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Research article

Non-parametric hypothesis testing to model some cancers based on goodness of fit

  • Received: 02 February 2022 Revised: 03 May 2022 Accepted: 05 May 2022 Published: 23 May 2022
  • MSC : 62G10, 62G20, 62N05

  • By observing the failure behavior of the recorded survival data, we aim to compare the different processing approaches or the effectiveness of the devices or systems applied in this non-parametric statistical test. We'll apply the proposed strategy of used better than aged in Laplace (UBAL) transform order, which assumes that the data used in the test will either behave as UBAL Property or exponential behavior. If the survival data is UBAL, it means that the suggested treatment strategy is effective, whereas if the data is exponential, the recommended treatment strategy has no negative or positive effect on patients, as indicated in the application section. To guarantee the test's validity, we calculated the suggested test's power in both censored and uncensored data, as well as its efficiency, compared the results to other tests, and then applied the test to a variety of real data.

    Citation: M. E. Bakr, M. Nagy, Abdulhakim A. Al-Babtain. Non-parametric hypothesis testing to model some cancers based on goodness of fit[J]. AIMS Mathematics, 2022, 7(8): 13733-13745. doi: 10.3934/math.2022756

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  • By observing the failure behavior of the recorded survival data, we aim to compare the different processing approaches or the effectiveness of the devices or systems applied in this non-parametric statistical test. We'll apply the proposed strategy of used better than aged in Laplace (UBAL) transform order, which assumes that the data used in the test will either behave as UBAL Property or exponential behavior. If the survival data is UBAL, it means that the suggested treatment strategy is effective, whereas if the data is exponential, the recommended treatment strategy has no negative or positive effect on patients, as indicated in the application section. To guarantee the test's validity, we calculated the suggested test's power in both censored and uncensored data, as well as its efficiency, compared the results to other tests, and then applied the test to a variety of real data.



    Failure occurs when a unit or component fails to perform its needed function. The analysis of survival dataset failure behavior entails identifying whether the data exhibit a UBAL, or a constant failure rate. The two primary characteristics of the exponential distribution are: The memoryless property and the constant rate of failure property. The exponential distribution is the most important member of the life distribution classes due to these two characteristics. We now have a dataset with two claims: First, that the data are exponential, and second, that the data are UBAL. A statistical test is required to support one of the two hypotheses or claims, indicating which one is correct. The classification of life probability distributions has recently aided in the creation of novel high-efficiency statistical tests.

    Several categories of life distributions have been studied to model data with different aging aspects. There are numerous definitions for various life distributions, like the IFR, IFRA, Navarro and Pellerey [1], Bryson and Siddiqui [2], Barlow and Proschan [3], Esary et al. [4] and Navarro J. [5]. Many researchers have discussed various aging classifications, such as NBUC and NWUC were introduced by Cao and Wang [6]. Fernandez-Ponce et al. [7] have also looked into the multivariate NBU. Furthermore, Ahmad [8] looked at UBA and UBAE. The Laplace order for UBA has been explored by Abu Youssef et al. [9].

    The implications of the common classes of life distributions, which include the majority of well-known classes such as IFR, UBA, UBAE, and UBAL, are discussed as follows:

    IFR[1]UBA[8]UBAL[9]UBAE[8]

    If 0<μ()< and for all x,t0, Ahmad [8] defined the life distribution of used better than aged (UBA) as:

    ¯F(t)exμ()¯F(x+t),x,t0,

    and used better than the aged in expectation (UBAE):

    μ(t)μ(),

    where

    ¯Ft(x)={¯F(x+t)¯F(t)¯F(t)>00¯F(t)=0,

    and

    μ=E(X)=0¯F(u)du,μ(t)=E(Xt)=t¯F(u)du¯F(t).

    Definition:

    We said that F has used better than aged in the Laplace (UBAL) transform order property if 0<μ()<, ∀x,t0,

    0¯F(x+t)esxdx¯F(t)μ()1+sμ(),s0, (1.1)

    for more details, see Abu Youssef and Bakr [10].

    The major aim of this research is to address the issue of comparing H0:F is exponential to H1:F is the greatest class of life distribution UBAL. The following is how the paper is structured: In Section 2, we provide a test statistic for complete data based on the goodness of fit technique, Monte Carlo critical values are simulated for different sample sizes, and power estimates are produced and presented. The test statistic for censored data is obtained in Section 3. Finally, in Section 4, we go through some examples of how the suggested statistical test can be used in practice.

