Citation: Bo Zheng, Wenliang Guo, Linchao Hu, Mugen Huang, Jianshe Yu. Complex wolbachia infection dynamics in mosquitoes with imperfect maternal transmission[J]. Mathematical Biosciences and Engineering, 2018, 15(2): 523-541. doi: 10.3934/mbe.2018024
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Aedes aegypti, Aedes albopictus, and Anopheles stephensi, are the primary vectors of some life-threatening mosquito-borne diseases such as dengue, malaria, and Zika. Since there are no effective vaccines available for these diseases, current controls mostly rely on environmental management by destructing vector breeding sites physically or chemically. Unfortunately, the chemical method of spraying pesticides causes severe environmental pollution and induces mosquito's insecticide resistance.
The study on the interaction of Wolbachia and mosquitoes has flourished due to the groundbreaking work [1,2,37,38,39,40], which paved an avenue for a biologically safe method of mosquito-borne disease control [5,10,17,18]. As expected, Wolbachia can block the replication of viruses such as dengue and Zika inside the mosquitoes [1,37,38,39,40] and confer resistance to the human malaria parasite Plasmodium falciparum [2]. In mosquitoes, maternally transmitted Wolbachia is associated with cytoplasmic incompatibility (CI), i.e., the reduced hatch rate of embryos produced from fertilization of uninfected ova by sperm from Wolbachia infected males. Infected females therefore have a reproductive advantage, allowing Wolbachia to spread in polymorphic populations [4,9,14].
An appealing strategy is to release a large number of Wolbachia infected males in the natural area so that the CI mechanism can drive all the mated females sterile and the whole population can be suppressed. However, a complete population suppression requires a nearly perfect separation of males from infected females, which exerts tremendous challenges in extending this technology over large areas. An alternative strategy to meet the challenge is to seed the natural population with infected mosquitoes, both male and female, so the reproductive advantage for infected females induced by CI and the high maternal transmission rate can drive Wolbachia infected mosquitoes to replace the wild population. For the success of population replacement, it is critical to identify the release threshold: above which Wolbachia will invade all mosquitoes, but below which it will be wiped out [4,9,12,34].
Some earlier mathematical models making use of difference equations have played an instrumental role in determining the release threshold for Wolbachia fixation in non-overlapping populations in laboratory [4,9]. Inspired by its great potential to eliminate the mosquito-borne diseases, modeling Wolbachia spread dynamics parameterized by laboratory or field data [7,11,14,23,27,36] has emerged as a hot topic for extensive studies. There have been models of ordinary [8,22,29], delayed differential equations [41] built to explore the subtle relations between Wolbachia invasion and important parameters. Such parameters include: (Infection peak versus the rate at which protective susceptible individuals forget) the maternal transmission rate (
In most of the current theoretical studies on Wolbachia spreading dynamics in mosquitoes, it was assumed that maternal transmission is perfect (
However, imperfect maternal transmission
It was predominantly believed that the maternal transmission of Wolbachia in mosquitoes is perfect. However, a very recent study [28] demonstrates that high temperatures (26-37
To proceed, we divide the mosquitoes into four classes: uninfected females
dIdt=bII⋅II+U+bI(1−μ)I⋅UI+U−δII(I+U), | (1) |
