0,∞)μs(x)<∞,1≤s≤n. If the initial value (g1(⋅),g2(⋅),⋯,gn(⋅)) of system (2.2) belongs to D(A2Φ), then system (2.2) admits a unique positive time-evolving solution (p1(⋅,t),p2(⋅,t),⋯,pn(⋅,t)) which satisfies
‖(p1(⋅,t),p2(⋅,t),⋯,pn(⋅,t))‖=1,∀t∈[0,∞). | (2.7) |
Proof. Due to (g1(⋅),g2(⋅),⋯,gn(⋅))∈D(A2Φ) and (g1(⋅),g2(⋅),⋯,gn(⋅))∈X+, it is easy to see that (g1(⋅),g2(⋅),⋯,gn(⋅))∈D(A2Φ)∩X+. By Theorem 1.81 of [12], we see that the system (1.6) has a unique positive time-evolving solution (p1(⋅,t),p2(⋅,t),⋯,pn(⋅,t)), which can be expressed as
(p1(⋅,t),p2(⋅,t),⋯,pn(⋅,t))=eAΦt(g1(⋅),g2(⋅),⋯,gn(⋅)),∀t∈[0,∞). | (2.8) |
From this together with Eq (2.7), we obtain
‖(p1(⋅,t),p2(⋅,t),⋯,pn(⋅,t))‖=‖eAΦt(g1(⋅),g2(⋅),⋯,gn(⋅))‖=1,∀t∈[0,∞). | (2.9) |
This illustrates the physical meaning of (p1(⋅,⋅),p2(⋅,⋅),⋯,pn(⋅,⋅)).
In this section, our main objective is to address the issue of asymptotic behavior of the time-evolving solution that we stated in Eq (2.8). In this regard, we prove that the time-evolving solution of the system (1.6) strongly converges but not exponentially converges to its static solution. In other words, hypothesis (H2) holds only in the context of strong convergence.
The main result of this subsection is given by the following Theorem 3.1.
Theorem 3.1. Let μs(x):[0,∞)→[0,∞) be a measurable function that satisfies
0<infx∈[0,∞)μs(x)≤μs(x)≤supx∈[0,∞)μs(x)<∞,1≤s≤n. |
Then, the time-evolving solution of the system (2.2) strongly converges to its static solution. In other words,
limt→∞‖(p1,p2,⋯,pn)(⋅,t)−⟨(p∗1,p∗2,⋯,p∗n),(g1,g2,⋯,gn)⟩(p1,p2,⋯,pn)(⋅)‖=0, |
where (p∗1,p∗2,⋯,p∗n) and (p1,p2,⋯,pn) are the eigenvectors associated to zero, respectively.
To prove the above Theorem 3.1, we need to find the spectra of AΦ along the imaginary axis. For this, we first provide the following seven lemmas.
Lemma 3.1. Let AΦ be defined by Eq (2.1). If μs(x):[0,∞)→[0,∞) is measurable function that satisfies
0<μ_s=infx∈[0,∞)μs(x)≤μs(x)≤¯μs=supx∈[0,∞)μs(x)<∞,1≤s≤n, |
then, zero is an eigenvalue of AΦ with geometric multiplicity one.
Proof. We need to solve AΦ(p1,p2,⋯,pn)=0 for unknown (p1,p2,⋯,pn). This equation is equivalent to
λ0p0,0=n∑s=1∫∞0p1,s(x)μs(x)dx, | (3.1a) |
dp1,s(x)dx=−[λs+μs(x)]p1,s(x), | (3.1b) |
dpk,s(x)dx=−[λs+μs(x)]pk,s(x)+λspk−1,s(x),k≥2, | (3.1c) |
p1,s(0)=qsλ0p0,0+∫∞0p2,s(x)μs(x)dx, | (3.1d) |
pk,s(0)=∫∞0pk+1,s(x)μs(x)dx,k≥2. | (3.1e) |
Solve Eqs (3.1b) and (3.1c) to obtain
pk,s(x)=e−λsx−∫x0μs(τ)dτk∑j=1(λsx)j−1(j−1)!pk−j+1,s(0),k≥1. | (3.2) |
If we take pk,s(0)=2−(k+1)p1,s(0),p1,s(0)=qsλ0p0,0>0 and define
ck,s:=∫∞0(λsx)kk!e−λsx−∫x0μs(τ)dτdx,dk,s:=∫∞0μs(x)(λsx)kk!e−λsx−∫x0μs(τ)dτdx,k≥1, |
then pk,s(0)=2−(k+1)p1,s(0) satisfies the boundary conditions (3.1d) and (3.1e). Therefore, since the Cauchy product of series, the formula ∫∞0μs(x)e−∫x0μs(ξ)dξdx=1, and
n∑s=1∞∑k=1pk,s(0)=λ0q0,0,∞∑k=1ck,s=∫∞0e−∫x0μs(τ)dτdx,∞∑k=1dk,s=1, |
we have
n∑s=1∞∑k=1∫∞0|pk,s(x)|dx=n∑s=1∞∑k=1k∑j=1cj,spk−j+1,s(0)=λ0p0,0∫∞0e−∫x0μs(τ)dτdx≤λ0μ_sp0,0<∞. | (3.3) |
Eq (3.3) means that zero is an eigenvalue of AΦ. Moreover, by Eqs (3.1a) and (3.1d)–(3.2), we see that the geometric multiplicity of zero is one.
Now, we use the idea of [19] to describe the other spectrum of AΦ along the imaginary axis. For this objective, we define the operator (A0,D(A0)) by
{A0(p1,p2,⋯,pn)=Am(p1,p2,⋯,pn),D(A0)={(p1,p2,⋯,pn)∈D(Am)|Ψ(p1,p2,⋯,pn)=0}. |
and discuss the inverse of A0.