    A random sample of F is represented by X1,X2,,Xn. We develop a test statistic to test the null hypothesis H0:F is exponential (F(t)=βeβt), vs H1:F is UBAL. Many writers have addressed non-parametric testing for classes of life distributions (see Fernandez-Ponce and Rodrıguez-Grinolo [11]; Abu-Youssef et al. [9]; Mahmoud et al. [12]; Abu-Youssef et al. [13] and Abu-Youssef et al. [14]. According to (1.1) and without loss of generality, we assume μ() is known and equal one; the measure of departure based on the goodness of fit approach can be stated as;

    δ(s)=E[0esx¯F(x+t)dx11+s¯F(t)]=0[0¯F(x+t)esxdx11+s¯F(t)]dF0(t). (2.1)

    It's worth noting that under H0:δ(S)=0 and under H1:δ(s)>0.

    The test statistic of the proposed test for the UBAL class is given by the following theorem.

    Theorem 2.1.

    Suppose X be a UBAL random variable with distribution function F, then we'll build the test statistic using the goodness of fit approach as,

    δ(s)=1(1s)[1s(1φ)+2(1+s)(0exdF(x)1)], (2.2)

    where φ(s)=0esxdF(x).

    Proof.

    δ(s)=0[0esx¯F(x+t)dx11+s¯F(t)]dF0(t).

    We can take F0(x)=1ex,x0, then

    δ(s)=00etsu¯F(u+t)dudt11+s0¯F(t)etdt=I1I2.

    Where,

    I1=00esuet¯F(u+t)dudt=0tes(xt)et¯F(x)dxdt=0t0es(tx)et¯F(t)dxdt=1s0(1est)et¯F(t)dt=11s[1s(1φ(s))1+0etdF(t)]. (2.3)

    And,

    I2=11+s0¯F(t)dF0(t)=11+s[10etdF(t)]. (2.4)

    From Eqs (2.3) and (2.4), we obtain (2.2).

    The statistic's empirical estimator can be calculated as follows:

    ˆδn(s)=1n(1s)i{1s(1esXi)2(1+s)(1eXi)}, (2.5)

    and the corresponding invariant test statistic can be found as:

    ˆΔn(s)=ˆδn(s)¯X=1n¯Xi{1(1s)(1s(1esXi)2(1+s)(1eXi))}. (2.6)

    The asymptotic normality of the demonstrated statistic in (2.2) is illustrated in the next theorem.

    Theorem 2.2.

    Using the theory of U-statistics According to Lee [15], the statistic δ(s) has the following characteristics:

    As n,n(ˆΔn(s)δ(s)) is asymptotically normal with μ0=0 and variance σ2(s), where

    σ2(s)=var{1(1s)[1s(1φ)+2(1+s)(0exdF(x)1)]}.

    The variance in H0 is calculated as follows

    σ20(s)=23(1+s)2(2+s)(1+2s).

    Proof.

    By derived direct calculations, we can get μ0 as:

    μ0=0(1(1s){1s(1esx)+2(1+s)(ex1)})dx=0,

    as well as the variance

    σ2(s)=var(1(1s)[1s(1φ)+2(1+s)(0exdF(x)1)])=E(1(1s)[1s(1φ)+2(1+s)(0exdF(x)1)])2.
    σ20(s)=23(2+s)(1+s)2(1+2s).

    We can compare our test to some other known classes to determine the quality of the suggested test technique. We use the test ˆΔ(2) proposed by Mahmoud, et al. [12] for the (RNBUL) class of life distribution and δFn presented Mahmoud and Abdul Alim [16] for (NBUFR) class of life distribution. The Pitman asymptotic relative efficiency PARE is then used to make comparisons. In this case, we'll use the following options:

    (ⅰ) Linear failure rate family (LFR):

    ¯F1(x)=exx22θ,θ,x0. (2.7)

    (ⅱ) Weibull family:

    ¯F2(x)=exθ,θ1,,x0. (2.8)

    (ⅲ) Makeham family:

    ¯F2(x)=exθ(x+ex1),θ,x0. (2.9)

    It's worth noting that H0 (the exponential distribution) is achieved at θ=0 in (ⅰ & ⅲ) and θ=1 in (ⅱ). The asymptotic efficiency of the Pitman (PAE) of δ(s) as s=0.01ands=0.1 is equal to

    PAE(δ(0.01))=1σ0(0.01)|10.00990e0.01xd¯F'θ0(x)20.99990exd¯F'θ0(x)|,
    PAE(δ(0.1))=1σ0(0.1)|10.090e0.1xd¯F'θ0(x)20.990exd¯F'θ0(x)|,

    where ¯F'θ0(x)=ddθ¯Fθ(u)|θθ0. This leads to:

    (ⅰ) PAE in case of the linear failure rate distribution:

    PAE(ˆδ(0.01))=1σ0(0.01)|10.00990e0.01xd(x22ex)+20.99990exd(x22ex)|=1.29.
    PAE(ˆδ(0.1))=1σ0(0.1)|10.090e0.1xd(x22ex)+20.990exd(x22ex)|=1.25.

