Research article Special Issues

On parabolic Adams's, the Chiarenza-Frasca theorems, and some other results related to parabolic Morrey spaces

  • We present several results of embedding type for parabolic Morrey and Lp spaces with or without mixed norms. Some other interpolation results for parabolic Morrey spaces are also given. The main object of investigation is the term biDiu and the ways to estimate it in various Morrey and Lp spaces in order to be able to treat it as a perturbation term in the parabolic equations.

    Citation: Nicolai Krylov. On parabolic Adams's, the Chiarenza-Frasca theorems, and some other results related to parabolic Morrey spaces[J]. Mathematics in Engineering, 2023, 5(2): 1-20. doi: 10.3934/mine.2023038

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  • We present several results of embedding type for parabolic Morrey and Lp spaces with or without mixed norms. Some other interpolation results for parabolic Morrey spaces are also given. The main object of investigation is the term biDiu and the ways to estimate it in various Morrey and Lp spaces in order to be able to treat it as a perturbation term in the parabolic equations.



    Let Rd, d1, be a Euclidean space of points x=(x1,...,xd). In 1975 D. Adams [1] among many other things proved that, if d2 and we are given uC0=C0(Rd) with its gradient Du=(D1u,...,Ddu), Di=/xi, satisfying

    |xy|<ρ|Du(y)|qdyρdβq, (1.1)

    with q>1, 1<βd/q, and any ρ(0,) and xRd, then for all ρ(0,) and xRd we have

    |xy|<ρ|u(y)|rdyNρd(β1)r (1.2)

    with a constant N independent of u and r satisfying (β1)r=βq.

    This fact played a crucial role in [10] where the author investigated the solvability of elliptic equations

    aijDiju+biDiu+u=f(Dij=DiDj) (1.3)

    with bLd,loc but rather satisfying for a sufficiently small ˆb, all sufficiently small ρ and all balls B of radius ρ

    B|b|d0dxˆbρdd0

    with certain d0(d/2,d).

    Our goal in this paper is to prepare necessary tools for developing a similar theory for parabolic equations. In Section 2 we prove an analog of Adams's intermediate estimate, which is the main starting point. Section 3 contains the parabolic analog of the embedding theorem mentioned in the beginning of the article. It also contains "local" interpolation inequalities in Morrey spaces allowing one to deal with Morrey's norms of expressions like biDiu in domains when b is bounded. Section 4 is devoted to the parabolic analog of a Chiarenza-Frasca theorem allowing to estimate the Lp-norm rather than Morrey's norm of biDiu. In Section 5 we treat parabolic Morrey spaces with mixed norms. The main object of investigation is the term biDiu and the ways to estimate it in various Morrey and Lp spaces in order to be able to treat it as a perturbation term in the parabolic analog of (1.3).

    We finish the introduction with some notation and a remark. Define Bρ(x)={yRd:|xy|<ρ}, Rd+1:={z=(t,x):tR,xRd},

    Cρ(t,x)={(s,y)×Rd+1:|xy|<ρ,ts<t+ρ2},Cρ=Cρ(0)

    and let Cρ be the collection of Cρ(z), zRd+1, C={Cρ,ρ>0}. For measurable ΓRd+1 set |Γ| to be its Lebesgue measure and when it makes sense set

    fΓ=Γfdz=1|Γ|Γfdz.

    Similar notation is used for f=f(x).

    Remark 1.1. Formally, Adams proved (1.2) assuming that d2. However, it is also true if d=1. To show this it suffices to take u depending only on one coordinate. The reader may wonder how the restriction βd/q will become β1/q. The point is that if d=1 and β>1/q, we have dβq<0 and condition (1.1) becomes only possible if u=0.

    An important quantity characterizing Lp=Lp(Rd+1) is what we call the index which is the exponent of ρ in the expression

    ICρLp that isd+2p.

    For domains QRd+1, p[1,), and β(0,(d+2)/p], introduce Morrey's space Ep,β(Q) as the set of g such that

    gEp,β(Q):=supρ<,(t,x)QρβgIQLp(Cρ(t,x))<, (2.1)

    where

    gLp(Γ)=(Γ|g|pdz)1/p.

    We abbreviate Ep,β=Ep,β(Rd+1). Observe that if Q=CR one can restrict ρ in (2.1) to ρR since β(d+2)/p. Also in that case one can allow (t,x) to be arbitrary, because, if |x|R, then BRBρ(x)BRBρ(Rx/|x|). It is also useful to observe that, in case Q=CR, one gets an equivalent norm by adding to the restrictions ρ<,(t,x)CR, the requirement that the geometric center of Cρ(t,x) be in CR. This follows from the fact that the Lp(Cρ(t,x))-norm of gICR will only increase if we pull Cρ(t,x) down the t axis to {t=0} (if ρ2>2R2) or to the moment that the shifted Cρ(t,x) has its geometric center inside CR.

    There are many different notations for the norms in Morrey spaces. The convenience of the above notation is well illustrated by Theorem 3.1 and Corollary 5.7.

    We will often, always tacitly, use the following formulas in which u(t,x)=v(t/R2,x/R):

    uLp(CR)=vLp(C1),uEp,β(Q)=RβvEp,β(QR),

    where QR={(t,x):(R2t,Rx)Q},

    DuEp,β(CR)=Rβ1DvEp,β(C1),D2uEp,β(CR)=Rβ2vEp,β(C1).

    For s,r>0,α>0, and appropriate f(t,x)'s on Rd+1 define

    pα(s,r)=1s(d+2α)/2er2/sIs>0,
    Pαf(t,x)=Rd+1pα(s,|y|)f(t+s,x+y)dyds.

