
The upper bounds for the powers of the iteration matrix derived via a numerical method are intimately related to the stability analysis of numerical processes. In this paper, we establish upper bounds for the norm of the nth power of the iteration matrix derived via a fourth-order compact θ-method to obtain the numerical solutions of delay parabolic equations, and thus present conclusions about the stability properties. We prove that, under certain conditions, the numerical process behaves in a stable manner within its stability region. Finally, we illustrate the theoretical results through the use of several numerical experiments.
Citation: Lili Li, Boya Zhou, Huiqin Wei, Fengyan Wu. Analysis of a fourth-order compact θ-method for delay parabolic equations[J]. Electronic Research Archive, 2024, 32(4): 2805-2823. doi: 10.3934/era.2024127
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The upper bounds for the powers of the iteration matrix derived via a numerical method are intimately related to the stability analysis of numerical processes. In this paper, we establish upper bounds for the norm of the nth power of the iteration matrix derived via a fourth-order compact θ-method to obtain the numerical solutions of delay parabolic equations, and thus present conclusions about the stability properties. We prove that, under certain conditions, the numerical process behaves in a stable manner within its stability region. Finally, we illustrate the theoretical results through the use of several numerical experiments.
Mathematical models for the spread of epidemic infectious diseases in populations have been studied for a long time [1]. One of the most classical epidemic models is the SIR epidemic model in which the total population is divided into three classes called susceptible, infected and removed [2]. Some types of SIR epidemic models without age structure are nonlinear systems of ordinary differential equations, and it is relatively easy to show that the long time behavior of its solution is completely determined by a threshold value
Some types of SIR epidemic models with age structure are nonlinear systems of partial differential equations, and the mathematical analysis for them is generally more difficult than that for the models without age structure. The most classical SIR epidemic model studied by Kermack and McKendrick [2] has the structure of infection age (time elapsed since the infection), and the complete global stability analysis for an infection age-structured SIR epidemic model was recently done by Magal et al, [5]. That is, they showed that the disease-free equilibrium in their model is globally asymptotically stable if
In basic epidemic models, the incidence rate is often assumed to take the bilinear form such as
In [27], Bentout and Touaoula established an infection age-structured SIR epidemic model with a general incidence rate. They proved for their model that if
The organization of this paper is as follows. In Section 2, we establish our main model. In Section 3, we define the basic reproduction number
Let
{dS(t)dt=A−μS(t)−f(S(t),J(t)),∂i(t,a)∂t+∂i(t,a)∂a=−(μ+θ(a))i(t,a),a>0,i(t,0)=f(S(t),J(t))+k∫+∞0θ(a)i(t,a)da+δR(t),dR(t)dt=(1−k)∫+∞0θ(a)i(t,a)da−(μ+δ)R(t), | (2.1) |
where
J(t)=∫+∞0β(a)i(t,a)da,t>0. |
The system (2.1) is completed by the following boundary and initial conditions,
{i(0,⋅)=i0(⋅)∈L1(R+,R+),S(0)=S0∈R+andR(0)=r0∈R+. | (2.2) |
For instance, diseases with relapse such as herpes simplex virus type 2 (HSV-2) [28] can be modeled by system (2.1). Throughout this paper, we make the following hypotheses on
● The function
● The parameters
The boundedness of
● (H0) The function
● (H1) For all
● (H2) The function
● (H3) The function
|f(S2,J2)−f(S1,J1)|≤L(|S2−S1|+|J2−J1|), | (2.3) |
whenever
Now, let us define the functional space
‖(S,i,R)‖X=|S|+∫+∞0|i(a)|da+|R|,S,R∈R,i∈L1(R+). |
We put
Theorem 2.1. Let consider an initial condition belonging to
We omit the proof of Theorem 2.1 as it is similar to the proof of [27,Theorem 2.2] except for a simple modification. We set,
N′(t)=A−μN(t). |
So, for
N(t)≤max{N(0),Aμ}, |
with
limt→+∞N(t)=Aμ. | (2.4) |
On the other hand, we can check that (
lim inft→+∞S(t)≥Aμ+L. |
In this section, we show the local and the global stability of the disease-free equilibrium. First, we begin by studying the local stability. We denote by
π(a)=e−∫a0(μ+θ(s))ds,a≥0. | (3.1) |
We can estimate the basic reproduction number by renewal process, which is the spectral radius of the next generation matrix. For more details, we refer the reader to [3]. The basic reproduction number
R0=∂f∂J(Aμ,0)∫+∞0β(a)π(a)da+((1−k)δμ+δ+k)∫+∞0θ(a)π(a)da. |
For the system (2.1), it is easy to see that the disease-free steady state always exists and it is given by
{dS(t)dt=−μS(t)−S(t)∂f∂S(Aμ,0)−J(t)∂f∂J(Aμ,0),∂i(t,a)∂t+∂i(t,a)∂a=−(μ+θ(a))i(t,a),a>0,i(t,0)=S(t)∂f∂S(Aμ,0)+J(t)∂f∂J(Aμ,0)+k∫+∞0θ(a)i(t,a)da+δR(t),dR(t)dt=(1−k)∫+∞0θ(a)i(t,a)da−(μ+δ)R(t). | (3.2) |
Next, the characteristic equation of (3.2) at
|λ+μ+∂f∂S(Aμ,0)P(λ)0−∂f∂S(Aμ,0)Q(λ)−δ0G(λ)λ+μ+δ|=0, |
where
P(λ):=∂f∂J(Aμ,0)∫+∞0β(a)π(a)e−λada, |
Q(λ):=1−∂f∂J(Aμ,0)∫+∞0β(a)π(a)e−λada−k∫+∞0θ(a)π(a)e−λada, |
and
G(λ):=−(1−k)∫+∞0θ(a)π(a)e−λada. |
We have the following theorem.
