Recently, the combined fractional operator (CFO) is introduced and discussed in Baleanu et al. [
Citation: Rabha W. Ibrahim, Dumitru Baleanu. On a combination of fractional differential and integral operators associated with a class of normalized functions[J]. AIMS Mathematics, 2021, 6(4): 4211-4226. doi: 10.3934/math.2021249
[1] | Rabha W. Ibrahim, Jay M. Jahangiri . Conformable differential operator generalizes the Briot-Bouquet differential equation in a complex domain. AIMS Mathematics, 2019, 4(6): 1582-1595. doi: 10.3934/math.2019.6.1582 |
[2] | K. Saritha, K. Thilagavathi . Differential subordination, superordination results associated with Pascal distribution. AIMS Mathematics, 2023, 8(4): 7856-7864. doi: 10.3934/math.2023395 |
[3] | Alina Alb Lupaş, Shujaat Ali Shah, Loredana Florentina Iambor . Fuzzy differential subordination and superordination results for q -analogue of multiplier transformation. AIMS Mathematics, 2023, 8(7): 15569-15584. doi: 10.3934/math.2023794 |
[4] | Georgia Irina Oros, Gheorghe Oros, Daniela Andrada Bardac-Vlada . Certain geometric properties of the fractional integral of the Bessel function of the first kind. AIMS Mathematics, 2024, 9(3): 7095-7110. doi: 10.3934/math.2024346 |
[5] | Alina Alb Lupaş, Georgia Irina Oros . Differential sandwich theorems involving Riemann-Liouville fractional integral of q-hypergeometric function. AIMS Mathematics, 2023, 8(2): 4930-4943. doi: 10.3934/math.2023246 |
[6] | Haiyan Zhou, K. A. Selvakumaran, S. Sivasubramanian, S. D. Purohit, Huo Tang . Subordination problems for a new class of Bazilevič functions associated with k-symmetric points and fractional q-calculus operators. AIMS Mathematics, 2021, 6(8): 8642-8653. doi: 10.3934/math.2021502 |
[7] | Madan Mohan Soren, Luminiţa-Ioana Cotîrlǎ . Fuzzy differential subordination and superordination results for the Mittag-Leffler type Pascal distribution. AIMS Mathematics, 2024, 9(8): 21053-21078. doi: 10.3934/math.20241023 |
[8] | Rabha W. Ibrahim, Dumitru Baleanu . Fractional operators on the bounded symmetric domains of the Bergman spaces. AIMS Mathematics, 2024, 9(2): 3810-3835. doi: 10.3934/math.2024188 |
[9] | Ekram E. Ali, Rabha M. El-Ashwah, R. Sidaoui . Application of subordination and superordination for multivalent analytic functions associated with differintegral operator. AIMS Mathematics, 2023, 8(5): 11440-11459. doi: 10.3934/math.2023579 |
[10] | Shatha S. Alhily, Alina Alb Lupaş . Sandwich theorems involving fractional integrals applied to the q -analogue of the multiplier transformation. AIMS Mathematics, 2024, 9(3): 5850-5862. doi: 10.3934/math.2024284 |
Recently, the combined fractional operator (CFO) is introduced and discussed in Baleanu et al. [
The topic of fractional calculus operators attracts the attention of many investigators to present different types of solutions such as numerical, approximation and analytic solutions for fractional differential equations (see [2,3,4]). The classical fractional calculus' operators, like the Riemann-Liouville, appeared in pure and theoretical studies while some new or modified operators can be useful for applications. The authors of [1] used the conventional differential operators in combination with the operators from Anderson and Ulness [5]. Baleanu et al. established a relation between their operator and the Mittag-Leffler function when they resolved some classes of differential equations. The purpose for which they produced this mixed operator was generating a common operator that permits demonstrating real information from a collection of procedures and systems. Recently, Ibrahim and Jahangiri [6] presented a new fractional differential operator in a complex region. It is an extension of Anderson-Ulness operator into a complex domain as well as of the differential operator of Salagean [7]. Recently, the Srivastava-Owa fractional differential and integral operators are employed in different applications, such as in image processing for denoising [8] and enhance images [9]. Also, the conformable operator is utilized to define a new model of of economic order quantity [10].
In this work, we introduce a generalized fractional operator in a complex domain and study its geometric properties. We employ this operator to define different classes of univalent functions (one-one analytic normalized functions in the complex domain). In addition, we present the operator in some structures of the subordination and superordination inequalities. Finally, as an application, we extend a category of Briot-Bouquet differential equations in a complex region and determine its upper bound solution by utilizing the generalized fractional operator.
