In this paper, we consider a boundary control problem associated with a non-homogeneous pseudo-parabolic type equation in a bounded two-dimensional domain. In the part of the bound of the given region, the value of the solution is given, and it is required to find control to get the average value of the solution. The initial-boundary problem is solved by the Fourier method, and the control problem under consideration is analyzed with the Volterra integral equation of the second kind. The control function is found using the Laplace transform method and proved to be admissible.
Citation: Farrukh Dekhkonov. On one boundary control problem for a pseudo-parabolic equation in a two-dimensional domain[J]. Communications in Analysis and Mechanics, 2025, 17(1): 1-14. doi: 10.3934/cam.2025001
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In this paper, we consider a boundary control problem associated with a non-homogeneous pseudo-parabolic type equation in a bounded two-dimensional domain. In the part of the bound of the given region, the value of the solution is given, and it is required to find control to get the average value of the solution. The initial-boundary problem is solved by the Fourier method, and the control problem under consideration is analyzed with the Volterra integral equation of the second kind. The control function is found using the Laplace transform method and proved to be admissible.
In this paper, we consider the following pseudo-parabolic equation in the rectangular domain Ω=(0,l1)×(0,l2):
∂u(x,y,t)∂t=∂∂x(p(x)∂u(x,y,t)∂x)+∂2∂t∂x(p(x)∂u(x,y,t)∂x)+∂∂y(q(y)∂u(x,y,t)∂y)+∂2∂t∂y(q(y)∂u(x,y,t)∂y),(x,y,t)∈ΩT:=Ω×(0,∞), | (1.1) |
with Dirichlet boundary conditions
u(0,y,t) = φ(y)ν(t),u(l1,y,t) = 0,t≥0, | (1.2) |
u(x,0,t) = 0,u(x,l2,t) = 0, | (1.3) |
where ν(t) is the control function and φ(y) is a given function, and the initial value condition
u(x,y,0) = 0,0≤x≤l1,0≤y≤l2. | (1.4) |
It is called that the control function ν(t)∈W12(R+) is admissible if it fulfills the conditions ν(0)=0 and |ν(t)|≤1 on the half-line t≥0.
Suppose that the functions p(x)∈C2(Ω) and q(y)∈C1(Ω) satisfy the conditions
p(x)>0,p′(x)≤0,q(y)>0,0≤x≤l1,0≤y≤l2. |
It is required that the given functions φ(y)∈W22(Ω) and ψ(y)∈L2(Ω) satisfy the following conditions:
φ(0)=φ(l2)=0,φn⋅ψn≥0,n=1,2,⋯, |
where φn and ψn are the Fourier coefficients of functions φ(y) and ψ(y), respectively.
Pseudo-parabolic equations are characterized by the occurrence of a time derivative appearing in the highest order term, which describes various important physical processes. We know that models of the theory of incompressible fluids with memory can be described by equations of pseudo-parabolic type [1].
Control Problem. Suppose that the function ϕ(t) is given and let ψ∈L2(Ω). Then we find the control function ν(t) from the condition
l1∫0l2∫0ψ(y)u(x,y,t)dydx=ϕ(t),t≥0, | (1.5) |
where u(x,y,t) is a solution of the mixed problem (1.1)-(1.4).
In [2], the control problem for the parabolic equation with the Neumann–Robin boundary condition was solved using the Laplace operator, and the optimal time for reaching the given temperature in the bounded domain was found. The boundary control problem for the heat transfer equation with the Robin boundary condition was studied in [3], and a mathematical model of the heating process of a cylindrical domain was developed.
In [4], the control problem related to the nonhomogeneous parabolic equation with Dirichlet boundary condition in a bounded one-dimensional domain was considered, and the optimal estimate of the minimum time required to reach a given temperature of a thin rod was found. In [5], the boundary control problem with the Neumann boundary condition for the heat transfer equation in a one-dimensional domain was studied, and an estimate of the minimum time for heating a thin rod was obtained.