Theorem 3.1. If
Proof. The characteristic equation of the disease free equilibrium
(λ+μ)H(λ)=0, | (3.3) |
where
H(λ)=(λ+μ+δ)(1−∂f∂J(Aμ,0)∫+∞0β(a)π(a)e−λada−k∫+∞0θ(a)π(a)e−λada)−δ(1−k)∫+∞0θ(a)π(a)e−λada. |
Obviously, we can see that
|λ0+μ+δ|=|δ(1−k)∫+∞0θ(a)π(a)e−λ0ada1−∫+∞0β(a)π(a)e−λ0ada∂f∂J(Aμ,0)−k∫+∞0θ(a)π(a)e−λ0ada|. |
Since
μ+δ≤|δ(1−k)∫+∞0θ(a)π(a)e−λ0ada||1−∫+∞0β(a)π(a)e−λ0ada∂f∂J(Aμ,0)−k∫+∞0θ(a)π(a)e−λ0ada|. |
Then,
δ(1−k)μ+δ|∫+∞0θ(a)π(a)e−λ0ada|≥1−|∫+∞0β(a)π(a)e−λ0ada∂f∂J(Aμ,0)−k∫+∞0θ(a)π(a)e−λ0ada|,≥1−|∫+∞0β(a)π(a)e−λ0ada∂f∂J(Aμ,0)|−k|∫+∞0θ(a)π(a)e−λ0ada|. |
Therefore,
R0≥|∫+∞0β(a)π(a)e−λ0ada∂f∂J(Aμ,0)|+(k+δ(1−k)μ+δ)|∫+∞0θ(a)π(a)e−λ0ada|≥1. |
We obtain that
H(0)=(μ+δ)(1−R0)<0andlimλ→+∞H(λ)=+∞. |
This ensures to the existence of a positive real root of (3.3). Hence,
Now, we focus on the global stability of
dˆi(h)dh=−[μ+ˆθ(h)]ˆi(h). |
Hence,
i(t+h,a+h)=i(t,a)e−∫h0(μ+θ(a+s))ds. |
Considering two cases
i(t,a)={i(t−a,0)e−∫a0(μ+θ(s))ds,a<t,i(0,a−t)e−∫t0(μ+θ(a−t+s))ds,a≥t. |
Hence, we obtain
i(t,a)={π(a)B(t−a),a<t,π(a)π(a−t)i0(a−t),a≥t, | (3.4) |
with
B(t)=f(S(t),J(t))+k∫t0θ(a)π(a)B(t−a)da+∫∞tθ(a)π(a)π(a−t)i0(a−t)da+δR(t), | (3.5) |
J(t)=∫t0β(a)π(a)B(t−a)da+∫∞tβ(a)π(a)π(a−t)i0(a−t)da, | (3.6) |
and
R′(t)=(1−k)∫t0θ(a)π(a)B(t−a)da+(1−k)∫∞tθ(a)π(a)π(a−t)i0(a−t)da−(μ+δ)R(t). | (3.7) |
We prove the following theorem.