In this section, we present the methodology to define the complex CFO.
Let S be the class of analytic functions in the open unit disk ∪:={ξ∈C:|ξ|<1} and S[ϕ,n] be the subclass of S having the function
ϕ(ξ)=ϕ+ϕnξn+ϕn+1ξn+1+..., |
where ϕ,ϕn,ϕn+1,n=1,2,..., are the coefficients constants of the analytic function ϕ(ξ). Let ∧ be the subclass of S indicating the function ϕ(ξ)=ξ+ϕ2ξ2+... (see [11]). Here, we give the definitions of the Riemann-Liouville fractional operators (integral and derivative) in the complex plane C as the following:
Definition 2.1. The integral of arbitrary order ℘,whereℜ{℘}>0 for a function h(ξ), is
I℘ξh(ξ)=(1Γ(℘))(∫ξ0h(ζ)(ξ−ζ)℘−1dζ);ℜ{℘}>0. | (2.1) |
Here, h is in a simply-connected region of (C) having (0,0) and the multiplicity of (ξ−ζ)℘−1 is vanished by indicating log(ξ−ζ) when ℜ(ξ−ζ)>0.
Definition 2.2. The Srivastava and Owa fractional derivative of order 0≤℘<1 (see [12]);
D℘ξh(ξ)=(1Γ(1−℘))ddξ(∫ξ0h(ζ)(ξ−ζ)℘dζ); | (2.2) |
such that h is analytic in a simply-connected region of C involving (0,0) and the multiplicity of (ξ−ζ)−℘ is isolated by using log(ξ−ζ) when ℜ(ξ−ζ)>0.
In our discussion, we deal with the class of analytic functions in the open unit disk H=H(∪). For m a positive integer and a∈C, let
H[a,m]={f∈H,f(ξ)=a+amξm+...}. |
Definition 2.3. Let k=1,2,.... Then for k−1<℘<k and analytic function ϕ(ξ); the Caputo derivative of order ℘ is given by the following construction
CD℘ξh(ξ)={1Γ(k−℘)∫ξ0h(k)(ζ)(ξ−ζ)k−℘−1dζ, ifk−1<℘<k;dndξnh(ξ),if℘=k. | (2.3) |
Where h and its k-derivatives are analytic in simply-connected region in C having the origin and the multiplicity of (ξ−ζ)k−℘−1 is deleted by utilizing log(ξ−ζ) when ℜ(ξ−ζ)>0.
Remark 2.4. The properties of D℘ξh(ξ) and CD℘ξh(ξ) are as follows:
●
D℘ξ(ξ)α=Γ(α+1)Γ(α+1−℘)(ξ)α−℘,I℘ξ(ξ)α=Γ(α+1)Γ(α+1+℘)(ξ)α+℘. |
Moreover, when h(k)(0)=0 for all k=1,2,..., then
D℘ξh(ξ)=CD℘ξh(ξ). |
●
D℘ξh(ξ)=dkdξkIk−℘ξh(ξ). |
●
CD℘ξh(ξ)=Ik−℘ξdkdξkh(ξ). |
Recently, Ibrahim and Jahangiri [6] introduced a definition of a conformable differential operator in a complex domain, specifically for function ϕ∈∧ as follows:
Definition 2.5. Let β be non-negative number and let [[β]] be the integer part of β. For ϕ∈∧, the complex conformable derivative Dβϕ of order β in defined by
