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Research article Special Issues

Revisiting Taibleson's theorem

  • Received: 26 November 2021 Revised: 25 January 2022 Accepted: 26 January 2022 Published: 10 February 2022
  • A new characterization of the weighted Taibleson's theorem for generalized Hölder spaces is given via a Hadamard-Liouville type operator (Djrbashian's generalized fractional operator).

    Citation: Humberto Rafeiro, Joel E. Restrepo. Revisiting Taibleson's theorem[J]. Electronic Research Archive, 2022, 30(2): 565-573. doi: 10.3934/era.2022029

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  • A new characterization of the weighted Taibleson's theorem for generalized Hölder spaces is given via a Hadamard-Liouville type operator (Djrbashian's generalized fractional operator).



    We consider a family of scalar conservation laws defined on an oriented graph Γ consisting of m incoming and n outgoing edges Ω, =1,m+n joining at a single vertex. Incoming edges are parametrized by x(,0] while outgoing edges by x[0,) in such a way that the junction is always located at x=0. We use the index i, i=1,,m, to refer to incoming edges and j, j=m+1,,m+n, for the outgoing ones.

    On the edge Ω we introduce a scalar conservation law, describing the evolution of a density ρ. Then on the incoming edges we have

    tρi+xfi(ρi)=0,t>0,x<0,i=1,...,m, (1)

    and on the outgoing ones

    tρj+xfj(ρj)=0,t>0,x>0,j=m+1,...,m+n. (2)

    The fluxes f1,...,fm+n, differ in general, however we assume that they are bell-shaped (unimodal), Lipschitz and non-degenerate nonlinear, i.e.

    (H.1) for each {1,...,m+n}, fC2([0,1]), f(0)=f(1)=0, f0, and there exist ¯ρ(0,1) such that f(ρ)(¯ρρ)>0 for every ρ[0,1]{¯ρ};

    (H.2) for any {1,...,m+n}, |{ρ:f(ρ)=0}|=0.

    We augment (1) and (2) with the initial conditions

    {ρi(0,x)=ρi,0(x),x<0,i=1,...,m,ρj(0,x)=ρj,0(x),x>0,j=m+1,...,m+n, (3)

    assuming that

    (H.3) ρ1,0,...,ρm,0L1(,0)BV(,0),

    ρm+1,0,...,ρm+n,0L1(0,)BV(0,)

    and 0ρ1,0,...,ρm+n,01.

    Finally, we introduce the necessary conservation assumption at the node, which transforms our family of independent equations into a single problem

    mi=1fi(ρi(t,0))=m+nj=m+1fj(ρj(t,0+)) for a.e. t0.

    Questions related to existence, uniqueness and stability of solutions for problems of this kind have been extensively investigated in recent years, mainly in relation with traffic modeling. The interested reader can refer to [7,13] for an overview of the subject. Here our point of view is different, as we do not focus on a specific model. We consider a parabolic regularization of the problem, similarly to what has been done in [11,10], but instead of enforcing a continuity condition at the node for the regularized solutions, we introduce a more general set of transmission conditions on the parabolic fluxes.

    In this work we adopt the following definition of weak solution for the problem (1), (2), and (3). We stress that this definition is for sure not sufficient to ensure uniqueness. On the contrary it fix somehow a minimal set of properties that any reasonable solution is expected to satisfy, see [3] and references therein for a more detailed discussion on this point.

    Definition 1.1. Let ρ1,...,ρm:[0,)×(,0]R and ρm+1,...,ρm+n:[0,)×[0,)R be functions. We say that (ρ1,....,ρm+n) is a weak solution of (1), (2), and (3) if

    (D.1) f1(ρ1),...,fm(ρm)BVloc((0,)×(,0)) and fm+1(ρm+1),...,fm+n(ρm+n)BVloc((0,)×(0,));

    (D.2) for every i{1,...,m}, every cR and every nonnegative test function φC(R×(,0)) with compact support

    00(|ρic|tφ+sign(ρic)(fi(ρi)fi(c))xφ)dtdx+0|ρi,0(x)c|φ(0,x)dx0;

    (D.3) for every j{m+1,...,m+n}, every cR and every nonnegative test function φC(R×(0,)) with compact support

    00(|ρjc|tφ+sign(ρjc)(fj(ρR)fj(c))xφ)dtdx+0|ρj,0(x)c|φ(0,x)dx0;

    (D.4) mi=1fi(ρi(t,0))=m+nj=m+1fj(ρj(t,0+)) for a.e. t0.

    Figure 1.  A junction consisting of m incoming and n outgoing edges.

