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Research article Special Issues

Novel inequalities for subadditive functions via tempered fractional integrals and their numerical investigations

  • Received: 29 January 2024 Revised: 25 March 2024 Accepted: 03 April 2024 Published: 09 April 2024
  • MSC : 26A33, 26A51, 26D07, 26D10, 26D15

  • In this paper, we proposed some new integral inequalities for subadditive functions and the product of subadditive functions. Additionally, a novel integral identity was established and a number of inequalities of the Hermite-Hadamard type for subadditive functions pertinent to tempered fractional integrals were proved. Finally, to support the major results, we provided several examples of subadditive functions and corresponding graphs for the newly proposed inequalities.

    Citation: Artion Kashuri, Soubhagya Kumar Sahoo, Pshtiwan Othman Mohammed, Eman Al-Sarairah, Nejmeddine Chorfi. Novel inequalities for subadditive functions via tempered fractional integrals and their numerical investigations[J]. AIMS Mathematics, 2024, 9(5): 13195-13210. doi: 10.3934/math.2024643

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  • In this paper, we proposed some new integral inequalities for subadditive functions and the product of subadditive functions. Additionally, a novel integral identity was established and a number of inequalities of the Hermite-Hadamard type for subadditive functions pertinent to tempered fractional integrals were proved. Finally, to support the major results, we provided several examples of subadditive functions and corresponding graphs for the newly proposed inequalities.



    The primary contribution to the concept of subadditive functions is due to the work of Hille and Phillips [1]. An extract from Rosenbaum's study on subadditive functions with several variables is also given [2]. The concepts of additivity, subadditivity, and superadditivity are used in many branches of mathematics as well as in mathematical inequalities, see [3,4,5,6,7,8].

    Definition 1.1. [9] F:IR[0,) is said to be subadditive function on I, if

    F(Θ1+Θ2)F(Θ1)+F(Θ2) (1.1)

    holds for all Θ1,Θ2I and Θ1+Θ2I. If the equality is achieved, then F is said to be additive, otherwise superadditive.

    Since many optimization issues require maximizing or minimizing a convex function while taking certain restrictions into account, convex functions are crucial in optimization. Additionally, they have appealing characteristics like a singular global minimum and nearly universal differentiability. Numerous fields, including optimization, game theory, economics, and computer science, use convexity theory. It offers strong tools for understanding and resolving optimization issues, and it has sparked the creation of several algorithms for quickly calculating answers to these issues.

    Definition 1.2. [10] F:IRR is said to be convex, if

    F(δΘ1+(1δ)Θ2)δF(Θ1)+(1δ)F(Θ2) (1.2)

    holds for all Θ1,Θ2I with δ[0,1].

    The given Hermite-Hadamard inequality (H-H) has a strong connection with convex functions.

    Theorem 1.1. [11,12] If F:IRR is convex on I, then

    F(Θ1+Θ22)1Θ2Θ1Θ2Θ1F(δ)dδF(Θ1)+F(Θ2)2 (1.3)

    holds for all Θ1,Θ2I and Θ1<Θ2.

    There are numerous well-known inequalities that may be obtained using the convexity feature, see [13,14,15,16,17,18].

    Let us denote by L[Θ1,Θ2] the set of all Lebesgue integrable functions on [Θ1,Θ2] and by I the interior set of I. The following H-H type for continuous subadditive functions were recently established by Sarikaya and Ali [19].

    Theorem 1.2. If F:IR[0,) is a continuous subadditive function with Θ1,Θ2I and 0<Θ1<Θ2, then

    12F(Θ1+Θ2)1Θ2Θ1Θ2Θ1F(δ)dδ1Θ1Θ10F(δ)dδ+1Θ2Θ20F(δ)dδ. (1.4)

    The fractional calculus focuses on integrals and derivatives of fractional orders. It extends the usual ideas of differentiation and integration to orders that are not integers. The order of differentiation or integration in fractional calculus can be any real number, including non-integer numbers. For instance, taking the square root of a derivative or integral corresponds to a half-order derivative or integral. Numerous disciplines, including physics, engineering, economics, and signal processing, use fractional calculus.

