Citation: Chen Huang, Gao Jia. Schrödinger-Poisson system without growth and the Ambrosetti-Rabinowitz conditions[J]. AIMS Mathematics, 2020, 5(2): 1319-1332. doi: 10.3934/math.2020090
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In this paper, we are interested in finding nontrivial solutions to the following one-parameter family of Schrödinger-Poisson system:
{−Δu+V(x)u+ϕu=λf(u),in R3,−Δϕ=u2, lim|x|→+∞ϕ(x)=0,in R3. | (1.1) |
In recent years, system (1.1) has been studied widely due to the fact that it arises in several physical phenomena (see [3,4,5,9,18]). From the viewpoint of quantum mechanics, this system describes a charged wave interacting with its own electrostatic field in the case that magnetic effects could be ignored. The terms u and ϕ describe the wave functions associated to the particle and electric potential. The term ϕu is nonlocal and concerns the interactions with electric field. The nonlinearity models the interaction between the particles and external nonlinear perturbations.
There has been a lot of contributions about the following Schrödinger-Poisson system
{−Δu+V(x)u+ϕu=f(x,u),in R3,−Δϕ=u2, lim|x|→+∞ϕ(x)=0,in R3, | (1.2) |
which was first introduced in [4]. The case V(x)=1 and f(x,u)=|u|p−2u, 2<p<6, has been studied in [7], where Ruiz gave existence and nonexistence results. The existence of a ground state solution of (1.2) with f(x,u)=|u|p−2u and 3<p<6 was proved by Azzollini [1]. For the general nonlinearity f and the potential V(x), in [6,12,13,15,20,21], the authors studied the existence and multiplicity of nontrivial solutions for the Schrödinger-Poisson system with superlinear and subcritical growth condition. The following global Ambrosetti-Rabinowitz type condition plays a crucial role in the above mentioned papers:
0<F(u):=∫u0f(s)ds≤1γuf(u), | (A−R) |
where γ>4. Since the nonlocal term ∫R3ϕuu2 in the energy functional of (1.2) is homogeneous of degree 4, if γ>4 from (A-R) then Ambrosetti-Rabinowitz condition guarantees boundedness of Palais-Smale sequences as well as existence of a mountain pass geometry.
It is very natural for us to pose the question: Can we replace (A-R) with a weaker condition? When V(x) is periodic or asymptotically periodic and f(u) does not satisfy the Ambrosetti-Rabinowitz condition, Alves, Souto and Soares [2] established the existence of positive ground state solutions by using the mountain pass theorem. In [14] Mao et al. studied the following Schrödinger-Poisson system of the form
{−Δu+V(x)u+εϕu=λf(u),in R3,−Δϕ=u2, lim|x|→+∞ϕ(x)=0,in R3,u>0,in R3, |
where f satisfies 0<4F(s)≤sf(s), for s>0 is small. Under the conditions that ε is small and λ is large, the authors proved the existence of a positive solution. Differently from the above-mentioned results, the purpose of this paper is to present some existence and multiplicity results of solutions of problem (1.1) under the nonlinearity f(t) which possesses only conditions in a neighborhood of the origin. More importantly, we consider the case that f satisfies 0<γF(t)≤tf(t) where γ∈(3,4], for t>0 is small. To the best of our knowledge, there are less results in the literatures on the case γ∈(3,4).
Firstly, we study problem (1.1) under the following conditions:
(V1): V∈C(R3,R), 0<VL≤V(x) for all x∈R3 and V(x) is coercive, i.e., lim|x|→∞V(x)=∞;
(V2): V∈C1(R3,R) and 2V(x)+∇V(x)⋅x≥0 for a.e. x∈R3 and ∇V(x)⋅x∈Lr(R3) for some r∈[32,∞].
(f0): f(t)=0 for t≤0;
(f1): there exists α∈(4,2∗) such that lim supt→0+f(t)ttα<+∞, where 2∗=6;
(f2): there exists β∈(4,2∗) such that lim inft→0+F(t)tβ>0;
(f3): there exists 3<γ≤4 such that 0<γF(t)≤tf(t), for t>0 is small;
(f′1): there exists α∈(4,2∗) such that lim supt→0f(t)t|t|α<+∞;
(f′2): there exists β∈(4,2∗) such that lim inft→0F(t)|t|β>0, where F(t)=∫t0f(s)ds;
(f′3): there exists ˜γ>4 such that 0<˜γF(t)≤tf(t), for |t| small and t≠0;
(f4): f(−t)=−f(t), for |t| small.
