We extend the weighted gradient estimate for solutions of nonlinear PDE associated to the prescribed k-th Lp-area measure problem to the case 0<p<1. The estimate yields non-collapsing estimate for symmetric convex bodied with prescribed Lp-area measures.
Citation: Pengfei Guan. A weighted gradient estimate for solutions of Lp Christoffel-Minkowski problem[J]. Mathematics in Engineering, 2023, 5(3): 1-14. doi: 10.3934/mine.2023067
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We extend the weighted gradient estimate for solutions of nonlinear PDE associated to the prescribed k-th Lp-area measure problem to the case 0<p<1. The estimate yields non-collapsing estimate for symmetric convex bodied with prescribed Lp-area measures.
Dedicated to Professor Neil Trudinger on the occasion of his 80th birthday.
The classical Christoffel-Minkowski problem is a problem of prescribing k-th area measure on Sn. Given a Borel measure μ=fdσSn on Sn, one seeks a convex body K⊂Rn+1 such that its k-th area measure Sk(K,x)=μ. It is a fundamental problem in convex geometry. The problem plays important rule in the development of nonlinear geometric partial differential equations.
The Christoffel-Minkowski problem corresponds to solving the following fully nonlinear elliptic equation
σk(W(x))=f(x),W(x)>0, ∀x∈Sn, | (1.1) |
where u is the support function of K defined on Sn and
W(x)=(uij(x)+uδij(x)),∀x∈Sn. |
The Christoffel problem and the Minkowski problem correspond to the cases k=1 and k=n respectively [1,2,4,7,15,16,17]. The notion of area measures in the Brunn-Minkowski theory is based on Minkowski summation. Lutwak [12] developed corresponding Lp Brunn-Minkowski-Firey theory based on Firey's p-sum [5]. Lp-Minkowski problem has attracted much attention, we refer [3,6,12,13,14] and references therein.
The focus of this paper is on the intermediate Lp-Christoffel-Minkowski problem. The problem is deduced to solve the following PDE on Sn,
σk(W(x))=up−1f(x),W(x)>0, ∀x∈Sn. | (1.2) |
p=1 is the classical Christoffel-Minkowski problem [7,17]. The case p≥k+1 was considered by Hu-Ma-Shen [9] and the case 1<p<k+1 was considered by Guan-Xia [8]. Very little is known for Eq (1.2) in the case 0<p<1.
In general, admissible solutions to σk(W)=f is not convex (i.e., W>0) if k<n. The existence of geometric solutions of (1.2) relies on two ingredients:
1) A priori upper and lower bounds of solutions,
2) Convexity of solutions (i.e., W>0).
When p−1<k<n, in general there is no direct non-collapsing estimate for convex body satisfying Eq (1.2) when k<n. For p≥k+1, maximum principle implies the upper and lower bounds of solutions [9]. When p<k+1, the lower bound of solutions are not true in general as discussed in examples in [8]. In [8], the upper and lower bounds for even solutions of (1.2) were obtained for 1<p<k+1. The estimate relies on a weighted gradient estimate for |∇u|2(u−mu)γ where mu=minx∈Snu. The purpose of this paper is to extend such estimate for the case 0<p<1.
Similar to the classical intermediate Christoffel-Minkowski problem, one needs to impose appropriate appropriate conditions on the prescribed function f in Eq (1.1) to ensure the convexity of solutions to (1.2). The key is the Constant Rank Theorem established by Guan-Ma in [7]. When p>1, a corresponding condition was deduced in [9] from the Constant Rank Theorem in [7]. When 0<p<1, it is an open problem to find a clean condition on f to guarantee the convexity of solutions to (1.2).
In this section, we modify the arguments in [8] to establish a weighted gradient estimate for solutions of the intermediate Christoffel-Minkowski problem (1.2) for 0<p≤1. Specifically, we extend Proposition 3.1 in [8] to the case 0<p<1. Recall Garding's cone
Γk={λ=(λ1,⋯,λn)∈Rn | σj(λ)>0, ∀j=1,⋯,k.} |
A symmetric matrix W is called in Γk if its eigenvalue vector λW∈Γk. A positive function u∈C2(Sn) is called an admissible solution to (1.2) if W(x)∈Γk, ∀x∈Sn.
