Research article Special Issues

Existence of nonradial positive and nodal solutions to a critical Neumann problem in a cone

  • We study the critical Neumann problem {Δu=|u|22uin Σω,uν=0on Σω, in the unbounded cone Σω:={tx:xω and t>0}, where ω is an open connected subset of the unit sphere SN1 in RN with smooth boundary, N3 and 2:=2NN2. We assume that some local convexity condition at the boundary of the cone is satisfied. If ω is symmetric with respect to the north pole of SN1, we establish the existence of a nonradial sign-changing solution. On the other hand, if the volume of the unitary bounded cone ΣωB1(0) is large enough (but possibly smaller than half the volume of the unit ball B1(0) in RN), we establish the existence of a positive nonradial solution.

    Citation: Mónica Clapp, Filomena Pacella. Existence of nonradial positive and nodal solutions to a critical Neumann problem in a cone[J]. Mathematics in Engineering, 2021, 3(3): 1-15. doi: 10.3934/mine.2021022

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  • We study the critical Neumann problem {Δu=|u|22uin Σω,uν=0on Σω, in the unbounded cone Σω:={tx:xω and t>0}, where ω is an open connected subset of the unit sphere SN1 in RN with smooth boundary, N3 and 2:=2NN2. We assume that some local convexity condition at the boundary of the cone is satisfied. If ω is symmetric with respect to the north pole of SN1, we establish the existence of a nonradial sign-changing solution. On the other hand, if the volume of the unitary bounded cone ΣωB1(0) is large enough (but possibly smaller than half the volume of the unit ball B1(0) in RN), we establish the existence of a positive nonradial solution.


    We consider the Neumann problem

    {Δu=|u|22uin Σω,uν=0on Σω, (1.1)

    in the unbounded cone Σω:={tx:xω and t>0}, where ω is an open connected subset of the unit sphere SN1 in RN with smooth boundary, N3, and 2:=2NN2 is the critical Sobolev exponent.

    It is well known that, if ω=SN1, i.e., if Σω is the whole space RN, then the only positive solutions to the critical problem

    Δw=|w|22w,wD1,2(RN), (1.2)

    are the rescalings and translations of the standard bubble U defined in (2.3). Moreover, they are the only nontrivial radial solutions to (1.2), up to sign. It is immediately deduced that, up to sign, the restriction of the bubbles (3.1) to Σω are the only nontrivial radial solutions of (1.1) in any cone; see Proposition 3.4. In addition, if the cone Σω is convex, it was shown in [8,Theorem 2.4] that these are the only positive solutions to (1.1). The convexity property of the cone is crucial in the proof of this result, and it is strongly related to a relative isoperimetric inequality obtained in [7].

    The aim of this paper is to establish the existence of nonradial solutions to (1.1), both positive and sign-changing. As mentioned above, the positive ones can only exist in nonconvex cones. On the other hand, nodal radial solutions to (1.1) do not exist, as this would imply the existence of a nontrivial solution to problem (2.5) in the bounded cone Λω:={tx:xω and t(0,1)}, which is impossible because of the Pohozhaev identity (2.6) and the unique continuation principle.

    For the problem (1.2) in RN various types of sign-changing solutions are known to exist; see [2,3,4,5]. In particular, a family of entire nodal solutions, which are invariant under certain groups of linear isometries of RN, were exhibited in [2]. These solutions arise as blow-up profiles of symmetric minimizing sequences for the critical equation in a ball, and are obtained through a fine analysis of the concentration behavior of such sequences.

    Here we use some ideas from [2] to produce sign-changing solutions to (1.1), but we exploit a different kind of symmetry. Our main result shows that, if ω is symmetric with respect to the north pole of SN1 and if the cone Σω has a point of convexity in the sense of Definition 2.6, then the problem (1.1) has an axially antisymmetric least energy solution, which is nonradial and changes sign; see Theorem 2.8. As far as we know, this is the first existence result of a nodal solution to (1.1).