The initial-boundary problem for a class of finite degenerate semilinear parabolic equations with a single potential term was studied in [6]. Also, the local existence and uniqueness of the weak solution were determined by applying the Galerkin method and the Banach invariance theorem. The initial-boundary value problems for nonlinear parabolic systems with power-type source terms are considered in [7].
Control problems for the infinite-dimensional case were studied by Egorov [8], who generalized Pontryagin's maximum principle to a class of equations in Banach space, and the proof of a bang-bang principle was shown in the particular conditions. The control problem for a linear parabolic type equation in a one-dimensional domain with a Robin boundary condition was studied by Fattorini and Russell [9]. In [10], an estimate of Carleman type for the one-dimensional heat equation was proved.
The stability, uniqueness, and existence of solutions of some classical problems for the pseudo-parabolic equation were studied in [11]. In [12], the point control problems for pseudo-parabolic and parabolic type equations are considered. In [13], some problems related to distributed parameter impulse control problems for systems were studied.
In [14], the control problem associated with a pseudo-parabolic type equation in a one-dimensional domain was studied, and the existence of an admissible control was proved using the Laplace transform method. Some boundary control problems for the pseudo-parabolic equation can be seen in [15]. An initial-boundary value problem for a pseudo-parabolic equation with singular potential was considered by Lian, et al. [16], and global existence and blow-up of solutions were studied. In [17], a class of semi-linear pseudo-parabolic equations was considered, and the invariance, global existence, non-existence, and asymptotic behavior of some sets with initial energy were proved by introducing a family of potential wells.
In this work, the boundary control problem associated with the pseudo-parabolic type equation is considered. Our main goal is to prove that there is a control function. The boundary control problem studied in this work is reduced to the Volterra integral equation of t the second type using the separation of variables method. The existence of a solution to this integral equation can also be proved using the Laplace transform method. In Section 2, the continuity of the kernel of the integral equation on the half-line t≥0 is proved. In Section 3, we prove the existence of an admissible control function and derive the required value for it.
In this section, we consider the reduction of the control problem to the Volterra integral equation of the second kind. For this we first need the following spectral problem:
∂∂x(p(x)∂v(x,y)∂x)+∂∂y(q(y)∂v(x,y)∂y)=−λv(x,y), |
where λ is a constant to be determined later, and with boundary conditions
v(0,y,t) = 0,v(l1,y,t) = 0,0≤y≤l2, |
and
v(x,0,t) = 0,v(x,l2,t) = 0,0≤x≤l1. |
As we know, the above spectral problem is self-adjoint in L2(Ω) and there exists a sequence of eigenvalues {λmn} so that 0<λ11≤...≤λmn→∞, m,n→∞. The corresponding eigenfunction vmn forms a complete orthonormal system {vmn} in L2(Ω), and these eigenfunctions belong to C(ˉΩ)(see [18,19]).
Let the eigenfunction vmn is vmn(x,y)=ϑm(x)ωn(y), and the eigenfunctions ϑm(x), ωn(y) are solutions of the following spectral problems
{ddx(p(x)dϑm(x)dx)=−μmϑm(x),0<x<l1,ϑm(0)=ϑm(l1)=0,0≤x≤l1, | (2.1) |
and
{ddy(q(y)dωn(y)dy)=−νnωn(y),0<y<l2,ωn(0)=ωn(l2)=0,0≤y≤l2, | (2.2) |
where μm and νn are eigenvalues of spectral problems (2.1) and (2.2), respectively. We denote the eigenvalues λmn by λmn=μm+νn, m,n=1,2,⋯.
