Research article

A characterization of b-generalized skew derivations on a Lie ideal in a prime ring

  • Received: 03 October 2024 Revised: 07 November 2024 Accepted: 21 November 2024 Published: 04 December 2024
  • MSC : 16N60, 16W25

  • This paper investigates the analysis of b-generalized skew derivations, denoted as Δ1 and Δ2, within a prime ring R with characteristic different from 2. Here, Qr represents the right Martindale quotient ring of R, and C denoted its extended centroid. Additionally, L is a noncentral Lie ideal of R. Assuming Δ1 and Δ2 are nontrivial b-generalized skew derivations associated with the same automorphism α, the paper aims to explore the detailed structure of these generalized derivations that satisfy the specific equation:

    puΔ1(u)+Δ1(u)uq=Δ2(u2), with p+qC,for all uL.

    The above-studied result generalized the already existing results [1,2] in the literature.

    Citation: Omaima Alshanqiti, Ashutosh Pandey, Mani Shankar Pandey. A characterization of b-generalized skew derivations on a Lie ideal in a prime ring[J]. AIMS Mathematics, 2024, 9(12): 34184-34204. doi: 10.3934/math.20241628

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  • This paper investigates the analysis of b-generalized skew derivations, denoted as Δ1 and Δ2, within a prime ring R with characteristic different from 2. Here, Qr represents the right Martindale quotient ring of R, and C denoted its extended centroid. Additionally, L is a noncentral Lie ideal of R. Assuming Δ1 and Δ2 are nontrivial b-generalized skew derivations associated with the same automorphism α, the paper aims to explore the detailed structure of these generalized derivations that satisfy the specific equation:

    puΔ1(u)+Δ1(u)uq=Δ2(u2), with p+qC,for all uL.

    The above-studied result generalized the already existing results [1,2] in the literature.



    A ring R is considered prime if, for any elements π and ξ in R, the condition πRξ=0 implies that either π=0 or ξ=0. In our discussion, unless otherwise stated, R refers to a prime ring with its center denoted by Z(R), and Qr refers to its right Martindale quotient ring. Notably, Qr retains the prime property of R. Additionally, the center of Qr, known as the extended centroid of R, is a field.

    To simplify the notation, we use [π,ξ]=πξξπ for all π,ξR. A subset L of R is called a Lie ideal of R if it forms an additive subgroup and satisfies the condition that the commutator of L with any element of R remains within L, i.e., [L,R]L.

    Definition 1.1. [3] A mapping d:RR is called a derivation if it is additive and

    d(πξ)=d(π)ξ+πd(ξ),for allπ,ξR.

    For a fixed vR, the mapping dv:RR defined as dv(π)=[v,π] for all πR is a derivation termed as an inner derivation induced by the element v. A derivation that is not inner is referred to as an outer derivation. In 1957, Posner [4] showed that if R is a prime ring and d is a nontrivial derivation of R such that [d(π),π]Z(R) for all πR, then R is commutative. Posner's results were later extended in various ways by other mathematicians.

    In 1991, M. Breˇsar [5] proposed a new kind of derivation, known as a generalized derivation.

    Definition 1.2. [5] A mapping Δ:RR is said to be a generalized derivation if Δ is additive and there exists a derivation δ on R such that

    Δ(πξ)=Δ(π)ξ+πδ(ξ),for allπ,ξR.

    For fixed elements v1,v2R, the mapping Δ(v1,v2):RR defined by Δ(v1,v2)(π)=v1π+πv2 is a generalized derivation on R, often referred to as a generalized inner derivation.

    Definition 1.3. [3] A mapping D:RR is called a skew derivation associated with the automorphism αAut(R) if it is additive and it satisfies

    D(πξ)=D(π)ξ+α(π)D(ξ),for all π,ξR.

    A skew derivation that is associated with the identity automorphism reduces to a derivation. For example, given a fixed element b in Qr, the mapping defined by πbπα(π)b is a notable example of a skew derivation, commonly known as an inner skew derivation. If a skew derivation does not fit this structure, it is termed an outer skew derivation.

    Definition 1.4. [3] A mapping ϕ:RR is called a generalized skew derivation associated with the automorphism αAut(R) if it is additive and there exists a skew derivation δ on R such that

    ϕ(πξ)=ϕ(π)ξ+α(π)δ(ξ),for all π,ξR.

    In 2021, De Filippis [6] studied the identity Δ1(Δ2(π))=0 for all πL, where Δ1 and Δ2 are generalized skew derivations on a prime ring R, with L being a Lie ideal of R. This identity was examined within the framework of generalized derivations.

    In 2018, De Filippis and Wei [7] developed the notion of b-generalized skew derivation, which broadens the concept of derivations and investigates different kinds of linear mappings in noncommutative algebras.

    Definition 1.5. [7] Let b be a fixed element in the right Martindale quotient ring Qr. The mapping Δ1:RQr is called a b-generalized skew derivation of R associated with the triplet (b,α,d) if it is additive and it satisfies the condition

    Δ1(πξ)=Δ1(π)ξ+bα(π)d(ξ)

    for all π,ξR, where d:RQr is an additive mapping and α is an automorphism of R.

    Furthermore, the authors showed that when b0, the corresponding additive map d, as defined earlier, acts as a skew derivation. Additionally, it has been established that the additive mapping Δ1 can be extended to the right Martindale quotient ring Qr, taking the form Δ1(π)=aπ+bd(π), where aQr. The concept of b-generalized skew derivation, characterized by the triplet (b,α,d), includes skew derivations, generalized derivations, and left multipliers, among other concepts. For instance, setting b=1 yields a skew derivation, while choosing b=1 and α=IR results in a generalized derivation, with IR representing the identity map on R. Additionally, if b=0 in Definition 1.5, then Δ1 reduces to a left multiplier map. The mapping Δ1:RQr, given by πaπ+bα(π)c is a notable example of b-generalized skew derivation of R associated with the triplet (b,v1,d), where a, b,cQr, and d(π)=α(π)ccπ for all πR. This type of b-generalized skew derivation is known as an inner b-generalized skew derivation. Therefore, the study of b-generalized skew derivations of a ring R provides insights into the study of other types of derivations.

    These broad results concerning b-generalized skew derivations lead to significant corollaries related to derivations, generalized derivations, and generalized skew derivations. Such findings offer valuable insights for applications and further advancements in the study of these related concepts.

    It is quite natural to examine the implications of substituting derivations with b-generalized skew derivations in the results originally obtained by Posner and Breˇsar. In 2021, Filippis et al. [8] made progress in extending Breˇsar's result by investigating the identity Δ1(π)ππΔ2(π)=0 involving b-generalized skew derivations Δ1 and Δ2 in a prime ring R. Here, π represents elements of the form ϕ(π1,,πn), where π=(π1,,πn)Rn, and ϕ(π) is a multi-linear polynomial over C. Relevant generalizations related to b-generalized skew derivations can be found in [3,7,8,9,10,11,12].