    Definition 1.3. [20,21] Let FL[Θ1,Θ2], where 0Θ1<Θ2. For α>0 and λ0, the tempered fractional integral operators Iα,λΘ+1F and Iα,λΘ2F are defined as

    Iα,λΘ+1F(x):=1Γ(α)xΘ1(xδ)α1eλ(xδ)F(δ)dδ(x>Θ1), (1.5)

    and

    Iα,λΘ2F(x):=1Γ(α)Θ2x(δx)α1eλ(δx)F(δ)dδ(x<Θ2), (1.6)

    respectively.

    Definition 1.4. Let x,λ0 and α>0, then λ-incomplete gamma function is given by

    γλ(α,x):=x0δα1eλδdδ.

    If λ=1, then

    γ(α,x):=x0δα1eδdδ.

    The following portions of this work are inspired by the aforementioned findings: We found some H-H inequalities for subadditive functions and their product using tempered fractional integrals in Section 2. We propose various fractional inequalities for subadditive functions relevant to tempered fractional integral operators with the help of a new lemma in Section 3. In Section 4, we provide a few numerical examples and graphs with numerical estimations to support our findings. In Section 5, some conclusions and new ideas for future research are discussed.

    Let us take Q:=[0,), where Q:=(0,). Throughout this paper, we will use the above notations for our simplicity.

    Theorem 2.1. Let F:QQ be a continuous subadditive function with Θ1,Θ2Q and Θ1<Θ2. Then for λ0 and α>0, we have

    12F(Θ1+Θ2)Γ(α)2γλ(α,Θ2Θ1)[Iα,λΘ+1F(Θ2)+Iα,λΘ2F(Θ1)](Θ2Θ1)α2γλ(α,Θ2Θ1)×{1Θα1Θ10δα1eλ(Θ2Θ1Θ1)δF(δ)dδ+1Θα1Θ10(Θ1δ)α1eλ(Θ2Θ1Θ1)(Θ1δ)F(δ)dδ+1Θα2Θ20δα1eλ(Θ2Θ1Θ2)δF(δ)dδ+1Θα2Θ20(Θ2δ)α1eλ(Θ2Θ1Θ2)(Θ2δ)F(δ)dδ}. (2.1)

    Proof. Using the hypothesis of subadditive function F on Q, we have

    F(Θ1+Θ2)=F(δΘ1+(1δ)Θ2+δΘ2+(1δ)Θ1)F(δΘ1+(1δ)Θ2)+F((1δ)Θ1+δΘ2). (2.2)

    Upon multiplication of (2.2) by δα1eλ(Θ2Θ1)δ, and then integrating with respect to δ over [0,1], we get

    γλ(α,Θ2Θ1)(Θ2Θ1)αF(Θ1+Θ2)10δα1eλ(Θ2Θ1)δF(δΘ1+(1δ)Θ2)dδ+10δα1eλ(Θ2Θ1)δF((1δ)Θ1+δΘ2)dδ=1(Θ2Θ1)α[Θ2Θ1(Θ2δ)α1eλ(Θ2δ)F(δ)dδ+Θ2Θ1(δΘ1)α1eλ(δΘ1)F(δ)dδ]=Γ(α)(Θ2Θ1)α[Iα,λΘ+1F(Θ2)+Iα,λΘ2F(Θ1)].

    Hence,

    12F(Θ1+Θ2)Γ(α)2γλ(α,Θ2Θ1)[Iα,λΘ+1F(Θ2)+Iα,λΘ2F(Θ1)].

    This concludes the first side (left) of (2.1). Next, for the other side (right) of (2.1), since F is subadditive on Q, one has

    F(δΘ1+(1δ)Θ2)F(δΘ1)+F((1δ)Θ2) (2.3)

    and

    F((1δ)Θ1+δΘ2)F((1δ)Θ1)+F(δΘ2). (2.4)

    By adding (2.3) and (2.4), we get

    F(δΘ1+(1δ)Θ2)+F((1δ)Θ1+δΘ2)F(δΘ1)+F(δΘ2)+F((1δ)Θ1)+F((1δ)Θ2). (2.5)

    Multiplying both sides of (2.5) by δα1eλ(Θ2Θ1)δ, and following the same procedure as above, we complete the proof.

    Remark 2.1. Choosing λ=0 and α=1 in Theorem 2.1, we obtain Theorem 1.2.

