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Research article

Exact solutions of a class of nonlinear dispersive long wave systems via Feng's first integral method

  • Received: 23 March 2021 Accepted: 11 May 2021 Published: 21 May 2021
  • MSC : 35A09, 35A24, 35C07, 35C08, 35F50, 35G50

  • In this paper, eight groups of exact solutions for the (1+1)-dimensional and (2+1)-dimensional nonlinear dispersive long wave systems are found respectively via Feng's first integral method. It is shown that there are some similarities in the expressions of the solutions of (1+1)-dimensional and (2+1)-dimensional DLWEs, while there exist some differences in their dimensions and their physical significance. Finally, some graphs are presented to show these features, which also show the effectiveness of the proposed method.

    Citation: Qiuci Lu, Songchuan Zhang, Hang Zheng. Exact solutions of a class of nonlinear dispersive long wave systems via Feng's first integral method[J]. AIMS Mathematics, 2021, 6(8): 7984-8000. doi: 10.3934/math.2021464

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  • In this paper, eight groups of exact solutions for the (1+1)-dimensional and (2+1)-dimensional nonlinear dispersive long wave systems are found respectively via Feng's first integral method. It is shown that there are some similarities in the expressions of the solutions of (1+1)-dimensional and (2+1)-dimensional DLWEs, while there exist some differences in their dimensions and their physical significance. Finally, some graphs are presented to show these features, which also show the effectiveness of the proposed method.



    The nonlinear dispersive long wave equations (DLWEs) are a class of important nonlinear partial differential equations (PDEs), which have widely arisen in oceanic water waves [1], fluid or plasma mechanics [2], dynamics [3] and other fields [4,5,6,7,8,9,10]. The solitary wave solutions of the DLWEs can be used to describe nonlinear wave phenomena such as dispersion, dissipation, diffusion, reaction, convection, etc. As far as we know, there exist some methods to find exact solutions of DLWEs, it is concluded that: the Bácklund transformations method and the Hirota bilinear method [1,2], the bifurcation method of planar dynamical systems [3], the modified Clarkson and Kruskal's (CK's) direct method [4], the variable separation approach [5], etc.

    In this paper, we consider the following (2+1)-dimensional nonlinear dispersive long wave system:

    uty+vxx+12(u2)xy=0,vt+(u+uv+uxy)x=0, (1.1)

    where u(x,y,t) is the horizontal velocity, v(x,y,t) represents the wave altitude above the undisturbed water surface, t denotes the time, and (x,y) stands for the spreading plane. In fact, the system (1.1) can be used to solve nonlinear evolutional problems in two spatial dimensions by inverse spectral transform, which was first obtained by Boiti [6] as a compatibility condition for a weak Lax pair. It is a hot topic to find the traveling wave solution of nonlinear partial differential equations (PDEs). Zhou [3] utilized dynamical systems and the numerical simulation method to study dynamical behaviors of travelling waves. Lou [7] gained nine types of two-dimensional partial differential equation and thirteen types of the ordinary differential equation with the help of the direct and nonclassical method. Zhang [8] obtained a kind of special multisoliton-like solutions of the system by using the Bácklund transform. Yomba [9] got some new soliton-like solutions in virtue of a modified extending tanh method. Elgarayhi [10] employed Jacobi elliptic functions to construct periodic wave solutions of the system (1.1). Recently, Zhu and Xia et al. studied the exact solutions of the Klein-Gordon equation and Hirota-Satsuma coupled KdV system [11] and Ginzburg-Landau equation [12] via method of the bifurcation theory of planar dynamical system. Zhang and Xia et al. also employed dynamical system method to obtain the exact solutions of the generalized combined double sinh-cosh-Gordon equation [13] and the fractional-order and integer-order Biswas-Milovic equation [14].

