
Citation: Alessandra De Luca, Veronica Felli. Unique continuation from the edge of a crack[J]. Mathematics in Engineering, 2021, 3(3): 1-40. doi: 10.3934/mine.2021023
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This paper presents a monotonicity approach to the study of the asymptotic behavior and unique continuation from the edge of a crack for solutions to the following class of elliptic equations
{−Δu(x)=f(x)u(x)in Ω∖Γ,u=0on Γ, | (1.1) |
where Ω⊂RN+1 is a bounded open domain, Γ⊂RN is a closed set, N≥2, and the potential f satisfies either a negligibility condition with respect to the inverse-square weight, see assumptions (H1-1)–(H1-3), or some suitable integrability properties, see assumptions (H2-1)–(H2-5) below.
We recall that the strong unique continuation property is said to hold for a certain class of equations if no solution, besides possibly the zero function, has a zero of infinite order. Unique continuation principles for solutions to second order elliptic equations have been largely studied in the literature since the pioneering contribution by Carleman [6], who derived unique continuation from some weighted a priori inequalities. Garofalo and Lin in [20] studied unique continuation for elliptic equations with variable coefficients introducing an approach based on the validity of doubling conditions, which in turn depend on the monotonicity property of the Almgren type frequency function, defined as the ratio of scaled local energy over mass of the solution near a fixed point, see [4].
Once a strong unique continuation property is established and infinite vanishing order for non-trivial solutions is excluded, the problem of estimating and possibly classifying all admissible vanishing rates naturally arises. For quantitative uniqueness and bounds for the maximal order of vanishing obtained by monotonicity methods we cite e.g., [23]; furthermore, a precise description of the asymptotic behavior together with a classification of possible vanishing orders of solutions was obtained for several classes of problems in [15,16,17,18,19], by combining monotonicity methods with blow-up analysis for scaled solutions.
The problem of unique continuation from boundary points presents peculiar additional difficulties, as the derivation of monotonicity formulas is made more delicate by the interference with the geometry of the domain. Moreover the possible vanishing orders of solutions are affected by the regularity of the boundary; e.g., in [15] the asymptotic behavior at conical singularities of the boundary has been shown to depend of the opening of the vertex. We cite [2,3,15,24,29] for unique continuation from the boundary for elliptic equations under homogeneous Dirichlet conditions. We also refer to [28] for unique continuation and doubling properties at the boundary under zero Neumann conditions and to [11] for a strong unique continuation result from the vertex of a cone under non-homogeneous Neumann conditions.
The aforementioned papers concerning unique continuation from the boundary require the domain to be at least of Dini type. With the aim of relaxing this kind of regularity assumptions, the present paper investigates unique continuation and classification of the possible vanishing orders of solutions at edge points of cracks breaking the domain, which are then highly irregular points of the boundary.
Elliptic problems in domains with cracks arise in elasticity theory, see e.g., [9,22,25]. The high non-smoothness of domains with slits produces strong singularities of solutions to elliptic problems at edges of cracks; the structure of such singularities has been widely studied in the literature, see e.g., [7,8,12] and references therein. In particular, asymptotic expansions of solutions at edges play a crucial role in crack problems, since the coefficients of such expansions are related to the so called stress intensity factor, see e.g., [9].
A further reason of interest in the study of problem (1.1) can be found in its relation with mixed Dirichlet/Neumann boundary value problems. Indeed, if we consider an elliptic equation associated to mixed boundary conditions on a flat portion of the boundary Λ=Λ1∪Λ2, more precisely a homogeneous Dirichlet boundary condition on Λ1 and a homogeneous Neumann condition on Λ2, an even reflection through the flat boundary Λ leads to an elliptic equation satisfied in the complement of the Dirichlet region, which then plays the role of a crack, see Figure 1; the edge of the crack corresponds to the Dirichlet-Neumann junction of the original problem. In [14] unique continuation and asymptotic expansions of solutions for planar mixed boundary value problems at Dirichlet-Neumann junctions were obtained via monotonicity methods; the present paper is in part motivated by the aim of extending to higher dimensions the monotonicity formula obtained in [14] in the 2-dimensional case, together with its applications to unique continuation. For some regularity results for second-order elliptic problems with mixed Dirichlet-Neumann type boundary conditions we refer to [21,27] and references therein.
In the generalization of the Almgren type monotonicity formula of [14] to dimensions greater than 2, some new additional difficulties arise, besides the highly non-smoothness of the domain: the positive dimension of the edge, a stronger interference with the geometry of the domain, and some further technical issues, related e.g., to the lack of conformal transformations straightening the edge. In particular, the proof of the monotonicity formula is based on the differentiation of the Almgren quotient defined in (4.9), which in turn requires a Pohozaev type identity formally obtained by testing the equation with the function ∇u⋅x; however our domain with crack doesn't verify the exterior ball condition (which ensures L2-integrability of second order derivatives, see [1]) and ∇u⋅x could be not sufficiently regular to be an admissible test function.
In this article a new technique, based on an approximation argument, is developed to overcome the aforementioned difficulty: we construct first a sequence of domains which approximate Ω∖Γ, satisfying the exterior ball condition and being star-shaped with respect to the origin, and then a sequence of solutions of an approximating problem on such domains, converging to the solution of the original problem with crack. For the approximating problems enough regularity is available to establish a Pohozaev type identity, with some remainder terms due to interference with the boundary, whose sign can nevertheless be recognized thanks to star-shapeness conditions. Then, passing to the limit in Pohozaev identities for the approximating problems, we obtain inequality (3.11), which is enough to estimate from below the derivative of the Almgren quotient and to prove that such quotient has a finite limit at 0 (Lemma 4.7). Once a finite limit of the Almgren frequency is shown to exist, a blow-up analysis for scaled solutions allows us to prove strong unique continuation and asymptotics of solutions.
In order to state the main results of the present paper, we start by introducing our assumptions on the domain. For N≥2, we consider the set
Γ={(x′,xN)=(x1,…,xN−1,xN)∈RN:xN≥g(x′)}, |
where g:RN−1→R is a function such that
g(0)=0,∇g(0)=0, | (1.2) |
g∈C2(RN−1). | (1.3) |
Let us observe that assumption (1.2) is not a restriction but just a selection of our coordinate system and, from (1.2) and (1.3), it follows that
|g(x′)|=O(|x′|2)as |x′|→0+. | (1.4) |
Moreover we assume that
g(x′)−x′⋅∇g(x′)≥0 | (1.5) |
for any x′∈B′ˆR:={x′∈RN−1:|x′|<ˆR}, for some ˆR>0. This condition says that ¯RN∖Γ is star-shaped with respect to the origin in a neighbourood of 0. It is satisfied for instance if the function g is concave in a neighborhood of the origin.
We are interested in studying the following boundary value problem
{−Δu=fuin BˆR∖Γ,u=0on Γ, | (1.6) |
where BˆR={x∈RN+1:|x|<ˆR}, for some function f:BˆR→R such that f is measurable and bounded in BˆR∖Bδ for every δ∈(0,ˆR). We consider two alternative sets of assumptions: we assume either that
limr→0+ξf(r)=0, | (H1-1) |
ξf(r)r∈L1(0,ˆR),1r∫r0ξf(s)sds∈L1(0,ˆR), | (H1-2) |
where the function ξf is defined as
ξf(r):=supx∈¯Br|x|2|f(x)|for any r∈(0,ˆR), | (H1-3) |
or that
limr→0+η(r,f)=0, | (H2-1) |
η(r,f)r∈L1(0,ˆR),1r∫r0η(s,f)sds∈L1(0,ˆR), | (H2-2) |
and
∇f∈L∞loc(BˆR∖{0}), | (H2-3) |
η(r,∇f⋅x)r∈L1(0,ˆR),1r∫r0η(s,∇f⋅x)sds∈L1(0,ˆR), | (H2-4) |
where
η(r,h)=supu∈H1(Br)∖{0}∫Br|h|u2dx∫Br|∇u|2dx+N−12r∫∂Br|u|2dS, | (H2-5) |
for every r∈(0,ˆR),h∈L∞loc(BˆR∖{0}).
Conditions (H1-1)–(H1-3) are satisfied e.g., if |f(x)|=O(|x|−2+δ) as |x|→0 for some δ>0, whereas assumptions (H2-1)–(H2-5) hold e.g., if f∈W1,∞loc(BˆR∖{0}) and f,∇f∈Lp(BˆR) for some p>N+12. We also observe that condition (H2-1) is satisfied if f belongs to the Kato class Kn+1, see [13].
In order to give a weak formulation of problem (1.6), we introduce the space H1Γ(BR) for every R>0, defined as the closure in H1(BR) of the subspace
C∞0,Γ(¯BR):={u∈C∞(¯BR):u=0 in a neighborhood of Γ}. |
We observe that actually
H1Γ(BR)={u∈H1(BR):τΓ(u)=0}, |
where τΓ denotes the trace operator on Γ, as one can easily deduce from [5], taking into account that the capacity of ∂Γ in RN+1 is zero, since ∂Γ is contained in a 2-codimensional manifold.
Hence we say that u∈H1(BˆR) is a weak solution to (1.6) if
{u∈H1Γ(BˆR),∫BˆR∇u(x)⋅∇v(x)dx−∫BˆRf(x)u(x)v(x)dx=0for any v∈C∞c(BˆR∖Γ). |
In the classification of the possible vanishing orders and blow-up profiles of solutions, the following eigenvalue problem on the unit N-dimensional sphere with a half-equator cut plays a crucial role. Letting SN={(x′,xN,xN+1):|x′|2+x2N+x2N+1=1} be the unit N-dimensional sphere and
Σ={(x′,xN,xN+1)∈SN:xN+1=0 and xN≥0}, |
we consider the eigenvalue problem
{−ΔSNψ=μψon SN∖Σ,ψ=0on Σ. | (1.7) |
We say that μ∈R is an eigenvalue of (1.7) if there exists an eigenfunction ψ∈H10(SN∖Σ), ψ≢0, such that
∫SN∇SNψ⋅∇SNϕdS=μ∫SNψϕdS |
for all ϕ∈H10(SN∖Σ). By classical spectral theory, (1.7) admits a diverging sequence of real eigenvalues with finite multiplicity {μk}k≥1; moreover these eigenvalues are explicitly given by the formula
μk=k(k+2N−2)4,k∈N∖{0}, | (1.8) |
see Appendix A. For all k∈N∖{0}, let Mk∈N∖{0} be the multiplicity of the eigenvalue μk and
{Yk,m}m=1,2,…,Mk be a L2(SN)-orthonormal basis of the eigenspace of (1.7) associated to μk. | (1.9) |
In particular {Yk,m:k∈N∖{0},m=1,2,…,Mk} is an orthonormal basis of L2(SN).
The main result of this paper provides an evaluation of the behavior at 0 of weak solutions u∈H1(BˆR) to the boundary value problem (1.6).
Theorem 1.1. Let N≥2 and u∈H1(BˆR)∖{0} be a non-trivial weak solution to (1.6), with f satisfying either assumptions (H1-1)–(H1-3) or (H2-1)–(H2-5). Then, there exist k0∈N, k0≥1, and an eigenfunction of problem (1.7) associated with the eigenvalue μk0 such that
λ−k0/2u(λx)→|x|k0/2ψ(x/|x|)as λ→0+ | (1.10) |
in H1(B1).
We mention that a stronger version of Theorem 1.1 will be given in Theorem 6.7.
As a direct consequence of Theorem 1.1 and the boundedness of eigenfunctions of (1.7) (see Appendix A), the following point-wise upper bound holds.
Corollary 1.2. Under the same assumptions as in Theorem 1.1, let u∈H1(BˆR) be a non-trivial weak solution to (1.6). Then, there exists k0∈N, k0≥1, such that
u(x)=O(|x|k0/2)as |x|→0+. |
We observe that, due to the vanishing on the half-equator Σ of the angular profile ψ appearing in (1.10), we cannot expect the reverse estimate |u(x)|≥c|x|k0/2 to hold for x close to the origin.
A further relevant consequence of our asymptotic analysis is the following unique continuation principle, whose proof follows straightforwardly from Theorem 1.1.
Corollary 1.3. Under the same assumptions as in Theorem 1.1, let u∈H1(BˆR) be a weak solution to (1.6) such that u(x)=O(|x|k) as |x|→0, for any k∈N. Then u≡0 in BˆR.
Theorem 6.7 will actually give a more precise description on the limit angular profile ψ: if Mk0≥1 is the multiplicity of the eigenvalue μk0 and {Yk0,i:1≤i≤Mk0} is as in (1.9), then the eigenfunction ψ in (1.10) can be written as
ψ(θ)=mk0∑i=1βiYk0,i, | (1.11) |
where the coefficients βi are given by the integral Cauchy-type formula (6.40).