A solution to the initial-boundary problem (1.1) - (1.4) is the function u(x,y,t), which is expressed as follows:
u(x,y,t)=ν(t)φ(y)l1−xl1−w(x,y,t), | (2.3) |
where the function w(x,y,t) with the regularity w(x,y,t)∈C2,2,1x,y,t(ΩT)∩C(ˉΩT) is the solution to the mixed problem
∂w∂t−∂2∂t∂x(p(x)∂w∂x)−∂∂x(p(x)∂w∂x)−∂2∂t∂y(q(y)∂w∂y)−∂∂y(q(y)∂w∂y)=ν(t)(φ(y)p′(x)l1−l1−xl1∂∂y(q(y)φ′(y)))+ν′(t)(φ(y)l1−xl1+φ(y)p′(x)l1−l1−xl1∂∂y(q(y)φ′(y))), |
with initial-boundary value conditions
w(x,y,t)∣∂Ω=0,w(x,y,0)=0. |
We set
βmn=(λmnamn−bmn+cmn)γmn, | (2.4) |
where the coefficients amn, bmn, cmn and γmn are as follows:
amn=l1∫0l2∫0φ(y)l1−xl1vmn(x,y)dydx, | (2.5) |
bmn=l1∫0l2∫0φ(y)p′(x)l1vmn(x,y)dydx, | (2.6) |
cmn=l1∫0l2∫0l1−xl1(q(y)φ′(y))′vmn(x,y)dydx, | (2.7) |
and
γmn=l1∫0l2∫0ψ(y)vmn(x,y)dydx. | (2.8) |
Thus, we obtain (see [18])
w(x,y,t)=∞∑m=1∞∑n=1bmn−cmn1+λmn(t∫0e−ρmn(t−s)ν(s)ds)vmn(x,y)+∞∑m=1∞∑n=1amn+bmn−cmn1+λmn(t∫0e−ρmn(t−s)ν′(s)ds)vmn(x,y), | (2.9) |
where ρmn=λmn1+λmn<1.
Using (2.3) and (2.9), we obtain the solution of the mixed problem (1.1)–(1.4):
u(x,y,t)=l1−xl1φ(y)ν(t)−∞∑m=1∞∑n=1bmn−cmn1+λmn(t∫0e−ρmn(t−s)ν(s)ds)vmn(x,y)−∞∑m=1∞∑n=1amn+bmn−cmn1+λmn(t∫0e−ρmn(t−s)ν′(s)ds)vmn(x,y). | (2.10) |
From (2.10) and the condition (1.5), we can write
ϕ(t)=l1∫0l2∫0ψ(y)u(x,y,t)dydx=ν(t)l1∫0l2∫0ψ(y)φ(y)l1−xl1dydx−∞∑m=1∞∑n=1(bmn−cmn)γmn1+λmnt∫0e−ρmn(t−s)ν(s)ds−∞∑m=1∞∑n=1(amn+bmn−cmn)γmn1+λmnt∫0e−ρmn(t−s)ν′(s)ds, |
where γmn is defined by (2.8).
According to the properties of the function ν(t), we have
ϕ(t)=ν(t)l1∫0l2∫0ψ(y)φ(y)l1−xl1dydx−ν(t)∞∑m=1∞∑n=1(amn+bmn−cmn)γmn1+λmn+∞∑m=1∞∑n=1(amnλmn−bmn+cmn)γmn(1+λmn)2t∫0e−ρmn(t−s)ν(s)ds. |
Note that
l1∫0l2∫0ψ(y)φ(y)l1−xl1dydx = ∞∑m=1∞∑n=1amnγmn. | (2.11) |
Using (2.11), we can write
ϕ(t)=ν(t)∞∑m=1∞∑n=1(amnλmn−bmn+cmn)γmn1+λmn+∞∑m=1∞∑n=1(amnλmn−bmn+cmn)γmn(1+λmn)2t∫0e−ρmn(t−s)ν(s)ds. |
We set
B(t) = ∞∑m=1∞∑n=1Λmne−ρmnt,t>0, | (2.12) |
and
α = ∞∑m=1∞∑n=1βmn1+λmn, | (2.13) |
where βmn is defined by (2.4), and Λmn is as follows:
Λmn=βmn(1+λmn)2,m,n=1,2,⋯. | (2.14) |
Thus, we have the following Volterra integral equation of the second kind:
αν(t)+t∫0B(t−s)ν(s)ds=ϕ(t),t>0. | (2.15) |
Lemma 1. The following estimate is valid:
0≤βmn≤Cφnψn,m,n=1,2,⋯, |
where C=const>0 and βmn is defined by (2.4).