Theorem 3.2. The disease-free equilibrium
Proof. It suffices to prove the global attractivity of
lim supt→+∞(S(t),B(t),R(t))=(S∞,B∞,R∞)andlim supt→+∞J(t)=J∞. |
By using the fluctuation lemma (see [37], Lemma A.14), there exist
R∞≤(1−k)∫+∞0θ(a)π(a)daμ+δB∞. | (3.8) |
Similarly using (3.5), (3.6) and the hypothesis (H0), we obtain
{B∞≤f(S∞,J∞)+kB∞∫+∞0θ(a)π(a)da+δR∞,J∞≤B∞∫+∞0β(a)π(a)da. | (3.9) |
Now, combining (3.8), (3.9) and the fact that
B∞≤f(S∞,J∞)+kB∞∫+∞0θ(a)π(a)da+δ(1−k)∫+∞0θ(a)π(a)daμ+δB∞. |
Since
B∞≤f(Aμ,J∞)+kB∞∫+∞0θ(a)π(a)da+δ(1−k)∫+∞0θ(a)π(a)daμ+δB∞. | (3.10) |
Next, from (H1), we easily obtain
f(Aμ,J∞)≤J∞∂f∂J(Aμ,0). | (3.11) |
By combining (3.10) with (3.11) and the second equation of (3.9), we get
B∞≤R0B∞. |
Since
In this section, we prove the existence of a compact attractor of all bounded subset of
Φ(t,(S0,i0(⋅),r0))=(S(t),i(t,⋅),R(t)),(S0,i0(⋅),r0)∈X+, | (4.1) |
which is generated by the unique solution of system (2.1). So, it is not difficult to show that this semiflow is continuous.
Theorem 4.1. The semiflow
Proof. Following Theorem 2.33 in [37], we need to check some properties of the semiflow
Ψ1(t,(S0,i0(⋅),r0))=(0,u(t,⋅),0) and Ψ2(t,(S0,i0(⋅),r0))=(S(t),v(t,⋅),R(t)), |
where
u(t,a)={0,a<t,π(a)π(a−t)i0(a−t),a>t, |
and
v(t,a)={π(a)B(t−a),a<t,0,a>t. |
Let
M1:=sup{S0+‖i0‖L1+r0,(S0,i0,r0)∈C} and M2:=max{M1,Aμ}. | (4.2) |
Using the same arguments as in Theorem 2.1 in [18], we have
∫+∞0|v(t,a+h)−v(t,a)|da=∫t−h0|π(a+h)B(t−a−h)−π(a)B(t−a)|da+∫tt−h|π(a)B(t−a)|da. | (4.3) |
Notice that, for
|B(t)|≤f(S(t),J(t))+k∫+∞0θ(a)i(t,a)da+δR(t),≤f(M2,‖β‖∞M2)+k‖θ‖∞M2+δM2, | (4.4) |
for all initial data in
Ih(t):=∫t−h0|π(a+h)B(t−a−h)−π(a)B(t−a)|da,≤∫t−h0|π(a)(B(t−a−h)−B(t−a))|da+∫t−h0|B(t−a−h)(π(a+h)−π(a)|da. | (4.5) |
From the system (2.1) and (4.2), we have, for
|S′(t)|≤A+μM2+f(M2,‖β‖∞M2), | (4.6) |
and
|R′(t)|≤(1−k)‖θ‖∞M2+(μ+δ)M2. | (4.7) |
Now, let us define
Ah(t,a):=|B(t−a−h)−B(t−a)|≤|f(S(t−a−h),J(t−a−h))−f(S(t−a),J(t−a))|+k|∫+∞0θ(σ)i(t−a−h,σ)dσ−∫+∞0θ(σ)i(t−a,σ)dσ|+δ|R(t−a−h)−R(t−a)|. |
Using the fact that the function
Ah≤L|S(t−a−h)−S(t−a)|+L|J(t−a−h)−J(t−a))|+k|∫+∞0θ(σ)i(t−a−h,σ)dσ−∫+∞0θ(σ)i(t−a,σ)dσ|+δ|R(t−a−h)−R(t−a)|. |
By (4.6) and (4.7), we can easily show that the first and the last term of
A1h(t,a):=L|J(t−a−h)−J(t−a)|+k|∫+∞0θ(σ)i(t−a−h,σ)dσ−∫+∞0θ(σ)i(t−a,σ)dσ|. | (4.8) |
For
J1(t)=∫t0β(a)π(a)f(S(t−a),J(t−a))daandJ2(t)=∫+∞0β(a+t)π(a+t)π(a)i0(a)da. | (4.9) |
Thus, for
|J(s+h)−J(s)|≤|J1(s+h)−J1(s)|+|J2(s+h)−J2(s)|. |
After a change of variable in (4.9), we obtain
J1(t)=∫t0β(t−σ)π(t−σ)f(S(σ),J(σ))dσ. |
Therefore, for
|J1(s+h)−J1(s)|≤∫s+hsβ(s+h−σ)π(s+h−σ)f(S(σ),J(σ))dσ+∫s0|β(s+h−σ)π(s+h−σ)−β(s−σ)π(s−σ)|f(S(σ),J(σ))dσ,≤‖β‖∞f(M2,‖β‖∞M2)h+f(M2,‖β‖∞M2)∫s0|β(s+h−σ)π(s+h−σ)−β(s−σ)π(s−σ)|dσ. |
Consequently, we can readily checked that these last terms tend to
|J2(s+h)−J2(s)|≤|∫+∞0β(a+s+h)π(a+s+h)π(a)i0(a)da−∫+∞0β(a+s)π(a+s)π(a)i0(a)da|,≤∫+∞0|β(a+s+h)−β(a+s)|π(a+s)π(a)i0(a)da+∫+∞0β(a+s+h)i0(a)|π(a+s+h)π(a)−π(a+s)π(a)|da. |
Using the fact that
|∫+∞0θ(σ)i(t−a−h,σ)dσ−∫+∞0θ(σ)i(t−a,σ)dσ|→0, |
as
Next, we describe the total trajectories of system (2.1). Let
{S′(t)=A−μS−f(S(t),J(t)),i(t,a)=π(a)B(t−a),B(t)=f(S(t),J(t))+k∫+∞0θ(a)i(t,a)da+δR(t),R′(t)=(1−k)∫+∞0θ(a)i(t,a)da−(μ+δ)R(t),J(t)=∫+∞0β(a)π(a)B(t−a)da. | (4.10) |
The following lemma gives some estimates on the total trajectories.