    In [10] the authors approximated (1), (2), and (3) in the following way

    {tρi,ε+xfi(ρi,ε)=ε2xxρi,ε,t>0,x<0,i,tρj,ε+xfj(ρj,ε)=ε2xxρj,ε,t>0,x>0,j,ρi,ε(t,0)=ρj,ε(t,0),t>0,i,j,mi=1(fi(ρi,ε(t,0))εxρi,ε(t,0))=m+nj=m+1(fj(ρj,ε(t,0))εxρj,ε(t,0)),t>0,ρi,ε(0,x)=ρi,0,ε(x),x<0,i,ρj,ε(0,x)=ρj,0,ε(x),x>0,j, (4)

    where i{1,...,m} and j{m+1,...,m+n} and ρi,0,ε,ρj,0,ε are smooth approximations of ρi,0,ρj,0. In this setting they showed that

    ρi,ερia.e. in (0,)×(,0) andin Lploc((0,)×(,0)),1p<, as ε0 for every i,ρj,ερja.e. in (0,)×(0,) and in Lploc((0,)×(0,)),1p<, as ε0 for every j,

    where (ρ1,....,ρm+n) is a weak solution of (1), (2), (3), in the sense of Definition 1.1.

    In this paper we modify the transmission condition of (4) and inspired by [14] we consider the following viscous approximation of (1), (2), and (3)

    {tρi,ε+xfi(ρi,ε)=ε2xxρi,ε,t>0,x<0,i,tρj,ε+xfj(ρj,ε)=ε2xxρj,ε,t>0,x>0,j,fi(ρi,ε(t,0))εxρi,ε(t,0)=βi(ρ1,ε(t,0),....,ρm+n,ε(t,0)),t>0,i,fj(ρj,ε(t,0))εxρj,ε(t,0)=βj(ρ1,ε(t,0),....,ρm+n,ε(t,0)),t>0,j,ρi,ε(0,x)=ρi,0,ε(x),x<0,i,ρj,ε(0,x)=ρj,0,ε(x),x>0,j, (5)

    where, of course,

    mi=1βi(ρ1,ε(t,0),,ρm+n,ε(t,0))=m+nj=m+1βj(ρ1,ε(t,0),,ρm+n,ε(t,0)). (6)

    The additional assumptions we make on the functions β and on the initial conditions ρ,0,ε are postposed to the next section.

    The main result of the paper is the following.

    Theorem 1.2. Assume(H.1), (H.2), and (H.3). There exist a sequence {εk}kN(0,), εk0, and a solution (ρ1,,ρm+n) of (1), (2), and (3), in the sense of Definition 1.1, such that

    ρi,εkρi,a.e.andinLploc((0,)×(,0)), (7)
    ρj,εkρj,a.e.andinLploc((0,)×(0,)), (8)
    f1(ρ1),...,fm(ρm)BV((0,)×(,0)),fm+1(ρm+1),...,fm+n(ρm+n)BV((0,)×(0,)), (9)

    for every 1p<,i{1,..,m},j{m+1,..,m+n}, where (ρ1,εk,...,ρm+n,εk) is the corresponding solution of (5).

    It worth mentioning that a complete characterization of the limit solution obtained from (4) as ε0 is given in [3], where the authors adapt to a star shaped graph setting some ideas and techniques originally developed for conservation laws with discontinous flux, see in particular [2,4,5].

    At the moment we are not able to formulate a similar characterization of the limit of (5). In general, however, the limits coming from parabolic regularization subject to the two different kinds of transmission conditions are different.

    To show this consider the simple case of a junction with one incoming and one outgoing edges. So we have the conservation law

    tρ1+xf1(ρ1)=0,t>0,x<0, (10)

    on the incoming edge and

    tρ2+xf2(ρ2)=0,t>0,x>0, (11)

    on the outgoing one. Assume that

    f1(0)=f1(1)=f2(0)=f2(1)=0,f1,f2<0,there exists 0<ˇρ<ˆρ<1 and G>0 such that f1(ˆρ)=f2(ˇρ)=G(ˆρˇρ). (12)

    Consider the simplified version of (5)

    {tρ1,ε+xf1(ρ1,ε)=ε2xxρ1,ε,t>0,x<0,tρ2,ε+xf2(ρ2,ε)=ε2xxρ2,ε,t>0,x>0,f1(ρ1,ε(t,0))εxρ1,ε(t,0)=f2(ρ2,ε(t,0))εxρ2,ε(t,0)=G(ρ1,ερ2,ε),t>0,ρ1,ε(0,x)=ˆρ,x<0,ρ2,ε(0,x)=ˇρ,x>0. (13)