    Theorem 2.2. Let Φ,Ψ:QQ be two continuous subadditive functions with Θ1,Θ2Q and Θ1<Θ2. Then for λ0 and α>0, we have

    12Φ(Θ1+Θ2)Ψ(Θ1+Θ2)Γ(α)2γλ(α,Θ2Θ1)[Iα,λΘ+1Φ(Θ2)Ψ(Θ2)+Iα,λΘ2Φ(Θ1)Ψ(Θ1)]+(Θ2Θ1)α2γλ(α,Θ2Θ1)×{10[δα1+(1δ)α1]eλ(Θ2Θ1)δ[Φ(δΘ1)Ψ(δΘ2)+Φ(δΘ2)Ψ(δΘ1)]dδ+1Θα1Θ10δα1eλ(Θ2Θ1Θ1)δ[Φ(δ)Ψ(Θ1δ)+Φ(Θ1δ)Ψ(δ)]dδ+1Θα2Θ20δα1eλ(Θ2Θ1Θ2)δ[Φ(δ)Ψ(Θ2δ)+Φ(Θ2δ)Ψ(δ)]dδ} (2.6)

    and

    Γ(α)2γλ(α,Θ2Θ1)[Iα,λΘ+1Φ(Θ2)Ψ(Θ2)+Iα,λΘ2Φ(Θ1)Ψ(Θ1)](Θ2Θ1)α2γλ(α,Θ2Θ1)×{10[δα1eλ(Θ2Θ1)δ+(1δ)α1eλ(Θ2Θ1)(1δ)][Φ(δΘ1)Ψ((1δ)Θ2)+Φ(δΘ2)Ψ((1δ)Θ1)]dδ+1Θα1Θ10[δα1eλ(Θ2Θ1Θ1)δ+(Θ1δ)α1eλ(Θ2Θ1Θ1)(Θ1δ)]Φ(δ)Ψ(δ)dδ+1Θα2Θ20[δα1eλ(Θ2Θ1Θ2)δ+(Θ2δ)α1eλ(Θ2Θ1Θ2)(Θ2δ)]Φ(δ)Ψ(δ)dδ}. (2.7)

    Proof. Using (2.2) and the hypothesis of subadditive functions Φ, and Ψ on Q, one has

    Φ(Θ1+Θ2)Φ(δΘ1+(1δ)Θ2)+Φ(δΘ2+(1δ)Θ1) (2.8)

    and

    Ψ(Θ1+Θ2)Ψ(δΘ1+(1δ)Θ2)+Ψ(δΘ2+(1δ)Θ1). (2.9)

    Multiplying (2.8) and (2.9), we get

    Φ(Θ1+Θ2)Ψ(Θ1+Θ2)[Φ(δΘ1+(1δ)Θ2)+Φ(δΘ2+(1δ)Θ1)][Ψ(δΘ1+(1δ)Θ2)+Ψ(δΘ2+(1δ)Θ1)]=Φ(δΘ1+(1δ)Θ2)Ψ(δΘ1+(1δ)Θ2)+Φ(δΘ1+(1δ)Θ2)Ψ(δΘ2+(1δ)Θ1)+Φ(δΘ2+(1δ)Θ1)Ψ(δΘ1+(1δ)Θ2)+Φ(δΘ2+(1δ)Θ1)Ψ(δΘ2+(1δ)Θ1)Φ(δΘ1+(1δ)Θ2)Ψ(δΘ1+(1δ)Θ2)+Φ(δΘ2+(1δ)Θ1)Ψ(δΘ2+(1δ)Θ1)+[Φ(δΘ1)+Φ((1δ)Θ2)][Ψ(δΘ2)+Ψ((1δ)Θ1)]+[Φ(δΘ2)+Φ((1δ)Θ1)][Ψ(δΘ1)+Ψ((1δ)Θ2)]=Φ(δΘ1+(1δ)Θ2)Ψ(δΘ1+(1δ)Θ2)+Φ(δΘ2+(1δ)Θ1)Ψ(δΘ2+(1δ)Θ1)+Φ(δΘ1)Ψ(δΘ2)+Φ(δΘ1)Ψ((1δ)Θ1)+Φ((1δ)Θ2)Ψ(δΘ2)+Φ((1δ)Θ2)Ψ((1δ)Θ1)+Φ(δΘ2)Ψ(δΘ1)+Φ(δΘ2)Ψ((1δ)Θ2)+Φ((1δ)Θ1)Ψ(δΘ1)+Φ((1δ)Θ1)Ψ((1δ)Θ2). (2.10)

    Multiplying both sides of (2.10) by δα1eλ(Θ2Θ1)δ and integrating with respect to δ over [0,1], we obtain (2.6).