Dβϕ(ξ)=Dβ−[[β]](D[[β]]ϕ(ξ))=κ1(β−[[β]],ξ)κ1(β−[[β]],ξ)+κ0(β−[[β]],ξ)(D[[β]]ϕ(ξ))+κ0(β−[[β]],ξ)κ1(β−[[β]],ξ)+κ0(β−[[β]],ξ)(ξ(D[[β]]ϕ(ξ))′), | (2.4) |
where for ℘=β−[[β]] ∈ [0,1),
D0ϕ(ξ)=ϕ(ξ)D℘ϕ(ξ)=κ1(℘,ξ)κ1(℘,ξ)+κ0(℘,ξ)ϕ(ξ)+κ0(℘,ξ)κ1(℘,ξ)+κ0(℘,ξ)(ξϕ′(ξ))D1ϕ(ξ)=ξϕ(ξ)′, ..., D[[℘]]ϕ(ξ)=D(D[[℘]]−1ϕ(ξ)), | (2.5) |
where the functions κ1,κ0:[0,1] ×∪→∪ are analytic in ∪ and thus κ1(℘,ξ)≠−κ0(℘,ξ),
lim℘→0κ1(℘,ξ)=1,lim℘→1κ1(℘,ξ)=0,κ1(℘,ξ)≠0, ∀ξ∈∪, ℘ ∈ (0,1), |
and
lim℘→0κ0(℘,ξ)=0,lim℘→1κ0(℘,ξ)=1,κ0(℘,ξ)≠0, ∀ξ∈∪℘ ∈ (0,1). |
Example 2.6. Let ϕ∈∧ taking the expansion formula ϕ(ξ)=ξ+∑∞n=2ϕnξn then
D℘ϕ(ξ)=κ1(℘,ξ)κ1(℘,ξ)+κ0(℘,ξ)ϕ(ξ)+κ0(℘,ξ)κ1(℘,ξ)+κ0(℘,ξ)(ξϕ′(ξ))=κ1(℘,ξ)κ1(℘,ξ)+κ0(℘,ξ)(ξ+∞∑n=2ϕnξn)+κ0(℘,ξ)κ1(℘,ξ)+κ0(℘,ξ)(ξ+∞∑n=2nϕnξn)=ξ+∞∑n=2(κ1(℘,ξ)+nκ0(℘,ξ)κ1(℘,ξ)+κ0(℘,ξ))ϕnξn. | (2.6) |
Thus, D℘ϕ(ξ)∈∧, whenever, ϕ∈∧. We consider the following functions with fractional indices κ0(℘,ξ)=℘ξ1−℘ and κ1(℘,ξ)=(1−℘)ξ℘ in the sequel.
By using the next property of CD℘ξ, we define the combined operator as follows:
CD℘ξϕ(ξ)=I1−℘ξϕ′(ξ)=1Γ(1−℘)∫ξ0ϕ′(ζ)(ξ−ζ)−℘dζ. |
Now, by replacing the term ϕ′(ξ) by the complex conformable differential operator in (2.5): D℘ϕ(ξ), we receive the following hybrid operator
HD℘ξϕ(ξ)=1Γ(1−℘)∫ξ0(κ1(℘,ζ)κ1(℘,ζ)+κ0(℘,ζ)ϕ(ζ)+κ0(℘,ζ)κ1(℘,ζ)+κ0(℘,ζ)(ζϕ′(ζ)))×(ξ−ζ)−℘dζ. | (2.7) |
A special case of (2.7) can be recognized, when κ1 and κ0 are constants depending on the fractional value ℘. We have the following construction of a linear hybrid operator:
LD℘ξϕ(ξ)=1Γ(1−℘)∫ξ0(κ1(℘)κ1(℘)+κ0(℘)ϕ(ζ)+κ0(℘)κ1(℘)+κ0(℘)(ζϕ′(ζ)))×(ξ−ζ)−℘dζ=(κ1(℘)κ1(℘)+κ0(℘))I1−℘ξϕ(ξ)+(κ0(℘)κ1(℘)+κ0(℘))1Γ(1−℘)∫ξ0(ζϕ′(ζ))(ξ−ζ)−℘dζ=(κ1(℘)κ1(℘)+κ0(℘))I1−℘ξϕ(ξ)+(κ0(℘)κ1(℘)+κ0(℘))1Γ(1−℘)(∫ξ0[(ζϕ(ζ))′−ϕ(ζ))](ξ−ζ)−℘dζ)=(κ1(℘)−κ0(℘)κ1(℘)+κ0(℘))I1−℘ξϕ(ξ)+(κ0(℘)κ1(℘)+κ0(℘))CD℘ξ(ξϕ(ξ)). | (2.8) |
It is clear that LD℘ξϕ(ξ) indicates a linear combination of the Srivastava and Owa integral operator for the analytic normalized function ϕ and the complex Caputo differential operator for ξϕ. For example, when κ1=1−℘ and κ0=℘, we get
LD℘ξϕ(ξ)=(1−2℘)I1−℘ξϕ(ξ)+℘CD℘ξ(ξϕ(ξ)). |
Remark 2.7. ● The operators HD℘ξ and LD℘ξ are non-local singular operators where they involve the kernel term (ξ−ζ)−℘. Therefore, every analytic univalent function ϕ admits integrable singularity when ξ=ζ of the integral, since ℘∈(0,1).