    The unique solution of (13) is

    ρ1,ε(,)=ˆρ,ρ2,ε(,)=ˇρ,ε>0. (14)

    Therefore, as ε0 we get the solution of (10)-(11)

    ρ1(,)=ˆρ,ρ2(,)=ˇρ. (15)

    This stationary solution is not admissible in the sense of the classical vanishing viscosity germ, see [5,Sec. 5], as it consists of a nonclassical shock. However, when dealing with conservation laws with discontinuous flux, it is well known that infinitely many L1 contractive semigroups of solutions exist, also in relation with different physical applications. In particular, when the right and left fluxes are bell-shaped, as we assume in condition (H.1), each of those notions of admissible solution is uniquely determined by the choice of a (A,B)-connection, see [1,5,9,12] for precise definitions and exemples. In the exemple above the couple (ˆρ,ˇρ) is a connection.

    It is worth noticing that entropy solutions admissible in the sense of a (A,B)-connection can be obtained as limits of a sequence of parabolic approximations made with adapted viscosities but a classical condition of continuity at the interface, see [5,Sec. 6.2] for a general result, but also [2,15] for an application to the Buckley-Leverett equation.

    It is difficult, however, to establish a direct equivalence between the aforementioned results and the one we put forward in this paper. In particular, in the present case we miss information on the boundary layers at the parabolic level and we do not know how the transmission conditions we impose on the parabolic fluxes translates into a condition for the hyperbolic problem.

    This means in particular that we have little information on the germ associated to the family of limit solutions obtained in Theorem 1.2 and, so far, we have not been able to prove that this germ is L1-dissipative. We conjecture, however, that this is due to a technical obstruction and that uniqueness of the limit solutions holds.

    The paper is organized as follows: Section 2 contains the precise list of assumptions on the initial and transmission conditions in the parabolic problem (5). In Section 3 we present the proofs of all necessary a priori estimates on (5). Finally, in Section 4 we detail the proof of Theorem 1.2.

    The initial conditions ρ,0, =1,,m+n, on the hyperbolic problem (1), (2), and (3) satisfy (H.3).

    Once the functions ρ,0 are fixed, we impose on (5) initial conditions ρ,0,ε such that

    ρi,0,εC((,0])L1(,0),ρj,0,εC([0,))L1(0,),ε>0,ρi,0,ερi,0a.e. in (,0) and in Lploc(,0),1p<, as ε0,ρj,0,ερj,0a.e. in (0,) and in Lploc(0,),1p<, as ε0,0ρi,0,ε,ρj,0,ε1,ε>0,ρi,0,εL1(,0)ρi,0L1(,0),ρj,0,εL1(0,)ρj,0L1(0,),ε>0,ρi,0,εL2(,0)ρi,0L2(,0),ρj,0,εL2(0,)ρj,0L2(0,),ε>0,xρi,0,εL1(,0)TV(ρi,0),xρj,0,εL1(0,)TV(ρj,0),ε>0,εxρi,0,εL1(,0),ε2xxρj,0,εL1(0,)C,ε>0, (16)

    for some constant C>0 independent on ε.

    The functions β appearing in the transmission conditions in (5) take the form

    βi(ρ1,ε(t,0),....,ρm+n,ε(t,0))=m+nj=m+1Gi,j(ρi,ε(t,0),ρj,ε(t,0))+ε(mh=1Ki,h(ρi,ε(t,0),ρh,ε(t,0))m+nh=1Kh,i(ρh,ε(t,0),ρi,ε(t,0))); (17)

    for i{1,,m}, and for j{m+1,,m+n}

    βj(ρ1,ε(t,0),....,ρm+n,ε(t,0))=mi=1Gi,j(ρi,ε(t,0),ρj,ε(t,0))+ε(m+nh=m+1Kh,j(ρh,ε(t,0),ρj,ε(t,0))m+nh=1Kj,h(ρj,ε(t,0),ρh,ε(t,0))). (18)

    The functions Gi,j(u,v)C(R2), i{1,,m}, j{m+1,,m+n}, and Kh,(u,v)C(R2), h,{1,,m+n}, satisfy

    vGi,j(,)0uGi,j(,),Gi,j(0,0)=Gi,j(1,1)=0,uKh,(,)0vKh,(,),Kh,(0,0)=Kh,(1,1)=0. (19)

    In particular, (19) implies

    (sign(u)sign(v))Gi,j(,)(u,v)0,u,vR,(sign(u)sign(v))Kh,(,)(u,v)0,u,vR,(sign(uu)sign(vv))(Gi,j(u,v)Gi,j(u,v))0,u,u,v,vR,(sign(uu)sign(vv))(Kh,(u,v)Kh,(u,v))0,u,u,v,vR,(χ(,0)(u)χ(,0)(v))Gi,j(u,v)0,u,vR,(χ(,0)(u)χ(,0)(v))Kh,(u,v)0,u,vR, (20)

    where χ(,0) is the characteristic function of the set (,0).