The paper is organized as follows. In Section 2 we construct a sequence of problems on smooth sets approximating the cracked domain, with corresponding solutions converging to the solution of problem (1.6). In Section 3 we derive a Pohozaev type identity for the approximating problems and consequently inequality (3.11), which is then used in Section 4 to prove the existence of the limit for the Almgren type quotient associated to problem (1.6). In Section 5 we perform a blow-up analysis and prove that scaled solutions converge in some suitable sense to a homogeneous limit profile, whose homogeneity order is related to the eigenvalues of problem (1.7) and whose angular component is shown to be as in (1.11) in Section 6, where an auxiliary equivalent problem with a straightened crack is constructed. Finally, in the appendix we derive the explicit formula (1.8) for the eigenvalues of problem (1.7).
Notation. We list below some notation used throughout the paper.
− For all r>0, Br denotes the open ball {x=(x′,xN,xN+1)∈RN+1:|x|<r} in RN+1 with radius r and center at 0.
− For all r>0, ¯Br={x=(x′,xN,xN+1)∈RN+1:|x|≤r} denotes the closure of Br.
− For all r>0, B′r denotes the open ball {x=(x′,xN)∈RN:|x|<r} in RN with radius r and center at 0.
−dS denotes the volume element on the spheres ∂Br, r>0.
We first prove a coercivity type result for the quadratic form associated to problem (1.6) in small neighbourhoods of 0.
Lemma 2.1. Let f satisfy either (H1-1) or (H2-1). Then there exists r0∈(0,ˆR) such that, for any r∈(0,r0] and u∈H1(Br),
∫Br(|∇u|2−|f|u2)dx≥12∫Br|∇u|2dx−ω(r)∫∂Bru2dS | (2.1) |
and
rω(r)<N−14, | (2.2) |
where
ω(r)={2N−1ξf(r)r,under assumption (H1−1),N−12η(r,f)r,under assumption (H2−1). | (2.3) |
Remark 2.2. For future reference, it is useful to rewrite (2.1) as
∫Br|f|u2dx≤12∫Br|∇u|2dx+ω(r)∫∂Bru2ds | (2.4) |
for all u∈H1(Br) and r∈(0,r0].
The proof of Lemma 2.1 under assumption (H1-1) is based on the following Hardy type inequality with boundary terms, due to Wang and Zhu [30].
Lemma 2.3 ([30], Theorem 1.1). For every r>0 and u∈H1(Br),
∫Br|∇u(x)|2dx+N−12r∫∂Br|u(x)|2dS≥(N−12)2∫Br|u(x)|2|x|2dx. | (2.5) |
Proof of Lemma 2.1. Let us first prove the lemma under assumption (H1-1). To this purpose, let r0∈(0,ˆR) be such that
4ξf(r)(N−1)2<12for all r∈(0,r0]. | (2.6) |
Using the definition of ξf(r) (H1-3) and (2.5), we have that for any r∈(0,ˆR) and u∈H1(Br)
∫Br|f|u2dx≤ξf(r)∫Br|u(x)|2|x|2dx≤4ξf(r)(N−1)2[∫Br|∇u|2dx+N−12r∫∂Bru2dS]. | (2.7) |
Thus, for every 0<r≤r0, from (2.6) and (2.7), we obtain that
∫Br(|∇u|2−|f|u2)dx≥(1−4ξf(r)(N−1)2)∫Br|∇u|2dx−2N−1ξf(r)r∫∂Bru2ds≥12∫Br|∇u|2dx−2N−1ξf(r)r∫∂Bru2ds |
and this completes the proof of (2.1) under assumption (H1-1).
Now let us prove the lemma under assumption (H2-1). Let r0∈(0,ˆR) be such that
η(r,f)<12for all r∈(0,r0]. | (2.8) |
From the definition of η(r,f) (H2-5) it follows that for any r∈(0,ˆR) and u∈H1(Br)
∫Br|f|u2dx≤η(r,f)[∫Br|∇u|2dx+N−12r∫∂Bru2dS]. | (2.9) |
Thus, for every 0<r≤r0, from (2.8) and (2.9) we deduce that
∫Br(|∇u|2−|f|u2)dx≥(1−η(r,f))∫Br|∇u|2dx−N−12η(r,f)r∫∂Bru2dS≥12∫Br|∇u|2dx−N−12η(r,f)r∫∂Bru2ds, |
hence concluding the proof of (2.1) under assumption (H2-1).
We observe that estimate (2.2) follows from the definition of ω in (2.3), (2.6), and (2.8).
Now we are going to construct suitable regular sets which are star-shaped with respect to the origin and which approximate our cracked domain. In order to do this, for any n∈N∖{0} let fn:R→R be defined as
fn(t)={n|t|+1ne2n2|t|n2|t|−2,if |t|<2/n2,n|t|,if |t|≥2/n2, |
so that fn∈C2(R), fn(t)≥n|t| and fn increases for all t>0 and decreases for all t<0; furthermore
fn(t)−tf′n(t)≥0for every t∈R. | (2.10) |
For all r>0 we define
˜Br,n={(x′,xN,xN+1)∈Br:xN<g(x′)+fn(xN+1)}, | (2.11) |
see Figure 2.
Let ˜γr,n⊂∂˜Br,n be the subset of Br defined as
˜γr,n={(x′,xN,xN+1)∈Br:xN=g(x′)+fn(xN+1)} |
and ˜Sr,n denote the set given by ∂˜Br,n∖˜γr,n. We note that, for any fixed r>0, the set ˜γr,n is not empty and ˜Br,n≠Br provided n is sufficiently large.
Lemma 2.4. Let 0<r≤ˆR. Then, for all n∈N∖{0}, the set ˜Br,n is star-shaped with respect to the origin, i.e., x⋅ν≥0 for a.e. x∈∂˜Br,n, where ν is the outward unit normal vector.
Proof. If ˜γr,n is empty, then ˜Br,n=Br and the conclusion is obvious. Let ˜γr,n be not empty.
The thesis is trivial if one considers a point x∈˜Sr,n.
If x∈˜γr,n, then x=(x′,g(x′)+fn(xN+1),xN+1) and the outward unit normal vector at this point is given by
ν(x)=(−∇g(x′),1,−f′n(xN+1))√1+|f′n(xN+1)|2+|∇g(x′)|2, |
hence we have that
x⋅ν(x)=g(x′)−∇g(x′)⋅x′+fn(xN+1)−xN+1 f′n(xN+1)√1+|f′n(xN+1|2+|∇g(x′)|2≥0 |
since g(x′)−∇g(x′)⋅x′≥0 by assumption (1.5) and fn(xN+1)−xN+1f′n(xN+1)≥0 by (2.10).
From now on, we fix u∈H1(BˆR)∖{0}, a non-trivial weak solution to problem (1.6), with f satisfying either (H1-1)–(H1-3) or (H2-1)–(H2-5). Since u∈H1Γ(BˆR), there exists a sequence of functions gn∈C∞0,Γ(¯BˆR) such that gn→u in H1(BˆR). We can choose the functions gn in such a way that
gn(x1,…,xN,xN+1)=0if (x1,⋯,xN)∈Γ and |xN+1|≤˜Cn, | (2.12) |
with
˜C>√2(r20+M2),where M=max{|g(x′)|:|x′|≤r0}. | (2.13) |
Remark 2.5. We observe that gn≡0 in Br0∖˜Br0,n. Indeed, if x=(x′,xN,xN+1)∈Br0∖˜Br0,n, then
xN≥g(x′)+fn(xN+1)>g(x′), |
so that (x′,xN)∈Γ. Moreover
xN≥fn(xN+1)+g(x′)≥n|xN+1|−M, |
with M as in (2.13). Hence either |xN+1|≤Mn or r20≥x2N≥(n|xN+1|−M)2≥n22|xN+1|2−M2. Thus |xN+1|≤√2(r20+M2)n<˜Cn, if we choose ˜C as in (2.13). Then gn(x)=0 in view of (2.12).
Now we construct a sequence of approximated solutions {un}n∈N on the sets ˜Br0,n. For each fixed n∈N, we claim that there exists a unique weak solution un to the boundary value problem
{−Δun=funin ˜Br0,n,un=gnon ∂˜Br0,n. | (2.14) |
Letting
vn:=un−gn, |
we have that un weakly solves (2.14) if and only if vn∈H1(˜Br0,n) is a weak solution to the homogeneous boundary value problem
{−Δvn−fvn=fgn+Δgnin ˜Br0,n,vn=0on ∂˜Br0,n, | (2.15) |
i.e.,
{vn∈H10(˜Br0,n),∫˜Br0,n(∇vn⋅∇ϕ−fvnϕ)dx=∫˜Br0,n(fgn+Δgn)ϕdxfor any ϕ∈H10(˜Br0,n). |
Lemma 2.6. Let r0 be as in Lemma 2.1. Then, for all n∈N, problem (2.15) has one and only one weak solution vn∈H10(˜Br0,n), where ˜Br0,n is defined in (2.11).
Proof. Let us consider the bilinear form
a(v,w)=∫˜Br0,n(∇v⋅∇w−fvw)dx, |
for every v,w∈H10(˜Br0,n). Lemma 2.1 implies that a is coercive on H10(˜Br0,n). Furthermore, from estimate (2.4) we easily deduce that a is continuous. The thesis then follows from the Lax-Milgram Theorem.
Proposition 2.7. Under the same assumptions of Lemma 2.6, there exists a positive constant C>0 such that ‖vn‖H10(Br0)≤C for every n∈N, where vn is extended trivially to zero in Br0∖˜Br0,n.
Proof. Let us observe that fgn and −Δgn are bounded in H−1(Br0) as a consequence of the boundedness of gn in H1(Br0): indeed, using (2.4), one has that, for any ϕ∈H10(Br0),
|∫Br0fgnϕdx|≤(∫Br0|f|g2ndx)12(∫Br0|f|ϕ2dx)12≤12(12∫Br0|∇gn|2dx+ω(r0)∫∂Br0g2nds)12(∫Br0|∇ϕ|2dx)12≤c1‖gn‖H1(Br0)‖ϕ‖H10(Br0), | (2.16) |
for some c1>0 independent on n and ϕ, and
|−∫Br0Δgnϕdx|=|∫Br0∇gn⋅∇ϕdx|≤c2‖gn‖H1(Br0)‖ϕ‖H10(Br0), | (2.17) |
for some c2>0 independent on n and ϕ. Thus from (2.15)–(2.17) and Lemma 2.1, it follows that
‖vn‖2H10(Br0)=∫Br0|∇vn|2dx≤2∫Br0(|∇vn|2−fv2n)dx=2∫Br0(fgn+Δgn)vndx≤2(c1+c2)‖gn‖H1(Br0)‖vn‖H10(Br0)≤c3‖vn‖H10(Br0), |
for some c3>0 independent on n. This completes the proof.
Proposition 2.8. Under the same assumptions of Lemma 2.6, we have that un⇀u weakly in H1(Br0), where un is extended trivially to zero in Br0∖˜Br0,n.
Proof. We observe that the trivial extension to zero of un in Br0∖˜Br0,n belongs to H1(Br0) since the trace of un on ˜γr0,n is null in view of Remark 2.5.
From Proposition 2.7 it follows that there exist ˜v∈H10(Br0) and a subsequence {vnk} of {vn} such that vnk⇀˜v weakly in H10(Br0). Then unk=vnk+gnk⇀˜u weakly in H1(Br0), where ˜u:=˜v+u. Let ϕ∈C∞c(Br0∖Γ). Arguing as in Remark 2.5, we can prove that ϕ∈H10(˜Br0,nk) for all sufficiently large k. Hence, from (2.14) it follows that, for all sufficiently large k,
∫Br0∇unk⋅∇ϕdx=∫Br0funkϕdx, | (2.18) |
where unk is extended trivially to zero in Br0∖˜Br0,nk. Passing to the limit in (2.18), we obtain that
∫Br0∇˜u⋅∇ϕdx=∫Br0f˜uϕdx |
for every ϕ∈C∞c(Br0∖Γ). Furthermore ˜u=u on ∂Br0 in the trace sense: indeed, due to compactness of the trace map γ:H1(Br0)→L2(∂Br0), we have that γ(unk)→γ(˜u) in L2(∂Br0) and γ(unk)=γ(gnk)→γ(u) in L2(∂Br0), since gn→u in H1(Br0).
Finally, we prove that ˜u∈H1Γ(Br0). To this aim, let Γδ={(x′,xN)∈RN:xN≥g(x′)+δ} for every δ>0. For every δ>0 we have that Γδ∩Br0⊂Br0∖˜Br0,n provided n is sufficiently large. Hence, since un is extended trivially to zero in Br0∖˜Br0,n, we have that, for every δ>0, un∈H1Γδ(Br0) provided n is sufficiently large. Since H1Γδ(Br0) is weakly closed in H1(Br0), it follows that ˜u∈H1Γδ(Br0) for every δ>0, and hence ˜u∈H1Γ(Br0).
