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Research article Special Issues

On periodic solutions of second-order partial difference equations involving p-Laplacian

  • By combining variational techniques with the saddle point theorem, we investigate the existence and nonexistence of periodic solutions to second-order partial difference equations involving p-Laplacians. Our obtained results generalize and complement some known ones. Finally, we display some examples and numerical simulations to show the validity of our main results.

    Citation: Dan Li, Yuhua Long. On periodic solutions of second-order partial difference equations involving p-Laplacian[J]. Communications in Analysis and Mechanics, 2025, 17(1): 128-144. doi: 10.3934/cam.2025006

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  • By combining variational techniques with the saddle point theorem, we investigate the existence and nonexistence of periodic solutions to second-order partial difference equations involving p-Laplacians. Our obtained results generalize and complement some known ones. Finally, we display some examples and numerical simulations to show the validity of our main results.



    Let Z, N, and R stand for the sets of integers, natural numbers and real numbers, respectively. Consider the existence and nonexistence of periodic solutions of a partial difference equation in the following form:

    1[ϕp(1x(n1,m))]2[ϕp(2x(n,m1))]=f((n,m),x(n,m)),n,mZ. (1.1)

    Here, i (i=1,2) represents the forward difference operator, and 1x(n1,m)=x(n,m)x(n1,m), 2x(n,m1)=x(n,m)x(n,m1). The p-Laplacian operator is defined as ϕp(x)=|x|p2x for 1<p<+ and xR. Given integers T1,T2>0, x={x(n,m)} is (T1,T2)-periodic, which means that x(n+T1,m)=x(n,m)=x(n,m+T2) for all (n,m)Z2. The nonlinearity fC(Z2×R,R) is T1-periodic in n and T2-periodic in m. Denote F((n,m),x)=x0f((n,m),s)ds for all (n,m)Z2.

    Owing to both in our real life and scientific research, many phenomena and data are recorded with discrete data; difference equations have a wide range of applications and a long research history in various fields to describe discrete phenomena [1,2]. With the popularization of computers and the rapid development of computer technology, the study of difference equation theory has made great progress in various aspects since Guo and Yu [3] first applied the variational method to difference equations. For example, the authors obtained periodic solutions [4], homoclinic solutions [5] of second-order difference equations, and standing waves solutions [6] for the discrete Schrödinger equations. As to difference equations involving p-Laplacians, here is a list of a few:

    (ϕp(xn1))+f(n,xn)=0,nZ, (1.2)

    where xn=xn+1xn, is a special case of Equation (1.1). Results on periodic solutions and positive solutions of (1.2) were given in [7] and [8], respectively. The authors [9] studied periodic solutions of

    (ϕp(xn1)+f(n,xn+1,xn,xn1)=0,nZ. (1.3)

    As (1.3) is in higher-order, homoclinic solutions and periodic solutions were displayed in [10] and [11].

    Nowadays, more and more phenomena need to be described by two or more multi-variables. Subsequently, both partial differential equations and partial difference equations, containing two or more than two variables, have caught the keen attention of many scholars, and rich results have emerged. Here mention a few; in [12,13,14], authors obtained a series of results for partial differential equations. Long studied discrete Kirchhoff-type problems and obtained a series of results on multiple solutions [15,16], least energy solutions [17] and infinitely many large energy solutions [18] (see also [19,20,21] and reference therein). In [22], the authors gave results on periodic solutions for a second- order difference equation. When partial difference equations contain p-Laplacian, multiple existence results were given in [23]. As to homoclinic solutions, Mei and Zhou [24] gave results for partial difference equations with mixed nonlinearities, and Long [25] considered nonlinear (p,q)-Laplacian partial difference equations with a parameter λ>0.

    Motivated by the above mentioned results, we deal with periodic solutions of (1.1) by variational techniques together with the saddle point theorem. To demonstrate the validity of our main results, we also present some examples and numerical simulations. Our results generalize and complement some known ones, as detailed in Remark 1.2.

    Now we state our main results as follows:

    Theorem 1.1. Assume the following suppositions are fulfilled.

    (A1) There exists a constant M0>0 such that

    f((n,m),x)∣≤M0, ((n,m),x)Z2×R.