    (ⅱ) PAE in case of the Weibull distribution:

    PAE(ˆδ(0.01))=1σ0(0.01)|10.00990e0.01xd(xln|x|ex)+20.99990exd(xln|x|ex)|=0.96.
    PAE(ˆδ(0.1))=1σ0(0.1)|10.090e0.1xd(xln|x|ex)+20.990exd(xln|x|ex)|=0.94.

    (ⅲ) PAE in case of the Makeham distribution.

    PAE(ˆδ(0.01))=1σ0(0.01)|10.00990e0.01xd((1xex)ex)+20.99990exd((1xex)ex)|=0.86.
    PAE(ˆδ(0.1))=1σ0(0.1)|10.090e0.1xd((1xex)ex)+20.990exd((1xex)ex)|=0.77.

    Table 1 summarizes the direct computations of PAE of of ˆΔ(2), δFn and our δ(0.01)andδ(0.1). The efficiencies in the table clearly illustrate that our test performs well for F1,F2andF3.

    Table 1.  PAE of ˆΔ(2), δFn and δ(0.01)andδ(0.1).
    Distribution ˆΔ(2) δFn δ(0.01) δ(0.1)
    LFR 0.915 0.217 1.29 1.25
    Weibull 0.618 0.050 0.96 0.94
    Makeham 0.172 0.144 0.86 0.77

     | Show Table
    DownLoad: CSV

    PARE's of δ(0.01) and δ(0.1) concerning ˆΔ(2) and δFn whose PAE are listed in Table 1 are shown in Table 2.

    Table 2.  PARE of δ(0.01) and δ(0.1) concerning δ(0.01)andδ(0.1).
    Distribution e(δ(0.01),ˆΔ(2)) e(δ(0.1),ˆΔ(2)) e(δ(0.01),δFn) e(δ(0.1),δFn)
    LFR 1.40 1.37 5.94 5.76
    Weibull 1.55 1.52 19.2 18.8
    Makeham 5 4.48 5.97 5.35

     | Show Table
    DownLoad: CSV

    Table 2 shows that for F1,F2andF3, the statistics δ(0.01) and δ(0.1) perform well. For all of the scenarios discussed above, it outperforms both ˆΔ(2) and δFn.

    At a significance level of 0.05, Table 3 will be utilized to evaluate the power of the proposed test. For the Weibull; LFR, and Gamma distributions, these powers were estimated using 10000 simulated samples with n = 10, 20, and 30.

    Table 3.  Powers estimates at α=0.05.
    Distribution n θ=2 θ=3 θ=4
    Weibull 10 0.9998 1 1
    20 1 1 1
    30 1 1 1
    LFR 10 0.9988 1 1
    20 1 1 1
    30 1 1 1
    Gamma 10 0.9441 0.9995 1
    20 0.9924 1 1
    30 0.9987 1 1

     | Show Table
    DownLoad: CSV

    As demonstrated in Table 3, our test has high powers for the Weibull, LFR, and Gamma families.

    Here, we use 10000 simulations with sample sizes n = 10(5)100 from the standard exponential distribution to calculate the test statistic of our test test ˆΔn(s) as s=0.01ands=0.1 given in (2.6) for some selected values s.

    The asymptotic normality of our test improves as s decreases, as shown in Table 4.