    Observe that, if f is independent of t, then

    Pαf(t,x)=Pαf(x)=N(α)Rd1|y|dαf(x+y)dy=NIαf(x),

    where Iα is the Riesz potential. Therefore, one can get the Adams estimate found in the proof of Proposition 3.1 of [1] from (2.3) below. In our investigation the most important values of α are 1 and 2. Set

    Mβf(t,x)=supρ>0ρβCρ(t,x)|f(z)|dz,0βd+2,
    Mf=M0f.

    The following lemma is obtained by integrating by parts.

    Lemma 2.1. Let β>0 be a finite number, f(t)0 be a function on [0,) such that

    tβt0f(s)ds0

    as t. Then, for any S0,

    Stβf(t)dtβStβ1(tSf(s)ds)dt.

    Lemma 2.2. For any α(0,β),β(0,d+2] there exist constants N(<) such that for any f0 and ρ(0,) we have

    Pα(ICρf)(0)NραMf(0),Pα(ICcρf)(0)NραβMβf(0), (2.2)
    PαfN(Mβf)α/β(Mf)1α/β. (2.3)

    In particular (by Hölder's inequality), for any p[1,], q(1,], and measurable Γ

    PαfLr(Γ)NMβfα/βLp(Γ)f1α/βLq, (2.4)

    provided that

    1r=αβ1p+(1αβ)1q.

    Proof. We basically mimic the proof of Proposition 3.1 of [1]. Observe that (2.3) at the origin is easily obtained from summing up the inequalities in (2.2) and minimizing with respect to ρ. At any other point it is obtained by changing the origin. Furthermore clearly, we may assume that f is bounded with compact support. Set Q1={(s,y):|y|s}, Q2={(s,y):|y|s}. Dealing with Pα(fIQ1) we observe that pα(s,r)Nr(d+2α) if rs. Therefore,

    Pα(fIQ1Ccρ)(0)Nρ1rd+2αr20(|y|=rf(s,y)dσr)dsdr,

    where dσr is the element of the surface area on |y|=r. By Lemma 2.1 (α<d+2)

    Pα(fIQ1Ccρ)(0)Nρ1rd+3αrρ(ρ20(|y|=ρf(s,y)dσρ)ds)dρdr
    Nρ1rd+3αr0(r20(|y|=ρf(s,y)dσρ)ds)dρdr
    =Nρ1rd+3αI(r)dr,

    where

    I(r)=Crf(s,y)dyds.

    We use that I(r)Nrd+2βMβf(0) and that α<β. Then we see that

    Pα(fIQ1Ccρ)(0)NραβMβf(0). (2.5)

    Next, by using Lemma 2.1 we obtain that

    Pα(fIQ2Ccρ)(0)ρ21s(d+2α)/2|y|sf(s,y)dyds
    Nρ21s(d+4α)/2I(s)ds=Nρ1rd+3αI(r)dr.

    This along with (2.5) prove the second inequality in (2.2).

    As long as the first inequality is concerned, observe that similarly to Lemma 2.1 using that α>0 we have

    Pα(fIQ1Cρ)(0)Nρ01rd+2αr20(|y|=rf(s,y)dσr)dsdr
    =Nρ01rd+2α(rr0(τ20|y|=τf(s,y)dστds)dτ)dr
    =J1+Nρ01rd+3αr0(τ20(|y|=τf(s,y)dστ)ds)dτdr
    J1+Nρ01rd+3αI(r)dr,

    where

    J1=N1ρd+2αρ0(τ20|y|=τf(s,y)dστds)dτN1ρd+2αI(ρ)

    Here I(r)Nrd+2Mf(0) and α>0, so that

    Pα(fIQ1Cρ)(0)NραMf(0). (2.6)

    Furthermore,

    Pα(fIQ2Cρ)(0)Nρ201s(d+2α)/2|y|sf(s,y)dyds
    J2+Nρ201s(d+4α)/2I(s)ds=J2+Nρ01rd+3αI(r)dr,

    where

    J2=N1ρd+2αρ20|y|τf(τ,y)dydτN1ρd+2αI(ρ).

    This and (2.6) prove the first inequality in (2.2). The lemma is proved.

    Remark 2.3. If d=α=1 and f is independent of t, the inequalities (2.2) and (2.3) are useless, because the first one in (2.2) follows by definition and the second one and (2.3) are trivial because Mβf= (β>α=1) unless f=0.

    If α is strictly less than the index of Lq, we have the following.

    Corollary 2.4. If α(0,(d+2)/q), q(1,), thenthere exists a constant N such that for any f0 we have

    PαfLrNfLq

    as long as

    d+2qα=d+2r.

    In particular, (a classical embedding result) if 1<q<d+2 and uC0=C0(Rd+1), then

    DuLrNtu+ΔuLq(t=/t)

    as long as

    d+2q1=d+2r.

    Indeed, the first assertion follows from Hölder's inequality and (2.4) with p= and β=(d+2)/q (>α). The second assertion follows from the first one with α=1 (<β) and the fact that for f=tu+Δu we have

    Du(t,x)=cRd+1+ys(d+2)/2e|y|2/(4s)f(t+s,x+y)dyds,

    where c is a constant and (|y|/s1/2)e|y|2/(4s)Ne|y|2/(8s).

    Remark 2.5. After Corollary 2.4 a natural question arises as to what power of summability b=(bi) will be sufficient for the term biDiu to be considered as a perturbation term in tu+Δu+biDiu in the framework of the Lq-theory. Observe that, in the notation of Corollary 2.4

    biDiuLqbLd+2DuLrNbLd+2tu+ΔuLq. (2.7)

    It follows that b should be of class Ld+2 and q<d+2. Of course, if b contains just bounded part, this part in biDiu is taken care of by interpolation inequalities.