    Different from them, we use Feng's first integral method [15] to obtain the exact solutions of the system (1.1). In fact, Feng's first integral method was initially proposed by Feng [16] which is based on the ring theory of commutative algebra. This powerful method has been widely applied to solve many PDEs and further developed by many authors [17,18,19,20,21,22,23]. Particularly, if x=y, the system (1.1) can be reduced to (1+1)-dimensional nonlinear dispersive long wave systems as follows:

    utx+vxx+12(u2)xx=0,vt+(u+uv+uxx)x=0, (1.2)

    where u(x,t) and v(x,t) stand for the horizontal velocity and height of water waves respectively. The system (1.2) can be used to describe the evolvement of the horizontal velocity composition u(x,t) and height v(x,t) of water waves which are spreading at an infinite narrow channel of finite constant depth in both directions [1,5].

    The rest of this paper is organized as follows: Section 2, we introduce the steps of first integral method for the nonlinear partial differential systems. In section 3, we obtain eight groups of solutions for the (1+1)-dimensional and (2+1)-dimensional nonlinear dispersive long wave system respectively via Feng's first integral method. In section 4, we make a short summary.

    Hosseini [22] and El-Sabbagh [23] had summarized the steps of Feng's first integral method for the PDEs. Here, we apply it to the system (1.2) as follows:

    Step I. Utilize traveling wave transformations u(x,t)=ϕ(ξ) and v(x,t)=φ(ξ), where ξ=xct, we can change (1.2) into an ordinary differential system as follows:

    cϕ+φ+12(ϕ2)=0,cφ+(ϕ+ϕφ+ϕ)=0, (2.1)

    where "" and "" etc denote the derivatives about the same variable ξ.

    Step II. By some proper mathematical calculation, we try to transform the system (2.1) into a second-order ordinary differential equation. Here, we can integrate the first equation of (2.1) once and let the integral constant be 0 and integrate it once. We have:

    cϕ+φ+12ϕ2=k1, (2.2)

    where k1 is an integral constant. Integrate the second equation of (2.1) once, we have:

    cφ+ϕ+ϕφ+ϕ=k2, (2.3)

    where k2 is an integral constant. We rewrite (2.2) as φ=cϕ12ϕ2+k1 and substitute it into (2.3), we have:

    ϕ=12ϕ332cϕ2+(c2k11)ϕ+ck1+k2. (2.4)

    Step III. With the introduction of new variables X=ϕ(ξ) and Y=ϕ(ξ)=X, (2.4) can be changed into a system of ODEs as the following forms:

    X=Y,Y=12X332cX2+(c2k11)X+ck1+k2. (2.5)

    Step IV. We try to seek one first integration to (2.5) which reduces (2.4) to a first-order integrable ordinary differential equation by the Division Theorem which is on the basis of ring theory of commutative algebra. Finally, we can establish an exact solution to (1.2) by means of solving the resulting first-order integrable differential equation.

    Division Theorem [24]: Suppose that P(w,z) and Q(w,z) are polynomials of two variables w and z and P(w,z) is irreducible in C[w,z]. If Q(w,z) vanishes at all zero points of P(w,z), then there exists a polynomial R(w,z) in C[w,z] such that

    Q(w,z)=P(w,z)R(w,z).

    Remark 2.1 If the system (1.2) is instead of a common partial differential system, the above train of thought and specific solving steps are the same (see [22,23]). Moreover, if the independent variables of (1.2) are x,y and t even more, the steps to resolve the system are similar.

    In this section, we try to seek the exact solutions for the (1+1)-dimensional and (2+1)-dimensional nonlinear dispersive long wave system via Feng's first integral method which was described in Sect. 2.