    By subadditivity of Φ and Ψ on Q, we have

    Φ(δΘ1+(1δ)Θ2)Φ(δΘ1)+Φ((1δ)Θ2) (2.11)

    and

    Ψ(δΘ1+(1δ)Θ2)Ψ(δΘ1)+Ψ((1δ)Θ2). (2.12)

    Multiplying inequalities (2.11) and (2.12), we get

    Φ(δΘ1+(1δ)Θ2)Ψ(δΘ1+(1δ)Θ2)Φ(δΘ1)Ψ(δΘ1)+Φ(δΘ1)Ψ((1δ)Θ2)+Φ((1δ)Θ2)Ψ(δΘ1)+Φ((1δ)Θ2)Ψ((1δ)Θ2). (2.13)

    Similarly,

    Φ((1δ)Θ1+δΘ2)Ψ((1δ)Θ1+δΘ2)Φ((1δ)Θ1)Ψ((1δ)Θ1)+Φ((1δ)Θ1)Ψ(δΘ2)+Φ(δΘ2)Ψ((1δ)Θ1)+Φ(δΘ2)Ψ(δΘ2). (2.14)

    Adding (2.13) and (2.14), we obtain

    Φ(δΘ1+(1δ)Θ2)Ψ(δΘ1+(1δ)Θ2)+Φ((1δ)Θ1+δΘ2)Ψ((1δ)Θ1+δΘ2)Φ(δΘ1)Ψ(δΘ1)+Φ(δΘ1)Ψ((1δ)Θ2)+Φ((1δ)Θ2)Ψ(δΘ1)+Φ((1δ)Θ2)Ψ((1δ)Θ2)+Φ((1δ)Θ1)Ψ((1δ)Θ1)+Φ((1δ)Θ1)Ψ(δΘ2)+Φ(δΘ2)Ψ((1δ)Θ1)+Φ(δΘ2)Ψ(δΘ2). (2.15)

    Multiplying both sides of (2.15) by δα1eλ(Θ2Θ1)δ, and following the same procedure as above, we have (2.7).

    Remark 2.2. Choosing λ=0 and α=1 in Theorem 2.2, we obtain ([19], Theorem 4).

    Theorem 2.3. Let F:QQ be a continuous subadditive function with Θ1,Θ2Q and Θ1<Θ2. Then for λ0 and α>0, we have

    12F(Θ1+Θ2)2α1Γ(α)γλ(α,Θ2Θ1)[Iα,2λ(Θ1+Θ22)+F(Θ2)+Iα,2λ(Θ1+Θ22)F(Θ1)]2α1(Θ2Θ1)αγλ(α,Θ2Θ1)×{1Θα1Θ120δα1e2λ(Θ2Θ1Θ1)δF(δ)dδ+1Θα1Θ1Θ12(Θ1δ)α1e2λ(Θ2Θ1Θ1)(Θ1δ)F(δ)dδ+1Θα2Θ220δα1e2λ(Θ2Θ1Θ2)δF(δ)dδ+1Θα2Θ2Θ22(Θ2δ)α1e2λ(Θ2Θ1Θ2)(Θ2δ)F(δ)dδ}. (2.16)

    Proof. From subadditivity of F, we have

    F(Θ1+Θ2)F(2δ2Θ1+δ2Θ2)+F(δ2Θ1+2δ2Θ2). (2.17)

    Multiplying both sides of (2.17) by δα1eλ(Θ2Θ1)δ, and then integrating over [0,1], we get

    γλ(α,Θ2Θ1)(Θ2Θ1)αF(Θ1+Θ2)10δα1eλ(Θ2Θ1)δF(δ2Θ1+2δ2Θ2)dδ+10δα1eλ(Θ2Θ1)δF(2δ2Θ1+δ2Θ2)dδ=(2Θ2Θ1)αΓ(α)[Iα,2λ(Θ1+Θ22)+F(Θ2)+Iα,2λ(Θ1+Θ22)F(Θ1)].