    This specific form of transmission conditions is reminiscent of the parabolic transmission conditions considered in [14,8], which were originally inspired from the Kedem-Katchalsky conditions for membrane permeability introduced in [16]

    Gh,(u,v)=ch,(uv), (21)

    for some constants ch,>0. Our conditions are more general and in particular we can notice that the function Gh, above satisfies

    Gh,(u,v)(uv)0, (22)

    that allows the authors in [14] to get the L2 conservation (see Lemma 3.3 below).

    We can observe that the equality (6) holds as

    mi=1βi(ρ1,ε(t,0),....,ρm+n,ε(t,0))=mi=1m+nj=m+1Gi,j(ρi,ε(t,0),ρj,ε(t,0))+εmi=1(mh=1Ki,h(ρi,ε(t,0),ρh,ε(t,0))m+nh=1Kh,i(ρh,ε(t,0),ρi,ε(t,0)))=mi=1m+nj=m+1(Gi,j(ρi,ε(t,0),ρj,ε(t,0))εKj,i(ρj,ε(t,0),ρi,ε(t,0))) (23)

    and analogously

    m+nj=m+1βj(ρ1,ε(t,0),....,ρm+n,ε(t,0))=m+nj=m+1mi=1(Gi,j(ρi,ε(t,0),ρj,ε(t,0))εKj,i(ρj,ε(t,0),ρi,ε(t,0))). (24)

    This section is devoted to establish a priori estimates, uniform with respect to ε, which are necessary toward the proof of our main convergence result in the next section.

    For every ε>0, let (ρ1,ε,...,ρm+n,ε) be a solution of (5) satisfying (16).

    Lemma 3.1 (L estimate). We have that

    0ρi,ε,ρj,ε1,i,j. (25)

    Proof. Consider the function

    η(ξ)=ξχ(,0)(ξ).

    Since

    η(ξ)=χ(,0)(ξ),

    using (19) we obtain

    ddt(mi=10η(ρi,ε)dx+m+nj=m+10η(ρj,ε)dx)=mi=10η(ρi,ε)tρi,εdx+m+nj=m+10η(ρj,ε)tρj,εdx=mi=10χ(,0)(ρi,ε)tρi,εdxm+nj=m+10χ(,0)(ρj,ε)tρj,εdx=mi=10χ(,0)(ρi,ε)x(fi(ρi,ε)εxρi,ε)dx+m+nj=m+10χ(,0)(ρj,ε)x(fj(ρj,ε)εxρj,ε)dx=mi=1χ(,0)(ρi,ε(t,0))(fi(ρi,ε(t,0))εxρi,ε(t,0))m+nj=m+1χ(,0)(ρj,ε(t,0))(fj(ρj,ε(t,0))εxρj,ε(t,0))+mi=10xρi,ε(fi(ρi,ε)εxρi,ε)dδ{ρi,ε=0}0+m+nj=m+10xρj,ε(fj(ρj,ε)εxρj,ε)dδ{ρj,ε=0}0m+nj=m+1mi=1(χ(,0)(ρi,ε(t,0))χ(,0)(ρj,ε(t,0)))(Gi,j(ρi,ε(t,0),ρj,ε(t,0))εKj,i(ρj,ε(t,0),ρi,ε(t,0)))0,

    where δ{ρi,ε=0} and δ{ρj,ε=0} are the Dirac deltas concentrated on the sets {ρi,ε=0} and {ρj,ε=0}, respectively and we apply [6,Lemma 2] to compute the value of the integrals as a limit. Integrating over (0,t) and using (16) we get

    0mi=10η(ρi,ε(t,x))dx+m+nj=m+10η(ρj,ε(t,x))dxmi=10η(ρi,0,ε)dx+m+nj=m+10η(ρj,0,ε)dx=0

    and then

    ρi,ε,ρj,ε0,i,j,

    that proves the lower bounds in (25). The upper bounds in (25) can be proved in the same way using the function ξ(ξ1)χ(1,)(ξ).