    Next, we investigate the existence of positive nonradial solutions. In this case we do not require the cone to have any particular symmetry. We establish the existence of a positive nonradial solution to (1.1) under some conditions involving the local convexity of Σω at a boundary point and the measure of the bounded cone Λω; see Corollary 3.5 and Theorem 3.6. We refer to Section 3 for the precise statements and further remarks.

    If Ω is a domain in RN we consider the Sobolev space

    D1,2(Ω):={uL2(Ω):uL2(Ω,RN)}

    with the norm

    u2Ω:=Ω|u|2.

    We denote by JΩ:D1,2(Ω)R the functional given by

    JΩ(u):=12Ω|u|212Ω|u|2,

    and its Nehari manifold by

    N(Ω):={uD1,2(Ω):u0 and Ω|u|2=Ω|u|2}.

    For uD1,2(Ω){0} let tu(0,) be such that tuuN(Ω). Then,

    JΩ(tuu)=1N[QΩ(u)]N2,where QΩ(u):=Ω|u|2(Ω|u|2)2/2. (2.1)

    Hence,

    cΩ:=infuN(Ω)JΩ(u)=infuD1,2(Ω){0}1N[QΩ(u)]N2. (2.2)

    We set c:=cRN. It is well known that this infimum is attained at the function

    U(x)=aN(11+|x|2)N22,aN:=(N(N2))N24, (2.3)

    which is called the standard bubble, and at every rescaling and translation of it, and that

    c=JRN(U)=1NSN2,

    where S is the best constant for the Sobolev embedding D1,2(RN)L2(RN).

    Let SN1 be the unit sphere in RN and let ω be a smooth domain in SN1 with nonempty boundary, i.e., ω is connected and open in SN1 and its boundary ω is a smooth (N2)-dimensional submanifold of SN1. The nontrivial solutions to the Neumann problem (1.1) in the unbounded cone

    Σω:={tx:xω and t>0}

    are the critical points of JΣω on N(Σω).

    To produce a nonradial sign-changing solution for (1.1) we introduce some symmetries. We write a point in RN as x=(x,xN)RN1×R, and consider the reflection ϱ(x,xN):=(x,xN). Then, a subset X of RN will be called ϱ-invariant if ϱxX for every xX, and a function u:XR will be called ϱ-equivariant if

    u(ϱx)=u(x)xX.

    Note that every nontrivial ϱ-equivariant function is nonradial and changes sign.

    Throughout this section we will assume that ω is ϱ-invariant. Note that (0,±1)ω because ω is smooth. Hence, ϱxx for every xΣω{0}. Our aim is to show that (1.1) has a ϱ-equivariant solution. We set

    D1,2ϱ(Σω):={uD1,2(Σω):u is ϱ-equivariant},
    Nϱ(Σω):={uN(Σω):u is ϱ-equivariant}

    and

    cϱΣω:=infuNϱ(Σω)JΣω(u)=infuD1,2ϱ(Σω){0}1N[QΣω(u)]N2. (2.4)

    Define

    Λω:={tx:xω and 0<t<1}

    and set Γ1:=Λω¯ω. In Λω we consider the mixed boundary value problem

    {Δu=|u|22uin Λω,u=0on ω,uν=0on Γ1. (2.5)

    We point out that (2.5) does not have a nontrivial solution. Indeed, by the well known Pohozhaev identity, a solution to (2.5) must satisfy

    0=Γ1ω((us)uν|u|22sν+F(u)sν)ds=ω((us)uν|u|22sν)ds=12ω|uν|2ds (2.6)

    because sν=0 for every sΓ1 and sν=1 for every sω. Therefore uν vanishes on ω. But then the trivial extension of u to the infinite cone Σω solves (1.1), contradicting the unique continuation principle.

    Let V(Λω) be the space of functions in D1,2(Λω) whose trace vanishes on ω. Note that V(Λω)D1,2(Σω) via trivial extension. Let JΛω:V(Λω)R be the restriction of JΣω to V(Λω) and set

    Nϱ(Λω):=Nϱ(Σω)V(Λω)andcϱΛω:=infuNϱ(Λω)JΛω(u).

    To produce a sign-changing solution for the problem (1.1) we will study the concentration behavior of ϱ-equivariant minimizing sequences for (2.5). We start with the following lemmas.

