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Research article

Existence and uniqueness of solution for a class of non-Newtonian fluids with non-Newtonian potential and damping

  • Received: 07 February 2023 Revised: 28 February 2023 Accepted: 08 March 2023 Published: 17 March 2023
  • This paper discusses the existence and uniqueness of local strong solution for a class of 1D non-Newtonian fluids with non-Newtonian potential and damping term. Here we allow the initial vacuum and viscosity term to be fully nonlinear.

    Citation: Qiu Meng, Yuanyuan Zhao, Wucai Yang, Huifang Xing. Existence and uniqueness of solution for a class of non-Newtonian fluids with non-Newtonian potential and damping[J]. Electronic Research Archive, 2023, 31(5): 2940-2958. doi: 10.3934/era.2023148

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  • This paper discusses the existence and uniqueness of local strong solution for a class of 1D non-Newtonian fluids with non-Newtonian potential and damping term. Here we allow the initial vacuum and viscosity term to be fully nonlinear.



    We consider the following class of 1D non-Newtonian fluids

    {ρt+(ρu)x=0,ρΦx+(ρu2)x+(ρu)t(|ux|p2ux)x+Px=αρu,(|Φq2x|Φx)x=4πg(ρ1|Ω|Ωρdx), (1.1)

    where u, ρ, M=ρu and P=Aργ(A>0,γ>1) denote velocity, the unknown density, momentum and pressure, respectively, g>0 is the acceleration of gravity and Φ is the gravitational potential. The constant α>0 models friction. Without losing generality, throughout the paper we take α=1. The initial and boundary value conditions of Eq (1.1) are as follows

    {(ρ,u,Φ)|t=0=(ρ0,u0,Φ0), for all x[0,1],u(0,t)=u(1,t)=0, for all t[0,T],Φ(0,t)=Φ(1,t)=0, for all t[0,T]. (1.2)

    Ω is considered as a one-dimensional bounded interval here. Furthermore, for simplicity, we only assume the Ω=I=(0,1), ΩT=I×(0,T). The initial density ρ00, p and q are given constants, and they are both studied in the case of less than 2, where since the method of study is similar for 1<p<43 and 43<p<2, we next study only the case of 43<p<2.

    According to classical Newtonian fluid mechanics, in parallel fluids, the shear force is proportional to shear velocity, and its proportion is the viscosity coefficient, i.e.,

    Γ=Γ(ρ,u)=μu,μ>0.

    Generally, we call a fluid with the above properties a Newtonian fluid. Accordingly, a fluid does not have this property is called a non-Newtonian fluid. For non-Newton fluids, Γ(ρ,u) has a reasonable choice (see Ladyzhenskaya[1])

    Γij=(μ0+μ1|E(u)|p2)Eij(u),

    and

    Eij(u)=12(uixj+ujxi).

    In chemistry, biomechanics, glaciology, geology, and blood rheology, there are many problems in non-Newtonian fluids, which lead to an interest in studying non-Newtonian fluids [2,3,4]. There are many theoretical and experimental studies in non-Newtonian fluid flow.

    In this paper, the vacuum condition i.e., the initial density, is zero. Strictly speaking, a vacuum, a gas state below atmospheric pressure in a given space, is a physical phenomenon. In real life, vacuum distillation, vacuum drying, and vacuum concentration are typical vacuum cases. The role of vacuum in vacuum distillation is mainly to reduce the boiling point temperature of substances and reduce the influence of temperature factors on substances. Vacuum drying and concentration both use a vacuum environment to accelerate the volatilization and evaporation of specific substances or enable the whole process to be completed at lower conditions. In particular, non-Newtonian fluids can expand in a vacuum. According to the experiment, as the air in the vacuum bottle decreases, tiny bubbles gradually appear on the surface of the non-Newtonian fluid, and the bubbles expand until they spill the container out. In any case, the theoretical knowledge of non-Newtonian fluids under vacuum must be continuously refined. To this end, this article allows for an initial vacuum.