Thus ˜u weakly solves
{−Δ˜u=f˜uin Br0∖Γ,˜u=uon ∂Br0,˜u=0on Γ. |
Now we consider the function U:=˜u−u: it weakly solves the following problem
{−ΔU=fUin Br0∖Γ,U=0on ∂Br0,U=0on Γ. | (2.19) |
Testing Eq (2.19) with U itself and using Lemma 2.1, we obtain that
12∫Br0|∇U|2dx≤∫Br0(|∇U|2−fU2)dx=0, |
so that U=0, hence u=˜u. By Urysohn's subsequence principle, we can conclude that un⇀u weakly in H1(Br0).
Our next aim is to prove strong convergence of the sequence {un}n∈N to u in H1(Br0).
Proposition 2.9. Under the same assumptions of Lemma 2.6, we have that un→u in H1(Br0).
Proof. From Proposition 2.8 we deduce that vn⇀0 in H1(Br0), hence testing (2.15) with vn itself, we have that
∫Br0(|∇vn|2−fv2n)dx=∫˜Br0,n(|∇vn|2−fv2n)dx=∫˜Br0,n(fgnvn−∇gn∇vn)dx=∫Br0(fgnvn−∇gn∇vn)dx→0 |
as n→∞. Thus, from Lemma 2.1, we deduce that ‖vn‖H10(Br0)→0 as n→∞, hence vn→0 in H1(Br0). This yields that un=gn+vn→u in H1(Br0).
In this section we derive a Pohozaev type identity for un in which we will pass to the limit using Proposition 2.9. For every r∈(0,r0) and v∈H1(Br), we define
R(r,v)={∫Brfv(x⋅∇v)dx,if f satisfies (H1-1)–(H1-3),r2∫∂Brfv2dS−12∫Br(∇f⋅x+(N+1)f)v2dx,if f satisfies (H2-1)–(H2-5). |
Lemma 3.1. Let 0<r<r0. There exists n0=n0(r)∈N∖{0} such that, for all n≥n0,
−N−12∫˜Br,n|∇un|2dx+r2∫˜Sr,n|∇un|2dS−12∫˜γr,n|∂un∂ν|2x⋅νdS−r∫˜Sr,n|∂un∂ν|2dS−R(r,un)=0. | (3.1) |
Proof. Since un solves (2.14) in the domain ˜Br0,n, which satisfies the exterior ball condition, and fun∈L2loc(˜Br0,n∖{0}), by elliptic regularity theory (see [1]) we have that un∈H2(˜Br,n∖Bδ) for all r∈(0,r0), n sufficiently large and all δ<rn, where rn is such that Brn⊂˜Br,n. Since
∫rn0[∫∂Br(|∇un|2+|f|u2n)dS]dr=∫Brn(|∇un|2+|f|u2n)dx<+∞, |
there exists a sequence {δk}k∈N⊂(0,rn) such that limk→∞δk=0 and
δk∫∂Bδk|∇un|2dS→0,δk∫∂Bδk|f|u2ndS→0as k→∞. | (3.2) |
Testing (2.14) with x⋅∇un and integrating over ˜Br,n∖Bδk, we obtain that
−∫˜Br,n∖BδkΔun(x⋅∇un)dx=∫˜Br,n∖Bδkfun(x⋅∇un)dx. | (3.3) |
Integration by parts allows us to rewrite the first term in (3.3) as
−∫˜Br,n∖BδkΔun(x⋅∇un)dx=∫˜Br,n∖Bδ∇un⋅∇(x⋅∇un)dx−r∫˜Sr,n|∂un∂ν|2dS−∫˜γr,n|∂un∂ν|2x⋅νdS+δk∫∂Bδk|∂un∂ν|2dS, | (3.4) |
where we used that x=rν on ˜Sr,n and that the tangential component of ∇un on ˜γr,n equals zero, thus ∇un=∂un∂νν on ˜γr,n. Furthermore, by direct calculations, the first term in (3.4) can be rewritten as
∫˜Br,n∖Bδk∇un⋅∇(x⋅∇un)dx=−N−12∫˜Br,n∖Bδk|∇un|2dx+r2∫˜Sr,n|∇un|2dS+12∫˜γr,n|∂un∂ν|2x⋅νdS−δk2∫∂Bδk|∇un|2dS. | (3.5) |
Taking into account (3.3)–(3.5), we obtain that
−N−12∫˜Br,n∖Bδk|∇un|2dx+r2∫˜Sr,n|∇un|2dS−12∫˜γr,n|∂un∂ν|2x⋅νdS−r∫˜Sr,n|∂un∂ν|2dS−δk2∫∂Bδk|∇un|2dS+δk∫∂Bδk|∂un∂ν|2dS−∫˜Br,n∖Bδkfun(x⋅∇un)dx=0. | (3.6) |
Under assumptions (H1-1)–(H1-3), the Hardy inequality (2.5) implies that fun(x⋅∇un)∈L1(Br) and hence
limk→∞∫˜Br,n∖Bδkfun(x⋅∇un)dx=limk→∞∫Br∖Bδkfun(x⋅∇un)dx=∫Brfun(x⋅∇un)dx. | (3.7) |
On the other hand, if (H2-1)–(H2-5) hold, we can use the Divergence Theorem to obtain that
∫˜Br,n∖Bδkfun(x⋅∇un)dx=r2∫˜Sr,nfu2ndS−12∫˜Br,n∖Bδk(∇f⋅x+(N+1)f)u2ndx−δk2∫∂Bδkfu2ndS=r2∫∂Brfu2ndS−12∫Br∖Bδk(∇f⋅x+(N+1)f)u2ndx−δk2∫∂Bδkfu2ndS. | (3.8) |
Since, under assumptions (H2-1)–(H2-5), (∇f⋅x+(N+1)f)u2n∈L1(Br), we can pass to the limit as k→∞ in (3.8) taking into account also (3.2), thus obtaining that
limk→∞∫˜Br,n∖Bδkfun(x⋅∇un)dx=r2∫∂Brfu2ndS−12∫Br(∇f⋅x+(N+1)f)u2ndx. | (3.9) |
Letting k→+∞ in (3.6), by (3.2), (3.7), and (3.9), we obtain (3.1).
Combining Lemma 3.1 with the fact that the domains ˜Br,n (defined as in (2.11)) are star-shaped with respect to the origin, we deduce the following inequality.
Corollary 3.2. Let 0<r<r0. There exists n0=n0(r)∈N∖{0} such that, for all n≥n0,
−N−12∫˜Br,n|∇un|2dx+r2∫˜Sr,n|∇un|2dS−r∫˜Sr,n|∂un∂ν|2dS−R(r,un)≥0. | (3.10) |
Proof. In view of (3.1), the left-hand side of (3.10) is equal to 12∫˜γr,n|∂un∂ν|2x⋅νdS, which is in fact non-negative, since x⋅ν≥0 on ˜γr,n by Lemma 2.4.
Passing to the limit in (3.10) as n→∞, a similar inequality can be derived for u.
Proposition 3.3. Let u solve (1.6), with f satisfying either (H1-1)–(H1-3) or (H2-1)–(H2-5). Then, for a.e. r∈(0,r0), we have that
−N−12∫Br|∇u|2dx+r2∫∂Br|∇u|2dS−r∫∂Br|∂u∂ν|2dS−R(r,u)≥0 | (3.11) |
and
∫Br|∇u|2dx=∫Brfu2dx+∫∂Bru∂u∂νdS. | (3.12) |
Proof. In order to prove (3.11), we pass to the limit inside inequality (3.10). As regards the first term, it is sufficient to observe that
∫˜Br,n|∇un|2dx=∫Br|∇un|2dx→∫Br|∇u|2dxas n→∞, |
for each fixed r∈(0,r0), as a consequence of Proposition 2.9. In order to deal with the second term, we observe that, by strong H1-convergence of un to u,
limn→+∞∫r00(∫∂Br|∇(un−u)|2dS)dr=0. | (3.13) |
Letting
Fn(r)=∫∂Br|∇(un−u)|2dS, |
(3.13) implies that Fn→0 in L1(0,r0). Then there exists a subsequence Fnk such that Fnk(r)→0 for a.e. r∈(0,r0), hence
∫˜Sr,nk|∇unk|2dS=∫∂Br|∇unk|2dS→∫∂Br|∇u|2dSas k→∞ |
for a.e. r∈(0,r0). In a similar way, we obtain that
∫˜Sr,nk|∂unk∂ν|2dS→∫∂Br|∂u∂ν|2dSas k→∞. |
It remains to prove the convergence of R(r,un). Under the set of assumptions (H1-1)–(H1-3), we first write
∫Br|fun(x⋅∇un)−fu(x⋅∇u)|dx=∫Br|f(un−u)(x⋅∇un)−fux⋅∇(u−un)|dx≤∫Br|f(un−u)(x⋅∇un)|dx+∫Br|fux⋅∇(u−un)|dx. | (3.14) |
The Hölder inequality, (2.5), and Proposition 2.9 imply that
∫Br|f(un−u)(x⋅∇un)|dx≤ξf(r)(∫Br|un−u|2|x|2dx)1/2(∫Br|∇un|2dx)1/2≤2N−1ξf(r)(∫Br|∇(un−u)|2dx+N−12r∫∂Br|un−u|2dS)1/2(∫Br|∇un|2dx)1/2→0 |
and
∫Br|fux⋅∇(un−u)|dx≤ξf(r)(∫Br|u(x)|2|x|2dx)1/2(∫Br|∇(un−u)|2dx)1/2≤2N−1ξf(r)(∫Br|∇u|2dx+N−12r∫∂Br|u|2dS)1/2(∫Br|∇(un−u)|2dx)1/2→0 |
as n→∞, for a.e. r∈(0,r0), since ξf(r) is finite a.e. as a consequence of assumption (H1-2). Hence, from (3.14) we deduce that
limn→∞R(r,un)=R(r,u) | (3.15) |
under assumptions (H1-1)–(H1-3). To prove (3.15) under assumptions (H2-1)–(H2-5), we first use Proposition 2.9 and the Hölder inequality to observe that
|∫Br[∇f⋅x+(N+1)f](u2n−u2)dx|≤(∫Br(|∇f⋅x|+(N+1)|f|)|un−u|2dx)12(∫Br(|∇f⋅x|+(N+1)|f|)|un+u|2dx)12≤(η(r,∇f⋅x)+(N+1)η(r,f))(∫Br|∇(un−u)|2dx+N−12r∫∂Br|un−u|2dS)12⋅(∫Br|∇(un+u)|2dx+N−12r∫∂Br|un+u|2dS)12→0, |
as n→∞, for a.e. r∈(0,r0), since η(r,∇f⋅x) and η(r,f) are finite a.e. as a consequence of assumptions (H2-4) and (H2-2) and {un+u}n is bounded in H1(Br) for every r∈(0,r0). Furthermore, by the fact that f is bounded far from the origin and the compactness of the trace map from H1(Br) to L2(∂Br), it follows that
∫∂Brfu2ndS→∫∂Brfu2dS, |
for a.e. r∈(0,r0). Hence, passing to the limit in R(r,un) we conclude the first part of the proof.
Finally (3.12) follows by testing (2.14) with un itself and passing to the limit arguing as above.
Let u∈H1Γ(BˆR) be a non trivial solution to (1.6). For every r∈(0,ˆR) we define
D(r)=r1−N∫Br(|∇u|2−fu2)dx | (4.1) |
and
H(r)=r−N∫∂Bru2dS. | (4.2) |
In the following lemma we compute the derivative of the function H.
Lemma 4.1. We have that H∈W1,1loc(0,ˆR) and
H′(r)=2r−N∫∂Bru∂u∂νdS | (4.3) |
in a distributional sense and for a.e. r∈(0,ˆR). Furthermore
H′(r)=2rD(r)for a.e.r∈(0,ˆR). | (4.4) |
Proof. First we observe that
H(r)=∫SN|u(rθ)|2dS. | (4.5) |
Let ϕ∈C∞c(0,ˆR). Since u,∇u∈L2(BˆR), we obtain that
−∫ˆR0H(r)ϕ′(r)dr=−∫ˆR0(∫∂B1u2(rθ)dS)ϕ′(r)dr=−∫BˆR|x|−N−1u2(x)∇v(x)⋅xdx=2∫BˆRv(x)|x|−N−1u∇u⋅xdx=2∫ˆR0ϕ(r)(∫∂B1u(rθ)∇u(rθ)⋅θdS)dr, |
where we set v(x)=ϕ(|x|). Thus we proved (4.3). Identity (4.4) follows from (4.3) and (3.12).
We now observe that the function H is strictly positive in a neighbourhood of 0.
Lemma 4.2. For any r∈(0,r0], we have that H(r)>0.
Proof. Assume by contradiction that there exists r1∈(0,r0] such that H(r1)=0, so that the trace of u on ∂Br1 is null and hence u∈H10(Br1∖Γ). Then, testing (1.6) with u, we obtain that
∫Br1|∇u|2dx−∫Br1fu2dx=0. | (4.6) |
Thus, from Lemma 2.1 and (4.6) it follows that
0=∫Br1[|∇u|2−fu2]dx≥12∫Br1|∇u|2dx, |
which, together with Lemma 2.3, implies that u≡0 in Br1. From classical unique continuation principles for second order elliptic equations with locally bounded coefficients (see e.g., [31]), we can conclude that u=0 a.e. in BˆR, a contradiction.