    Lemma 2.1. 0<cϱΛω=cϱΣωc.

    Proof. It is shown in [8,Theorem 2.1] that cϱΛω>0.

    Since Nϱ(Λω)Nϱ(Σω), we have that cϱΛωcϱΣω. To prove the opposite inequality, let φkNϱ(Σω)C(¯Σω) be such that φk has compact support and J(φk)cϱΣω as k. Then, we may choose εk>0 such that the support of ˜φk(x):=ε(N2)/2kφk(ε1kx) is contained in ¯Λω¯ω. Thus, ˜φkNϱ(Λω) and, hence,

    cϱΛωJ(˜φk)=J(φk)for all k.

    Letting k we conclude that cϱΛωcϱΣω.

    To prove that cϱΣωc we fix a point ξΣω{0} and a sequence of positive numbers εk0, and we set Σk:=ε1k(Σωξ). Since Σω{0} is smooth, the limit of the sequence of sets (Σk) is the half-space

    Hν:={zRN:zν<0}, (2.7)

    where ν is the exterior unit normal to Σω at ξ. Let uk(x):=ε(2N)/2kU(xξεk), where U is the standard bubble (2.3). Then,

    limkΣω|uk|2=limkΣk|U|2=Hν|U|2=12NSN2, (2.8)
    limkΣω|uk|2=limkΣk|U|2=Hν|U|2=12NSN2. (2.9)

    The function

    ˆuk(x)=uk(x)uk(ϱx)=ε2N2kU(xξεk)ε2N2kU(xϱξεk)

    is ϱ-equivariant, and from (2.4), (2.8) and (2.9) we obtain

    cϱΣωlimk1N[QΣω(ˆuk)]N2=1NSN2=c.

    This concludes the proof.

    Lemma 2.2. Given a domain Ω in RN and ε>0, we set Ωε:={ε1x:xΩ}. If Ω is Lipschitz continuous, then there exist linear extension operators Pε:W1,2(Ωε)D1,2(RN) and a positive constant C, independent of ε, such that

    (i)(Pεu)(x)=u(x) for every xΩε.

    (ii)RN|(Pεu)|2CΩε|u|2.

    (iii)RN|Pεu|2CΩε|u|2.

    (iv) If Ω is ϱ-invariant, then Pεu is ϱ-equivariant if u is ϱ-equivariant.

    Proof. The existence of an extension operator Pε:W1,2(Ωε)D1,2(RN) satisfying (i)(iii) is well known, and the fact that the constant C does not depend on ε was proved in [6,Lemma 2.1]. To obtain (iv) we replace Pεu by the function x12[(Pεu)(x)(Pεu)(ϱx)].

    The following proposition describes the behavior of minimizing sequences for JΛω on Nϱ(Λω).

    Proposition 2.3. Let ukNϱ(Λω) be such that

    JΛω(uk)cϱΛωandJΛω(uk)0in(V(Λω)).

    Then, after passing to a subsequence, one of the following statements holds true:

    (i) There exist a sequence of positive numbers (εk), a sequence of points (ξk) in Γ1 and a function wD1,2(RN) such that ε1kdist(ξk,ˉω{0}), w|H solves the Neumann problem

    Δw=|w|22w,wD1,2(H), (2.10)

    in some half-space H, JH(w)=12c,

    limkukε2N2kw(ξkεk)+ε2N2k(wϱ)(ϱξkεk)Σω=0,

    and cϱΣω=cϱΛω=c.

    (ii) There exist a sequence of positive numbers (εk) with εk0, and a ϱ-equivariant solution wD1,2(Σω) to the problem (1.1) such that

    limkukε2N2kw(εk)Σω=0,

    and JΣω(w)=cϱΣω=cϱΛωc.

    Proof. Since

    1Nuk2Λω=JΛω(uk)12JΛω(uk)ukC+o(1)ukΛω, (2.11)

    the sequence (uk) is bounded and, after passing to a subsequence, uku weakly in V(Λω). Then, JΛω(u)=0. Since the problem (2.5) does not have a nontrivial solution, we conclude that u=0.