For given (y1,y2,⋯,yn)∈X, consider (γI−A0)(p1,p2,⋯,pn)=(y1,y2,⋯,yn) of unknown (p1,p2,⋯,pn)∈D(A0). This equation can be equivalently written as the following system of equations
(γ+λ0)p0,0=y0,0+n∑s=1∫∞0p1,s(x)μs(x)dx, | (3.4a) |
dp1,s(x)dx=−[γ+λs+μs(x)]p1,s(x)+y1,s(x), | (3.4b) |
dpk,s(x)dx=−[γ+λs+μs(x)]pk,s(x)+λspk−1,s(x)+yk,s(x),k≥2, | (3.4c) |
pk,s(0)=0,k≥1;1≤s≤n. | (3.4d) |
By solving Eqs (3.4a)–(3.4c) and using Eq (3.4d), we obtain
p1,s(x)=e−(γ+λs)x−∫x0μs(τ)dτ∫x0y1,s(τ)e(γ+λs)τ+∫τ0μs(ξ)dξdτ, | (3.5a) |
pk,s(x)=e−(γ+λs)x−∫x0μs(τ)dτ∫x0yk,s(τ)e(γ+λs)τ+∫τ0μs(ξ)dξdτ+λse−(γ+λs)x−∫x0μs(τ)dτ∫x0pk−1,s(τ)e(γ+λs)τ+∫τ0μs(ξ)dξdτ,k≥2, | (3.5b) |
p0,0=1γ+λ0y0,0+1γ+λ0n∑s=1∫∞0p1,s(x)μs(x)dx=1γ+λ0y0,0+1γ+λ0n∑s=1∫∞0μs(x)×[e−(γ+λs)x−∫x0μs(τ)dτ∫x0y1,s(τ)e(γ+λs)τ+∫τ0μs(ξ)dξdτ]dx. | (3.5c) |
Denoting by
Esf(x)=e−(γ+λs)x−∫x0μs(τ)dτ∫x0f(τ)e(γ+λs)τ+∫τ0μs(ξ)dξdτ,f∈L1[0,∞), | (3.6) |
then the Eqs (3.5a)–(3.5c) and φsf(x)=∫∞0f(x)μs(x)dx,f∈L1[0,∞) give, if the resolvent of A0 exists,
(γI−A0)−1(y1,y2,⋯,yn)=((1γ+λ0∑ns=1φsEsy1,s(x)0⋮)+(1γ+λ0000⋯0E100⋯0λ1E21E10⋯0λ21E31λ1E21E1⋯⋮⋮⋮⋱)(y0,0y1,1(x)y2,1(x)y3,1(x)⋮),(E200⋯λ2E22E20⋯λ22E32λ2E22E2⋯⋮⋮⋱)(y1,2(x)y2,2(x)y3,2(x)⋮),⋯,(En00⋯λnE2nEn0⋯λ2nE3nλnE2nEn⋯⋮⋮⋱)(y1,n(x)y2,n(x)y3,n(x)⋮)). | (3.7) |
The following Lemma 3.2 indicates the resolvent set ρ(A0) of A0.
Lemma 3.2. Let μs(x):[0,∞)→[0,∞) be a measurable function that satisfies
0<μ_s=infx∈[0,∞)μs(x)≤μs(x)≤¯μs=supx∈[0,∞)μs(x)<∞,1≤s≤n. |
Then, {γ∈C∣Re(γ)+λ0>0,Re(γ)+μ_s>0}⊂ρ(A0).
Proof. For all f∈L1[0,∞), by performing integration by parts to Eq (3.6), it is easy to obtain that Es satisfies the following inequality:
‖Es‖≤1Re(γ)+λs+μ_s. |
Then, using the inequality ‖φs‖≤supx∈[0,∞)μs(x), we calculate for any (y1,y2,⋯,yn)∈X that
‖(γI−A0)−1(y1,y2,⋯,yn)‖≤1Re(γ)+λ0|y0,0|+1Re(γ)+λ0n∑s=1‖φs‖‖Es‖‖y1,s‖L1[0,∞)+∞∑k=1λk−11‖E1‖k∞∑j=1‖yj,1‖L1[0,∞)+∞∑k=1λk−12‖E2‖k∞∑j=1‖yj,2‖L1[0,∞)+⋯+∞∑k=1λk−1n‖En‖k∞∑j=1‖yj,n‖L1[0,∞)≤1Re(γ)+λ0|y0,0|+1Re(γ)+λ0n∑s=1¯μsRe(γ)+λs+μ_s‖y1,m‖L1[0,∞)+1Re(γ)+λ1+μ_1∞∑k=1(λ1Re(γ)+λ1+μ_1)k−1∞∑j=1‖yj,1‖L1[0,∞)+1Re(γ)+λ2+μ_2∞∑k=1(λ2Re(γ)+λ2+μ_2)k−1∞∑j=1‖yj,2‖L1[0,∞)+⋯+1Re(γ)+λn+μ_n∞∑k=1(λnRe(γ)+λn+μ_n)k−1∞∑j=1‖yj,n‖L1[0,∞)=1Re(γ)+λ0|y0,0|+1Re(γ)+λ0n∑s=1¯μsRe(γ)+λs+μ_s‖y1,s‖L1[0,∞)+n∑s=11Re(γ)+μ_s∞∑j=1‖yj,s‖L1[0,∞)≤sup{1Re(γ)+λ0+1Re(γ)+λ0¯μ1Re(γ)+λ1+μ_1+1Re(γ)+μ_1,1Re(γ)+λ0¯μ2Re(γ)+λ2+μ_2+1Re(γ)+μ_2,⋯,1Re(γ)+λ0¯μnRe(γ)+λn+μ_n+1Re(γ)+μ_n}‖(y1,y2,⋯,yn)‖. | (3.8) |
That is, inequality (3.8) means that the result of this lemma is correct.
Next, we use the following Lemma 3.3 to provide a specific expression for the Dirichlet operator.
Lemma 3.3. Let γ∈{γ∈C∣Re(γ)+λ0>0,Re(γ)+μ_s>0}. Then, we have (p1,p2,⋯,pn)∈ker(γI−Am) if, and only if,
p0,0=1γ+λ0n∑s=1p1,s(0)∫∞0μs(x)e−(γ+λs)x−∫x0μs(τ)dτdx, | (3.9a) |
pk,s(x)=e−(γ+λs)x−∫∞0μs(τ)dτk∑j=1(λsx)j−1(j−1)!pk−j+1,s(0),k≥1, | (3.9b) |
ps(0)=(p1,s(0),p2,s(0),p3,s(0),⋯)∈l1,1≤s≤n. | (3.9c) |
Proof. If (p1,p2,⋯,pn)∈ker(γI−Am), then (γI−Am)(p1,p2,⋯,pn)=0, that is,
(γ+λ0)p0,0=n∑s=1∫∞0p1,s(x)μs(x)dx, | (3.10a) |
dp1,s(x)dx=−[γ+λs+μs(x)]p1,s(x), | (3.10b) |
dpk,s(x)dx=−[γ+λs+μs(x)]pk,s(x)+λspk−1,s(x). | (3.10c) |
By solving Eqs (3.10a)–(3.10c), we obtain
pk,s(x)=e−(γ+λs)x−∫x0μs(τ)dτk∑j=1(λsx)j−1(j−1)!pk−j+1,s(0),k≥1, | (3.11a) |
p0,0=1γ+λ0n∑s=1p1,s(0)∫∞0μs(x)e−(γ+λs)x−∫x0μs(τ)dτdx. | (3.11b) |
Since (p1,p2,⋯,pn)∈ker(γI−Am), according to the Sobolev embedding theorem [22], we can easily obtain
∞∑k=1|pk,s(0)|≤∞∑k=1‖pk,s‖L∞[0,∞)≤∞∑k=1(‖pk,s‖L1[0,∞)+‖dpk,sdx‖L1[0,∞))<∞. | (3.12) |
Hence, Eqs (3.11a)–(3.12) show that Eqs (3.9a)–(3.9c) are true.
