Since the outbreak of COVID-19 in Wuhan, China in December 2019, it has spread quickly and become a global pandemic. While the epidemic has been contained well in China due to unprecedented public health interventions, it is still raging or not yet been restrained in some neighboring countries. Chinese government adopted a strict policy of immigration diversion in major entry ports, and it makes Suifenhe port in Heilongjiang Province undertook more importing population. It is essential to understand how imported cases and other key factors of screening affect the epidemic rebound and its mitigation in Heilongjiang Province. Thus we proposed a time switching dynamical system to explore and mimic the disease transmission in three time stages considering importation and control. Cross validation of parameter estimations was carried out to improve the credibility of estimations by fitting the model with eight time series of cumulative numbers simultaneous. Simulation of the dynamics shows that illegal imported cases and imperfect protection in hospitals are the main reasons for the second epidemic wave, the actual border control intensities in the province are relatively effective in early stage. However, a long-term border closure may cause a paradox phenomenon such that it is much harder to restrain the epidemic. Hence it is essential to design an effective border reopening strategy for long-term border control by balancing the limited resources on hotel rooms for quarantine and hospital beds. Our results can be helpful for public health to design border control strategies to suppress COVID-19 transmission.
Citation: Xianghong Zhang, Yunna Song, Sanyi Tang, Haifeng Xue, Wanchun Chen, Lingling Qin, Shoushi Jia, Ying Shen, Shusen Zhao, Huaiping Zhu. Models to assess imported cases on the rebound of COVID-19 and design a long-term border control strategy in Heilongjiang Province, China[J]. Mathematical Biosciences and Engineering, 2022, 19(1): 1-33. doi: 10.3934/mbe.2022001
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Since the outbreak of COVID-19 in Wuhan, China in December 2019, it has spread quickly and become a global pandemic. While the epidemic has been contained well in China due to unprecedented public health interventions, it is still raging or not yet been restrained in some neighboring countries. Chinese government adopted a strict policy of immigration diversion in major entry ports, and it makes Suifenhe port in Heilongjiang Province undertook more importing population. It is essential to understand how imported cases and other key factors of screening affect the epidemic rebound and its mitigation in Heilongjiang Province. Thus we proposed a time switching dynamical system to explore and mimic the disease transmission in three time stages considering importation and control. Cross validation of parameter estimations was carried out to improve the credibility of estimations by fitting the model with eight time series of cumulative numbers simultaneous. Simulation of the dynamics shows that illegal imported cases and imperfect protection in hospitals are the main reasons for the second epidemic wave, the actual border control intensities in the province are relatively effective in early stage. However, a long-term border closure may cause a paradox phenomenon such that it is much harder to restrain the epidemic. Hence it is essential to design an effective border reopening strategy for long-term border control by balancing the limited resources on hotel rooms for quarantine and hospital beds. Our results can be helpful for public health to design border control strategies to suppress COVID-19 transmission.
In this paper, we consider the following initial boundary value problem for higher-order nonlinear viscous parabolic type equations.
{ut+(−Δ)Lu+(−Δ)Kut−∫t0g(t−s)(−Δ)Lu(s)ds=a|u|R−2u,x∈Ω,t≥0, (1.1)u(x,0)=u0(x)∈HL0(Ω), (1.2)∂iu∂vi=0,i=0,1,2,...L−1x∈∂Ω,t≥0, (1.3) |
where L,K≥1 is an integer number, R≥ max {2,2a,2H} where a>0 is a real number, and Ω⊆RN(N≥1) is a bounded domain with a smooth boundary ∂Ω.
Equation (1.1) includes many important physical models. In the absence of the memory term and dispersive term, and with L=K=1 and a=0, Eq (1.1) becomes the linear pseudo-parabolic equation
ut−Δu−βut=0. | (1.4) |
Showalter and Ting [1] and Gopala Rao and Ting [2] investigated the initial boundary value problem of the linear Eq (1.4) and proved the existence and uniqueness of solutions. Pseudo-parabolic equations appear in many applications for natural sciences, such as radiation with time delay [3], two-phase porous media flow models with dynamic capillarity or hysteresis [4], phase field-type models for unsaturated porous media flows [5], heat conduction models [6], models to describe lightning [7], and so on. A number of authors (Showalter [8,9], DiBenedetto and Showalter [10], Cao and Pop [11], Fan and Pop [12], Cuesta and Pop [13], Schweizer [14], Kaikina [15,16], Matahashi and Tsutsumi [17,18]) have considered this kind of equation by various methods and made a lot of progress. Not only were the existence, uniqueness, and nonexistence results for pseudo-parabolic equations were obtained, but the asymptotic behavior, regularity, and other properties of solutions were also investigated.