    Hence,

    12F(Θ1+Θ2)2α1Γ(α)γλ(α,Θ2Θ1)[Iα,2λ(Θ1+Θ22)+F(Θ2)+Iα,2λ(Θ1+Θ22)F(Θ1)],

    which proves the left part of (2.16). Consequently, to prove the right part, we have

    F(δ2Θ1+2δ2Θ2)F(δ2Θ1)+F(2δ2Θ2) (2.18)

    and

    F(2δ2Θ1+δ2Θ2)F(2δ2Θ1)+F(δ2Θ2). (2.19)

    By adding (2.18) and (2.19), we obtain

    F(2δ2Θ1+δ2Θ2)+F(δ2Θ1+2δ2Θ2)F(δ2Θ1)+F(δ2Θ2)+F(2δ2Θ1)+F(2δ2Θ2). (2.20)

    Multiplying both sides of (2.20) by δα1eλ(Θ2Θ1)δ, and following the same procedures as done in earlier theorems, we have the right part.

    Lemma 3.1. Assume that F:QQ is a differentiable continuous function for Θ1,Θ2Q and Θ1<Θ2. Then for λ0 and α>0, we have

    F(Θ1)+F(Θ2)22α1Γ(α)γλ(α,Θ2Θ1)[Iα,2λΘ+1F(Θ1+Θ22)+Iα,2λΘ2F(Θ1+Θ22)]=(Θ2Θ1)α+14γλ(α,Θ2Θ1)×10γλ(Θ2Θ1)(α,δ)[F(Θ1+1+δ2(Θ2Θ1))F(Θ1+1δ2(Θ2Θ1))]dδ. (3.1)

    Proof. Let us denote, respectively,

    I1:=10γλ(Θ2Θ1)(α,δ)F(Θ1+1+δ2(Θ2Θ1))dδ

    and

    I2:=10γλ(Θ2Θ1)(α,δ)F(Θ1+1δ2(Θ2Θ1))dδ.

    Then, we have

    10γλ(Θ2Θ1)(α,δ)[F(Θ1+1+δ2(Θ2Θ1))F(Θ1+1δ2(Θ2Θ1))]dδ=I1I2. (3.2)

    Using integration by parts, we get

    I1=2Θ2Θ1γλ(Θ2Θ1)(α,δ)F(Θ1+1+δ2(Θ2Θ1))|102Θ2Θ110δα1eλ(Θ2Θ1)δF(Θ1+1+δ2(Θ2Θ1))dδ=2Θ2Θ1γλ(Θ2Θ1)(α,1)F(Θ2)(2Θ2Θ1)α+1×Θ2Θ1+Θ22(δΘ1+Θ22)α1e2λ(δΘ1+Θ22)F(δ)dδ=2Θ2Θ1γλ(Θ2Θ1)(α,1)F(Θ2)(2Θ2Θ1)α+1Γ(α)Iα,2λΘ2F(Θ1+Θ22).

    Similarly,

    I2=2Θ2Θ1γλ(Θ2Θ1)(α,1)F(Θ1)+(2Θ2Θ1)α+1Γ(α)Iα,2λΘ+1F(Θ1+Θ22).

    From Definition 1.4, we get

    γλ(Θ2Θ1)(α,1)=γλ(α,Θ2Θ1)(Θ2Θ1)α.

    Multiplying both sides of (3.2) by the factor (Θ2Θ1)α+14γλ(α,Θ2Θ1) and using above relation, we have the desired result (3.1).

    Theorem 3.1. Suppose that F:QQ is a differentiable continuous function with Θ1,Θ2Q and Θ1<Θ2. If |F|q for p>1 and 1p+1q=1 is a subadditive function, then for λ0 and α>0, we have

    |F(Θ1)+F(Θ2)22α1Γ(α)γλ(α,Θ2Θ1)[Iα,2λΘ+1F(Θ1+Θ22)+Iα,2λΘ2F(Θ1+Θ22)]|212qq(Θ2Θ1)α+1γλ(α,Θ2Θ1)C1p(γ,p)×{[1Θ1Θ120|F(δ)|qdδ+1Θ2Θ2Θ22|F(δ)|qdδ]1q+[1Θ1Θ1Θ12|F(δ)|qdδ+1Θ2Θ220|F(δ)|qdδ]1q}, (3.3)

    where

    C(γ,p):=10[γλ(Θ2Θ1)(α,δ)]pdδ.