Next, we give our main results.
Theorem 1.1. Assume (V1), (V2) and (f0)−(f3) hold. Then the problem (1.1) has a positive solution u∈X (X is defined in Sect.2) for all sufficiently large λ.
Remark 1.1. (V2) is used to obtain a special bounded Palais-Smale sequence with Jeanjean's monotonicity trick. That ∇V(x)⋅x∈Lr(R3) for some r∈[32,∞] plays an important role in deriving the Pohozaev identity for the weak solutions of (2.2).
To prove Theorem 1.1, we are faced with several difficulties. On one hand, due to the nonlinearity f without any growth condition at infinity, the natural variational functional associated to (1.1) may be not well defined. Inspired by work of Costa [8] and Huang [10], we modify f(t) to a new well-defined nonlinearity. Furthermore by Moser iteration, we shall show that for large λ, the solutions of the modified problem are the solutions of the original problem.
On the other hand, different from [8] and [14], since we don't assume the global Ambrosetti-Rabinowitz condition about f(t), the boundedness of Palais-Smale sequence seems hard to verify. We use an argument developed by Jeanjean [11] to overcome this difficulty. Then Pohozaev type identity [19] and the condition (V2) are used to construct a special bounded Palais-Smale sequence for the modified functional Jλ (will be defined in Section 2).
Theorem 1.2. Assume (V1), (f′1)−(f′3) and (f4) hold. Then for any given positive integer k≥1 the problem (1.1) has k pairs of solutions ±ui∈X(i=1,2,...,k) for all sufficiently large λ.
The key to prove Theorem 1.2 is a priori estimate of the weak solution for the modified problem. Firstly, we modify f to a new nonlinearity h which is odd and satisfies the Ambrosetti-Rabinowitz condition (see Lemma 2.1). By symmetric mountain pass theorem, the modified problem has a sequence of weak solutions. Secondly, it will be shown that the solutions converge to zero in L∞-norm as λ→∞. Therefore, for λ large, they are solutions of the original problem.
Remark 1.2. It is evident that the following function satisfies hypotheses (f′1)−(f′3) and (f4):
f(t)=C1|t|α−2t+C2|t|q−2t, |
where 4<α<2∗<q<∞ and C1, C2 are positive constants.
This paper is organized as follows. In Section 2, we describe the related mathematical tools and give the proof of Theorem 1.1. Theorem 1.2 is proved in Section 3.
In what follows, C and Ci will denote positive generic constants.
As usual, the norm of Ls(RN) (s≥1) is denoted by |⋅|s. Define
X={u∈D1,2(R3): ∫R3V(x)u2dx<∞} |
endowed with the following norm
‖u‖=(∫RN(|∇u|2+V(x)u2)dx)1/2. |
By (V1), it well known that X↪Lp(R3) continuously for p∈[2,6], compactly for p∈[2,6).
By the conditions (f0), (f1) and (f2), there exist positive constants δ∈(0,12), C3 and C4 such that
F(t)≤C3tα and F(t)≥C4tβ for 0≤t≤2δ. | (2.1) |
For the fixed δ>0, we now consider d(t)∈C1(R,R) is a cut-off function satisfying
d(t)={1, if t≤δ,0, if t≥2δ, |
|d′(t)|≤2δ and 0≤d(t)≤1 for t∈[δ,2δ]. Define G(t)=d(t)F(t)+(1−d(t))F∞(t), where
F∞(t)={C3|t|α, if t>0,0, if t≤0. |
Set g(t)=G′(t). We observe that the conditions (f0)–(f3) imply some properties of g(t).
Lemma 2.1. (1) g∈C(R,R), g(t)=0, for all t≤0 and g(t)=o(1) as t→0+;
(2) limt→+∞g(t)t3=+∞;
(3) there exists C5>0 such that g(t)≤C5tα−1, for all t≥0;
(4) for any T>0, there exists a constant C(T)>0 such that G(t)≥C(T)tβ for all t∈[0,T];
(5) for all t>0, we have 0<γG(t)≤tg(t).