On the other hand, if Eqs (3.9a)–(3.9c) hold, due to the formula
∫∞0e−cxxkdx=c−(k+1)k! |
it holds true for any c>0 and positive integer k≥1, and performing integration by parts, we deduce
‖pk,s‖L1[0,∞)≤∫∞0e−(Re(γ)+λs)x−∫x0μs(τ)dτk∑j=1(λsx)j−1(j−1)!|pk−j+1,s(0)|dx≤k∑j=1λj−1s(j−1)!|pk−j+1,s(0)|∫∞0xj−1e−[Re(γ)+λs+infx∈[0,∞)μs(x)]xdx=k∑j=1λj−1s[Re(γ)+λs+μ_s]j|pk−j+1,s(0)|. |
Then, by the Cauchy product of series, we calculate that
∞∑k=1‖pk,s‖L1[0,∞)≤∞∑k=1k∑j=1λj−1s[Re(γ)+λs+μ_s]j|pk−j+1,s(0)|=1Re(γ)+λs+μ_s∞∑j=1(λsRe(γ)+λs+μ_s)j−1∞∑k=1|pk,s(0)|=1Re(γ)+μ_s∞∑k=1|pk,s(0)|<∞, | (3.13) |
for any γ>−μ_s. Inequalities (3.12) and (3.13) show that (p1,p2,⋯,pn)∈X. In addition, by Eq (3.9b), we have
dp1,s(x)dx=−[γ+λs+μs(x)]p1,s(0)e−(γ+λs)x−∫x0μs(τ)dτ=−[γ+λs+μs(x)]p1,s(x), | (3.14a) |
dpk,s(x)dx=−[γ+λs+μs(x)]e−(γ+λs)x−∫x0μs(τ)dτk∑j=1(λsx)j−1(j−1)!pk−j+1,s(0)+λse−(γ+λs)x−∫x0μs(τ)dτk−1∑j=1(λsx)j−1(j−1)!pk−j,s(0)=−[γ+λs+μs(x)]pk,s(x)+λspk−1,s(x),k≥2. | (3.14b) |
Combining the above Eqs (3.14a) and (3.14b) with inequality (3.13), we obtain
∞∑k=1‖dpk,sdx‖L1[0,∞)≤(|γ|+2λs+supx∈[0,∞)μs(x))∞∑k=1‖pk,s‖L1[0,∞)<∞. |
This inequality implies that
n∑s=1∞∑k=1‖dpk,sdx‖L1[0,∞)<∞. | (3.15) |
Hence, Eqs (3.13)–(3.15) indicate that (p1,p2,⋯,pn)∈D(Am) and
(γI−Am)(p1,p2,⋯,pn)=0. |
Clearly, by the definition it is not difficult to show that the boundary operator Ψ is surjective. In addition, for all γ∈ρ(A0), the operator
Ψ|ker(γI−Am):ker(γI−Am)→∂X, |
is invertible. Now, for any γ∈ρ(A0), we introduce the Dirichlet operator by
Dγ:=(Ψ|ker(γI−Am))−1:∂X→ker(γI−Am). |
Then, using Lemma 3.3, for any γ∈ρ(A0), we can obtain the following specific expression for Dγ:
Dγ(p1(0),p2(0),⋯,pn(0))=((1γ+λ0∑ns=1p1,s(0)φsε1,s000⋮)+(0000⋯ε1,1000⋯ε2,1ε1,100⋯ε3,1ε2,1ε1,10⋯⋮⋮⋮⋮⋱)(p1,1(0)p2,1(0)p3,1(0)p4,1(0)⋮),(ε1,200⋯ε2,2ε1,20⋯ε3,2ε2,2ε1,2⋯⋮⋮⋮⋱)(p1,2(0)p2,2(0)p3,2(0)⋮),⋯,(ε1,n00⋯ε2,nε1,n0⋯ε3,nε2,nε1,n⋯⋮⋮⋮⋱)(p1,n(0)p2,n(0)p3,n(0)⋮)), | (3.16) |
where
εj,s=(λsx)j−1(j−1)!e−(γ+λs)x−∫x0μs(τ)dτ,j≥1,1≤s≤n. |
Finally, using the expression of Dirichlet operator (3.16) and the boundary operator Φ, we can calculate the specific expression of ΦDγ as follows:
ΦDγ(p1(0),p2(0),⋯,pn(0))=(J1,J2,⋯,Jn)(p1(0),p2(0),⋯,pn(0)), | (3.17) |
where
Jk=(qkλ0γ+λ0n∑s=1p1,s(0)φsε1,s00⋮)+(φkε2,kφkε1,k0⋯φkε3,kφkε2,kφkε1,k⋯φkε4,kφkε3,kφkε2,k⋯⋮⋮⋮⋱)(p1,k(0)p2,k(0)p3,k(0)⋮),1≤k≤n. |
The following Lemma 3.4 was found in [23], and we use this lemma along with the above results in this subsection to provide spectrum σ(AΦ) of AΦ on the imaginary axis.
Lemma 3.4. Assume γ∈ρ(A0). If there exists γ0 that satisfies 1∉σ(ΦDγ0), then γ∈σ(AΦ) if, and only if, 1∈σ(ΦDγ).
Lemma 3.5. Let AΦ be defined by Eq (2.1). If μs(x):[0,∞)→[0,∞) is a measurable function that satisfies
0<infx∈[0,∞)μs(x)≤μs(x)≤supx∈[0,∞)μs(x)<∞,1≤s≤n, |
then, we have iR∩σ(AΦ)={0},i2=−1.