    In the next section we will also need the following result.

    Corollary 2.6. For any α(0,β),β(0,d+2] there exists a constant N such that for any g0, ρ(0,), and (t,x)Cρ we have

    Pα(ICc2ρg)(t,x)NραβMβg(t,x).

    Indeed, since

    {t+s4ρ2or|x+y|2ρ}{sρ2or|y|ρ}

    for f=g(t+,x+) we have

    Pα(ICc2ρg)(t,x)Rd+1ICcρ(s,y)pα(s,y)g(t+s,x+y)dyds=Pα(ICcρf)(0)
    NραβMβf(0)=NραβMβg(t,x).

    Theorem 3.1. For any α(0,β),β(0,(d+2)/q], q(1,), and r such that

    r(βα)=qβ,

    there is a constant N such that for any f0 we have

    PαfEr,βαNfEq,β. (3.1)

    Proof. It suffices to prove that for any ρ>0

    ρβα(Cρ|Pαf|rdz)1/rNfEq,β,

    that is

    ρβα(d+2)/r(Cρ|Pαf|rdz)1/rNfEq,β, (3.2)

    Observe that by Hölder's inequality MβfNfEq,β and by definition

    (Rd+1IC2ρfqdz)1/qNρ(d+2)/qβfEq,β.

    It follows from Lemma 2.2 with p= that

    (Cρ|Pα(IC2ρf)|rdz)1/rNρ((d+2)/qβ)(1α/β)fEq,β
    =Nρ(d+2)/rβ+αfEq,β.

    Furthermore, by Corollary 2.6

    (Cρ|Pα(ICc2ρf)|rdz)1/rNρ(d+2)/rsupCρPα(ICc2ρf)
    Nρ(d+2)/r+αβEq,βf.

    By combining these estimates we come to (3.2) and the theorem is proved.

    Remark 3.2. We did not explicitly used that β(d+2)/q and formally the proof is valid for any β(0,) if in Definition 2.1 we allow any β>0. However, if β>(d+2)/q and f0, the right-hand side of (3.1) is infinite. Therefore, to make Theorem 3.1 nontrivial one requires β(d+2)/q.

    Remark 3.3. There is a simple relation of Pα1Pα2 to Pα1+α2, which, in light of Theorem 3.1, implies that, if β>α2α1>0, q1,q2(1,), q1(βα1)=q2(βα2)d+2, then Pα2fEq2,βα2NPα1fEq1,βα1. We leave details of the proof to the reader and we do not use this fact in what follows.

    The following, obtained similarly to Corollary 2.4, was communicated to the author by Hongjie Dong.

    Corollary 3.4. If 1<q<d+2, β(1,(d+2)/q], and uC0, then

    DuEr,β1Ntu+ΔuEq,β

    as long as

    r(β1)=qβ,that is1r=1q1βq. (3.3)

    Remark 3.5. For β=(d+2)/q Corollary 3.4 yields the second part of Corollary 2.4 once more. This is because Eq,(d+2)/q=Lq.

    Remark 3.6. In the framework of the Morrey spaces Corollary 3.4 opens up the possibility to treat the terms like biDiu as perturbation terms in operators like tu+Δu+biDiu even with rather low summability properties of b=(bi). To show this, observe that for f,g0 in the notation of Corollary 3.4

    ρβfgICρLqρfICρLβqρβ1gICρLr.

    It follows that

    biDiuEq,βbEβq,1DuEr,β1NbEβq,1tu+ΔuEq,β. (3.4)

    For β=(d+2)/q estimate (3.4) coincide with (2.7), but for β<(d+2)/q in the framework of Morrey spaces we allow b to be summable to the power βq<d+2 in contrast with Remark 2.5. However, we need bEβq,1< and, if we ask ourselves what r should be in order for bLr to have bEβq,1<, the answer is r=d+2 at least. Still we gain the possibility to have higher singularities of b than functions from Ld+2. Elliptic versions of (3.4) for usual or generalized Morrey spaces are found in many papers, see, for instance, [5] and the references therein.

    Next we move to deriving "local" versions of the above results. A statement somewhat weaker than Corollary 3.4 can be obtained from the following general result by taking (S,T) to be large enough and then sending S,T.

    Theorem 3.7. Let 1<q<d+2, β(1,(d+2)/q] and let (3.3) hold. Thenthere is a constant N such thatfor any uC0, <S<T<, and QS,T=(S,T)×Rd

    DuEr,β1(QS,T)N|tu|+|Δu|Eq,β(QS,T)+N(TS)1uEq,β(QS,T). (3.5)

    Proof. Shifting and changing the scales in Rd+1 allow us to assume that S=1=T. In that case consider the mapping Φ:[3/2,3/2][1,1], Φ(t)=t(2/(|t|1)1) that preserves [1,1], is Lipschitz continuous and has Lipschitz continuous inverse if restricted to [3/2,3/2](1,1). Then, obviously, for w(t,x)=v(Φ(t),x) we have

    wIQ3/2,3/2Eq,βNvEq,β(Q1,1), (3.6)

    where N=N(q).

    Now take (t,x)Q1,1, ρ(0,), and take ζC0(R) such that ζ=1 on (1,1), ζ=0 outside (3/2,3/2), and |ζ|+|ζ|4.

    Although the function ζw, where w(s,y)=u(Φ(s),y), is not as smooth as required in Corollary 3.4 the argument leading to it applies to ζ(s)w(s,y) (we have a general Remark 5.14 to that effect) and since r(β1)=qβ we have

    ρβ1DuIQ1,1Lr(Cρ(t,x))Nρβ1D(ζw)Lr(Cρ(t,x))
    NIQ3/2,3/2(|t(ζw)|+|ζΔw|)Eq,β.