By [17], for every u∈H1(R3), there exists a unique ϕu∈D1,2(R3) such that
−Δϕu=u2 |
and
∫R3∇ϕu⋅∇vdx=∫R3u2vdx, for all v∈D1,2(R3). |
It has the following properties:
Lemma 2.2. For any u∈X⊂H1(R3), we have
(1) ϕu≥0;
(2) ϕtu=t2ϕu;
(3) ‖ϕu‖2D1,2=∫R3ϕuu2dx≤C6|u|412/5≤C7‖u‖4, where C6, C7 are constants.
We now consider the modified equation of (1.1) given by
{−Δu+V(x)u+ϕu=λg(u),in R3,−Δϕ=u2, lim|x|→+∞ϕ(x)=0,in R3. | (2.2) |
By definition of G and Lemma 2.1, for u∈X, the functional associated to (2.2) given by
Jλ(u)=12∫R3(|∇u|2+V(x)u2)dx+14∫R3ϕu(x)u2dx−λ∫R3G(u)dx | (2.3) |
is well-defined.
Noticing that we can not ensure that the modified nonlinearity g satisfies the classical Ambrosetti-Rabinowitz condition, the boundedness of Palais-Smale sequence seems hard to prove. The following abstract result [11] is used to construct a special Palais-Smale sequence.
Proposition 1. Let X be a Banach space equipped with a norm ‖⋅‖X and let J⊂R+ be an interval. {Φμ}μ∈J are C1-functionals on X of the form
Φμ(u)=A(u)−μB(u), for all μ∈J, |
where B(u)≥0 for all u∈X and either A(u)→+∞ or B(u)→+∞ as ‖u‖X→+∞. Suppose that there exist two points u1, u2∈X such that
cμ=infγ∈Γmaxt∈[0,1]Φμ(γ(t))>max{Φμ(u1),Φμ(u2)}, for all μ∈J, |
where Γ={γ∈C([0,1],X): γ(0)=u1, γ(1)=u2}. Then, for almost every μ∈J, there exists a sequence {un(μ)}⊂X such that
(1) {un(μ)} is bounded in X,
(2) Φμ(un(μ))→cμ,
(3) Φ′μ(un(μ))→0, in X∗, where X∗ is dual space of X.
Furthermore, the map μ→cμ is continuous from the left.
Consider a family of functionals
Jμ,λ(u):=12∫R3(|∇u|2+V(x)u2)dx+14∫R3ϕu(x)u2dx−μ∫R3λG(u)dx,u∈X. | (2.4) |
Denote A(u)=12∫R3(|∇u|2+V(x)u2)dx+14∫R3ϕu(x)u2dx, B(u)=∫R3λG(u)dx and J=[12,1]. Then Jμ,λ(u)=A(u)−μB(u). The next lemma ensures that Jμ,λ satisfies all assumptions of Proposition 1.
Lemma 2.3. Assume that (V1) and (f0)−(f2) hold. For all u∈X, then
(1) B(u)≥0;
(2) A(u)→∞ as ‖u‖→∞;
(3) there exists u0∈X, independent of μ, such that Jμ,λ(u0)<0 for all μ∈[12,1];
(4) for all μ∈[12,1], it holds
cμ=infγ∈Γmaxt∈[0,1]Jμ,λ(γ(t))>max{Jμ,λ(γ(0)),Jμ,λ(γ(1))}, |
where Γ={γ∈C([0,1],X): γ(0)=0, γ(1)=u0}.
Proof. From Lemma 2.1-(1) and (V1), (1) and (2) are proved directly. To prove (3), let us fix some nonnegative radially symmetric function e(x)∈C∞0(R3)∖{0}. Then, for t>0, we have
J1/2,λ(te)=t22∫R3|∇e|2dx+t22∫R3V(x)e2dx+t44∫R3ϕe(x)e2dx−12∫R3λG(te)dx≤t42(1t2‖e‖2+12∫R3ϕe(x)e2dx−∫R3λG(te)t4dx). | (2.5) |
By Lemma 2.1-(2), it is easy to see that J1/2,λ(te)<0 for t large.
It remains to prove (4). By Lemma 2.1-(3) and the Sobolev embedding theorem, we have
Jμ,λ(u)≥12∫R3(|∇u|2+V(x)u2)dx−μ∫R3λG(u)dx≥12‖u‖2−C8‖u‖α. |
From this, we get cμ>0 and complete the proof.