    (A2)

    limx∣→+F((n,m),x)=+,(n,m)Z2.

    Then Equation (1.1) possesses at least a (T1,T2)-periodic solution.

    Theorem 1.2. Let f satisfy

    (A3) there exist positive constants R1 and α (2p<α<2) such that

    0<xf((n,m),x)αp2F((n,m),x), (n,m)Z2 and x∣≥R1;

    (A4) there exist positive constants b1, b2, and β (2p<βα) such that

    F((n,m),x)b1xβp2b2, ((n,m),x)Z2×R.

    Then Equation (1.1) admits at least a (T1,T2)-periodic solution.

    Remark 1.1. Substitute (A3) by

    (A3) there exist constants a1,a2>0 such that

    F((n,m),x)a1xαp2+a2, ((n,m),x)Z2×R.

    The conclusion of Theorem 1.2 is still valid.

    Further, to obtain nontrivial periodic solutions, we have

    Theorem 1.3. Assume the following conditions hold

    (A5) F((n,m),0)=0, (n,m)Z2;

    (A6) there exists a constant 2p<α<2 such that

    0<xf((n,m),x)αp2F((n,m),x), (n,m)Z2 and x0;

    (A7) there exist constants b3>0 and 2p<βα such that

    F((n,m),x)b3xβp2, ((n,m),x)Z2×R.

    Then Equation (1.1) has at least one nontrivial (T1,T2)-periodic solution.

    Theorem 1.4. Suppose (A1), (A2), and (A5) hold. Moreover,

    (A8) there exist constants b4>0 and 0<γ<2 such that

    F((n,m),x)b4xγp2, ((n,m),x)Z2×R.

    Then Equation (1.1) possesses at least one nontrivial (T1,T2)-periodic solution.

    Theorem 1.5. If for all (n,m)Z2 and x0, there holds

    xf((n,m),x)<0.

    Then Equation (1.1) has no nontrivial (T1,T2)-periodic solution.

    Remark 1.2. Our Theorems 1.1, 1.2, 1.3 and 1.4 are generalizations of Theorems 1.1, 1.2, 1.3, and 1.4 in [9], respectively. Moreover, Theorem 1.5 supplements the nonexistence of periodic solutions of Equations (1.1) and (1.2).

    The rest of this paper is organized as follows. In Section 2, we establish the variational framework corresponding to Equation (1.1) and give some basic lemmas that play a vital role in proving our main results. Section 3 presents detailed proofs of our main results. Finally, three examples and numerical simulations are provided in Section 4.

    For convenience, we give some notations. Denote Z(t,s):={t,t+1,,s} with integers ts and Ω:=Z(1,T1)×Z(1,T2). Let

    x={x(n,m)}n,mZ=(;,x(1,0),x(2,0),;,x(1,1),x(2,1),;).

    Define a T1T2-dimensional subspace E of vector space S={x={x(n,m)}|x(n,m)R,n,mZ} by

    E={x={x(n,m)}S|x(n+T1,m)=x(n,m)=x(n,m+T2),n,mZ},

    which is endowed with the inner product

    x,y=T1n=1T2m=1x(n,m)y(n,m),x,yE.

    Thus, the induced norm is

    x=(T1n=1T2m=1|x(n,m)|2)12,xE,

    and E is isomorphic to RT1T2.

    Write

    xp=(T1n=1T2m=1|x(n,m)|p)1p,xE.

    It follows that x2=x and there exist positive constants ζp and ξp with ζpξp=(T1T2)2p2p such that

    ζpxxpξpx,xE. (2.1)

    Further, we have, for any xE, there exist positive constants C1, C2, C3 such that

    C1xαp2xC2xβp2, (2.2)
    C1xαp2xC3xγp2. (2.3)

    Consider the associated functional I:ER in the form as

    I(x)=1pT1n=1T2m=1[|1x(n1,m)|p+|2x(n,m1)|p]+T1n=1T2m=1F((n,m),x(n,m)). (2.4)

    Then I is C1. Using periodic conditions, simple calculation yields that

    Ix(n,m)=1[ϕp(1x(n1,m))]+2[ϕp(2x(n,m1))]+f((n,m),x(n,m)),

    which means that Equation (1.1) is the corresponding Euler-Lagrange equation for I. Consequently, we transform the problem to find (T1,T2)-periodic solutions of Equation (1.1) to the problem to seek critical points of I in E.