Proof. Step 1. Using (2.1), (2.5), and the formula for integration by parts, we write
amnμm=μml1∫0l2∫0φ(y)l1−xl1ϑm(x)ωn(y)dydx=−φnl1∫0l1−xl1ddx(p(x)dϑm(x)dx)dx=φnp(0)ϑ′m(0)−φnl1∫0p(x)l1ϑ′m(x)dx=φnp(0)ϑ′m(0)+φnl1∫0p′(x)l1ϑm(x)dx=φnp(0)ϑ′m(0)+bmn, |
where bmn is defined by (2.6).
Then, by (2.2) and (2.5), we have
amnνn=νnl1∫0l2∫0φ(y)l1−xl1ϑm(x)ωn(y)dydx=−l1∫0l1−xl1ϑm(x)dxl2∫0φ(y)ddy(q(y)dωndy)dy=l1∫0l1−xl1ϑm(x)dxl2∫0φ′(y)q(y)dωndydy=−l1∫0l1−xl1ϑm(x)dxl2∫0[q(y)φ′(y)]′ωn(y)dy=−cmn, |
where cmn is defined by (2.7).
Then we have the following equality:
amn(μm+νn)−bmn+cmn=φnp(0)ϑ′m(0), | (2.16) |
where μm+νn=λmn.
Step 2. As we know, the following inequality holds for the eigenfunctions of problem (2.1) (see [14])
ϑ′m(0)l1∫0ϑm(τ)dτ≥0,m=1,2,⋯. | (2.17) |
Step 3. By (2.4), (2.16), and (2.17), we obtain
βmn=(amnλmn−bmn+cmn)γmn=φnp(0)ϑ′m(0)l1∫0ϑm(x)dxl2∫0ψ(y)ωn(y)dy=φnψnp(0)ϑ′m(0)l1∫0ϑm(x)dx. | (2.18) |
If the function p(x)∈C1(Ω), we can write the following estimate (see [20])
max0≤x≤l1|ϑ′m(x)|≤C1μ1/2m. |
Therefore,
|ϑ′m(0)|≤C1μ1/2m,|ϑ′m(l1)|≤C1μ1/2m, | (2.19) |
where C1=const>0.
Then, by integrating the equation (2.1) from 0 to l1, we obtain
p(l1)ϑ′m(l1)−p(0)ϑ′m(0)=−μml1∫0ϑm(x)dx. | (2.20) |
According to (2.19) and (2.20), we have the estimate
|ϑ′m(0)l1∫0ϑm(x)dx|≤|ϑ′m(0)μm(p(l1)ϑ′m(l1)−p(0)ϑ′m(0))|≤C1. |
Thus, we obtain the required estimate
0≤βmn≤Cφnψn. |
Proposition 1. Assume that φ,ψ∈L2(Ω). Then, the kernel B(t) of the integral equation (2.15) is continuous on the half-line t≥0.
Proof. According to Lemma 1 and (2.12), we have the estimate
0<B(t) = ∞∑m=1∞∑n=1Λmne−ρmnt≤∞∑m=1∞∑n=1Λmn=∞∑m=1∞∑n=1βmn(1+λmn)2≤C∞∑m=1∞∑n=1φnψn(1+λmn)2, |
where C=const>0.
In this section, we consider the existence of a solution to the Volterra integral equation of the second kind, that is, the existence of an admissible control function.
For any M>0, we denote W(M) the set of functions ϕ ∈W12(−∞,+∞), which satisfying the following conditions
‖ϕ‖W12(R+)≤M,ϕ(t)=0fort≤0. |
Now, we present the main theorem for proving the existence of admissible control.