Lemma 4.2. For all
S(t)>Aμ+L,S(t)+∫+∞0i(t,a)da+R(t)≤Aμandi(t,a)≤ξπ(a),a≥0. |
with
Proof. We set,
I(t):=∫+∞0i(t,a)da=∫+∞0π(a)B(t−a)da. |
After a change of variable, for
I(t)=∫t−∞π(t−a)B(a)da. |
By differentiating
I′(t)=B(t)−∫+∞0(μ+θ(a))π(a)B(t−a)da. |
Combining this equation with the system (4.10), we obtain,
S′(t)+I′(t)+R′(t)≤A−μ(S(t)+I(t)+R(t)), |
Thus, for
S(t)+I(t)+R(t)≤Aμ. | (4.11) |
Moreover, from the equation of
S′(t)≥A−μS−LS(t), |
so,
S(t)≥Aμ+L,t∈R. |
On the other hand, using the fact that
i(t,a)=π(a)(f(S(t),J(t))+k∫+∞0θ(a)i(t,a)da+δR(t)),≤π(a)(LJ(t)+k‖θ‖∞I(t)+δR(t)), |
According to (4.11), we conclude that
i(t,a)≤ξπ(a),a>0, |
where
The main purpose of this section is to study the global asymptotic stability of the endemic equilibrium. We first need to prove the strong uniform persistence of the solution of problem (4.10).
We begin by the following lemma which concern the existence of a positive equilibria.
Lemma 5.1. Assume that
limJ→0+f(A/μ,J)f(S,J)>1,forS∈[0,A/μ). |
If
Proof. Let
Φ(t,(S∗,i∗(.),R∗))=(S∗,i∗(.),R∗), for t≥0. |
From (4.1) and (3.4), we have
i∗(a)={π(a)i∗(0),0<a<t,π(a)π(a−t)i∗(a−t),a>t, | (5.1) |
and
{A=μS∗+f(S∗,J∗),J∗=∫+∞0β(a)i∗(a)da. | (5.2) |
Remark that if we consider
i∗(a−t)=π(a−t)i∗(0),=π(a−t)π(a)i∗(a), |
and thus
i∗(a)=π(a)π(a−t)i∗(a−t),=π(a)π(a−t)π(a−t)i∗(0),=π(a)i∗(0). |
We can proceed by iteration in order to prove the result. Therefore,
i∗(a)=π(a)i∗(0),for alla≥0. | (5.3) |
Combining (5.2) and (5.3), we get
i∗(0)=1Df(S∗,J∗), |
with
D=1−(k+δ(1−k)μ+δ)∫+∞0θ(a)π(a)da, | (5.4) |
thus,
i∗(a)=1Df(S∗,J∗)π(a),∀a≥0. | (5.5) |
Moreover, from (5.2) and (5.5), we obtain
{A=μS∗+f(S∗,J∗),J∗=MDf(S∗,J∗), | (5.6) |
where
Lemma 5.2. Under (H0) and (H1), we have following assertions,
f(.,J)Jis a nonincreasing function with respect toJ, | (5.7) |
and
{xJ∗<f(S,x)f(S,J∗)<1,for0<x<J∗,1<f(S,x)f(S,J∗)<xJ∗,forx>J∗. | (5.8) |
Now we focus on the uniform persistence of the solution of problem (4.10). We define,
ˉθ(a):=∫+∞0θ(a+t)π(a+t)π(a)dt, |
and
ˉβ(a):=∫+∞0β(a+t)π(a+t)π(a)dt. |
We set
X0={(S0,i0(⋅),r0)∈X+|r0+∫∞0i0(a)ˉθ(a)da+∫∞0i0(a)ˉβ(a)da>0}. |
Lemma 5.3. If
Proof. Recall that
B(t)=f(S(t),J(t))+k∫+∞0θ(a)i(t,a)da+δR(t). |
The third equation of system (2.1) implies that, for
R(t)=r0e−(μ+δ)t+(1−k)∫t0e−(μ+δ)(s−t)∫+∞0θ(σ)i(s,σ)dσds. |
We can rewrite
B(t)=f(S(t),J(t))+k∫+∞0θ(a)i(t,a)da+δr0e−(μ+δ)t+(1−k)δ∫t0e−(μ+δ)(s−t)∫+∞0θ(σ)i(s,σ)dσds. |