Let us now differentiate the function D and estimate from below its derivative.
Lemma 4.3. The function D defined in (4.1) belongs to W1,1loc(0,ˆR) and
D′(r)≥2r1−N∫∂Br|∂u∂ν|2dS+(N−1)r−N∫Brfu2dx+2r−NR(r,u)−r1−N∫∂Brfu2dS | (4.7) |
for a.e. r∈(0,r0).
Proof. We have that
D′(r)=(1−N)r−N∫Br(|∇u|2−fu2)dx+r1−N∫∂Br(|∇u|2−fu2)dS | (4.8) |
for a.e. r∈(0,r0) and in the distributional sense. Combining (3.11) and (4.8), we obtain (4.7).
Thanks to Lemma 4.2, the frequency function
N:(0,r0]→R,N(r)=D(r)H(r) | (4.9) |
is well defined. Using Lemmas 4.1, 4.3, and 2.1 we can estimate from below N and its derivative.
Lemma 4.4. The function N defined in (4.9) belongs to W1,1loc((0,r0]) and
N′(r)≥ν1(r)+ν2(r), | (4.10) |
for a.e. r∈(0,r0), where
ν1(r)=2r[(∫∂Br|∂u∂ν|2dS)(∫∂Br|u|2dS)−(∫∂Bru∂u∂νdS)2](∫∂Br|u|2dS)2 |
and
ν2(r)=2[N−12∫Brfu2dx+R(r,u)−r2∫∂Brfu2dS]∫∂Br|u|2dS. | (4.11) |
Furthermore,
N(r)>−N−14for everyr∈(0,r0) | (4.12) |
and, for every ε>0, there exists rε>0 such that
N(r)>−εfor every r∈(0,rε), | (4.13) |
i.e., lim infr→0+N(r)≥0.
Proof. From Lemmas 4.1, 4.2, and 4.3, it follows that N∈W1,1loc((0,r0]). From (4.4) we deduce that
N′(r)=D′(r)H(r)−D(r)H′(r)(H(r))2=D′(r)H(r)−12r(H′(r))2(H(r))2 |
and the proof of (4.10) easily follows from (4.3) and (4.7). To prove (4.12) and (4.13), we observe that (4.1) and (4.2), together with Lemma 2.1, imply that
N(r)=D(r)H(r)≥r[12∫Br|∇u|2dx−ω(r)∫∂Br|u|2dS]∫∂Br|u|2dS≥−rω(r) | (4.14) |
for every r∈(0,r0), where ω is defined in (2.3). Then (4.12) follows directly from (2.2). From either assumption (H1-1) or (H2-1) it follows that limr→0+rω(r)=0; hence (4.14) implies (4.13).
Lemma 4.5. Let ν2 be as in (4.11). There exists a positive constant C1>0 such that
|ν2(r)|≤C1α(r)[N(r)+N−12] | (4.15) |
for all r∈(0,r0), where
α(r)={r−1ξf(r),under assumptions (H1−1)–(H1−3),r−1(η(r,f)+η(r,∇f⋅x)),under assumptions (H2−1)–(H2−5). | (4.16) |
Proof. From Lemma 2.1 we deduce that, for all r∈(0,r0),
∫Br|∇u|2dx≤2(rN−1D(r)+ω(r)rNH(r)), | (4.17) |
where ω(r) is defined in (2.3).
Let us first suppose to be under assumptions (H1-1)–(H1-3). Estimating the first term in the numerator of ν2(r) we obtain that
|∫Brfu2dx|≤ξf(r)∫Br|u(x)|2|x|2dx≤ξf(r)4(N−1)2[∫Br|∇u|2dx+N−12r∫∂Bru2dS]≤8(N−1)2rN−1ξf(r)D(r)+16(N−1)3rN−1(ξf(r))2H(r)+2N−1rN−1ξf(r)H(r)≤8(N−1)2rN−1ξf(r)D(r)+4N−1rN−1ξf(r)H(r)=8(N−1)2rN−1ξf(r)(D(r)+N−12H(r)), | (4.18) |
where we used (H1-3), Lemma 2.3, (4.17) and (2.6). Using Hölder inequality, (4.18), (2.6), and (4.17), the second term can be estimated as follows
|∫Brfux⋅∇udx|≤ξf(r)(∫Br|u(x)|2|x|2dx)12(∫Br|∇u|2dx)12≤ξf(r)4N−1rN−1(D(r)+N−12H(r))12(D(r)+2N−1ξf(r)H(r))12≤ξf(r)4N−1rN−1(D(r)+N−12H(r)). | (4.19) |
For the last term we have that
r|∫∂Brfu2ds|≤ξf(r)r∫∂Bru2ds=ξf(r)rN−1H(r). | (4.20) |
Combining (4.18)–(4.20), we obtain that, for all r∈(0,r0),
|ν2(r)|≤C1ξf(r)r−1[N(r)+N−12] |
for some positive constant C1>0 which does not depend on r.
Now let us suppose to be under assumptions (H2-1)–(H2-5). In this case, the definition of R(r,u) allows us to rewrite ν2 as
ν2(r)=−∫Br(2f+∇f⋅x)u2dx∫∂Bru2ds. |
From (H2-5), (4.17) and (2.8) it follows that
|∫Br(2f+∇f⋅x)u2dx|≤(2η(r,f)+η(r,∇f⋅x))(∫Br|∇u|2dx+N−12r∫∂Br|u|2ds)≤2(2η(r,f)+η(r,∇f⋅x))rN−1(D(r)+N−12η(r,f)H(r)+N−14H(r))≤2(2η(r,f)+η(r,∇f⋅x))rN−1(D(r)+N−12H(r)). |
Therefore, we have that
|ν2(r)|≤2(2η(r,f)+η(r,∇f⋅x))r(N(r)+N−12) |
and estimate (4.15) is proved also under assumptions (H2-1)–(H2-5), with C1=4.
Lemma 4.6. Letting r0 be as in Lemma 2.1 and N as in (4.9), there exists a positive constant C2>0 such that
N(r)≤C2 | (4.21) |
for all r∈(0,r0).
Proof. By Lemma 4.4, Schwarz's inequality, and Lemma 4.5, we obtain
(N+N−12)′(r)≥ν2(r)≥−C1α(r)[N(r)+N−12] | (4.22) |
for a.e. r∈(0,r0), where α is defined in (4.16). Taking into account that N(r)+N−12>0 for all r∈(0,r0) in view of (4.12) and α∈L1(0,r0) thanks to assumptions (H1-2), (H2-2) and (H2-4), after integration over (r,r0) it follows that
N(r)≤−N−12+(N(r0)+N−12)exp(C1∫r00α(s)ds) |
for any r∈(0,r0), thus proving estimate (4.21).
Lemma 4.7. The limit
γ:=limr→0+N(r) |
exists and is finite. Moreover γ≥0.
Proof. Since N′(r)≥−C1α(r)[N(r)+N−12] in view of (4.22) and α∈L1(0,r0) by assumptions (H1-2), (H2-2) and (H2-4), we have that
ddr[eC1∫r0α(s)ds(N(r)+N−12)]≥0, |
therefore the limit of r↦eC1∫r0α(s)ds(N(r)+N−12) as r→0+ exists; hence the function N has a limit as r→0+.
From (4.21) and (4.13) it follows that C2≥γ:=limr→0+N(r)=lim infr→0+N(r)≥0; in particular γ is finite.
A first consequence of the above analysis on the Almgren's frequency function is the following estimate of H(r).
Lemma 4.8. Let γ be as in Lemma 4.7 and r0 be as in Lemma 2.1. Then there exists a constant K1>0 such that
H(r)≤K1r2γfor all r∈(0,r0). | (4.23) |
On the other hand, for any σ>0 there exists a constant K2(σ)>0 depending on σ such that
H(r)≥K2(σ)r2γ+σfor all r∈(0,r0). | (4.24) |
Proof. By (4.22) and (4.21) we have that
N′(r)≥−C1(C2+N−12)α(r)a.e. in (0,r0). | (4.25) |
Hence, from the fact that α∈L1(0,r0) and Lemma 4.7, it follows that N′∈L1(0,r0). Therefore from (4.25) it follows that
N(r)−γ=∫r0N′(s)ds≥−C1(C2+N−12)∫r0α(s)ds=−C3rF(r), | (4.26) |
where C3=C1(C2+N−12) and
F(r):=1r∫r0α(s)ds. |
We observe that, thanks to assumptions (H1-2), (H2-2) and (H2-4),
F∈L1(0,r0). | (4.27) |
From (4.4) and (4.26) we deduce that, for a.e. r∈(0,r0),
H′(r)H(r)=2N(r)r≥2γr−2C3F(r), |
which, thanks to (4.27), after integration over the interval (r,r0), yields (4.23).
Let us prove (4.24). Since γ:=limr→0+N(r), for any σ>0 there exists rσ>0 such that N(r)<γ+σ/2 for any r∈(0,rσ) and hence
H′(r)H(r)=2N(r)r<2γ+σrfor all r∈(0,rσ). |
Integrating over the interval (r,rσ) and by continuity of H outside 0, we obtain (4.24) for some constant K2(σ) depending on σ.
In this section we develop a blow-up analysis for scaled solutions, with the aim of classifying their possible vanishing orders. The presence of the crack produces several additional difficulties with respect to the classical case, mainly relying in the persistence of the singularity even far from the origin, all along the edge. These difficulties are here overcome by means of estimates of boundary gradient integrals (Lemma 5.5) derived by some fine doubling properties, in the spirit of [19], where an analogous lack of regularity far from the origin was instead produced by many-particle and cylindrical potentials.
Throughout this section we let u be a non trivial weak H1(BˆR)-solution to equation (1.6) with f satisfying either (H1-1)–(H1-3) or (H2-1)–(H2-5). Let D and H be the functions defined in (4.1) and (4.2) and r0 be as in Lemma 2.1. For λ∈(0,r0), we define the scaled function
wλ(x)=u(λx)√H(λ). | (5.1) |
We observe that wλ∈H1Γλ(Bλ−1ˆR), where
Γλ:=λ−1Γ={x∈RN:λx∈Γ}={x=(x′,xN)∈RN:xN≥g(λx′)λ}, |
and
∫Bλ−1ˆR∇wλ(x)⋅∇v(x)dx−λ2∫Bλ−1ˆRf(λx)wλ(x)v(x)dx=0for all v∈C∞c(Bλ−1ˆR∖Γλ), |
i.e., wλ weakly solves
{−Δwλ(x)=λ2f(λx)wλ(x)in Bλ−1ˆR∖Γλ,wλ=0on Γλ. | (5.2) |
Remark 5.1. From assumptions (1.2) and (1.3) we easily deduce that RN+1∖Γλ converges in the sense of Mosco (see [10,26]) to the set RN+1∖˜Γ, where
˜Γ={(x′,xN)∈RN:xN≥0}. | (5.3) |
In particular, for every R>0, the weak limit points in H1(BR) as λ→0+ of the family of functions {wλ}λ belong to H1˜Γ(BR).
Lemma 5.2. For λ∈(0,r0), let wλ be defined in (5.1). Then {wλ}λ∈(0,r0) is bounded in H1(B1).
Proof. From (4.5) it follows that
∫∂B1|wλ|2dS=1. | (5.4) |
By scaling and (2.1) we have that
N(λ)≥λ1−NH(λ)(12∫Bλ|∇u|2dx−ω(λ)∫∂Bλu2dS)=12∫B1|∇wλ(x)|2dx−λω(λ). | (5.5) |
From (5.5), (4.21), and (2.2) it follows that
12∫B1|∇wλ(x)|2dx≤C2+N−14 | (5.6) |
for every λ∈(0,r0). The conclusion follows from (5.6) and (5.4), taking into account (2.5).
In the next lemma we prove a doubling type result.
Lemma 5.3. There exists C4>0 such that
1C4H(λ)≤H(Rλ)≤C4H(λ)for any λ∈(0,r0/2) and R∈[1,2], | (5.7) |
∫BR|∇wλ(x)|2dx≤2N−1C4∫B1|∇wRλ(x)|2dxfor any λ∈(0,r0/2) and R∈[1,2], | (5.8) |
and
∫BR|wλ(x)|2dx≤2N+1C4∫B1|wRλ(x)|2dxfor any λ∈(0,r0/2) and R∈[1,2], | (5.9) |
where wλ is defined in (5.1).