    In 1996, J. Málek, J. Neˇcas, M. Rokyta, M. R˙uˇziˇcka divided non-Newnewton flows with regard to p in the monograph [5] : when 1<p<2, we call such a fluid a shear thinning fluid, when p>2, we call such a fluid a shear thickening fluid. For non-Newtonian fluids, Yuan Hongjun and Xu Xiaojing [6] studied existence of a solution and whether it is unique of a class of non-Newtonian fluid solution with singularity and vacuum. Takashi Suzuki and Takayuki Kobayashi [7] proved the existence of weak solution to the Navier-Stokes-Poisson equation. Meng Qiu and Yuan Hongjun [8] proved the existence and uniqueness of a class of local solution under conditions where compressible non-Newtonian fluids with a non-Newtonian bit potential in a one-dimensional bounded interval. Song Yukun, Yuan Hongjun, and Yang Chen [9] investigated the existence and uniqueness of a class of local solution in the presence of isentropic compressible non-Newtonian fluids in a one-dimensional bounded area. Liu Hongzhi, Yuan Hongjun, Qiao Jiezeng and Li Fanpei [10] constructed the global existence of robust solution of Navier-Stokes equations with non-Newtonian potential. Li Huapeng and Yuan Hongjun [11] demonstrated the local existence and uniqueness of 1D non-Newtonian fluid solution with damping.

    The damping item comes from resistance to fluid motion. Model (1.1) describes more natural phenomena. For example, porous media flow. We can refer to [12,13,14,15] contents of the damp item. However, for non-Newtonian fluid, there is no degradation result with non-Newtonian potential and damp item. We construct a system (1.1)–(1.2) with local existence and uniqueness of the strong solution of non-Newtonian fluids with the non-Newtonian potentials and friction damping. The result is the following theorem:

    Theorem 1. Assume that

    43<p<2,1<q<2,0ρ0H1(Ω),u0H10(I)H2(I),Φ0H20(I)H3(I)

    and that there is a function gL2(I), makes the following equation true almost everywhere on I:

    (|u0x|p2u0x)x+Px(ρ0)=ρ120g, (1.3)

    then there exists a small time T(0,+) and a unique strong solution (ρ,u,Φ) to the initial boundary value problem (1.1)–(1.2) such that:

    {ρC([0,T];H1(I)),ρtC([0,T];L2(I)),ΦL(0,T;H2(I)),ΦtL(0,T;H1(I)),uC([0,T];H10(I))L(0,T;H2(I)),utL2(0,T;H10(I)),ρutL(0,T;L2(I)),(|ux|p2ux)xC([0,T];L2(I)). (1.4)

    For the above theorem, we will be divided it into four parts to prove. In the first part, we use the iterative method to get the approximate solution system of problems (1.1)–(1.2) and then make a consistent estimate of its approximate solution. In the second part, the convergence of the approximate solution is proved by the weak convergence method. In the third and fourth parts, we demonstrated that a locally strong solution to problems (1.1)–(1.2) exists uniquely.

    Lemma 1. (Embedding inequality). Assume that f=0 on Ω, here ΩR1 is bounded and open, fC2+α(ˉΩ). Then

    |f|L(Ω)d12(Ω)|f|L2(Ω)

    where d(Ω) denotes the length of Ω.

    See the literature [4] for proof.

    The system of Eqs (1.1) we studied contains more unknowns, and (1.1)2 and (1.1)3 are non-linear, so we cannot get a direct solution (from Abelian theorem, the fifth and higher order algebraic equations have no analytical solution). Therefore, we are inspired to seek approximate solutions to the system of equations.

    Therefore, we apply an iterative approach to problems (1.1)–(1.2), which yields its approximate solution system.

    ρkt+uk1ρkx+uk1xρk=0, (2.1)
    ρkukt+ρkuk1ukx+ρkΦkx+Łεpuk+Pkx=ρkuk, (2.2)
    (|Φkx|q2Φkx)x=4πg(ρkm0), (2.3)
    {(ρk,uk,Φk)|t=0=(ρδ0,uε0,Φε0),x[0,1],uk(0,t)=uk(1,t)=0,t[0,T], (2.4)

    we take the initial mass m0=10ρ0(x)dx>0, Pk=P(ρk)=A(ρk)γ, A>0, γ>1, ρδ0=δ+ρ0Jδ, δ>0,

    Łεpuk=[(ε(ukx)2+1(ukx)2+ε)2p2ukx]x,

    For problem (2.5), uε0H2(I)H10(I) is a smooth solution to it

    {[(ε(uε0x)2+1(uε0x)2+ε)2p2u0x]x+Px(ρδ0)=(ρδ0)12g,uε0(0)=uε0(1)=0. (2.5)

    Then, we will conduct a consistent estimation of the approximate solution and prove that the limit of the approximate solution is just the solution of the Eqs (1.1)–(1.2).