So, from (3.4),
B(t)=f(S(t),J(t))+k∫t0θ(a)π(a)B(t−a)da+k∫+∞tθ(a)π(a)π(a−t)i0(a−t)da+δr0e−(μ+δ)t+(1−k)δ∫t0e−(μ+δ)(s−t)(∫s0θ(σ)π(σ)B(s−σ)dσ+∫+∞sθ(σ)π(σ)π(σ−s)i0(σ−s)dσ)ds. | (5.9) |
If
I0(t):=∫+∞tθ(a)π(a)π(a−t)i0(a−t)da=∫+∞0θ(a+t)π(a+t)π(a)i0(a)da. | (5.10) |
By integrating
∫+∞0I0(t)dt=∫+∞0i0(a)∫+∞0θ(a+t)π(a+t)π(a)dtda=∫+∞0i0(a)ˉθ(a)da. |
In the following, we will use translations of solutions: for
Br(t)≥k∫t0θ(a)π(a)Br(t−a)da+kI0r(t). |
Since
Now, if
B(t)=f(S(t),J(t))+k∫t0θ(a)π(a)B(t−a)da+k∫+∞tθ(a)π(a)π(a−t)i0(a−t)da+(1−k)δ∫t0e−(μ+δ)(s−t)(∫s0θ(σ)π(σ)B(s−σ)dσ+∫+∞sθ(σ)π(σ)π(σ−s)i0(σ−s)dσ)ds. | (5.11) |
From the definition of the space
B(t)≤L∫t0β(a)π(a)B(t−a)da+k∫t0θ(a)π(a)B(t−a)da+(1−k)δ∫t0e−(μ+δ)(s−t)∫s0θ(σ)π(σ)B(s−σ)dσds. |
We can apply the Fubini's Theorem to the last term and using the assumptions on
B(t)≤(L‖β‖∞+(k+(1−k)δμ+δ)‖θ‖∞)∫t0B(a)da. |
By Gronwall's inequality, we obtain
We define the persistence function
ρ(S0,i0(⋅),r0)=f(S0,J0)+∫+∞0θ(a)i0(a)da+r0. |
By definition, we have,
ρ(Φ(t,(S0,i0(⋅),r0)))=B(t), |
Lemma 5.4. Assume that (5.7) holds. If
lim supt→+∞ρ(Φ(t,x))>ϵ, |
for all solutions of (2.1) provided that
Proof. We suppose that the function
lim supt→+∞ρ(Φ(t,x))<ϵ. |
By Theorem 2.1, we have
lim supt→+∞J(t)<ϵ0. |
Let
0≥A−μS∞−ϵ. |
Therefore,
S∞≥Aμ−ψ(ϵ), |
with
h(ϵ1)=f(Aμ−ψ(ϵ1),ϵ1)ϵ1∫+∞0β(a)π(a)da+(k+(1−k)δϵ1+μ+δ)∫+∞0θ(a)π(a)da>1. | (5.12) |
From system (2.1), we have, for all
R′(t)=(1−k)∫+∞0θ(a)i(t,a)da−(μ+δ)R(t). |
Therefore, for
R′(t)≥(1−k)∫t0θ(a)π(a)B(t−a)da−(μ+δ)R(t). |
Next, we introduce the Laplace transform to this inequality, which is given by, for
λˆR(λ)−R(0)≥(1−k)ˆθ(λ)ˆB(λ)−(μ+δ)ˆR(λ), |
Thus, we get
ˆR(λ)≥(1−k)ˆθ(λ)λ+μ+δˆB(λ). | (5.13) |
where
ˆB(λ)=∫+∞0B(a)e−λadaandˆθ(λ)=∫+∞0θ(a)π(a)e−λada. |
Moreover, since there exists
f(S,J)J≥f(Aμ−ψ(ϵ0),J)J≥f(Aμ−ψ(ϵ0),ϵ0)ϵ0. |
Then, for
B(t)≥f(S(t),J(t))J(t)J(t)+k∫t0θ(a)π(a)B(t−a)da+δR(t), |
so, for
B(t)≥f(Aμ−ψ(ϵ0),ϵ0)ϵ0∫t0β(a)π(a)B(t−a)da+k∫t0θ(a)π(a)B(t−a)da+δR(t). |
Similarly, we apply the Laplace transform to the last inequality, we get, for
ˆB(λ)≥ˆβ(λ)ˆB(λ)f(Aμ−ψ(ϵ0),ϵ0)ϵ0+kˆθ(λ)ˆB(λ)+δˆR(λ), |
where
ˆβ(λ)=∫+∞0β(a)π(a)e−λada. |
By using (5.13), we obtain
ˆB(λ)≥ˆβ(λ)ˆB(λ)f(Aμ−ψ(ϵ0),ϵ0)ϵ0+(k+δ(1−k)λ+μ+δ)ˆθ(λ)ˆB(λ). |
Since,
1≥ˆβ(λ)f(Aμ−ψ(ϵ0),ϵ0)ϵ0+(k+δ(1−k)λ+μ+δ)ˆθ(λ). |
We can choose
1≥h(ϵ0). |
which contradicts (5.12). This completes the proof.