In the rest of the paper, we denote
(λ | 1)=(0,λ2,⋯,λn), ∀λ=(λ1,λ2,⋯,λn)∈Rn. |
Proposition 2.1. Let 0<p≤1 and let u be a positive admissible solution to (1.2). Denote mu=minu and Mu=maxu. Set
γ=2pk+4. | (2.1) |
Then there exist some positive constants A depending only on n,k,p and ‖logf‖C1, such that
|∇u|2|u−mu|γ≤AM2−γu. | (2.2) |
The weighted gradient estimate for |∇u|2uγ was used in [6], later in [8,10,11]. It's useful tool to obtain lower bound of solution u.
Proof. After proper rescale, we may assume minx∈Snf(x)=1. Maximum principle yields that there is Cn,k,p>0, such that
Mu≥Cn,k,p. |
Set
Φ=|∇u|2(u−mu)γ, |
where 0<γ<1 as in (2.1). As pointed out in [8] that Φ is well-defined and it makes sense to define Φ=0 at the minimum point of u.
Let x0 be a maximum point of Φ. Then u(x0)>mu if u is not a constant. We may pick an orthonormal frame on Sn such that u1(x0)=|∇u|(x0) and ui(x0)=0 for i=2,⋯,n. At x0,
2ululi|∇u|2=γuiu−mu for each i. |
Thus u1i=0 for i=2,⋯,n and
u11=γ2u21u−mu=γ2Φ1(u−mu)1−γ. | (2.3) |
Re-rotating the remaining n−1 coordinates, we may assume
(uij) is diagonal, so are (Wij(x0)) and (Fij)(x0)=(∂σk∂Wij)(x0). |
We may assume ΦM2−γu is sufficiently large at x0. In the rest of proof, constant C may change line by line, but under control.
W11≤u11(1+C(M2−γuΦ)). | (2.4) |
At x0, it follows from (2.3) and (1.2),
0≥Fii(logΦ)ii=Fii2u2ii+2ululii|∇u|2−γFiiuiiu−mu+γ(1−γ)Fiiu2i(u−mu)2=2Fiiu2iiu21+2Fiiu1(Wii1−uiδ1i)u21−γFiiuiiu−mu+γ(1−γ)Fiiu2i(u−mu)2=2Fiiu2iiu21+2(p−1)up−2f+2up−1f1u1−2F11−γFiiuiiu−mu+γ(1−γ)Fiiu2i(u−mu)2≥2Fiiu2iiu21+2(p−1)up−2f+γ(1−γ)F11u21(u−mu)2+2up−1f1u1−2F11−γFiiWiiu−mu≥2Fiiu2iiu21+2(1−γ)F11u11u−mu+2up−1f1u1−2F11−(kγ−2(p−1))σk(W)u−mu≥2(1−γ)F11u11u−mu+2up−1f1u1+2F11(u211u21−1)−(kγ−2(p−1))σk(W)u−mu. | (2.5) |
It follows the definition of Φ,
2up−1f1u1≥−Cup−1fΦ−12(u−mu)−γ2≥−Cσk(W)u−muM1−γ2uΦ12. | (2.6) |
Note that M2−γuΦ sufficiently small by the assumption.
By (2.3) and (2.4),
u211u21−1=γ2u11u−mu−1=γ2W11u−mu(1−CM2−γuΦ). | (2.7) |
W11≥γ4Φ(u−mu)1−γ≥γ4ΦM2−γuM2−γu(u−mu)1−γ. | (2.8) |
Put (2.6) and (2.7) to (2.5),
0≥(2−γ−CM2−γuΦ)F11W11u−mu−(kγ−2(p−1)+CM1−γ2uΦ12)σk(W)u−mu | (2.9) |
We divide in to two cases.
Case Ⅰ.
σk(W|1)≤γσk−1(W|1)W11. |
We have,
σk(W)=σk−1(W|1)W11+σk(W|1)≤(1+γ)σk−1(W|1)W11=(1+γ)F11W11. |
Put this into (2.9), we obtain
0≥2−γ−(1+γ)(kγ−2(p−1)+CM1−γ2uΦ12). |
By the choice of γ in (2.1),
CM1−γ2uΦ12≥pk+4. |
(2.2) is verified in this case.
Case Ⅱ.