In 1972, Gopala Rao et al. [2,19] studied the equation ut−kΔut−Δu=0. They use the principle of maximum value to establish the uniqueness and the existence of solutions. Using the potential well method and the comparison principle, Xu and Su[20] studied the overall existence, nonexistence, and asymptotic behavior of the solution of the equation ut−Δut−Δu=uq, and they also proved that the solution blows up in finite time when J(u0)>d.
When L=K=1, Eq (1.1) becomes
ut−Δu=∫t0b(t−τ)Δu(τ)dτ+f(u). | (1.5) |
Equation (1.5) originates from various mathematical models in engineering and physical sciences, such as in the study of heat conduction in materials with memory. Yin [21] discussed the problem of initial boundary values of Eq (1.5) and obtained the global existence of classical solutions under one-sided growth conditions. Replacing the memory term b(⋅) in (1.5) by −g(⋅), Messaoudi[22] proves the blow-up of the solution with negative and vanishing initial energies. When f(u)=|u|q−2u, Messaoudi[23] proved the result of the blow-up of solutions for this equation with positive initial energy under the appropriate conditions of b and q. Sun and Liu [24] studied the equation
ut−Δu−Δut+∫t0g(t−τ)Δu(τ)dτ=uq−2u. | (1.6) |
They applied the Galerkin method, the concavity method, and the improved potential well method to prove existence of a global solution and the blow-up results of the solution when the initial energy J(u(0))≤d(∞), and Di et al. [25] obtained the blow-up results of the solution of Eq (1.6) when the initial energy is negative or positive and gave some upper bounds on the blow-up time, and they proved lower bounds on the blow up time by applying differential inequalities.
When m>1, Cao and Gu[26] studied the higher order parabolic equations
ut+(−Δ)mu=|u|qu. | (1.7) |
By applying variational theory and the Galerkin method, they obtained existence and uniqueness results for the global solution. When the initial value belongs to the negative index critical space H−s,Rs,Rs=nαw−sα, Wang[27,28] proved the existence and uniqueness of the local and the global solutions of the Cauchy problem of Eq (1.7) by using Lr−Lq estimates. Caristi and Mitidieri [29] applied the method in [30] to prove the existence and nonexistence of the global solution of the initial boundary value problem for higher-order parabolic equations when the initial value decays slowly. Budd et al. [31] studied the self-similar solutions of Eq (1.7) for n=1,k>1. Ishige et al. [32] proved the existence of solutions to the Cauchy problem for a class of higher-order semilinear parabolic equations by introducing a new majority kernel, and also gave the existence of a local time solution for the initial data and necessary conditions for the solution of the Cauchy problem, and determine the strongest singularity of the initial data for the solutions of the Cauchy problem.
When K=L,g=0, problem (1.1) becomes the following n-dimensional higher-order proposed parabolic equation
ut(x,t)+(−1)MΔMut(x,t)+(−1)MΔMu(x,t)=a|u|q−1u. | (1.8) |
Equation (1.8) describes some important physical problems [33] and has attracted the attention of many scholars. Xiao and Li [34] have proved the existence of a non-zero weak solution to the static problem of problem (1.8) by means of the mountain passing theorem, and, additionally, based on the method of potential well theory, they proved the existence of a global weak solution of the development in the equations.
Based on the idea of Li and Tsai [35], this paper discusses the property of the solution of problem (1.1)–(1.3) regarding the solution blow-up in finite time under different initial energies E(0). An upper bound on the blow-up time T∗ is established for different initial energies, and, additionally, a lower bound on the blow-up time T∗ is established by applying a differential inequality.