    Continuing the investigation of above cited results, we focus to study the following identity pπΔ1(π)+Δ1(π)πq=Δ2(π2), where p+qC for all πL. The primary motivation for this identity comes from the articles [1] and [2]. In [1], the authors examined the identity pπF(π)+F(π)πq=G(π2), where F, G are derivations and πS, a particular subset of R. In [2], the same identity was explored with F and G considered as generalized derivations. Naturally, it is of interest to investigate this identity further by taking F and G as b-generalized skew derivations. The following theorem establishes our result:

    Theorem 1.6. Let R be a prime ring with characteristic different from 2, Qr its right Martindale quotient ring, C its extended centroid, and L a noncentral Lie ideal of R. Suppose Δ1 and Δ2 are non-zero b-generalized skew derivations of R with associated triples (b,α,d) and (b,α,h), respectively, satisfying the identity:

    pπΔ1(π)+Δ1(π)πq=Δ2(π2)for somep,qRwithp+qC, πL.

    Then, for all πR, one of the following holds:

    1) There exist aC and cQr such that Δ1(π)=aπ, Δ2(π)=πc with pa=caqC.

    2) There exist aC and c,cQr such that Δ1(π)=aπ, Δ2(π)=cπ+πc with pacC and (p+q)a=c+c.

    3) There exist a,qC and cQr such that Δ1(π)=aπ, Δ2(π)=cπ with (p+q)a=c.

    4) There exist a,b,u,v,tQr, and λ,ηC such that Δ1(π)=(a+bπ)π, Δ2(π)=cπ+btπt1v with t1v+ηq=λC, (a+bπ)+ηbt=0, and p(a+bπ)c=λbt.

    5) R satisfies s4.

    The standard polynomial identity s4 in four variables is defined as follows:

    s4(π1,π2,π3,π4)=σSym(4)(1)σπσ(1)πσ(2)πσ(3)πσ(4),

    where (1)σ is +1 or 1 depending on whether σ represents an even or odd permutation in the symmetric group Sym(4).

    The general approach for proving the main theorem can be extended to demonstrate a broader result for multi-linear polynomials. Consequently, from a theoretical standpoint, there is no distinction between cases involving Lie ideals and those involving multi-linear polynomials. Applying the proof method suitable for multi-linear polynomials streamlines the process by minimizing excessive calculations. The paper is structured as follows: Section 2 provides a review of fundamental concepts regarding prime rings. Section 3 explores the case where the b-generalized skew derivations Δ1 and Δ2 are inner. In Section 4, we establish our main theorem by carefully examining each case.

    We frequently utilize the following facts to establish our results:

    Fact 2.1. [13] Let R be a prime ring and I a two-sided ideal of R. Then, R, I, and Qr satisfy the same generalized polynomial identities with coefficients in Qr.

    Fact 2.2. [14] Let R be a prime ring and I a two-sided ideal of R. Then, R,I, and Qr satisfy the same differential identities.

    Fact 2.3. [13] Let R be a prime ring. Then, every derivation d of R can be uniquely extended to a derivation of Qr.

    Fact 2.4. [15, Chuang] Let R be a prime ring, d be a nonzero skew derivation on R, and I a nonzero ideal of R. If I satisfies the differential identity.

    f(ζ1,ζ2,,ζn,d(ζ1),d(ζ2),d(ζn))=0

    for any ζ1,,zetanI, then either

    I satisfies the generalized polynomial identity,

    f(ζ1,ζ2,ζn,ξ1,xi2,xin)=0

    for all ξ1,,ξnR.

    or

    d is Qr-inner,

    f(ζ1,ζ2,,ζn,[p,ζ1],[p,ζ2],[p,ζn])=0.

    Fact 2.5. [16] Let K be an infinite field and m2 an integer. If P1,,Pk are non-scalar matrices in Mm(K), then there exists some invertible matrix PMm(K) such that each matrix PP1P1,,PPkP1 has all nonzero entries.

    Fact 2.6. [17] Let R be a noncommutative prime ring of characteristic not equal to 2 with right Martindale quotient ring Qr and extended centroid C, and let f(ζ1,,ζn) be a multi-linear polynomial over C, which is not central valued on R. Suppose that there exists a,b,cQr such that f(χ)af(χ)+f(χ)2bcf(χ)2=0 for all χ=(ζ1,,ζn)R. Then, one of the following holds:

    1) b,cC, Cb=a=αC.

    2) f(ζ1,,ζn)2 is central valued and there exists αC such that cb=a=α.

    Fact 2.7. [7] If d is a nonzero skew derivation on a prime ring R, then associated automorphism α is unique.

    Fact 2.8. [6] Let R be a prime ring, ϕ,γ be two automorphisms of Qr and d,g be two skew derivations on R associated with the same automorphism ϕ. If there exist a nonzero central element ν and vQr such that

    G(ζ)=(vζγ(ζ)v)+νd(ζ),for allζR.

    then, G(ζ)=νd(ζ) and one of the following holds:

    1) ϕ=γ.

    2) v=0.

    Fact 2.9. [6] Let R be a prime ring, ϕ,γ be two automorphisms of Qr, and d,g be two skew derivations on R associated with the same automorphism ϕ. If there exist a nonzero central element ν and vQr such that

    G(ζ)=(vζγ(ζ)v)+νd(ζ),for allζR.

    If d is inner skew derivation, then so is G.

    In this paper, R will consistently refer to a nontrivial, associative prime ring (unless specified otherwise). Additionally, the term "GPI" will be used as a shorthand for generalized polynomial identity.

    In this section, we focus on the case where Δ1 and Δ2 are inner b-generalized skew derivations of R associated with the pair (b,α). More specifically, we investigate Theorem 1.6 under the conditions Δ1(π)=aπ+bα(π)u and Δ2(π)=cπ+bα(π)v for all πR, where a,b,c,u,vQr. To establish the main result, we first present the following lemmas:

    Lemma 3.1. Let R be a prime ring of char(R)2 and a1, a2, a3, a4, and a5R such that

    a1u2+a2u2a3+a4u2a5=0,  u=[π1,π2][R,R]. (3.1)

    Then, one of the following holds:

    1) R satisfies s4.

    2) a3,a4C, and a1+a2a3=a5a4C.

    3) a3,a5C, and a1+a2a3+a5a4=0.

    4) a1,a2,a4C, and a1+a2a3+a5a4=0.