    By the steps of Feng's first integral method which were described in Sect. 2, we utilize the Division Theorem to seek the first integration of (2.5) now. Assume that X=X(ξ) and Y=Y(ξ) are the nontrivial solutions to (2.5) and P(X,Y)=mi=0si(X)Yi is an irreducible polynomial in C[X,Y] such that:

    P(X(ξ),Y(ξ))=mi=0si(X)Yi=0, (3.1)

    where si(X),i=0,1,2,...,m are polynomials of X, which sm(X)0. In this case, we generally take m=1 or m=2. Equation (3.1) is also called the first integration to (2.5). According to the Division Theorem, there exists a polynomial Q(X,Y)=g(X)+h(X)YC[X,Y] such that:

    dPdξ=dPdXdXdξ+dPdYdYdξ=[g(X)+h(X)Y]mi=0si(X)Yi. (3.2)

    Case 1: We suppose m=1 in (3.1) and equate the coefficients of Yi,i=0,1 on both sides of (3.2), that we can obtain a group of equations as follows:

    s1(X)=s1(X)h(X),s0(X)=s0(X)h(X)+s1(X)g(X),s1(X)[12X332cX2+(c2k11)X+ck1+k2]=s0(X)g(X). (3.3)

    As si(X),i=0,1 are polynomials of X, then from the first equation of (3.3), we can conclude that s1(X) is a constant and h(X)=0. Without loss of generality, we take s1(X)=1 and substitute it into the second and third equations of (3.3), then balance the degrees of g(X) and s0(X), that we can conclude that deg(g(X))=1. Thus, we can assume g(X)=A1X+A0, where A10, A1 and A0 are undetermined constants, then from the second equation of (3.3), we obtain:

    s0(X)=12A1X2+A0X+B, (3.4)

    where B is an integral constant. We substitute s0(X),s1(X) and g(X) into the third equation of (3.3) and equate the coefficient of each power of X to zero, which yields:

    12=12A21,32c=32A0A1,c2k11=A1B+A0,ck1+k2=A0B. (3.5)

    Solving (3.5), which leads to:

    A1=1,A0=c,k1=B1,k2=c, (3.6)

    and

    A1=1,A0=c,k1=B1,k2=c, (3.7)

    where c and B are arbitrary constants. By substituting (3.6), (3.7) into (3.1) and considering Y=X, we can derive two first-order ordinary differential equations for X as follows:

    X+12X2cX+B=0, (3.8)

    and

    X12X2+cX+B=0. (3.9)

    By solving (3.8) and (3.9) respectively and considering X(ξ)=ϕ(ξ), u(x,t)=ϕ(ξ), v(x,t)=φ(ξ), ξ=xct and φ=cϕ12ϕ2+k1, we obtain four groups of solutions for (1.2) as follows:

    u=c2Bc2tan[2Bc22(xct)+C1],v=(12c2B)[tan(2Bc22(xct)+C1)]2+12c2B1, (3.10)

    where c and B are arbitrary constants, 2Bc2>0 and C1 is an integral constant.

    u=c+c22Bcoth[c22B2(xct)+C2],v=(B12c2)[coth(c22B2(xct)+C2)]2+12c2B1, (3.11)

    where c and B are arbitrary constants, 2Bc2<0 and C2 is an integral constant.

    u=c+(2B+c2)tan[(2B+c2)2(xct)+C3],v=(B+12c2)[tan((2B+c2)2(xct)+C3)]2+12c2+B1, (3.12)

    where c and B are arbitrary constants, 2B+c2<0 and C3 is an integral constant.

    u=c2B+c2coth[2B+c22(xct)+C4],v=(B+12c2)[coth(2B+c22(xct)+C4)]2+12c2+B1, (3.13)

    where c and B are arbitrary constants, 2B+c2>0 and C4 is an integral constant.

    Remark 3.1 We have got four groups of solitary wave solutions for (1.2) via Feng's first integral method when m=1 in (3.1).