σk(W|1)>γσk−1(W|1)W11. |
If k≥2, by the Newton-MacLaurin inequality,
σkk−1k−1(W|1)≥Cn,kσk(W|1). |
In turn,
σkk−1k−1(W|1)≥Cn,kσk(W|1)>Cn,kγσk−1(W|1)W11. |
Hence, σ1k−1k−1(W|1)≥Cn,kγW11. We now have,
up−1f=σk(W)=σk(W|1)+σk−1(W|1)W11≥(1+γ)σk−1(W|1)W11≥(Cn,kγ)k−1Wk11. |
Note that the above inequality is trivial for k=1 in this case. We obtain
W11≤(Cn,kγ)k−1kup−1kf1k. | (2.10) |
Then (2.2) follows from (2.10), (2.3) and (2.4).
When u is a convex solution of (1.2), estimate (2.2) in Proposition 2.1 can be refined. We will use this type of refined estimates to establish existence of convex even solutions for Eq (1.2) when 0<1−p is close to 0.
Proposition 2.2. Let 0<p≤1 and let u be a positive convex solution to (1.2).
a. If k=1, then
Mγ−2u|∇u(x)|2(u(x)−mu)γ≤(2nγ)γpeγπp‖∇logf‖C0, ∀0<γ<1. ∀x∈Sn. | (2.11) |
b. If 2≤k<n, then there exists An,k,p depending only on n,k,p, such that
Mγ−2u|∇u|2|u−mu|γ≤An,k,peγπk−1+p‖∇logf‖C0, | (2.12) |
where
γ=pk+1. | (2.13) |
Proof. For 0<γ<1, let Φ=|∇u|2(u−mu)γ as in the proof of Proposition 2.1. We may assume
minx∈Snf(x)=1. |
By Eq (1.2),
Mk+1−pu≥(n−k)!k!n!. | (2.14) |
Set
q=2−γp, β=1p(1−γ), | (2.15) |
and
Aγ=maxx∈SnΦ(x)M2−γu=Φ(x0)M2−γu. | (2.16) |
We want to estimate Aγ.
Suppose x0 is a maximum point of Φ. Let η>0 is a positive number to be determined. If,
(u(x0)−muMu)1−γ≥(γη)β, |
then
(u(x0)−mu)γ≥Mγu(γη)2−q. |
Since u is convex, |∇u(x)|2≤M2u, ∀x∈Sn. We have
Aγ=Φ(x0)M2−γu≤Mγu(u−mu)γ≤(ηγ)2−q. | (2.17) |
We now assume that at x0,
(u−muMu)1−γ≤(γη)β. | (2.18) |
As in the proof of Proposition 2.1, one may pick an orthonormal frame on Sn near x0, such that |∇u(x0)|=u1(x0), (Wij(x0)) is diagonal,
u11=γ2u21u−mu=γ2AγM2−γu(u−mu)1−γ, | (2.19) |
and
W11>u11=γ2AγM2−γu(u−mu)1−γ. | (2.20) |
We first consider the simple case k=1.
Case k=1. Since p≤1, up−1≤(u−mu)p−1. By (2.20), at maximum point x0 of Φ,
(u−mu)p−1f≥up−1f=σ1(W)≥W11≥u11=γ2AγM2−γu(u−mu)1−γ. |
It follows
Aγ≤2nγ(u−muMu)p−γMp−2uf≤2nγ(γη)(p−γ)(2−q)γf≤2nγ(γη)(p−γ)(2−q)γeπ‖∇logf‖C0, | (2.21) |
here we used minx∈Snf(x)=1 and (2.14) for k=1. Use (2.15) to equalize quantities on the right hand sides of (2.17) and (2.21), we pick
η=2neπ‖∇logf‖C0. |
Thus,
Aγ≤γ−γp(2neπ‖∇logf‖C0)γp, ∀0<γ<1. |
(2.11) is proved. We may let γ→1,
|∇u(x)|2u(x)−mu≤(2neπ‖∇logf‖C0)1pMu, ∀x∈Sn. | (2.22) |
We note that in this case, bound on ‖∇f‖ can be replaced by ratio of Mfmf in above estimate.