Proof. By (4.12), (4.21), and (4.4), it follows that
−N−12r≤H′(r)H(r)=2N(r)r≤2C2rfor any r∈(0,r0). |
Let R∈(1,2]. For any λ<r0/R, integrating over (λ,Rλ) the above inequality and recalling that R≤2, we obtain
2(1−N)/2H(λ)≤H(Rλ)≤4C2H(λ)for any λ∈(0,r0/R). |
The above estimates trivially hold also for R=1, hence (5.7) with C4=max{4C2,2(N−1)/2} is established.
For every λ∈(0,r0/2) and R∈[1,2], (5.7) yields
∫BR|∇wλ(x)|2dx=λ1−NH(λ)∫BRλ|∇u(x)|2dx=RN−1H(Rλ)H(λ)∫B1|∇wRλ(x)|2dx≤RN−1C4∫B1|∇wRλ(x)|2dx, |
thus proving (5.8). A similar argument allows deducing (5.9) from (5.7).
Lemma 5.4. For every λ∈(0,r0), let wλ be as in (5.1). Then there exist M>0 and λ0>0 such that, for any λ∈(0,λ0), there exists Rλ∈[1,2] such that
∫∂BRλ|∇wλ|2dS≤M∫BRλ|∇wλ(x)|2dx. |
Proof. From Lemma 5.2 we know that the family {wλ}λ∈(0,r0) is bounded in H1(B1). Moreover Lemma 5.3 implies that the set {wλ}λ∈(0,r0/2) is bounded in H1(B2) and hence
lim supλ→0+∫B2|∇wλ(x)|2dx<+∞. | (5.10) |
For every λ∈(0,r0/2), the function fλ(r)=∫Br|∇wλ(x)|2dx is absolutely continuous in [0,2] and its distributional derivative is given by
f′λ(r)=∫∂Br|∇wλ|2dSfor a.e. r∈(0,2). |
We argue by contradiction and assume that for any M>0 there exists a sequence λn→0+ such that
∫∂Br|∇wλn|2dS>M∫Br|∇wλn(x)|2dxfor all r∈[1,2] and n∈N, |
i.e.,
f′λn(r)>Mfλn(r)for a.e. r∈[1,2] and for every n∈N. | (5.11) |
Integration of (5.11) over [1,2] yields fλn(2)>eMfλn(1) for every n∈N and consequently
lim supn→+∞fλn(1)≤e−M⋅lim supn→+∞fλn(2). |
It follows that
lim infλ→0+fλ(1)≤e−M⋅lim supλ→0+fλ(2)for all M>0. |
Therefore, letting M→+∞ and taking into account (5.10), we obtain that lim infλ→0+fλ(1)=0 i.e.,
lim infλ→0+∫B1|∇wλ(x)|2dx=0. | (5.12) |
From (5.12) and boundedness of {wλ}λ∈(0,r0) in H1(B1) there exist a sequence ˜λn→0 and some w∈H1(B1) such that w˜λn⇀w in H1(B1) and
limn→+∞∫B1|∇w˜λn(x)|2dx=0. | (5.13) |
The compactness of the trace map from H1(B1) to L2(∂B1) and (5.4) imply that
∫∂B1|w|2dS=1. | (5.14) |
Moreover, by weak lower semicontinuity and (5.13),
∫B1|∇w(x)|2dx≤limn→+∞∫B1|∇w˜λn(x)|2dx=0. |
Hence w≡ const in B1. On the other hand, in view of Remark 5.1, w∈H1˜Γ(B1) so that w≡0 in B1, thus contradicting (5.14).
Lemma 5.5. Let wλ be as in (5.1) and Rλ be as in Lemma 5.4. Then there exists ¯M such that
∫∂B1|∇wλRλ|2dS≤¯Mfor any 0<λ<min{λ0,r02}. |
Proof. Since
∫∂B1|∇wλRλ|2dS=λ2R2−NλH(λRλ)∫∂BRλ|∇u(λx)|2dS=R2−NλH(λ)H(λRλ)∫∂BRλ|∇wλ|2dS, |
from (5.7), (5.8), Lemma 5.4, Lemma 5.2, and the fact that 1≤Rλ≤2, we deduce that, for every 0<λ<min{λ0,r02},
∫∂B1|∇wλRλ|2dS≤C4M∫BRλ|∇wλ(x)|2dx≤2N−1C24M∫B1|∇wλRλ(x)|2dx≤¯M<+∞, |
thus completing the proof.
Lemma 5.6. Let u∈H1(BˆR)∖{0} be a non-trivial weak solution to (1.6) with f satisfying either (H1-1)–(H1-3) or (H2-1)–(H2-5). Let γ be as in Lemma 4.7. Then
(i) there exists k0∈N∖{0} such that γ=k02;
(ii) for every sequence λn→0+, there exist a subsequence {λnk}k∈N and an eigenfunction ψ of problem (1.7) associated with the eigenvalue μk0 such that ‖ψ‖L2(SN)=1 and
u(λnkx)√H(λnk)→|x|γψ(x|x|)strongly in H1(B1). | (5.15) |
Proof. For λ∈(0,min{r0,λ0}), let wλ be as in (5.1) and Rλ be as in Lemma 5.4. Let λn→0+. By Lemma 5.2, we have that the set {wλRλ:λ∈(0,min{r0/2,λ0})} is bounded in H1(B1). Then there exists a subsequence {λnk}k such that wλnkRλnk⇀w weakly in H1(B1) for some function w∈H1(B1). The compactness of the trace map from H1(B1) into L2(∂B1) and (5.4) ensure that
∫∂B1|w|2dS=1 | (5.16) |
and, consequently, w≢0. Furthermore, in view of Remark 5.1 we have that w∈H1˜Γ(B1), where ˜Γ is the set defined in (5.3).
Let ϕ∈C∞c(B1∖˜Γ). It is easy to verify that ϕ∈C∞c(B1∖Γλ) provided λ is sufficiently small. Therefore, since wλnkRλnk weakly satisfies Eq (5.2) with λ=λnkRλnk and, for sufficiently large k, B1⊂B(λnkRλnk)−1ˆR, we have that
∫B1∇wλnkRλnk⋅∇ϕdx−(λnkRλnk)2∫B1f(λnkRλnkx)wλnkRλnkϕdx=0 | (5.17) |
for k sufficiently large.
Under the set of assumptions (H1-1)–(H1-3), from (2.5) it follows that
λ2|∫B1f(λx)wλ(x)ϕ(x)dx|≤ξf(λ)(∫B1|wλ(x)|2|x|2dx)1/2(∫B1|ϕ(x)|2|x|2dx)1/2≤4ξf(λ)(N−1)2(∫B1|∇wλ|2dx+N−12)1/2(∫B1|∇ϕ|2dx)1/2=o(1) | (5.18) |
as λ→0+. Similarly, under assumptions (H2-1)–(H2-5), by scaling, we obtain that, as λ→0+,
λ2|∫B1f(λx)wλ(x)ϕ(x)dx|≤η(λ,f)(∫B1|∇wλ|2dx+N−12)1/2(∫B1|∇ϕ|2dx)1/2=o(1). | (5.19) |
The weak convergence of wλnkRλnk to w in H1(B1) and (5.18)–(5.19) allow passing to the limit in (5.17) thus yielding that w∈H1˜Γ(B1) satisfies
∫B1∇w(x)⋅∇ϕ(x)dx=0for all ϕ∈C∞c(B1∖˜Γ), |
i.e., w weakly solves
{−Δw(x)=0in B1∖˜Γ,w=0on ˜Γ. | (5.20) |
We observe that, by classical regularity theory, w is smooth in B1∖˜Γ.
From Lemma 5.5 and the density of C∞(¯B1∖˜Γ) in H1˜Γ(B1), it follows that
∫B1∇wλnkRλnk⋅∇ϕdx=λ2nkR2λnk∫B1f(λnkRλnkx)wλnkRλnkϕdx+∫∂B1∂wλnkRλnk∂νϕdS | (5.21) |
for every ϕ∈H1˜Γ(B1) as well as for every ϕ∈H1ΓλnkRλnk(B1). From Lemma 5.5 it follows that, up to a subsequence still denoted as {λnk}, there exists g∈L2(∂B1) such that
∂wλnkRλnk∂ν⇀gweakly in L2(∂B1). | (5.22) |
Passing to the limit in (5.21) and taking into account (5.18)–(5.19), we then obtain that
∫B1∇w⋅∇ϕdx=∫∂B1gϕdSfor every ϕ∈H1˜Γ(B1). |
In particular, taking ϕ=w above, we have that
∫B1|∇w|2dx=∫∂B1gwdS. | (5.23) |
On the other hand, from (5.21) with ϕ=wλnkRλnk, (5.18), (5.19) and (5.22), the weak convergence of wλnkRλnk to w in H1(B1) (which implies the strong convergence of the traces in L2(∂B1) by compactness of the trace map from H1(B1) into L2(∂B1)), and (5.23) it follows that
limk→+∞∫B1|∇wλnkRλnk|2dx=limk→+∞(λ2nkR2λnk∫B1f(λnkRλnkx)|wλnkRλnk|2dx+∫∂B1∂wλnkRλnk∂νwλnkRλnkdS)=∫∂B1gwdS=∫B1|∇w|2dx |
which implies that
wλnkRλnk→wstrongly in H1(B1). | (5.24) |
For every k∈N and r∈(0,1], let
Dk(r)=r1−N∫Br(|∇wλnkRλnk(x)|2−λ2nkR2λnkf(λnkRλnkx)|wλnkRλnk(x)|2)dx |
and
Hk(r)=r−N∫∂Br|wλnkRλnk|2dS. |
We also define, for all r∈(0,1],
Dw(r)=r1−N∫Br|∇w|2dxandHw(r)=r−N∫∂Br|w|2dS. |
A change of variables directly gives
Nk(r):=Dk(r)Hk(r)=D(λnkRλnkr)H(λnkRλnkr)=N(λnkRλnkr)for all r∈(0,1]. | (5.25) |
From (5.24), (5.18), (5.19) and compactness of the trace map from H1(Br) into L2(∂Br), it follows that, for every fixed r∈(0,1],
Dk(r)→Dw(r)andHk(r)→Hw(r). | (5.26) |
We observe that Hw(r)>0 for all r∈(0,1]; indeed if, for some r∈(0,1], Hw(r)=0, then w=0 on ∂Br and, testing (5.20) with w∈H10(Br∖˜Γ), we would obtain ∫Br|∇w|2dx=0 and hence w≡0 in Br, thus contradicting classical unique continuation principles for second order elliptic equations (see e.g., [31]). Therefore the function
Nw:(0,1]→R,Nw(r):=Dw(r)Hw(r) |
is well defined. Moreover (5.25), (5.26), and Lemma 4.7, imply that, for all r∈(0,1],
Nw(r)=limk→∞N(λnkRλnkr)=γ. | (5.27) |
Therefore Nw is constant in (0,1] and hence N′w(r)=0 for any r∈(0,1). Hence, from (5.20) and Lemma 4.4 with f≡0, we deduce that, for a.e. r∈(0,1),
0=N′w(r)≥ν1(r)=2r[(∫∂Br|∂w∂ν|2dS)(∫∂Br|w|2dS)−(∫∂Brw∂w∂νdS)2](∫∂Br|w|2dS)2≥0 |
so that (∫∂Br|∂w∂ν|2dS)(∫∂Br|w|2dS)−(∫∂Brw∂w∂νdS)2=0. This implies that w and ∂w∂ν have the same direction as vectors in L2(∂Br) for a.e. r∈(0,1). Then there exists a function ζ=ζ(r), defined a.e. in (0,1), such that ∂w∂ν(rθ)=ζ(r)w(rθ) for a.e. r∈(0,1) and for all θ∈SN∖Σ. Multiplying by w(rθ) and integrating over SN we obtain that
∫SN∂w∂ν(rθ)w(rθ)dS=ζ(r)∫SNw2(rθ)dS |
and hence, in view of (4.3) and (4.5), ζ(r)=H′w(r)2Hw(r) for a.e r∈(0,1). This in particular implies that ζ∈L1loc(0,1]. Moreover, after integration, we obtain
w(rθ)=e∫r1ζ(s)dsw(1θ)=φ(r)ψ(θ)for all r∈(0,1),θ∈SN∖Σ, |
where φ(r)=e∫r1ζ(s)ds and ψ=w|SN. The fact that w∈H1˜Γ(B1) implies that ψ∈H10(SN∖Σ); moreover (5.16) yields that
∫SNψ2(θ)dS=1. | (5.28) |
Equation (5.20) rewritten in polar coordinates r,θ becomes
(−φ″(r)−Nrφ′(r))ψ(θ)−φ(r)r2ΔSNψ(θ)=0on SN∖Σ. |
The above equation for a fixed r implies that ψ is an eigenfunction of problem (1.7). Letting μk0=k0(k0+2N−2)4 be the corresponding eigenvalue, φ solves
−φ″(r)−Nrφ′(r)+μk0r2φ(r)=0. |
Integrating the above equation we obtain that there exist c1,c2∈R such that
φ(r)=c1rσ+k0+c2rσ−k0, |
where
σ+k0=−N−12+√(N−12)2+μk0=k02 |
and
σ−k0=−N−12−√(N−12)2+μk0=−(N−1+k02). |
Since the function |x|σ−k0ψ(x|x|)∉L2∗(B1) (where 2∗=2(N+1)/(N−1)), we have that |x|σ−k0ψ(x|x|) does not belong to H1(B1); then necessarily c2=0 and φ(r)=c1rk0/2. Since φ(1)=1, we obtain that c1=1 and then
w(rθ)=rk0/2ψ(θ),for all r∈(0,1) and θ∈SN∖Σ. | (5.29) |
Let us now consider the sequence {wλnk}. Up to a further subsequence still denoted by wλnk, we may suppose that wλnk⇀¯w weakly in H1(B1) for some ¯w∈H1(B1) and that Rλnk→¯R for some ¯R∈[1,2]. Strong convergence of wλnkRλnk in H1(B1) implies that, up to a subsequence, both wλnkRλnk and |∇wλnkRλnk| are dominated by a L2(B1)-function uniformly with respect to k. Furthermore, in view of (5.7), up to a subsequence we can assume that the limit
ℓ:=limk→+∞H(λnkRλnk)H(λnk) |
exists and is finite. The Dominated Convergence Theorem then implies
limk→+∞∫B1wλnk(x)v(x)dx=limk→+∞RN+1λnk∫B1/Rλnkwλnk(Rλnkx)v(Rλnkx)dx=limk→+∞RN+1λnk√H(λnkRλnk)H(λnk)∫B1χB1/Rλnk(x)wλnkRλnk(x)v(Rλnkx)dx=¯RN+1√ℓ∫B1χB1/¯R(x)w(x)v(¯Rx)dx=¯RN+1√ℓ∫B1/¯Rw(x)v(¯Rx)dx=√ℓ∫B1w(x/¯R)v(x)dx |
for any v∈C∞c(B1). By density it is easy to verify that the previous convergence also holds for all v∈L2(B1). We conclude that wλnk⇀√ℓw(⋅/¯R) weakly in L2(B1); as a consequence we have that ¯w=√ℓw(⋅¯R) and wλnk⇀√ℓw(⋅/¯R) weakly in H1(B1). Moreover
limk→+∞∫B1|∇wλnk(x)|2dx=limk→+∞RN+1λnk∫B1/Rλnk|∇wλnk(Rλnkx)|2dx=limk→+∞RN−1λnkH(λnkRλnk)H(λnk)∫B1χB1/Rλnk(x)|∇wλnkRλnk(x)|2dx=¯RN−1ℓ∫B1χB1/¯R(x)|∇w(x)|2dx=¯RN−1ℓ∫B1/¯R|∇w(x)|2dx=∫B1|√ℓ∇(w(x/¯R))|2dx. |
Therefore we conclude that wλnk→¯w=√ℓw(⋅/¯R) strongly in H1(B1). Furthermore, by (5.29) and the fact that ∫∂B1|¯w|2dS=∫∂B1|w|2dS=1, we deduce that ¯w=w.