    Identify x={x(n,m)}n,mZE with

    x=(x(1,1),,x(T1,1);x(1,2),,x(T1,2);;x(1,T2),,x(T1,T2))T,

    and write

    x=Dx=(x(1,1),,x(1,T2);x(2,1),,x(2,T2);;x(T1,1),,x(T1,T2))T,

    where

    T12T1(T21)T1+1D=(100000000000100000000000100010000000000010000000000010001000000000001000000000001)T22T2(T11)T2+1.

    Then xs=xs for all s>1.

    Let

    Akl=(Bk0Bk0Bk)kl×kl

    with

    Bk=(2100112100012000002110012)k×k.

    By [9], the eigenvalues of matrix AT1T2 are λi=2(1cos2iπT1), i=0,1,2,,T11. Thus λ0=0 and λi>0 for 1iT11. Further, each λi is T2-multiple and

    {λ_=min{λ1,λ2,,λT11}=4sin2πT1,¯λ=max{λ1,λ2,,λT11}=4cos21(1)T14T1π. (2.5)

    Similarly, AT2T1 has eigenvalues μj (0jT21) and

    {μ_=min{μ1,μ2,,μT21}=4sin2πT2,¯μ=max{μ1,μ2,,μT21}=4cos21(1)T24T2π. (2.6)

    We split E as E=VY with Y={yE|y={c,c,,c},cR}. It follows that

    T1n=1T2m=1|1x(n1,m)|pξpp¯λp2xp,xE,T1n=1T2m=1|2x(n,m1)|pξpp¯μp2xp=ξpp¯μp2xp,xE, (2.7)

    and

    T1n=1T2m=1|1x(n1,m)|pζppλ_p2xp,xV,T1n=1T2m=1|2x(n,m1)|pζppμ_p2xp=ζppμ_p2xp,xV. (2.8)

    Now, we state some basic definitions. Let X be a real Banach space. IC1(X,R) satisfies the Palais-Smale (P.S. for short) condition, which states that any sequence {xn}X such that {I(xn)} is bounded and limnI(xn)0 possesses a convergent subsequence.

    We denote by Bρ, the open ball with center 0 and radius ρ in X, and Bρ its boundary. Recall the Saddle Point Theorem, introduced in [26], which plays a crucial role in proofs of our main results.

    Lemma 2.1. (Saddle Point Theorem [26]) Let X=X1X2 be a real Banach space with finite-dimensional subspace X1{0}. Suppose IC1(X,R) fulfills the P.S. condition and

    (J1) IBρX1σ for constants σ and ρ>0;

    (J2) Ie+X2ω for constants eBρX1 and ω>σ.

    Then I admits a critical value cω with

    c=infhΓmaxxBρX1I(h(x))andΓ={hC(ˉBρX1,X)hBρX1=id}.

    In this section, we present detailed proofs of our main results.

    Proof of Theorem 1.1 We complete the proof by Lemma 2.1 in three steps.

    Step 1 I satisfies the P.S. condition on E.

    Assume that {xk}E is a P.S. sequence, that is, limkI(xk)=0 and there exists a constant M1>0 such that I(xk)∣≤M1. Then for k large enough and any xE, we have

    I(xk),xx. (3.1)