    It only remains to note that the last expression is less than the right-hand side of (3.5) in light of (3.6). The theorem is proved.

    To prove an interpolation theorem in CR we need two lemmas.

    Lemma 3.8. Let 0<R1<1<R2<, 1q<, β(0,(d+2)/q]. Define Γ1=ˉB1BR1, Γ2=ˉBR2B1 and let Φ:Γ2Γ1 be a smoothone-to-one mapping with |DΦ|,|DΦ1|K, where K is a constant. Let v(t,x)0 be zero outside G2:=(0,1)×Γ2 and set u(t,x)=v(t,Φ1(x))IΓ1(x). Then

    vEq,β((0,1)×BR2)N(d,q,β,K)uEq,β(C1). (3.7)

    Proof. Take (t,x)(0,1)×BR2 and ρ>0. Then

    ρβ(1ρd+2Cρ(t,x)I(0,1)×BR2vqdyds)1/q
    Nρβ(1ρd+2Ψ(Cρ(t,x)G2)IC1uqdyds)1/q=:I,

    where Ψ(s,y)=(s,Φ(y)). Observe that, if Cρ(t,x)G2, then |y1y2|2ρ for any y1,y2Cρ(t,x)G2. It follows that Φ(Cρ(t,x)G2)B, where B is a ball of radius 2Kρ with center in B1, and

    IN(2Kρ)β(1(2Kρ)d+2(t,t+(2Kρ)2)×BIC1uqdyds)1/qNuEq,β(C1).

    This proves the lemma.

    The following lemma about the interpolation inequality (3.9) is quite natural and obviously useful, but its elliptic counterpart was proved only rather late in [10]. One of its goals is to be able to treat biDiu, when b is bounded, as a perturbation term.

    Lemma 3.9. Let p(1,), 0<β(d+2)/p. Then there is a constant N such that, for any R(0,), ρ2R, CCρ with its geometric centerin CR, ε(0,1], and uC0, we have

    ρβICRDuLp(C)NεRsupρs2RsβICR(|tu|+|D2u|)Lp(C(s))
    +Nε1R1supρs2RsβICR(uc)Lp(C(s)), (3.8)

    where c is any constant and C(s)Cs with the geometric centerthe same as C. In particular,

    DuEp,β(CR)NεR|tu|+|D2u|Ep,β(CR)+Nε1R1uEp,β(CR). (3.9)

    Proof. Changing scales shows that we may assume that R=1. Obviously we may also assume that c=0. Then denote v=Du, w=|tu|+|D2u|, Gs=C(s)C1,

    U=supρs2sβuLp(Gs),W=supρs2sβ(|tu|+|D2u|)Lp(Gs),

    By Poincaré's inequality (see, for instance, Lemma 5.9), for ρs2,

    vvGsLp(Gs)N(d,p)swLp(Gs)Ns1βW.

    Also by interpolation inequalities, there exists a constant N=N(d,p) such that, for ε(0,1] and εs2,

    vvGsLp(Gs)2vLp(Gs)Nw1/2Lp(Gs)u1/2Lp(Gs)
    +Ns1uLp(Gs)Nw1/2Lp(Gs)u1/2Lp(Gs)+Nε1uLp(Gs), (3.10)

    which for 2sερ yields

    sβvvGsLp(Gs)NW1/2U1/2+Nε1U.

    Hence, for any ε(0,1] and ρs2

    sβvvGsLp(Gs)N1εW+N2ε1U,

    where N1=N1(d,p), N2=N2(d,p).

    Following Campanato, one can transform this result to estimate vGs going along ρ, 2ρ, ... and, since β(0,(d+2)/p], by Campanato's results (cf. for instance, Proposition 5.4 in [8]) one gets that

    ρβvLp(Gρ)N3(N1εW+N2ε1U)+N3vLp(G2),

    where N3=N3(d,p,β). We estimate the last term as in (3.10) and come to what implies (3.8). The lemma is proved.

    The following is a local version of Corollary 3.4. It allows us to draw the same conclusions as in Remark 3.6 in bounded domains.

    Theorem 3.10. Let 1<q<d+2, β(1,(d+2)/q] and let r(β1)=qβ. Then there is a constant N such thatfor any R(0,], uC0,

    DuEr,β1(CR)N|tu|+|D2u|Eq,β(CR)+NR2uEq,β(CR). (3.11)

    Proof. The case of R= is obtained by passing to the limit. In case R<, as usual, we may assume that R=1. In that case, mimicking the Hestenes formula, for 1|x|6/5 define

    v(t,x)=6u(t,x(2/|x|1))8u(t,x(3/|x|2))+3u(t,x(4/|x|3))
    =:6v18v2+3v3

    and for |x|1 set v(t,x)=u(t,x). One can easily check that vC1,2([0,1]×B6/5). In light of Lemmas 3.8 and 3.9, for instance,

    D2vEq,β((0,1)×B6/5)D2uEq,β(C1)+NIB6/5B1D2v1Eq,β((0,1)×B6/5)+...
    +NIB6/5B1D2v3Eq,β((0,1)×B6/5)ND2uEq,β(C1)+NDuEq,β(C1)
    ND2uEq,β(C1)+NuEq,β(C1). (3.12)

    Now take (t,x)C1, ρ(0,), and take ζC0(Rd) such that ζ=1 on B1, ζ=0 outside B6/5, and |ζ|+|Dζ|+|D2ζ|N=N(d).