To describe the main results of this paper, this section gives some notations, generalizations, and important lemmas. We adopt the usual notations and convention. Let HL(Ω) denote the Sobolev space with the usual scalar products and norm, Where HL0(Ω) denotes the closure in HL0(Ω) of C∞0(Ω). For simplicity of notation, hereafter we denote by ||.||p the Lebesgue space Lp(Ω) norm, and by ||.|| the L2(Ω) norm; equivalently we write the norm ||DL⋅|| instead of the HL0(Ω) norm ||.||HL0(Ω), where D denotes the gradient operator, that is, D⋅=▽⋅=(∂∂x1,∂∂x2,....∂∂xn). Moreover, DL⋅=△j⋅ if L=2j, and DL⋅=D△j⋅ if L=2j+1.
Lp(Ω)=Lp,||u||Lp(Ω)=||u||p=(∫Ω|u|pdx)1p, |
HL0(Ω)=WL,20(Ω)=HL0,||u||HL0(Ω)=||u||HL0=(∫Ω|u|2+|DLu|2dx)12. |
To justify the main conclusions of this paper, the following assumptions are made on K L, and the relaxation function g(⋅).
(A1) 1≤K<L are integers with 2a≤R<+∞ if n<2L; 2a≤R≤2nn−2L if n>2L,
where a>1
(A2) g:R+→R+ is a C1 function, satisfing
g(t)≥0,g′(t)≤0,2aR−2a<β=1−∫∞0g(s)ds≤1−∫t0g(s)ds. | (2.1) |
Define the energy functional of problem (1.1)−(1.3) as
E(t)=∫t0∥ut∥2+12(1−∫t0g(s)ds)∥DLu∥2+12(g∘DLu)(t)−aR∥u∥RR | (2.2) |
where (g∘DLu)(t)=∫t0g(t−s)∥DLu(t)−DLu(s)∥2ds.
Both sides of Eq (1.1) are simultaneously multiplied by ut and integrated over Ω, and from (A1) and (2.1) we have that
E′(t)=−∥DKut∥2+12(g′∘DLu)(t)−12g(t)∥DLu∥2<0. | (2.3) |
Definition 2.1 We say that u(x,t) is a weak solution of problem (1.1) if u∈L∞([0,T);HL0(Ω)),ut∈L2([0,T);HL0(Ω)), and u satisfies
(ut,v)+(DLu,DLv)+(DKut,DKv)−∫t0g(t−τ)(DLu(τ),DLv)dτ=(a|u|R−2u,v) |
for all test functions v∈HL0(Ω) and t∈[0,T].
Theorem 2.1 (Local existence) Suppose that (A1) and (A2) hold. If (u0,u1)∈HL0(Ω)×L2(Ω), then there exists T>0 such that problem (1.1) admits a unique local solution u(t) which satisfies
u∈L2([0,T);HL0(Ω)),ut∈L2([0,T);L2(Ω)∩L2([0,T];HK0(Ω)). |
Moreover, at least one of the following statements holds true:
∫t0||u||2+||DLu||2→+∞,as t→T,orT=+∞. |
The existence and uniqueness of the local solution for problem (1.1) can be obtained by using Faedo-Galerkin methods and the contraction mapping principle in [30,36,37,38].