    Fix δ(0,N2cϱΛω). As

    Λω|uk|2=N(JΛω(uk)12JΛω(uk)uk)NcϱΛω,

    there are bounded sequences (εk) in (0,) and (xk) in RN such that, after passing to a subsequence,

    δ=supxRNΛωBεk(x)|uk|2=ΛωBεk(xk)|uk|2,

    where Br(x):={yRN:|yx|<r}. Note that, as δ>0, we have that dist(xk,Λω)<εk. We claim that, after passing to a subsequence, there exist ξkˉΛω and C0>0 such that

    ε1k|xkξk|<C0kN, (2.12)

    and one of the following statements holds true:

    (a)ξk=0 for all kN.

    (b)ξkω=¯ω¯Γ1 for all kN.

    (c)ξkΓ1 for all kN and ε1kdist(ξk,ˉω{0}).

    (d)ξkω for all kN and ε1kdist(ξk,Γ1).

    (e)ξkΛω for all kN, ε1kdist(ξk,Λω) and, either ε1k|ξkϱξk|, or ξk=ϱξk for all kN.

    This can be seen as follows: If the sequence (ε1k|xk|) is bounded, we set ξk:=0. Then, (2.12) and (a) hold true. If (ε1kdist(xk,ω)) is bounded, we take ξkω such that |xkξk|=dist(xk,ω). Then, (2.12) and (b) hold true. If both (ε1k|xk|) and (ε1kdist(xk,ω)) are unbounded and (ε1kdist(xk,Γ1)) is bounded, we take ξkΓ1 with |xkξk|=dist(xk,Γ1). Then, (2.12) and (c) hold true. If (ε1kdist(xk,Γ1)) is unbounded and (ε1kdist(xk,ω)) is bounded, we take ξkω with |xkξk|=dist(xk,ω). Then, (2.12) and (d) hold true. Finally, if (ε1kdist(xk,Λω)) is unbounded, we set ξk:=xk+ϱxk2 if (ε1k|xkϱxk|) is bounded and ξk:=xk if (ε1k|xkϱxk|) is unbounded. Then, (2.12) and (e) hold true.

    Set C1:=C0+1. Inequality (2.12) yields

    δ=ΛωBεk(xk)|uk|2ΛωBC1εk(ξk)|uk|2. (2.13)

    We consider uk as a function in D1,2(Σω) via trivial extension, and we define ˆukD1,2(Σω) as ˆuk(z):=ε(N2)/2kuk(εkz). Since ˆuk is ϱ-equivariant, so is its extension PεkˆukD1,2(RN) given by Lemma 2.2. Let

    wk(z):=(Pεkˆuk)(z+ε1kξk)D1,2(RN).

    Then,

    wk(z)=εN22kuk(εkz+ξk)if zΛk:=ε1k(Λωξk), (2.14)
    wk(zε1kξk)=wk(ϱzε1kξk)for every zRN, (2.15)
    δ=supzRNΛkB1(z)|wk|2ΛkBC1(0)|wk|2, (2.16)

    and (wk) is bounded in D1,2(RN). Hence, a subsequence satisfies that wkw weakly in D1,2(RN), wkw a.e. in RN and wkw strongly in L2loc(RN). Choosing δ sufficiently small and using (2.16), a standard argument shows that w0; see, e.g., [10,Section 8.3]. Moreover, we have that ξkξ and εk0, because uk0 weakly in V(Λω) and w0.

    Let E be the limit of the domains Λk. Since (wk) is bounded in D1,2(RN), using Hölder's inequality we obtain

    |EΛkwkφ|C(EΛk|φ|2)12=o(1),|EΛk|wk|22wkφ|C(EΛk|φ|2)12=o(1),

    for every φCc(RN), and similarly for the integrals over ΛkE. Therefore, as wkw weakly in D1,2(E), rescaling and using (2.14) we conclude that

    EwφE|w|22wφ=EwkφE|wk|22wkφ+o(1)=ΛkwkφΛk|wk|22wkφ+o(1)=ΛωukφkΛω|uk|22ukφk+o(1), (2.17)

    where φk(x):=ε(2N)/2kφ(xξkεk). Next, we analyze all possibilities, according to the location of ξk.