    Proof. Under the assumption of Lemma 3.1, subadditivity of |F|q on Q and Hölder's inequality, we have

    |F(Θ1)+F(Θ2)22α1Γ(α)γλ(α,Θ2Θ1)[Iα,2λΘ+1F(Θ1+Θ22)+Iα,2λΘ2F(Θ1+Θ22)]|(Θ2Θ1)α+14γλ(α,Θ2Θ1)10|γλ(Θ2Θ1)(α,δ)|[|F(Θ1+1+δ2(Θ2Θ1))|+|F(Θ1+1δ2(Θ2Θ1))|]dδ(Θ2Θ1)α+14γλ(α,Θ2Θ1)(10[γλ(Θ2Θ1)(α,δ)]pdδ)1p×{(10|F(Θ1+1+δ2(Θ2Θ1))|qdδ)1q+(10|F(Θ1+1δ2(Θ2Θ1))|qdδ)1q}(Θ2Θ1)α+14γλ(α,Θ2Θ1)C1p(γ,p)×{[10(|F((1+δ2)Θ2)|q+|F((1δ2)Θ1)|q)dδ]1q+[10(|F((1δ2)Θ2)|q+|F((1+δ2)Θ1)|q)dδ]1q}=212qq(Θ2Θ1)α+1γλ(α,Θ2Θ1)C1p(γ,p)×{[1Θ1Θ120|F(δ)|qdδ+1Θ2Θ2Θ22|F(δ)|qdδ]1q+[1Θ1Θ1Θ12|F(δ)|qdδ+1Θ2Θ220|F(δ)|qdδ]1q}.

    The proof of Theorem 3.1 is completed.

    Corollary 3.1. Choosing |F|K in Theorem 3.1, we get

    |F(Θ1)+F(Θ2)22α1Γ(α)γλ(α,Θ2Θ1)[Iα,2λΘ+1F(Θ1+Θ22)+Iα,2λΘ2F(Θ1+Θ22)]|21qqK(Θ2Θ1)α+1γλ(α,Θ2Θ1)C1p(γ,p). (3.4)

    Theorem 3.2. Assume that F:QQ is a differentiable continuous function with Θ1,Θ2Q and Θ1<Θ2. If |F|q for q1 is a subadditive function, then for λ0 and α>0, we have

    |F(Θ1)+F(Θ2)22α1Γ(α)γλ(α,Θ2Θ1)[Iα,2λΘ+1F(Θ1+Θ22)+Iα,2λΘ2F(Θ1+Θ22)]|212qq(Θ2Θ1)α+1γλ(α,Θ2Θ1)C11q(γ)×{[1Θ1Θ120γλ(Θ2Θ1)(α,12δΘ1)|F(δ)|qdδ+1Θ2Θ2Θ22γλ(Θ2Θ1)(α,2δΘ21)|F(δ)|qdδ]1q+[1Θ1Θ1Θ12γλ(Θ2Θ1)(α,2δΘ11)|F(δ)|qdδ+1Θ2Θ220γλ(Θ2Θ1)(α,12δΘ2)|F(δ)|qdδ]1q}, (3.5)

    where

    C(γ):=10γλ(Θ2Θ1)(α,δ)dδ=γλ(α,Θ2Θ1)(Θ2Θ1)αγλ(α+1,Θ2Θ1)(Θ2Θ1)α+1.

    Proof. Under the assumption of Lemma 3.1, subadditivity of |F|q on Q and power-mean inequality, we have