It remains to prove part (ⅰ). From (5.29) and (5.28) it follows that Hw(r)=rk0. Therefore (5.27) and Lemma 4.1 applied to w imply that
γ=r2H′w(r)Hw(r)=r2k0rk0−1rk0=k02, |
thus completing the proof.
In order to make more explicit the blow-up result proved above, we are going to describe the asymptotic behavior of H(r) as r→0+.
Lemma 5.7. Let γ be as in Lemma 4.7. The limit limr→0+r−2γH(r) exists and it is finite.
Proof. Thanks to estimate (4.23), it is enough to prove that the limit exists. By (4.4) and Lemma 4.7 we have
ddrH(r)r2γ=2r−2γ−1(D(r)−γH(r))=2r−2γ−1H(r)∫r0N′(s)ds. | (5.30) |
Let us write N′=α1+α2, where, using the same notation as in Section 4,
α1(r)=N′(r)+C1(C2+N−12)α(r)andα2=−C1(C2+N−12)α(r). |
From (4.25) we have that α1(r)≥0 for a.e. r∈(0,r0). Moreover (4.16) and assumptions (H1-2), (H2-2) and (H2-4) ensure that α2∈L1(0,r0) and
1s∫s0α2(t)dt∈L1(0,r0). | (5.31) |
Integration of (5.30) over (r,r0) yields
H(r0)r2γ0−H(r)r2γ=∫r0r2s−2γ−1H(s)(∫s0α1(t)dt)ds+∫r0r2s−2γ−1H(s)(∫s0α2(t)dt)ds. | (5.32) |
Since α1(t)≥0 we have that limr→0+∫r0r2s−2γ−1H(s)(∫s0α1(t)dt\bigamma)ds exists. On the other hand, (4.23) and (5.31) imply that
|s−2γ−1H(s)(∫s0α2(t)dt)ds|≤K1s−1∫s0α2(t)dt∈L1(0,r0) |
for all s∈(0,r0), thus proving that s−2γ−1H(s)(∫s0α2(t)dt)∈L1(0,r0). Then we may conclude that both terms in the right hand side of (5.32) admit a limit as r→0+ and at least one of such limits is finite, thus completing the proof of the lemma.
In order to detect the sharp vanishing order of the function H and to give a more explicit blow-up result, in this section we construct an auxiliary equivalent problem by a diffeomorphic deformation of the domain, inspired by [15], see also [2] and [29]. The purpose of such deformation is to straighten the crack; the advantage of working in a domain with a straight crack will then rely in the possibility of separating radial and angular coordinates in the Fourier expansion of solutions (see (6.30)).
Lemma 6.1. There exists ˉr∈(0,r0) such that the function
Ξ:Bˉr→Bˉr, |
Ξ(y)=Ξ(y′,yN,yN+1)={(y′,yN−g(y′),yN+1)√1+g2(y′)−2g(y′)yN|y′|2+y2N+y2N+1,ify≠0,0,ify=0, |
is a C1-diffeomorphism. Furthermore, setting Φ=Ξ−1, we have that
Φ(Br∖˜Γ)=Br∖Γ,Φ−1(Br∖Γ)=Br∖˜Γfor allr∈(0,ˉr), | (6.1) |
Φ(∂Br)=∂Brfor allr∈(0,ˉr), | (6.2) |
Φ(x)=x+O(|x|2)andJacΦ(x)=IdN+1+O(|x|)as |x|→0, | (6.3) |
Φ−1(y)=y+O(|y|2)andJacΦ−1(y)=IdN+1+O(|y|)as |y|→0, | (6.4) |
detJacΦ(x)=1+O(|x|)anddetJacΦ−1(y)=1+O(|y|)as |x|→0, |y|→0. | (6.5) |
Proof. The proof follows from the local inversion theorem, (1.2)–(1.4), and direct calculations.
Let u∈H1(BˆR) be a weak solution to (1.6). Then
v=u∘Φ∈H1(Bˉr) | (6.6) |
is a weak solution to
{−div(A(x)∇v(x))=˜f(x)v(x)in Bˉr∖˜Γ,v=0on ˜Γ, | (6.7) |
i.e.,
{v∈H1˜Γ(Bˉr),∫BˉrA(x)∇v(x)⋅∇φ(x)dx−∫Bˉr˜f(x)v(x)φ(x)dx=0for any φ∈C∞c(Bˉr∖˜Γ). |
where
A(x)=|detJacΦ(x)|(JacΦ(x))−1((JacΦ(x))T)−1,˜f(x)=|detJacΦ(x)|f(Φ(x)). | (6.8) |
By Lemma 6.1 and direct calculations, we obtain that
A(x)=IdN+1+O(|x|)as |x|→0. | (6.9) |
Lemma 6.2. Letting H be as in (4.2) and v=u∘Φ as in (6.6), we have that
H(λ)=(1+O(λ))∫SNv2(λθ)dSasλ→0+, | (6.10) |
and
∫B1|∇ˆvλ(x)|2dxH(λ)=(1+O(λ))∫B1|∇wλ(y)|2dy=O(1)asλ→0+, | (6.11) |
where wλ is defined in (5.1) and ˆvλ(x):=v(λx).
Proof. From (6.1) and a change of variable it follows that
∫Bλu2(x)dx=∫Bλv2(y)|detJacΦ(y)|dyfor all λ∈(0,ˉr). |
Differentiating the above identity with respect to λ we obtain that
∫∂Bλu2dS=∫∂Bλv2|detJacΦ|dSfor a.e. λ∈(0,ˉr). |
Hence, by the continuity of H,
H(λ)=λ−N∫∂Bλv2|detJacΦ|dS=∫SNv2(λθ)|detJacΦ(λθ)|dSfor all λ∈(0,ˉr), |
which yields (6.10) in view of (6.5).
From (6.1) and a change of variable it also follows that
∫B1|∇ˆvλ(x)|2dxH(λ)=∫B1|∇wλ(y)JacΦ(Φ−1(λy))|2|detJacΦ−1(λy)|dy |
for all λ∈(0,ˉr). The above identity, together with (6.3)–(6.5) and the boundedness in H1(B1) of {wλ} established in Lemma 5.2, implies estimate (6.11).
Lemma 6.3. Let v=u∘Φ be as in (6.6) and let k0 and γ be as in Lemma 5.6 (i). Then, for every sequence λn→0+, there exist a subsequence {λnk}k∈N and an eigenfunction ψ of problem (1.7) associated with the eigenvalue μk0 such that ‖ψ‖L2(SN)=1, the convergence (5.15) holds and
v(λnk⋅)√∫SNv2(λnkθ)dS→ψstrongly in L2(SN). |
Proof. From Lemma 5.6, there exist a subsequence λnk and an eigenfunction ψ of problem (1.7) associated with the eigenvalue μk0 such that ‖ψ‖L2(SN)=1 and (5.15) holds. From (5.15) it follows that, up to passing to a further subsequence, wλnk|∂B1 converges to ψ in L2(SN) and almost everywhere on SN, where wλ is defined in (5.1). From Lemma 6.2 it follows that {ˆvλ/√H(λ)}λ is bounded in H1(B1) and hence, in view of (6.10), there exists ˜ψ∈L2(SN) such that, up to a further subsequence,
v(λnk⋅)√∫SNv2(λnkθ)dS→˜ψstrongly in L2(SN) and almost everywhere on SN. | (6.12) |
To conclude it is enough to show that ˜ψ=ψ. To this aim we observe that, for every φ∈C∞c(SN), from (6.6), (6.10), and a change of variable it follows that
∫SNv(λnkθ)√∫SNv2(λnk⋅)dSφ(θ)dS=(1+O(λnk))∫SNwλnk(θ)φ(Φ−1(λnkθ)λnk)|detJacΦ−1(λnkθ)|dS. | (6.13) |
In view of (6.4) and (6.5) we have that, for all θ∈SN,
limk→∞φ(Φ−1(λnkθ)λnk)|detJacΦ−1(λnkθ)|=φ(θ), |
so that, by the Dominated Convergence Theorem, the right hand side of (6.13) converges to ∫SNψ(θ)φ(θ)dS. On the other hand (6.12) implies that the left hand side of (6.13) converges to ∫SN˜ψ(θ)φ(θ)dS. Therefore, passing to the limit in (6.13), we obtain that
∫SNψ(θ)φ(θ)dS=∫SN˜ψ(θ)φ(θ)dSfor all φ∈C∞c(SN) |
thus implying that ψ=˜ψ.
Lemma 6.4. Let k0 be as in Lemma 5.6 and let Mk0∈N∖{0} be the multiplicity of μk0 as an eigenvalue of (1.7). Let {Yk0,m}m=1,2,…,Mk0 be as in (1.9). Then, for any sequence λn→0+, there exists m∈{1,2,…,Mk0} such that
lim infn→+∞|∫SNv(λnθ)Yk0,m(θ)dS|√H(λn)>0. |
Proof. We argue by contradiction and assume that, along a sequence λn→0+,
lim infn→+∞|∫SNv(λnθ)Yk0,m(θ)dS|√H(λn)=0 | (6.14) |
for all m∈{1,2,…,Mk0}. From Lemma 6.3 and (6.10) it follows that there exist a subsequence {λnk} and an eigenfunction ψ of problem (1.7) associated to the eigenvalue μk0 such that ‖ψ‖L2(SN)=1 and
v(λnkθ)√H(λnk)→ψ(θ)strongly in L2(SN). |
Furthermore, from (6.14) we have that, for every m∈{1,2,…,Mk0}, there exists a further subsequence {λnmk} such that
limk→+∞∫SNv(λnmkθ)√H(λnmk)Yk0,m(θ)dS=0. |
Therefore ∫SNψYk0,mdS=0 for all m∈{1,2,…,Mk0}, thus implying that ψ≡0 and giving rise to a contradiction.