Remark 2.1. By Lemma 2.3 and Proposition 1, then for almost every μ∈[12,1], there exists a sequence {un}⊂X satisfying
{un} is bounded in X, Jμ,λ(un)→cμ and J′μ,λ(un)→0 in X∗. | (2.6) |
Lemma 2.4. The sequence {un} given in (2.6), up to subsequence, converges to a positive critical point uμ of Jμ,λ with Jμ,λ(uμ)=cμ.
Proof. Since {un} is bounded in X, we have
un⇀uμ in X, un→uμ in Lα(R3), un→uμ a.e. in RN, |
for some uμ∈X. For all φ∈C∞0(R3), using Lebesgue's Theorem, we have that
⟨J′μ,λ(un)−J′μ,λ(uμ),φ⟩→0, |
where we used un⇀uμ in X, Lemma 2.1-(3) and un→uμ in Lα(R3). Thus recalling that J′μ,λ(un)→0 we indeed have J′μ,λ(uμ)=0.
Next we prove un→uμ in X. Using Lemma 2.1-(3) and the fact un→uμ in Lα(R3), we get
limn→+∞∫R3(g(un)−g(uμ))(un−uμ)dx=0. |
Hence
on(1)=⟨J′μ,λ(un)−J′μ,λ(uμ),un−uμ⟩=∫R3(∇un−∇uμ)2dx+∫R3V(x)(un−uμ)2dx+∫R3(ϕunun−ϕuμuμ)(un−uμ)dx−μ∫R3λ(g(un)−g(uμ))(un−uμ)dx=‖un−uμ‖2+on(1), | (2.7) |
where we used the elementary inequalities
|∫R3(ϕunun−ϕuμuμ)(un−uμ)dx|≤|∫R3ϕun(un−uμ)2dx|+|∫R3(ϕun−ϕuμ)uμ(un−uμ)dx|≤|ϕun|6|un−uμ|212/5+|ϕun−ϕuμ|6|un−uμ|12/5|u|12/5. | (2.8) |
Therefore, un→uμ in X. The positivity of uμ follows by a standard argument (see [19]).
To show the above results are true when μ=1, we need the following remark and lemmas.
Remark 2.2. Assume that (V1) and (f0)−(f2) hold. Then there exist {μn}⊂[12,1] and {uμn}⊂X∖{0} such that limn→+∞μn=1, uμn>0, Jμn,λ(uμn)=cμn≤c12 and J′μn,λ(uμn)=0.
Lemma 2.5. (See [12]) If u∈X is a critical point of Jμ,λ and (V1) holds, then
12∫R3|∇u|2dx+32∫R3V(x)u2dx+54∫R3ϕuu2dx+12∫R3∇V(x)⋅xu2dx−3μ∫R3λG(u)dx=0. | (2.9) |
Lemma 2.6. Assume that (V2) and (f0)−(f3) hold. Then the sequence {uμn} obtained in Remark 2.2 is bounded with respect to μn in X.
Proof. Using the fact Jμn,λ(uμn)≤c12, ⟨J′μn,λ(uμn),uμn⟩=0 and Lemma 2.5, we have
(3−γ2)c12≥(3−γ2)Jμn,λ(uμn)−⟨J′μn,λ(uμn),uμn⟩+(γ2−1)⋅(2.9)L |
and
(3−γ2)c12≥(γ4−12)∫R3(2V(x)+∇V(x)⋅x)u2μndx+(γ2−32)∫R3ϕuμnu2μndx+λ∫R3(uμng(uμn)−γG(uμn))dx≥(γ2−32)∫R3ϕuμnu2μndx. | (2.10) |
Using (V2), Lemma 2.1 and the fact that 3<γ≤4, it implies that {∫R3ϕuμnu2μndx} is bounded.
Next we prove that ‖uμn‖ is bounded. By ⟨J′μn,λ(uμn),uμn⟩=0, we obtain
γc12≥(γ2−1)∫R3(|∇uμn|2+V(x)uμn)dx+(γ4−1)∫R3ϕuμnu2μndx+∫R3(uμng(uμn)−γG(uμn))dx≥(γ2−1)∫R3(|∇uμn|2+V(x)uμn)dx−(4−γ)(6−γ)4γ−12c12, |
then we complete the proof.
Lemma 2.7. Assume that (V1), (V2) and (f0)−(f3) hold. Then problem (2.2) has at least one positive solution.