To prove the uniform strong
Lemma 5.5. If
Proof. Assume that
B(t)≤L∫+∞0β(a)i(t,a)da+k∫+∞0θ(a)i(t,a)da+δ∫t0e(μ+δ)(s−t)∫+∞0θ(σ)π(σ)B(s−σ)dσds, |
thus since
B(t)≤L‖β‖∞∫t0B(a)da+k‖θ‖∫t0B(a)da+δ∫t0e(μ+δ)(s−t)∫s0θ(s−σ)π(s−σ)B(σ)dσds. |
So,
B(t)≤L‖β‖∞∫t0B(a)da+k‖θ‖∫t0B(a)da+δ∫t0θ(s−σ)π(s−σ)B(σ)e(μ+δ)(σ−t)dσ. |
Finally, according to Fubini's Theorem,
B(t)≤(L‖β‖∞+k‖θ‖∞+δ‖θ‖∞μ+δ)∫t0B(a)da. |
Applying the Gronwall's inequality, we get
B(t)=0,t>0. |
Lemma 5.6. The following alternative holds: either
Proof. From Lemma 5.5, we can deduce that for each
Bn(t)≥k∫∞0θ(a)π(a)Bn(t−a)da. |
After a change of variable,
Bn(t)≥k∫t−∞θ(t−s)π(t−s)Bn(s)ds, |
where
0=Bn(ϵ)≥k∫ϵ−∞θ(ϵ−s)π(ϵ−s)Bn(s)ds. |
Then,
Now we are ready to prove the strong uniform persistence of the disease.
Theorem 5.7. Assume that
Proof. By Lemmas 5.4, 5.5 and 5.6, we can apply Theorem 5.2 in [37] to conclude that uniform weak
From Theorem 5.7 in [37], we have the following result.
Theorem 5.8. There exists a compact attractor
ρ(Φ(t,(S0,i0(⋅),r0))≥Γ, for all (S0,i0(.),r0)∈A1. | (5.14) |
We will need the following estimates later.
Lemma 5.9. For all
i(t,a)i∗(a)>Γ0,a>0,t∈RandR(t)>η2,t∈R, |
with
Proof. Recall that the compact attractor of bounded set is the union of bounded total trajectories, see Proposition 2.34 in [37]. Thus, there exists a total trajectory
i(t,a)i∗(a)=π(a)B(t−a)π(a)f(S∗,J∗)D>ΓDf(S∗,J∗). |
In addition, from the equation of
R′(t)≥(1−k)Γ∫+∞0θ(a)π(a)da−(μ+δ)R(t). |
Finally, by a straightforward computation, we find
R(t)≥η2,t∈R, |
with
Now, we are ready to prove the global asymptotic stability of the unique positive endemic equilibrium.