dUdt=bIμI⋅UI+U+bU⋅U⋅(1−II+U)−δUU(I+U). | (2) |
In (2), the first term accounts for the birth of uninfected progeny from infected mothers, and the second term accounts for the birth from uninfected mothers, who have a probability
If we apply the rescaling
x=δUbUI,y=δUbUU,s=bUt,β=bIbU,δ=δIδU, | (3) |
and rewrite
dxdt=βx2x+y+β(1−μ)xyx+y−δx(x+y):=f(x,y), | (4) |
dydt=βμxyx+y+y2x+y−y(x+y):=g(x,y). | (5) |
In [41], we studied the case of perfect maternal transmission (i.e.,
The remaining part of this paper is divided into three sections. In Section 2, we prove invariance and boundedness of solutions to system (4)-(5), and present two useful identities together with additional preliminary results. These help us study the global dynamics in Section 3 and prove that the system can exhibit monomorphic, bistable, and polymorphic dynamics, and give sufficient and necessary conditions for each case. Imperfect maternal transmission could lead to infinitely many polymorphic states, see Theorem 3.1. Also, our discussions in Section 4 highlights some challenges associated with the release of
Noticing that
Lemma 2.1. Every solution of (4)-(5) initiated from the first quadrant is bounded. Moreover, for each
ω(x0,y0)⊂{(x,y):0≤x≤β(2−μ)/δ, 0≤y≤βμ+1}, | (6) |
where
Proof. Let
x′(t)<βx+β(1−μ)x−δx2=δx[β(2−μ)δ−x] |
Hence
lim supt→∞x(t)≤β(2−μ)/δ. |
Similarly, if
y′(t)<(βμ+1)y−y2=y(βμ+1−y)<0, |
and so
Besides
Γx:βx+β(1−μ)y=δ(x+y)2, | (7) |
Γy:βμx+y=(x+y)2. | (8) |
Multiplying (8) by
(C1):μδ=1,andβ(1−μ)=δ. |
When (C1) is not satisfied, we subtract (7) by the product of (8) with
β(1−μδ)x=[δ−β(1−μ)]y. | (9) |
Lemma 2.2. System (4)-(5) admits interior equilibrium points if and only if one of the following conditions holds:
(C2):
(C3):
In this case, there is exactly one interior equilibrium point given by
x∗=βμ+k(1+k)2,y∗=k(βμ+k)(1+k)2, | (10) |
where
k:=β(1−μδ)δ−β(1−μ). | (11) |
Proof. If the system admits interior equilibrium point
If none of (C1)-(C3) holds, then system (4)-(5) does not admit any interior equilibrium point. For convenience of later discussion, we classify the remaining cases as the following 6 cases.
(C4):
(C5):
(C6):
(C7):
(C8):
(C9):
As
J=(β−βμ⋅y2(x+y)2−δ(2x+y)−βμ⋅x2(x+y)2−δx(βμ−1)⋅y2(x+y)2−yβμ⋅x2(x+y)2+y(2x+y)(x+y)2−(x+2y)). | (12) |
At
J(E1)=(−β−β(μ+1)0β(μδ−1)/δ),J(E2)=(β(1−μ)−δ0βμ−2−1) |
and at
J(E∗)=(β−βμk2(k+1)2−δ(2+k)x∗−βμ(k+1)2−δx∗(βμ−1)⋅k2(k+1)2−kx∗βμ(k+1)2+k(k+2)(k+1)2−(1+2k)x∗). |
Lemma 2.3. (i) At
detJ(E∗)=βk(k+1)2[β(1−μ)δ⋅μδ−1]. | (13) |
(ii) The trace of
trJ(E∗)=−k2+(1−β)k−β(k+1)2. | (14) |
Proof. Write
J11=β−βμk2(k+1)2−δ(2+k)βμ+k(1+k)2=1(k+1)2[β(k+1)2−βμk2−δ(2+k)(βμ+k)]=1(k+1)2[(β(1−μ)−δ)k2+(2β−βμδ−2δ)k+β(1−2μδ)]. |
By the definition of
[β(1−μ)−δ]k=−β(1−μδ), |
and hence
J11=1(k+1)2[−β(1−μδ)k+(2β−βμδ−2δ)k+β(1−2μδ)]=1(k+1)2[(β−2δ)k+β(1−2μδ)]. |
The other three entries
J(E∗)=1(k+1)4((β−2δ)k+β(1−2μδ)−δk−βμ(1+δ)k[(βμ−2)k−βμ]k[−k+(1−2βμ)]). |
(i) For notation simplicity, instead of calculating
ˉJ:=(k+1)4kdetJ(E∗), |
and then
ˉJ=[(β−2δ)k+β(1−2μδ)]⋅[−k+(1−2βμ)]+[δk+βμ(1+δ)]⋅[(βμ−2)k−βμ]=−β(1−μδ)k2+[(βμ)2δ+(βμ)2+3βμδ−2β2μ−2βμ−2δ]k+3(βμ)2δ+β−(βμ)2−2β2μ−2βμδ. |
Note that (11) is equivalent to each of the following two identities
δk=β(1−μ)k+β(1−μδ), | (15) |
βμδ=β+[β(1−μ)−δ]k, | (16) |
which help us simplify
1βˉJ=−(1−μδ)k2+{βμ+μ[β(1−μ)−δ]k+βμ2+3μδ−2βμ−2μ}k−2(1−μ)k−2(1−μδ)+3μ{β+[β(1−μ)−δ]k}+1−βμ2−2βμ−2μδ=(βμ−βμ2−1)k2+2(βμ−βμ2−1)k+(βμ−βμ2−1)=(βμ−βμ2−1)(k+1)2=[β(1−μ)δ⋅μδ−1](k+1)2. |
Therefore
detJ(E∗)=k(k+1)4ˉJ=βk(k+1)2[β(1−μ)δ⋅μδ−1]. |
(ii) Again, by using of (15),
trJ∗=J11+J22=1(k+1)2[(β−2δ)k+β(1−2μδ)−k2+(1−2βμ)k]=1(k+1)2[−k2+(β−2δ+1−2βμ)k+β(1−2μδ)]=1(k+1)2[−k2+(β+1−2βμ)k−2δk+β(1−2μδ)]=1(k+1)2[−k2+(β+1−2βμ)k−2β(1−μ)k−2β(1−μδ)+β(1−2μδ)]=1(k+1)2[−k2+(1−β)k−β]. |
This completes the proof.