Lemma 2.1[39]. Let q be a real number with 2≤q≤+∞ if n≤2L, and 2≤q≤2nn−2L if n>2L. Then there exists a constant B dependent on Ω and q such that
∥u∥q≤B∥DLu∥,u∈HL0(Ω). | (2.4) |
Remark 2.1. According to Eqs (1.1)−(1.3) and Lemma 2.1, we get
E(t)≥12(1−∫t0g(s)ds)‖DLu‖2+12(g∘DLu)(t)−aR‖u‖RR≥12β‖DLu‖2+12(g∘DLu)(t)−aBRR(‖DLu‖2)R2≥12[(g∘DLu)(t)+β‖DLu‖2]−aBRRβR2[β‖DLu‖2+(g∘DLu)(t)]R2=Q([β‖DLu‖2+(g∘DLu)(t)]12). | (2.5) |
Let Q(ξ)=12ξ2−aBRRβR2ξR,ξ=(β‖DLu‖2+(g∘DLu)(t))12>0. A direct calculation yields that Q′(ξ)=ξ−aBRβR2ξR−1,Q″(ξ)=1−a(R−1)BRβR2ξR−2. From Q′(ξ)=0, we get that ξ1=(βaB2)R2(R−2). When ξ=ξ1, direct calculation gives Q″(ξ)=2−R<0. Therefore, Q(ξ) is maximum at ξ1, and its maximum value is
H=Q(ξ1)=R−22R(βaB2)R(R−2)=R−22Rξ21. | (2.6) |
Lemma 2.2. Let conditions (A1),(A2) hold, u be a solution of ((1.1−(1.3)), E(0)<H, and β12‖DLu0‖>ξ1. Then there exists ξ2>ξ1, such that
β‖DLu‖2+(g∘DLu)(t)≥ξ22. | (2.7) |
Proof. From Remark 2.1, Q(ξ) is increasing on (0,ξ1) and decreasing on (ξ1,+∞). Q(ξ)→−∞,(ξ→∞). According to E(0)<H, there exists ξ′2,ξ2 such that ξ1∈(ξ′2,ξ2), and Q(ξ′2)=Q(ξ2)=E(0). To prove Eq (2.7), we use the converse method. Assume that there exists t0>0 such that
β‖DLu(t0)‖2+(g∘DLu)(t0)<ξ22. | (2.8) |
1) If ξ′2<(β‖DLu(t0)‖2+(g∘DLu)(t0))12<ξ2, then
Q([β‖DLu(t0)‖2+(g∘DLu)(t0)]12)>Q(ξ′2)=Q(ξ2)=E(0)>E(t0). |
This contradicts (2.5).
2) If (β‖DLu(t0)‖2+(g∘DLu)(t0))12≤ξ′2.
As β12||DLu0||>ξ1, according to (2.5), Q(β12‖DLu0‖)<E(0)=Q(ξ2), which implies that β12‖DLu0‖>ξ2. Applying the continuity of (β‖DLu(t0)‖2+(g∘DLu)(t0))12, we know that there exists a t1∈(0,t0) such that ξ′2<(β‖DLu(t1)‖2+(g∘DLu)(t1))12<ξ2. hence, we have Q((β‖DLu(t1)‖2+(g∘DLu)(t1))12)>E(0)≥E(t0), which contradicts (2.5).
The following lemma is very important and is similar to the proof of Lemma 4.2 in [35]. Here, we make some appropriate modifications
Lemma 2.3[40]. Let Γ(t) be a nonincreasing function of [t0,∞],t0≥0. Satisfying the differential inequality
Γ′2(t)≥ρ+ψΓ(t)2+1ε,t≥t0 | (2.9) |
where ρ>0,ψ<0, there exists a positive number T∗ such that
limt→T∗Γ(t)=0. | (2.10) |
The upper bound for T∗ is
T∗≤t0+1√−ψln√ρ−ψ√ρ−ψ−Γ(t0) | (2.11) |
where Γ(t0)<min{1,√ρ−ψ}, and Tmax denotes the maximal existence time of the solution
Tmax=sup{T>0:u(.,t)∈[0,T]}<+∞. |
In this section, we will give some blow-up results for solutions with initial energy (i) E(0)<0; (ii) 0≤E(0)<wR−2H; and (iii) wR−2H≤E(0)<||u0||2+||DKu0|||2μ. Moreover, some upper bounds for blow-up time T∗ depending on the sign and size of initial energy E(0) are obtained for problem (1.1)–(1.3).
Define the functionals
Φ(t)=∫t0‖u‖2ds+∫t0‖DKu‖2ds, | (3.1) |
Γ(t)=[Φ(t)+(T0−t)(‖u0‖2+‖DKu0‖2)]−ε | (3.2) |
where 1β≤ε≤R−2a2a, and T0 is positive.
Lemma 3.1. Let X,Y, and ϕ be positive, with p,q≥1,1p+1q=1. Then,
XY≤ϕpXpp+Yqqϕq. | (3.3) |
Lemma 3.2. Let (A1),(A2) hold, u0∈HL0(Ω), and u be a solution of (1.1)−(1.3). Then, we have
Φ″(t)−4(1+ε)∫t0‖ut‖2ds≥Π(t) | (3.4) |
where Π(t)=−4(1+ε)E(0)+w[β‖DLu‖2+(g∘DLu)],w=2ε−12β>0.