Proof. Using Remark 2.2 and Lemma 2.6, there exist {μn}⊂[12,1] and a bounded sequence {uμn}⊂X∖{0} such that
limn→+∞μn=1, Jμn,λ(uμn)=cμn, J′μn,λ(uμn)=0. |
Furthermore
limn→∞Jλ(uμn)=limn→∞(Jμn,λ(uμn)+(μn−1)∫R3λG(uμn)dx)=limn→∞cμn=c1, |
where we used the fact that μ↦cμ is continuous from the left. By the similar argument, we get
J′λ(uμn)→0 in X∗. |
Thus {uμn} is a bounded Palais-Smale sequence for Jλ and limn→∞Jλ(uμn)=c1. By the argument of Lemma 2.4 again, we complete the proof.
Indeed, the critical points of Jλ with L∞-norm not more than δ are also the weak solutions of problem (1.1). So next we shall study the L∞-estimates for solutions of (2.2), which is essentially contained in the work of Brezis-Kato.
Lemma 2.8. Assume (V1), (V2), (f0)−(f3) hold and u∈X is a weak solution of problem (2.2). Then u∈L∞(R3). Moreover,
|u|∞≤C9λ12∗−α‖u‖2∗−22∗−α, | (2.11) |
where C9>0 only depends on α.
Proof. Let u∈X be a weak solution of
{−Δu+V(x)u+ϕu=λg(u),in R3,−Δϕ=u2, lim|x|→+∞ϕ(x)=0,in R3, | (2.12) |
which is equivalent to
∫R3∇u⋅∇φdx+∫R3V(x)uφdx+∫R3ϕuuφdx−λ∫R3g(u)φdx=0, for all φ∈X. | (2.13) |
From the above Lemma 2.7, we know that u>0. Let T>0, and define
uT={u, if 0<u≤T,T, if u≥T. |
Choosing φ=u2(η−1)Tu in (2.13), where η>1, we get
∫R3|∇u|2⋅u2(η−1)Tdx+2(η−1)∫{x|u(x)<T}u2(η−1)−1Tu|∇u|2dx+∫R3ϕu(x)u2u2(η−1)Tdx+∫R3V(x)u2u2(η−1)Tdx=λ∫R3g(u)u2(η−1)Tudx. |
Combining Lemma 2.1-(3) and the nonnegativity of the second, the third and the fourth terms in the left side of the above equation, we obtain
∫R3|∇u|2⋅u2(η−1)Tdx≤λ∫R3g(u)u2(η−1)Tudx≤λC5∫R3uαu2(η−1)Tdx. | (2.14) |
On the other hand, by the Sobolev inequality, we obtain
(∫R3(uuη−1T)2∗dx)22∗≤C10∫R3|∇(uuη−1T)|2dx≤C11∫R3|∇u|2u2(η−1)Tdx+C10(η−1)2∫R3|∇u|2u2(η−1)Tdx≤C12η2∫R3|∇u|2u2(η−1)Tdx, |
where we used the fact that (a+b)2≤2(a2+b2).
By (2.14), the Hölder inequality and the Sobolev embedding theorem, we have
(∫R3(uuη−1T)2∗dx)22∗≤λC13η2∫R3uα−2u2u2(η−1)Tdx≤λC13η2(∫R3u2∗dx)α−22∗(∫R3(uuη−1T)22∗2∗−α+2dx)2∗−α+22∗≤λC14η2‖u‖α−2(∫R3uη22∗2∗−α+2dx)2∗−α+22∗, |
where we used the fact that 0≤uT≤u.
In what follows, taking ζ=22∗2∗−α+2, we get
(∫R3(uuη−1T)2∗dx)22∗≤λC14η2‖u‖α−2|u|2ηηζ. |
Using the Fatou's lemma, letting T→+∞, it follows that
|u|η2∗≤(λC14η2‖u‖α−2)12η|u|ηζ. | (2.15) |
Define ηn+1ζ=2∗ηn, where n=0,1,2,... and η0=2∗+2−α2. By (2.15) we have
|u|η12∗≤(λC14η21‖u‖α−2)12η1|u|2∗η0≤(λC14‖u‖α−2)12η1+12η0η1η00η1η11|u|2∗. |
By iteration we have
|u|ηn2∗≤(λC14‖u‖α−2)12η0∑ni=0(ζ2∗)i(η0)1η0∑ni=0(ζ2∗)i(2∗ζ)1η0∑ni=0i(ζ2∗)i|u|2∗. |
Thus, we obtain |u|∞≤C9λ12∗−α‖u‖2∗−22∗−α.