    By using Theorem 3.7 we get

    ρβ1DuIC1Lr(Cρ(t,x))Nρβ1IQ0,1D(ζv)Lr(Cρ(t,x))
    ND(ζv)Er,β1(Q0,1)N|t(ζv)|+|Δ(ζv)|Eq,β(Q0,1)+NζvEq,β(Q0,1)
    N|t(ζv)|+|Δ(ζv)|Eq,β((0,1)×B6/5)+NvEq,β((0,1)×B6/5)

    It only remains to note that the last expression is less than the right-hand side of (3.11) as is well seen from (3.12). The theorem is proved.

    Remark 3.11. By considering functions depending only on x we naturally obtain "elliptic" analogs of our results. For instance, for GRd by defining

    gEp,β(G)=supρ<,xGρβgIGLp(Bρ(x)),

    we get from (3.11) for uC0(Rd) that

    DuEr,β1(BR)N|D2uEq,β(BR)+NR2uEq,β(BR), (3.13)

    whenever 1<q<d,β(1,d/q] and r(β1)=qβ. Actually, formally, one gets (3.13) even for β(d+2)/q, but for β>d/q, both sides of (3.13) are infinite unless u=0.

    After that arguing as in (3.4) we see that for 1<q<d,β(1,d/q]

    biDiuEq,β(B1)NbEβq,1(B1)ΔuEq,β(B1)+NuEq,β(B1). (3.14)

    From the point of view of the theory of elliptic equations the most desirable version of (3.14) would be

    biDiuEq,β(B1)εΔuEq,β(B1)+N(ε)uEq,β(B1) (3.15)

    for any ε>0 with N(ε) independent of u. This fact is, actually, claimed in Theorem 5.4 of [5]. We will show that (3.15) cannot hold if ε is small enough.

    Let h(t) be a smooth nondecreasing function on R such that h(t)=0 for t0, h(t)=t for t1 and for δ>0 set uδ(x)=h(ln(δ/|x|)). Let 1<q<d/2, β=2, b(x)=1/|x|.

    Then

    uEq,β(B1)N(d)uδLd(B1)0

    as δ0. At the same time

    Diuδ=xi|x|2h,Dijuδ=1|x|2(2xixj|x|2δij)h+1|x|2xixj|x|2h".

    It is seen that |D2uδ|N(d)/|x|2 and, since q<d/2, the Eq,β(B1)-norm of D2uδ is bounded as δ0. Also, for |x|δ/e, we have b|Duδ|=1/|x|2, so that for rδ/e

    (|x|rbq|Duδ|qdx)1/q=N(d,p)r2.

    It follows that the Eq,β(B1)-norm of b|Duδ| is bounded away from zero as δ0 and this shows that (3.15) cannot hold for all δ>0 if ε is small enough.

    In Remark 3.6 we have shown how to estimate a Morrey norm of |b||Du| in terms of a Morrey norm of b. Here, following [4], we show how to estimate an Lp-norm of the same quantity through the Lp-norms of tu and D2u.

    Theorem 4.1. Let d+2q>p>1, bEq,1. Then for any f0 we have

    I:=Rd+1|b|p(P1f)pdzNbpEq,1fLp, (4.1)

    where N depends only on d,p,q.In particular (see the proof ofCorollary 2.4), for any uC0

    Rd+1|b|p|Du|pdzNbpEq,1K, (4.2)

    where K=D2u,tupLp and N depends only on d,p,q.

    Observe that we already know this result if q=d+2 from Remarks 2.5 or 3.6.

    In the proof we are going to use "parabolic" versions of some results from Real Analysis associated with balls and cubes. These versions are obtained by easy adaptation of the corresponding arguments by replacing balls with parabolic cylinders and cubes with parabolic boxes. To make the adaptation more natural we introduce the "symmetric" maximal parabolic function operator by

    ˆMf(t,x)=supCC,C(t,x)C|f|dz,

    where (recall that) C is the set of Cr(z), r>0, zRd+1. To prove the theorem we need the following.

    Lemma 4.2. a) For r(0,) define Dr={|t|r2,|x|r}. Then

    ˆMIDr(t,x)ID2r+NIDc2rrd+2|t|(d+2)/2|x|d+2N2ˆMIDr(t,x), (4.3)

    where N=N(d).

    b) For any nonnegative g(t,x), q[1,), β(0,d+2], α>0, α>1qβ/(d+2), and r(0,)

    Rdgq(ˆMIDr)αdzN(d,q,α,β)rd+2qβgqEq,β. (4.4)

    Proof. Assertion a) is proved by elementary means. To prove b), we use a) and split Dc2r into two parts Dc2r{|x|2|t|} and Dc2r{|x|2<|t|} and, taking into account obvious symmetries, we see that it suffices to show that

    I1:=4r2Btgq(t,x)tα(d+2)/2dxdtNr(d+2)(1α)qβgqEq,β,
    I2:=|x|2r|x|20gq(t,x)|x|α(d+2)dtdxNr(d+2)(1α)qβgqEq,β.

    By observing that

    1tα(d+2)/2t4r2(Bsgq(s,x)dx)dst(d+2)/2qβ/2tα(d+2)/2gqEq,β0

    as t, we have

    I1=4r21tα(d+2)/2ddt(t4r2(Bsgq(s,x)dx)ds)dt
    =N4r21tα(d+2)/2+1(t4r2Bsgq(s,x)dxds)dt
    NgqEq,β4r2t(d+2)/2qβ/2tα(d+2)/2+1dt=Nr(d+2)(1α)qβgqEq,β.

    Also as is easy to see

    I2=N2r1ρα(d+2)ρ20(|x|=ρgp(t,x)dσρ)dtdρ
    N2r1ρα(d+2)ρ(ρ24r2(|x|ρgp(t,x)dx)dt)dρ
    NgqEq,β2rρd+2qβρα(d+2)+1dρ=Nr(d+2)(1α)qβgqEq,β.