Proof. If we take γ=ib,i2=−1,b∈R∖{0}, then applying the Riemann-Lebesgue lemma, we obtain that there exists M>0 that satisfies
|∫∞0μs(x)(λsx)k−1(k−1)!e−(ib+λs)x−∫x0μs(τ)dτdx|<∫∞0μs(x)(λsx)k−1(k−1)!e−λsx−∫x0μs(τ)dτdx, | (3.18) |
for all |b|>M. Hence, using inequality (3.18) and the formulas ∑ns=1qs=1 and
∫∞0μs(x)e−∫x0μs(τ)dτdx=1, |
we calculate for ps(0)=(p1,s(0),p2,s(0),p3,s(0),⋯)∈l1∖{0} that
‖ΦDib(p1(0),p2(0),⋯,pn(0))‖≤λ0√b2+λ20n∑s=1|p1,s(0)||φsε1,s|+n∑s=1∞∑k=2|φsεk,s||p1,s(0)|+n∑s=1∞∑k=1|φsεk,s|∞∑j=2|pj,s(0)|<n∑s=1∞∑k=1|φsεk,s|∞∑j=1|pj,s(0)|=n∑s=1∞∑k=1|∫∞0μs(x)(λsx)k−1(k−1)!e−(ib+λs)x−∫x0μs(τ)dτdx|∞∑j=1|pj,s(0)|<n∑s=1∞∑k=1∫∞0μs(x)(λsx)k−1(k−1)!e−λsx−∫x0μs(τ)dτdx∞∑j=1|pj,s(0)|=n∑s=1∫∞0μs(x)∞∑k=1(λsx)k−1(k−1)!e−λsx−∫x0μs(τ)dτdx∞∑j=1|pj,s(0)|=n∑s=1∫∞0μs(x)e−∫x0μs(τ)dτdx∞∑j=1|pj,s(0)|=n∑s=1∞∑j=1|pj,s(0)|=‖(p1(0),p2(0),⋯,pn(0))‖. | (3.19) |
That is, ‖ΦDib‖<1 for all |b|>M. Since λ0>0 and μ_s>0, there exists γ1=min{λ0,μ_s}>0 such that {γ∈C∣Re(γ)>−γ1}⊂ρ(A0). This means that γ=ib∈ρ(A0). Then, by the above inequality (3.31), we know that the spectral radius r(ΦDib) of operator ΦDib satisfies r(ΦDib)≤‖ΦDib‖<1 if |b|>M. In other words, 1∉σ(ΦDib) for |b|>M. This indicates that there must be γ0=2|b| satisfying 1∉σ(ΦDγ0). Consequently, using Lemma 3.4, we obtain γ=ib∉σ(AΦ) for |b|>M, i.e.,
{ib||b|>M}⊂ρ(AΦ) and{ib||b|≤M}⊂σ(AΦ)∩iR. |
On the other hand, since eAΦt is a positive uniformly bounded semigroup (Theorem 2.1), using Corollary 2.3 of [24], we obtain that σ(AΦ)∩iR is imaginary additively cyclic, which states that ib∈σ(AΦ)∩iR, and we deduce that ibk∈σ(AΦ)∩iR for every integer k. Therefore, combining the above discussion with the inclusion relationship {ib||b|≤M}⊂σ(AΦ)∩iR and Lemma 3.1, we have σ(AΦ)∩iR={0}.
Lemma 3.6. The specific expression of the adjoint operator AΦ∗ of AΦ is as follows:
A∗Φ(p∗1,p∗2,⋯,p∗n)=((λ0n∑s=1qsp∗1,s(0)0μ1(x)p∗1,1(0)μ1(x)p∗2,1(0)⋱)+(−λ0000⋯μ1(x)ϕ1λ10⋯00ϕ1λ1⋯000ϕ1⋯⋮⋮⋮⋮⋱)(p∗0,0p∗1,1(x)p∗2,1(x)p∗3,1(x)⋮),(μ2(x)p∗0,0μ2(x)p∗1,2(0)μ2(x)p∗2,2(0)⋱)+(ϕ2λ200⋯0ϕ2λ20⋯00ϕ2λ2⋯⋮⋮⋮⋱)(p∗1,2(x)p∗2,2(x)p∗3,2(x)⋮),⋯⋯,(μn(x)p∗0,0μn(x)p∗1,n(0)μn(x)p∗2,n(0)⋱)+(ϕnλn00⋯0ϕnλn0⋯00ϕnλn⋯⋮⋮⋮⋱)(p∗1,n(x)p∗2,n(x)p∗3,n(x)⋮)), |
with domain D(A∗Φ)={(p∗1,p∗2,⋯,p∗n)∈X∗∣dp∗k,s(x)dxexisting andp∗k,s(∞)=h}, where ϕs=ddx−[λs+μs(x)] and h is a positive constant that is independent of k and s.
Proof. For (p1,p2,⋯,pn)∈D(AΦ) and (p∗1,p∗2,⋯,p∗n)∈D(A∗Φ), using integration by parts, we calculate that
⟨AΦ(p1,p2,⋯,pn),(p∗1,p∗2,⋯,p∗n)⟩=[−λ0p0,0+n∑s=1∫∞0p1,s(x)μs(x)dx]p∗0,0+n∑s=1{∞∑k=1∫∞0[−dpk,s(x)dx−(λs+μs(x))pk,s(x)]p∗k,s(x)dx+∞∑k=2∫∞0λspk−1,s(x)p∗k,s(x)dx}=−λ0p0,0p∗0,0+p∗0,0n∑s=1∫∞0p1,s(x)μs(x)dx+n∑s=1∞∑k=1pk,s(0)p∗k,s(0)+n∑s=1∞∑k=1∫∞0pk,s(x)[dp∗k,s(x)dx−(λs+μs(x))p∗k,s(x)]dx+λsn∑s=1∞∑k=1∫∞0pk,s(x)p∗k+1,s(x)dx=−λ0p0,0p∗0,0+p∗0,0n∑s=1∫∞0p1,s(x)μs(x)dx+n∑s=1(qsλ0p∗0,0+∫∞0p∗2,s(x)μs(x)dx)p∗1,s(0)+n∑s=1∞∑k=2∫∞0pk+1,s(x)μs(x)dxp∗k,s(0)+n∑s=1∞∑k=1∫∞0pk,s(x)[dp∗k,s(x)dx−(λs+μs(x))p∗k,s(x)]dx+n∑s=1λs∞∑k=1∫∞0pk,s(x)p∗k+1,s(x)dx=−λ0p0,0p∗0,0+p∗0,0n∑s=1∫∞0p1,s(x)μs(x)dx+λ0p0,0n∑s=1qsp∗1,s(0)+n∑s=1∞∑k=1∫∞0pk+1,s(x)μs(x)dxp∗k,s(0)+n∑s=1∞∑k=1∫∞0pk,s(x)[dp∗k,s(x)dx−(λs+μs(x))p∗k,s(x)]dx+n∑s=1λs∞∑k=1∫∞0pk,s(x)p∗k+1,s(x)dx=⟨(p0,p1,⋯,pn),A∗Φ(p∗0,p∗1,⋯,p∗n)⟩. | (3.20) |
Then, from the last equation of the above Eq (3.20), we can obtain AΦ∗.