    Case 2: Suppose m=2 in (3.1) and equalize the coefficients of Yi,i=0,1,2 on both sides of (3.2), we obtain a group of equations as follows:

    s2(X)=s2(X)h(X),s1(X)=a1(X)h(X)+s2(X)g(X),s0(X)+2s2(X)[12X332cX2+(c2k11)X+ck1+k2]=s0(X)h(X)+s1(X)g(X),s1(X)[12X332cX2+(c2k11)X+ck1+k2]=s0(X)g(X). (3.14)

    Because si(X),i=0,1,2 are polynomials of X, then from the first equation of (3.14) we can conclude that s2(X) is a constant and h(X)=0. Without loss of generality, we take s2(X)=1 and substitute it into the second and third and fourth equations of (3.14), then balance the degrees of g(X) and s1(X) as well as s0(X) and s1(X), we can conclude that deg(g(X))=1. Thus, we assume g(X)=A1X+A0, where A10, A1 and A0 are undetermined constants, then from the second equation of (3.14), we have:

    s1(X)=12A1X2+A0X+B, (3.15)

    where B is an integral constant. Then we substitute s2(X),s1(X) and g(X) into the third equation of (3.14). We have:

    s0(X)=(18A2114)X4+(12A0A1+c)X3+(12A1B+12A20c2+k1+1)X2+(A0B2(ck1+k2))X+B1. (3.16)

    We substitute s0(X),s1(X), s2(X) and g(X) into the fourth equation of (3.14) and equate the coefficient of each power of X to zero, that we can obtain a system of equations made up of A1,A0,B,B1,c,k1 and k2. By solving this system, that we obtain two groups of solutions as follows:

    A1=2,A0=2c,B1=14B2,k1=12B1,k2=c, (3.17)

    and

    A1=2,A0=2c,B1=14B2,k1=12B1,k2=c, (3.18)

    where c and B are arbitrary constants. We substitute (3.17) and (3.18) into (3.15) and (3.16) respectively, that we can obtain the expressions for s0(X),s1(X) and s2(X), then we plug these expressions into (3.1) and consider Y=X, that we can derive two second-order equations for X as follows:

    (X)2+(X22cX+B)X+12X4cX3+(c2+12B)X2cBX+14B2=0, (3.19)

    and

    (X)2+(X2+2cX+B)X+12X4cX3+(c212B)X2+cBX+14B2=0. (3.20)

    Solve (3.19) and (3.20) respectively, we obtain the following two first-order ordinary differential equations for X:

    X=12(X22cX+B), (3.21)

    and

    X=12(X22cXB). (3.22)

    Solve (3.21) and (3.22) respectively and consider X(ξ)=ϕ(ξ), u(x,t)=ϕ(ξ), v(x,t)=φ(ξ), ξ=xct and φ=cϕ12ϕ2+k1, we obtain four groups of solutions for (1.2) as follows:

    u=cBc2tan[Bc22(xct)+C5],v=12(c2B)[tan(Bc22(xct)+C5)]2+12c212B1, (3.23)

    where c and B are arbitrary constants, Bc2>0 and C5 is an integral constant.

    u=c+c2Bcoth[c2B2(xct)+C6],v=12(Bc2)[coth(c2B2(xct)+C6)]2+12c212B1, (3.24)

    where c and B are arbitrary constants, Bc2<0 and C6 is an integral constant.

    u=c+(B+c2)tan[(B+c2)2(xct)+C7],v=12(B+c2)[tan((B+c2)2(xct)+C7)]2+12c2+12B1, (3.25)

    where c and B are arbitrary constants, B+c2<0 and C7 is an integral constant.

    u=cB+c2coth[B+c22(xct)+C8],v=12(B+c2)[coth(B+c22(xct)+C8)]2+12c2+12B1, (3.26)

    where c and B are arbitrary constants, B+c2>0 and C8 is an integral constant.

    Remark 3.2 We have got four groups of solitary wave solutions for (1.2) via Feng's first integral method when m=2 in (3.1). All exact solutions of the (1+1)-dimensional nonlinear dispersive long wave system (1.2) have been obtained.