By the similar argument in Lemma 2.6, we can obtian the following lemma.
Lemma 2.9. Let λ>VL2 and uλ be a critical point of Jλ with Jλ(uλ)=c1. Then there exists C16>0 (independent of λ) such that
‖uλ‖2≤C16c1. | (2.16) |
Proof of Theorem 1.1. Let u0∈C∞0(RN)∩X∖{0} be a nonnegative function such that Jλ(u0)<0. Then, the functional Jλ has the mountain pass geometry and we can define
dλ=infγ∈Γmaxt∈[0,1]Jλ(γ(t))>0, |
where Γ={γ∈C([0,1],X): γ(0)=0, γ(1)=u0}. By Lemma 2.7, there exists a positive critical point uλ of Jλ with Jλ(uλ)=dλ. And more remarkable dλ=c1.
Furthermore, taking T=|u0|∞, from Lemma 2.1-(4), we obtain
dλ≤maxt∈[0,1]Jλ(tu0)≤maxt∈[0,1](t22∫R3(|∇u0|2+V(x)u20)dx+t44∫R3ϕu0u20dx−λ∫R3G(tu0)dx)≤maxt∈[0,1](t22∫R3(|∇u0|2+V(x)u20+12ϕu0u20)dx−C17λtβ∫R3uβ0dx)≤C18λ−2β−2. | (2.17) |
By (2.11), (2.16) and (2.17), we see that
|uλ|∞≤C19λβ−2∗2∗−α. |
Then there exists λ0>0 such that for all λ>λ0, we get
|uλ|∞≤δ, |
where δ is fixed in (2.1). Thus, the uλ is a positive solution of the original problem (1.1).
We start by finding that the conditions (f′1) and (f′2) imply the existence of positive constants C20,C21 such that
F(t)≤C20|t|α | (3.1) |
and
F(t)≥C21|t|β | (3.2) |
with |t| small. Consider ρ(t)∈C1(R,R) an even cut-off function satisfying:
ρ(t)={1, if |t|≤δ,0, if |t|≥2δ, |
0≤ρ(t)≤1, tρ′(t)≤0 and |tρ′(t)|≤2δ, where 0<δ<12 is chosen such that (3.1), (3.2) hold for |t|≤2δ and (f4) holds for |t|≤δ. Define
H(t)=ρ(t)F(t)+(1−ρ(t))˜F∞(t)andh(t)=H′(t), |
where ˜F∞(t)=C22|t|α. From (f′1) and the definitions of ρ(t) and h(t), for u∈X we have
|h(u)|≤C23|u|α−1. | (3.3) |
Lemma 3.1. (See [8]) If f satisfies (f′1)−(f′3), then for all t≠0, we have
0<θH(t)≤th(t), |
where θ=min{α,˜γ}.
We now consider another modified equation of (1.1) given by
{−Δu+V(x)u+ϕu=λh(u),in R3,−Δϕ=u2, lim|x|→+∞ϕ(x)=0,in R3. | (3.4) |
By the definition of H(t) and (3.3), the functional associated to (3.4) stated by
Iλ(u)=12∫R3(|∇u|2+V(x)u2)dx+14∫R3ϕuu2dx−λ∫R3H(u)dx, u∈X | (3.5) |
is well-defined. It is well known that its critical points are the weak solutions of (3.4).
The goal of this section is to prove Theorem 1.2. To this end, we use the Lemma 3.1 to get the boundedness of Palais-Smale sequence. Moreover, by the similar argument in Lemma 2.4, it is easy to show that Iλ satisfies Palais-Smale condition. These are standard results which can be found in textbooks and no proof is given here.
Lemma 3.2. Assume that (f′1)−(f′3) are satisfied. If u∈X is a critical point of Iλ, then
‖u‖2≤C24Iλ(u), | (3.6) |
where C24 depends on θ.
The proof of the above result is quite similar to the one used in Lemma 2.6 and so is omitted.