For all k∈N∖{0}, m∈{1,2,…,Mk}, and λ∈(0,ˉr), we define
φk,m(λ):=∫SNv(λθ)Yk,m(θ)dS | (6.15) |
and
Υk,m(λ)=−∫Bλ(A−IdN+1)∇v(x)⋅∇SNYk,m(x/|x|)|x|dx+∫Bλ˜f(x)v(x)Yk,m(x/|x|)dx+∫∂Bλ(A−IdN+1)∇v(x)⋅x|x|Yk,m(x/|x|)dS, | (6.16) |
where the functions {Yk,m}m=1,2,…,Mk are introduced in (1.9).
Lemma 6.5. Let k0 be as in Lemma 5.6. For all m∈{1,2,…,Mk0} and R∈(0,ˉr]
φk0,m(λ)=λk02(R−k02φk0,m(R)+2N+k0−22(N+k0−1)∫Rλs−N−k02Υk0,m(s)ds+k0R−N+1−k02(N+k0−1)∫R0sk02−1Υk0,m(s)ds)+o(λk02) | (6.17) |
as λ→0+.
Proof. For all k∈N∖{0} and m∈{1,2,…,Mk}, we consider the distribution ζk,m on (0,ˉr) defined as
D′(0,ˉr)⟨ζk,m,ω⟩D(0,ˉr)=∫ˉr0ω(λ)(∫SN˜f(λθ)v(λθ)Yk,m(θ)dS)dλ+H−1(Bˉr)⟨div((A−IdN+1)∇v),|x|−Nω(|x|)Yk,m(x/|x|)⟩H10(Bˉr) |
for all ω∈D(0,ˉr), where
H−1(Bˉr)⟨div((A−IdN+1)∇v),ϕ⟩H10(Bˉr)=−∫Bˉr(A−IdN+1)∇v⋅∇ϕdx |
for all ϕ∈H10(Bˉr). Letting Υk,m be defined in (6.16), we observe that Υk,m∈L1loc(0,ˉr) and, by direct calculations,
Υ′k,m(λ)=λNζk,m(λ)in D′(0,ˉr). | (6.18) |
From the definition of ζk,m, (6.7), and the fact that Yk,m is an eigenfunction of (1.7) associated to the eigenvalue μk, it follows that, for all k∈N∖{0} and m∈{1,2,…,Mk}, the function φk,m defined in (6.15) solves
−φ″k,m(λ)−Nλφ′k,m(λ)+μkλ2φk,m(λ)=ζk,m(λ) |
in the sense of distributions in (0,ˉr), which, in view of (1.8), can be also written as
−(λN+k(λ−k2φk,m(λ))′)′=λN+k2ζk,m(λ) |
in the sense of distributions in (0,ˉr). Integrating the right-hand side of the above equation by parts and taking into account (6.18), we obtain that, for every k∈N∖{0}, m∈{1,2,…,Mk}, and R∈(0,ˉr], there exists ck,m(R)∈R such that
(λ−k2φk,m(λ))′=−λ−N−k2Υk,m(λ)−k2λ−N−k(ck,m(R)+∫Rλsk2−1Υk,m(s)ds) |
in the sense of distributions in (0,ˉr). In particular, φk,m∈W1,1loc(0,ˉr) and, by a further integration,
φk,m(λ)=λk2(R−k2φk,m(R)+∫Rλs−N−k2Υk,m(s)ds)+k2λk2∫Rλs−N−k(ck,m(R)+∫Rstk2−1Υk,m(t)dt)ds=λk2(R−k2φk,m(R)+2N+k−22(N+k−1)∫Rλs−N−k2Υk,m(s)ds−kck,m(R)R−N+1−k2(N+k−1))+kλ−N+1−k22(N−1+k)(ck,m(R)+∫Rλtk2−1Υk,m(t)dt). | (6.19) |
Let now k0 be as in Lemma 5.6. We claim that
the function s↦s−N−k02Υk0,m(s) belongs to L1(0,ˉr) for any m∈{1,2,…,Mk0}. | (6.20) |
To this purpose, let us estimate each term in (6.16). By (6.9), (6.11), Lemma 5.2, the Hölder inequality and a change of variable we obtain that, for all s∈(0,ˉr),
|∫Bs(A(x)−IdN+1)∇v(x)⋅∇SNYk0,m(x|x|)|x|dx|≤const∫Bs|x||∇v(x)||∇SNYk0,m(x|x|)||x|dx≤const√∫Bs|∇v(x)|2dx√∫Bs|∇SNYk0,m(x|x|)|2dx≤constsN−12sN+12√H(s)√∫B1|∇ˆvs(x)|2H(s)dx≤constsN√H(s). | (6.21) |
By the Hölder inequality, (6.6), (6.1), and the definition of ˜f in (6.8) we have that,
|∫Bs˜f(x)v(x)Yk0,m(x|x|)dx|≤√∫Bs|˜f(x)|v2(x)dx√∫Bs|˜f(x)|Y2k0,m(x|x|)dx=√∫Bs|f(y)|u2(y)dy√∫Bs|f(y)|Y2k0,m(Φ−1(y)|Φ−1(y)|)dy. |
From (H2-5), (4.17), (2.8), (4.21), and (4.18) it follows that
∫Bs|f|u2dx≤constβ(s,f)sN−1H(s) |
where β(s,f)=η(s,f) under assumptions (H2-1)–(H2-5) and β(s,f)=ξf(s) under assumptions (H1-1)–(H1-3). Moreover, by (H2-5), (2.7) and direct calculations we also have that
∫Bs|f(y)|Y2k0,m(Φ−1(y)|Φ−1(y)|)dy≤constβ(s,f)sN−1. |
Therefore we conclude that, for all s∈(0,ˉr),
|∫Bs˜f(x)v(x)Yk0,m(x|x|)dx|≤constβ(s,f)sN−1√H(s). | (6.22) |
As regards the last term in (6.16), we observe that, for a.e. s∈(0,ˉr),
|∫∂Bs(A−IdN+1)∇v(x)⋅x|x|Yk0,m(x|x|)dS|≤consts∫∂Bs|∇v||Yk0,m(x|x|)|dS, | (6.23) |
as a consequence of (6.9). Integrating by parts and using (6.11), Lemma 5.2, the Hölder inequality and a change of variable we have that, for every R∈(0,ˉr],
∫R0s−N−k02+1(∫∂Bs|∇v||Yk0,m(x|x|)|dS)ds=R−N−k02+1∫BR|∇v||Yk0,m(x|x|)|dx+(N+k02−1)∫R0s−N−k02(∫Bs|∇v||Yk0,m(x|x|)|dx)ds≤const(R−k02+1√H(R)+∫R0s−k02√H(s)ds). | (6.24) |
From (6.16), (6.21), (6.22), (6.23), and (6.24) we deduce that, for all m∈{1,2,…,Mk0} and R∈(0,ˉr],
∫R0s−N−k02|Υk0,m(s)|ds≤constR−k02+1√H(R)+∫R0s−k02√H(s)(1+s−1β(s,f))ds. | (6.25) |
Thus claim (6.20) follows from (6.25), (4.23) and assumptions (H1-2) and (H2-2).
From (6.20) we deduce that, for every fixed R∈(0,ˉr],
λk02(R−k02φk0,m(R)+2N+k0−22(N+k0−1)∫Rλs−N−k02Υk0,m(s)ds−k0ck0,m(R)R−N+1−k02(N+k0−1))=O(λk02)=o(λ−N+1−k02)as λ→0+. | (6.26) |
On the other hand, (6.20) also implies that t↦tk02−1Υk0,m(t)∈L1(0,ˉr). We claim that, for every R∈(0,ˉr],
ck0,m(R)+∫R0tk02−1Υk0,m(t)dt=0. | (6.27) |
Suppose by contradiction that (6.27) is not true for some R∈(0,ˉr]. Then, from (6.19) and (6.26) we infer that
φk0,m(λ)∼k0λ−N+1−k022(N−1+k0)(ck0,m(R)+∫R0tk02−1Υk0,m(t)dt)as λ→0+. | (6.28) |
Lemma 2.3 and the fact that v∈H1(Bˉr) imply that
∫ˉr0λN−2|φk0,m(λ)|2dλ≤∫ˉr0λN−2(∫SN|v(λθ)|2dS)dλ=∫B˜r|v(x)|2|x|2dx<+∞, |
thus contradicting (6.28). Claim (6.27) is thereby proved.
From (6.20) and (6.27) it follows that, for every R∈(0,ˉr],
|λ−N+1−k02(ck0,m(R)+∫Rλtk02−1Υk0,m(t)dt)|=λ−N+1−k02|∫λ0tk02−1Υk0,m(t)dt|≤λ−N+1−k02∫λ0tN+k0−1|t−N−k02Υk0,m(t)|dt≤λk02∫λ0|t−N−k02Υk0,m(t)|dt=o(λk02) | (6.29) |
as \lambda\rightarrow 0^+ .
The conclusion follows by combining (6.19), (6.29), and (6.27).
Lemma 6.6. Let \gamma be as in Lemma 4.7. Then \lim_{r\rightarrow 0^+} r^{-2\gamma}\mathcal{H}(r) > 0 .
Proof. For any \lambda\in (0, \bar{r}) , we expand \theta\mapsto v(\lambda\theta)\in L^2(\mathbb{S}^N) in Fourier series with respect to the orthonormal basis \{Y_{k, m}\}_{m = 1, 2, \dots, M_{k}} introduced in (1.9), i.e.,
\begin{equation} v(\lambda\theta) = \sum\limits_{k = 1}^\infty\sum\limits_{m = 1}^{M_k} \varphi_{k,m}(\lambda) Y_{k ,m}(\theta)\quad \text{in}\ L^2(\mathbb{S}^N), \end{equation} | (6.30) |
where, for all k\in{\mathbb N}\setminus\{0\} , m\in\{1, 2, \dots, M_{k}\} , and \lambda\in (0, \bar{r}) , \varphi_{k, m}(\lambda) is defined in (6.15).
Let k_0\in\mathbb{N} , k_0\geq 1 , be as in Lemma 5.6, so that
\begin{equation} \gamma = \lim\limits_{r\rightarrow 0^+}\mathcal{N}(r) = \frac{k_0}2. \end{equation} | (6.31) |
From (6.10) and the Parseval identity we deduce that
\begin{equation} \mathcal{H}(\lambda) = (1+O(\lambda))\int_{\mathbb{S}^N}v^2(\lambda\theta)\, dS = (1+O(\lambda))\sum\limits_{k = 1}^\infty\sum\limits_{m = 1}^{M_k}\varphi_{k,m}^2(\lambda), \end{equation} | (6.32) |
for all 0 < \lambda\leq \bar{r} . Let us assume by contradiction that \lim_{\lambda\rightarrow 0^+}\lambda^{-2\gamma}\mathcal{H}(\lambda) = 0 . Then, (6.31) and (6.32) imply that
\begin{equation} \lim\limits_{\lambda\rightarrow 0^+} \lambda^{-k_0/2}\varphi_{k_0,m}(\lambda) = 0\quad \text{for any $m\in\{1,2,\dots,M_{k_0}\}$}. \end{equation} | (6.33) |
From (6.17) and (6.33) we obtain that
\begin{equation} \begin{split} R^{-\frac {k_0}2}\varphi_{k_0,m}(R)&+\frac{2N+k_0-2}{2(N+k_0-1)}\int_0^{R} s^{-N-\frac {k_0}2}\Upsilon_{k_0,m}(s)ds\\&\quad+\frac{k_0\, R^{-N+1-k_0}}{2(N+k_0 -1)}\int_0^{R} s^{\frac {k_0}2-1}\Upsilon_{k_0,m}(s)\,ds = 0 \end{split} \end{equation} | (6.34) |
for all R\in (0, \bar{r}] and m\in\{1, 2, \dots, M_{k_0}\} .