    (a) If ξk=0 for all kN, then E=Σω and wk is ϱ-equivariant. Hence, w is ϱ-equivariant. Let φCc(RN). Then, φk|ΛωV(Λω) for large enough k, and from (2.17) we obtain

    JΣω(w)[φ|Σω]=ΣωwφΣω|w|22wφ=JΛω(uk)[φk|Λω]=o(1).

    This shows that w|Σω solves (1.1). Therefore,

    cϱΣω1Nw2Σωlim infk1Nwk2Σω=limk1Nuk2Λω=cϱΛω.

    Together with Lemma 2.1, this implies that JΣω(w)=cϱΣω=cϱΛωc and

    o(1)=wkwΣω=ukε2N2kw(εk)Σω.

    So, in this case, we obtain statement (ii).

    (b) If ξkω for all kN, then E=HξHν, where ξ=limkξk, \; ν is the exterior unit normal to Σω at ξ, and Hξ and Hν are half-spaces defined as in (2.7). If φCc(Hξ), then φk|ΛωV(Λω) for large enough k, and using (2.17) we conclude that w|E solves the mixed boundary value problem

    Δw=|w|22w,w=0 on EHξ,wν=0 on EHν.

    Since ξ and ν are orthogonal, extending w|E by reflection on EHν, yields a nontrivial solution to the Dirichlet problem

    Δw=|w|22w,wD1,20(Hξ). (2.18)

    It is well known that this problem does not have a nontrivial solution, so (b) cannot occur.

    (c) If ξkΓ1 for all kN and ε1kdist(ξk,ˉω{0}), then E=Hν, where ν is the exterior unit normal to Σω at ξ=limkξk. Using (2.17) we conclude that w|Hν solves the Neumann problem (2.10) in Hν. Since ε1k|ξk|, we have that ε1k|ξkϱξk|. Therefore,

    wk(wϱ)(+ε1k(ξkϱξk))wweakly in D1,2(RN).

    Note also that wkϱwϱ weakly in D1,2(RN). Using these facts and performing suitable rescalings and translations we obtain

    ukε2N2kw(ξkεk)+ε2N2k(wϱ)(ϱξkεk)2Σω=ˆukw(ε1kξk)+(wϱ)(ε1kϱξk)2Σω=wkw+(wϱ)(+ε1k(ξkϱξk))2Σωε1kξk=wk+(wϱ)(+ε1k(ξkϱξk))2Σωε1kξkw2Hν+o(1)=wkϱ+wϱ2Σωε1kϱξkw2Hν+o(1)=ˆuk2Σω2w2Hν+o(1)=uk2Λω2w2Hν+o(1)=NcϱΛω2w2Hν+o(1).

    Since JHν(w)=1Nw2Hν12c, applying Lemma 2.1 we conclude that JHν(w)=12c, cϱΣω=cϱΛω=c, and

    limkukε2N2kw(ξkεk)+ε2N2k(wϱ)(ϱξkεk)2Σω=0.

    So, in this case we obtain statement (i).

    (d) If ξkω for all kN and ε1kdist(ξk,Γ1), then E=Hξ and using (2.17) we conclude that w|Hξ solves the Dirichlet problem (2.18). So this case does not occur.

    (e) If ξkΛω for all kN and ε1kdist(ξk,Λω), then E=RN and w solves the problem (1.2). If ρξk=ξk for every k, then wk is ϱ-equivariant, and so is w. Since w is a sign-changing solution to (1.2) we have that

    2c<1Nw2RNlimk1Nwk2RN=limk1Nuk2Λω=cϱΛω,

    contradicting Lemma 2.1. On the other hand, if ε1k|ϱξkξk|, then, arguing as in case (c), we conclude that

    2c2Nw2RNlimk1Nwk2RN=limk1Nuk2Λω=cϱΛω,

    contradicting Lemma 2.1 again. So (e) cannot occur.

    We are left with (a) and (c). This concludes the proof.

    Proposition 2.3 immediately yields the following result.