    Table 4.  The upper percentile points of ˆδn(s).
    ^δδn(0.01) ^δδn(0.1)
    n 90% 95% 99% 90% 95% 99%
    5 0.222947 0.296991 0.416736 0.190928 0.250687 0.331011
    10 0.175661 0.234867 0.328956 0.148956 0.191851 0.266253
    15 0.152844 0.198555 0.282422 0.129411 0.164337 0.222148
    20 0.136991 0.180429 0.255117 0.111626 0.143976 0.200654
    25 0.12162 0.157556 0.223607 0.103156 0.132082 0.18402
    30 0.112775 0.14715 0.211407 0.0963509 0.122499 0.169919
    35 0.10628 0.136184 0.193097 0.0845552 0.109254 0.159572
    39 0.10213 0.13368 0.184562 0.083692 0.10837 0.150329
    40 0.102546 0.133687 0.186511 0.0836914 0.107069 0.15120
    41 0.096624 0.125063 0.178481 0.0801545 0.10443 0.14379
    45 0.095567 0.122137 0.174346 0.078977 0.100291 0.141727
    50 0.0933263 0.119181 0.167259 0.075482 0.0966459 0.132828
    55 0.0883399 0.113484 0.162532 0.0716097 0.0924242 0.127282
    60 0.0845056} 0.109896 0.156001 0.0709048 0.0905189 0.123108
    65 0.0800721 0.106347 0.149221 0.0674512 0.0854014 0.119576
    70 0.079694 0.102598 0.147153 0.0655145 0.0847923 0.11628
    75 0.0781665 0.0990352 0.138235 0.0634726 0.0803639 0.112566
    80 0.0750521 0.0960944 0.13506 0.0623859 0.0801786 0.110811
    85 0.0709399 0.0906362 0.12933 0.0593002 0.0768853 0.102688
    90 0.0704061 0.0898579 0.125016 0.0579873 0.0741982 0.102586
    95 0.0689002 0.0886083 0.124733 0.0555379 0.0718737 0.0998331
    100 0.068162 0.0866082 0.123173 0.054814 0.0702883 0.0990065

     | Show Table
    DownLoad: CSV

    In this section, a test statistic is provided to compare H0 and H1 using data that has been randomly right-censored.

    Let the test statistic written as follows:

    δc(s)=1(1s)nj=1j1k=1(1s(1ˆφ(s))+2(1+s)(1)), (3.1)

    where

    ˆφ(s)=nm=1esZ(m)(m2p=1CIppm1p=1CIpp),
    =nm=1esZ(m)(m2p=1CIppm1p=1CIpp)andCm=nmnm+1,t[0,z(m)].

    Again, based on 10000 simulated and sample sizes n = 5(5)100 from the standard exponential distribution in Table (5) below, the 90%, 95% and 99% percentage points of the test statistic in (3.1) are simulated for some selected values s.

    Table 5.  The upper percentile points of ˆδc(s).
    ^δδn(0.01) ^δδn(0.1)
    n 90% 95% 99% 90% 95% 99%
    5 79.1722 99.0099 99.0099 7.24026 9.09091 9.09091
    10 58.5798 66.7518 82.4772 5.30214 6.06734 7.54631
    15 48.3237 55.6325 69.5771 4.34842 5.05073 6.38021
    20 41.8856 48.071 59.9788 3.69852 4.28524 5.42593
    25 37.4361 43.4792 54.1946 3.35664 3.90187 4.99075
    30 34.2465 39.6075 50.708 3.09701 3.61357 4.69185
    35 31.8667 36.4782 46.2339 2.84254 3.34405 4.29118
    40 29.906 34.817 44.2144 2.6558 3.08495 3.97099
    45 28.031 32.6912 42.216 2.47709 2.86345 3.72305
    50 26.5686 30.8355 40.6515 2.34039 2.73995 3.48289
    51 26.2765 30.713 40.2296 2.3204 2.72125 3.40845
    55 25.321 29.3385 37.4214 2.24602 2.64514 3.37032
    60 24.4339 28.3712 36.8932 2.13922 2.49681 3.19249
    61 24.2339 28.3127 35.9142 2.09573 2.44195 3.13856
    65 23.3836 7.2437 34.2578 2.02729 2.3679 3.07914
    70 22.5253 26.2706 33.526 1.98388 2.31408 2.90431
    75 21.8598 25.6862 32.4598 1.9148 2.23591 2.90803
    80 20.927 24.4351 30.753 1.84222 2.15769 2.75052
    85 20.3111 23.9109 30.7706 1.76628 2.06116 2.66595
    90 19.9521 23.3886 29.6384 1.72034 2.0335 2.60288
    95 19.4658 22.4647 28.5529 1.70941 1.99008 2.54748
    100 18.6863 21.6688 28.2181 1.63263 1.93282 2.48212

     | Show Table
    DownLoad: CSV

    When s decreases, our test of ˆδc(s) behaves better in terms of asymptotic normality, as seen in Table 5.

    The powers estimate of the proposed test ˆδ will be carried out in Table 6 at the significant level α=0.05. These powers are estimated for Weibull, LFR and Gamma distributions based on 10000 simulated samples for sizes n=10,20 and 30.