    Take xk=vk+ykVY, it follows that

    I(xk),vk=T1n=1T2m=1{1[ϕp(1xk(n1,m))]+2[ϕp(2xk(n,m1))]+f((n,m),xk(n,m))}vk(n,m)=T1n=1T2m=1[ϕp(1vk(n,m))ϕp(1vk(n1,m))]vk(n,m)+T1n=1T2m=1[ϕp(2vk(n,m))ϕp(2vk(n,m1))]vk(n,m)+T1n=1T2m=1f((n,m),xk(n,m))vk(n,m)=T1n=1T2m=1[ϕp(1vk(n1,m))vk(n1,m)ϕp(1vk(n1,m))vk(n,m)]+T1n=1T2m=1[ϕp(2vk(n,m1))vk(n,m1)ϕp(2vk(n,m1))vk(n,m)]+T1n=1T2m=1f((n,m),xk(n,m))vk(n,m)=T1n=1T2m=1[ϕp(1vk(n1,m))1vk(n1,m)+ϕp(2vk(n,m1))2vk(n,m1)]+T1n=1T2m=1f((n,m),xk(n,m))vk(n,m)=T1n=1T2m=1[|1vk(n1,m)|p+|2vk(n,m1)|p]+T1n=1T2m=1f((n,m),xk(n,m))vk(n,m).

    Together with (A1) and (3.1), we deduce that

    T1n=1T2m=1[|1vk(n1,m)|p+|2vk(n,m1)|p]T1n=1T2m=1[f((n,m),xk(n,m))vk(n,m)]+vkM0T1n=1T2m=1vk(n,m)+vk(M0T1T2+1)vk. (3.2)

    By (2.8), we have

    T1n=1T2m=1[|1vk(n1,m)|p+|2vk(n,m1)|p]ζpp(λ_p2+μ_p2)vkp. (3.3)

    Thus, combining (3.2) with (3.3), we obtain

    ζpp(λ_p2+μ_p2)vkp(M0T1T2+1)vk. (3.4)

    Since p>1, (3.4) ensures that vk has a maximum value. Thus, {vk} is a bounded sequence.

    Next, we show that {yk} is also a bounded sequence. Owing to (A1), (2.7) and

    M1I(xk)=1pT1n=1T2m=1[|1xk(n1,m)|p+|2xk(n,m1)|p]+T1n=1T2m=1F((n,m),xk(n,m))=1pT1n=1T2m=1[|1vk(n1,m)|p+|2vk(n,m1)|p]+T1n=1T2m=1F((n,m),yk(n,m))+Tn=1T1m=1[F((n,m),xk(n,m))F((n,m),yk(n,m))],

    we attain that, for θ(0,1), there holds

    T1n=1T2m=1F((n,m),yk(n,m))M1+1pT1n=1T2m=1[|1vk(n1,m)|p+|2vk(n,m1)|p]+T1n=1T2m=1F((n,m),xk(n,m))F((n,m),yk(n,m))M1+ξppp(¯λp2+¯μp2)vkp+T1n=1T2m=1f((n,m),(yk+θvk)(n,m))vk(n,m)M1+ξppp(¯λp2+¯μp2)vkp+M0T1n=1T2m=1vk(n,m)M1+ξppp(¯λp2+¯μp2)vkp+M0T1T2vk.

    Notice that {vk} is bounded, then {T1n=1T2m=1F((n,m),yk(n,m))} is bounded. We claim that {yk} is bounded. Otherwise, we assume that limkyk=. Let yk=(ck,ck,,ck)TY where ckR, kN, then

    yk=(T1n=1T2m=1ck2)12=T1T2ck∣→+ask+.

    In view of (A2),

    F((n,m),yk(n,m))=F((n,m),ck)+ as k.

    Thus, {T1n=1T2m=1F((n,m),yk(n,m))}+, which is a contradiction. Therefore, {yk} is bounded. Consequently, {xk}E is a bounded sequence on the finite-dimensional space E, and the P.S. condition is verified.

    Step 2 (J1) of Lemma 2.1 is fulfilled.

    From (A1), there exists a constant M0>0 such that

    F((n,m),z)∣≤M0z+M0, ((n,m),z)Z2×R.

    Utilizing (2.8), for any vV, it follows that

    I(v)=1pT1n=1T2m=1[|1v(n1,m)|p+|2v(n,m1)|p]+T1n=1T2m=1F((n,m),v(n,m))ζppp(λ_p2+μ_p2)vp+M0T1n=1T2m=1v(n,m)+M0T1T2ζppp(λ_p2+μ_p2)vp+M0T1T2v+M0T1T2,asv+.

    Therefore, (J1) holds.

    Step 3 (J2) of Lemma 2.1 is satisfied.

    For any yY, there is cR such that

    y=(c,c,,c)T.