    Now, we plot the three-dimensional graphs of the solutions (3.10) and (3.11) respectively (see the following Figures 14), the graphs of the rest of three groups of solutions (3.12), (3.23) and (3.25) are similar to (3.10), while the graphs of the rest of other three groups of solutions (3.13), (3.24) and (3.26) are similar to (3.11). We illustrate the figures as follows:

    Figure 1.  The three-dimensional graph of the solution u(x,t) of (3.10) for c=1,B=1,C1=0.
    Figure 2.  The three-dimensional graph of the solution v(x,t) of (3.10) for c=1,B=1,C1=0.
    Figure 3.  The three-dimensional graph of the solution u(x,t) of (3.11) for c=3,B=4,C2=0.
    Figure 4.  The three-dimensional graph of the solution v(x,t) of (3.11) for c=3,B=4,C2=0.

    (1) Figure 1(a) displays the three-dimensional graph of the solution u(x,t) of (3.10) with eligible parameters "c=1,B=1,C1=0 '' and small variable intervals "x(2,2),t(0,2)''. Figure 1(b) shows the three-dimensional graph of the solution u(x,t) of (3.10) which takes the same eligible parameters and larger variable intervals "x(30,30),t(0,30)''. The process of drawing and simulation shows that this is a class of solitary wave solution and the number and size of the solitons change greatly as the interval changes.

    (2) Figure 2 displays the three-dimensional graph of the solution v(x,t) of (3.10) with c=1,B=1 and C1=0. Let "x(2,2),t(0,2)'' in Figure 2(a), while the larger variable intervals "x(30,30),t(0,30)'' is taken in Figure 2(b). The process of drawing and simulation shows that it is a distorted wave solution if we take a smaller variable interval, while it is a class of solitary wave solution if we take a larger variable interval. The number and size of these solitons change greatly as the interval changes.

    (3) Figures 3(a) and 3(b) display the three-dimensional graphs of the solution u(x,t) of (3.11) with eligible parameters c=3,B=4 and C2=0 while Figures 4(a) and 4(b) display the three-dimensional graphs of the solution v(x,t) of (3.11) with eligible parameters c=3,B=4 and C2=0. The process of drawing and simulation shows that they are also a class of solitary wave solutions and the number and size of the solitons change greatly as the intervals change.

    By using the travel wave transformations u(x,t)=ϕ(ξ) and v(x,t)=φ(ξ), where ξ=x+ayct, we change (1.1) into an ordinary differential system as follows:

    acϕ+φ+a2(ϕ2)=0,cφ+(ϕ+ϕφ+aϕ)=0. (3.27)

    Integrate the first equation of (3.27) once and let the integral constant be equal to 0 and integrate it once. We have:

    acϕ+φ+a2ϕ2=k3, (3.28)

    where k3 is an integral constant. Integrate the second equation of (3.27) once, we obtain:

    cφ+ϕ+ϕφ+aϕ=k4, (3.29)

    where k4 is an integral constant. We rewrite (3.28) as φ=acϕa2ϕ2+k3 and substitute it into (3.29), we have:

    ϕ=12ϕ332cϕ2+(c2k3+1a)ϕ+ck3+k4a. (3.30)

    With the introduction of new variables ϕ(ξ)=X(ξ) and X(ξ)=Y(ξ), (3.30) converts to a system of ODEs:

    X=Y,Y=12X332cX2+(c2k3+1a)X+ck3+k4a. (3.31)

    We utilize the Division Theorem to seek the first integration to (3.31) now. Assume that X=X(ξ) and Y=Y(ξ) are the nontrivial solutions to (3.31) and P(X,Y)=mi=0si(X)Yi is an irreducible polynomial in C[X,Y] such that:

    P(X(ξ),Y(ξ))=mi=0si(X)Yi=0, (3.32)

    where si(X),i=0,1,2,...,m are polynomials of X, which sm(X)0. In this case, we generally take m=1 or m=2. Equation (3.32) is also referred to as the first integration to (3.31). According to Division Theorem [24], there exists a polynomial Q(X,Y)=g(X)+h(X)YC[X,Y] such that:

    dPdξ=dPdXdXdξ+dPdYdYdξ=[g(X)+h(X)Y]mi=0si(X)Yi. (3.33)

    Case 3: Assume m=1 in (3.32) and equate the coefficients of Yi,i=0,1 on both sides of (3.33), we derive a groups of equations as follows:

    s1(X)=s1(X)h(X),s0(X)=s0(X)h(X)+s1(X)g(X),s1(X)[12X332cX2+(c2k3+1a)X+ck3+k4a]=s0(X)g(X). (3.34)

    Because si(X),i=0,1 are polynomials of X, then from the first equation of (3.34), we can conclude that s1(X) is a constant and h(X)=0. Without loss of generality, we take s1(X)=1 and substitute it into the second and third equations of (3.34), then balance the degrees of g(X) and s0(X), we can conclude that deg(g(X))=1. Thus, we assume g(X)=A1X+A0, where A10,A1 and A0 are undetermined constants, then from the second equation of (3.34), we have:

    s0(X)=12A1X2+A0X+B, (3.35)

    where B is an integral constant. We substitute s0(X),s1(X) and g(X) into the third equation of (3.34) and equate the coefficient of each power of X to zero that we obtain a system of equations made up of a,A1,A0,B,c,k3 and k4. By solving this system, we obtain two groups of solutions as follows:

    A1=1,A0=c,k3=aB1,k4=c, (3.36)

    and

    A1=1,A0=c,k3=aB1,k4=c, (3.37)

    where a,c and B are arbitrary constants. Substitute (3.36) and (3.37) into (3.32) and consider Y=X, we derive two first-order ordinary differential equations for X as follows:

    X+12X2cX+B=0, (3.38)

    and

    X12X2+cX+B=0. (3.39)

    Now, by solving Eqs (3.38) and (3.39) respectively and considering X(ξ)=ϕ(ξ), u(x,t)=ϕ(ξ), v(x,t)=φ(ξ), ξ=x+ayct and φ=acϕa2ϕ2+k3, we obtain four groups of solutions for (1.1) as follows:

    u=c2Bc2tan[2Bc22(x+ayct)+C9],v=(12ac2aB)[tan(2Bc22(x+ayct)+C9)]2+12ac2aB1, (3.40)

    where a,c and B are arbitrary constants, 2Bc2>0 and C9 is an integral constant.

    u=c+c22Bcoth[c22B2(x+ayct)+C10],v=(aB12ac2)[coth(c22B2(x+ayct)+C10)]2+12ac2aB1, (3.41)

    where a,c and B are arbitrary constants, 2Bc2<0 and C10 is an integral constant.

    u=c+(2B+c2)tan[(2B+c2)2(x+ayct)+C11],v=(aB2+12ac2)[tan((2B+c2)2(x+ayct)+C11)]2+12ac2+aB1, (3.42)

    where a,c and B are arbitrary constants, 2B+c2<0 and C11 is an integral constant.

    u=c2B+c2coth[2B+c22(x+ayct)+C12],v=(aB2+12ac2)[coth(2B+c22(x+ayct)+C12)]2+12ac2+aB1, (3.43)

    where a,c and B are arbitrary constants, 2B+c2>0 and C12 is an integral constant.

    Remark 3.3 We have got four groups of solitary wave solutions for (1.1) via Feng's first integral method when m=1 in (3.32).