Proof. From (3.1), a direct calculation yields that
Φ′(t)=‖u‖2+‖DKu‖2=2∫t0∫Ωuutdxdτ+‖u0‖2+2∫t0∫ΩDKuDKutdxds+‖DKu0‖2, | (3.5) |
Φ″(t)=2∫Ωuutdx+2∫ΩDKuDKutdx=2∫Ωu[−(−△)Lu−(−△)Kut+∫t0g(t−s)(−△)Lu(s)ds+a|u|R−2u]dx+2∫ΩDKuDKutdx=−2‖DLu‖2−ddt‖DKu‖2+2∫t0∫Ωg(t−s)DLu(s)DLu(t)dxds+2a‖u‖RR+ddt‖Dku‖2. | (3.6) |
We infer from (2.2),(2.3), and (3.6) that
Φ″(t)−4(1+ε)∫t0‖ut‖2ds=Φ″(t)−4(1+ε)E(t)+(2+2ε)(1−∫t0g(s)ds)∥DLu∥2+(2+2ε)(g∘DLu)−4a(1+ε)R∥u∥RR≥−4(1+ε)E(0)+2ε∥DLu∥2+(2+2ε)(g∘DLu)+[2−4a(1+ε)R]∥u∥RR−(2+2ε)∫t0g(s)ds‖DLu‖2+2∫t0∫Ωg(t−s)DLu(s)DLu(t)dxds. | (3.7) |
Applying Lemma 3.1 yields
∫t0∫Ωg(t−s)DLu(t)DLu(s)dxds=∫t0∫Ωg(t−s)DLu(t)[DLu(s)−DLu(t)]dxds+∫t0∫Ωg(t−s)DLu(t)Dlu(t)dxds≥−(g∘DLu)(t)+34∫t0g(s)ds‖DLu(t)‖2. | (3.8) |
Combining (3.7) and (3.8), we get
Φ″(t)−4(1+ε)∫t0‖ut‖2ds≥−4(1+ε)E(0)+2ε‖DLu‖2+2ε(g∘DLu)−(12+2ε)∫t0g(s)ds‖DLu‖2>−4(1+ε)E(0)+2ε‖DLu‖2+2ε(g∘DLu)+(12+2ε)(β−1)‖DLu‖2>−4(1+ε)E(0)+w[β‖DLu‖2+(g∘DLu)(t)] | (3.9) |
where w=2ε−12β.
Therom 3.1. Let assumptions (A1) and (A2) hold, and T0<1‖u0‖2+‖DKu0‖2. In addition, it is assumed that one of the following conditions holds true:
(1)E(0)<0;(2)0≤E(0)<wR−2H,β12‖DLu0‖>ξ1;(3)0<wR−2H<E(0)<‖u0‖2+‖DKu0‖2μ. |
Then, the solution of problem (1.1)−(1.3) blows up in finite time, which means the maximum time T∗ of u is finite and
limt→T∗(∫t0‖u‖2ds+∫t0‖DKu‖2ds)=+∞. | (3.10) |
Case (1). if E(0)<0, an upper bound on the blow-up time T∗ can also be estimated according to the sign and size of energy E(0). Then,
T∗≤√−(2ε+1)8ε2(ε+1)E(0)⋅ln11−√T0(‖u0‖2+‖DKu0‖2). |
Case (2). if 0<E(0)<wR−2H, and ξ1<β12‖DLu0‖, then
T∗≤√2ε+18ε2(ε+1)[wR−2H−E(0)]. |
Case (3). if wR−2H≤E(0)<‖u0‖2+‖DKu0‖2μ, then
T∗≤√2ε+12ε2Λχ(0)⋅ln11−√T0(‖u0‖2+‖DKu0‖2) |
where χ(0)=‖u0‖2+‖DKu0‖2−μE(0)=Φ′(0)−μE(0), μ=4(1+δ)Λ,Λ=wβ1B.