    Taking account of (A2), one gets that there exists a constant R0>0 such that F((n,m),x)>0 for any (n,m)Z2 and x∣>R0. Let

    M2=minx∣≤R0F((n,m),x), M2=min{0,M2}.

    Then

    F((n,m),x)M2, ((n,m),x)Z2×R.

    Hence, we have

    I(y)=T1n=1T2m=1F((n,m),c)M2T1T2,yY,

    which indicates that I satisfies (J2) of Lemma 2.1 with e=0. Thus, the desired result follows.

    Proof of Theorem 1.2 To prove Theorem 1.2 by Lemma 2.1, it is necessary to verify that I satisfies the P.S. condition on E and the geometry conditions (J1) and (J2) of Lemma 2.1.

    First, we testify that the P.S. condition is satisfied. Suppose {xk}E and there is a constant M3>0 such that

    limkI(xk)=0andI(xk)∣≤M3,kN. (3.5)

    Then for k is large enough, there holds

    I(xk),xk∣≤xk. (3.6)

    Recall

    I(xk),xk=T1n=1T2m=1[|1xk(n1,m)|p+|2xk(n,m1)|p]+T1n=1T2m=1f((n,m),xk(n,m))xk(n,m).

    In combination with (3.5) and (3.6), we have

    M3+1pxkI(xk)1pI(xk),xk=T1n=1T2m=1[F((n,m),xk(n,m))1pf((n,m),xk(n,m))xk(n,m)]. (3.7)

    Write Ω=Ω1Ω2, where

    Ω1={(n,m)Ω |xk(n,m)|R1},Ω2={(n,m)Ω |xk(n,m)|<R1}. (3.8)

    Then (3.7) and (A3) imply that

    M3+1pxkT1n=1T2m=1F((n,m),xk(n,m))1p(n,m)Ω1f((n,m),xk(n,m))xk(n,m)1p(n,m)Ω2f((n,m),xk(n,m))xk(n,m)T1n=1T2m=1F((n,m),xk(n,m))α2(n,m)Ω1F((n,m),xk(n,m))1p(n,m)Ω2f((n,m),xk(n,m))xk(n,m)=(1α2)T1n=1T2m=1F((n,m),xk(n,m))+1p(n,m)Ω2[α2pF((n,m),xk(n,m))f((n,m),xk(n,m))xk(n,m)].

    Moreover, α2pF((n,m),z)f((n,m),z)z is continuous with respect to z, which means that there is a constant M4>0 such that

    α2pF((n,m),z)f((n,m),z)zM4,(n,m)Z2andz∣≤R1.

    Thus,

    M3+1pxk(1α2)T1n=1T2m=1F((n,m),xk(n,m))1pT1T2M4. (3.9)

    By (A4) and (3.9), we achieve

    M3+1pxk(1α2)b1T1n=1T2m=1xk(n,m)βp2(1α2)b2T1T21pT1T2M4=(1α2)b1T1n=1T2m=1xk(n,m)βp2M5,

    where M5=(1α2)b2T1T2+1pT1T2M4. Joint with (2.3), we obtain

    M3+1pxk(1α2)b1Cβp22xkβp2M5,

    that is,

    (1α2)b1Cβp22xkβp21pxkM3+M5. (3.10)

    Remind 2p<βα<2, (3.10) guarantees {xk} is bounded. Since E is finite dimensional, the P.S. condition is satisfied.

    Second, we complete the proof by verifying that I satisfies the geometry conditions (J1) and (J2) of Lemma 2.1. For any y=(c,c,,c)Y with cR, (A4) means that

    I(y)=T1n=1T2m=1F((n,m),y(n,m))b1T1n=1T2m=1y(n,m)βp2b2T1T2=b1T1T2cβp2b2T1T2=:ω0.

    For any vV, (A3), (2.2) and (2.8) yield

    I(v)=1pT1n=1T2m=1[|1v(n1,m)|p+|2v(n,m1)|p]+T1n=1T2m=1F((n,m),v(n,m))ζppp(λ_p2+μ_p2)vp+a1T1n=1T2m=1v(n,m)αp2+a2T1T2ζppp(λ_p2+μ_p2)vp+a1Cαp21vαp2+a2T1T2. (3.11)

    Notice that 2p<α<2, (3.11) indicates that there is a constant ρ0>0 large enough such that

    I(v)ω01<ω0,vV,v=ρ0.