Since we are assuming by contradiction that \lim_{\lambda\rightarrow 0^+}\lambda^{-2\gamma}\mathcal{H}(\lambda) = 0 , there exists a sequence \{R_n\}_{n\in\mathbb{N}}\subset (0, \bar{r}) such that R_{n+1} < R_n , \lim_{n\to\infty}R_n = 0 and
\begin{equation*} R_n^{-k_0/2}\sqrt{\mathcal{H}(R_n)} = \max\limits_{s\in[0,R_n]}\left(s^{-k_0/2}\sqrt{\mathcal{H}(s)}\right). \end{equation*} |
By Lemma 6.4 with \lambda_n = R_n , there exists m_0\in \{1, 2, \dots, M_{k_0}\} such that, up to a subsequence,
\begin{equation} \lim\limits_{n\rightarrow\infty}\frac{\varphi_{k_0,m_0}(R_n)}{\sqrt{\mathcal{H}(R_n)}}\neq 0. \end{equation} | (6.35) |
By (6.34), (6.25), (6.35), (4.23), (H1-2) and (H2-2), we have
\begin{equation} \begin{split} \bigg| R_n^{-\frac {k_0}2}\varphi_{k_0,m_0}(R_n)& +\frac{k_0\, R_n^{-N+1-k_0}}{2(N+k_0 -1)}\int_0^{R_n} s^{\frac {k_0}2-1}\Upsilon_{k_0,m_0}(s)\,ds\bigg|\\ & = \bigg| \frac{2N+{k_0}-2}{2(N+{k_0}-1)}\int_0^{R_n} s^{-N-\frac {k_0}2}\Upsilon_{{k_0},m_0}(s)ds\bigg|\\ &\leq \frac{2N+{k_0}-2}{2(N+{k_0}-1)}\int_0^{R_n} s^{-N-\frac {k_0}2}|\Upsilon_{{k_0},m_0}(s)|ds\\ &\leq {\rm const\,} \biggl( R_n^{-\frac{k_0}2+1}\sqrt{\mathcal{H}(R_n)}+ \int_0^{R_n} s^{-\frac{k_0}2}\sqrt{\mathcal{H}(s)}\Big(1+s^{-1}\beta(s,f)\Big)\,ds\biggr)\\ &\leq {\rm const\,}\biggl(R_n^{-\frac{k_0}2}\sqrt{\mathcal{H}(R_n)}R_n+ R_n^{-\frac{k_0}2}\sqrt{\mathcal{H}(R_n)} \int_0^{R_n}\frac{\beta(s,f)}{s}ds\biggr)\\ &\leq {\rm const\,}\biggl( \biggl|\frac{\sqrt{\mathcal{H}(R_n)}}{\varphi_{k_0,m_0}(R_n)}\biggr|\biggl|\frac{\varphi_{k_0,m_0} (R_n)}{R_n^{k_0/2}}\biggr|R_n+\biggl|\frac{\sqrt{\mathcal{H}(R_n)}}{\varphi_{k_0,m_0}(R_n)}\biggr|\biggl|\frac{\varphi_{k_0,m_0}(R_n)}{R_n^{k_0/2}}\biggr|\int_0^{R_n}\frac{\beta(s,f)}{s}ds\biggr)\\ & = o\biggl(\frac{\varphi_{k_0,m_0}(R_n)}{R_n^{k_0/2}}\biggr) \end{split} \end{equation} | (6.36) |
as n\rightarrow +\infty . On the other hand, by (6.36) we also have that
\begin{equation} \ \begin{split} \frac{k_0\, R_n^{-N+1-k_0}}{2(N+k_0 -1)}&\left| \int_0^{R_n} t^{\frac {k_0}2-1}\Upsilon_{k_0,m_0}(t)dt\right|\\ & = \frac{k_0\, R_n^{-N+1-k_0}}{2(N+k_0 -1)}\left| \int_0^{R_n} t^{N+k_0-1} t^{-N-\frac {k_0}2}\Upsilon_{k_0,m_0}(t)dt\right| \\ &\leq \frac{k_0}{2(N+k_0 -1)} \int_0^{R_n} t^{-N-\frac {k_0}2}|\Upsilon_{k_0,m_0}(t)|dt = o\biggl(\frac{\varphi_{k_0,m_0}(R_n)}{R_n^{k_0/2}}\biggr) \end{split} \end{equation} | (6.37) |
as n\rightarrow +\infty . Combining (6.36) with (6.37) we obtain that
R_n^{-\frac {k_0}2}\varphi_{k_0,m_0}(R_n) = o\Bigl(R_n^{-\frac {k_0}2}\varphi_{k_0,m_0}(R_n)\Bigr) \quad\text{as }n\rightarrow +\infty, |
which is a contradiction.
Combining Lemma 5.6, Lemma 6.3 and Lemma 6.6, we can now prove the following theorem which is a more precise and complete version of Theorem 1.1.
Theorem 6.7. Let N\geq 2 and u\in H^1(B_{\hat{R}})\setminus \{0\} be a non-trivial weak solution to (1.6), with f satisfying either assumptions (H1-1)–(H1-3) or (H2-1)–(H2-5). Then, letting \mathcal{N}(r) be as in (4.9), there exists k_0\in\mathbb{N} , k_0\geq 1 , such that
\begin{equation} \lim\limits_{r\rightarrow 0^+} \mathcal{N}(r) = \frac{k_0}{2}. \end{equation} | (6.38) |
Furthermore, if M_{k_0}\in \mathbb{N}\setminus\{0\} is the multiplicity of \mu_{k_0} as an eigenvalue of problem (1.7) and \{Y_{k_0, m}\}_{m = 1, 2, \dots, M_{k_0}} is a L^{2}(\mathbb{S}^{N}) -orthonormal basis of the eigenspace associated to \mu_{k_0} , then
\begin{equation} \lambda^{-k_0/2}u(\lambda x)\rightarrow |x|^{k_0/2}\sum\limits_{m = 1}^{M_{k_0}} \beta_mY_{k_0,m}\biggl(\frac{x}{|x|}\biggr) \quad \mathit{\text{in $H^1(B_1)$}} \quad \mathit{\text{as $\lambda\rightarrow 0^+$}}, \end{equation} | (6.39) |
where (\beta_{1}, \beta_{2}, \dots, \beta_{M_{k_0}})\neq (0, 0, \dots, 0) and
\begin{equation} \begin{split} \beta_m = \int_{\mathbb{S}^N} &R^{-k_0/2} u(\varPhi (R\theta))Y_{k_0,m}(\theta) dS\\ & +\frac{1}{1-N-k_0}\int_0^R\biggl(\frac{1-N-\frac{k_0}2}{s^{N+\frac{k_0}2}}-\frac{k_0 \,s^{\frac{k_0}2-1}}{2R^{N-1+k_0}}\biggr) \Upsilon_{k_0,m}(s)\, ds \end{split} \end{equation} | (6.40) |
for all R\in (0, \bar{r}) for some \bar{r} > 0 , where \Upsilon_{k_0, m} is defined in (6.16) and \Phi is the diffeomorphism introduced in Lemma 6.1.
Proof. Identity (6.38) follows immediately from Lemma 5.6.
In order to prove (6.39), let \{\lambda_n\}_{n\in\mathbb{N}}\subset (0, \infty) be such that \lambda_n\rightarrow 0^+ as n\rightarrow +\infty . By Lemmas 5.6, 5.7, 6.3, 6.6 and (6.10), there exist a subsequence \{\lambda_{n_j}\}_j and constants \beta_{1}, \beta_{2}, \dots, \beta_{M_{k_0}}\in \mathbb{R} such that (\beta_{1}, \beta_{2}, \dots, \beta_{M_{k_0}})\neq (0, 0, \dots, 0) ,
\begin{equation} \lambda_{n_j}^{-\frac{k_0}2}u(\lambda_{n_j}x)\rightarrow |x|^{\frac{k_0}2}\sum\limits_{m = 1}^{M_{k_0}}\beta_mY_{k_0,m}\biggl(\frac{x}{|x|}\biggr) \quad \text{in $H^1(B_1)$} \quad\text{as $j\rightarrow +\infty$} \end{equation} | (6.41) |
and
\begin{equation} \lambda_{n_j}^{-\frac{k_0}2}v(\lambda_{n_j}\cdot)\rightarrow \sum\limits_{m = 1}^{M_{k_0}}\beta_mY_{k_0,m} \quad \text{in $L^2(\mathbb{S}^N)$} \quad\text{as $j\rightarrow +\infty$}. \end{equation} | (6.42) |
We will now prove that the \beta_m 's depend neither on the sequence \{\lambda_n\}_{n\in\mathbb{N}} nor on its subsequence \{\lambda_{n_j}\}_{j\in\mathbb{N}} . Let us fix R\in (0, \bar{r}) , with \bar{r} as in Lemma 6.1, and define \varphi_{k_0, m} as in (6.15). From (6.42) it follows that, for any m = 1, 2, \dots, M_{k_0} ,
\begin{equation} \lim\limits_{j\rightarrow +\infty}\lambda_{n_j}^{-\frac{k_0}2}\varphi_{k_0,m}(\lambda_{n_j}) = \lim\limits_{j\rightarrow +\infty}\int_{\mathbb{S}^N}\frac{v(\lambda_{n_j}\theta)}{\lambda_{n_j}^{k_0/2}} Y_{k_0,m}(\theta) dS = \sum\limits_{i = 1}^{M_{k_0}}\beta_i\int_{\mathbb{S}^N}Y_{k_0,i}\, Y_{k_0,m}dS = \beta_m. \end{equation} | (6.43) |
On the other hand, (6.17) implies that, for any m = 1, 2, \dots, M_{k_0} ,
\begin{multline*} \lim\limits_{\lambda \rightarrow 0^+}\lambda^{-\frac{k_0}2}\varphi_{k_0,m}(\lambda) = R^{-\frac {k_0}2}\varphi_{k_0,m}(R)+\frac{2N+k_0-2}{2(N+k_0-1)}\int_0^{R} s^{-N-\frac {k_0}2}\Upsilon_{k_0,m}(s)ds\\+\frac{k_0\, R^{-N+1-k_0}}{2(N+k_0 -1)}\int_0^{R} s^{\frac {k_0}2-1}\Upsilon_{k_0,m}(s)\,ds, \end{multline*} |
with \Upsilon_{k_0, m} as in (6.16), and therefore from (6.43) we deduce that
\begin{equation*} \beta_m = R^{-\frac {k_0}2}\varphi_{k_0,m}(R)+\frac{2N+k_0-2}{2(N+k_0-1)}\int_0^{R} s^{-N-\frac {k_0}2}\Upsilon_{k_0,m}(s)ds+\frac{k_0\, R^{-N+1-k_0}}{2(N+k_0 -1)}\int_0^{R} s^{\frac {k_0}2-1}\Upsilon_{k_0,m}(s)\,ds \end{equation*} |
for any m = 1, 2, \dots, M_{k_0} . In particular the \beta_m 's depend neither on the sequence \{\lambda_n\}_{n\in\mathbb{N}} nor on its subsequence \{\lambda_{n_k}\}_{k\in\mathbb{N}} , thus implying that the convergence in (6.41) actually holds as \lambda\rightarrow 0^+ , and proving the theorem.
The authors declare no conflict of interest.
In this appendix, we derive the explicit formula (1.8) for the eigenvalues of problem (1.7).
Let us start by observing that, if \mu is an eigenvalue of (1.7) with an associated eigenfunction \psi , then, letting \sigma = -\frac{N-1}2+\sqrt{\big(\frac{N-1}2\big)^2+\mu} , the function W(\rho\theta) = \rho^\sigma\psi(\theta) belongs to H^1_{\tilde{\Gamma}}(B_1) and is harmonic in B_1\setminus \tilde{\Gamma} . From [8] it follows that there exists k\in\mathbb{N}\setminus\{0\} such that \sigma = \frac k2 , so that \mu = \frac k4(k+2N-2) . Moreover, from [8] we also deduce that W\in L^\infty(B_1) , thus implying that \psi\in L^\infty(\mathbb{S}^N) .
Viceversa, let us prove that all numbers of the form \mu = \frac k4(k+2N-2) with k\in\mathbb{N}\setminus\{0\} are eigenvalues of (1.7). Let us fix k\in\mathbb{N}\setminus\{0\} and consider the function W defined, in cylindrical coordinates, as
W(x',r\cos t,r\sin t) = r^{k/2}\sin\bigg(\frac k2 \,t\bigg),\quad x'\in \mathbb{R}^{N-1},\ r\geq 0,\ t\in [0,2\pi]. |
We have that W belongs to H^1_{\tilde{\Gamma}}(B_1) and is harmonic in B_1\setminus \tilde{\Gamma} ; furthermore W is homogeneous of degree k/2 , so that, letting \psi: = W\big|_{ \mathbb{S}^N} , we have that \psi\in H^1_0(\mathbb{S}^N\setminus\Sigma) , \psi\not\equiv0 , and
\begin{equation} W(\rho\theta) = \rho^{k/2}\psi(\theta),\quad \rho\geq0,\ \theta\in \mathbb{S}^N. \end{equation} | (A.1) |
Plugging (A.1) into the equation \Delta W = 0 in B_1\setminus \tilde{\Gamma} , we obtain that
\rho^{\frac k2-2}\Big( \tfrac k2\big(\tfrac k2-1+N\big)\psi(\theta) +\Delta_{ \mathbb{S}^N}\psi\Big) = 0,\quad \rho \gt 0,\ \theta\in \mathbb{S}^N\setminus\Sigma, |
so that \frac k4(k+2N-2) is an eigenvalue of (1.7).
We then conclude that the set of all eigenvalues of problem (1.7) is \left\{ \frac{k(k+2N-2)}4:\, k\in \mathbb{N}\setminus\{0\}\right\} and all eigenfunctions belong to L^\infty(\mathbb{S}^N) .
We observe in particular that the first eigenvalue \mu_1 = \frac {2N-1}4 is simple and an associated eigenfunction is given by the function
\Phi(\theta',\theta_N,\theta_{N+1}) = \sqrt{ \sqrt{\theta_N^2+\theta_{N+1}^2}-\theta_N},\quad (\theta',\theta_N,\theta_{N+1})\in \mathbb{S}^N. |
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