Lemma 3.7. The zero is an eigenvalue of A∗Φ with geometric multiplicity one.
Proof. We consider A∗Φ(p∗1,p∗2,⋯,p∗n)=0. This equation is equivalent to
−λ0p∗0,0+λ0n∑s=1qsp∗1,s(0)=0, | (3.21a) |
dp∗1,s(x)dx−[λs+μs(x)]p∗1,s(x)+λsp∗2,s(x)+μs(x)p∗0,0=0, | (3.21b) |
dp∗k,s(x)dx−[λs+μs(x)]p∗k,s(x)+λsp∗k+1,s(x)+μs(x)p∗k−1,s(0)=0,k≥2, | (3.21c) |
p∗k,s(∞)=h,k≥1,1≤s≤n. | (3.21d) |
By the above equations, it is easy to investigate that
(p∗1,p∗2,⋯,p∗n)(h):=((h⋮),(h⋮),⋯,(h⋮))∈D(A∗Φ), |
is a positive solution of Eqs (3.21a)–(3.21d). In addition, Eqs (3.21a)–(3.21d) are equivalent to
p∗0,0=n∑s=1qsp∗1,s(0), | (3.22a) |
p∗2,s(x)=1λs[−dp∗1,s(x)dx+(λs+μs(x))p∗1,s(x)−μs(x)p∗0,0], | (3.22b) |
p∗k+1,s(x)=1λs[−dp∗k,s(x)dx+(λs+μs(x))p∗k,s(x)−μs(x)p∗k−1,s(0)],k≥2. | (3.22c) |
Clearly, Eqs (3.22a)–(3.22c) imply that the geometric multiplicity of zero is one.
Proof of Theorem 3.1: Theorem 2.1 shows that semigroup eAΦt is a uniformly bounded C0−semigroup on Banach space X. In addition, using Lemmas 3.1, 3.5, and 3.7, we obtain that σp(AΦ)∩iR=σp(A∗Φ)∩iR={0} and {γ∈C∣γ=ib,b≠0,b∈R}⊂ρ(AΦ), and zero is an eigenvalue of A∗Φ with algebraic multiplicity one. Hence, due to Theorem 1.96 of [12], we obtain that the time-evolving solution of system (2.2) converges strongly to its static solution. In other words,
limt→∞‖(p1,p2,⋯,pn)(⋅,t)−⟨(p∗1,p∗2,⋯,p∗n),(g1,g2,⋯,gn)⟩(p1,p2,⋯,pn)(⋅)‖=0, |
where (p∗1,p∗2,⋯,p∗n) and (p1,p2,⋯,pn) are the eigenvectors associated to zero in Lemmas 3.7 and 3.1, respectively.
To prove the exponential convergence of the time-evolving solution, we need to find the spectral distribution of AΦ on the left-half complex plane. For this objective, we first provide the following Lemma 3.8.
Lemma 3.8. If λs<μs,1≤s≤n, then each point in
Λ:={γ∈C||γ+λs+μs±√(γ+λs+μs)2−4λsμs|<2μs,Re(γ)+μs>0}∪{0}, |
is an eigenvalue of AΦ with geometric multiplicity one, in particular
(−min1≤s≤n{μs},min1≤s≤n{2√λsμs−λs−μs})⋃[max1≤s≤n{2√λsμs−λs−μs},0]⊂σ(AΦ). |
Proof. For each γ∈Λ, we consider the equation AΦ(p1,p2,⋯,pn)=γ(p1,p2,⋯,pn) of unknown (p1,p2,⋯,pn)∈D(AΦ). This is equivalent to the following system:
(γ+λ0)p0,0=n∑s=1μs∫∞0p1,s(x)dx, | (3.23a) |
dp1,s(x)dx=−(γ+λs+μs)p1,s(x), | (3.23b) |
dpk,s(x)dx=−(γ+λs+μs)pk,s(x)+λspk−1,s(x),k≥2, | (3.23c) |
p1,s(0)=qsλ0p0,0+μs∫∞0p2,s(x)dx, | (3.23d) |
pk,s(0)=μs∫∞0pk+1,s(x)dx,k≥2. | (3.23e) |
Solving Eqs (3.23b) and (3.23c), we have
pk,s(x)=e−(γ+λs+μs)xk∑j=1(λsx)k−j(k−j)!pj,s(0),k≥1;1≤s≤n. | (3.24) |
From this together with the formula
∫∞0xk−je−(γ+λs+μs)xdx=(k−j)!(γ+λs+μs)k+1−j,Re(γ)+λs+μs>0, |
we obtain
∫∞0pk,s(x)dx=k∑j=1λk−js(γ+λs+μs)k+1−jpj,s(0),k≥1. | (3.25) |
We can thus combine Eqs (3.23e) and (3.25) to obtain
pk,s(0)=μsk+1∑j=1λk+1−js(γ+λs+μs)k+2−jpj,s(0),k≥2. | (3.26) |
This yields
pk+1,s(0)−λsγ+λs+μspk,s(0)=μsγ+λs+μspk+2,s(0),k≥2. |
Clearly, the above equation is equivalent to
pk+2,s(0)=γ+λs+μsμspk+1,s(0)−λsμspk,s(0),k≥2. | (3.27) |
For any complex number ξs and ηs,1≤s≤n, if we set
pk+2,s(0)−ξspk+1,s(0)=ηs[pk+1,s(0)−ξspk,s(0)],k≥2, | (3.28) |
then it is easy to see that ξs and ηs satisfy the following two equations:
ξs+ηs=γ+λs+μsμs,ξsηs=λsμs. | (3.29) |
From Eq (3.29), it is easy to determine that
ξs=γ+λs+μs+√(γ+λs+μs)2−4λsμs2μs, | (3.30a) |
ηs=γ+λs+μs−√(γ+λs+μs)2−4λsμs2μs. | (3.30b) |
Note that from Eq (3.28), we observe that