    Corollary 2.4. If cϱΣω<c, then the problem (1.1) has a ϱ-equivariant least energy solution in D1,2(Σω).

    Equality is not enough, as the following example shows. Set

    SN1+:={(x1,,xN)SN1:xN>0}.

    Example 2.5. If ω=SN1+, then problem (1.1) does not have a ϱ-equivariant least energy solution in D1,2(Σω).

    Proof. Σω is the upper half-space RN+:={(x1,,xN)RN:xN>0}. If u were a ϱ-equivariant least energy solution to (1.1) in RN+ then, extending u by reflection on (RN+), would yield a sign-changing solution ˜u to the problem (1.2) in RN with JRN(˜u)2c. But the energy of any sign-changing solution to (1.2) is >2c; see [9].

    The following local geometric condition guarantees the existence of a minimizer. It was introduced by Adimurthi and Mancini in [1].

    Definition 2.6. A point ξω is a point of convexity of Σω (of radius r>0) if Br(ξ)ΣωHν and the mean curvature of Σω at ξ with respect to the exterior unit normal ν at ξ is positive.

    As in [1] we make the convention that the curvature of a geodesic in Σω is positive at ξ if it curves away from the exterior unit normal ν. The half-space Hν is defined as in (2.7). Examples of cones having a point of convexity are given as follows.

    Proposition 2.7. If ¯ωSN1+, then Σω has a point of convexity.

    Proof. Let β be the smallest geodesic ball in SN1, centered at the north pole (0,,0,1), which contains ω. Then, ωβ and ¯βSN1+. Hence, every point on β is a point of convexity of Σβ. As ωβ, we have that any point ξωβ is a point of convexity of Σω.

    Theorem 2.8. If Σω has a point of convexity, then cϱΣω<c. Consequently, the problem (1.1) has a ϱ-equivariant least energy solution in D1,2(Σω). This solution is nonradial and changes sign.

    Proof. Let ξω be a point of convexity of Σω of radius r>0. It is shown in [1,Lemma 2.2] that, after fixing r small enough and a radial cut-off function ψCc(RN) with ψ(x)=1 if |x|r4 and ψ(x)=0 if |x|r2, the function uε,ξ(x):=ψ(xξ)ε(2N)/2U(ε1(xξ)), with U as in (2.3), satisfies

    QΣω(uε,ξ)={S22/NdNHω(ξ)Sεln(ε2)+O(ε)if N=3,S22/NdNHω(ξ)Sε+O(ε2ln(ε2))if N4, (2.19)

    where dN is a positive constant depending only on N and Hω(ξ) is the mean curvature of Σω at ξ. Hence, for ε small enough,

    JΣω(tε,ξuε,ξ)=1N[QΣω(uε,ξ)]N2<12NSN2=12c,

    where tε,ξ>0 is such that tε,ξuε,ξN(Σω); see (2.1). Choosing r so that Br(ξ)Br(ϱξ)= we conclude that tε,ξ(uε,ξuε,ξϱ)Nϱ(Σω) and

    cϱΣωJΣω(tε,ξ(uε,ξuε,ξϱ))<c.

    The existence of a ϱ-equivariant least energy solution to (1.1) follows from Corollary 2.4.

    In this section ω is not assumed to have any symmetries.

    We are interested in positive solutions to the problem (1.1). Note that this problem has always a positive radial solution given by the restriction to Σω of the standard bubble U defined in (2.3). The question we wish to address in this section is whether problem (1.1) has a positive nonradial solution.

    Recall the notation introduced in Section 2 and set

    cΣω:=infuN(Σω)JΣω(u)=infuD1,2(Σω){0}1N[QΣω(u)]N2,
    N(Λω):=N(Σω)V(Λω)andcΛω:=infuN(Λω)JΛω(u).

    It is shown in [8,Theorem 2.1] that cΛω>0. As in Lemma 2.1 one shows that cΣω=cΛω12c. We start by describing the behavior of minimizing sequences for JΛω on N(Λω).

    Proposition 3.1. Let ukN(Λω) be such that

    JΛω(uk)cΛωandJΛω(uk)0in(V(Λω)).