    Case 4: Suppose m=2 in (3.32) and equate the coefficients of Yi,i=0,1,2 on both sides of (3.33), we obtain equations as follows:

    s2(X)=s2(X)h(X),s1(X)=s1(X)h(X)+s2(X)g(X),s0(X)+2s2(X)[12X332cX2+(c2k3+1a)X+ck3+k4a]=s0(X)h(X)+s1(X)g(X),s1(X)[12X332cX2+(c2k3+1a)X+ck3+k4a]=s0(X)g(X). (3.44)

    Since si(X),i=0,1,2 are polynomials of X, then from the first equation of (3.44), we can conclude that s2(X) is a constant and h(X)=0. For simplicity, we take s2(X)=1 and substitute it into the second and third and forth equations of (3.44), then balance the degrees of g(X) and s1(X) as well as s0(X) and s1(X), we can conclude that deg(g(X))=1. Thus, we can assume g(X)=A1X+A0, where A10, A1 and A0 are undetermined constants, from the second equation of (3.44), we have:

    s1(X)=12A1X2+A0X+B, (3.45)

    where B is an integral constant. Then we substitute s2(X),s1(X) and g(X) into the third equation of (3.44), we obtain:

    s0(X)=(18A2114)X4+(12A0A1+c)X3+(12A1B+12A20c2+k3+1a)X2+(A0B2(ck3+k4)a)X+B1. (3.46)

    Now we substitute s0(X),s1(X), s2(X) and g(X) into the fourth equation of (3.44) and equate the coefficient of each power of X to zero, that we can derive a system of equations made up of a,A1,A0,B,B1,c,k3 and k4. By solving this system, we obtain two groups of solutions as follows:

    A1=2,A0=2c,B1=14B2,k3=12aB1,k4=c, (3.47)

    and

    A1=2,A0=2c,B1=14B2,k3=12aB1,k4=c, (3.48)

    where a,c and B are arbitrary constants.

    Now we substitute (3.47), (3.48) into (3.45) and (3.46) respectively and obtain the expressions for s0(X),s1(X) and s2(X), then plug them into (3.32) and consider Y=X, that we can derive two equations for X:

    (X)2+(X22cX+B)X+12X4cX3+(c2+12B)X2cBX+14B2=0, (3.49)

    and

    (X)2+(X2+2cX+B)X+12X4cX3+(c212B)X2+cBX+14B2=0. (3.50)

    Solve (3.49) and (3.50) respectively, we obtain the following two first-order ordinary differential equations:

    X=12(X22cX+B), (3.51)

    and

    X=12(X22cXB). (3.52)

    Now, resolve (3.51) and (3.52) respectively and consider X(ξ)=ϕ(ξ), u(x,t)=ϕ(ξ), v(x,t)=φ(ξ), ξ=x+ayct and φ=acϕa2ϕ2+k3, that we obtain four groups of solutions for (1.1) as follows:

    u=cBc2tan[Bc22(x+ayct)+C13],v=a2(c2B)[tan(Bc22(x+ayct)+C13)]2+12ac212aB1, (3.53)

    where a,c and B are arbitrary constants, Bc2>0 and C13 is an integral constant.

    u=c+c2Bcoth[c2B2(x+ayct)+C14],v=a2(Bc2)[coth(c2B2(x+ayct)+C14)]2+12ac212aB1, (3.54)

    where a,c and B are arbitrary constants, Bc2<0 and C14 is an integral constant.

    u=c+(B+c2)tan[(B+c2)2(x+ayct)+C15],v=a2(B+c2)[tan((B+c2)2(x+ayct)+C15)]2+12ac2+12aB1, (3.55)

    where a,c and B are arbitrary constants, B+c2<0 and C15 is an integral constant.

    u=cB+c2coth[B+c22(x+ayct)+C16],v=a2(B+c2)[coth(B+c22(x+ayct)+C16)]2+12ac2+12aB1, (3.56)

    where a,c and B are arbitrary constants, B+c2>0 and C16 is an integral constant.

    Remark 3.4 We have got four groups of solitary wave solutions for (1.1) via Feng's first integral method when m=2 in (3.32). Now, all exact solutions of the (2+1)-dimensional nonlinear dispersive long wave system (1.1) have been obtained.