Lemma 2.4. Assume that
ztz(t)=ln(x1/δ(t)y−1(t)) | (17) |
Then the derivative of
z′(t)z′(t)=βδ(1−μδ)xx+y+[β(1−μ)δ−1]yx+y. | (18) |
Proof. By rewriting
z′(t)=f(x,y)δx−g(x,y)y=βδxx+y+β(1−μ)δyx+y−βμxx+y−yx+y=βδ(1−μδ)xx+y+[β(1−μ)δ−1]yx+y. |
This completes the proof.
For fixed constant
Lemma 2.5. For fixed constant
lc′(t)l′c(t)|Lc=y[(δ−1)f(x,y)δx+z′(t)]. | (19) |
proof. By interchanging
l′c(t)|Lc=c[βx2x+y+β(1−μ)xyx+y−δx(x+y)]−[βμxyx+y+y2x+y−y(x+y)]=y[βxx+y+β(1−μ)yx+y−δ(x+y)−βμxx+y−yx+y+(x+y)]=y[β(1−μ)−yx+y−(δ−1)(x+y)]=y{(δ−1)[βδ−βμδyx+y−(x+y)]+β(1−μ)−yx+y+βμ(δ−1)δyx+y−β(δ−1)δ}=y{(δ−1)[βδ−βμδyx+y−(x+y)]+[βδ−βμδyx+y−βμxx+y−yx+y]}=y{(δ−1)[βδ−βμδyx+y−(x+y)]+βδ(1−μδ)xx+y+[β(1−μ)δ−1]yx+y}. |
By applying the relation (18) and
βδ−βμδyx+y−(x+y)=f(x,y)δx, |
the proof is completed.
Assume that (C1) holds. Then both
dydx=yδx, | (20) |
and the two nullclines defined in (7) and (8) are identical. All points on this coincident nullcline in
Theorem 3.1. Let (C1) hold. Let
y=y0(xx0)1/δ, | (21) |
and
Proof. The relation (21) is easily derived by solving (20) with the initial condition. The only non-trivial part in the proof of the remaining conclusions is to show that
Let
β(1−μ)=δ=1μ⟹βμ=11−μ>1, |
it holds that
x+y<βμx+y=(x+y)2<βμx+βμy,1<x+y<βμ. |
Now if
dydx=−2(x+y)−βμ2(x+y)−1<0. |
Hence
If
yδx>βμ−2(x+y)2(x+y)−1. | (22) |
Actually, by using
(22)⇔y[2(x+y)−1]>δx[βμ−2(x+y)]⇔2y(x+y)−y>βx−2δx(x+y)⇔2(x+y)(y+δx)>βx+y⇔2(x+y)2(y+δx)>(βx+y)(x+y)⇔2(y+βμx)(y+δx)>(y+βx)(y+x)⇔y2+[2δ+2βμ−β−1]xy+βx2>0. |
The last inequality always holds for case (C1) due to
β=δ1−μ=1μ(1−μ)>1, |
and hence
2δ+2βμ−β−1=2β(1−μ)+2βμ−β−1=β−1>0. |
This completes the proof.
The following theorem shows that Condition (C2) leads to a polymorphic scenario.