Theorem 1. There exists M>0 such that, for any function ϕ∈W(M), the equation (2.15) has a solution ν(t) meeting the condition |ν(t)|≤1.
We rewrite the Volterra integral equation (2.15) as follows:
ϕ(t) = αν(t)+t∫0B(t−s)ν(s)ds,t>0. |
It is known that we can write the Laplace transform of the function ν(t) as follows:
˜ν(p)=∞∫0e−ptν(t)dt, | (3.1) |
where p=σ+iζ, σ>0, ζ∈R.
Then, applying the Laplace transform to the integral equation (2.15), we obtain
˜ϕ(p)=α∞∫0e−ptν(t)dt+∞∫0e−ptt∫0B(t−s)ν(s)dsdt=α˜ν(p)+˜B(p)˜ν(p), |
where α is defined by (2.13).
Then we can write
˜ν(p)=˜ϕ(p)α+˜B(p), |
and
ν(t)=12πiσ+i∞∫σ−i∞˜ϕ(p)α+˜B(p)eptdp=12π+∞∫−∞˜ϕ(σ+iζ)α+˜B(σ+iζ)e(σ+iζ)tdζ. | (3.2) |
Lemma 2. The following estimate
|α+˜B(σ+iζ)|≥α,σ>0,ζ∈R, |
is valid, where α=const>0 is defined by (2.13).
Proof. According to Lemma 1 and (2.13), we can write
α = ∞∑m=1∞∑n=1βmn1+λmn≤const∞∑m=1∞∑n=1φnψn1+λmn. |
It is known that we can write the Laplace transform of the function B(t) as follows:
˜B(p)=∞∫0B(t)e−ptdt=∞∑m=1∞∑n=1Λmn∞∫0e−(p+ρmn)tdt=∞∑m=1∞∑n=1Λmnp+ρmn, |
where function B(t) is defined by (2.12). Then we can write
α+˜B(σ+iζ)=α+∞∑m=1∞∑n=1Λmnσ+ρmn+iζ=α+∞∑m=1∞∑n=1Λmn(σ+ρmn)(σ+ρmn)2+ζ2−iζ∞∑m=1∞∑n=1Λmn(σ+ρmn)2+ζ2=Re(α+˜B(σ+iζ))+iIm(α+˜B(σ+iζ)), |
where
Re(α+˜B(σ+iζ))=α+∞∑m=1∞∑n=1Λmn(σ+ρmn)(σ+ρmn)2+ζ2, |
and
Im(α+˜B(σ+iζ))=−ζ∞∑m=1∞∑n=1Λmn(σ+ρmn)2+ζ2. |
We can see that the following inequality holds:
(σ+ρmn)2+ζ2≤((σ+ρmn)2+1)(1+ζ2). |
As a result, we obtain
1(σ+ρmn)2+ζ2≥11+ζ21(σ+ρmn)2+1. | (3.3) |
Then, using the inequality (3.3), we can obtain the following assumptions:
|Re(α+˜B(σ+iζ))|=α+∞∑m=1∞∑n=1Λmn(σ+ρmn)(σ+ρmn)2+ζ2≥α+11+ζ2∞∑m=1∞∑n=1Λmn(σ+ρmn)(σ+ρmn)2+1 | (3.4) |
=α+C1,σ1+ζ2, | (3.5) |
and
|Im(α+˜B(σ+iζ))|=|ζ|∞∑m=1∞∑n=1Λmn(σ+ρmn)2+ζ2≥|ζ|1+ζ2∞∑m=1∞∑n=1Λmn(σ+ρmn)2+1=C2,σ|ζ|1+ζ2, | (3.6) |
where C1,σ and C2,σ are defined as follows:
C1,σ=∞∑m=1∞∑n=1Λmn(σ+ρmn)(σ+ρmn)2+1, C2,σ=∞∑m=1∞∑n=1Λmn(σ+ρmn)2+1. |
By (3.4) and (3.6), we obtain the required estimate
|α+˜B(σ+iζ)|≥α+Cσ√1+ζ2≥α, | (3.7) |
where Cσ=min(C1,σ,C2,σ) is bounded for all σ>0.