    5) a2,a5C, and a1+a4a5=a2a3C.

    6) There exist λ, η, μC such that a5+ηa3=λ, a2ηa4=μ, and a1+λa4=μa3C

    Proof. If u2 is a centrally valued element in R, then R satisfies the identity s4, which leads to our first conclusion. Now, suppose u2 is not central. Let S be the additive subgroup of R generated by the set {u2:u[R,R]}. Clearly, S0, and we have the relation:

    a1π+a2πa3+a4πa5=0

    for all πS.

    According to [18], either SZ(R), or char(R)=2 and R satisfies s4, unless S contains a non-central ideal L of R. Since u2 is not centrally valued in R, the first possibility is excluded. Additionally, since char(R)2, it follows that S contains a noncentral Lie ideal L of R. By [19], there exists a noncentral two-sided ideal I of R such that [I,R]L. Under the given hypothesis, we have

    a1[π1,π2]+a2[π1,π2]a3+a4[π1,π2]a5=0

    for all π1,π2I. From Fact 2.1, since Qr, I, and R satisfy the same GPI, it follows that

    a1[π1,π2]+a2[π1,π2]a3+a4[π1,π2]a5=0

    for all π1,π2R. Therefore, by [[20], Proposition 2.13], we obtain the desired conclusions.

    Lemma 3.2. Let R=Mm(C), where m2, be the ring of all m×m matrices over an infinite field C with characteristic not equal to 2. Suppose a,b,c,u,v,p,qR satisfy:

    pΠaΠ+pΠbΠu+aΠ2q+bΠuΠqcΠ2bΠ2v=0

    for all Π=[π1,π2][R,R]. Then, either bC, uC, or p+qC.

    Proof. Assume the field C is infinite. From the hypothesis:

    pΠaΠ+pΠbΠu+aΠ2q+bΠuΠqcΠ2bΠ2v=0 (3.2)

    for all Π[R,R]. If we assume that p+q, b, and u are not central elements, and since Eq (3.2) holds invariantly under any automorphism of R (as stated in Fact 2.5), it implies that all entries of p+q, b, and u are nonzero. By selecting Π=eij in Eq (3.2), we obtain:

    peijaeij+peijbeiju+beijueijq=0. (3.3)

    Next, multiplying Eq (3.3) both on the right and the left by eij gives:

    (p+q)jiujibjieij=0,

    which implies that either (p+q)ji=0, uji=0, or bji=0. Each of these scenarios leads to a contradiction. Therefore, it follows that either p+qC, or bC, or uC.

    Lemma 3.3. Let R=Mm(C), where m2, be the ring of all m×m matrices over a field C with characteristic not equal to 2. Suppose a,b,c,u,v,p,qR satisfy:

    pΠaΠ+pΠbΠu+aΠ2q+bΠuΠqcΠ2bΠ2v=0

    for all Π=[π1,π2][R,R]. Then, either bC, uC, or p+qC.

    Proof. If C is an infinite field, the conclusion follows directly from Lemma 3.2. Now, let's consider the case where the field C is finite. Let K be an infinite extension field of C, and set ˉR=Mm(K)RCK. It is important to note that a multi-linear polynomial is central-valued on R if and only if it is central-valued on ˉR.

    Consider the generalized polynomial identity for R given by

    Q(π1,π2)=p[π1,π2]a[π1,π2]+p[π1,π2]b[π1,π2]u+a[π1,π2]2q+b[π1,π2]u[π1,π2]qc[π1,π2]2b[π1,π2]2v. (3.4)

    This polynomial has a multi-degree of (2,2) with respect to the indeterminates π1 and π2. Therefore, the complete linearization of Q(π1,π2) results in a multi-linear generalized polynomial Θ(π1,π2,ξ1,ξ2) involving four indeterminates. Additionally, we have the relation Θ(π1,π2,π1,π2)=4Q(π1,π2).

    It is clear that the multi-linear polynomial Θ(π1,π2,ξ1,ξ2) serves as a generalized polynomial identity for both R and ˉR. Given that the characteristic of R is not equal to 2, as per the assumption, we conclude that Q(π1,π2)=0 for all π1,π2ˉR. Hence, the result follows from Lemma 3.2.

    Lemma 3.4. Let R be a prime ring of characteristic different from 2, with Martindale quotient ring Qr and extended centroid C. Suppose that for some a,b,c,u,v,p,qR, the following holds:

    pΠaΠ+pΠbΠu+aΠ2q+bΠuΠqcΠ2bΠ2v=0

    for all Π=[π1,π2][R,R]. Then, either bC, uC, or p+qC.

    Proof. Case 1: Suppose none of b, u, or p+q is central. Given the hypothesis, we have

    h(π1,π2)=p[π1,π2]a[π1,π2]+p[π1,π2]b[π1,π2]u+a[π1,π2]2q+b[π1,π2]u[π1,π2]qc[π1,π2]2b[π1,π2]2v (3.5)

    for all π1,π2R. Define D=QrCC{π1,π2}, the free product of Qr and the free C-algebra C{π1,π2} in non-commuting indeterminates π1 and π2. Since both R and Qr satisfy the same GPI (from Facts 2.1 and 2.2), Qr satisfies h(π1,π2)=0 in D.

    Now, let's treat h(π1,π2) as a trivial GPI for R. Thus, h(π1,π2) is a zero element in D. However, since b, u, and p+q are assumed not to be central, it must be that either b[π1,π2]u[π1,π2]q or p[π1,π2]b[π1,π2]u appears nontrivially in h(π1,π2), leading to a contradiction.

    Hence, at least one of b, u, or p+q belongs to C.

    Case 2: Now, suppose that h(π1,π2) is a nontrivial GPI for Qr. If C is infinite, then h(π1,π2)=0 for all π1,π2QrCˉC, where ˉC is the algebraic closure of C. Since Qr and QrCˉC are both prime and centrally closed (refer to Theorems 2.5 and 3.5 in [21]), we can replace R by either Qr or QrCˉC, depending on whether C is finite or infinite. Thus, R is centrally closed over C, and h(π1,π2)=0 for all π1,π2R.

    By Martindale's theorem [22], R is a primitive ring with a nonzero socle, soc(R), and C as its associated division ring. By Jacobson's theorem (see p.75 in [23]), R is isomorphic to a dense ring of linear transformations on a vector space V over C.

    Assuming first that V is finite-dimensional over C, i.e., dimCV=m, the density of R implies RMm(C). Since R is noncommutative, therefore, m2. In this case, the result follows from Lemma 3.2.