● The endpoint limits when ℘∈[0,1] satisfies
lim℘→0HD℘ξϕ(ξ)=lim℘→0LD℘ξϕ(ξ)=∫ξ0ϕ(ζ)dζ; |
lim℘→1HD℘ξϕ(ξ)=lim℘→1LD℘ξϕ(ξ)=(ξϕ(ξ))′−I1−℘ξϕ(ξ). |
Theorem 2.8. Let ϕ∈∧. Then the operator Ω℘ϕ∈∧, where
Ω℘ϕ(ξ):=Γ(3−℘)(LD℘ξϕ(ξ)ξ1−℘). |
Proof. For ϕ∈∧ and by using Remark 2.4 and Eq (2.8), we have
Γ(3−℘)(LD℘ξϕ(ξ)ξ1−℘)=Γ(3−℘)(I1−℘ξ(κ1(℘)κ1(℘)+κ0(℘)ϕ(ζ)+κ0(℘)κ1(℘)+κ0(℘)(ζϕ′(ζ)))ξ1−℘)=Γ(3−℘)(I1−℘ξ(ξ+∑∞n=2Kn(℘)ϕnξn)ξ1−℘)=Γ(3−℘)(Γ(2)Γ(3−℘)ξ1+1−℘+∑∞n=2Kn(℘)ϕnΓ(n+1)Γ(n+2−℘)ξn+1−℘ξ1−℘)=ξ+∞∑n=2Kn(℘)ϕn(Γ(3−℘)Γ(n+1)Γ(n+2−℘))ξn, | (2.9) |
where Kn(℘):=(κ1(℘)+nκ0(℘)κ1(℘)+κ0(℘)). Hence, Ω℘∈∧.
Remark 2.9 ● Note that when ℘→1, we have
Ωϕ(ξ)=(LDξϕ(ξ)). |
Consequently, we get the following expansion
Ωϕ(ξ)=ξ+∞∑n=2nϕnξn, |
which is reduced to the well-known Salagean operator. Therefore, one can generalize the Salagean classes of analytic functions [13,14,15] by utilizing the fractional operator Ω℘.
● The fractional operator Ω℘ acts on the convex function ϕ(ξ)=ξ/(1−ξ) as follows:
Ω℘ϕ(ξ)=ξ+∞∑n=2Kn(℘)(Γ(3−℘)Γ(n+1)Γ(n+2−℘))ξn. |
If Kn(℘)≤(Γ(3−℘)Γ(n+1)Γ(n+2−℘)),∀n≥2, then Ω℘ϕ(ξ) is also convex in ∪.
Next part of this paper indicates some classes of analytic univalent functions involving the operator Ω℘.
In this section, we aim to investigate the geometric properties of the operator Ω℘. For this purpose, we need the following definitions from the geometric function theory:
A function ϕ∈∧ is starlike through the origin if the linear slice linking the origin to all added point of ϕ deceits completely in ϕ(ξ:|ξ|<1). A univalent function (injective function of a complex variable) ϕ is convex in ∪ if the linear slice linking every two points of ϕ(ξ:|ξ|<1) sets wholly in ϕ(ξ:|ξ|<1). We denote these classes by S∗ and C for starlike and convex correspondingly. Next, we assume that the class P includes all mappings ψ analytic in ∪ with a positive real part in ∪ realizing ψ(0)=1,ψ′(0)>0. Consistently, ϕ∈S∗⇔ξϕ′(ξ)/ϕ(ξ) ∈ P and ϕ∈C⇔1+ξϕ″(ξ)/ϕ′(ξ) ∈ P. Consistently, ℜ(ξϕ′(ξ)/ϕ(ξ))>0 for the starlikeness and ℜ(1+ξϕ″(ξ)/ϕ′(ξ))>0 for the convexity.
Let f and g be analytic functions in ∪. The function f is said to be subordinate to g, written f≺g or f(ξ)≺g(ξ), if there exists a function ω analytic in ∪, with ω(0)=0 and |ω(ξ)|<1, and such that f(ξ)=g(ω(ξ)). If g is univalent, then f≺g if and only if f(0)=g(0) and f(∪)⊂g(∪) (see[16]).
Linking the definitions of starlike and convex function in the subordination concept, Ma and Minda [17] formulated the next sub-classes
ξϕ′(ξ)ϕ(ξ)≺⋎(ξ),⋎∈P |
and
1+ξϕ″(ξ)ϕ′(ξ)≺⋏(ξ),⋏∈P. |
We request the following result [18]:
Lemma 3.1. Suppose that h,ℏ∈∪, then the subordination h≺ℏ yields
∫2π0|h(ζ)|pdθ≤∫2π0|ℏ(ζ)|pdθ, | (3.1) |
where ζ=reiθ,r∈(0,1) and p∈R+.