Theorem 3.2. Let (C2) hold. Then both
Proof.Both
μδ>1⇒δ>1⇒β(1−μ)>δ>1⇒β>11−μ>1, | (23) |
and hence,
trJ(E∗)=−k2+(1−β)k−β(k+1)2<0. |
Thus
B(x,y)=1/(xy2)>0 | (24) |
in
∇⋅(Bf,Bg)=∂∂x[βxy2(x+y)+β(1−μ)y(x+y)−δ(x+y)y2]+∂∂y[βμy(x+y)+1x(x+y)−x+yxy]=βy(x+y)2−β(1−μ)y(x+y)2−δy2−βμx+2yy2(x+y)2−1x(x+y)2+1y2=−βμ[xy2(x+y)2+1y(x+y)2]−1x(x+y)2+1−δy2<0 |
which declares nonexistence of closed orbits in
The following theorem indicates that (C3) corresponds to a bistable scenario.
Theorem 3.3. Assume that (C3) holds. Then the unique interior equilibrium point
h0(x)=y∗x∗x,h1(x)=y∗(xx∗)1/δ. | (25) |
Proof.Condition
Noticing that along
z′(t)|y=cx=β(1−μδ)−[δ−β(1−μ)]cδ(1+c). | (26) |
We have
z′(t)|y=cx=0⇔c=k;z′(t)|y=cx<0⇔c>k;z′(t)|y=cx>0⇔c<k. | (27) |
By (19), we have
l′k(t)|Lk=y(δ−1)f(x,y)δx. |
There are three cases to consider.
(i)
(ii)
D1={(x,y):0<x<x∗, h0(x)<y<h1(x)}. |
We claim that
l′k(t)|Lk=y(δ−1)f(x,y)δx>0. |
It follows that solutions of system (4)-(5) initiated within
Similarly, consider
D2={(x,y):x>x∗,h1(x)<y<h0(x)}. |
Then we have
(iii)
D3={(x,y):0<x<x∗,h1(x)<y<h0(x)} |
and
D4={(x,y):x>x∗,h0(x)<y<h1(x)} |
could be proved by dissecting the sign of
Theorem 3.4. Assume that one of the Conditions (C4), (C5) and (C6) holds. Then
Proof.From (18),
Theorem 3.5. Assume that one of the Conditions (C7), (C8) and (C9) holds. Then
Proof.It is easily seen that
The asymptotic behavior of the Wolbachia spreading dynamics in a mixed population of infected and uninfected mosquitoes depends strongly on the life parameters modified by the Wolbachia infection. We classify the system parameters into Cases (C1) to (C9) and identify their correspondence to three different scenarios:
Polymorphism: Theorems 3.1 and 3.2 show that the mixed population remains polymorphic for which both infected and uninfected mosquitoes coexist when (C1) or (C2) holds. If the degenerate case (C1) occurs, then the ultimate coexistent state may change with the initial infection level. When (C2) occurs, the asymptotic population size is independent of the initial value and the infection frequency at the steady-state is
Bistability: For case (C3), Theorem 3.3 offers a sharp threshold given by the separatrix
Monomorphism: Theorem 3.4 implies that under either (C4) or (C5) or (C6), for any initial positive release, the Wolbachia infected mosquitoes will eventually replace the wild ones. Theorem 3.5 shows that under either (C7) or (C8) or (C9), Wolbachia infection will fail to establish, regardless of the number of initial release.
With perfect maternal transmission rate, i.e.,
dxdt=βx−δx(x+y), | (28) |
dydt=y2x+y−y(x+y) | (29) |
When
Comparing to perfect maternal transmission, the imperfect maternal transmission generates richer dynamics. To see this, we fix
ν1=1δ,ν2=1−δβ. |
The detailed outcomes in different cases are shown in Figure 3. For example, in the fitness cost case (i), small
We consider two Wolbachia strains, the benign
β=0.39760.3976=1,δ=9.4482×10−68.5034×10−6≈1.1111 |
for the benign
β=0.21540.3976≈0.5418,δ=1.4172×10−58.5034×10−6≈1.6667 |
for the virulent
In 2011, the Wolbachia strain
In contrast to the effective and sustainable invasion of the
We can claim that maternal transmission leakage even makes a transient establishment of Wolbachia in the wild mosquito population a big challenge. Consider again the
dxdt=βx2x+y+β(1−μ)xyx+y−δx(x+y), | (30) |
dydt=βμxyx+y+y⋅(1−sh⋅xx+y)−y(x+y). | (31) |
Again, we can determine the unique threshold value
This work was supported by National Natural Science Foundation of China (11631005,11626246,11571084), Program for Changjiang Scholars and Innovative Research Team in University (IRT_16R16), and National Research and Development Plan of China (2016YFC1200500). We thank the anonymous reviewers for their careful reading of our manuscript and stimulating comments.
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