    |F(Θ1)+F(Θ2)22α1Γ(α)γλ(α,Θ2Θ1)[Iα,2λΘ+1F(Θ1+Θ22)+Iα,2λΘ2F(Θ1+Θ22)]|(Θ2Θ1)α+14γλ(α,Θ2Θ1)10|γλ(Θ2Θ1)(α,δ)|[|F(Θ1+1+δ2(Θ2Θ1))|+|F(Θ1+1δ2(Θ2Θ1))|]dδ(Θ2Θ1)α+14γλ(α,Θ2Θ1)(10γλ(Θ2Θ1)(α,δ)dδ)11q×{(10γλ(Θ2Θ1)(α,δ)|F(Θ1+1+δ2(Θ2Θ1))|qdδ)1q+(10γλ(Θ2Θ1)(α,δ)|F(Θ1+1δ2(Θ2Θ1))|qdδ)1q}(Θ2Θ1)α+14γλ(α,Θ2Θ1)C11q(γ)×{[10γλ(Θ2Θ1)(α,δ)(|F((1+δ2)Θ2)|q+|F((1δ2)Θ1)|q)dδ]1q+[10γλ(Θ2Θ1)(α,δ)(|F((1δ2)Θ2)|q+|F((1+δ2)Θ1)|q)dδ]1q}=212qq(Θ2Θ1)α+1γλ(α,Θ2Θ1)C11q(γ)×{[1Θ1Θ120γλ(Θ2Θ1)(α,12δΘ1)|F(δ)|qdδ+1Θ2Θ2Θ22γλ(Θ2Θ1)(α,2δΘ21)|F(δ)|qdδ]1q+[1Θ1Θ1Θ12γλ(Θ2Θ1)(α,2δΘ11)|F(δ)|qdδ+1Θ2Θ220γλ(Θ2Θ1)(α,12δΘ2)|F(δ)|qdδ]1q}.

    The proof of Theorem 3.2 is completed.

    Corollary 3.2. Taking q=1 in Theorem 3.2, we have

    |F(Θ1)+F(Θ2)22α1Γ(α)γλ(α,Θ2Θ1)[Iα,2λΘ+1F(Θ1+Θ22)+Iα,2λΘ2F(Θ1+Θ22)]|(Θ2Θ1)α+12γλ(α,Θ2Θ1)×{1Θ1Θ120γλ(Θ2Θ1)(α,12δΘ1)|F(δ)|dδ+1Θ2Θ220γλ(Θ2Θ1)(α,12δΘ2)|F(δ)|dδ+1Θ1Θ1Θ12γλ(Θ2Θ1)(α,2δΘ11)|F(δ)|dδ+1Θ2Θ2Θ22γλ(Θ2Θ1)(α,2δΘ21)|F(δ)|dδ}. (3.6)

    Corollary 3.3. Choosing |F|K in Theorem 3.2, we get

    |F(Θ1)+F(Θ2)22α1Γ(α)γλ(α,Θ2Θ1)[Iα,2λΘ+1F(Θ1+Θ22)+Iα,2λΘ2F(Θ1+Θ22)]|212qqK(Θ2Θ1)α+1γλ(α,Θ2Θ1)C11q(γ)×{[1Θ1Θ120γλ(Θ2Θ1)(α,12δΘ1)dδ+1Θ2Θ2Θ22γλ(Θ2Θ1)(α,2δΘ21)dδ]1q+[1Θ1Θ1Θ12γλ(Θ2Θ1)(α,2δΘ11)dδ+1Θ2Θ220γλ(Θ2Θ1)(α,12δΘ2)dδ]1q}. (3.7)

    Remark 3.1. For suitable choices of α and λ in Theorems 3.1 and 3.2, one will able to get interesting integral inequalities.

    It is shown that the functions F(δ)=eδ and δ for all δ>0 are subadditive. It can be observed that these graphs illustrate and confirm the correctness of our obtained inequalities.

    Example 4.1. If we take subadditive function F(δ)=δ in Theorem 2.1 for all δ>0, 0<α<1 and λ=1, then we observe the following numerical verification (see Table 1).

    Table 1.  Estimations of inequalities in Theorem 2.1 for F(δ)=δ,Θ1=1 and Θ2=2.
    α Left side Middle side Right side
    0.10 0.866025 1.20951 1.31914
    0.20 0.866025 1.21150 1.39740
    0.30 0.866025 1.21314 1.45415
    0.40 0.866025 1.21450 1.49635
    0.50 0.866025 1.21562 1.52827
    0.60 0.866025 1.21653 1.55268
    0.70 0.866025 1.21728 1.57148
    0.80 0.866025 1.21788 1.58599
    0.90 0.866025 1.21837 1.59717

     | Show Table
    DownLoad: CSV

    Example 4.2. If we take subadditive function F(δ)=eδ in Theorems 2.1 and 2.3 for all δ>0, 0<α<1 and λ=1, then we observe the following numerical verifications (see Tables 2 and 3) and corresponding graphs (see Figures 1 and 2).