    Lemma 3.2 (L1 estimate). We have that

    mi=1ρi,ε(t,)L1(,0)+m+nj=m+1ρj,ε(t,)L1(0,)mi=1ρi,0L1(,0)+m+nj=m+1ρj,0L1(0,),t0. (26)

    Proof. Thanks to (5), (23), (24), and (25), we have that

    ddt(mi=10|ρi,ε|dx+m+nj=m+10|ρj,ε|dx)=ddt(mi=10ρi,εdx+m+nj=m+10ρj,εdx)=mi=10tρi,εdx+m+nj=m+10tρj,εdx=mi=10x(fi(ρi,ε)εxρi,ε)dxm+nj=m+10x(fj(ρj,ε)εxρj,ε)dx=mi=1βi(ρ1,ε(t,0),,ρm+n,ε(t,0))+m+nj=m+1βj(ρ1,ε(t,0),,ρm+n,ε(t,0))=0.

    Integrating over (0,t) and using (16) we get (26).

    Lemma 3.3 (L2 estimate). We have that

    mi=1ρi,ε(t,)2L2(,0)+m+nj=m+1ρj,ε(t,)2L2(0,)+2εt0(mi=1xρi,ε(s,)2L2(,0)+m+nj=m+1xρj,ε(s,)2L2(0,))dsmi=1ρi,02L2(,0)+m+nj=m+1ρj,02L2(0,)+2(m+n=1βL((0,1)m+n)+mi=1fiL1(0,1))t, (27)

    for every t0.

    Proof. Thanks to (5), we have that

    ddt(mi=10ρ2i,ε2dx+m+nj=m+10ρ2j,ε2dx)=mi=10ρi,εtρi,εdx+m+nj=m+10ρj,εtρj,εdx=mi=10ρi,εx(fi(ρi,ε)εxρi,ε)dxm+nj=m+10ρj,εx(fj(ρj,ε)εxρj,ε)dx=mi=1ρi,ε(t,0)(fi(ρi,ε(t,0))εxρi,ε(t,0))+m+nj=m+1ρj,ε(t,0)(fj(ρj,ε(t,0))εxρj,ε(t,0))+mi=10x(ρi,ε(t,x)0fi(ξ)dξ)dx+m+nj=m+10x(ρj,ε(t,x)0fj(ξ)dξ)dxεmi=10(xρi,ε)2dxεm+nj=m+10(xρj,ε)2dx=mi=1ρj,ε(t,0)βi(ρ1,ε(t,0),....,ρm+n,ε(t,0))m+nj=m+1ρi,ε(t,0))βj(ρ1,ε(t,0),....,ρm+n,ε(t,0))+mi=1ρi,ε(t,0)0fi(ξ)dξm+nj=m+1ρj,ε(t,0)0fj(ξ)dξ0εmi=10(xρi,ε)2dxεm+nj=m+10(xρj,ε)2dxm+n=1βL((0,1)m+n)+mi=1fiL1(0,1)εmi=10(xρi,ε)2dxεm+nj=m+10(xρj,ε)2dx.

    Integrating over (0,t) and using (16) we get (27).

    Lemma 3.4 (BV estimate). We have that

    mi=1tρi,ε(t,)L1(,0)+m+nj=m+1tρj,ε(t,)L1(0,)(m+n)C+mi=1fiL(0,1)TV(ρi,0)+m+nj=m+1fjL(0,1)TV(ρj,0), (28)

    for every t0.

    Proof. From (5) we get

    2ttρi,ε+x(fi(ρi,ε)tρi,ε)=ε3txxρi,ε,2ttρj,ε+x(fj(ρj,ε)tρj,ε)=ε3txxρj,ε,fi(ρi,ε(t,0))tρi,ε(t,0)ε2txρi,ε(t,0)=m+nj=m+1Gi,j(ρi,ε(t,0),ρj,ε(t,0))(tρi,ε(t,0),tρj,ε(t,0))+εmh=1Ki,h(ρi,ε(t,0),ρh,ε(t,0))(tρi,ε(t,0),tρh,ε(t,0))εm+nh=1Kh,i(ρh,ε(t,0),ρi,ε(t,0))(tρh,ε(t,0),tρi,ε(t,0)),fj(ρj,ε(t,0))tρj,ε(t,0)ε2txρj,ε(t,0)=mi=1Gi,j(ρi,ε(t,0),ρj,ε(t,0))(tρi,ε(t,0),tρj,ε(t,0))+εm+nh=m+1Kh,j(ρh,ε(t,0),ρj,ε(t,0))(tρh,ε(t,0),tρj,ε(t,0))εm+nh=1Kj,h(ρj,ε(t,0),ρh,ε(t,0))(tρi,ε(t,0),tρh,ε(t,0)).