    Next, suppose V is infinite-dimensional over C. For any e2=esoc(R), we have eReMt(C) where t=dimCVe. Since none of b, u, or p+q is central, there exist h1,h2,h3soc(R) such that [b,h1]0, [u,h2]0, and [p+q,h3]0. By Litoff's theorem [24], there is an idempotent esoc(R) such that bh1,h1b,uh2,h2u,(p+q)h3,h3(p+q),h1,h2,h3eRe. Then, from Eq (3.5), we have:

    e{p[eπ1e,eπ2e]a[eπ1e,eπ2e]+p[eπ1e,eπ2e]b[eπ1e,eπ2e]u+a[eπ1e,eπ2e]2q+b[eπ1e,eπ2e]u[eπ1e,eπ2e]qc[eπ1e,eπ2e]2b[eπ1e,eπ2e]2v}e=0 (3.6)

    for all π1,π2R. The subring eRe satisfies:

    epe[π1,π2]eae[π1,π2]+epe[π1,π2]ebe[π1,π2]eue+eae[π1,π2]2eqe+ebe[π1,π2]eue[π1,π2]eqeece[π1,π2]2ebe[π1,π2]2eve=0 (3.7)

    for all π1,π2R. By the finite-dimensional case above, either ebe, or eue, or e(p+q)e is a central element of eRe. Thus, one of the following must hold: bh1=(ebe)h1=h1ebe=h1b, or uh2=(eue)h2=h2(eue)=h2u, or (p+q)h3=e(p+q)eh3=h3(e(p+q)e)=h3(p+q), which contradicts the initial assumption.

    Therefore, we conclude that either bC, or uC, or p+qC.

    From the previous arguments, we can prove the following lemmas:

    Lemma 3.5. Let R be a prime ring of characteristic different from 2 with Martindale quotient ring Qr and extended centroid C. Suppose that for some a,p,qR,

    pΠaΠ+aΠ2q=0

    for all Π=[π1,π2][R,R]. Then, either aC or both p and paC.

    Lemma 3.6. Let R be a prime ring of characteristic different from 2 with Martindale quotient ring Qr and extended centroid C. Suppose that for some p,qR,

    pΠ2+Π2q=0

    for all Π=[π1,π2][R,R]. Then, either R satisfies s4 or p+q=0.

    Proposition 3.7. Let R be a prime ring of characteristic different from 2, Qr be its Martindale ring of quotients with extended centroid C, and L=[R,R] be a Lie ideal of R. Let Δ1,Δ2 be two b-generalized skew inner derivations of R with associated pair (b,α). Suppose there exist elements p,qR such that

    pΠΔ1(Π)+Δ1(Π)Πq=Δ2(Π2), with p+qC, ΠL.

    Then, for all πR, one of the following holds:

    1) There exist aC and cQr such that Δ1(π)=aπ,Δ2(π)=πc with pa=caqC.

    2) There exist aC and c,cQr such that Δ1(π)=aπ, Δ2(π)=cπ+πc with pacC and (p+q)a=c+c.

    3) There exist a,qC and cQr such that Δ1(π)=aπ, Δ2(π)=cπ with (p+q)a=c.

    4) There exist a,b,u,v,tQr and λ,ηC such that Δ1(π)=(a+bu)π, Δ2(π)=cπ+btπt1v with t1v+ηq=λC, (a+bu)+ηbt=0, and p(a+bu)c=λbt.

    5) R satisfies s4.

    Proof. From the hypothesis, we have:

    pΠaΠ+pΠbα(Π)u+aΠ2q+bα(Π)uΠqcΠ2bα(Π2)v=0 (3.8)

    for all Π=[π1,π2][R,R].

    Case 1: Suppose the associated automorphism α is inner, then there exists an invertible element tR such that α(π)=tπt1 for all πR. Thus, Eq (3.8) becomes:

    pΠaΠ+pΠbtΠt1u+aΠ2q+btΠt1uΠqcΠ2btΠ2t1v=0 (3.9)

    for all Π[R,R]. Then from Lemma 3.4, either btC or t1uC.

    Sub-case (a): If btC, then Eq (3.9) reduces to:

    pΠaΠ+pΠ2bu+aΠ2q+ΠbuΠqcΠ2Π2bv=0 (3.10)

    for all Π[R,R]. Again, by previous arguments, one of the following holds:

    1) p,pa,buC.

    2) a,buC.

    3) a,q,buqC.

    Now, we will discuss each of the above cases in detail.

    1) Suppose pa,p,buC, then Eq (3.10) reduces to:

    (pac)Π2+aΠ2q+Π2(pbu+buqbv)=0 (3.11)

    for all Π=[π1,π2][R,R]. Then, from Lemma 3.1, one of the following holds:

    R satisfies s4, which is our Conclusion (5).

    qC, which implies that p+qC, a contradiction.

    q,(pbu+buqbv)C, which implies that p+qC, a contradiction.

    (pac),aC, which implies that cC. Thus, from Eq (3.11), we get (a+bu)p=(c+bv)(a+bu)q. Hence, in this case, we get Δ1(π)=(a+bu)π and Δ2(π)=π(c+bv) for all πR with (a+bu)p=(c+bv)(a+bu)q, which is our Conclusion (1).

    q,(pbu+buqbv)C, which gives that p+qC, a contradiction.

    ● There exist η,λ,μC such that (pbu+buqbv)+ηq=λ, aη=μ and (pac)+λ=μqC. If μ0, then qC, which implies p+qC, a contradiction. If μ=0, then pac,aC; then by previous arguments, we get our Conclusion (1).

    2) Suppose a,buC. Then, Eq (3.10) reduces to:

    (p(a+bu)c)Π2+aΠ2q+Π2(buqbv)=0 (3.12)

    for all Π=[π1,π2][R,R]. Then, from Lemma 3.1, one of the following holds:

    R satisfies s4, which is our Conclusion 5.

    qC and p(a+bu)c+aq=buq+bvC. Thus, in this case, we get our Conclusion (2).

    q,(buqbv)C, which implies bvC. Thus, from Eq (3.12), we get (pa+pbuc+aq+buqbv)Π2=0, which implies (a+bu)q=(c+bv)(a+bu)pC. Hence, in this case, we get Δ1(π)=(a+bu)π and Δ2(π)=(c+bv)π for all πR with (a+bu)q=(c+bv)(a+bu)pC, which is our Conclusion (3).

    (p(a+bu)c)C. Then, from Eq (3.12), we get Π2(pa+pbuc+aq+buqbv)=0, which implies (p+q)(a+bu)=(c+bv). Thus, in this case, we get Δ1(π)=(a+bu)π, Δ2(π)=cπ+πbv for all πR with (p+q)(a+bu)=(c+bv), which is our Conclusion (2).