    Then, after passing to a subsequence, one of the following statements holds true:

    (i) There exist a sequence of positive numbers (εk), a sequence of points (ξk) in Γ1 and a function wD1,2(RN) such that ε1kdist(ξk,ˉω{0}), w|H solves the Neumann problem

    Δw=|w|22w,wD1,2(H),

    in some half-space H, JH(w)=12c,

    limkukε2N2kw(ξkεk)Σω=0,

    and cΣω=cΛω=12c.

    (ii) There exist a sequence of positive numbers (εk) with εk0 and a solution wD1,2(Σω) to the problem (1.1) such that

    limkukε2N2kw(εk)Σω=0,

    and JΣω(w)=cΣω=cΛω12c.

    Proof. The proof is similar, but simpler than that of Proposition 2.3.

    The following statement is an immediate consequence of this proposition.

    Corollary 3.2. If cΣω<12c, then the problem (1.1) has a positive least energy solution in D1,2(Σω).

    Theorem 3.3. If Σω has a point of convexity, then cΣω<12c. Consequently, the problem (1.1) has a positive least energy solution in D1,2(Σω).

    Proof. The proof is similar to that of Theorem 2.8.

    Let D1,2rad(Σω) be the subspace of radial functions in D1,2(Σω), and define Nrad(Σω):=N(Σω)D1,2rad(Σω) and

    cradΣω:=infuNrad(Σω)JΣω(u)=infuD1,2rad(Σω){0}1N[QΣω(u)]N2.

    It was shown in [8,Theorem 2.4] that, if Σω is convex, then cradΣω=cΣω and the only positive minimizers are the restrictions of the rescalings

    Uε(x)=aN(εε2+|x|2)N22,ε>0, (3.1)

    of the standard bubble to Σω. In fact, the proof of [8,Theorem 2.4] shows that these are the only positive solutions of (1.1) in a convex cone. Moreover, the following statement holds true.

    Proposition 3.4. For any cone Σω, the restrictions to Σω of the functions Uε defined in (3.1) are minimizers of JΣω on Nrad(Σω). These are the only nontrivial radial solutions to (1.1), up to sign. Moreover,

    cradΣω=bN|Λω|,wherebN=c|B1(0)|

    and |X| is the Lebesgue measure of X. In particular, cradΣω increases with |Λω|.

    Proof. A radial function u solves (1.1) in Σω if and only if the function ˉu given by ˉu(r):=u(x) with r=x solves

    ddr(rN1ˉu(r))=rN1|ˉu(r)|N2ˉu(r) in (0,),ˉu(0)=u(0),ˉu(0)=0.

    This last problem does not depend on ω. It is well known that, up to sign, the functions Uε are the only nontrivial radial solutions to the problem (1.2) in RN=ΣSN1. Hence, their restrictions to Σω are the only nontrivial radial solutions to (1.1).

    As in Lemma 2.1 one shows that cradΣω=cradΛω:=infuNrad(Λω)JΛω(u). For uVrad(Λω):=D1,2rad(Λω)V(Λω),u0, we have that

    QΛω(u)=Λω|u|2(Λω|u|2)2/2=N|Λω|10|ˉu(r)|2rN1dr(N|Λω|10|ˉu(r)|2rN1dr)2/2.

    Therefore,

    cradΛω=infuVrad(Λω){0}1N[QΛω(u)]N2=infuVrad(Λω){0}10|ˉu(r)|2rN1dr(10|ˉu(r)|2rN1dr)2/2|Λω|=:bN|Λω|.

    The same formula holds true when we replace ω by SN1. In this case, the left-hand side is c. Hence, bN=c|B1(0)|, as claimed.

    Corollary 3.5. If Σω has a point of convexity and |Λω|12|B1(0)|, then

    (i) the problem (1.1) has a positive least energy solution in D1,2(Σω),

    (ii) every least energy solution of (1.1) is nonradial.

    Proof. From Theorem 3.3 and Proposition 3.4 we get that cΣω is attained and

    cΣω<12c=cradRN+=bN2|B1(0)|bN|Λω|=cradΣω,

    where RN+:={(x1,,xN)RN:xN>0}. So every least energy solution is nonradial.