Since X is a real, reflexive, and separable Banach space, there exists {ej}j∈N⊂X such that
X=¯span{ej:j=1,2,...}. |
We denote
Yk=span{e1,...,ek}, Zk=¯span{ek+1,...}. |
Lemma 3.3. Set θk,λ=supu∈YkIλ(u). If λ>1, then
θk,λ≤C25λ−2β−2, | (3.7) |
where C25 depends on α, β and k.
Proof. We notice that δ>0 was chosen in Section 3 such that
H(t)=˜F∞(t)=C22|t|α for |t|≥2δ, | (3.8) |
H(t)≥F(t)≥C26|t|β for |t|≤2δ. | (3.9) |
For u∈Yk, denote Ω1={x∈R3: |u(x)|≥2δ}, Ω2={x∈R3: |u(x)|<2δ}, and let u1=u|Ω1, u2=u|Ω2. Since all norms in Yk are equivalent, from (3.8) and (3.9) we obtain
∫R3H(u1)dx≥ˆC(k)|u1|α2 |
and
∫R3H(u2)dx≥ˆC(k)|u2|β2, |
where ˆC(k) is a positive constant. By the same reason, we can define
γk=sup{‖u‖:u∈Yk, |u|2=1}<∞. |
Then for u∈Yk, it follows that
Iλ(u)≤γk2|u|22+C74‖u‖4−λˆC(k)|u1|α2−λˆC(k)|u2|β2≤γk2|u1|22+C7γk4|u1|42−λˆC(k)|u1|α2+γk2|u2|22+C7γk4|u2|42−λˆC(k)|u2|β2≤¯C1(k)λ−2α−2+¯C2(k)λ−2β−2. |
For λ>1, by 4<α≤β<2∗, we have
θk,λ≤C25λ−2β−2, |
where C25:=¯C1(k)+¯C2(k).
Lemma 3.4. Assume that u∈X is a weak solution of problem (3.4). Then u∈L∞(RN). Moreover,
|u|∞≤C27λ12∗−α‖u‖2∗−22∗−α, | (3.10) |
where C27>0 only depends on α.
The proof of Lemma 3.4 is quite similar to Lemma 2.8 and so is omitted.
To prove Theorem 1.2, we will apply the following symmetric mountain pass theorem due to Rabinowitz [16].
Proposition 2. Let X be an infinite dimensional Banach space, J∈C1(X,R) be even, satisfy (PS) condition and J(0)=0. If X=Y⨁Z with dimY<+∞, and J satisfies
(1) there are constants ρ,α>0 such that J|∂Bρ∩Z≥α,
(2) for any finite dimensional subspace W⊂X, there is an R=R(W) such that J≤0 on W∖BR(W), then J has a sequence of critical values.
Remark 3.1. We point out that Iλ satisfies all assumptions of Proposition 2. By Proposition 2, then Iλ possesses a sequence of critical points.
Proof of Theorem 1.2. Fix an integer k. Choose R>0 such that Iλ(u)≤0 for all u∈Yk with ‖u‖≥R, and for all λ≥1. For BR={u∈X: ‖u‖<R}, let D=BR∩Yk. Define
Γ:={γ∈C(D,X): γ is odd, γ(u)=u,if ‖u‖=R}. |
Let i(A) be the genus of symmetric subset A. For j≤k, we denote
Θj={γ(¯D∖B): γ∈Γ, i(B)≤k−j} |
and
cj,λ=infA∈Θjsupu∈AIλ(u). |
From Proposition 2 and Remark 3.1, and under our conditions on h, we get
0<c1,λ≤c2,λ≤...≤ck,λ. |
Moreover, they are also critical values of Iλ and there exist at least 2k critical points {±uj,λ}kj=1 at these critical values. Since Id∈Γ, the definition of Θj and Lemma 3.3, we obtain
cj,λ≤θj,λ≤C(j)λ−2β−2. | (3.11) |
By Lemmas 3.2–3.4, we have
|uj,λ|∞≤C28λβ−2∗(β−2)(2∗−α). |
Since 4<β<2∗, there exists λ1>0 such that |uj,λ|∞≤δ, for all λ>λ1. Thus, ±uj,λ(j=1,2,⋯,k) are weak solutions of problem (1.1).
This work was supported by the National Natural Science Foundation of China (11171220). The authors wish to thank the referees and the editor for their valuable comments and suggestions.
All authors declare no conflicts of interest in this paper.
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