Case (1). if E(0)<0, from (3.9) we infer that
Φ″(t)≥−4(1+ε)E(0)+w[β‖DLu‖2+(g∘DLu(t))]+4(1+ε)∫t0‖ut‖2ds>0,t≥0. | (3.11) |
Thus, it follows that Φ′(t) is monotonically increasing. Therefore, Φ′(t)>Φ′(0)=‖u0‖2+‖DKu0‖2
and the second derivative of Eq (3.2) gives
Γ′(t)=−εΓ(t)1+1ε[Φ′(t)−‖u0‖2], | (3.12) |
Γ″(t)=−εΓ(t)1+1ε{Φ″(t)[Φ(t)+(T0−t)(‖u0‖2+‖DKu0‖2)]−(1+ε)[Φ′(t)−‖u0‖2−‖DKu0‖2]2}=−εΓ(t)1+2εV(t) | (3.13) |
where
V(t)=Φ″(t)[Φ(t)+(T0−t)(‖u0‖2+‖DKu0‖2)]−(1+ε)[Φ′(t)−‖u0‖2−‖DKu0‖2]2. |
From Lemma 3.2, we have
Φ″(t)[Φ(t)+(T0−t)(‖u0‖2+‖DKu0‖2)]≥[Π(t)+4(1+ε)∫t0‖ut‖2ds][∫t0‖u‖2ds+∫t0‖DKu‖2ds+(T0−t)(‖u0‖2+DKu0‖2)]≥Π(t)Γ(t)−1ε+4(1+ε)∫t0‖ut‖2ds∫t0‖u‖2ds+4(1+ε)∫t0‖ut‖2ds∫t0‖DKu‖2ds. | (3.14) |
Therefore,
[Φ′(t)−‖u0‖2−‖DKu0‖2]2=4(∫t0∫Ωuutdxds)2+4(∫t0∫ΩDKuDKutdxds)2+8∫t0∫Ωuutdxds∫t0∫ΩDKuDKutdxds. | (3.15) |
Applying Holder's inequality, Lemma 3.1 yields
4(∫t0∫Ωuutdxds)2≤4∫t0‖u‖2ds⋅∫t0‖ut‖2ds, | (3.16) |
4(∫t0∫ΩDKu⋅DKutdxds)2≤4∫t0‖DKu‖2ds⋅∫t0‖DKut‖2ds, | (3.17) |
8∫t0∫Ωuutdxds⋅∫t0∫ΩDKu⋅DKutdxds≤4∫t0‖u‖2ds⋅∫t0‖DKut‖2ds+4∫t0‖DKu‖2ds⋅∫t0‖ut‖2ds. | (3.18) |
Substituting (3.14)−(3.18) into (3.13) yields
V(t)>Π(t)Γ(t)−1ε+4(1+ε)∫t0‖ut‖2ds∫t0‖u‖2ds+4(1+ε)∫t0‖ut‖2ds∫t0‖DKu‖2ds−4(1+ε)∫t0‖DKu‖2ds∫t0‖DKut‖2ds−4(1+ε)∫t0‖u‖2ds∫t0‖ut‖2ds−4(1+ε)∫t0‖u‖2ds∫t0‖DKut‖2ds−4(1+ε)∫t0‖DKu‖2ds∫t0‖ut‖2ds>Π(t)Γ(t)−1ε. | (3.19) |
From the definitions of (3.12), (3.19), and Π(t), it follows that
Γ″(t)≤−εΠ(t)Γ(t)1+1ε≤ε(1+ε)E(0)Γ(t)1+1ε. | (3.20) |
From Φ′(t)>Φ′(0)=‖u0‖2+‖DKu0‖2>0 and (3.12), we get Γ′(t)<0, Γ′(0)=0. (3.20) multiplied by Γ′(t) and integrated over (0,t) gives
Γ′(t)2≥−8ε2(1+ε)1+2εE(0)Γ(0)2+1ε+8ε2(1+ε)1+2εE(0)Γ(0)2+1ε=ρ+ψΓ(t)2+1ε | (3.21) |
where
ρ=−8ε2(1+ε)1+2εE(0)Γ(0)2+1ε>0, | (3.22) |
ψ=8ε2(1+ε)1+2εE(0)<0 | (3.23) |
where Γ(0)=[T0(‖u0‖2+‖DKu0‖2)]−ε.