    Now, we plot the three-dimensional graphs of the solution (3.55) and (3.56) respectively (see the following Figures 58). The rest of three groups of graphs for (3.40), (3.42) and (3.53) are similar to (3.55), while the rest of other three groups of graphs for (3.41), (3.43) and (3.54) are similar to (3.56). We illustrate the figures as follows:

    Figure 5.  The three-dimensional graph of the solution u(x,y,t) of (3.55) for c=1,B=5,a=2,C15=0.
    Figure 6.  The three-dimensional graph of the solution v(x,y,t) of (3.55) for c=1,B=5,a=2,C15=0.
    Figure 7.  The three-dimensional graph of the solution u(x,y,t) of (3.56) for c=1,B=3,a=2,C16=0.
    Figure 8.  The three-dimensional graph of the solution v(x,y,t) of (3.56) for c=2,B=5,a=2,C16=0.

    (1) Figure 5(a) displays the three-dimensional graph of the solution u(x,y,t) of (3.55) with c=1,B=5,a=2,C15=0,t=0 and small variable intervals x(1,1),y(1,1). Figure 5(b) shows the three-dimensional graph of the solution u(x,y,t) of (3.55) with same parameters and larger variable intervals x(20,20),y(20,20). The process of drawing and simulation shows that this is a class of solitary wave solution and the number and size of these solitons change greatly as the interval changes. (Remark: Here we let t as a constant, while the case is similar to Figure 1 if we take x (or y) as a constant and y (or x) and t are variable. The cases for Figures 68 are the same).

    (2) Figure 6 displays the three-dimensional graph of the solution v(x,y,t) of (3.55) with c=1,B=5,a=2,C15=0 and t=1. Let x(1,1),y(1,1) in Figure 6(a), while the larger variable interval x(20,20),y(20,20) is taken in Figure 6(b). The process of drawing and simulation shows that it is also a class of solitary wave solution and the number and size of the solitons change greatly as the interval changes.

    (3) Figures 7(a) and 7(b) display the three-dimensional graphs of the solution u(x,y,t) of (3.56) with c=1,B=3,a=2,C16=0 and t=12, while Figures 8(a) and 8(b) show the three-dimensional graphs of the solution v(x,y,t) of (3.56) with c=2,B=5,a=2,C16=0 and t=1. The process of drawing and simulation shows that they are also a class of solitary wave solutions and the number and size of the solitons change greatly as the intervals change.

    In this paper, Feng's first integral method was successfully applied to solve the (1+1)-dimensional and (2+1)-dimensional nonlinear dispersive long wave systems. We gain eight groups of exact solutions for the (1+1)-dimensional and (2+1)-dimensional nonlinear dispersive long wave system respectively via Feng's first integral method. We find that there exist some similarities in the expressions of the solutions of (1+1)-dimensional and (2+1)-dimensional DLWEs but there exists some differences in their dimensions for their respective solutions. While system (1.1) and system (1.2) have different physical significance due to their dimensions. We plot their figures typically to illustrate the features of the results. The process of drawing and simulation shows that the solutions of system (1.1) and (1.2) all belong to solitary wave solutions except that we take a minimum interval that it belongs to a distorted wave solution for the example Figure 2(a). The number and size of their solitons change greatly as the intervals change. There exist some problems that subject to be resolved in this paper, for example, if we take m=3 or larger number in (3.1) and (3.32), do the system (1.1) and (1.2) exist solutions or can we find out? This can be the direction of our future work.

    This paper was supported by Natural Science Foundation of Fujian Province under Grant (No. 2017J01769), Science and Technology Project of Education Department of Fujian Province (No. JA15512), and Senior talent introduction program (No. YJ201802). We give thanks to Professor Y. H. Xia also his series of papers [11,12,13,14] which gave a lot of enlightenments for this paper.

    The authors declare that there is no conflict of interest regarding publication of this paper.



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