pk+2,s(0)−ξspk+1,s(0)=ηk−1s[p3,s(0)−ξsp2,s(0)],k≥2. | (3.31) |
Then, by reusing the above equations and organizing it, we obtain
pk+2,s(0)=ξspk+1,s(0)−ξs[pk+1,s(0)−ξspk,s(0)]−ξ2s[pk,s(0)−ξspk−1,s(0)]−ξ3s[pk−1,s(0)−ξspk−2,s(0)]−ξk−2s[p4,s(0)−ξsp3,s(0)]=[ηk−1s+ξsηk−2s+⋯+ξk−2sηs+ξk−1s]p3,s(0)−[ηk−2s+ξsηk−3s+⋯+ξk−3sηs+ξk−2s]ξsηsp2,s(0),k≥2. | (3.32) |
If ξs=ηs, then Eq (3.32) is simplified as
pk+2,s(0)=kξk−1sp3,s(0)−(k−1)ξksp2,s(0),k≥2. |
The inequality |pk+2,s(0)|≤k|ξs|k−1|p3,s(0)|+(k−1)|ξs|k|p2,s(0)| can be obtained by taking the absolute value of the above equation. Then, taking the sum of k=2 to ∞ for this inequality, we obtain
∞∑k=2|pk+2,s(0)|≤|p3,s(0)|∞∑k=2k|ξs|k−1+|p2,s(0)|∞∑k=2(k−1)|ξs|k. | (3.33) |
If ξs≠ηs, then Eq (3.32) can be written as
pk+2,s(0)=p3,s(0)−ηsp2,s(0)ξs−ηsξks−p3,s(0)−ξsp2,s(0)ξs−ηsηks. |
This means that
∞∑k=2|pk+2,s(0)|≤|p3,s(0)−ηsp2,s(0)ξs−ηs|∞∑k=2|ξs|k+|p3,s(0)−ξsp2,s(0)ξs−ηs|∞∑k=2|ηs|k. | (3.34) |
Moreover, take the L1[0,∞)−norm on both sides of Eq (3.34), and using the formula
∫∞0xk−je−(Re(γ)+λs+μs)xdx=(k−j)!(Re(γ)+λs+μs)k+1−j, |
for all Re(γ)+μs>0, we have
‖pk,s‖L1[0,∞)≤k∑j=1λk−js(k−j)!|pj,s(0)|∫∞0xk−je−(Re(γ)+λs+μs)xdx=1Re(γ)+λs+μsk∑j=1(λsRe(γ)+λs+μs)k−j|pj,s(0)|. | (3.35) |
Therefore, for all Re(γ)+μs>0, by the above inequalities and Cauchy product of series, we obtain
∞∑k=1‖pk,s‖L1[0,∞)≤1Re(γ)+λs+μs∞∑k=1k∑j=1(λsRe(γ)+λs+μs)k−j|pj,s(0)|=1Re(γ)+λs+μs∞∑k=1|pk,s(0)|∞∑j=1(λsRe(γ)+λs+μs)j−1=1Re(γ)+μs∞∑k=1|pk,s(0)|. | (3.36) |
In addition, from Eqs (3.23a), (3.25), (3.23d), and (3.26), it is easy to calculate that
p0,0=1γ+λ0n∑s=1μsγ+λs+μsp1,s(0), | (3.37a) |
p1,s(0)=qsλ0p0,0+μs[λs(γ+λs+μs)2p1,s(0)+1γ+λs+μsp2,s(0)], | (3.37b) |
p2,s(0)=(γ+λs+μs)2−λsμsμs(γ+λs+μs)p1,s(0)−(γ+λs+μs)qsλ0μsp0,0, | (3.37c) |
p3,s(0)=(γ+λs+μs)2−λsμsμs(γ+λs+μs)p2,s(0)−(λsγ+λs+μs)2p1,s(0). | (3.37d) |
Finally, by Eqs (3.30a) and (3.30b), it is easy to see that γ∈Λ if, and only if, Re(γ)+μs>0 and |ξs|<1,|ηs|<1,1≤s≤n. Therefore, if γ∈Λ, then from Eqs (3.36), (3.33), (3.34), (3.37a), and (3.37d), we obtain
‖(p1,p2,⋯,pn)‖=|p0,0|+n∑s=1∞∑k=1‖pk,s‖L1[0,∞)<∞. | (3.38) |
The Eq (3.38) shows that for any γ in Λ is an eigenvalue of AΦ. Moreover, Eqs (3.24), (3.26), (3.32), (3.37a), and (3.37d) mean that the geometric multiplicity of every γ∈Λ is one.
Next, we observe the case γ∈R. Since Theorem 2.3 implies that (0,∞)⊂ρ(AΦ), the real spectrum of AΦ in the interval (−∞,0] exists. We discuss the real spectrum of AΦ in the following three cases.
Case 1: (γ+λs+μs)2>4λsμs if, and only if, |γ+λs+μs|>2√λsμs. Since γ+μs>0 and γ+λs+μs>2√λsμs, we have γ>2√λsμs−λs−μs. From this together with λs<μs and γ+μs>0, it is easy to calculate that
γ<0⇒4μs(γ+λs)−4λsμs<0⇒(γ+λs)2+2μs(γ+λs)+μ2s−4λsμs<(γ+λs)2−2μs(γ+λs)+μ2s⇒√(γ+λs+μs)2−4λsμs<−(γ+λs−μs)⇒γ+λs+μs+√(γ+λs+μs)2−4λsμs<2μs⇒0<ξs=γ+λs+μs+√(γ+λs+μs)2−4λsμs2μs<1,0<ηs=γ+λs+μs−√(γ+λs+μs)2−4λsμs2μs<ξs<1. | (3.39) |
This implies (max1≤s≤n{2√λsμs−λs−μs},0)⊂σ(AΦ). Then, from this together with Lemma 3.1, we obtain
(max1≤s≤n{2√λsμs−λs−μs},0]⊂σ(AΦ). |
Case 2: (γ+λs+μs)2=4λsμs if, and only if, |γ+λs+μs|=2√λsμs. Since γ+μs>0 and γ+λs+μs=2√λsμs, we deduce γ=2√λsμs−λs−μs. Then, using λs<μs and γ+μs>0, we have
0<ξs=ηs=γ+λs+μs2μs=2√λsμs2μs=√λsμs<1. |
This shows that max{2√λ1μ1−λ1−μ1,⋯,2√λnμn−λn−μn} is an eigenvalue of AΦ.