    In order to do this, we will first get the uniform estimate on uε0. The uε0 is known from the smooth solution of the boundary value problem

    uε0xx=(ε(uε0x)2+1(uε0x)2+ε)p2((uε0x)2+ε)2(Px(ρδ0)(ρδ0)12g)(ε(uε0x)2+1)((uε0x)2+ε)(2p)(1ε2)(uε0x)2, (2.6)

    then

    |uε0xx|L2(I)|((uε0x)2+εε(uε0x)2+1)1p2|L(I)|Px(ρδ0)(ρδ0)12g|L2(I)(|uε0x|2L(I)+1)1p2(|(ρδ0)12g|L2(I)+|Px(ρδ0)|L2(I)) (2.7)
    (|uε0xx|2L2(I)+1)1p2(|(ρδ0)12g|L2(I)+|Px(ρδ0)|L2(I)).

    Using Young's inequality, we have

    |uε0xx|L2(I)C, (2.8)

    with the help of the Lemma 1, we get

    |uε0|L(I)+|uε0x|L(I)+|uε0xx|L2(I)C, (2.9)

    where C>0 is a constant that depends only on M0, which may not necessarily be fixed. Next, we denote

    M0=1+|ρ0|H1(I)+u0H10(I)H20(I)+|g|L2(I).

    For any fixed integer K, define

    JK(t)=max1kKsup0st(1+|ρk(s)|H1(I)+|uk(s)|W1,p0(I)+|ρkukt(s)|L2(I)), (2.10)

    then we will prove that JK(t) is locally bounded for 43<p<2. We estimate each term in JK(t) in the following sections.

    Multiplying (2.2) by ukt, Integrating over (0,1) concerning x and integrating over (0,t) to s gives, we can get

    t010ρk|ukt|2dxds+t010[(ε(ukx)2+1(ukx)2+ε)2p2ukx]ukxtdxds=10Pkukx(0)dx+10Pkukx(t)dxt010(Pktukx+ρkΦkxukt+ρkukukt+ρkuk1ukxukt)dxds. (2.11)

    We firstly compute the second term of (2.11), we obtain

    10[(ε(ukx)2+1(ukx)2+ε)2p2ukx]ukxtdx=12ddt10((ukx)20(εs+1s+ε)2p2ds)dx, (2.12)

    and

    (ukx)20(εs+1s+ε)2p2ds(ukx)20(s+1)p22ds=2p(((ukx)2+1)p21). (2.13)

    Substituting (2.12), (2.13) into (2.11), by (2.9) and Young's inequality, we have

    t0|ρkukt(s)|2L2(I)ds+1p10|ukx(t)|pdxC+10|Pkukx(t)|dxt010|Pktukx|dxdst010ρk|uk||ukt|dxdst010ρk|uk1||ukx||ukt|dxdst010ρk|Φkx||ukt|dxds. (2.14)

    By (2.1), we get

    Pkt=γPkuk1Pkxuk1.

    Then the above inequality can be expressed as

    t0|ρkukt(s)|2L2(I)ds+|ukx(t)|pLp(I)t010(|ρkukukt|+|ρkuk1ukxukt|+|ρkΦkxukt|dxds+10|Pkukx|dx+t010|Pkxuk1ukx|+γ|Puk1xukx|)dxds+CCηt0|ρkuk|2L2(I)ds+Cηt0|ρk(s)|L(I)|uk1x(s)|2Lp(I)|ukxx(s)|2L2(I)ds+C|Pk(t)|pp1Lpp1(I)+t0(Aγ|ρk|γ1L(I)|ρkx|L2(I)|uk1|L(I)|ukx(s)|L(I)+γ|P(s)|L(I)|uk1x(s)|Lp(I)|ukx(s)|L(I))ds+Cηt0|ρk|H1(I)|Φkxx|2L2(I)ds+12t0|ρkukt|2L2(I)(s)ds+12|ukx(t)|pLp(I)+C, (2.15)

    where 0<η1. To estimate the right part of the (2.14), we have the following estimates

    |ρk(t)|L(I)+|Pk(t)|H1(I)CJγK(t). (2.16)