    This proves the lemma.

    Proof of Theorem 4.1. We follow some arguments in [4] and may assume that b0. First set r0=(p+q)/2 and assume that there is a constant N0 such that ˆM(|b|r0)N0|b|r0, that is, |b|r0 is in the class A1 of Muckenhoupt. Observe that by Hölder's inequality bEr0,1bEq,1. It is convenient to prove the following version of (4.1) (notice r0 in place of q)

    INbpEr0,1fLp, (4.5)

    Then assume that b0, set u=P1f, and write

    I=Rd+2(bpup1)P1fdz=Rd+2P1(bpup1)fdzfLpP1(bpup1)Lp, (4.6)

    where p=p/(p1) and P1 is the conjugate operator for P1, namely, for any g0,

    (P1g)(s,x)=(P1(g(,))(s,x). (4.7)

    Next, take γ>0, such that (1+γ)pr0, 1+γpr0, and p1+γ. Note that

    P1(bpup1)=P1(b1+γ(bp1γup1))(P1(b(1+γ)p))1/p(P1(bpγpup)(p1)/p.

    It follows that

    P1(bpup1)Lp(RdbpγpupP1[(P1(b(1+γ)p))1/(p1)]dz)(p1)/p.

    Now in light of (4.6) we see that, to prove (4.5) in our particular case, it only remains to show that

    P1[(P1(b(1+γ)p))1/(p1)]NbγpbpEr0,1. (4.8)

    For α=1 and β=(1+γ)p (>α) it follows from (2.3) and (4.7) that

    P1(b(1+γ)p)NbEβ,1(ˆM(b(1+γ)p))11/(p+γp).

    where the last factor by assumption (and Hölder's inequality) is dominated by Nb(1+γ)p1 and bEβ,1bEr0,1. After that to obtain (4.8) it suffices to use again (2.3) with α=1 and β=1+γp to see that

    P1(b1+γp)NbE1+γp,1(M(b1+γp))11/(1+γp)NbEr0,1bγp.

    We now get rid of the assumption that ˆM(|b|r0)N0|b|r0 as in [4].

    For r1=(r0+q)/2 we have |b|r0(ˆM(|b|r1))r0/r1:=˜br0 and since r0/r1<1, ˜br0 is an A1-weight with N0=N0(r0/r1) (see, for instance, [7] p. 158). Therefore, (4.5) holds with ˜b in place of b and it only remains to show that

    ˜bEr0,1NbEq,1,

    that is, for any t,x,ρ,

    Cρ(t,x)˜br0dzNρd+2r0br0Eq,1. (4.9)

    Of course, we may assume that t=0,x=0. Then by Hölder's inequality we see that the left-hand side of (4.9) is less than

    Nρ(d+2)(qr0)/q(Rd+1(ˆM(|b|r1))q/r1ICρdz)r0/q,

    where the integral by a Fefferman-Stein Lemma 1, p. 111 of [6] and the fact that q/r1>1 is dominated by

    NRd+1|b|qˆMICρdzNρd+2qbqEq,1,

    where we used Lemma 4.2 b) for α=β=1. Hence,

    Cr˜br0dzNρ(d+2)(qr0)/q+(d+2q)r0/qbr0Eq,1,

    which is (4.9).

    An alternative way to get the result is to follow the proof of Theorem 3 of [3]. We have

    Rd+1(ˆM(|b|r1))q/r1ICρdzRd+1(ˆM(|b|r0))q/r0(ˆMICρ)αdz=:J,

    where α(0,1). An easy exercise leads to the well-known result that (ˆMICρ)α is an A1-weight, and, hence, an Aq/r0-weight. By the Muckenhoupt theorem

    JNRd+1|b|q(ˆMICρ)αdz

    and it only remains to use Lemma 4.2 b) again with β=1 and any appropriate α. The theorem is proved.

    Remark 4.3. In the above proof we tacitly assumed that I<. One can easily avoid it by taking f with compact support, replacing |b| with |b|bn, where n1bn=1(|t|+|x|)1, observe that br0nA1, and while checking that the new I is finite use Hölder's inequality and Corollary 2.4.

    For q1,q2[1,] and measurable f and ΓRd+1 introduce

    fLq1,q2=(R(Rd|f(t,x)|q1dx)q2/q1dt)1/q2,
    fLq1,q2(Γ)=IΓ1Lq1,q2fIΓLq1,q2.

    Here the index of Lq1,q2 which is the exponent of ρ in the expression

    ICρLq1,q2 isdq1+2q2.

    If in addition 0<βd/q1+2/q2, set

    fEq1,q2,β(Q)=supρ<,(t,x)QρβIQfLq1,q2(Cρ(t,x)).

    We also introduce the spaces Lq1,q2(Q) and Eq1,q2,β(Q) as the spaces of functions whose respective norms are finite. We abbreviate Lq1,q2=Lq1,q2(Rd+1), Eq1,q2,β=Eq1,q2,β(Rd+1).

    The following is certainly well known.

    Lemma 5.1. Let f be a nonnegative function on Rd+1, p,q(1,). Then forany wx(x),wt(t) which are Ap Muckenhoupt weights on Rd and R, respectively, we have

    Rd+1|ˆMf|pwxwtdxdtNRd+1|f|pwxwtdxdt, (5.1)

    where N depends only on d,p, and the Ap-constants of wx,wt. Furthermore,

    (Rd|ˆMf|pdx)q/pdtN(Rd|f|pdx)q/pdt, (5.2)

    where N depends only on d,p,q.