Case 3: (γ+λs+μs)2<4λsμs if, and only if, −2√λsμs<γ+λs+μs<2√λsμs. Since γ+μs>0 and 0<γ+λs+μs<2√λsμs, we obtain γ<2√λsμs−λs−μs. Then, from this together with λs<μs, γ+μs>0, and i2=−1, we have
ξs,ηs=γ+λs+μs±i√4λsμs−(γ+λs+μs)22μs. |
Therefore,
|ξs|=|ηs|=√(γ+λs+μs)2+4λsμs−(γ+λs+μs)22μs=√λsμs<1. | (3.40) |
Hence, this implies that
(−min1≤s≤n{μs},min1≤s≤n{2√λsμs−λs−μs})⊂σ(AΦ). |
Consequently, by summing up the above three cases, we obtain
(−min1≤s≤n{μs},min1≤s≤n{2√λsμs−λs−μs})⋃[max1≤s≤n{2√λsμs−λs−μs},0]⊂σ(AΦ). |
Let ω0(AΦ), ωess(AΦ), s(AΦ) represent the growth bound, the essential growth bound, and spectral bound of AΦ, respectively. The spectral mapping theorem [11] means that
σp(eAΦt)=etσp(AΦ)∪{0}, |
Hence, from this property and Lemma 3.8, we obtain that eAΦt has uncountable eigenvalues. Therefore, eAΦt is not compact and it is not eventually compact by Corollary V.3.2 of [11].
Additionally, due to eAΦt being a C0−semigroup on X with generator AΦ, using Corollary IV.2.11 of [11], we know that ω0=max{ωess,s(AΦ)} and σ(AΦ)∩{γ∈C|Re(γ)≥w} is finite for every w>ωess. Using Lemma 3.8, we can obtain that the spectrum determined condition ω0=s(AΦ) holds and ω0=s(AΦ)=0 (we suggest that readers refer to the proof of Theorem 4.1 in [25] for similar proofs in this part). Hence, using the aforementioned discussions, we have ωess=0. Then, by Proposition 3.5 of [11], we derive that eAΦt is not quasi-compact.
The main result of this subsection is given by the following Theorem 3.2.
Theorem 3.2. Let μs(⋅):=μs be a constant and λs<μs,1≤s≤n. Then, the time-evolving solution of the system (2.2) cannot exponentially converge to its static solution. That is to say, there are no constants M>0 and ε>0 such that
‖eAΦt((p1,p2,⋯,pn)(0)+AΦ(p1,p2,⋯,pn))−(p1,p2,⋯,pn)(0)‖≤Me−εt‖(p1,p2,⋯,pn)‖, |
for any t≥0 and (p1,p2,⋯,pn)∈D(AΦ), where (p1,p2,⋯,pn)(0) is the eigenvector associated to zero.
Proof. Assume that (p1,p2,⋯,pn)(0) and (p1,p2,⋯,pn)(r) are the eigenvectors of 0 and
rmax1≤s≤n{2√λsμs−λs−μs}:=rβs, |
in Lemma 3.8, respectively, for any r∈(0,1). Hence, using AΦ(p1,p2,⋯,pn)(0)=0 and AΦ(p1,p2,⋯,pn)(r)=rβs(p1,p2,⋯,pn)(r), we have
eAΦt[(p1,p2,⋯,pn)(0)+AΦ(p1,p2,⋯,pn)(r)]=eAΦt(p1,p2,⋯,pn)(0)+eAΦtAΦ(p1,p2,⋯,pn)(r)=(p1,p2,⋯,pn)(0)+eAΦtrβs(p1,p2,⋯,pn)(δ)=(p1,p2,⋯,pn)(0)+rβserβst(p1,p2,⋯,pn)(r). | (3.41) |
Therefore,
‖eAΦt((p1,p2,⋯,pn)(0)+AΦ(p1,p2,⋯,pn)(r))−(p1,p2,⋯,pn)(0)‖=r|βs|erβst‖(p1,p2,⋯,pn)(r)‖,∀t≥0,∀r∈(0,1). | (3.42) |
That is, there are no constants M>0 and ε>0 such that
‖eAΦt((p1,p2,⋯,pn)(0)+AΦ(p1,p2,⋯,pn))−(p1,p2,⋯,pn)(0)‖≤Me−εt‖(p1,p2,⋯,pn)‖. |
for any t≥0 and (p1,p2,⋯,pn)∈D(AΦ).
In neural network [17] and reliability model [12], it has been proven that the semigroup corresponding to these systems is a quasi-compact strongly continuous semigroup, thus they obtain the dynamic solution of the corresponding system that strongly converges to its steady-state solution. Therefore, the result of Theorem 3.2 is significantly different from those in [12,17].
Define the time-evolving queue length of system (1.6) by
L(t)=p0,0(t)+n∑s=1∞∑k=1∞∫0pk,s(x,t)dx. |
Then, by combining Theorems 2.1, 2.3 and 3.1 and Lemma 3.1, we can obtain the asymptotic behavior of L(t).