Definition 3.2. Let ℘∈[0,1]. A function ϕ∈∧ is in the class S∗℘(σ) if and only if
ξ(Ω℘ϕ(ξ))′Ω℘ϕ(ξ)≺ω(ξ),ξ∈∪, |
where ω is univalent function with a positive real part in ∪ achieving
ω(0)=1,ℜ(ω′(ξ))>0. |
Theorem 3.3. Let ϕ∈∧ and ℘∈[0,1]. If ϕ∈C (the class of convex functions in the open unit disk) then
|Ω℘ϕ(ξ)|≤r(rF(1,2;3−℘;r))′, | (3.2) |
where F is Gauss hypergeometric function. The equality occurs for the Koebe function of the first type K(ξ)=ξ/(1−ξ),ξ∈∪.
Proof. Let ϕ∈C then the coefficients satisfy |ϕn|<1 for all n. Moreover, we have the following limit
lim℘→1Kn(℘)=lim℘→1(κ1(℘)+nκ0(℘)κ1(℘)+κ0(℘))=n. |
A calculation implies
|Ω℘ϕ(ξ)|=|∞∑n=1Kn(℘)ϕn(Γ(3−℘)Γ(n+1)Γ(n+2−℘))ξn|≤Γ(3−℘)∞∑n=1n(Γ(n+1)Γ(n+2−℘))rn=Γ(3−℘)r∞∑n=0(n+1)(Γ(n+2)Γ(n+3−℘))rn=Γ(3−℘)r∞∑n=0(Γ(n+2)Γ(n+1)Γ(n+3−℘))(n+1)rnn!=Γ(3−℘)rΓ(3−℘)∞∑n=0((1)n(2)n(3−℘)n)(n+1)rnn!=r∞∑n=0((1)n(2)n(3−℘)n)(n+1)rnn!=r(rF(1,2;3−℘;r))′, |
where (b)n=Γ(b+n)Γ(b) is the Pochhammer symbol. Lastly, by assuming the Koebe function K(ξ), with ϕn=1 in the above conclusion, we have the sharp result.
Theorem 3.4. Let ϕ∈∧ and ℘∈[0,1]. If ϕ is univalent in ∪ then
|Ω℘ϕ(ξ)|≤r(rF(2,2;3−℘;r))′, | (3.3) |
where F is Gauss hypergeometric function. The equality occurs for the Koebe function of the second type K(ξ)=ξ/(1−ξ)2,ξ∈∪.
Proof. Let ϕ univalent in ∪ then by De Branges' Theorem, the coefficients satisfy |ϕn|<n for all n. Moreover, we have the following limit lim℘→1Kn(℘)=n. A calculation implies
|Ω℘ϕ(ξ)|=|∞∑n=1Kn(℘)ϕn(Γ(3−℘)Γ(n+1)Γ(n+2−℘))ξn|≤Γ(3−℘)∞∑n=1n2(Γ(n+1)Γ(n+2−℘))rn=Γ(3−℘)r∞∑n=0(n+1)2(Γ(n+2)Γ(n+3−℘))rn=Γ(3−℘)r∞∑n=0(Γ(n+2)(n+1)Γ(n+1)Γ(n+3−℘))(n+1)rnn!=Γ(3−℘)r∞∑n=0(Γ(n+2)Γ(n+2)Γ(n+3−℘))(n+1)rnn!=Γ(3−℘)rΓ(3−℘)∞∑n=0((2)n(2)n(3−℘)n)(n+1)rnn!=r∞∑n=0((2)n(2)n(3−℘)n)(n+1)rnn!=r(rF(2,2;3−℘;r))′. |
By replacing the Koebe function K(ξ), with ϕn=n in the above conclusion, we can receive the sharp outcome.