    Table 6.  Powers estimates at α=0.05.
    n θ Distribution
    Weibull LFR Gamma
    10 1 0.9504 0.9532 0.9537
    2 0.9516 0.9534 0.9551
    3 0.9521 0.9534 0.9570
    20 1 0.9487 0.940 0.9465
    2 0.950 0.945 0.9468
    3 0.9516 0.950 0.9469
    30 1 0.950 0.9511 0.9541
    2 0.9523 0.9581 0.9545
    3 0.9591 0.9587 0.9549

     | Show Table
    DownLoad: CSV

    Our test has good powers for the Weibull, LFR, and Gamma families, as shown in Table 6.

    To demonstrate the utility of the conclusions in this study, we apply them to various real data sets.

    Application 1: Case of complete data.

    Example 1: Analyze the data in Abouammoh et al. [17], which show the ages (in years) of 40 patients aged with blood cancer (leukemia) in one of Saudi Arabia's health ministry hospitals.

    In the two situations of ˆΔn(0.01) and ˆΔn(0.1) as n=40, we calculate the statistic in (2.6) ˆΔn(0.01)=0.42 and ˆΔn(0.1)=0.35, which are both higher than the corresponding critical value in Table 4. As a result, we infer that this set of data seems to have the UBAL property rather than the exponential characteristic.

    Example 2: Take, for example, the data in Mahmoud et al. [12], which represent 39 liver cancer patients from Egypt's Ministry of Health's Elminia Cancer Center 2000.

    In the two situations of ˆΔn(0.01) and ˆΔn(0.1) as n=39, we calculate the statistic in (2.6) ˆΔn(0.01)=0.68 and ˆΔn(0.1)=0.16, which are both higher than the critical value in Table 4. As a result, we infer that this set of data seems to have the UBAL property rather than the exponential characteristic.

    Example 3: This data set from Abu-Youssef and Silvana Gerges [18] shows the survival times (in years) of 43 patients with a specific kind of leukemia diagnosis.

    In the two situations of ˆΔn(0.01) and ˆΔn(0.1) as n=43, we calculate the statistic in (2.6) ˆΔn(0.01)=0.098 and ˆΔn(0.1)=0.0097, which are both smaller than the critical value in Table 4. As a result, we infer that this set of data seems to have the exponential characteristic property rather than the UBAL.

    Application 2: Case of censored data.

    Example 1: In this application, we use the data from Mahmoud et al. [12], which reflects the ages (in days) of 51 liver cancer patients from the Elminia cancer center Ministry of health Egypt, who began the medical investigation in the year 2000. In the investigation, only 39 patients are watched (right-censored), while the remaining 11 are dropped (missing from the investigation).

    In the two situations of ˆΔn(0.1,0.2) and ˆΔn(0.5,5) as n=51, we calculate the statistic in (3.1) ˆΔn(0.01)=44.9 and ˆΔn(0.1)=8.42, which are both higher than the critical value in Table 5. As a result, we infer that this set of data seems to have the UBAL property rather than the exponential characteristic.

    Example 2: Consider the data in Kamran Abbas et al. [19] and in Lee and Wolfe [20], the survival times, in weeks, of 61 patients with inoperable lung cancer treated with cyclophosphamide. There are 33 uncensored observations and 28 censored observations, representing the patients whose treatment was terminated because of a devolving condition.

    In the two situations of ˆΔn(0.01) and ˆΔn(0.1) as n=61, we calculate the statistic in (3.1) ˆΔn(0.01)=28.4 and ˆΔn(0.1)=6.87, which are both higher than the critical value in Table 5. As a result, we infer that this set of data seems to have the UBAL property rather than the exponential characteristic.

    In this paper, a non-parametric testing for the UBAL based on goodness of fit is developed in both complete and censored cases. The percentage points of the proposed statistics are simulated. The efficacies of our developed tests are compared to Mahmoud, et al. [12] for the (RNBUL) class of life distribution and δFn presented by Mahmoud and Abdul Alim [16] based on Pitman asymptotic relative efficiency using some well-known life distributions; namely, Linear failure rate family (LFR), Makeham and Weibull family. Finally, the findings of the paper are applied to some medical real data sets.

    Notations and abbreviations.

    IFR Increasing failure rate.
    IFRA Increasing failure rate average.
    NBU New better than used.
    NB(W)UC New better (worse) than used in a convex ordering.
    UBA Used better than age.
    UBAE Used better than age in expectation.
    UBAL Used better than age in Laplace transform.

     | Show Table
    DownLoad: CSV

    This research was supported by King Saud University Research Supporting Project number (RSP-2021/156), King Saud University, Riyadh, Saudi Arabia.

    The authors declare there is no conflict of interest.



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