    Thanks to (20), we have that

    ddt(mi=10|tρi,ε|dx+m+nj=m+10|tρj,ε|dx)=mi=102ttρi,εsign(tρi,ε)dx+m+nj=m+102ttρj,εsign(tρj,ε)dx=mi=10sign(tρi,ε)x(fi(ρi,ε)tρi,εε2txρi,ε)dxm+nj=m+10sign(tρj,ε)x(fj(ρj,ε)tρj,εε2txρj,ε)dx=mi=1sign(tρi,ε(t,0))(fi(ρi,ε(t,0))tρi,ε(t,0)ε2txρi,ε(t,0))+m+nj=m+1sign(tρj,ε(t,0))(fj(ρj,ε(t,0))tρj,ε(t,0)ε2txρj,ε(t,0))+2mi=102txρi,ε(fi(ρi,ε)tρi,εε2txρi,ε)dδ{tρi,ε=0}0+2m+nj=m+102txρj,ε(fj(ρj,ε)tρj,εε2txρj,ε)dδ{tρj,ε=0}0mi=1m+nj=m+1(sign(tρi,ε(t,0))sign(tρj,ε(t,0)))××Gi,j(ρi,ε(t,0),ρj,ε(t,0))(tρi,ε(t,0),tρj,ε(t,0))+εmi=1m+nj=m+1(sign(tρi,ε(t,0))sign(tρj,ε(t,0)))××Kj,i(ρi,ε(t,0),ρj,ε(t,0))(tρi,ε(t,0),tρj,ε(t,0))0,

    where δ{tρi,ε=0} and δ{tρj,ε=0} are the Dirac deltas concentrated on the sets {tρi,ε=0} and {tρj,ε=0}, respectively and we apply [6,Lemma 2].

    Integrating over (0,t) and using (16), (25) we get

    mi=1tρi,ε(t,)L1(,0)+m+nj=m+1tρj,ε(t,)L1(0,)mi=1tρi,ε(0,)L1(,0)+m+nj=m+1tρj,ε(0,)L1(0,)=mi=1ε2xxρi,0,εxfi(ρi,0,ε)L1(,0)+m+nj=m+1ε2xxρj,0,εxfj(ρj,0,ε)L1(0,)mi=1(ε2xxρi,0,εL1(,0)+fi(ρi,0,ε)L(,0)xρi,0,εL1(,0))+m+nj=m+1(ε2xxρj,0,εL1(0,)+fj(ρj,0,ε)L(0,)xρj,0,εL1(0,))(m+n)C+mi=1fiL(0,1)TV(ρi,0)+m+nj=m+1fjL(0,1)TV(ρj,0),

    that is (28).

    Lemma 3.5 (Stability estimate). Let (ρ1,ε,...,ρm+n,ε) and (¯ρ1,ε,...,¯ρm+n,ε) be two solutions of (5). The following estimate holds

    mi=1ρi,ε(t,)¯ρi,ε(t,)L1(,0)+m+nj=m+1ρj,ε(t,)¯ρj,ε(t,)L1(0,)mi=1ρi,0,ε¯ρi,0,εL1(,0)+m+nj=m+1ρj,0,ε¯ρj,0,εL1(0,),t0. (29)

    Proof. From (5) we get

    t(ρi,ε¯ρi,ε)+x(fi(ρi,ε)fi(¯ρi,ε))=ε2xx(ρi,ε¯ρi,ε),t(ρj,ε¯ρj,ε)+x(fj(ρj,ε)fj(¯ρj,ε))=ε2xx(ρj,ε¯ρj,ε).

    Thanks to (5), (20), and (25), we have that

    ddt(mi=10|ρi,ε¯ρi,ε|dx+m+nj=m+10|ρj,ε¯ρj,ε|dx)=mi=10sign(ρi,ε¯ρi,ε)t(ρi,ε¯ρi,ε)dx+m+nj=m+10sign(ρj,ε¯ρj,ε)t(ρj,ε¯ρj,ε)dx=mi=10sign(ρi,ε¯ρi,ε)x((fi(ρi,ε)fi(¯ρi,ε))εx(ρi,ε¯ρi,ε))dxm+nj=m+10sign(ρj,ε¯ρj,ε)x((fj(ρj,ε)fj(¯ρj,ε))εx(ρj,ε¯ρj,ε))dx=mi=1m+nj=m+1[sign(ρi,ε(t,0)¯ρi,ε(t,0))sign(ρj,ε(t,0)¯ρj,ε(t,0))]××[Gi,j(ρi,ε(t,0),ρj,ε(t,0))Gi,j(¯ρi,ε(t,0),¯ρj,ε(t,0))]+εmi=1m+nj=m+1[sign(ρi,ε(t,0)¯ρi,ε(t,0))sign(ρj,ε(t,0)¯ρj,ε(t,0))]××[Kj,i(ρi,ε(t,0),ρj,ε(t,0))Gi,j(¯ρi,ε(t,0),¯ρj,ε(t,0))]+2mi=10x(ρi,ε¯ρi,ε)((fi(ρi,ε)fi(¯ρi,ε))εx(ρi,ε¯ρi,ε))dδ{ρi,ε=¯ρi,ε}0+2m+nj=m+10x(ρj,ε¯ρj,ε)((fi(ρj,ε)fi(¯ρj,ε))εx(ρj,ε¯ρj,ε))dδ{ρj,ε=¯ρj,ε}00,