    Note that the hypothesis that |Λω|12|B1(0)| implies that Σω is not convex.

    A closer look at the estimate (2.19) allows to refine Corollary 3.5 and to produce examples of cones Σω with |Λω|<12|B1(0)| for which the problem (1.1) has a positive nonradial solution.

    To this end, we fix a smooth domain ω0 in SN1 for which Σω0 has a point of convexity ξω0 of radius r>0, and we define

    (ω0,ξ,r):={ω:ω is a smooth domain in SN1,Br(ξ)Σω0Br(ξ)Σωand dist(Br(ξ)Σω0,Br(ξ)(ΣωΣω0))>0}.

    Then, we have the following result.

    Theorem 3.6. There exists αξ(0,12|B1(0)|), depending only on Br(ξ)Σω0, such that, for every ω(ω0,ξ,r) with |Λω|>αξ, the following statements hold true:

    (i) the problem (1.1) has a positive least energy solution in D1,2(Σω),

    (ii) every least energy solution of (1.1) is nonradial,

    (iii)Σω is not convex.

    Proof. Recall that the functions uε,ξ, introduced in the proof of Theorem 2.8, vanish outside the ball Br/2(0). Moreover, the value QΣω0(uε,ξ) and the estimate (2.19) depend only on the value of uε,ξ in Br(ξ)Σω0. We fix ε0>0 small enough so that

    Qξ:=QΣω0(uε0,ξ)<S22/N,

    and we set αξ:=1NbNQN/2ξ with bN as in Proposition 3.4. Then,

    αξ<12NbNSN2=12|B1(0)|.

    Given ω(ω0,ξ,r), we fix a function ˆuε0,ξCc(Br(0)) such that ˆuε0,ξ(x)=uε0,ξ(x) if xBr(ξ)Σω0 and ˆuε0,ξ(x)=0 if xBr(ξ)(ΣωΣω0). So, if |Λω|>αξ, we have that

    cΣω1N[QΣω(ˆuε0,ξ)]N2=1NQN2ξ=bNαξ<bN|Λω|=cradΣω.

    Note that ξ is a point of convexity of ω. Hence, by Theorem 3.3 and the previous inequality, cΣω is attained at a nonradial solution of (1.1). Finally, recall that, if Σω were convex, then cΣω=cradΣω; see [8,Theorem 2.4]. This completes the proof.

    Corollary 3.7. There exists a smooth domain ωSN1+ such that the problem (1.1) has a positive nonradial solution in Σω.

    Proof. Let ω0 be the geodesic ball in SN1 of radius π/4 centered at the north pole and let ξ be any point on ω0. Fix r>0 such that Br(ξ)SN1SN1+. Clearly, ξ is a point of convexity of Σω0 of radius r, so we may fix αξ>0 as in Theorem 3.6. As αξ<12|B1(0)|, there exists ω(ω0,ξ,r) with ωSN1+ and |Λω|>αξ. Now, Theorem 3.6 yields a positive nonradial solution to problem (1.1) in Σω.

    Remark 3.8. Let ωSN1+ be such that Σω is convex. Then, every point ξω is a point of convexity of radius r for any r>0. Fix r=1, and fix ε>0 such that

    Qξ:=QΣω(uε,ξ)<S22/Nξω.

    Now, define αξ:=1NbNQN/2ξ, as in Theorem 3.6. Since Σω is convex, we must have that

    |Λω|αξ=|B1(0)|SN/2QN/2ξ,ξω,

    where the equality follows from the definition of bN; see Proposition 3.4. Hence, for any convex cone Σω, we obtain the upper bound

    |Λω||B1(0)|SN/2minξωQξ

    for the measure of Λω, which is given in terms of the Sobolev constant and the local energy of the standard bubbles.

    M. Clapp was partially supported by UNAM-DGAPA-PAPIIT grant IN100718 (Mexico) and CONACYT grant A1-S-10457 (Mexico). F. Pacella was partially supported by PRIN 2015 (Italy) and INDAM-GNAMPA (Italy).

    The authors declare no conflict of interest.



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