Combining (3.21)−(3.23) and Lemma 2.3 shows that there exists T∗ such that limt→T∗Γ(t)=0. I.e.
limt→T∗(∫t0‖u‖2ds+‖DKu‖2ds)=+∞. |
Furthermore, according to Lemma 2.3, the upper bound on the blow-up is given by
T∗≤√−(2ε+1)8ε2(1+ε)E(0ln11−√T0(‖u0‖2+‖DKu0‖2). | (3.24) |
Case (2). if 0<E(0)<wR−2H, and β12‖DLu0‖>ξ1, by Lemma 2.2 and the definition of ξ1
Π(t)=−4(1+ε)E(0)+w[β‖DLu‖2+(g∘DLu)(t)]≥−4(1+ε)E(0)+wξ22≥−4(1+ε)E(0)+wξ21>−4(1+ε)E(0)+w4(1+ε)r−2H=4(1+ε)[wr−2H−E(0)]>0. | (3.25) |
Substituting (3.25) into (3.9) yields
Φ″(t)≥Π(t)+(4+4ε)∫t0‖ut‖2ds>(4+4ε)[wR−2H−E(0)]+(4+4ε)∫t0‖ut‖2ds>0. | (3.26) |
Hence, Φ′(t)>Φ′(0)=‖u0‖2+‖DKu0‖2≥0.
Similar to case (1), we get
Γ″(t)=−εΓ(t)1+2ε⋅V(t),V(t)≥Π(t)Γ(t)−1ε. | (3.27) |
From (3.25) and (3.27), we get
Γ″(t)≤−εΠ(t)Γ(t)1+1ε≤−4ε(1+ε)[wR−2H−E(0)]Γ(t)1+1ε,t≥0. | (3.28) |
Similar to case (1), we have Γ′(t)<0, Γ(0)=0. (3.28) Multiply by Γ′(t) and integratig over (0,t) gives
Γ′(t)2≥8ε2(ε+1)2ε+1[wR−2H−E(0)][H(0)2+1ε−H(t)2+1ε]=ρ1+ψ1Γ(t)2+1ε | (3.29) |
where
ρ1=8ε2(ε+1)2ε+1[wR−2H−E(0)]Γ(0)2+1ε>0, | (3.30) |
ψ1=8ε2(ε+1)2ε+1[wR−2H−E(0)]>0. | (3.31) |
By Lemma 2.3 and (3.29)−(3.31), there exists T∗ such that
limt→T∗Γ(t)=0, |
limt→T∗(∫t0‖u‖2ds+∫t0‖DKu‖2 ds)=+∞ |
and
T∗≤√2ε+18ε2(ε+1)[wR−2H−E(0)]ln11−√T0(‖u0‖2+‖DKu0‖2). | (3.32) |
Case (3) : wR−2H≤E(0)<‖u0‖2+‖DKu0‖2μ.
Define
χ(t)=‖u‖2+‖DKu‖2−μE(0)=Φ′(t)−μE(0) | (3.33) |
where μ=4(1+ε)Λ,Λ=wβ1B.