    (buqbv),aC, and p(a+bu)c+buqbv=aqC. Since buqbvC, we have p(a+bu)cC. Thus, in this case, we get our Conclusion (2).

    ● There exist η,λ,μC such that (buqbv)+ηq=λ, aη=μ, and (p(a+bu)c)+λ=μqC. If μ0, then qC, which implies bvC. Thus, by previous arguments, we get our Conclusion (3). If μ=0, then p(a+bu)cC, and by previous arguments, we get our Conclusion (2).

    3) Suppose a,q,buqC, then Eq (3.10) reduces to:

    (ap+aq+buqc)Π2+pΠ2buΠ2bv=0 (3.13)

    for all Π[R,R]. Then, from Lemma 3.1, one of the following holds:

    R satisfies s4, which is our Conclusion (5).

    buC and ap+aq+buqc+pbu=bvC. Therefore, we have p(a+bu)cC. Also, we have (a+bu)qC. If a+bu=0, then c+bv=0, and we get our conclusion (1). If a+bu0, then we get qC; thus, in this situation, we get Conclusion (3).

    bu,bvC, and our functions take the form Δ1(π)=(a+bu)π, Δ2(π)=(c+bv)π for all πR with (a+bu)q=(c+bv)(a+bu)p, which is our Conclusion (3).

    (ap+aq+buqc),pC; this gives p+qC, a contradiction.

    p,bvC; this gives p+qC, a contradiction.

    ● There exist η,λ,μC such that bv+ηbu=λ, pη=μ, and (ap+aq+buqc)+λ=μbuC. This gives that p=η+μC, and, hence, p+qC, a contradiction.

    Sub-case (b): If t1uC, then Eq (3.9) reduces to:

    pΠaΠ+pΠbuΠ+aΠ2q+buΠ2qcΠ2btΠ2t1v=0 (3.14)

    for all Π[R,R]. Again, by previous arguments, one of the following holds:

    a) p,p(a+bu)C,

    b) a+buC.

    a) Now, if p,p(a+bu)C, then Eq (3.14) reduces to the following:

    (p(a+bu)c)Π2+(a+bu)Π2qbtΠ2t1v=0. (3.15)

    Now, by Lemma 3.1, one of the following holds:

    R satisfies s4, which is our Conclusion (5).

    q,btC, which implies p+qC, a contradiction.

    t1v,qC, which implies p+qC, a contradiction.

    p(a+bu)c,(a+bu),btC with p(a+bu)c+(a+bu)q=bv, which implies cC and p(a+bu)=q(a+bu)+(c+bv)C. Thus, in this situation, we get Δ1(π)=(a+bu)π and Δ2(π)=π(c+bv) for all πR, which is our Conclusion (1).

    (a+bu),t1vC with p(a+bu)cbv=(a+bu)qC. If a+bu=0, then c+bv=0 and, thus, we get our Conclusion (1). Now, if a+bu0, then qC. Therefore, p+qC, which is a contradiction.

    ● There exist η,λ,μC such that t1v+ηq=λC, (a+bu)+ηbt=μC, and p(a+bu)cλbt=μqC. If μ0, then qC and, thus, p+qC, a contradiction.

    Again, if μ=0, then t1v+ηq=λC, (a+bu)+ηbt=0, and p(a+bu)c=λbt. Thus, in this situation, we get our Conclusion (4).

    b) Now, if (a+bu)C, then Eq (3.14) transforms into the following:

    (p(a+bu)c)Π2btΠ2t1v+Π2(a+bu)q=0 (3.16)

    for all Π[R,R]. By Lemma 3.1, one of the following holds:

    R satisfies s4, which is our Conclusion (5).

    t1vC and (p(a+bu)c)bv=(a+bu)qC. In this situation, we get Δ1(π)=(a+bu)π and Δ2(π)=(c+bv)π for all πR with q(a+bu)=(c+bv)p(a+bu). This is our Conclusion (2).

    t1v,(a+bu)qC, and p(a+bu)+(a+bu)qcbv=0. In this situation, we get our conclusion from previous arguments.

    (p(a+bu)c),btC, and p(a+bu)+(a+bu)qcbv=0. The functions Δ1 and Δ2 take the form Δ1(π)=(a+bu)π, Δ2(π)=cπ+πbv for all πR with (p+q)(a+bu)=(c+bv). This is our Conclusion (2).

    bt,(a+bu)q,t1vC, and p(a+bu)c+(a+bu)q=bvC. Thus, the functions Δ1 and Δ2 take the form Δ1(π)=(a+bu)π, Δ2(π)=(c+bv)π for all πR with q(a+bu)=(c+bv)(a+bu)p. This is our Conclusion (2).

    ● There exist η,λ,μC such that (a+bu)q+ηt1v=λ, btη=μ, and (p(a+bu)c)+λ=μt1vC. If μ0, then q,t1vC. Thus, from Eq (3.16), we get (p+q)(a+bu)=(c+bv). Hence, in this situation, the functions Δ1 and Δ2 take the form Δ1(π)=(a+bu)π, Δ2(π)=(c+bv)π for all πR. This is our Conclusion (3).

    Now, if μ=0, then bt,p(a+bu)cC. Then, by previous arguments, we get our Conclusion (2).

    Case 2: Since R and Qr satisfy the same differential polynomial identities with coefficients in Qr (see Fact 2.2), it follows from Eq (3.8) that:

    pΠaΠ+pΠbα(Π)u+aΠ2q+bα(Π)uΠqcΠ2bα(Π2)v=0, (3.17)

    for all Π=[π1,π2][Qr,Qr]. If α is an outer derivation, then by Fact 2.4, we have:

    p[π1,π2]a[π1,π2]+p[π1,π2]b[ξ1,ξ2]u+a[π1,π2]2q+b[ξ1,ξ2]u[π1,π2]qc[π1,π2]2b[ξ1,ξ2]2v=0, (3.18)

    for all π1,π2,ξ1,ξ2R. In particular, Qr satisfies b[ξ1,ξ2]2v=0, which implies either b=0 or v=0.

    If b=0, then Eq (3.18) simplifies to:

    p[π1,π2]a[π1,π2]+a[π1,π2]2qc[π1,π2]2=0, (3.19)

    for all π1,π2R. Thus, from Sub-case (b) of Case 1, we reach our conclusions. Now, if v=0, then Eq (3.18) reduces to:

    p[π1,π2]a[π1,π2]+p[π1,π2]b[ξ1,ξ2]u+a[π1,π2]2q+b[ξ1,ξ2]u[π1,π2]qc[π1,π2]2=0, (3.20)

    for all π1,π2,ξ1,ξ2R. Specifically, Qr satisfies:

    p[π1,π2]b[ξ1,ξ2]u+b[ξ1,ξ2]u[π1,π2]q=0, (3.21)

    for all π1,π2,ξ1,ξ2R. Setting ξ1=π1 and ξ2=π2 in Eq (3.21), we get:

    p[π1,π2]b[π1,π2]u+b[π1,π2]u[π1,π2]q=0, (3.22)

    for all π1,π2R. Now, by Lemma (3.4), either bC or uC.