    Proof. Estimate (5.1) follows by application of the Muckenhoupt theorem to wxwt, which is an Ap-weight on Rd+1. Then observe that in the particular case that wx1, (5.1) means that

    [(Rd|ˆMf|pdx)1/p]pwtdtN[(Rd|f|pdx)1/p]pwtdt

    for any Ap-weight wt, which implies (5.2) by the Rubio de Francia extrapolation theorem. The lemma is proved.

    This lemma, (2.3), and Hölder's inequality immediately yield the following.

    Lemma 5.2. For any α(0,β),β(0,d+2], p[1,], q1,q2(1,], there exists a constant N such that for any f0 and measurable Γ we have

    PαfLr1,r2(Γ)NMβfα/βLp(Γ)f1α/βLq1,q2, (5.3)

    provided that

    1ri=αβ1p+(1αβ)1qi,i=1,2.

    Similarly to Corollary 2.4 we have

    Corollary 5.3. Let q1,q2(1,],

    β:=dq1+2q2>0,

    α(0,β). Then for any f0 we have

    PαfLr1,r2NfLq1,q2

    as long as qiβ=ri(βα), i=1,2.

    In particular, (almost follows fromTheorem 10.2 of [2])if β>1, and uC0, then

    DuLr1,r2Ntu+ΔuLq1,q2 (5.4)

    as long as qiβ=ri(β1), i=1,2.

    Corollary 5.4. Under the assumptions of Corollary5.3, if β>1, there is a constant N such that, for any b=(bi)Lβq1,βq2 and uC0,

    biDiuLq1,q2NbLβq1,βq2tu+ΔuLq1,q2. (5.5)

    Indeed, by Hölder's inequality

    biDiuLq1,q2bLβq1,βq2DuLr1,r2.

    Remark 5.5. It is instructive to compare this result with Remark 2.5. Now we can treat bLs1,s2 with si(1,] satisfying d/s1+2/s2=1.

    Since Eq1,q2,β=Lq1,q2 if β=d/q1+2/q2, the following is a generalization of Corollary 5.3.

    Theorem 5.6. Let q1,q2(1,],

    dq1+2q2β>0,

    α(0,β). Then there is a constant N such that for any f0 we have

    PαfEr1,r2,βαNfEq1,q2,β, (5.6)

    where ri(βα)=qiβ, i=1,2.

    Proof. It suffices to prove that for any ρ>0

    ρβα(ρ20(Bρ|Pαf|r1dy)r2/r1ds)1/r2NfEq1,q2,β,

    that is

    ρβα(d/r1+2/r2)(ρ20(Bρ|Pαf|r1dy)r2/r1ds)1/r2NfEq1,q2,β. (5.7)

    Observe that by Hölder's inequality MβfNfEq1,q2,β and by definition

    IC2ρfLq1,q2=Nρd/q1+2/q2(4ρ20(B2ρ|f|q1dy)q2/q1ds)1/q2
    Nρd/q1+2/q2βfEq1,q2,β=Nρ(d/r1+2/r2)β/(βα)βfEq1,q2,β.

    It follows from Lemma 5.2 with p= that (5.7) holds with IC2ρf in place of f on the left.

    Furthermore, by Corollary 2.6 we have |Pα(ICc2ρf)|NραβMβf in Cρ. Therefore,

    ρβα(ρ20(Bρ|Pα(ICc2ρf)|r1dy)r2/r1ds)1/r2NsupMβfNfEq1,q2,β.

    By combining these results we come to (3.2) and the theorem is proved.

    Corollary 5.7. Under the assumptions of Theorem 5.6, if β>1, for any uC0, we have

    DuEr1,r2,β1Ntu+ΔuEq1,q2,β,

    where ri(β1)=qiβ, i=1,2. This coincides with (5.4) if β is equal to the index of Lq1,q2.

    Remark 5.8. Corollary 5.7 opens up the possibility to treat the terms like biDiu as perturbation terms in operators like tu+Δu+biDiu with even lower summability properties of b=(bi) than in Remark 5.5. To show this observe that for q1,q2,β as in Theorem 5.6 with β>1 and si=βqi(1,], i=1,2, we have

    ρβICρbiDiuLq1,q2ρbICρLs1,s2ρβ1ICρDuLr1,r2

    implying that

    biDiuEq1,q2,βbEs1,s2,1DuEr1,r2,β1NbEs1,s2,1tu+ΔuEq1,q2,β, (5.8)

    where d/s1+2/s21.

    However, note that we also need

    ρbICρ(t,x)Ls1,s2

    to be bounded as a function of ρ,t,x. If we ask ourselves what τ>0 should be to guarantee this boundedness if bLτs1,τs2, if d/s1+2/s2>1, the slightly disappointing answer is that τ=d/s1+2/s2, so that d/(τs1)+2/(τs2)=1. Still functions in Es1,s2,1 may have higher singularities than those in Lτs1,τs2.

    Another advantage of (5.8) in comparison with (5.5) is seen when b depends only on t or |b(t,x)|ˆb(t). In that case (5.8) becomes

    biDiuEq1,q2,βNˆbEβq2,1/2(R)tu+ΔuEq1,q2,β,

    and if βq2=2, then

    ˆbEβq2,1/2(R)=ˆbL2(R).

    Thus for any q1(1,] and q2(1,2)

    biDiuEq1,q2,2/q2NˆbL2(R)tu+ΔuEq1,q2,2/q2.

    In case q1(1,d), q2(1,], 1<βd/q1, and b(,t)Eβq1,1(Rd)ˆb< for any t, we also have

    biDiuEq1,q2,βNˆbtu+ΔuEq1,q2,β.

    An application of the last inequality in case u,b are independent of t, β=d/q1, q1(1,d), and q2=, yields the well-known estimate

    biDiuLq1(Rd)NbLd(Rd)ΔuLq1(Rd).