Theorem 3.5. Let ϕ∈∧ and Θ(ξ) is univalent convex in ∪ achieving the subordination inequality
ξ(Ω℘ϕ(ξ))′Ω℘ϕ(ξ)≺Θ(ξ). | (3.4) |
Then
Ω℘ϕ(ξ)≺ξexp(∫ξ0Θ(ϑ(ι))−1ιdι), | (3.5) |
where ϑ(ξ) is analytic in ∪, with ϑ(0)=0, |ϑ(ξ)|<1 and it is the upper limit in the above integral. Furthermore, for |ξ|=ι, Ω℘ϕ(ξ) fulfills the formula
exp(∫10Θ(ϑ(−ι))−1ιdι)≤|Ω℘ϕ(ξ)ξ|≤exp(∫10Θ(ϑ(ι))−1ιdι). |
Proof. In view of the definition of the subordination, there occurs a Schwarz map with ϑ(0)=0 and |ϑ(ξ)|<1 satisfying
ξ(Ω℘ϕ(ξ))′Ω℘ϕ(ξ)=Θ(ϑ(ξ)),ξ∈∪. |
This implies that
(Ω℘ϕ(ξ))′Ω℘ϕ(ξ)−1ξ=Θ(ϑ(ξ))−1ξ. |
Integrate both sides, we have
logΩ℘ϕ(ξ)−logξ=∫ξ0Θ(ϑ(ι))−1ιdι. |
A computation yields
log(Ω℘ϕ(ξ)ξ)=∫ξ0Θ(ϑ(ι))−1ιdι. | (3.6) |
Then, for some Schwarz function, we get the inequality
Ω℘ϕ(ξ)≺ξexp(∫ξ0Θ(ϑ(ι))−1ιdι). |
Moreover, Θ maps the disk 0<|ξ|<ι<1 onto a territory which is symmetric convex w.r.t x-axis, which means
Θ(−ι|ξ|)≤ℜ(Θ(ϑ(ιξ)))≤Θ(ι|ξ|),ι∈(0,1), |
therefore, we have the relations
Θ(−ι)≤Θ(−ι|ξ|),Θ(ι|ξ|)≤Θ(ι). |
By using the above relations, we conclude that
∫10Θ(Ψ(−ι|ξ|))−1ιdι≤ℜ(∫10Θ(ϑ(ι))−1ιdι)≤∫10Θ(ϑ(ι|ξ|))−1ιdι, |
which implies that
∫10Θ(ϑ(−ι|ξ|))−1ιdι≤log|Ω℘ϕ(ξ)ξ|≤∫10Θ(ϑ(ι|ξ|))−1ιdι, |
and
exp(∫10Θ(ϑ(−ι|ξ|))−1ιdι)≤|Ω℘ϕ(ξ)ξ|≤exp(∫10Θ(ϑ(ι|ξ|))−1ιdι). |
We indicate that
exp(∫10Θ(ϑ(−ι))−1ιdι)≤|Ω℘ϕ(ξ)ξ|≤exp(∫10Θ(ϑ(ι))−1ιdι). |
Theorem 3.6. Suppose that ϕ∈∧ with non-negative connections and ℘∈[0,1]. If Θ is univalent convex in ∪, then there is a solution satisfying
Ω℘ϕ(ξ)≺ξexp(∫ξ0Θ(ϑ(ι))−1ιdι), | (3.7) |
where ϑ(ξ) is analytic in ∪, with ϑ(0)=0 and |ϑ(ξ)|<1.
Proof. We check the following formula for the real parts:
ℜ(ξ(Ω℘ϕ(ξ))′Ω℘ϕ(ξ))>0⇔ℜ(ξ+∞∑n=2nKn(℘)ϕn(Γ(3−℘)Γ(n+1)Γ(n+2−℘))ξnξ+∞∑n=2Kn(℘)ϕn(Γ(3−℘)Γ(n+1)Γ(n+2−℘))ξn)>0⇔ℜ(1+∞∑n=2nKn(℘)ϕn(Γ(3−℘)Γ(n+1)Γ(n+2−℘))ξn−11+∞∑n=2Kn(℘)ϕn(Γ(3−℘)Γ(n+1)Γ(n+2−℘))ξn−1)>0⇔ℜ(1+∞∑n=2nKn(℘)(Γ(3−℘)Γ(n+1)Γ(n+2−℘))ϕn1+∞∑n=2Kn(℘)(Γ(3−℘)Γ(n+1)Γ(n+2−℘))ϕn)>0,ξ→1⇔(1+∞∑n=2nKn(℘)(Γ(3−℘)Γ(n+1)Γ(n+2−℘))ϕn)>0. |
Moreover, we indicate that (Ω℘ϕ(0)=0, which yields
ξ(Ω℘ϕ(ξ))′Ω℘ϕ(ξ)∈P. |
Hence, according to Theorem 3.4, we have (3.7).
Example 3.7. In this example, we illustrate some special forms of Θ when μ∈[0,1].
(1) Θ(ξ)=μ+(1−μ)√1+ξ,
(2) Θ(ξ)=μ+(1−μ)eξ,
(3) Θ(ξ)=μ+(1−μ)(1+sin(ξ)),
(4) Θ(ξ)=μ+(1−μ)eeξ−1.