Theorem 4.1. Let μs(x):[0,∞)→[0,∞) be a measurable function that satisfies
0<infx∈[0,∞)μs(x)≤μs(x)≤supx∈[0,∞)μs(x)<∞,1≤s≤n. |
If the initial value (g1(⋅),g2(⋅),⋯,gn(⋅)) of the system (1.6) and the eigenvector (˜p1(⋅),˜p2(⋅),⋯,˜pn(⋅)) corresponding to zero satisfying ˜ps(⋅)≥us(⋅), then time-evolving queue length L(⋅) of system (1.6) converges to its static queue length. That is to say,
limt→∞L(t)=˜p0,0+n∑s=1∞∑k=1∞∫0˜pk,s(x)dx. |
Proof. For any (p1,p2,⋯,pn) and (y1,y2,⋯,yn) in X, we introduce an order relation "≥" by
(p1,p2,⋯,pn)≥(y1,y2,⋯,yn)⟺ps≥ys,1≤s≤n⟺p0,0≥y0,0andpk,s(x)≥yk,s(x),x∈[0,∞),k≥1,1≤s≤n. |
Then, it is not difficult to show that "≥" is a partial order relation in X. Therefore, (X,≥) is a poset. Let (˜p1,˜p2,⋯,˜pn) be the positive eigenvector associated to zero of AΦ (Lemma 3.1). Let (˜p1,˜p2,⋯,˜pn) and the initial value (g1,g2,⋯,gn) of the system (2.2) satisfy the aforementioned partial order relation
˜p0,0≥g0,0,˜pk,s(x)≥gk,s(x),x∈[0,∞),k≥1,1≤s≤n. |
That is, (˜p1,˜p2,⋯,˜pn)≥(g1,g2,⋯,gn). Due to eAΦt being a positive linear operator (Theorem 2.1), it is a monotone increasing operator. In addition, by Theorem 2.3 and Lemma 3.1, we know that
{(p1(⋅,t),p2(⋅,t),⋯,pn(⋅,t))=eAΦt(g1(⋅),g2(⋅),⋯,gn(⋅)),t≥0,eAΦt(˜p1(⋅),˜p2(⋅),⋯,˜pn(⋅))=(˜p1(⋅),˜p2(⋅),⋯,˜pn(⋅)),t≥0. |
Therefore, from this together with the partial order relation (˜p1,˜p2,⋯,˜pn)≥(g1,g2,⋯,gn), we have
eAΦt(˜p1(⋅),˜p2(⋅),⋯,˜pn(⋅))≥eAΦt(g1(⋅),g2(⋅),⋯,gn(⋅))⟹(˜p1(⋅),˜p2(⋅),⋯,˜pn(⋅))≥(p1(⋅,t),p2(⋅,t),⋯,pn(⋅,t))⟹˜p0,0≥p0,0(t),˜pk,s(⋅)≥pk,s(⋅,t),k≥1,⟹∞>˜p0,0+n∑s=1∞∑k=1∞∫0˜pk,s(x)dx≥p0,0(t)+n∑s=1∞∑k=1∞∫0pk,s(x,t)dx,t≥0. |
Theorem 3.1 includes the following result:
limt→∞[|p0,0(t)−˜p0,0|+n∑s=1∞∑k=1∞∫0|pk,s(x,t)−˜pk,s(x)|dx]=0. |
Hence, by Lemma 3.1 and the Lebesgue theorem, we obtain
limt→∞|L(t)−[˜p0,0+n∑s=1∞∑k=1∞∫0˜pk,s(x)dx]|≤limt→∞[|p0,0(t)−˜p0,0|+n∑s=1∞∑k=1∞∫0|pk,s(x,t)−˜pk,s(x)|dx]=0. |
This inequality shows that
limt→∞L(t)=˜p0,0+n∑s=1∞∑k=1∞∫0˜pk,s(x)dx. |
Remark 4.1. In Theorem 4.1, the static queue length is obtained by using the eigenvector that related to zero (Lemma 3.1). This is the same as the result obtained by introducing probability generating functions in [3].
Similarly, we can obtain the other time-evolving indicators of system (1.6) such as the convergence of the time-evolving average number of customers to its static average number of customers.
To prove the correctness of the exponential convergence results in this article, we perform numerical analysis on the spectral results in Lemma 3.8. The numerical analysis results are shown in Figures 1 and 2. We obtain these numerical results using Matlab.
In Figure 1(a), we consider that system (1.6) only has the idle period and one operational phase, that is, n=1 in system (1.6). In other words, we consider the classical queuing model [5], and the point spectrum results of the system operator AΦ of this queueing model [5] are obtained in detail in [8,9,10]. If we take λ1=0.1,μ1=0.9, then it is easy to see that λ1μ1=0.10.9<1 and 2√λ1μ1−λ1−μ1=−0.4. In addition, Figure 1(a) means that 0<ξ1<1 and 0<η1<1 for all γ∈(−0.4,0). Hence, by Eqs (3.34) and (3.36), we see that every γ∈(−0.4,0) is the point spectrum of AΦ.
In Figure 1(b), we consider that system (1.6) only has the idle period and two operational phases, that is, n=2 in system (1.6). In this case, we take λ1=0.1,μ1=0.9 and λ2=0.2,μ2=0.8. Then, these values satisfy λ1μ1=19,λ2μ2=14, and maxs=1,2{2√λsμs−λs−μs}=−0.2. Moreover, when γ∈(−0.2,0), from Figure 1(b) we see that ξ1,ξ2,η1, and η2 satisfy 0<ξn<1 and 0<ηn<1. Therefore, by Eqs (3.34) and (3.36), we know that all γ∈(−0.2,0) are the point spectrum of AΦ. Figure 1 means that the point spectrum results in Lemma 3.8 are correct if λs<μs,s=1,2. Therefore, the exponential convergence result of Theorem 3.2 is valid.
In the following, we check whether the condition λs<μs,1≤s≤n in Lemma 3.8 is necessary. In Figure 2, we consider that system (1.6) only has the idle period and two operational phases, that is, n=2 in system (1.6). If we take λ1=0.1,μ1=0.9 and λ2=0.8,μ2=0.2, then we have λ1<μ1 and λ2>μ2. In this case, Figure 2(a) means that 0<ξ1<1,0<η1<1, and ξ2>1,η2>1 for all γ∈(−0.2,0).
If we take λ1=0.9,μ1=0.1 and λ2=0.8,μ2=0.2, then we have λn>μn. In this case, Figure 2(b) implies that ξn>1 and ηn>1 for all γ∈(−0.2,0). Of course, we can choose some different λn and μn, at least one of which satisfies λs0>μs0 for some s0=1,2,⋯,n, to obtain the same conclusion. As a result, Figure 2 means that we cannot obtain whether it is γ∈σp(AΦ), or even whether it is γ∈σ(AΦ) under the above circumstances, where γ∈(max1≤s≤n{2√λsμs−λs−μs},0). Therefore, in Lemma 3.8 (or in Theorem 3.2), we must consider the condition λs<μs. This condition is also the stability condition obtained for system (1.6) in reference [3].
In this article, we conduct a dynamic analysis of the M/G/1 queueing system with multiple phases of operation. Using operator semigroup theory, we prove that there exists a unique time-evolving solution for this system. We obtain the spectral distribution of the system operator on the imaginary axis and prove that the system operator has an infinite number of eigenvalues on the left-half of the complex plane. As a result, the above solution converges at most strongly to its static solution. We also discuss the compactness of the system's corresponding semigroup by using these spectral results. However, we have not obtained the complete spectrum of the system operator on the left-half of the complex plane. This is the work we will continue to do in the future. Additionally, we obtain that the dynamic queue length of the model strongly converges to its static queue length.
The method described in this article can only be applied to queuing systems established using the supplementary variable method and described by partial differential equations. For example, we cannot use the method proposed in this paper for the queuing systems in [1,26,27].
The authors declare that they have not used Artificial Intelligence (AI) tools in the creation of this article.
We are grateful to the anonymous referees, who read carefully the manuscript and made valuable comments and suggestions. This work was supported by the National Natural Science Foundation of China (No: 12301150) and Natural Science Foundation of Xinjiang Uygur Autonomous Region (No: 2024D01C229).
The authors declare there is no conflict of interest.
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