Case 2≤k<n. At x0,
W11=u11(1+2γA−1γu(u−mu)1−γM2−γu). | (2.23) |
By (2.5),
0≥2(1−γ)F11u11u−mu+2up−1f1u1+2F11(u211u21−1)−(kγ−2(p−1))σk(W)u−mu. | (2.24) |
Since f1f≥−‖∇logf‖C0, (2.6) can be refined as
2up−1f1u1≥−2up−1f‖∇logf‖C0Φ−12(u−mu)−γ2=−2‖∇logf‖C0A−12γ(u−muMu)1−γ2σk(W)u−mu. | (2.25) |
By (2.19), (2.23) and (2.20),
u211u21−1=γ2u11u−mu−1≥γ2W11u−mu(1−8γ2A−1γu(u−mu)1−γM2−γu). | (2.26) |
Put (2.25) and (2.26) to (2.24), as p≤1,
0≥(2−γ)F11W11u−mu−{kγ−2(p−1)+(4γA−1γu(u−mu)1−γM2−γu+2‖∇logf‖C0A−12γ(u−muMu)1−γ2)}σk(W)u−mu. | (2.27) |
Choose
η=(22k−1(n−k)k−1nkkeπ‖∇logf‖C0)pk−1+p, | (2.28) |
and
γ=pk+1, δ=12γ1−pp. | (2.29) |
We divide in to two subcases.
Subcase Ⅰ. Assume that
σk(W|1)>δσk−1(W|1)W11. |
If k≥2, by the Newton-MacLaurin inequality,
σkk−1k−1(W|1)≥Cn,kσk(W|1), |
where
Cn,k=kn−k((n−1)!(n−k)!(k−1)!)1k−1. | (2.30) |
In turn,
σkk−1k−1(W|1)≥Cn,kσk(W|1)>Cn,kδσk−1(W|1)W11. |
Hence,
σ1k−1k−1(W|1)≥Cn,kδW11. |
By Eq (1.2),
up−1f=σk(W)≥σk−1(W|1)W11≥(Cn,kδ)k−1Wk11. | (2.31) |
Note that (2.31) is trivial for k=1 in this subcase. Thus it is true ∀k≥1. As p≤1, up−1k≤(u−mu)p−1k, we deduce from (2.20) and (2.31) that,
Aγ≤2γ(Cn,kδ)1−kkM−1+p−1ku(u−muMu)1−γ+p−1kf1k. |
By (2.18), (2.14), (2.28), (2.29) and (2.30), and the fact that minf=1,
Aγ≤2γ(Cn,kδ)1−kkM−1+p−1ku(γη)2−qγ(1−γ+p−1k)eπk‖∇logf‖C0≤2(Cn,k2)1−kk(n!(n−k)!k!)1k(1η)2−qγ(1+p−1k)eπk‖∇logf‖C0(γη)q−2=(γη)q−2. | (2.32) |
Subcase Ⅱ. Assume that
σk(W|1)≤δσk−1(W|1)W11. |
We have,
σk(W)=σk−1(W|1)W11+σk(W|1)≤(1+δ)σk−1(W|1)W11=(1+δ)F11W11. |
Put this into (2.27), we obtain
0≥2−γ−(1+δ){kγ−2(p−1)+(4γA−1γu(u−mu)1−γM2−γu+2‖∇logf‖C0A−12γ(u−muMu)1−γ2)}. |
From (2.13) and (2.29),
2−γ−(1+δ)(kγ−2(p−1))≥γ(1+δ). |
Hence
0≥γ−(4γA−1γu(u−mu)1−γM2−γu+2‖∇logf‖C0A−12γ(u−muMu)1−γ2). |
Again by (2.13) and (2.29),
4γA−1γu(u−mu)1−γM2−γu+2‖∇logf‖C0A−12γ(u−muMu)1−γ2≥γ. |
It follows from (2.18) that,
4γA−1γ(γη)1−γp+2‖∇logf‖C0A−12γ(γη)1−γ2p≥γ. |
We obtain
Aγ≤8(η−1pγ1p−2+‖∇logf‖2C0η−2pγ2p−2)(ηγ)γp=8(η−1pγ1p−2+‖∇logf‖2C0η−2pγ2p−2)(ηγ)2−q. | (2.33) |
By (2.13) and (2.28), direct computation yields
η−1pγ1p−2+‖∇logf‖2C0η−2pγ2p−2≤4ek+2π−2e−2k4. |
We obtain that
Aγ≤(4ek+2π−2e−2k4)(ηγ)γp, | (2.34) |
where γ,η as in (2.13) and (2.28).