    Thus, both (J1) and (J2) are satisfied. Therefore, Lemma 2.1 ensures that Equation (1.1) possesses at least a (T1,T2)-periodic solution. The proof is completed.

    Proof of Theorem 1.3 To obtain nontrivial solutions, we divide the proof of Theorem 1.3 in four steps.

    Step 1 I satisfies the P.S. condition on E.

    Let sequence {xk}E such that

    limkI(xk)=0,I(xk)∣≤M6,kN,

    where M6>0 is a constant. For k large enough, one obtains

    I(xk),xk∣≤xk.

    Moreover,

    I(xk),xk=T1n=1T2m=1[|1xk(n1,m)|p+|2xk(n,m1)|p]+T1n=1T2m=1f((n,m),xk(n,m))xk(n,m).

    Together with (2.3), (A6) and (A7), it follows that

    M6+1pxkI(xk)1pI(xk),xk=T1n=1T2m=1[F((n,m),xk(n,m))1pf((n,m),xk(n,m))xk(n,m)]T1n=1T2m=1[F((n,m),xk(n,m))α2F((n,m),xk(n,m))]=(1α2)T1n=1T2m=1F((n,m),xk(n,m))(1α2)b3T1n=1T2m=1xk(n,m)βp2(1α2)b3Cβp22xkβp2.

    Namely,

    (1α2)b3Cβp22xkβp21pxkM6. (3.12)

    Recall 2p<βα<2, (3.12) implies that {xk} is a bounded sequence. Due to the fact that E is a finite-dimensional space, then I satisfies the P.S. condition.

    Step 2 I meets (J1) of Lemma 2.1.

    For any vV, (3.11) gives

    I(v)ζppp(λ_p2+μ_p2)vp+a1Cαp21vαp2+a2T1T2  as v+.

    Therefore, (J1) of Lemma 1 is satisfied.

    Step 3 I fulfills (J2) of Lemma 2.1.

    Given x=v0+y with v0V and yY, from (A7), (2.3), and (2.7), we have that

    I(x)=1pT1n=1T2m=1[|1x(n1,m)|p+|2x(n,m1)|p]+T1n=1T2m=1F((n,m),x(n,m))ξppp(¯λp2+¯μp2)v0p+b3T1n=1T2m=1(v0+y)(n,m)βp2ξppp(¯λp2+¯μp2)v0p+b3Cβp22v0βp2+b3Cβp22yβp2,

    which means that there is a sufficiently small positive constant δ1 satisfying

    I(v0+y)δβp21(b3Cβp22ξppp(¯λp2+¯μp2)δpβp21):=ω1>0,

    for v0Bδ1V and yY. Then (J2) is valid.

    Step 4 I has a nontrivial critical point.

    Applying the saddle point theorem, we find a critical value cω1>0 of I. Let ˉxE be the corresponding critical point, that is,

    I(ˉx)=cω1>0. (3.13)

    Further, ˉx is a nontrivial critical point, that is, ˉx0. Or else, if ˉx=0, by (A5), we have

    I(ˉx)=T1n=1T2m=1F((n,m),0)=0.

    This contradicts (3.13). Hence, ˉx0 and the proof is completed.

    Proof of Theorem 1.4 From the proof of Theorem 1.1, we know that (A1) and (A2) ensure that the P.S. condition and (J1) of Lemma 2.1 are valid. Then we only need to prove that (J2) of Lemma 2.1 also holds.

    Taking x=v0+y, where v0V and yY, by (A8), (2.3) and (2.8), we obtain

    I(x)=1pT1n=1T2m=1[|1x(n1,m)|p+|2x(n,m1)|p]+T1n=1T2m=1F((n,m),x(n,m))=1pT1n=1T2m=1[|1v0(n1,m)|p+|2v0(n,m1)|p]+T1n=1T2m=1F((n,m),(v0+y)(n,m))ξppp(¯λp2+¯μp2)v0p+b4T1n=1T2m=1(v0+y)(n,m)γp2ξppp(¯λp2+¯μp2)v0p+b4Cγp23v0γp2+b4Cγp23yγp2,

    which means that, for v0Bδ2V and any yY, there exists a sufficiently small constant δ2>0 such that

    I(v0+y)δγp22(b4Cγp23ξppp(¯λp2+¯μp2)δpγp22):=ω2>0.