    Sub-case 1: First, we assume that bC. Then, Eq (3.22) reduces to:

    p[π1,π2]2bu+[π1,π2]bu[π1,π2]q=0, (3.23)

    for all π1,π2R. Similarly, by parallel arguments, we obtain buC or q,buqC.

    Assume that buC. If bu0, then from Eq (3.23), we have:

    p[π1,π2]2+[π1,π2]2q=0, (3.24)

    for all π1,π2R. Then, by Lemma 3.6, R either satisfies s4, which is our conclusion, or p+q=0, a contradiction.

    If bu=0, then either b=0 or u=0. If b=0, we conclude as before. Assuming u=0, then from Eq (3.20), Qr satisfies:

    p[π1,π2]a[π1,π2]+a[π1,π2]2qc[π1,π2]2=0, (3.25)

    for all π1,π2R. Eq (3.25) is analogous to Eq (3.14), and thus, we reach the required conclusion by previous arguments.

    Now, assume that q,buqC. If q0, then buC. Thus, the conclusion follows from the previous argument. If q=0, then from Eq (3.23), we get p[π1,π2]2bu=0. It follows from [25] that either p=0 or bu=0. If p=0, then p+q=0C, a contradiction. Again, if bu=0, then we get our conclusion from previous arguments.

    Suba-case 2: If uC, then we get our conclusion by previous arguments.

    In this final section, we aim to prove the main result, Theorem 1.6. Throughout the proof, we assume that R does not satisfies s4. According to [26], there exist elements a,cQr and skew derivations d and g associated with the automorphism α, such that Δ1(π)=aπ+bd(π) and Δ2(x)=cπ+bg(π) for all πR. Given that L is noncentral and the characteristic of R is not 2, there is a nonzero ideal J of R such that 0[J,R]L (see [27], p.45; [28], Lemma 2 and Proposition 1; [29], Theorem 4). Consequently, we have:

    pΠΔ1(Π)+Δ1(Π)Πq=Δ2(Π2),for all Π[J,J].

    Since R, Qr, and J satisfy the same generalized differential identities, the following holds for all X[R,R]:

    pΠΔ1(Π)+Δ(Π)Πq=Δ2(Π2).

    Thus, Qr satisfies:

    p[π,ξ]a[π,ξ]+p[π,ξ]bd([π,ξ])+a[π,ξ]2q+bd([π,ξ])[π,ξ]qc[π,ξ]2bg([π,ξ]2)=0, (4.1)

    for all π,ξR.

    dis a skew inner derivation andgis a skew outer derivation.

    Since d is a skew inner derivation of R, there exists an element bQr such that d(π)=bπα(π)b for all πR. Substituting this into Eq (4.1), we obtain:

    p[π,ξ]a[π,ξ]+p[π,ξ]b(b[π,ξ]α([π,ξ])b)+a[π,ξ]2q+b(b[π,ξ]α([π,ξ])b)[π,ξ]qc[π,ξ]2bg([π,ξ]2)=0 (4.2)

    for all π,ξR.

    Applying the definition of g, we have:

    p[π,ξ]a[π,ξ]c[π,ξ]2+p[π,ξ]b(b[π,ξ]α([π,ξ])b)+a[π,ξ]2q+b(b[π,ξ]α([π,ξ])b)[π,ξ]qb{(g(π)ξ+α(π)g(ξ)g(ξ)πα(ξ)g(π))[π,ξ]+α([π,ξ])(g(π)ξ+α(π)g(ξ)g(ξ)πα(ξ)g(π))}=0, (4.3)

    for all π,ξR. Since g is a skew outer derivation, applying Chuang's theorem (see Fact 2.4) to Eq (4.3), we obtain:

    p[π,ξ]a[π,ξ]+p[π,ξ]b(b[π,ξ]α([π,ξ])b)+a[π,ξ]2q+b(b[π,ξ]α([π,ξ])b)[π,ξ]qc[π,ξ]2b{(s1ξ+α(π)s2s2πα(ξ)s1)[π,ξ]+α([π,ξ])(s1ξ+α(π)s2s2πα(ξ)s1)}=0, (4.4)

    for all π,ξ,s1,s2R. Specifically, setting s2=0 in Eq (4.4), we obtain:

    b{(α(π)s2s2π)[π,ξ]+α([π,ξ])(α(π)s2s2π)}=0, (4.5)

    for all π,ξ,s2R.

    Now, if the automorphism α is not inner, then according to [30], Eq (4.5) simplifies to:

    b{(s3s2s2π)[π,ξ]+[s3,s4](s3s2s2π)}=0,

    for all π,ξ,s3,s2R. In particular, we have:

    2b[π,ξ]2=0b=0,

    which implies that both Δ1 and Δ2 are inner b-generalized skew derivations, contradicting our initial assumption.

    Furthermore, if α is an inner automorphism, then there exists some tQr such that α(π)=tπt1, and Eq (4.5) simplifies to:

    b{(tπt1s2s2π)[π,ξ]+t[π,ξ]t1(tπt1s2s2π)}=0, (4.6)

    for all π,ξ,s2R.

    In particular, setting s2=tξ, we get:

    2bt[π,ξ]2=0bt=0b=0,

    which again leads to a contradiction.

    dis skew outer andgis skew inner derivation.

    In this scenario, there exists an element cQr such that g(π)=cπα(π)c for all πR. Consequently, Eq (4.1) simplifies to:

    p[π,ξ]a[π,ξ]+p[π,ξ]b(d(π)ξ+α(π)d(ξ)d(ξ)πα(ξ)d(π))+a[π,ξ]2q+b(d(π)ξ+α(π)d(ξ)d(ξ)πα(ξ)d(π))[π,ξ]qc[π,ξ]2b(c[π,ξ]2α([π,ξ]2)c)=0 (4.7)

    for all π,ξR. Since d is an outer derivation, by applying Fact 2.4, Eq (4.7) further reduces to:

    p[π,ξ]a[π,ξ]+p[π,ξ]b(s1ξ+α(π)s2s2πα(ξ)s1)c[π,ξ]2b(c[π,ξ]2+a[π,ξ]2q+b(s1ξ+α(π)s2s2πα(ξ)s1)[π,ξ]q)α([π,ξ]2)c=0 (4.8)

    for all π,ξ,s1,s2R. In particular, setting s2=0 in Eq (4.8), Qr satisfies the following:

    p[π,ξ]b(α(π)s2s2π)+b(α(π)s2s2π)[π,ξ]q=0 (4.9)

    for all π,ξ,s2R.