    where we use [6,Lemma 2] and we denote by δ{ρi,ε=¯ρi,ε} and δ{ρj,ε=¯ρj,ε} respectively the Dirac deltas concentrated on the sets {ρi,ε=¯ρi,ε} and {ρj,ε=¯ρj,ε}.

    Integrating over (0,t) we get (29).

    The well-posedness of smooth solutions for (5) can be proved following the argument used in [10,Theorem 1.2] to establish the well-posedness of smooth solutions for (4). Indeed, the existence of a linear semigroup of solutions in the linear case (i.e., when f0) is shown in [14]. Then the Duhamel Formula, estimates similar to the ones in the previous section and a fixed point argument lead to the result.

    The main result of this section is the following.

    Lemma 4.1. Let (ρ1,ε,...,ρm+n,ε) be the solution of (5). There exist a sequence {εk}kN(0,),εk0, and m+n maps ρ1,...,ρm+n such that

    ρ1,...,ρmL1((0,)×(,0))L((0,)×(,0)), (30)
    ρm+1,...,ρm+nL1((0,)×(0,))L((0,)×(0,)), (31)
    0ρ1,{1,...,m+n}, (32)
    ρi,εkρi,a.e.andinLploc((0,)×(,0)), (33)
    ρj,εkρj,a.e.andinLploc((0,)×(0,)), (34)

    for every 1p<,i{1,..,m},j{m+1,..,m+n}. Moreover, we have that

    mi=1ρi(t,)L1(,0)+m+nj=m+1ρj(t,)L1(0,) (35)
    mi=1ρi,0L1(,0)+m+nj=m+1ρj,0L1(0,),mi=1ρi(t,)2L2(,0)+m+nj=m+1ρj(t,)2L2(0,) (36)
    mi=1ρi,02L2(,0)+m+nj=m+1ρj,02L2(0,)+2(m+n=1βL((0,1)m+n)+mi=1fiL1(0,1))t,mi=1TV(fi(ρi(t,)))+m+nj=m+1TV(fj(ρj(t,)))=mi=1tρi(t,)M(,0)+m+nj=m+1tρj(t,)M(0,)(m+n)C+mi=1fiL(0,1)TV(ρi,0)+m+nj=m+1fjL(0,1)TV(ρj,0). (37)

    Thanks to the genuine nonlinearity of f1,...,fm+n, we can use the Tartar compensated compactness method [18] to obtain strong convergence of a subsequence of viscosity approximations. The notation R can stand for (0,) or (,0).

    Theorem 4.2 (Tartar). Let {vν}ν>0 be a family of functions defined on (0,)×R such that

    vνL((0,T)×R)MT,T,ν>0,

    and the family

    {tη(vν)+xq(vν)}ν>0

    is compact in H1loc((0,)×R), for every convex ηC2(R), where q=fη. Then there exist a sequence {νn}nN(0,),νn0, and a map vL((0,T)×R),T>0, such that

    vνnva.e.andinLploc((0,)×R),1p<.

    The following compact embedding of Murat [17] is useful.

    Theorem 4.3 (Murat). Let Ω be a bounded open subset of RN, N2. Suppose the sequence {Ln}nN of distributions is bounded in W1,(Ω). Suppose also that

    Ln=L1,n+L2,n,

    where {L1,n}nN lies in a compact subset of H1loc(Ω) and {L2,n}nN lies in a bounded subset of L1loc(Ω). Then {Ln}nN lies in a compact subset of H1loc(Ω).

    Proof of Lemma 4.1. Let us fix i{1,...,m} and prove the lemma for the incoming edges, as the proof for the outgoing ones is analogous.