Then in view of Theorem 3.5, the subordination ξ(Ω℘ϕ(ξ))′Ω℘ϕ(ξ)≺Θ(ξ) implies
Ω℘ϕ(ξ)≺ξexp(∫ξ0Θ(ϑ(ι))−1ιdι). |
For Θ(ξ)=μ+(1−μ)√1+ξ,μ=0, we have
Ω℘ϕ(ξ)≺e(2√ξ+1)(1−√ξ+1)(√ξ+1+1). |
Moreover, for Θ(ξ)=μ+(1−μ)(1+sin(ξ)),μ=0, we obtain
Ω℘ϕ(ξ)≺ξ+ξ2+ξ3/2+ξ4/9−ξ5/72+O(ξ6). |
Remark 3.8. If ℘=μ=0 in Example 3.7, we have the sub-classes in [13,14,15] respectively.
Theorem 3.9. Let ϕ∈∧ be convex univalent in ∪ and ℘∈[0,1]. Then
∫2π0|Ω℘ϕ(ξ)|pdθ≤∫2π0|ξ(1+ξ1−ξ)δ|pdθ,p>0 | (3.8) |
and
∫2π0|(Ω℘ϕ(ξ))′|pdθ≤∫2π0|(1+ξ1−ξ)δ|pdθ,p>0, | (3.9) |
where (1+ξ1−ξ)δ is the Janowski function of order δ≥1.
Proof. Let
σ(ξ,δ)=ξ(1+ξ1−ξ)δ,ζ∈∪,δ≥1. | (3.10) |
Then, a computation implies that
σ(ζ,1)=ξ+2ξ2+2ξ3+2ξ4+2ξ5+2ξ6+O(ξ7)σ(ξ,2)=ξ+4ξ2+8ξ3+12ξ4+16ξ5+20ξ6+...σ(ξ,3)=ξ+6ξ2+18ξ3+38ξ4+....σ(ξ,4)=ξ+8ξ2+16ξ3+24ξ4+....⋮ |
Since ϕ(ξ) is convex then its coefficients satisfy the inequality |ϕn|≤1 for all n and lim℘→0Kn(℘)=1, and
lim℘→0Γ(2+℘)Γ(n+1)Γ(n+1+℘)=1. |
Moreover, the coefficients of Ω℘ achieve the inequality
|Kn(℘)ϕn(Γ(3−℘)Γ(n+1)Γ(n+2−℘))|≤1. | (3.11) |
Which means that Ω℘ϕ(ξ) is majorized by the function σ(ξ,δ) for all δ≥1. By the properties of majority [19], we obtain
Ω℘ϕ(ξ)≺σ(ξ,δ),ξ∈∪. | (3.12) |
Thus, according to Lemma 3.1, we conclude that
∫2π0|Ω℘ϕ(ξ)|pdθ≤∫2π0|ξ(1+ξ1−ξ)δ|pdθ,p>0. |
Similarly for the (Ω℘)′ we have
∫2π0|(Ω℘ϕ(ξ))′|pdθ≤∫2π0|(1+ξ1−ξ)δ|pdθ,p>0. |
Remark 3.10. The condition on ϕ which is convex univalent in ∪, can be replaced by the following condition
|ϕn|≤|(Γ(n+2−℘)Kn(℘)Γ(3−℘)Γ(n+1))|; |
or ϕ is univalent then |ϕ|≤n and δ≥2.
In this part, we focus on the integral operator Υ℘ϕ(ξ),ϕ∈∧, corresponding to the operator Ω℘ϕ(ξ). The formula of Υ℘ϕ(ξ) is given by the expansion
Υ℘ϕ(ξ)=∞∑n=1ϕn(Γ(n+2−℘)Kn(℘)Γ(3−℘)Γ(n+1))ξn,ϕ1=1. | (3.13) |
Definition 3.11. The Hadamard product of two functions ρ1 and ρ2∈∧ is defined by the formula:
ρ1(ξ)∗ρ2(ξ)=(ξ+∞∑n=2anξn)∗(ξ+∞∑n=2bnξn)=(ξ+∞∑n=2anbnξn),ξ∈∪. | (3.14) |
Definition 3.12. The Mittag-Leffler function Ξa,b is an entire function defined by the series
Ξa,b(ξ)=∞∑n=0ξnΓ(an+b),a>0, |
where Γ(θ) is the gamma function.