ddtχ(t)=Φ″(t)≥−4(1+ε)E(0)+w[β‖DLu‖2+(g∘DLu)(t)]+4(1+ε)∫t0‖ut‖2ds−4(1+ε)E(0)+wβ1β‖u‖2+4(1+ε)∫t0‖ut‖2ds=wββ[‖u‖2−4(1+ε)BwβE(0)]+4(1+ε)∫t0‖ut‖2ds>Λ[‖u‖2+‖DKu‖2−μE(0)]+4(1+δ)∫t0‖ut‖2ds=Λχ(t)+4(1+ε)∫t0‖ut‖2ds. | (3.34) |
According to (3.31) and
‖u0‖2+‖DKu‖2−μE(0)=Φ′(0)−μE(0)=χ(0)>0 | (3.35) |
we have ddtχ(t)≥Λχ(t), i.e., χ(t)≥χ(0)eΛt. Thereby, we have
χ(t)=Φ′(t)−μE(0)≥χ(0)eΛt≥χ(0)>0,t≥0. | (3.36) |
By (3.34)−(3.36), we obtain
ddtχ(t)=Φ″(t)≥Λχ(t)≥Λχ(0)>0. | (3.37) |
Thus, we get
Φ′(t)>Φ′(0)=‖u0‖2+‖DKu0‖2>0,t>0. |
Similar to the process in case (1), it is possible to derive
Γ″(t)≤−εΠ(t)Γ(t)1+1ε,t≥0. | (3.38) |
By (3.34)−(3.36), we conclude that
Π(t)≥Λχ(t)≥Λχ(0). |
Consequently,
Γ″(t)≤−εΠ(t)Γ(t)1+1ε≤−εΛχ(0)Γ(t)1+1ε,t>0. | (3.39) |
Multiplying both sides of (3.39) by Γ(t), and integrating over [0,t], we have
Γ′(t)2≥2ε2Γχ(0)2ε+1[Γ2+1ε0−Γ(t)2+1ε]=ρ2+ψ2Γ(t)2+1ε, | (3.40) |
ρ2=2ε2Γχ(0)2ε+1Γ(0)2+1ε>0,ψ2=2ε2Γχ(0)2ε+1>0. | (3.41) |
By Lemma 2.3 and (3.40)−(3.41), there exists a time T∗ such that
limt→T∗(∫t0‖u‖2ds+∫t0‖DKu‖2ds)=+∞ |
and
T∗≤√2ε+12ε2Λχ(0)ln11−√T0(‖u0‖2+‖DKu0‖2). |
This section investigates a lower bound on the blow-up time T∗ when the solution of Eqs (1.1)−(1.3) occurs in finite time.
Theorem 4.1. Let A1 and A2 hold, u0∈HL0(Ω), and u be a solution of Eqs (1.1)−(1.3). If u blows up in the sense of HL0(Ω), then the lower bound T∗ of the blow-up can be estimated as
T∗≥∫+∞R(0)1K1+a(4+2R)rBRKR21+4E(0)dK1. |
Proof. Let
R(t)=‖u‖2+‖DLu‖2. | (4.1) |
Differentiating (1.5) with respect to t, we know from (1.1) that
R′(t)=2∫Ωu⋅utdx+ddt‖DLu‖2=2∫Ωu[−(−Δ)Lu−(−Δ)Kut] | (4.2) |
+2∫Ωu[∫t0g(t−s)(−Δ)Lu(s)ds+a|u|R−2u+ddt‖DLu‖2]=−2‖DLu‖2+2∬Ωg(t−s)DLu(s)DLu(t)dxds | (4.3) |
+2a‖u‖RR−ddt‖DKu‖2+ddt‖DLu‖2. | (4.4) |
By Lemma 3.1, we have
2∫t0∫Ωg(t−s)DLu(s)DLu(t)dxds≤2(g∘DLu‖2+12∫t0g(s)ds‖DLu‖2+2∫t0g(s)‖DLu‖2=2(g∘DLu‖2+52∫t0g(s)ds‖DLu‖2. | (4.5) |
Substituting (4.5) into (1.6) yields
R′(t)≤[52∫t0g(s)ds−1]‖DLu‖2+12‖DL‖2+2(g∘DLu)(t)+2a‖u‖RR−ddt‖DKu‖2+ddt‖DLu‖2<12‖DL‖2+4∫t0‖ut‖2ds+2(1−∫t0g(s)ds)‖DLu‖2+2(g∘DLu)(t)−4aR‖u‖RR+(4aR+2a)‖u‖RR<R(t)+4E(0)+a(4R+2)BR‖DLu‖R<R(t)+4E(0)+a(4R+2)BRR(t)R2. | (4.6) |
Integrating (4.6) over [0,t] yields
∫R(t)R(0)1K1+a4+2RRBRKR21+4E(0)dK1≤t. | (4.7) |
If u blows up with HL0, then T∗ has a lower bound
T∗≥∫+∞R(0)1K1+a4+2RRBRKR21+4E(0), | (4.8) |
which thereby completes the proof of Theorem 4.1.
By using concavity analysis, we get the blow-up results of the solution when the initial energy is negative or positive and an upper bound on the blow-up time T∗. In addition, a lower bound on the blow-up time T∗ is obtained by applying differential inequalities in the case where the solution has a blow-up.
The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.
The authors declare there is no conflict of interest.
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