    Using (2.1), we have

    10|Pk(t)|pp1dx=10|Pk(0)|pp1dx+t0s(10(Pk(s))pp1dx)dsC(1+t0J2γ+1p1K(s)ds). (2.17)

    By virtue of (2.2), we have

    [(ε(ukx)2+1(ukx)2+ε)2p2ukx]x=ρkukt+ρkΦkx+ρkuk1ukx+Pkx+ρkuk,

    then we have

    |ukxx|=(ε(ukx)2+1(ukx)2+ε)p2[(ukx)2+ε]2(ε(ukx)2+1)((ukx)2+ε)(2p)(1ε2)(ukx)2|ρkukt+ρkuk1ukx+ρkΦkx+Pkx+ρkuk|1p1(|ukx|2p+1)|ρkukt+ρkuk1ukx+ρkΦkx+Pkx+ρkuk|, (2.18)

    taking the above inequality by L2 norm, using Young's inequality, we obtain

    |ukxx|p1L2(I)C[1+|ρkukt|L2(I)+|ρkuk1ukx|L2(I)+|ρkΦkx|L2(I)+|Pkx|L2(I)+|ρkuk|L2(I)]C[1+|ρk|12L(I)|ρkukt|L2(I)+(|ρk|L(I)|uk1x|Lp(I)|ukx|p2Lp(I))2(p1)3p4+|ρk|H1(I)|Φkxx|L2(I)+|Pkx|L2(I)+|ρkuk|L2(I)]+12|ukxx|p1L2(I).

    We deal with |Φkxx|L2(I), by (2.3) we have

    |Φkxx|1q1|Φkx|2q|4πg(ρkm0)|,

    taking it by L2-norm, using Young's inequality and Lemma 1, we get

    |Φkxx|L2(I)CJ1q1K(t), (2.19)

    then

    |ukxx(t)|L2(I)CJ(4+p)γ3p4K(t)CJ6γ3p4K(t). (2.20)

    Using (2.14) and the above inequality, we get

    t0|ρkukt(s)|2L2(I)ds+|ukx(t)|pLp(I)C(1+t0J24γ3p4K(s)ds), (2.21)

    for all k,1kK.

    We differentiate (2.2) with respect to t, and multiply it by ukt, and integrating it over (0,1) with respect to x, we obtain

    12ddt10ρk|ukt|2(t)dx+10[(ε(ukx)2+1(ukx)2+ε)2p2ukx]tukxt(t)dx=10[(ukuktuk1ukxΦkx)ρktρkuk1tukxρkΦkxtρkukt]uktdx+10Pktukxtdx. (2.22)

    Since

    [(ε(ukx)2+1(ukx)2+ε)2p2ukx]tukxt=(ε(ukx)2+1(ukx)2+ε)p2(ε(ukx)2+1)((ukx)2+ε)(2p)(1ε2)(ukx)2((ukx)2+ε)2(ukxt)2(p1)((ukx)2+1)p22(ukxt)2, (2.23)

    let

    βk=((ukx)2+1)p24.

    by (2.20), we have

    |β1k|L(I)=|((ukx)2+1)2p4|L(I)(|ukx|2L(I)+1)2p4|ukx|2p2L(I)+1CJ3γ3p4K(t).

    Then (2.22) can be rewritten as

    12ddt10ρk|ukt|2dx+(p1)10((ukx)2+1)p22(ukxt)2dx102ρk|uk1||ukt||ukxt|dx+10|ρkx||uk1|2|ukx||ukt|dx+10|ρkx|uk1|uk (2.24)

    Using Sobolev embedding theorem and Young's inequality, we obtain

    In order to estimate , we need to deal with . Differentiating (2.3) with respect to , multiplying it by and integrating over , we have

    By (2.23), we have

    Let

    then

    we have

    Using Young's inequality, combining the above estimate we obtain

    Substituting into (2.24), integrating over on time variable, we have

    (2.25)

    then, from the above recursive relation, for , we obtain

    Thus, we deduce from (2.25) that

    (2.26)

    where is a positive constant, depending only on .