We have the following propositions.
Proposition 3.13. Let ϕ∈∧ and ℘∈[0,1]. Then
(Ω℘∗Υ℘)∗ϕ(ξ)=(Υ℘∗Ω℘)∗ϕ(ξ)=ϕ(ξ),ξ∈∪. |
Proof. By applying the Hadamard product definition, we have
(Ω℘∗Υ℘)∗ϕ(ξ)=(∞∑n=1Kn(℘)(Γ(3−℘)Γ(n+1)Γ(n+2−℘))ξn)∗(∞∑n=1(Γ(n+2−℘)Kn(℘)Γ(3−℘)Γ(n+1))ξn)∗ϕ(ξ)=(∞∑n=1(Γ(n+2−℘)Kn(℘)Γ(3−℘)Γ(n+1))ξn)∗(∞∑n=1Kn(℘)(Γ(3−℘)Γ(n+1)Γ(n+2−℘))ξn)∗ϕ(ξ)=(Υ℘∗Ω℘)∗ϕ(ξ)=(∞∑n=1ξn)∗ϕ(ξ)=ϕ(ξ). |
Proposition 3.14. Let ϕ∈∧ and ℘∈[0,1]. Then
Ω℘ϕ(ξ)=ψ1(ξ)∗Ξ1,(1+℘)∗ϕ(ξ) |
and
Υ℘ϕ(ξ)=ψ2(ξ)∗Ξ1,1∗ϕ(ξ), |
where Ξa,b indicates the Mittag-Leffler function and
ψ1(ξ)=∞∑n=0Kn(℘)Γ(3−℘)Γ(n+1)ξn |
and
ψ2(ξ)=∞∑n=1(Γ(n+2−℘)Kn(℘)Γ(3−℘))ξn. |
Proof. Let ϕ∈∧ such that ϕ0=0 and ϕ1=1. Thus, we have
Ω℘ϕ(ξ)=∞∑n=0Kn(℘)ϕn(Γ(3−℘)Γ(n+1)Γ(n+2−℘))ξn=(∞∑n=0Kn(℘)Γ(3−℘)Γ(n+1)ξn)∗(∞∑n=0ξnΓ(n+2−℘))∗(∞∑n=0ϕnξn)=ψ1(ξ)∗Ξ1,(1+℘)∗ϕ(ξ). |
Now, for the integral Υ℘, we have
Υ℘ϕ(ξ)=∞∑n=1ϕn(Γ(n+2−℘)Kn(℘)Γ(3−℘)Γ(n+1))ξn=(∞∑n=1(Γ(n+2−℘)Kn(℘)Γ(3−℘))ξn)∗(∞∑n=0ξnΓ(n+1))∗(∞∑n=0ϕnξn)=ψ2(ξ)∗Ξ1,1∗ϕ(ξ). |
Theorem 3.15. Let ϕ∈∧ and ℘∈[0,1]. If ϕ is univalent then
|Υ℘ϕ(ξ)|≤rF(1,(3−℘);2;r),r<1. | (3.15) |
Proof. Likely of Theorem 3.3 and for a univalent function ϕ, we have
|Υ℘ϕ(ξ)|=|∞∑n=1ϕn(Γ(n+2−℘)Kn(℘)Γ(3−℘)Γ(n+1))ξn|≤1Γ(3−℘)∞∑n=1(nΓ(n+2−℘)nΓ(n+1))rn=rΓ(3−℘)∞∑n=0(Γ(n+1)Γ(n+3−℘)Γ(n+2))rnn!=r∞∑n=0((1)n(3−℘)n(2)n)rnn!=rF(1,(3−℘);2;r),r<1. |
Note that, when ϕ∈∧ is convex, then we obtain the same result in Theorem 3.15.
We considered two fractional operators (differential and integral) in the open unit disk. We showed that these operators are preserving the normalized class (h(0)=h′(0)−1=0). We proved that the fractional operators are bounded by the Gauss hypergeometric function and they are represented by a convoluted formula with the Mittag-Leffler functions. We indicated that the differential operator LD℘ξϕ(ξ) is a linear combination of the Srivastava-Owa differential operator for the analytic normalized function ϕ and the complex Caputo differential operator for ξϕ. For future work, one can suggest the mixed conformable operators in other classes of analytic functions like the multi-valent and harmonic classes.
The authors wish to express their profound gratitude to the anonymous referees for their careful reading of the manuscript and the very useful comments that have been implemented in the final version of the manuscript.
The authors declare no conflict of interest.
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