Theorem 5.10. Suppose that
Proof. Let
ϕ(a)=∫+∞a[(δR∗∫+∞0θ(a)i∗(a)da+k)θ(σ)+β(σ)J∗f(S∗,J∗)]i∗(σ)dσ, | (5.15) |
and, for
H(y)=y−ln(y)−1. |
Then, for
V1(Ψ(t))=S(t)−S∗−∫S(t)S∗f(S∗,J∗)f(η,J∗)dη, |
V2(Ψ(t))=∫+∞0H(i(t,a)i∗(a))ϕ(a)da, |
and
V3(Ψ(t))=ΩH(R(t)R∗),withΩ:=δR∗2(1−k)∫+∞0θ(a)i∗(a)da. |
First, using the equation of
ddtV1(Ψ(t))=(1−f(S∗,J∗)f(S(t),J∗))(A−f(S(t),J(t))−μS(t)),=μ(S∗−S(t))(1−f(S∗,J∗)f(S(t),J∗))+(1−f(S∗,J∗)f(S(t),J∗))(f(S∗,J∗)−f(S(t),J(t))). |
By using the same arguments as in the proof of Lemma 9.18 in [37], we find
ddtV2(Ψ(t))=H(i(t,0)i∗(0))ϕ(0)+∫+∞0H(i(t,a)i∗(0))ϕ′(a)da,=H(Δ1f(S(t),J(t))f(S∗,J∗)+Δ2∫+∞0θ(a)i(t,a)da∫+∞0θ(a)i∗(a)da+Δ3R(t)R∗)ϕ(0)+∫+∞0H(i(t,a)i∗(a))ϕ′(a)da, |
where
Δ1:=f(S∗,J∗)i∗(0),Δ2:=k∫+∞0θ(a)i∗(a)dai∗(0)andΔ3:=δR∗i∗(0). |
In view of the third equation of (4.10), by
i∗(0)=f(S∗,J∗)+k∫+∞0θ(a)i∗(a)da+δR∗, |
we have
ddtV2(Ψ(t))≤[Δ1H(f(S(t),J(t))f(S∗,J∗))+Δ2H(∫+∞0θ(a)i(t,a)da∫+∞0θ(a)i∗(a)da)+Δ3H(R(t)R∗)]ϕ(0)+∫+∞0H(i(t,a)i∗(a))ϕ′(a)da. |
By adding
(V1+V2)′(Ψ(t))≤μ(S∗−S(t))(1−f(S∗,J∗)f(S(t),J∗))−f(S,J)+f(S∗,J∗)f(S,J)f(S,J∗)+f(S∗,J∗)(1−f(S∗,J∗)f(S,J∗))+f(S∗,J∗)(f(S,J)f(S∗,J∗)−lnf(S,J)f(S∗,J∗)−1)+Δ2i∗(0)H(∫+∞0θ(a)i(t,a)da∫+∞0θ(a)i∗(a)da)+Δ3i∗(0)H(R(t)R∗)+∫+∞0H(i(t,a)i∗(a))ϕ′(a)da. |
We reorder these terms, and using the fact that
lnf(S,J)f(S∗,J∗)=lnf(S,J)f(S,J∗)+lnf(S,J∗)f(S∗,J∗), |
we obtain
(V1+V2)′(Ψ(t))≤μ(S∗−S(t))(1−f(S∗,J∗)f(S(t),J∗))+f(S∗,J∗)(−lnf(S,J∗)f(S∗,J∗)−f(S∗,J∗)f(S,J∗)+1)+f(S∗,J∗)H(f(S,J)f(S,J∗))+Δ2i∗(0)H(∫+∞0θ(a)i(t,a)da∫+∞0θ(a)i∗(a)da)+Δ3i∗(0)H(R(t)R∗)+∫+∞0H(i(t,a)i∗(a))ϕ′(a)da. |
On the other hand,
ddtV3(Ψ(t))=ΩR∗H′(R(t)R∗)((1−k)∫+∞0θ(a)i(t,a)da−(μ+δ)R(t)),=Ω(μ+δ)R∗(1−R∗R)(R∗−R)+Ω(1−k)R∗H′(R(t)R∗)(∫+∞0θ(a)i(t,a)da−∫+∞0θ(a)i∗(a)da). |
By adding and subtracting the same term
Ω(1−k)R∗H′(R(t)R∗)∫+∞0θ(a)i∗(a)daR(t)R∗, |
it yields,
ddtV3(Ψ(t))=Ω(μ+δ)R∗(1−R∗R)(R∗−R)+Ω(1−k)R∗H′(R(t)R∗)∫+∞0θ(a)i∗(a)(i(t,a)i∗(a)−R(t)R∗)da+Ω(1−k)R∗H′(R(t)R∗)(R(t)R∗−1)∫+∞0θ(a)i∗(a)da. |
Next, by summing
V′(Ψ(t))≤μ(S∗−S(t))(1−f(S∗,J∗)f(S(t),J∗))+f(S∗,J∗)(−lnf(S,J∗)f(S∗,J∗)−f(S∗,J∗)f(S,J∗)+1)+f(S∗,J∗)H(f(S,J)f(S,J∗))+∫+∞0H(i(t,a)i∗(a))ϕ′(a)da+Δ2i∗(0)H(∫+∞0θ(a)i(t,a)da∫+∞0θ(a)i∗(a)da)+Δ3i∗(0)H(R(t)R∗)+Ω(1−k)R∗H′(R(t)R∗)∫+∞0θ(a)i∗(a)(i(t,a)i∗(a)−R(t)R∗)da+Ω(μ+δ)R∗(1−R∗R)(R∗−R)+Ω(1−k)R∗H′(R(t)R∗)(R(t)R∗−1)∫+∞0θ(a)i∗(a)da. |
Using the fact
H(∫+∞0θ(a)i(t,a)da∫+∞0θ(a)i∗(a)da)=H(∫+∞0θ(a)i∗(a)∫+∞0θ(a)i∗(a)dai(t,a)i∗(a)da),≤∫+∞0θ(a)i∗(a)∫+∞0θ(a)i∗(a)daH(i(t,a)i∗(a))da. |
Thus, by combining this with the fact that
Ω(1−k)R∗=δR∗∫+∞0θ(a)i∗(a)da, |
we obtain
V′(Ψ(t))≤μ(S∗−S(t))(1−f(S∗,J∗)f(S(t),J∗))+f(S∗,J∗)(−lnf(S,J∗)f(S∗,J∗)−f(S∗,J∗)f(S,J∗)+1)+f(S∗,J∗)H(f(S,J)f(S,J∗))+∫+∞0H(i(t,a)i∗(a))ϕ′(a)da+Δ2i∗(0)∫+∞0θ(a)i∗(a)∫+∞0θ(a)i∗(a)daH(i(t,a)i∗(a))da+Δ3i∗(0)H(R(t)R∗)+δR∗∫+∞0θ(a)i∗(a)daH′(R(t)R∗)∫+∞0θ(a)i∗(a)(i(t,a)i∗(a)−R(t)R∗)da. |