    To obtain the estimate of , we need to estimate

    Using (2.2), we get

    Since is a smooth solution, we obtain

    Thus, using (2.9), we deduce

    Taking a limit on for inequality , we obtain, as

    (2.27)

    We differentiate (2.1) concerning , multiply it by , integrating it over (0, 1) for , and using Sobolev embedding theorem, we obtain

    applying Gronwall's inequality, it follows that

    (2.28)

    Substituting (2.20) into the above inequality, we get

    (2.29)

    Using (2.29) and (2.1), we have

    (2.30)

    By virtue of (2.20), (2.27), (2.29) and (2.30), we conclude that

    (2.31)

    where are two positive constants, depending only on . By the definition of , we obtain

    (2.32)

    If

    then we take . On the other hand, if

    we can find , such that

    So we have

    and

    so

    then we have

    (2.33)

    Given this inequality, we can acquire a short-time such that:

    (2.34)

    It is demonstrated that the approximate solution strongly converge to the solution of the Eqs (1.1)–(1.2) with positive density. We give the following definition

    then we verify that satisfy the system of equations

    (3.1)
    (3.2)
    (3.3)

    the initial boundary value conditions are given as follows

    Multiplying (3.1) by , integrating over with respect to , we deduce that

    (3.4)

    where , for all and .

    Multiplying (3.2) by , integrating over with respect to , using (3.1), Hölder inequality and Lemma 1, we obtain

    (3.5)

    Let

    so

    (3.6)

    using (3.4) and (3.5), we have

    (3.7)

    Using (2.34), (3.7) and Young's inequality, (3.5) could be rewritten as

    (3.8)

    where , for all and . Using (2.31), we derive

    According to Eq (2.3)

    let's multiply both sides of this equation by , about in integral, available

    then

    By combining the above formula, Hlder inequality and Lemma 1 are obtained

    (3.9)

    Collecting (3.4), (3.8) and (3.9), we deduce that

    (3.10)

    Using Gronwall's inequality, we have

    Then, we choose and then so small that and , we get

    Hence, we combine the above inequalities, in view of Gronwall's inequality, we deduce that

    (3.11)

    Therefore, we conclude that the full sequence converges to a limit in the following strong sense:

    (3.12)
    (3.13)

    Combining (3.3) and the convergence of (3.12), we can get

    (3.14)

    From the lower semi-continuity of the norm, we get:

    (3.15)

    The proof of existence should be completed in three steps, namely, taking limits on , and . Since the method is similar, we will only describe the process of taking limits on below. The first two steps can be found in the literature [4].

    We take to be a very small positive number, let , is a mollifier on , is the unique smooth solution of the boundary value problem:

    there exists satisfies

    For there is a subsequence , as satisfing

    Therefore, satisfies the following problem

    There exists a , the initial-boundary value problem

    admits a unique solution . Moreover, satisfies the uniform estimate

    According to the above uniform estimate, by the lower semi-continuity of norm, as we deduce the following uniform estimate:

    Suppose is a strong solution to the problem (1.1)–(1.2), is also a strong solution to the problem (1.1)–(1.2), then we have

    (5.1)

    where .

    Then using Hölder inequality together with Lemma 1, we have

    By (3.7), we have

    where .

    Then, following from (5.1), by choosing , we derive

    (5.2)

    where .

    As is known from the definition of a strong solution, we take , then

    (5.3)

    where . Similarly, we have

    (5.4)

    where . Similarly, we have

    Combining , and , we obtain

    where . Using Gronwall's inequality, we can get

    then

    we can get

    Therefore

    The authors thank Beihua University for funding and supporting this work through The Science and Technology Research Project of the Jilin Provincial Education Department (Grant No.JJKH20220040KJ).

    The authors declare there is no conflicts of interest.



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