    Let η:RR be any convex C2 entropy function, and let qi:RR be the corresponding entropy flux defined by qi=ηfi. By multiplying ith equation in (5) by η(ρi,ε) and using the chain rule, we get

    tη(ρi,ε)+xqi(ρi,ε)=ε2xxη(ρi,ε)L1,εεη(ρi,ε)(xρi,ε)2L2,ε. (38)

    We claim that

    L1,ε0inH1((0,T)×(,0)),T>0,asε0,{L2,ε}εisuniformlyboundedinL1((0,T)×(,0)),T>0. (39)

    Indeed, (25) and (27) imply

    εxη(ρi,ε)L2((0,T)×(,0))εηL(0,1)εxρi,εL2((0,)×(,0))εηL(0,1)(mi=1ρi,ε,0L2(,0)+m+nj=m+1ρj,ε,0L2(0,)+2(m+n=1βL((0,1)m+n)+mi=1fiL1(0,1))T)0,εη(ρi,ε)(xρi,ε)2L1((0,T)×(,0))ηL(0,1)(mi=1ρi,ε,02L2(,0)+m+nj=m+1ρj,ε,02L2(0,)+2(m+n=1βL((0,1)m+n)+mi=1fiL1(0,1))T).

    Due to (16), (39) follows. Therefore, Theorems 4.3 and 4.2 give the existence of a subsequence {ρi,εk}kN and a limit function ρi satisfying (30) such that as k

    ρi,εkρiinLploc((0,)×(,0))foranyp[1,),ρi,εkρia.e.in(0,)×(,0), (40)

    that guarantees (32) and (33).

    Finally, thanks to Lemmas 3.2, 3.3, and 3.4 we have (35), (36), and (37).

    Proof of Theorem 1.2.. The first part of the statement related to the convergence of vanishing viscosity approximations has been proved in Lemma 4.1.

    Let us fix i{1,,m} and prove (9) for the incoming edges, the case of the outgoing ones is analogous.

    Thanks to (3.4) and (33), for all φC((0,)×(,0)) with compact support, we have

    00ρitφdxdt=limk00ρi,εktφdxdt=limk00tρi,εkφdxdtφL((0,)×(,0))((m+n)C+mi=1fiL(0,1)TV(ρi,0)+m+nj=m+1fjL(0,1)TV(ρj,0)),

    therefore

    tρiM((0,)×(,0)), (41)

    where M((0,)×(,0)) is the set of all Radon measures on (0,)×(,0). Moreover, from the equations in (1) and (2) we have also

    xfi(ρi)M((0,)×(,0)). (42)

    Clearly (41) and (42) give (9) and so the trace at the junction f(ρi(t,0)) exists for a.e. t>0.

    We prove now that the identity

    mi=1fi(ρi(t,0))=n+mj=m+1fj(ρj(t,0+)) (43)

    holds for a.e. t>0; consequently the functions ρ1,,ρm+n provide a solution to (1), (2), and (3) in the sense of Definition 1.1.

    Let φC1([0,)),φ(0)=0 with compact support. Consider the sequence {rν}νN{0}C2([0,)) of cut-off functions satisfying

    0rν(x)1,rν(0)=1,supp(rν)[0,1ν], (44)

    for every x0 and ν1. Moreover, for every ν1, we define the sequence {˜rν}νN{0}C2((,0]) by writing ˜rν(x)=rν(x) for every x0.

    From (5) we have that

    0=mi=100(tρi,εk+xfi(ρi,εk)εk2xxρi,εk)φ(t)˜rν(x)dxdt+m+nj=m+100(tρj,εk+xfj(ρj,εk)εk2xxρj,εk)φ(t)rν(x)dxdt=mi=100(ρi,εkφ(t)˜rν(x)+fi(ρi,εk)φ(t)˜rν(x)εkxρi,εkφ(t)˜rν(x))dxdtm+nj=m+100(ρj,εkφ(t)rν(x)+fj(ρj,εk)φ(t)rν(x)εkxρj,εkφ(t)rν(x))dxdt+mi=10(fi(ρi,εk(t,0))εkxρi,εk(t,0))φ(t)dtm+nj=m+10(fj(ρj,εk(t,0))εkxρj,εk(t,0))φ(t)dt=mi=100(ρi,εkφ(t)˜rν(x)+fi(ρi,εk)φ(t)˜rν(x)εkxρi,εkφ(t)˜rν(x))dxdtm+nj=m+100(ρj,εkφ(t)rν(x)+fj(ρj,εk)φ(t)rν(x)εkxρj,εkφ(t)rν(x))dxdt.

    As k, due to (27), (33), and (34),

    0=mi=100(ρiφ(t)˜rν(x)+fi(ρi)φ(t)˜rν(x))dxdtm+nj=m+100(ρjφ(t)rν(x)+fj(ρj)φ(t)rν(x))dxdt.

    Finally, sending ν,

    0=mi=10fi(ρi(t,0))φ(t)dt+m+nj=m+10fj(ρj(t,0+))φ(t)dt,

    that gives (43).



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