Remark 2.1. Constant An,k,p in Proposition 2.2 can be computed explicitly. We observe that if u is even, (2.22) and (2.12) in Proposition 2.2 can be improved respectively as
Mγ−2u|∇u(x)|2(u(x)−mu)γ≤(2nγ)γpeγπ2p‖∇logf‖C0, ∀0<γ<1, ∀x∈Sn. | (2.35) |
and
Mγ−2u|∇u|2|u−mu|γ≤An,k,peγπ2(k−1+p)‖∇logf‖C0. | (2.36) |
This is due to the fact that one may choose maximum and minimum points of f such that the distance is at most π2 in this case.
Remark 2.2. It is of interest to obtain some form of weighted gradient estimate for Eq (1.2) in the case p=0.
In general, there is no positive lower bound for convex solutions of (1.2) when p<k+1 [8]. We may obtain lower bound for even convex solutions of (1.2) in the case of 0<p<1.
For convex body Ω⊂Rn+1, denote ρ−(Ω) and ρ+(Ω) to be the inner radius and outer radius of Ω respectively.
Lemma 3.1. If u is a positive convex function on Sn satisfying condition
|∇u(x)|2(u(x)−mu)γ≤AM2−γu, ∀x∈Sn, | (3.1) |
for some γ>0, A>0. Let Ωu be the convex body with support function u, and suppose there is an ellipsoid E centred at the origin such that
E⊂Ωu⊂βE. | (3.2) |
Then the following non-collapsing estimate holds,
ρ+(Ωu)ρ−(Ωu)≤β2γ+1A1γ24γ(2−γ). | (3.3) |
Proof. Write E
x21a21+⋯+x2n+1a2n+1≤1 |
with longest axis a1, and the shortest axis an+1. We have
a1≤Mu≤βa1,an+1≤mu≤βan+1. |
Recall that
uE(x)=√a21x21+a22x22+⋯+a2n+1x2n+1,x∈Sn |
By (3.2), support functions of Ω and E are equivalent.
uE(x)≤u(x)≤(n+1)uE(x), ∀x∈Sn. |
Restrict the support function uE,u to the slice S:={x∈Sn|x=(x1,0,…,0,xn+1)}. Set
v(s):=uE(s,0,…,0,√1−s2)=√a21s2+a2n+1(1−s2)=√a2n+1+(a21−a2n+1)s2. |
We have
taγ21a2−γ2n+1≤v(t(an+1a1)2−γ2), ∀t∈[0,1]. |
On the other hand, set q(s)=(u(s,0,…,0,√1−s2)−mu)2−γ2. By the weighted gradient estimate (3.1),
|ddsq(s)|≤A12M1−γ2u≤A12β1−γ2a1−γ21. |
This implies, ∀0<t≤1,
q(t(an+1a1)2−γ2)≤tA12β1−γ2(an+1a1)2−γ2a1−γ21+q(0)=tβ1−γ2A12a2−γ2n+1+q(0). |
As q(0)≤β2−γ2a2−γ2n+1,
q(t(an+1a1)2−γ2)≤(tβ1−γ2A12+β2−γ2)a2−γ2n+1. |
Thus,
u((an+1a1)2−γ2,0,…,0,1−(an+1a1)2−γ)≤β1−γ2(tA12+1)22−γan+1. |
Since u(x)≥uE(x), we obtain
taγ21a2−γ2n+1≤β(tA12+1)22−γan+1. |
This yields
a1an+1≤(βt(tA12+1)22−γ)2γ. |
Choose t=A−12,
a1an+1≤β2γA1γ24γ(2−γ). | (3.4) |
Corollary 3.1. If u is a positive, even, convex solution to (1.2) for 0<p<k+1. Then
Mumu≤(An,k,peγπ2(k−1+p)‖∇logf‖C0)1γ(n+1)1γ+1224γ(2−γ), | (3.5) |
where γ and An,k,p as in Proposition 2.2. As a consequence,
|∇u(x)|2u2(x)≤(An,k,peγπ2(k−1+p)‖∇logf‖C0)2−γγ+1(n+1)4−γ22γ24γ. | (3.6) |
In the case k=1,
|∇u(x)|2u2(x)≤8(n+1)32(2n)2peπp‖∇logf‖C0. | (3.7) |
Moreover, there exist positive constant C1, C2 depending only on n,k,p,‖logf‖C1, such that
C1≤u(x)≤C2>0, ∀x∈Sn;‖u‖C1(Sn)≤C. |
Proof. Since Ωu is even, we may pick β=√n+1 in (3.2). We let A=An,k,peγπ2(k−1+p)‖∇logf‖C0 as in (2.36). (3.5) follows Lemma 3.1. By (3.5),
|∇u(x)|2u2(x)=|∇u(x)|2uγ(x)M−2+γu(Muu)2−γ≤|∇u(x)|2(u−mu)γM−2+γu(Mumu)2−γ≤(An,k,peγπ2(k−1+p)‖∇logf‖C0)2−γγ+1(n+1)4−γ22γ24γ. |
Inequality (3.7) follows from (2.35). By Eq (1.2), mu is bounded from above and Mu is bounded from below. Therefore, u is bounded from below and above by (3.5).