Let the Laplace transform of function ϕ(t) satisfy the condition
+∞∫−∞|˜ϕ(iζ)|dζ<+∞. |
If we proceed to the limit as σ→0 in the equality (3.2), we have
ν(t)=12π+∞∫−∞˜ϕ(iζ)α+˜B(iζ)eiζtdζ. | (3.8) |
Also, to prove Theorem 1, we need the following lemma.
Lemma 3. Suppose that the function ϕ(t) belongs to W(M). Then for the imaginary part of the Laplace transform of function ϕ(t) the following estimate holds
+∞∫−∞|˜ϕ(iζ)|dζ<+∞. |
Proof. Using the formula for integration by parts in (3.1), we can write
˜ϕ(σ+iζ)=∞∫0e−(σ+iζ)tϕ(t)dt=−ϕ(t)e−(σ+iζ)tσ+iζ|t=∞t=0+1σ+iζ∞∫0e−(σ+iζ)tϕ′(t)dt. |
Then, we have
(σ+iζ)˜ϕ(σ+iζ)=∞∫0e−(σ+iζ)tϕ′(t)dt, |
Further, for σ→0 we obtain
iζ˜ϕ(iζ)=∞∫0e−iζtϕ′(t)dt. |
Besides
˜ϕ(iζ)=∞∫0e−iζtϕ(t)dt. |
Thus, we can write the following inequality:
+∞∫−∞|˜ϕ(iζ)|2(1+ζ2)dζ≤C2‖ϕ‖2W12(R+), |
where C2=const>0.
By using elementary identities and inequalities, we have
+∞∫−∞|˜ϕ(iζ)|dζ=+∞∫−∞|˜ϕ(iζ)|1+ζ2dζ++∞∫−∞ζ2|˜ϕ(iζ)|1+ζ2dζ≤(+∞∫−∞|˜ϕ(iζ)|2dζ)1/2(+∞∫−∞1(1+ζ2)2dζ)1/2+(+∞∫−∞ζ2|˜ϕ(iζ)|2dζ)1/2(+∞∫−∞ζ2(1+ζ2)2dζ)1/2≤C+∞∫−∞|˜ϕ(iζ)|2(1+ζ2)dζ≤C2‖ϕ‖2W12(R+). |
Now we present the proof of Theorem 1.
Proof of Theorem 1. Let us show that ν∈W12(R+). Indeed, using (3.7) and (3.8), we can write
+∞∫−∞|˜ν(ζ)|2(1+|ζ|2)dζ = +∞∫−∞|˜ϕ(iζ)α+˜B(iζ)|2(1+|ζ|2)dζ ≤1α2+∞∫−∞|˜ϕ(iζ)|2(1+|ζ|2)dζ = const‖ϕ‖2W12(R). |
Now, we show that the function ν(t) satisfies the Lipschitz condition. Actually,
|ν(t)−ν(s)| = |t∫sν′(ξ)dξ|≤ ‖ν′‖L2(Ω)√t−s. |
Using (3.7), (3.8), and Lemma 3, we have the following estimate
|ν(t)|≤12π+∞∫−∞|˜ϕ(iζ)||α+˜B(iζ)|dζ≤12πα+∞∫−∞|˜ϕ(iζ)|dζ≤C22πα‖ϕ‖W12(R+)≤C2M2πα=1, |
where α is defined by (2.13) and
M=2παC2,C2=const>0. |
Theorem 1 is proved.
The author declare they have not used Artificial Intelligence (AI) tools in the creation of this article.
The authors declare there is no conflict of interest.
[1] |
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