    Thus (J2) is verified. Therefore, Lemma 2.1 means that I admits a critical value cω2>0. Denote the corresponding critical point by ˉx, that is, I(ˉx)=c>0. With (A5), we get

    I(0)=T1n=1T2m=1F((n,m),0)=0,

    which implies that ˉx0. Thus our proof is done.

    Proof of Theorem 1.5 For the sake of contradiction, we assume that x is a nontrivial (T1,T2)-periodic solution of Equation (1.1), which is equivalent to the fact that x is a nontrivial critical point of I on E. Hence, I(x)=0 with x0. Direct computation gives that

    I(x),x=T1n=1T2m=1[|1x(n1,m)|p+|2x(n,m1)|p]+T1n=1T2m=1f((n,m),x(n,m))x(n,m).

    Therefore,

    T1n=1T2m=1f((n,m),x(n,m))x(n,m)=T1n=1T2m=1[|1x(n1,m)|p+|2x(n,m1)|p]0. (3.14)

    On the other hand, (A9) gives

    T1n=1T2m=1f((n,m),x(n,m))x(n,m)<0.

    This is in conflict with (3.14). Consequently, the proof is finished.

    We give three examples to illustrate applications of our main results. Write

    ˉE={x={x(n,m)}S|x(n+2,m)=x(n,m)=x(n,m+2),n,mZ}.

    To facilitate the presentation of numerical simulations, we abbreviate xˉE as

    x=(x(1,1),x(2,1),x(1,2),x(2,2)).

    Example 4.1. Take T1=T2=2 and p=3. Consider

    1[ϕ3(1x(n1,m))]+2[ϕ3(2x(n,m1))]+16x(n,m)1+x2(n,m)=0,n,mZ. (4.1)

    Here

    f((n,m),x)=16x1+x2,xR.

    By integration, it yields

    F((n,m),x)=8ln(1+x2),xR.

    Direct calculations give

    f((n,m),x)∣=∣16x1+x2∣≤8,limx∣→+F((n,m),x)=+.

    Thus, Equation (4.1) fulfills all the assumptions of Theorem 1.1, which guarantees that Equation (4.1) has at least a (2,2)-periodic solution. Use Matlab; a solution xˉE of Equation (4.1) is presented as

    x=(1,1,1,1).

    Example 4.2. Take p=3 and T1=T2=2. Consider

    1[ϕ3(1x(n1,m))]+2[ϕ3(2x(n,m1))]+4x(n,m)=0,n,mZ. (4.2)

    Here

    f((n,m),x)=4x,xR,

    then

    F((n,m),x)=2x2,xR.

    Take α=43 and β=43, then (A3) and (A4) of Theorem 1.2 hold. Thus, Equation (4.2) has at least a (2,2)-periodic solution.

    Further, we know that F((n,m),0)=0 for any n,mZ. Thus, (A5), (A6), and (A7) of Theorem 1.3 are also true. Thereby, it can be further confirmed that Equation (4.2) holds at least one nontrivial (2,2)-periodic solution. We list a solution xˉE of Equation (4.2) as follows:

    x=(12,12,12,12).

    Example 4.3. Consider Equation (1.1) with f((n,m),x)=x. Then Equation (1.1) turns into

    1[ϕ3(1x(n1,m))]+2[ϕ3(2x(n,m1))]x(n,m)=0. (4.3)

    It is clear that the condition (A9) of Theorem 1.5 is valid. Therefore, Equation (4.3) has no nontrivial (T1,T2)-periodic solution.

    Dan Li: Writing-original draft, formal analysis; Yuhua Long: Methodology, writing-review editing.

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.

    We wish to thank the handling editor and the referees for their valuable comments and suggestions. We would also like to thank the National Natural Science Foundation of China 12471177.

    The authors declare there is no conflict of interest.



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