Now, for the values of
H(f(S,J)f(S,J∗))<H(J(t)J∗),=H(∫+∞0β(a)i∗(a)∫+∞0β(a)i∗(a)dai(t,a)i∗(a)da),≤∫+∞0β(a)i∗(a)∫+∞0β(a)i∗(a)daH(i(t,a)i∗(a))da,=∫+∞0β(a)i∗(a)J∗H(i(t,a)i∗(a))da. |
This implies that
V′(Ψ(t))≤μ(S∗−S(t))(1−f(S∗,J∗)f(S(t),J∗))+f(S∗,J∗)(−lnf(S,J∗)f(S∗,J∗)−f(S∗,J∗)f(S,J∗)+1)+∫+∞0H(i(t,a)i∗(a))[ϕ′(a)+f(S∗,J∗)J∗β(a)i∗(a)+kθ(a)i∗(a)]da+δR∗H(R(t)R∗)+δR∗∫+∞0θ(a)i∗(a)daH′(R(t)R∗)∫+∞0θ(a)i∗(a)(i(t,a)i∗(a)−R(t)R∗)da. |
Finally, in view of the expression of
V′(Ψ(t))≤μ(S∗−S(t))(1−f(S∗,J∗)f(S(t),J∗))+f(S∗,J∗)(−lnf(S,J∗)f(S∗,J∗)−f(S∗,J∗)f(S,J∗)+1)+∫+∞0[H(R(t)R∗)−H(i(t,a)i∗(a))+H′(R(t)R∗)(i(t,a)i∗(a)−R(t)R∗)]δR∗θ(a)i∗(a)∫+∞0θ(a)i∗(a)dada. |
Since
V′(Ψ(t))≤0. |
By applying the same arguments for the values of
i(t,a)i∗(a)=B(t−a)i∗(0)=R(t)R∗, ∀a≥0, | (5.16) |
this implies that
A−μS∗=f(S∗,J(t)). |
Moreover, from equations of equilibrium we know that
A−μS∗=f(S∗,J∗), |
thus we obtain
Now, since
V(Ψ(t))→V(S∗,i∗(.),R∗), as t→±∞. |
On the other hand, we have
limt→+∞V(Ψ(t))≤V(Ψ(t))≤limt→−∞V(Ψ(t)), |
for all
In this section, the results of the previous sections are illustrated by numerical simulations. We use the following numerical method: we discretize our problem by the upwind method for solving hyperbolic partial differential equation. For instance, the approximation
(∂u∂t)n≃un+1i−uniΔt,(∂u∂a)i≃uni−uni−1Δa. |
The equations of susceptible and recover are solving by explicit Euler method for the ODE. The non-local terms are approximated by one of the composite integration formulas.
Let's consider the Beddington-Deangelis functional response defined by
f(S,J)=SJ1+α1S+α2J. |
We note that this function
R0=Aμ+α1A∫+∞0β(a)π(a)da+((1−k)δμ+δ+k)∫+∞0θ(a)π(a)da. |
We consider the following values of parameters
A=2.10−3,μ=1.10−2andδ=1.10−2, |
with the initial conditions
S0=1.10−3,r0=2.10−4andi0(a)=8.10−4e−0.1a. |
The functions
β(a)={0, if a≤τ1,56.10−3(a−τ1)2e−0.2(a−τ1), if a>τ1, |
and
θ(a)={0, if a≤τ2,3.10−2(a−τ2)2e−0.15(a−τ2); if a>τ2, |
with
In first time, we choose
In second time, we take
In this paper, we proposed and analyzed an infection age-structured SIR epidemic model with a general incidence rate. We showed the basic characters of the solution including existence, uniqueness and positivity. We obtained the basic reproduction number
In this paper, we have not considered the case where
The authors would like to thank the associate editor and the anonymous reviewers for their careful reading and helpful comments. TK was supported by Grant-in-Aid for Young Scientists (B) of Japan Society for the Promotion of Science (Grant No. 15K17585).
All authors declare no conflicts of interest in this paper.
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