Lemma 3.1 yields a direct estimate of inner radius of the classical Christoffel-Minkowski problem: convex solutions to Eq (1.1). When k=n, such estimate was proved in [2], it also follows from John's lemma. For k<n, we are not aware any such estimate in the literature.
Lemma 3.2. Suppose u is convex solution to (1.1). Let Ω be the convex body determined by u as the support function, let ρ−(Ω) be the inner radius of Ω. Then there exist positive constants C1, C2 depending only on n,k and ‖logf‖C1, such that
C2≥ρ+(Ω)≥ρ−(Ω)≥C1. |
Proof. As we may shift the origin to the center of the ellipsoid E in (3.2) with β=n+1. Lemma follows Lemma 3.1, since mu is bounded from above and Mu is bounded from below by (1.1).
With the upper and lower bounds of u for solutions of (1.2), the maximum principle (e.g., [8]) yields C2 estimate. Higher regularity a priori estimates follows the standard elliptic theory.
Proposition 3.1. Let u be a positive, even convex solution to (1.2). For any l∈Z+ and 0<α<1, there exists some positive constant C, depending on n,k,p,l,α and ‖logf‖Cl, such that
‖u‖Cl+1,α(Sn)≤C. | (3.8) |
For Lp Christoffel-Minkowski problem, we want to find solution u of (1.2) which is convex, i.e., W>0. The sufficient condition introduced in [7] for convexity of solution u to equation (1.1) is
((f−1k)ij(x)+f−1k(x)δij)≥0, ∀x∈Sn. | (4.1) |
Corresponding condition for (1.2) for p>1 is
((˜f−1k)ij(x)+˜f−1k(x)δij)≥0, ∀x∈Sn, | (4.2) |
where ˜f=up−1f. Write ˜h=log˜f=(p−1)logu+logf, (4.2) is equivalent to
1k(˜h′)2+k−˜h″(x)≥0, ∀x∈Sn, | (4.3) |
where derivatives are along any geodesic passing through x. Denote ϕ=logf, (4.3) is equivalent to
1k(ϕ′)2+k−ϕ″+(p−1){−u″u+(1+p−1k)(u′u)2+2ku′uϕ′}≥0. | (4.4) |
In the case p≥1, it was observed in [9] that (4.2) would be valid if f satisfies
((f−1k+p−1)ij(x)+f−1k+p−1(x)δij)>0, ∀x∈Sn. | (4.5) |
This relies on the fact that the coefficient p−1+(p−1)2k in front of term (u′u)2 in (4.4) is nonnegative when p≥1. In the case 0<p<1, p−1+(p−1)2k<0. If
k−1+p−ϕ″+(p−1)(u′u)2≥0, | (4.6) |
then (4.4) holds, as W is assumed semi-positive definite.
The main problem is to control (p−1)(u′u)2 in (4.6) when p<1. When 0≤1−p is small, one may impose a condition that f is a positive C2 even function on Sn satisfying
k−1+p−ϕ″+(p−1)(An,k,peγπ2(k−1+p)‖∇ϕ‖C0)2−γγ+1(n+1)4−γ22γ24γ≥0. | (4.7) |
By Corollary 3.1, Condition (4.7) implies Condition (4.6). The Constant Rank Theorem in [7] implies that there is a convex even solution u∈C3,α(Sn), ∀0<α<1 of (1.2).
In the case k=1, one may use (3.7) to deduce a simpler condition for convex even solutions to Lp Christoffel problem:
p−ϕ″+8(p−1)(n+1)32(2n)2peπp‖∇logf‖C0≥0, | (4.8) |
Conditions (4.7) and (4.8) are not satisfactory. It only makes some sense when 1−p is small. It is an open problem to find a clean pointwise condition on f for existence of convexity solutions to equation (1.2), 0<p<1.
Research is supported in part by an NSERC Discovery grant.
The author declares no conflict of interest.
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