    Now, if the automorphism α is not inner, then according to [30], Eq (4.9) simplifies to:

    p[π,ξ]b(z1s2s2π)+b(z1s2s2π)[π,ξ]q=0

    for all π,ξ,z1,s2R. Specifically, we have:

    p[π,ξ]b[π,ξ]+b[π,ξ]2q=0 (4.10)

    for all π,ξR. By Lemma 3.5, it follows that either p,pbC, or bC.

    First, assume that p,pbC. If p=0, then from Eq (4.10), we get q=0, implying p+q=0, which is a contradiction. If p0, then bC, and thus, from Eq (4.10) we obtain [π,ξ]2(p+q)=0, implying p+q=0, which is also a contradiction.

    Next, if bC, similar arguments lead to the conclusion that p+q=0, again resulting in a contradiction.

    Moreover, if the automorphism α is inner, there exists an element tQr such that α(π)=tπt1. In this case, Eq (4.9) reduces to:

    p[π,ξ]b(tπt1s2s2π)+b(tπt1s2s2π)[π,ξ]q=0 (4.11)

    for all π,ξ,s2R. Substituting s2=tξ into Eq (4.11), we obtain:

    p[π,ξ]bt[π,ξ]+bt[π,ξ]2q=0 (4.12)

    for all π,ξR. Since Eq (4.12) is analogous to Eq (4.10), the previous arguments lead us to the same contradiction.

    Now, let's consider the case where both d and g are skew outer derivations. Then, we have the following scenarios:

    dandgareC-modulo independent.

    In this case, after applying the definitions of d and g, Qr satisfies the following equation:

    p[π,ξ]a[π,ξ]+p[π,ξ]b(d(π)ξ+α(π)d(ξ)d(ξ)πα(ξ)d(π))+a[π,ξ]2q+b(d(π)ξ+α(π)d(ξ)d(ξ)πα(ξ)d(π))[π,ξ]qc[π,ξ]2b{(g(π)ξ+α(π)g(ξ)g(ξ)πα(ξ)g(π))[π,ξ]+α([π,ξ])(g(π)ξ+α(π)g(ξ)g(ξ)πα(ξ)g(π))}=0 (4.13)

    for all π,ξR. Then, by Chuang's theorem (see Fact 2.4), Eq (4.13) reduces to

    p[π,ξ]a[π,ξ]+p[π,ξ]b(s1ξ+α(π)s2s2πα(ξ)s1)+a[π,ξ]2qc[π,ξ]2+b(s1ξ+α(π)s2s2πα(ξ)s1)[π,ξ]qb{(s3ξ+α(π)s4s4πα(ξ)s3)[π,ξ]+α([π,ξ])(s3ξ+α(π)s4s4πα(ξ)s3)}=0 (4.14)

    for all π,ξ,s1,s2,s3,s4R. Choosing s4=0 in Eq (4.14), we obtain:

    b{(α(π)s2s2π)[π,ξ]+α([π,ξ])(α(π)s2s2π)}=0 (4.15)

    for all s2,π,ξR. Now, Eq (4.15) is analogous to Eq (4.5). Therefore, using similar arguments as in Case 1, we arrive at a contradiction.

    dandgareC-modulo dependent.

    Consider the case where Δ1(π)=aπ+bd(π) and Δ2(π)=cπ+bg(π) for all πR, where a,cQr are suitable constants, and d and g are nonzero skew derivations of R associated with the automorphism α. Additionally, assume that d and g are linearly C-dependent modulo inner skew derivations. Then, there exist η,τC, vQr, and an automorphism ϕ of R such that

    ηd(π)+τg(π)=vπϕ(π)v,for all πR.

    Case 1: η0 and τ0. Then, we have

    d(π)=a1g(π)+(a2πϕ(π)a2),for all πR,where a1=η1τ,a2=η1v.

    It is important to note that if d is an inner skew derivation, then, according to Fact 2.9, g also becomes an inner skew derivation. In this case, the conclusion follows directly from Proposition 3.7. Therefore, in the following analysis, we will assume that d is a nonzero outer skew derivation. Consequently, using Fact 2.8, we conclude that either ϕ=α or a2=0. Summarizing, we reach one of the following conclusions:

    a) d(π)=a1g(π)+(a2πα(π)a2),

    b) d(π)=a1g(π).

    We now demonstrate that each of these conditions leads to a contradiction. For brevity, we focus on Case 1, as it can be shown that Case 2 follows from Case 1. Thus, let d(π)=a1g(π)+(a2πα(π)a2) for all πR.

    Thus, from Eq (4.1), we have

    p[π,ξ]a[π,ξ]+p[π,ξ]b(a1g([π,ξ])+(a2[π,ξ]α([π,ξ])a2))c[π,ξ]2+a[π,ξ]2q+b(a1g([π,ξ])+(a2[π,ξ]α([π,ξ])a2))[π,ξ]qbg([π,ξ])2=0 (4.16)

    for all π,ξR. Using the definition of g in Eq (4.16), we have

    p[π,ξ]a[π,ξ]+a[π,ξ]2q+b{a1(g(π)ξ+α(π)g(ξ)g(ξ)πα(ξ)g(π))}[π,ξ]q+p[π,ξ]b{a1(g(π)ξ+α(π)g(ξ)g(ξ)πα(ξ)g(π))+(a2[π,ξ]α([π,ξ])a2)}b{(g(π)ξ+α(π)g(ξ)g(ξ)πα(ξ)g(π))[π,ξ]+α([π,ξ])(g(π)ξ+α(π)g(ξ)g(ξ)πα(ξ)g(π))}+b{a2[π,ξ]α([π,ξ])a2}[π,ξ]qc[π,ξ]2=0 (4.17)

    for all π,ξR. Applying Fact 2.4 in Eq (4.17), we obtain:

    p[π,ξ]a[π,ξ]+a[π,ξ]2qc[π,ξ]2+p[π,ξ]b{a1(s1ξ+α(π)s2s2πα(ξ)s1)+(a2[π,ξ]α([π,ξ])a2)}b{(s1ξ+α(π)s2s2πα(ξ)s1)[π,ξ]+α([π,ξ])(s1ξ+α(π)s2s2πα(ξ)s1)}+b{a1(s1ξ+α(π)s2s2πα(ξ)s1)+(a2[π,ξ]α([π,ξ])a2)}[π,ξ]q=0 (4.18)

    for all π,ξ,s1,s2R. Now, choosing s1=0 in Eq (4.18), we obtain:

    p[π,ξ]b(a1(s1ξα(ξ)s1))+b(a1(s1ξα(ξ)s1))[π,ξ]qb{(s1ξα(ξ)s1)[π,ξ]+[α(π),α(ξ)](s1ξα(ξ)s1)}=0 (4.19)

    for all π,ξ,s1R. If the automorphism α is not inner, then from [15]

    p[π,ξ]b(a1(s1ξs3s1))+b(a1(s1ξs3s1))[π,ξ]qb{(s1ξs3s1)[π,ξ]+[s1,s3](s1ξs3s1)}=0 (4.20)

    for all π,ξ,s1,s3R. In particular, choosing π=0 and ξ=s3 in Eq (4.20), we have

    b[s1,s3]2=0 (4.21)

    for all s1,s3R, which implies that b=0, a contradiction. Suppose the automorphism α is inner, then there exists tQr such that α(π)=tπt1, and Eq (4.19) takes the form

    p[π,ξ]b(a1(s1ξtξt1s1))+b(a1(s1ξtξt1s1))[π,ξ]qb{(s1ξtξt1s1)[π,ξ]+[tπt1,tξt1](s1ξtξt1s1)}=0 (4.22)

    for all π,ξ,s1R. In particular, choosing s1=ts1 and π=tπ in Eq (4.22), we obtain:

    p[π,ξ]bt(a1(s1ξξs1))+b(a1t(s1ξξs1))[π,ξ]qbt{(s1ξξs1)[π,ξ]+[π,ξ](s1ξξs1)}=0 (4.23)

    for all π,ξ,s1R. In particular, we get:

    p[π1,π2]bta1[π1,π2]+bta1[π1,π2]2q2bt[π1,π2]2=0 (4.24)

    for all π1,π2R. Thus, from Lemma (3.4), we get p+qC, a contradiction.

    Case 2: η=0 and τ0. Then, we have

    g(π)=a2πϕ(π)a2, for all πR, where a2=τ1v.

    In this case, we can assume that the skew derivation d is not inner. If it were inner, the conclusion would follow from Proposition 3.7. Additionally, since the automorphism associated with a skew derivation is unique, in this scenario, we have ϕ=α. Therefore, Qr satisfies:

    p[π,ξ]a[π,ξ]+p[π,ξ]bd([π,ξ])+a[π,ξ]2q+bd([π,ξ])[π,ξ]qc[π,ξ]2b(a2[π,ξ])2α([π,ξ]2a2))=0 (4.25)

    for all π,ξR. Applying the definition of d in Eq (4.25), we get

    p[π,ξ]a[π,ξ]+p[π,ξ]b{d(π)ξ+α(π)d(ξ)d(ξ)πα(ξ)d(π)}+a[π,ξ]2qc[π,ξ]2+b{d(π)ξ+α(π)d(ξ)d(ξ)πα(ξ)d(π)}[π,ξ]qb(a2[π,ξ])2α([π,ξ]2a2))=0 (4.26)

    for all π,ξR. Then by using Fact 2.4 in Eq (4.26), we obtain:

    p[π,ξ]a[π,ξ]+p[π,ξ]b(s2ξ+α(π)s1s1πα(ξ)s2)+a[π,ξ]2qc[π,ξ]2+b(s2ξ+α(π)s1s1πα(ξ)s2)[π,ξ]qb(a2[π,ξ])2α([π,ξ]2a2))=0 (4.27)

    for all π,ξ,s2,s1R. In particular, choosing s1=0 in Eq (4.27), Qr satisfies the blended component

    p[π,ξ]b(α(π)s1s1π)+b(α(π)s1s1π)[π,ξ]q=0 (4.28)

    for all π,ξ,s1R. The above Eq (4.28) is similar to Eq (4.9), therefore this case also leads to a contradiction.

    Case 3: η0 and τ=0. Then, we have

    d(π)=a1πϕ(π)a1, for all πR, where a1=η1v.

    Similar to Case 2, here we are assuming that g is not inner and α=ϕ. Hence, Qr satisfies:

    p[π,ξ]a[π,ξ]+p[π,ξ]b(a1[π,ξ]α([π,ξ]a1))+a[π,ξ]2q+b(a1[π,ξ]b{(g(π)ξ+α(π)g(ξ)g(ξ)πα(ξ)g(π))[π,ξ]+α([π,ξ])(g(π)ξ+α(π)g(ξ)g(ξ)πα(ξ)g(π))}α([π,ξ]a1))[π,ξ]qc[π,ξ]2=0 (4.29)

    for all π,ξR. Then, from Fact 2.4, we have

    p[π,ξ]a[π,ξ]+p[π,ξ]b(a1[π,ξ]α([π,ξ]a1))α([π,ξ]a1))[π,ξ]qc[π,ξ]2b{(s2ξ+α(π)s1s1πα(ξ)s2)[π,ξ]+α([π,ξ])(s2ξ+α(π)s1s1πα(ξ)s2)}+a[π,ξ]2q+b(a1[π,ξ])=0 (4.30)

    for all π,ξ,s2,s1R. Choosing s1=0 in Eq (4.30), we have

    b{α(π)s1s1π)[π,ξ]+α([π,ξ])(α(π)s1s1π)}=0 (4.31)

    for all π,ξ,s1R. The above (4.31) is similar to Eq (4.5), therefore, this case also leads to a contradiction.

    In this article, we characterize all possible forms of b-generalized skew derivations Δ1 and Δ2 that satisfy the identity pπΔ1(π)+Δ1(π)πq=Δ2(π2) for all πL. The advantage of the methodology used in this article is that it can be applied to all additive maps for which Facts 2.3 and 2.4 hold. Unfortunately, however, it does not hold for many additive maps for example, it is not valid for (α,β)-derivations [31].

    It would be an interesting problem to study this identity further by considering the case p+qC or by examining the identity pπΔ1(π)+Δ1(π)Δ3(π)=Δ2(π2), for all πL, where Δ3 is another b-generalized skew derivation.

    Ashutosh Pandey: contributed to the conceptualization and formulation of the problem, conducted a significant portion of the mathematical analysis, and participated in drafting the manuscript; Mani Shankar Pandey: played a central role in developing the theoretical framework, performing key computations, and revising the manuscript; Omaima Alshanqiti: provided guidance on the research methodology, assisted with the mathematical proofs, and was involved in reviewing and refining the manuscript. All authors read and approved the final version of the manuscript.

    We would like to extend our sincere gratitude to the referees for their insightful comments and suggestions, which have greatly contributed to improving the quality of this paper.

    The authors declare that they have no conflicts of interest or competing interests that could have influenced the results and/or discussion presented in this paper.



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