    Table 2.  Estimations of inequalities in Theorem 2.1 for F(δ)=eδ,Θ1=1 and Θ2=2.
    α Left side Middle side Right side
    0.10 0.0248935 0.247754 1.21353
    0.20 0.0248935 0.244558 1.18203
    0.30 0.0248935 0.241912 1.15601
    0.40 0.0248935 0.239727 1.13457
    0.50 0.0248935 0.237928 1.11694
    0.60 0.0248935 0.236451 1.1025
    0.70 0.0248935 0.235245 1.09073
    0.80 0.0248935 0.234267 1.08119
    0.90 0.0248935 0.233479 1.07353

     | Show Table
    DownLoad: CSV
    Table 3.  Estimations of inequalities in Theorem 2.3 for F(δ)=eδ,Θ1=1 and Θ2=2.
    α Left side Middle side Right side
    0.10 0.0248935 0.248907 1.22482
    0.20 0.0248935 0.246526 1.20127
    0.30 0.0248935 0.244423 1.18051
    0.40 0.0248935 0.242560 1.16217
    0.50 0.0248935 0.240906 1.14592
    0.60 0.0248935 0.239435 1.13149
    0.70 0.0248935 0.238122 1.11863
    0.80 0.0248935 0.236947 1.10716
    0.90 0.0248935 0.235894 1.09689

     | Show Table
    DownLoad: CSV
    Figure 1.  Graphical representation of Theorem 2.1 with F(δ)=eδ, Θ1=1, Θ2=2, 0<α<1.
    Figure 2.  Graphical representation of Theorem 2.3 for F(δ)=eδ,δ>0 and 0<α<1.

    Example 4.3. Taking Φ(δ)=Ψ(δ)=eδ in Theorem 2.2 for all δ>0, 0<α<1 and λ=1, then we observe the following numerical verifications (see Tables 4 and 5) and corresponding graphs (see Figures 3 and 4).

    Table 4.  Estimations of the first inequality of Theorem 2.2 for Φ(δ)=Ψ(δ)=eδ, Θ1=1 and Θ2=2.
    α Left side Right side
    0.10 0.00123937 5.73786
    0.20 0.00123937 5.1814
    0.30 0.00123937 4.7129
    0.40 0.00123937 4.31749
    0.50 0.00123937 3.98298
    0.60 0.00123937 3.69935
    0.70 0.00123937 3.45838
    0.80 0.00123937 3.25324
    0.90 0.00123937 3.07834

     | Show Table
    DownLoad: CSV
    Table 5.  Estimations of the second inequality of Theorem 2.2 for Φ(δ)=Ψ(δ)=eδ, Θ1=1 and Θ2=2.
    α Left side Right side
    0.10 0.0730897 1.48926
    0.20 0.0700023 1.41475
    0.30 0.0674546 1.35365
    0.40 0.0653563 1.30362
    0.50 0.0636327 1.26275
    0.60 0.0622219 1.22945
    0.70 0.0610724 1.20245
    0.80 0.0601415 1.18068
    0.90 0.0593939 1.16326

     | Show Table
    DownLoad: CSV
    Figure 3.  Graphs of first inequality of Theorem 2.2 for Φ(δ)=Ψ(δ)=eδ,δ>0 and 0<α<1.
    Figure 4.  Graphs of second inequality of Theorem 2.2 for Φ(δ)=Ψ(δ)=eδ,δ>0 and 0<α<1.

    Several new fractional H-H types for subadditive functions and their products are developed in this paper. As an ancillary finding, we also obtain inequalities for subadditive functions using tempered fractional integrals and a new identity. To confirm the veracity of our findings, we give several examples of subadditive functions, their graphical representations, and numerical calculations. For those interested in this topic and working on it, our findings utilizing the tempered fractional integral operators provide a number of new opportunities and make it possible for them to create additional approximations for many other varieties of operators.

    The authors declare that they have not used Artificial Intelligence (AI) tools in the creation of this article.

    This work was supported by the Researchers Supporting Project number (RSP2024R153), King Saud University, Riyadh, Saudi Arabia.

    The authors declare that they have no competing interests.



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