    To extend the embedding and interpolation results to Morrey spaces with mixed norms we need the following result very useful also in other circumstances.

    Lemma 5.9 (Poincaré's inequality). Let 1r1,r2<, uC0, ρ(0,).Then

    Du(Du)Cρr2Lr1,r2(Cρ)N(d,r1,r2)ρr2|tu|+|D2u|r2Lr1,r2(Cρ). (5.9)

    Proof. We follow the usual way (see, for instance, Lemma 4.2.2 of [9]). First, due to self-similar transformations, we may take ρ=1. In that case, for a ζC0(B1) with unit integral, introduce

    v(t)=B1ζ(y)Du(t,y)dy.

    Then by the usual Poincaré inequality

    B1|Du(t,x)v(t)|r1dx=B1|B1[Du(t,x)Du(t,y)]ζ(y)dy|r1dx
    NB1B1|Du(t,x)Du(t,y)|r1dxdyNB1|D2u(t,x)|r1dx. (5.10)

    Next, observe that for any constant vector v the left-hand side of (5.9) is less than a constant times (recall that ρ=1)

    10(B1|Du(t,x)v|r1dx)r2/r1dt
    N10(B1|Du(t,x)v(t)|r1dx)r2/r1dt+N10|v(t)v|r2dt.

    By (5.10) the first term on the right is less than the right-hand side of (5.9). To estimate the second term, take

    v=10v(t)dt.

    Then by Poincaré's inequality

    10|v(t)v|r2dtN10|B1ζtDudx|r2dt=N10|B1(Dζ)tudx|r2dt

    and to finish the proof it only remains to use Hölder's inequality. The lemma is proved.

    The usual Poincaré inequality was used in the proof of Lemma 3.9. Also observe that mixed-norms estimates like (3.10) are available in [2] (see Theorem 9.5 there). Therefore, by using Lemma 5.9 and following very closely the proofs of Lemmas 3.8, 3.9, and Theorems 3.10 we arrive at the following results about interpolation and embedding for Morrey spaces with mixed norms.

    Lemma 5.10. Let q1,q2(1,), 0<βd/q1+2/q2. Then there is a constant N such that, for any R(0,), ε(0,1], and uC0,

    DuEq1,q2,β(CR)NεR|tu|+|D2u|Eq1,q2,β(CR)+Nε1R1uEq1,q2,β(CR). (5.11)

    Theorem 5.11. Let q1,q2(1,), 1<βd/q1+2/q2 and let ri(β1)=qiβ, i=1,2. Then there is a constant N such that for any R(0,], uC0 we have

    DuEr1,r2,β1(CR)N|tu|+|D2u|Eq1,q2,β(CR)+NR2uEq1,q2,β(CR). (5.12)

    Remark 5.12. By taking u depending only on x we recover from Lemma 5.10 and Theorem 5.11 their "elliptic" counterpart stated as Lemmas 4.4 and 4.7 in [10], respectively.

    Remark 5.13. Theorem 5.11 is the most general results of the paper containing as particular cases our previous results on embeddings. Thus, Corollary 5.7 (in an obvious rougher form) follows from Theorem 5.11 when R= and contains embedding results for Lebesgue spaces with mixed norms as β=d/q1+2/q2 and for Lq-spaces as q=q1=q2.

    Remark 5.14. We stated our results only for uC0 just for convenience. Let us show why, for instance, Theorem 5.11 is valid as long as tu,Du,D2uEq1,q2,β(CR). For that, it suffices to prove that for any R<R, ρ>0, (t,x)CR the quantity

    I:=ρβICRDuLr1,r2(Cρ(t,x))

    is less than the right-hand side of (5.12) with (R)2 in place of R2. For ε>0 define u(ε)=(ICRu)ζε, where ζε(x)=εd1ζ(t/ε,x/ε), nonnegative ζC0 has integral one and ζ(t,x)=0 for t0. Also introduce Iε by replacing u in the definition of I with u(ε). Of course, IεI as ε0 and by Theorem 5.11

    IεN|tu(ε)|+|D2u(ε)|Eq1,q2,β(CR)+N(R)2u(ε)Eq1,q2,β(CR)=:Jε.

    Observe that if ε is small enough and (s,y)CR, then tu(ε)(s,y)=(ICRtu)ζε(s,y). Similar formulas are valid for D2u(ε) and by Minkowski's inequality (the norm of a sum is less then the sum of norms) we have

    JεRd+1ζ(s,y)(NICR(|tu|+|D2u|)(ε(s,y)Eq1,q2,β(CR)
    +N(R)2ICRu(ε(s,y)Eq1,q2,β(CR))dyds
    =Rd+1ζ(s,y)(NICR(|tu|+|D2u|)Eq1,q2,β(CRε(s,y))
    +N(R)2ICRuEq1,q2,β(CRε(s,y)))dyds.

    Since in the last integral CRε(s,y)CR if ε is small enough, it follows that for small ε

    JεNICR(|tu|+|D2u|)Eq1,q2,β(CR)+N(R)2ICRuEq1,q2,β(CR)

    which yields the desired result.

    The author brings his gratitude to the referees for their useful comments.

    The author declares no conflict of interest.



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    6. Julie Clutterbuck, Jiakun Liu, Preface to the Special Issue: Nonlinear PDEs and geometric analysis – Dedicated to Neil Trudinger on the occasion of his 80th birthday, 2023, 5, 2640-3501, 1, 10.3934/mine.2023095
    7. N.V. Krylov, Once again on weak solutions of time inhomogeneous Itô’s equations with VMO diffusion and Morrey drift, 2024, 29, 1083-6489, 10.1214/24-EJP1159
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